True. Security is especially important when data or processing is performed at a centralized facility, as it often contains sensitive information and resources. Centralized facilities may be more prone to targeted attacks compared to remote locations, making proper security measures crucial.
True. When data or processing is performed at a centralized facility, there is a higher risk of unauthorized access or breaches. It is important to have proper security measures in place to protect sensitive information and prevent cyber attacks. Remote locations may also require security measures, but the risk is often lower due to the smaller scale of operations.
True. Security is especially important when data or processing is performed at a centralized facility, as it often contains sensitive information and resources. Centralized facilities may be more prone to targeted attacks compared to remote locations, making proper security measures crucial.
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The statement "Security is especially important when data or processing is performed at a centralized facility, rather than at remote locations" is true. Centralized facilities, such as data centers, have become increasingly common in recent years as companies seek to consolidate their IT infrastructure and reduce costs. However, with this increased centralization comes an increased risk of security breaches.
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In Female, the twenty-third pair of chromosomes is called in in
Which element of impurity plays a significant role in deciding the mechanical properties of commercially pure titanium?
The element of impurity that plays a significant role in deciding the mechanical properties of commercially pure titanium is oxygen.
High levels of oxygen impurities can negatively affect the mechanical properties of titanium, such as reducing ductility and increasing brittleness. This is because oxygen can form interstitial solid solutions with titanium, leading to the formation of brittle titanium oxides and decreased mechanical strength. Therefore, controlling oxygen levels in commercially pure titanium is important for ensuring optimal mechanical properties.
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© 2022. Grand Canyon University. All Rights Reserved.APA Activity 2: Citing PracticeCreate a reference page by citing the following sources in correct APA format. You may use your text or the GCU Library website to help you, but do not use citation generators.•A textbook: The second edition of Psychology and Your Life by Robert S. Feldman written in 2013. The publishing city is New York, New York published from McGraw Hill Companies.•Snickers commercial https://youtu.be/2rF_FRCd_LA •PBS Frontline special League of Denial •The document found at this address:http://www.eia.gov/forecasts/aeo/er/pdf/0383er(2013).pdf•The movie Silver Linings Playbook•The episode of Friends titled: The One After Joey and Rachel Kiss•The 7th edition of the APA Manual
Using APA reference style, the references is attached below from Feldman, R. S. (2013) to American Psychology Association (2020)
What is APA Reference StyleAPA reference style is a style of citing sources used by the American Psychological Association. It is primarily used in the social sciences and includes guidelines for citing sources both within the text of a document and in the reference list at the end of the document. The guidelines provide a consistent way of citing sources to make it easier for readers to identify and locate the sources cited in a document.
In the given problem, if we need to write the reference using APA style, it will take this format below
Reference Page:
Feldman, R. S. (2013). Psychology and your life (2nd ed.). New York, NY: McGraw Hill Companies.
Frontline. (n.d.). League of denial. Retrieved from https://www.pbs.org/wgbh/frontline/film/league-of-denial/
Friends. (2004). The one after Joey and Rachel kiss [Television series episode]. In D. Crane, & M. Kauffman (Executive producers), Friends. Burbank, CA: Warner Bros. Television.
Silver Linings Playbook. (2012). [Motion Picture]. United States: The Weinstein Company.
U.S. Energy Information Administration. (2013). Annual energy outlook 2013 with projections to 2040. Retrieved from http://www.eia.gov/forecasts/aeo/er/pdf/0383er(2013).pdf
Snickers. (2013, April 2). You’re not you when you’re hungry [Video file]. Retrieved from https://youtu.be/2rF_FRCd_LA
American Psychological Association. (2020). Publication manual of the American Psychological Association (7th ed.). doi:10.1037/0000165-000
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Describe some three materials with nanocrystalline structures and identify each example of those material
Ultrafine crystalline grains in the nanometer range that are separated by grain boundaries or interfaces define nanocrystalline materials.
A nanocrystalline structure: what is it?A polycrystalline substance with a few nanometer-sized crystallites is referred to as a nanocrystalline (NC) substance. These materials bridge the gap between traditional coarse-grained materials and amorphous materials devoid of long-range organisation. Materials that contain clusters, crystallites, or molecules with diameters between 1 and 100 nm are said to be nanostructured materials.
What is an example of a nanostructure?The gecko's foot, iridescent butterfly wings, and hydrophobic leaves are just a few examples of nanostructures found in nature. Scientists and engineers are employing biomimicry to develop new goods with these nano-inspired qualities.
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Of the following, which is not a consideration that must be addressed in determining inspection intervals for AST's?
A) Corrosion prevention systems
B) Inspection Interval of other equipment located near the tank under consideration
C) Changes in service(Including changes in water bottoms)
D) Previous inspection results
Answer:
B) Inspection Interval of other equipment located near the tank under consideration is not a consideration that must be addressed in determining inspection intervals for AST's.
Explanation:
A ball bearing has been selected with the bore size specified in the catalog as 35.000 mm to 35.020 mm. Specify appropriate minimum and maximum shaft diameters to provide a locational interference fit.
Answer:
A ball bearing has been selected with the bore size specified in the catalog as 35.000 mm to 35.020 mm. Specify.... ... has been selected with the bore size specified in the catalog as 35.000 mm to 35.020 mm. Specify appropriate minimum and maximum shaft diameters to provide a locational interference fit.
Explanation:
A circuit has two resistors in parallel, each resistor is 6 ohms. This circuit is connected to a single resistor of 6 ohms, to form a series-parallel circuit. What is the total resistance of the circuit?
The tatal resistance of the series-parallel circuit with two resistor connected in parallel which combination is connected in series to a single resistor is 9 ohms.
What is a resistance?
This can be defined as the opposition to current flow in a circuit.
To calculate the total resistance, first we need to find the total resistance of the parallel resistor.
For parallel,
R' = (R₁R₂)/(R₁+R₂)............Equation 1Where:
R' = Total resistance of the parallel resistor.
From the question,
Given:
R₁ = 6 ohmsR₂ = 6 ohmsSubstitute these values into equation 1
R' = (6×6)(6+6)R' = 3 ohms.Finally, we combine the effective parallel resistance in series to the single resistance to the the total resistance of the circuit.
Rt = R'+R₃.................. Equation 2Where:
Rt = Total resistance of the circuit.From the question,
R' = 3 ohmsR₃ = 6 ohmsSubstitute these values into equation 2
Rt = 3+6Rt = 9 ohms.Hence, the total resistance of the circuit is 9 ohms.
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To read signs you need good focal vision
Answer:eyesight
Explanation:
Discuss three objectives of Tariff and elaborate on three characteristics of it
Answer:
The Tariff can be called the custom duty tax. This tax is levied on customers when they have been crossed the good from the national boundaries.
Explanation:
The words called custom, duty is used with tariff services. The tariff is laid on people because to save the domestic product or to raise the revenue. The tariff is firstly used to protect the product and then maybe to yield the revenue.
The domestic products bear tariffs if the goods are equal to the tariff or the foreign brands bear the tariff if the tariff is equal to the products. Then the duty will be equal and beneficial for both services.
The tariff has been classified into three categories such as:
The transit dutyThe export dutiesThe import duties.
A 110-V rms, 60-Hz source is applied to impedance Z. Theapparent power entering the load is 120 VA at a power factor of0.707 lagging.(a) Calculate the complex power.(b) Find the rms current supplied to the load.(c) Determine Z.(d)Assuming that Z=R+jωL, find the values of R andL.
(a) To calculate the complex power (S), we can use the formula S = P + jQ, where P is the real power (in watts), and Q is the reactive power (in VARs). Since we are given the apparent power (120 VA) and the power factor (0.707 lagging), we can find the real and reactive power using the following equations:
P = S * power factor = 120 VA * 0.707 = 84.84 W
Q = √(S^2 - P^2) = √(120^2 - 84.84^2) = 84.84 VAR (lagging)
Now we can write the complex power as S = 84.84 + j84.84.
(b) To find the rms current (I) supplied to the load, we can use the formula I = S / V, where V is the rms voltage. Rearranging the formula and plugging in the given values, we get:
I = 120 VA / 110 V = 1.0909 A rms
(c) To determine the impedance (Z), we can use the formula Z = V / I, where V is the rms voltage, and I is the rms current. Plugging in the values, we get:
Z = 110 V / 1.0909 A = 100.8 + j100.8 ohms (approx)
(d) Assuming that Z = R + jωL, we can find the values of R and L by equating the real and imaginary parts:
R = 100.8 ohms
ωL = 100.8 ohms
To find L, we can use the formula ω = 2πf, where f is the frequency. Given the 60-Hz source, we can calculate ω as follows:
ω = 2π * 60 Hz = 377 rad/s
Now we can solve for L:
L = ωL / ω = 100.8 ohms / 377 rad/s ≈ 0.268 H
So, the values of R and L are 100.8 ohms and 0.268 H, respectively.
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Consider the following code segment: int[][] mystery = new int[3][3]; int counter = 0; while(counter < mystery.length) { for(int col = 0; col < mystery[counter].length; col++) { if(counter == 0) { mystery[col][counter] = 1; } else if(counter == 1) { mystery[counter][col] = 2; } else { mystery[counter][counter] = 3; } } counter++; }
What will the value of each element in mystery be after the execution of the code segment?
a) {{1, 0, 0} {2, 2, 2} {1, 0, 3}}
b) {{1, 1, 1} {2, 2, 2} {3, 3, 3}}
c) {{1, 2, 0} {1, 2, 0} {1, 2, 3}}
d) {{3, 0, 0} {2, 2, 2} {1, 0, 3}}
e) {{1, 2, 3} {1, 2, 3} {1, 2, 3}}
The value of each element in mystery be after the execution of the code segme is c) {{1, 2, 0}, {1, 2, 0}, {1, 2, 3}}.
Here's how the code works:
1. First, a 3x3 array called "mystery" is created and initialized with all 0's.
2. Then, a variable called "counter" is set to 0.
3. A while loop is started that will run as long as "counter" is less than the length of "mystery".
4. Inside the while loop, a for loop is started that will iterate through each column of the row specified by the current value of "counter".
5. Depending on the value of "counter", one of three things will happen:
a) If "counter" is 0, then the current element of "mystery" at the current column and row (col and counter, respectively) will be set to 1.
b) If "counter" is 1, then the current element of "mystery" at the current row and column (counter and col, respectively) will be set to 2.
c) If "counter" is anything other than 0 or 1 (i.e. it's 2), then the current element of "mystery" at the current row and column (counter and counter) will be set to 3.
6. After the for loop finishes iterating through all the columns of the current row, "counter" is incremented by 1.
7. The while loop then repeats the above steps with the next row of "mystery", until all rows have been processed.
So, putting it all together, here's what happens:
1. The first row of "mystery" is processed. The for loop iterates through all 3 columns of this row.
a) At column 0, "counter" is 0, so the element at (0,0) is set to 1.
b) At column 1, "counter" is 0, so nothing happens.
c) At column 2, "counter" is 0, so nothing happens.
2. The second row of "mystery" is processed. The for loop iterates through all 3 columns of this row.
a) At column 0, "counter" is 1, so the element at (1,0) is set to 2.
b) At column 1, "counter" is 1, so the element at (1,1) is set to 2.
c) At column 2, "counter" is 1, so the element at (1,2) is set to 2.
3. The third row of "mystery" is processed. The for loop iterates through all 3 columns of this row.
a) At column 0, "counter" is 2, so the element at (2,0) is set to 1.
b) At column 1, "counter" is 2, so the element at (2,1) is set to 2.
c) At column 2, "counter" is 2, so the element at (2,2) is set to 3.
So, after the code segment finishes executing, the "mystery" array will look like this:
{{1, 2, 0}, {1, 2, 0}, {1, 2, 3}}.
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(Entity relationship diagram)
Question:
1) Control of payment of a school: a school requires a system for the
registration and control of payment of the students of the different grades (1st. to 6th.
Grade).
*Please pass image with complete diagram*
Answer: The accounting procedures and financial management systems used by a school to record and report on the transactions in the Federal Student Aid programs play a major role in the school’s management of those programs. In this appendix, we will discuss the minimum criteria for those procedures and systems, identify areas where problems might arise, and point out potential system weaknesses.
Explanation:
design a randomized variant of binary search where in each iteration we compare the target with multiple middle elements chosen at random
Iterative implementation of Randomized Binary Search in Python based program.
# Python program to implement recursive
# randomized algorithm.
# To generate random number
# between x and y ie.. [x, y]
from random import randint
def getRandom(x, y):
return randint(x,y)
# A iterative randomized binary search function.
# It returns location of x in
# given array arr[l..r] if present, otherwise -1
def randomizedBinarySearch(arr, l, r, x):
while (l <= r):
# Here we have defined middle as
# random index between l and r ie.. [l, r]
m = getRandom(l, r)
# Check if x is present at mid
if (arr[m] == x):
return m
# If x greater, ignore left half
if (arr[m] < x):
l = m + 1
# If x is smaller, ignore right half
else:
r = m - 1
# if we reach here, then element was
# not present
return -1
# Driver code
arr = [2, 3, 4, 10, 40]
n = len(arr)
x = 10
result = randomizedBinarySearch(arr, 0, n-1, x)
if result == 1:
print("Element is not present in array")
else:
print("Element is present at index", result)
Output:
Element is present at index 3
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What is 90 to the power of 46
Answer:Just multiply 90 by itself 46 times
Explanation:
do it
Where is a clutch (bell) housing flange face most susceptible to wear at its mating surface with the flywheel housing?
The clutch housing flange face is most susceptible to wear at its mating surface with the flywheel housing due to constant contact and friction between the two surfaces. Over time, this can lead to surface damage, such as grooves or rough spots, which can cause problems with the proper functioning of the clutch and transmission.
In particular, the area around the dowel pins is especially prone to wear and damage, as this is where the majority of the force is concentrated during clutch engagement and disengagement. Additionally, if the clutch is not properly aligned with the flywheel housing, it can cause uneven wear and damage to the flange face.
To prevent excessive wear and damage to the clutch housing flange face, it is important to regularly inspect the clutch system for proper alignment and function, and to address any issues promptly. This may include replacing worn components, adjusting the clutch linkage, or realigning the clutch assembly with the flywheel housing.
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me that both a triaxial shear test and a direct shear test were performed on a sample of dry sand. When the triaxial test is performed, the specimen was observed to fail when the major and minor principal stresses were 100 lb/in2 and 20 lb/in2, respectively. When the direct shear test is performed, what shear strength can be expected if the normal stress is 3000 lb/ft2
Answer:
shear strength = 2682.31 Ib/ft^2
Explanation:
major principal stress = 100 Ib / in2
minor principal stress = 20 Ib/in2
Normal stress = 3000 Ib/ft2
Determine the shear strength when direct shear test is performed
To resolve this we will apply the coulomb failure criteria relationship between major and minor principal stress a
for direct shear test
use Mohr Coulomb criteria relation between normal stress and shear stress
Shear strength when normal strength is 3000 Ib/ft = 2682.31 Ib/ft^2
attached below is the detailed solution
The Automotive Component Education tab includes which of the following? Select the correct option and click NEXTa. Part numbers and exploded viewsb. Information related to automobile componentsc. Technical education about automobilesd. In-depth automotive training
The Automotive Component Education tab includes information related to automobile components. Thus, the correct option for this question is B.
The automotive component may be characterized as the automotive industry in the use of robots. They have embraced robotic technology as a means to achieve some specific tasks and functions in order to facilitate the work of individuals.
An automobile is made of several components, assemblies, and systems. The growing automotive industry has given rise to a growing auto component.
An automobile has several parts. But there are four essential components and parts of the automobile. These are Chassis, Engine, Transmission System, & Body.
Therefore, the Automotive Component Education tab includes information related to automobile components. Thus, the correct option for this question is B.
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A settling tank has an influent rate of 0.6 mgd. It is 12 ft deep and has a surface area of 8000 ft². What is the hydraulic retention time?
Answer: hydraulic retention time,τ=28.67 hours
Explanation:
The hydraulic retention time τ (tau), is given as The volume of the settling tank(V) divided by the influent flowrate(Q)
τ =V/Q
But Volume is not known and is given as
Volume = surface area x depth of the tank
= 8000 ft² X 12 ft
= 96,000 ft³
Also, the influent flow rate is in mgd ( million gallons per day), we change it to ft³/sec so as to be in same unit with the volume in ft³
1 million gallons/day = 1.5472286365101 cubic feet/second
0.6mgd = 1.5472286365101 cubic feet/second x 0.6
=0.93cubic feet/second
τ =V/Q
96,000 ft³/0.93 ft³/sec
τ=103,225.8 secs
changing to hours
103,225.8 /3600 =28.67 hours
The hydraulic retention time =28.67 hours
what do you think of web 3.0? do you think it will be realized someday in the future?
Answer:
is this a question for hoework
The bronze C86100 pipe has an outer diameter of 1. 5 in. And a thickness of 0. 125 in. The coupling on it at C is being tightened using a wrench. If the applied force is F = 20 lb, determine the maximum shear stress in the pipe
The bronze C86100 pipe's maximum shear stress with an outer diameter of 1. 5 in. is around 16.98 psi.
How to determine shear stress?To find the maximum shear stress in the pipe, use the formula:
τ = F / (2A)
where τ = shear stress, F = applied force, and A = area on which the force is acting.
Assume that the force is evenly distributed around the circumference of the pipe, so the area on which it is acting is equal to the circumference times the thickness:
A = πD t
where D = outer diameter and t = thickness.
Substituting the given values:
D = 1.5 in
t = 0.125 in
F = 20 lb
A = πD t = π(1.5)(0.125) = 0.589 in²
Therefore, the maximum shear stress is:
τ = F / (2A) = 20 / (2 × 0.589) = 16.98 psi
So the maximum shear stress in the pipe is approximately 16.98 psi.
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Which terminal of the OBD-II data link connector is the chassis ground for all vehicles?
4
1
5
3
The OBD-II data link connector is a standardized diagnostic connector found in most modern vehicles. It is usually located under the dashboard or steering wheel and is used to communicate with the vehicle's onboard computer systems.
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Technician A says that 5W-30 would be better to use than 20W-50 in most vehicles in
cold weather conditions. Technician B says 20W-50 flows better than 5W-30 in cold
weather. Who is correct?
20
Explanation:
Technician A says that primary vibration is created by slight differences in the inertia of the pistons between top dead center and bottom dead center. Technician B says that secondary vibration is a strong low-frequency vibration caused by the movement of the piston traveling up and down the cylinder. Who is correct? O A. Neither Technician A nor B OB. Technician B O C. Both Technicians A and B D. Technician A
Select the correct answer.
Which chemical can you use to assist with your motor fuel needs?
O A.
ethylene glycol
OB.
ethanol
O c.
butanol
OD.
pentanol
O E.
propranolol
Reset
Next
Answer: Ethanol
Explanation:
Describe the differences between case hardening and through hardening, insofar as engineering applications of metals are concerned.
Answer:
The answer is below
Explanation:
Case hardening is a form of steel hardening that is applied on mild steel with a high temperature of heat.
It results in material forming a hard surface membrane, while the inner layer is soft.
It is mostly used for universal joints, construction cranes, machine tools, etc.
On the other hand, Through hardening is a form of steel hardening in engineering that involves heat treatment of carbon steel.
It increases the hardness and brittleness of the material.
It is often used for axles, blades, nuts and bolts, nails, etc.
What phase best describes the function of a thermostat?
Answer:
a formula containing arguments
Explanation:
Hopefully that's correct
what is the condition for sampling frequency to reconstruct the information signal ?
Assume you have created a class named MyClass and that is contains a private field named
myField and a nonstatic public method named myMethod(). Which of the following is
true?
a. myMethod() has access to and can use myField
b. myMethod() does not have access to and cannot use myFeild.
c. myMethod() can use myField but cannot pass it to other methods.
d. myMethod() can use myField only in myField is passed to myMethod() as a
parameter.
Answer:
a. myMethod() has access to and can use myField.
Explanation:
Logic programming is a kind of programming which is largely based on formal logic. The statement are written in logical forms which express rules about the domain. In the given scenario the my method will have access to my field which is private field. My method non static public field can also use my field class.
a) what would if we tried to further accelerate a
Supersonic fluid with a
diverging diffuser?
If we tried to further accelerate a Supersonic fluid with a diverging diffuser, the pressure will decrease due to an increase in area. This can be described as :
dA/A = dP/ρV² (1-M²) for supersonic flow Mach Number, M: M > 11 - M² < 0 (dA/A) = -K (dP/ρV²)k = 1-M²
What is Supersonic Fluid?Supersonic flow fields have Mach numbers greater than one at every location. Supersonic flows are usually characterized by the presence of shock waves, which cause abrupt changes in flow characteristics and streamlines (in contrast to the smooth, continuous variations in subsonic flows).
Supersonic and subsonic relate to speeds that are faster or slower than the speed of sound, respectively. Supersonic means traveling faster than the speed of sound, which is 343.2 m/s (1,126 ft/s). Subsonic speeds are defined as anything moving slower than the speed of sound.
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cubical tank 1 meter on each edge is filled with water at 20 degrees C. A cubical pure copper block 0.46 meters on each edge with an initial temperature of 100 degrees C is quickly submerged in the water, causing an amount of water equal to the volume of the smaller cube to spill from the tank. An insulated cover is placed on the tank. The tank is adiabatic. Estimate the equilibrium temperature of the system (block + water). Be sure to state all applicable assumptions.
Answer:
final temperature = 26.5°
Explanation:
Initial volume of water is 1 x 1 x 1 = 1 \(m^{3}\)
Initial temperature of water = 20° C
Density of water = 1000 kg/\(m^{3}\)
volume of copper block = 0.46 x 0.46 x 0.46 = 0.097 \(m^{3}\)
Initial temperature of copper block = 100° C
Density of copper = 8960 kg/\(m^{3}\)
Final volume of water = 1 - 0.097 = 0.903 \(m^{3}\)
Assumptions:
since tank is adiabatic, there's no heat gain or loss through the wallsthe tank is perfectly full, leaving no room for cooling airtotal heat energy within the tank will be the summation of the heat energy of the copper and the water remaining in the tank.mass of water remaining in the tank will be density x volume = 1000 x 0.903 = 903 kg
specific heat capacity of water c = 4186 J/K-kg
heat content of water left Hw = mcT = 903 x 4186 x 20 = 75.59 Mega-joules
mass of copper will be density x volume = 8960 x 0.097 = 869.12 kg
specific heat capacity of copper is 385 J/K-kg
heat content of copper Hc = mcT = 869.12 x 385 x 100 = 33.46 Mega-joules
total heat in the system = 75.59 + 33.46 = 109.05 Mega-joules
this heat will be distributed in the entire system
heat energy of water within the system = mcT
where T is the final temperature
= 903 x 4186 x T = 3779958T
for copper, heat will be
mcT = 869.12 x 385 = 334611.2T
these component heats will sum up to the final heat of the system, i.e
3779958T + 334611.2T = 109.05 x \(10^{6}\)
4114569.2T = 109.05 x \(10^{6}\)
final temperature T = (109.05 x \(10^{6}\))/4114569.2 = 26.5°
Hello, here are 16 questions about basic electricity lesson. Could you please give an immediate solution? I would be very happy if you could solve them all.
The energy residing within the capacitor is effectively equal to 24 microjoules.
How to calculate the energyUsing the formula for capacitance, C = Q/V, where C is represented in Farads and V is distinguished by the voltage across the capacitor, we arrange the equation to obtain V = Q/C. Applying the given values of 0.12 mC & 3 µF culminates in 40 volts as our hypothetical voltage across the 3 µF capacitor.
Furthermore, if our desired outcome is the determinate energy stored within the capacitor, then, in accordance with E = 1/2 * C * V^2 (where E is measured in Joules), substituting the priorly acquired answers results in 24 µJ. Ergo, the energy residing within the capacitor is effectively equal to 24 microjoules.
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