Select all that are equivalent to 43.


12


64


4 × 3


4 × 4 × 4


(4 × 4) × 4


3 × 3 × 3 × 3

Answer: c. 27

Step-by-step explanation: 48-21=27

Answer:

you multipy 3 everytime

The value of the third quartile would be 57.4

Given that,

The percentage of the popular vote that each winning candidate in each of the 15 presidential elections received.

Now arrange the given data in ascending order.

\(43.2, 43.4, 47.9, 49.2, 49.6, 49.7, 50.1, 50.7, 51.2, 53.9, 55.1, 57.4, 58.8, 60.7, 61.1\)

So, divide the data into four equal parts.

Since there are 15 values, the third quartile will be the value in the position:

\(\dfrac{3}{4} \times 15 = 11.25\)

For the third quartile, round up to the nearest whole number, which gives us position 12.

Here, the value at the 12th position is 57.4

Therefore, the third quartile is 57.4

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The equation can have no solution or as many solutions as possible

Terrence's conclusion that the equation has infinitely many solutions is false

The equation is given as:

101 - 6+ 2 = 4(3x - 1) - 2

Open the bracket

101 - 6+ 2 = 12x - 4 - 2

Collect the like terms

12x = 101 - 6+ 2 + 4 + 2

Evaluate the like terms

12x = 103

Divide both sides by 12

x =103/12

The above shows that the equation has one solution

Hence, Terrence's conclusion that the equation has infinitely many solutions is false

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Answer:

Look at the picture attached.

Step-by-step explanation:

Your x-intercept is 6 and your y-intercept is 4, that is where your 2 points will go. According to the slope, you should go up 2 and over 3, if you don't want to find the x-intercept. Then you would just plot the y-intercept which is 4, and then go up 2, over three and plot the next.

Hope this helps! :)

Answer:

Answer is in the picture, hope i got it right :)

Organizations that build strategic information systems create systems that are paramount to business success. The correct option is(D).

Strategic information systems are those that support the long-term goals and objectives of an organization, aligning the use of technology with the strategic direction of the business. These systems provide a competitive advantage by enabling the organization to achieve its strategic goals and objectives more efficiently and effectively.

They typically involve the integration of different types of information systems, such as transaction processing systems, decision support systems, and executive information systems, to support the decision-making process at all levels of the organization.

By building strategic information systems, organizations can improve their overall performance, enhance their operational efficiency, and gain a competitive advantage in the marketplace.

Such systems can help organizations to better understand their customers, identify new market opportunities, improve supply chain management, and optimize business processes.

In today's rapidly changing business environment, strategic information systems are essential for organizations to remain competitive and achieve long-term success.

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This student performed better than 68% of the other test-takers in the verbal part and better than 27% in the quantitative part.

Given,

Test-taker scored at the 68th percentile for their verbal grade and at the 27th percentile for their quantitative grade .

Now,

68% percentile : 68% scores equal or less .

27% percentile : 27^ scored equal or less .

Thus option D

This student performed better than 68% of other test taker in verbal and better than 27% in quantitative part .

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Solution

x=\frac{-5 \pm \sqrt{13}}{6}

The addendum, dedendum, circular pitch, and base-circle diameter are 0.3333 inches, 0.4167 inches, 1.0472 inches, and 8.1667 inches, respectively.

A spur pinion of 21 teeth mates with a gear of 28 teeth, with a diametral pitch of 3 teeth/inch and a pressure angle of 20 degrees..

To find the addendum, dedendum, circular pitch, and base-circle diameters, we will use the following formulas:

Addendum = 1/DP

Dedendum = 1.25/DP

Circular pitch = pi/DP

Base-circle diameter = D - 2.5/P

Where DP is the diametral pitch, pi is the constant, D is the pitch diameter, and P is the circular pitch.

Let us calculate the values one by one:

Addendum:

Addendum = 1/DP  

Addendum = 1/3  

Addendum = 0.3333 inches

Dedendum:

Dedendum = 1.25/DP  

Dedendum = 1.25/3  

Dedendum = 0.4167 inches  

Circular pitch:

Circular pitch = pi/DPCircular pitch = pi/3Circular pitch = 1.0472 inches

Base-circle diameter:

Base-circle diameter = D - 2.5/P  

Base-circle diameter = (21 + 28)/6

Base-circle diameter = 8.1667 inches

Therefore, the addendum, dedendum, circular pitch, and base-circle diameter are 0.3333 inches, 0.4167 inches, 1.0472 inches, and 8.1667 inches, respectively.

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Answer:

Step-by-step explanation:

The multiplicity of a root of a polynomial equation is the number of times it appears in the solution.

Multiplicity is important because it can tell us two things about the polynomial that we work on and how it is graphed. first: it tells us the number repeating factor a polynomial has to determine the number of the real (positive or negative) roots and complex roots of the polynomial.

About graph behaves at the roots : Behavior of a polynomial function near a multiple root

The root −4 is a 'simple' root (of multiplicity 1), and therefore the graph crosses the x-axis at this root. The root 1 is of even multiplicity and therefore the graph bounces off the x-axis at this root.

Answer:

When we say that an allele is "fixed," it means that a particular allele has reached a frequency of 100% in a population.

Step-by-step explanation:

Alleles are different forms of a gene that occupy the same position on homologous chromosomes. In a population, different alleles can exist for a specific gene. However, through various evolutionary processes such as natural selection, genetic drift, or gene flow, one allele may become predominant and eventually fixate within the population.

The fixation of an allele can occur through different mechanisms. For example, if a beneficial allele provides a selective advantage to individuals carrying it, it is more likely to increase in frequency and eventually become fixed in the population. On the other hand, genetic drift, which is the random change in allele frequencies due to chance events, can also lead to the fixation of an allele, especially in small populations.

Once an allele is fixed in a population, it means that all future generations will inherit that allele, and no alternative alleles will be present at that particular gene locus.

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To find the displacement and total distance traveled by the object from t=0 to t=6, we need to integrate the velocity function over the given time interval.

The displacement can be found by integrating the velocity function v(t) with respect to t over the interval [0, 6]. The integral of v(t) represents the net change in position of the object during this time interval.

The total distance traveled can be determined by considering the absolute value of the velocity function over the interval [0, 6]. This accounts for both the forward and backward movements of the object.

Now, let's calculate the displacement and total distance traveled using the given velocity function v(t) = t^2 - (1/t) - 12 over the interval [0, 6].

To find the displacement, we integrate the velocity function as follows:

Displacement = ∫[0,6] (t^2 - (1/t) - 12) dt.

To find the total distance traveled, we integrate the absolute value of the velocity function as follows:

Total distance = ∫[0,6] |t^2 - (1/t) - 12| dt.

By evaluating these integrals, we can determine the displacement and total distance traveled by the object from t=0 to t=6.

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Answer:

The altitude is 6.53 cm

Step-by-step explanation:

A regular tetrahedron is a triangular pyramid having equilateral triangular faces, therefore we have;

Sides of the equilateral triangle = 8 cm

Given that the slant height, the edge of the tetrahedron, and half the base edge of the tetrahedron form a right triangle, we have;

The slant height, h = √(8² - (8/2)²) = √48 = 4×√3

The segment representing the altitude, H, of the tetrahedron forms a right triangle with the edge of the tetrahedron and 2/3×h

Therefore;

8² = H² + (2/3×4×√3)²

H² = 8² - (2/3×4×√3)²

H² = 64 - 64/3 = 128/3

The altitude H = √(128/3) = √6×8/3 = 6.53 cm.

Answer:

she cant

Step-by-step explanation:

Sarkis cannot draw a triangle with these side lengths. Therefore, option A is correct.

Given that, a triangle with sides measuring 4 ft, 10 ft, and 16 ft.

What are the conditions to construct a triangle?

In the triangle, the sum of any two sides is always greater than the third side. The difference between any two sides of the triangle is always less than the third side.

Sarkis cannot draw a triangle with these side lengths. Therefore, option A is correct.

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Answer:

Nadia

Step-by-step explanation:

6/8 is 3/4 and both are 75% of a pizza but, the eighths of a pizza is a smaller slice of pizza.

4/4 is four slices of pizza

8/8 is eight slices of pizza        

They are different amounts.

The largest glass bottle on record was blown in 1992 by a team in Millville, New Jersey, with a volume of 193 U.S. fluid gallons.

The information provided states that the largest glass bottle ever made had a volume of 193 U.S. fluid gallons and was created in 1992 by a team in Millville, New Jersey. This indicates that, as of 1992, no other known glass bottle had surpassed the size of this particular bottle.

The fact that this record-setting bottle was blown in 1992 suggests that, up until that point, no larger glass bottle had been successfully created. It signifies that the team in Millville, New Jersey, achieved a milestone in glassblowing by producing a bottle with a volume of 193 U.S. fluid gallons, surpassing any previous records or known instances of such a large glass container. The mention of this specific record serves as a historical reference point for the largest glass bottle ever made.

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Answer:

7. about 41.8 degrees or 0.72972 radians (used \(sin^{-1} (\frac{4}{6} )\), because the given leg is opposite from the angle)

8. about 50.4 degrees or 0.87946 radians (used \(tan^{-1} (\frac{29}{24} )\))

9. about 12.8 degrees or 0.224 radians (used \(sin^{-1} (\frac{12}{54} )\))

10. about 51.3 degrees or 0.8957 radians (used \(cos^{-1} (\frac{25}{40} )\), given leg is opposite from angle)

Step-by-step explanation:

S.O.H.--C.A.H.--T.O.A

sine = opposite (to angle)/hypotenuse

cosine = adjacent (to angle)/hypotenuse

tangent = opposite (to angle)/adjacent (to angle)

I didn't know if it was degrees or radians, so I did both! I saw you on the film question asking for help, so I just wanted to do so! Have a great day!

Answer:

Step-by-step explanation:

9% of the volume of the original volume is removed.

Given that the dimensions of solid box is 15 cm by 10 cm by 8 cm.

So the volume of solid box = 15*10*8 cubic cm = 1200 cubic centimeter

The volume of the cube with side 3 cm = 3*3*3 = 27 cubic centimeter

For each corner one cube so the number of cube is 4

So total volume removed = 4*27 = 108 cubic centimeters

The percent of volume is removed = (108/1200)*100% = 9%

Hence the percentage of volume removed is 9%.

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Answer:

x = 10

Step-by-step explanation:

well all three angles would equal 180 in a triangle

6x - 6 + 7x + 1 + 55 = 180

combine terms

13x + 50 = 180

13x = 130

x = 10

Answer:

40% of Camilla shots were made, it is LESS THAN Emily's percent of shots.

Step-by-step explanation:

2/5=p/100

0.4x100=p

p=40

40%<75%

The percentage of shots Emily made is more than Emily's percentage of shots because Camilla's percentage shots are 40% and for Emily is 75%.

It's the ratio of two integers stated as a fraction of a hundred parts. It is a metric for comparing two sets of data, and it is expressed as a percentage using the percent symbol.

It is given that:

Camilla makes 2 of her 5 shots attempted.

From the data given:

2/5 = p/100

p = 0.4x100

p = 40

40%<75%

Thus, the percentage of shots Emily made is more than Emily's percentage of shots because Camilla's percentage shots are 40% and for Emily is 75%.

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Answer:

13.5=x

Step-by-step explanation:

-3+6=2x-24

3=2x-24

+24   +24

___________

27=2x

÷2   ÷2

___________-

13.5 = x

Hope this helps :D

Comparing the means of the two samples, we find that the difference between the means is significant. Therefore, we can reject the claim and conclude that male and female high school students have different exam scores.

To perform the two-sample t-test, we first calculate the standard error of the difference between the means using the formula:

SE = sqrt((s1^2 / n1) + (s2^2 / n2))

Where s1 and s2 are the population standard deviations of the male and female students respectively, and n1 and n2 are the sample sizes. Plugging in the values, we have:

SE = sqrt((47^2 / 49) + (4.3^2 / 53))

Next, we calculate the t-statistic using the formula:

t = (x1 - x2) / SE

Where x1 and x2 are the sample means. Plugging in the values, we have:

t = (239 - 21.1) / SE

We can then compare the t-value to the critical t-value at α = 0.01 with degrees of freedom equal to the sum of the sample sizes minus 2. If the t-value exceeds the critical t-value, we reject the null hypothesis.

In this case, the t-value is calculated and compared to the critical t-value using the provided standard normal distribution table. Since the t-value exceeds the critical t-value, we can reject the claim that male and female high school students have equal exam scores.

Therefore, the correct answer is:

B. Male and female high school students have different exam scores.

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Given that the triangular plate is fixed at its base, and its apex a is given a horizontal displacement of 5 mm. suppose that a = 600 mm.In order to find the deflection, consider the right triangle OAB where O is the origin,

A (0,600) and B (x,y).So,OB² = OA² + AB²= 600² + x²Since the length of the side opposite to angle B is given as 600 - y, we can use Pythagoras' theorem to express y in terms of x and hence find the equation of the line AB, i.e. y = f(x).Thus, OB² = OA² + AB²x² + (600 - y)² = 600² + x²y = 600 - √(600² - x²)From the geometry of the figure, it can be seen that the deflection at point A is equal to the displacement of B in the x direction, i.e.5 mm. Therefore, the deflection at point A is 5 mm.Long Answer:The problem is about finding the deflection at a point of a triangular plate that is fixed at its base and has an apex that is given a horizontal displacement of 5 mm. It is also given that a = 600 mm. In order to solve the problem,

we need to consider the geometry of the situation and use some elementary trigonometry.The figure below shows the triangular plate with the origin at the left end of the base and the y-axis perpendicular to the base at the origin. The apex of the triangle is at point A with coordinates (0,600).Let B (x,y) be a point on the plate such that OB is perpendicular to the base. Then, OB = x and AB = y. From the geometry of the figure, we can write the following equation:OB² = OA² + AB²where OB² = x², OA = 600, and AB² = (600 - y)²Therefore, we havex² = 600² + (600 - y)²Simplifying the equation, we getx² = 720000 - 1200y + y² + x²600y = 720000 - y²y² + 600y - 720000 = 0Solving for y, we gety = -300 + √(90000 + 360000 - 4×720000)/2y = 600 - √(600² - x²)Since the deflection at point A is equal to the displacement of B in the x direction, the deflection at A is given by 5 mm.Answer: The deflection at point A is 5 mm.

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The high-low method is a cost estimation technique that involves analyzing the two most extreme periods of activity to estimate fixed and variable cost behavior. It is commonly used in managerial accounting to determine the fixed and variable components of a mixed cost.

Here are the characteristics of the high-low method:

Based on the two most extreme periods of activity: The method compares the cost incurred during the period of highest activity (high point) and the cost incurred during the period of lowest activity (low point). By examining the differences in costs between these two points, it attempts to separate the fixed and variable elements of the cost.

Provides a good estimate of true fixed and variable cost behavior: The high-low method assumes that the variable cost component varies proportionally with the level of activity, while the fixed cost component remains constant. By using the high and low points, it calculates the slope of the cost line and the y-intercept, which represent the variable and fixed costs, respectively.

Difficult to apply and requires a statistical software package: While the high-low method is a relatively simple technique, it can be challenging to apply in practice. Determining the high and low points requires careful analysis of the available data. Additionally, the method may not capture all the nuances of cost behavior, especially if the relationship between cost and activity is not linear. To perform the calculations accurately, statistical software packages or spreadsheets are often utilized.

Uses only two data points: One of the limitations of the high-low method is that it relies on only two data points. This can lead to potential inaccuracies if the data points chosen are not representative of the entire range of activity. The method assumes that the cost behavior between the high and low points is linear, which may not always be the case.

In summary, the high-low method is a cost estimation technique that provides an estimate of fixed and variable cost behavior by analyzing the two most extreme periods of activity. It can be a useful tool, but it has limitations and requires careful consideration of data selection and interpretation.

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Step-by-step explanation: 2 x 4 ² - 2x + 10

                                                2 x 4 = 8

                                                8 x 8 = 64

                                               64 - 2x + 10

                                               64 - 2 x 4 + 10

                                                64 - 8 + 10

                                                56 + 10 = 66

When palpating the abdomen, you should note whether the liver is enlarged in the right upper quadrant, option d.

The liver is the largest internal organ located in the upper right portion of the abdomen. When assessing for liver enlargement through palpation, healthcare professionals typically focus on the right upper quadrant of the abdomen.

By concentrating on the right upper quadrant during palpation, healthcare professionals can gather information about the size, tenderness, or abnormalities of the liver. This specific region provides the best access and proximity to assess the liver and detect any potential enlargement or abnormalities.

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