Section Two (2): INSTRUCTIONS FOR COMPLETING SECTION TWO (2): Derive equations for velocity, acceleration, and distance where necessary, and answer the following questions 1, which includes 1(a) and 1

Answers

Answer 1

With an initial velocity of 20 m/s and a constant acceleration of 4 m/s², the car would travel a distance of 150 meters after 5 seconds. This is calculated using the equation s = ut + (1/2)at².

Given a car with an initial velocity of 20 m/s and a constant acceleration of 4 m/s², we can determine the distance traveled by the car after 5 seconds using the equations of motion.

Using the equation for distance, which is derived by integrating the velocity equation with respect to time, we have:

s = ut + (1/2)at²

Plugging in the given values:

s = (20 m/s)(5 s) + (1/2)(4 m/s²)(5 s)²

Simplifying the equation, we get:

s = 100 m + (1/2)(4 m/s²)(25 s²)

s = 100 m + 2 m/s² * 25 s²

s = 100 m + 50 m

s = 150 m

Hence, the car would have traveled a distance of 150 meters after 5 seconds, assuming it started with an initial velocity of 20 m/s and experienced a constant acceleration of 4 m/s².

This distance is obtained by substituting the given values into the equation for distance.

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Complete question:

Derive equations for velocity, acceleration, and distance where necessary, and answer the following questions  1(a): Given a car with an initial velocity of 20 m/s and a constant acceleration of 4 m/s², calculate the distance traveled by the car after 5 seconds.


Related Questions

In a 30cm by 25cm rectangle, a quadrant of a circle of radius 7cm has been cut away from each corner. What is the perimeter of the part left? ​

Answers

Answer: 98cm

Explanation:

Dimension of rectangle = 30cm by 25cm

Length(l) = 30cm

Width(w) = 25cm

Perimeter of a rectangle = 2(l + w)

Quadrant of circle cut away of each side of the rectangle :

Radius = 7 cm =

That is, the dimension of the triangle reduces by 2 * 7 = 14cm

New length = 30 - 14 = 16cm

New width = 25 - 14 = 11cm

The four corners =( 4 × 2πr ) / 4

2πr = 2 × 22/7 × 7 = 44cm

Perimeter = 2(16cm + 11cm)

= 2(27cm)

Perimeter = 54cm + 44 = 98cm

In a 30cm by 25cm rectangle, a quadrant of a circle of radius 7cm has been cut away from each corner.

is the force ratio fp/fe greater than 1, less than 1, or equal to 1? explain.

Answers

The force ratio fp/fe is equal to 1. This is because the unsigned charges of the proton and the electron are equal, and they experience the same electric field. The magnitude of the electric force experienced by a charged particle in an electric field at a position is equal to the product of the electric field and the unsigned charge of the particle.

F = qE

where

F is the force

q is the charge

E is the electric field

The proton and the electron have the same charge, so the magnitude of the force they experience is equal. The electric field is also the same, so the force ratio fp/fe is equal to 1.

fp/fe = q_p E / q_e E = 1

In other words, the force on the proton is equal to the force on the electron.

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I need help! anyone trynna help?

I need help! anyone trynna help?

Answers

Answer:

300 pascals

Explanation:

P=F/A

P=15N/0.05

P=300 pascals

Please help me. I have to submit this today.

Please help me. I have to submit this today.

Answers

B I think hope this helps

hey besties, im having a mental breakdown on this question. pls help :D
A tennis ball with a speed of 28.4 m/s is
moving perpendicular to a wall. After striking
the wall, the ball rebounds in the opposite
direction with a speed of 26.412 m/s.
If the ball is in contact with the wall for
0.0158 s, what is the average acceleration of
the ball while it is in contact with the wall?
Take “toward the wall” to be the positive
direction.
Answer in units of m/s
2

Answers

With "toward the wall" designated as the positive direction, the average acceleration felt the ball in the 0.0158 s of contact with the wall is

\(a_{\rm ave} = \dfrac{-26.412\frac{\rm m}{\rm s} - 28.4\frac{\rm m}{\rm s}}{0.0158\,\mathrm s} ≈ \boxed{-3470 \dfrac{\rm m}{\mathrm s^2}}\)

13. A 1.2 kg ball of clay is thrown horizontally with a speed of 2 m/s, hits a wall and sticks to it. The amount of energy
stored as thermal energy is
A) 0 J
B) 1.6 J
C) 2.4 J
D) Cannot be determined since clay is an inelastic material

Answers

The amount of energy stored as thermal energy is 2.4 J.

The correct option to the given question is option C.

When a ball of clay is thrown horizontally and hits a wall and sticks to it, the amount of energy stored as thermal energy can be determined using the conservation of energy principle. Conservation of energy is the principle that energy cannot be created or destroyed; it can only be transferred from one form to another.

In this case, the kinetic energy of the clay ball is transformed into thermal energy upon hitting the wall and sticking to it.

Kinetic energy is given by the equation  KE = 0.5mv²,

where m is the mass of the object and v is its velocity.

Plugging in the given values,

KE = 0.5 x 1.2 kg x (2 m/s)² = 2.4 J.

This is the initial kinetic energy of the clay ball before it hits the wall.

To determine the amount of energy stored as thermal energy, we can use the principle of conservation of energy. Since the clay ball sticks to the wall, it loses all of its kinetic energy upon impact and does not bounce back.

Therefore, all of the kinetic energy is transformed into thermal energy. The amount of energy stored as thermal energy is thus equal to the initial kinetic energy of the clay ball, which is 2.4 J.

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Forces and pres
4 A manometer is used to indicate the pressure in a steel
vessel, as shown in the diagram.
What value does the liquid manometer give for the pressure
in the vessel?
A It is zero.
B It is between zero and atmospheric pressure.
C It is equal to atmospheric pressure.
D It is greater than atmospheric pressure.
5 The diagrams show two mercury barometers standing side

Answers

Answer:

A.  It is zero.

Explanation:

D Later in the day, more power is developed in lifting each box. 12 A manometer is used to indicate the pressure in a steel vessel, as shown in the diagram. What value does the liquid manometer give for the pressure in the vessel? It is zero

upon what basic quantity does kinetic energy depend? size position force motion request answer part b upon what basic quantity does potential energy depend?

Answers

Kinetic energy depends on the mass and speed of an object, while potential energy depends on the position and arrangement of objects in a system.

Part A: Kinetic energy is the energy of motion, and it depends on the mass and velocity of an object, represented by the formula KE = 1/2mv², where KE is kinetic energy, m is the mass of the object, and v is the velocity. The greater the mass or velocity of the object, the greater its kinetic energy.

Part B: Potential energy, on the other hand, is energy stored in an object or a system due to its position or configuration. Potential energy depends on the position and arrangement of objects in a system, such as the height of an object above the ground or the distance between charged particles.

The formula for potential energy is PE = mgh, where PE is potential energy, m is the mass of the object, g is the acceleration due to gravity, and h is the height of the object above the reference point. Potential energy can also be stored in chemical bonds, as in the case of fuel molecules, and in elastic systems such as springs.

The complete question is:
Part A: Upon what basic quantity does kinetic energy depend?
-Force  -Position -Mass -Speed
Part B: Upon what basic quantity does potential energy depend?

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M= 1000 g g= 10 m/s2 h= 10 K.E at GROUND = 400 j M.E = ....... ........J the answer is 400 so plz explain how

Answers

Answer:

M = 500 J

Explanation:

Given that,

Mass, M = 1000 g = 1 kg

Height, h = 10 m

Potential energy is given by :

P = mgh

P = 1×10×10

P = 100 J

The kinetic energy at ground = 400 J

Mechanical energy = sum of kinetic and potential energy

So,

M = 100 + 400

M = 500 J

So, the mechanical energy of the system is 500 J.

Prove that acceleration=v/time

Answers

Answer:

Explanation:

Main Answer:

The equation acceleration = v/time can be proven using the fundamental definitions of acceleration, velocity, and time. Acceleration is defined as the rate of change of velocity, and velocity is the rate of change of displacement with respect to time. Let's consider an object moving with an initial velocity v0 and final velocity v in a time interval t.

Explanation:

The change in velocity, Δv, can be calculated as the final velocity minus the initial velocity, Δv = v - v0. Similarly, the change in time, Δt, is the final time minus the initial time, Δt = t - t0.

By substituting these values into the equation for acceleration, we have:

acceleration = Δv/Δt

Now, substituting Δv = v - v0 and Δt = t - t0, we get:

acceleration = (v - v0)/(t - t0)

Since v0 and t0 represent the initial velocity and time, respectively, we can rewrite the equation as:

acceleration = (v - v0)/t

By rearranging the equation, we find:

acceleration = v/t

Thus, we have proved that acceleration is equal to v/time.

Internal Link:

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1) A rock is dropped from a cliff with a height of 200 m. With what velocity will the rock hit the ground

could anyone help explain

1) A rock is dropped from a cliff with a height of 200 m. With what velocity will the rock hit the groundcould

Answers

A rock is dropped from a 200 m high cliff. How long does it take to fall (a) the first 100 m and (b) the last 50 m?

The basic equation you want is:

s=at22

Solving for t:

t=2sa−−−√

We’ll assume a=9.8 , so 2a−−√=14.9−−−√≈0.4518

So, for (a)s=100 , so t=0.4518100−−−√=4.518

The total time is 0.4518200−−−√≈6.389

The time to fall 150 m is 0.4518150−−−√≈5.533

So the time to fall the last 50 m is 6.389 - 5.533 = 0.856 seconds

(

The answer is in the attachment below:
1) A rock is dropped from a cliff with a height of 200 m. With what velocity will the rock hit the groundcould

Distance v. Time
What is the velocity at 1 meters?
4.5
4
3.5
3
2.5
Distance (m)
2.
1.5
1
0.5
0
0
2
6
8
10
Time (s)

Answers

Answer:

4

(m)

2 ( s )

Explanation:

ok...........

How would newtons laws of motion relate to the movement of bumper cars how might the mass of the riders and the speed of the cars affect this movement

Answers

Answer:

the law of interaction, says that if one body exerts a force on a second body, the second body exerts a force equal in magnitude and opposite in direction on the first body. It's the law of action-reaction, and it helps to explain why you feel a jolt when you collide with another bumper car.

Heavier cars have more momentum, so they travel further, given the same amount of friction.

Explanation:

What volume of silver metal will have a mass of exactly 2500.0 g? The density of silver is 10.50 g/cm3.

*Include your units!

Round your answer to the nearest tenth.

Answers

Explanation:

The density of silver is 10.5g/cm3

=2500.0g/10.5g/cm3

=238.09cm3

238.1cm3 to nearest tenth.

I hope my answer helps. Please mark as brainliest.

A 60.-kilogram physics student would weigh 1560
newtons on the surface of planet X. What is the
magnitude of the acceleration due to gravity on the
surface of planet X?

Answers

Answer:

26m/s²

Explanation:

Given parameters:

Mass of the student  = 60kg

Weight  = 1560N

Unknown:

Acceleration due to gravity  = ?

Solution:

Weight is a force on a body due to gravity;

  Weight  = mass x gravity

   

Insert the given parameters and solve;

    1560  = 60 x gravity

    Gravity  = \(\frac{1560}{60}\)   = 26m/s²

Asteroids move much slower and less frequently than stars. True False

it's false​

Answers

Answer:

false plz mark brainliest

Answer:
False for sure :)

two point masses m and m are separated by a distance d. if the separation d remains fixed and the masses are increased to the values 3m and 3m respectively, how does the gravitational force between them change?

Answers

When the masses of two point masses increase while the distance between them remains constant, the gravitational force between them increases proportionally to the square of the increase in mass.

What is gravitational force?

Gravitational force is the force of attraction between two masses. It is one of the four fundamental forces of nature and is responsible for the motion of celestial bodies, such as planets and stars, as well as the behavior of objects on the surface of the Earth.

The force of gravity between two masses can be described by Newton's law of universal gravitation, which states that every particle in the universe attracts every other particle with a force proportional to the product of their masses and inversely proportional to the square of the distance between them.

The formula for the gravitational force is given by Newton's law of universal gravitation:

F = G * (m1 * m2) / d^2

where:

F is the gravitational force between two masses

G is the gravitational constant (G = 6.67 x 10^-11 N m^2/kg^2)

m1 and m2 are the masses of the two objects

d is the distance between the centers of the two masses.

Calculation

The gravitational force between two point masses is given by the formula:

\(F = G * (m1 * m2) / d^2\)

where G is the gravitational constant and m1 and m2 are the masses of the two objects.

If the masses of the two point masses are increased from m to 3m, then the new formula for the gravitational force becomes:

\(F' = G * (3m * 3m) / d^2 = 9 * (G * (m * m) / d^2)\)

Thus, the gravitational force between the two point masses is increased by a factor of 9 when the masses are increased to 3m.

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The Sun has a mass of 1.99 x 10^30kg [^30 is an exponent] and is 1.5 x 10^11m [^11 is an exponent] from the earth. The planet Earth is 5.98 x 10^24kg [^24 is an exponent]. What is the gravitational attraction between the sun and the earth? G=6.67×10^-11 (-11 is an exponent)​

Answers

Answer:

F = G M m / R^2 = 6.67E-11 * 1.99E30 * 5.98E24 / (1.5E11)^2

F = 6.67 * 1.99 * 5.98 / 2.25 E21 Newtons

F = 3.53E22 N

How do you do binomial expansion on a calculator?

Answers

Binomial Expansion is a mathematical technique that involves expanding a given expression with two terms (binomial) raised to a power. It can be useful in solving complex mathematical problems, but finding the expansion of a binomial expression by hand can be time-consuming and error-prone.

Fortunately, modern calculators can help simplify this process by providing built-in functions for binomial expansion. The specific method for using a calculator to perform a binomial expansion will depend on the type of calculator you have, but here is a general explanation for how it can be done:

Make sure your calculator is in the correct mode: Before using your calculator for binomial expansion, you need to make sure it is in the correct mode. For most calculators, this is the "math" or "algebra" mode.

Choose the correct function: Most calculators have a function specifically designed for binomial expansion, often referred to as the "binomial theorem" or "nCr" function. This function calculates the individual terms of the binomial expansion.

Input the binomial expression: Enter the binomial expression you want to expand, including the power to which it is raised. For example, if you want to expand (a + b)^3, enter (a + b) and then "^" followed by the power, "3".

Use the binomial theorem function: Apply the binomial theorem function to the expression. This will give you the individual terms of the expansion.

Verify the expansion: Compare the expansion generated by your calculator to a known result or to a binomial expansion table to make sure the expansion is correct.

Note: Not all calculators have a built-in binomial theorem function, so you may need to use a different method or software to expand binomials.

In conclusion, using a calculator to perform a binomial expansion can save time and reduce the risk of calculation errors. The specific steps may vary depending on the type of calculator you have, but the general idea is to choose the correct function and input the binomial expression.

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The distance between 2 successive crests of a water travelling at 3.6m per second is 0.45m. calculate the frequency of the wave​

Answers

Answer:

8 hz

Explanation:

Wave Frequency = \(\frac{velocity}{wavelength}\)

\(F=\frac{3.6}{0.45} = 8\)

A cylinder in a steam engine contains 1.8kg of steam at 50 kPa and a volume of 0.200m^3.Heat is added to the steam, causing it to expand against a frictionless piston, until the temperature reaches 500 degrees celsius

Answers

The final volume of the steam is 0.8 m^3, which is an increase of four times the initial volume. This expansion is due to the heat added to the steam, causing the steam molecules to move faster and occupy a larger volume.

How to determine the inal state of the steam?

To determine the final state of the steam after it has been heated, we can use the ideal gas law, which states that PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature in kelvin.

We can use this equation to solve for the final volume of the steam after it has been heated to 500 degrees celsius. We can assume the steam is an ideal gas.

First, convert the initial temperature of 50 kPa to kelvin:

T1 = 50 + 273.15 = 323.15 K

Next, convert the final temperature of 500 degrees celsius to kelvin:

T2 = 500 + 273.15 = 773.15 K

The ideal gas constant R = 8.314 J/mol.K

We know the mass of steam is 1.8 kg, and we can use the molar mass of water, which is 18 g/mol, to calculate the number of moles of steam n = 1.8 kg / 18 g/mol = 0.1 mol.

Now we can use the ideal gas law to solve for the final volume of the steam, using the information we have:

P1V1 = nRT1

V1 = nRT1/P1 = 0.1 mol * 8.314 J/mol.K * 323.15 K / 50 kPa = 0.200 m^3

P2V2 = nRT2

V2 = nRT2/P2 = 0.1 mol * 8.314 J/mol.K * 773.15 K / 50 kPa = 0.8 m^3

The final volume of the steam is 0.8 m^3, which is an increase of four times the initial volume. This expansion is due to the heat added to the steam, causing the steam molecules to move faster and occupy a larger volume.

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A family goes on a road trip that is 500 km long. It takes the family 2 hours and 30 minutes to complete the trip. What was the family’s speed?
A) 2.17 km/h
B) 200 km/h
C) 1.33 km/h
D) 250 km/h

Answers

Answer:

d

Explanation:

30 minutes = 50 km/h * 5 =250km/h

A family goes on a road trip that is 500 km long. It takes the family 2 hours and 30 minutes to complete the trip. then the family’s speed is 200 km/hr. Hence option B is correct.

What is speed ?

Speed is a rate of change of distance with respect to time. i.e. v =dx÷dt. Speed can also be defined as distance over time i.e. speed= distance ÷ time it is denoted by v and its SI unit is m/s. it is a scalar quantity. i.e. it has only magnitude not direction. ( velocity is a vector quantity, it has both magnitude and direction. when we define velocity, we should know about its direction) Speed shows how much distance can be traveled in unit time. As speed is scalar quantity it has nothing to do with the direction. but when magnitude of speed is given and the direction as well, then we can say that a car or body is moving with this much speed at this direction(east, north, west, south).

Speed = distance/ time

Speed = 500 km/2.5hr

Speed = 200 km/hr

Hence option B is correct.

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A force of 10 lb is required to hold a spring stretched 2 in. beyond its natural length. How much work W is done in stretching it from its natural length to 7 in. beyond its natural length? W X ft-lb

Answers

The work done in stretching the spring from its natural length to 7 inches beyond its natural length is 112.5 ft-lb.

We are given a spring which is stretched beyond its natural length by 2 inches, by applying a force of 10 pounds.

We have to calculate the work done in stretching it further to 7 inches beyond its natural length, in ft-lb.

In order to calculate the work done, we need to know the spring constant (k) of the spring and then use the formula for work done by a spring, which is given by

W = (1/2)k(x2² - x1²)

Where, W is the work done, k is the spring constant, x1 is the initial position of the spring, and x2 is the final position of the spring.So, we need to find the spring constant k of the spring, in order to calculate the work done.Let the spring constant be k lb/inch.

We know that F = kx

where, F is the force applied, x is the displacement, and k is the spring constant.

Substituting the values, we get10 = k(2)k = 5 lb/inch.

Now, we can use the formula for work done, which is W = (1/2)k(x2² - x1²)

Substituting the values, we get W = (1/2)(5)(7² - 2²)W = (1/2)(5)(45)W = 112.5 ft-lb.

Therefore, the work done in stretching the spring from its natural length to 7 inches beyond its natural length is 112.5 ft-lb.

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Two people try to lift a heavy box. Jack pulls upward with a 100-newton
force. Jill pulls upward with a 50-newton force, but neither person moves the
box.
Compare the amount of work done on the box by Jack and Jill.
OA) Jack did twice as much work as Jill.
OB) Jack did fifty times more work than Jill.
OC) Jack and Jill did the same amount of work.​

Answers

Answer:

A ( Jack did twice as much work as Jill

Explanation:

Are mass and weight the same thing?
Yes
No

Answers

Answer:

Explanation:

Definitely NOT! Mass is unchanging, wherever you go. On the moon you will have the same mass as you will on the earth. Mass is just a measure of the matter that makes up a body. Weight, however, is dependent upon the pull of gravity which is different on earth than it is on the the moon, for example.

Mass doesn't change with proximity whereas weight can.

Answer: No

Explanation: The terms'mass' and 'weight' are frequently used interchangeably, yet they have distinct meanings. Your mass remains constant regardless of where you are in the universe; nevertheless, your weight varies. The mass of anything is a measure of how much power is required to change its course.

What will be the resistance Rstretched of the wire if it is stretched to twice its original length? Assume that the density and resistivity of the material do not change when the wire is stretched.

Answers

Answer:

Hence, the resistance of the stretched wire will be four times that of the original wire.

Explanation:

The resistance of a material is expressed as R = ρL/A

Volume of the original material V = Area * Length = A*L

ρ is the resistivity of the material

R is the resistance

A is the cross sectional area

L is the length of the wire.

If the wire is stretched o twice its original length then new length of the wire L₂ = 2L. Note that an increase in the length of wire will affect its area but its volume and density will not change.

This means V = V₂

A*L = = A₂*L₂

A*L = A₂*(2 L)

A = 2 A₂

A₂ = A/2

The new resistance of the material Rf = ρL₂/A₂

R₂ = ρ(2 L)/(A/2)

Rf =  2ρL * 2/A

Rf = 4(ρL/A)

Since R = ρL/A

R₂ = 4R

Hence, the resistance of the stretched wire will be four times that of the original wire.

If the wire is stretched to twice its original length, the new resistance would be quadrupled.

The resistance (R) of a wire is given by:

\(R=\rho\frac{L}{A} \\\\where\ L\ is\ length\ of\ wire, A\ is\ the\ cross\ sectional\ area\ and\ \rho\ \\is\ the\ resistivity\)

Since the wire is stretched, the new length (L₁) is twice its original length, hence:

L₁ = 2L

An increase in length affects the area, the new area (A₁) is:

initial volume = volume after stretch

AL = A₁L₁

AL = A₁(2L)

A₁ = A/2

The resistance of the stretched wire (R₁) is:

\(R_1=\rho\frac{L_1}{A_1} \\\\R_1=\rho\frac{2L}{A/2} \\\\R_1=4\rho\frac{L}{A}=4R\)

Therefore if the wire is stretched to twice its original length, the new resistance would be quadrupled.

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A flashlight is connected to a dry cell of voltage 3.50 V. It draws 20.0 ma (1000 ma = 1A) what is the resistance?

175 ohm

225 ohm

350 ohm

400 ohm

Answers

Answer:

175 ohm

Explanation:

i worked it on on a seprate sheet so its hard to explain

Answer:

a. 175

Explanation:

equation= R=V/I

R= resistance

V= voltage

I= current

so just substitute, R= 3.50/20.0

which is 0.175

all u need to do is 0.175 x 1000

which is 175

(the other person got it right i just wanted to show how it was done incase anyone wanted)

A power station that is being started up for the first time generates 6120 MWh of energy over a 10 hour period. (i) If the rated power at full capacity is 660 MW, calculate how long it takes the power station to reach its full power output. (You may assume a constant increase in power from zero to full power) (ii) State what type of power station can be started up fastest and explain why the start-up times for other types of power station are slower. Explain briefly, how this is relevant to optimising the usage of windfarms. c) What is the Bremsstrahlung effect and how can it be avoided in shielding design? d) Sketch the electromagnetic field output from an antenna, describing in detail the two main regions in the output field.

Answers

(i)Therefore, it takes approximately 9.27 hours to reach its full power output.(ii)It is necessary to have quick-start power sources, this helps maintain a stable and reliable electricity supply even when wind speeds fluctuate.(c)The Bremsstrahlung effect needs to be considered to ensure proper radiation protection.(d) The near-field region is characterized by strong electric and magnetic fields while the far-field region represents the radiation zone.

(i) To calculate the time it takes for the power station to reach its full power output, we can use the formula:

Energy = Power × Time

Given that the power station generates 6120 MWh of energy over a 10-hour period and the rated power at full capacity is 660 MW, we can rearrange the formula to solve for time:

Time = Energy ÷ Power

Converting the energy to watt-hours (Wh):

Energy = 6120 MWh × 1,000,000 Wh/MWh = 6,120,000,000 Wh

Converting the power to watt-hours (Wh):

Power = 660 MW × 1,000,000 Wh/MW = 660,000,000 Wh

Now we can calculate the time:

Time = 6,120,000,000 Wh ÷ 660,000,000 Wh ≈ 9.27 hours

Therefore, it takes approximately 9.27 hours (or 9 hours and 16 minutes) for the power station to reach its full power output.

(ii) The type of power station that can be started up fastest is a gas-fired power station. Gas-fired power stations can reach full power output relatively quickly because they use natural gas combustion to produce energy.

In contrast, other types of power stations, such as coal-fired or nuclear power stations, have longer start-up times. Coal-fired power stations require time to heat up the boiler and generate steam, while nuclear power stations need to go through a complex series of procedures to ensure safe and controlled nuclear reactions.

This is relevant to optimizing the usage of windfarms because wind power is intermittent and dependent on the availability of wind. This helps maintain a stable and reliable electricity supply even when wind speeds fluctuate.

(c) The Bremsstrahlung effect is a phenomenon that occurs when charged particles, such as electrons, are decelerated or deflected by the electric fields of atomic nuclei or other charged particles. As a result, they emit electromagnetic radiation in the form of X-rays or gamma rays.

In shielding design, the Bremsstrahlung effect needs to be considered to ensure proper radiation protection. These materials effectively absorb and attenuate the emitted X-rays and gamma rays, reducing the exposure of individuals to harmful radiation.

(d) The electromagnetic field output from an antenna can be represented by two main regions:

Near-field region: This region is closest to the antenna and is also known as the reactive near-field. It extends from the antenna's surface up to a distance typically equal to one wavelength. In the near-field region, the electromagnetic field is characterized by strong electric and magnetic field components.

Far-field region: Also known as the radiating or the Fraunhofer region, this region extends beyond the near-field region.The electric and magnetic fields are perpendicular to each other and to the direction of propagation.  The far-field region is further divided into the "Fresnel region," which is closer to the antenna and has some characteristics of the near field, and the "Fraunhofer region," which is farther away and exhibits the properties of the far-field.

The transition between the near-field and the far-field regions is gradual and depends on the antenna's size and operating frequency. The size of the antenna and the distance from it determine the boundary between these regions.

In summary, the near-field region is characterized by strong electric and magnetic fields, while the far-field region represents the radiation zone where the energy is radiated away as electromagnetic waves.

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While accelerating at a constant rate from 12.0 m/s to 18.0 m/s, a car moves over a distance of 60.0 m. how much time does it take?

Answers

While accelerating at a constant rate from 12.0 m/s to 18.0 m/s, a car moves over a distance of 60.0 m. The time taken by the car will be 4 seconds. the correct answer is option(c).

When acceleration is constant, the rate of change in velocity is also constant. In the absence of any acceleration, velocity remains constant. When acceleration is positive, velocity becomes more significant.

Let a denote acceleration, u denote initial velocity, v denote final velocity, and t denote time.

The equation of motion is stated as,

v = u + at

v² = u² + 2as

A car travels across a distance of 60.0 m while accelerating constantly from 12.0 m/s to 18.0 m/s.

Then the time taken by the car will be,

u = 12 m/s

v = 18 m/s

s = 60 m

Put these in the equation v² = u² + 2as.

18² = 12² + 2 x a x 60

a = 1.5

Then the time will be

18 = 12 + 1.5t

1.5t = 6

t = 4 seconds

Hence, the time taken is 4 s.

The complete question is:

While accelerating at a constant rate from 12.0 m/s to 18.0 m/s, a car moves over a distance of 60.0 m. How much time does it take?

1.00 s

2.50 s

4.00 s

4.50 s

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Katherine sped up to 65 miles per hour. Calculate this speed in meters per second.

Answers

Answer:

29.06 m/s

Explanation:

Explanation:

65 mi/hr × 1 hr/60 mins × 1 min/60 secs × 1 mi/1609.34m

The units hour, minutes, and miles cancel out. It's easier to notice when writing on paper versus typing.

Now multiple the numerators and divide by the denominators

Numerators: 65 × 1 × 1 × 1 = 65

Denominators: 1 × 60 × 60 × 1609.34 = 5793624

65 m ÷ 5793624 s = 0.0000112192 m/s

Round to appropriate sig figs

0.000011 m/s

This answer sounds wrong, but this is my thinking. Hopefully it helps in some way

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