Sean prepared 44 kilograms of dough after working 11 hours. How many hours did Sean work if he prepared 48 kilograms of dough? Assume the relationship is directly proportional.

Answer:

He used 20 ounces of the 10% alloy.

Step-by-step explanation:

Let x represent the number of ounces of alloy containing 10%

silver that was used.

Let y represent the number of ounces of alloy containing 40%

silver that was used.

The weight of the alloy made is 60 ounces. It means that

x + y = 60

The amount of silver contained in the first alloy is 10/100 × x = 0.1x

The amount of silver contained in the second alloy is 40/100 × x = 0.4x

The amount of silver contained in the mixture is 30/100 × 60 = 18

Therefore,

0.1x + 0.4y = 18- - - - - - - - - - - - -1

Substituting x = 60 - y into equation 1, it becomes

0.1(60 - y) + 0.4y = 18

6 - 0.1y + 0.4y = 18

- 0.1y + 0.4y = 18 - 6

0.3y = 12

y = 12/0.3

y = 40

x = 60 - 40

x = 20

Answer:

the second answer choice

Answer:

p^5 - p^3 r^2

Step-by-step explanation:

Answer:

so i got x=-3 i didnt get any signs in between

Step-by-step explanation:

Answer:

infinite solutions

4x+ 12 - 4 = 4x + 8

4x + 8 = 4x + 8

Step-by-step explanation:

look at the picture

*for the equation you can choose any of the two points

Answer:

Step-by-step explanation:

You would have to go up 2 and then go to your Left 5 .

You would have to go over to your right -1 and then go up 2

Answer:

from last question,

x = 25

25 + 15 = 40

The value of the integral C1 and C2 are below:

∫[C1] (y + x – 4ix³) dz = -1/2 + 4/3 i

∫[C2] (y + x – 4ix³) dz = 0

To evaluate the integral, we need to parameterize the given contour C and express it as a function of a single variable. Then we substitute the parameterization into the integrand and evaluate the integral with respect to the parameter.

Let's evaluate the integral along contour C1: the straight line from Z = 0 to Z = 1 + i.

Parameterizing C1:

Let's denote the parameter t, where 0 ≤ t ≤ 1.

We can express the contour C1 as a function of t using the equation of a line:

Z(t) = (1 - t) ×0 + t× (1 + i)

= t + ti, where 0 ≤ t ≤ 1

Now, we'll calculate the differential dz/dt:

dz/dt = 1 + i

Substituting these into the integral:

∫[C1] (y + x – 4ix³) dz = ∫[0 to 1] (Im(Z) + Re(Z) - 4i(Re(Z))³)(dz/dt) dt

= ∫[0 to 1] (t + 0 - 4i(0)³)(1 + i) dt

= ∫[0 to 1] (t + 0)(1 + i) dt

= ∫[0 to 1] (t + ti)(1 + i) dt

= ∫[0 to 1] (t + ti - t + ti²) dt

= ∫[0 to 1] (2ti - t + ti²) dt

= ∫[0 to 1] (-t + 2ti + ti²) dt

Now, let's integrate each term:

∫[0 to 1] -t dt = [-t²/2] [0 to 1] = -1/2

∫[0 to 1] 2ti dt = \(t^{2i}\)[0 to 1] = i

∫[0 to 1] ti² dt = (1/3)\(t^{3i}\) [0 to 1] = (1/3)i

Adding the results together:

∫[C1] (y + x – 4ix³) dz = -1/2 + i + (1/3)i = -1/2 + 4/3 i

Therefore, the value of the integral along contour C1 is -1/2 + 4/3 i.

Let's now evaluate the integral along contour C2: along the imaginary axis from Z = 0 to Z = i.

Parameterizing C2:

Let's denote the parameter t, where 0 ≤ t ≤ 1.

We can express the contour C2 as a function of t using the equation of a line:

Z(t) = (1 - t)× 0 + t × i

= ti, where 0 ≤ t ≤ 1

Now, we'll calculate the differential dz/dt:

dz/dt = i

Substituting these into the integral:

∫[C2] (y + x – 4ix³) dz = ∫[0 to 1] (Im(Z) + Re(Z) - 4i(Re(Z))³)(dz/dt) dt

= ∫[0 to 1] (0 + 0 - 4i(0)³)(i) dt

= ∫[0 to 1] (0)(i) dt

= ∫[0 to 1] 0 dt

= 0

Therefore, the value of the integral along contour C2 is 0.

In summary:

∫[C1] (y + x – 4ix³) dz = -1/2 + 4/3 i

∫[C2] (y + x – 4ix³) dz = 0

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Answer:

  -1

Step-by-step explanation:

"Gradient" is yet another term for "slope" or "rate of change." It is the ratio of "rise" to "run."

Here, the graph goes through grid intersections such that 1 to the right is 1 down. The "rise" is -1 for a "run" of 1, and the slop (gradient) is ...

  m = rise/run = -1/1 = -1

The gradient of the graphed line is -1.

Answer:

Step-by-step explanation:

Base is right triangle, so:

B = ¹/₂•4•6 = 12 mm²

H = 7 mm

V = ¹/₃•B•H

V = ¹/₃•12•7 = 4•7 = 28 mm³

Answer:

V=28 mm³

Step-by-step explanation:

V= volume of the pyramide

G = square of the triangle

h = high of the pyramide

V = 1/3 * G* h

G=1/2 *a*b

G = 1/2 * 6 * 4

G = 12

V= 1/3 *12*7

V=28 mm³

Answer:

Hopes this helps not sure rlly

Step-by-step explanation:

3,277.32

That Radius R = 9 mL = 3 mg = 9.8 m/sec²Density, p = 1005 kg/m³Work required to empty a full tank = 9.534 × 10⁷ J

A hemispherical tank is given with radius R = 9 m and it is filled with water. A spout is L = 3 m above the top of the tank. We have to find the work required to empty all the water out of the spout.Work done against gravity to empty the water in the tank = mgh.

Here, m = mass of the water in the tankg = gravitational constanth height from the top of the tank to the spoutWe need to find the mass of the water in the tank, then we can easily find the work done against gravity using above formula.To find the mass of water in the tank, we can use the formula of the volume of the hemispherical tank.V = 2/3 πr³

V = 2/3 × π × 9³

V = 2/3 × π × 729

V = 486 π cubic meters1

m³ = 1000 liters1 liter of

water = 1 kg of massWeight of water in the

tank = pVgWeight of water in the

tank = 1005 × 486 π × 9.8Weight of water in the

tank = 4.74 × 10⁶ π NewtonsThe height from the top of the tank to the spout is given as 3 m.The work done against gravity to empty the tank isW = mgh

W = (4.74 × 10⁶ π) × 3 × 9.8

W = 139.97 × 10⁶ π JThe work done against gravity to empty all the water from the tank through the spout is 139.97 × 10⁶ π J.The required work is 139.97 × 10⁶ π J.

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Answer:

5. x = 25.6

6. x = 11.0

7. x = 41.8°

8. x = 64.2°

9. x = 12.8°

10. x = 51.3°

Step-by-step explanation:

Let's find the x value for each triangle.

For point 5      

We have:

x: is the opposite cathetus to 52°  

20: is the adjacent cathetus to 52°  

52°: is the angle

We can find "x" with the following trigonometric function:

\( tan(52) = \frac{x}{20} \)

\( x = tan(52)*20 = 25.6 \)

For point 6      

We have:

x: is the hypotenuse  

5: is the opposite cathetus to the given angle  

27°: is the angle

To find "x" we need to use the trigonometric function:

\( sin(27) = \frac{5}{x} \)

\(x = \frac{5}{sin(27)} = 11.0\)

For point 7

We know:

x°: is the angle

6: is the hypotenuse

4: is the opposite cathetus to x°

Hence, x is:

\( sin(x) = \frac{4}{6} \)

\( x = sin^{-1}(\frac{4}{6}) = 41.8 \)

For point 8    

We have:

x°: is the angle

14: is the adjacent cathetus to x°

29: is the opposite cathetus to x°

To calculate "x" we need to use the trigonometric function tan(x):

\( tan(x) = \frac{29}{14} \)

\( x = tan^{-1}(\frac{29}{14}) = 64.2 \)

For point 9    

We have:

x°: is the angle

54: is the hypotenuse

12: is the opposite cathetus to x°

We can use sin(x) to solve for x:

\( sin(x) = \frac{12}{54} \)

\( x = sin^{-1}(\frac{12}{54}) = 12.8 \)

For point 10  

We have:

x°: is the angle

40: is the hypotenuse

25: is the adjacent cathetus to x°

We need to use cos(x) to solve for x:

\( cos(x) = \frac{25}{40} \)  

\( x = cos^{-1}(\frac{25}{40}) = 51.3 \)

I hope it helps you!

To solve the given questions, either of the trigonometric functions; sine, cosine and tangent of an angle has to be applied appropriately to either of the questions. The answers to the questions are:

5. x = 25.60

6. x = 11.00

7. x = \(41.8^{o}\)

8. x = \(64.2^{o}\)

9. x = \(12.8^{o}\)

10. x = \(51.3^{o}\)

The questions given are right angled triangles which requires the application of trigonometric functions appropriately. A right angle triangle is one that has one of its angles to be \(90^{o}\).

So, each of the questions can be solved as follows:

5. Tan θ = \(\frac{opposite}{adjacent}\)

Tan 52 = \(\frac{x}{20}\)

⇒  x = Tan 52 * 20

       = 25.5988

x = 25.60

6. Sin θ = \(\frac{opposite}{hypotenuse}\)

Sin 27 = \(\frac{5}{x}\)

⇒ x = \(\frac{5}{Sin 27}\)

       = 11.0134

x = 11.00

7. Sin θ = \(\frac{opposite}{hypotenuse}\)

Sin x = \(\frac{4}{6}\)

        = 0.66667

x = \(Sin^{-1}\) 0.66667

  = \(41.8^{o}\)

x = \(41.8^{o}\)

8. Tan θ = \(\frac{opposite}{adjacent}\)

Tan x = \(\frac{29}{14}\)

          = 2.0714

x = \(Tan^{-1}\) 2.0714

  = \(64.2^{o}\)

x = \(64.2^{o}\)

9. Sin θ = \(\frac{opposite}{hypotenuse}\)

Sin x = \(\frac{12}{54}\)

        = 0.22222

x = \(Sin^{-1}\) 0.22222

  = \(12.8^{o}\)

x = \(12.8^{o}\)

10. Cos θ = \(\frac{adjacent}{hypotenuse}\)

Cos x = \(\frac{25}{40}\)

         = 0.625

x = \(Cos^{-1}\) 0.625

  = \(51.3^{o}\)

x = \(51.3^{o}\)

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Step 1:

Given data

The average mass of a cow = 410 kg

Step 2:

To find the mass of 150 cows, you will multiply 150 cows by 410 kg.

Therefore

Final answer

Write the total weight in scientific notation

Outlet A sold the greatest number of copies of album x in July and August

The tables of values are given as:

July

Album X Album Y Album Z

Outlet A 14 8 6

Outlet B 7 13 4

Outlet C 2 11 1

August

Album X Album Y Album Z

Outlet A 12 14 10

Outlet B 5 12 8

Outlet C 16 12 7

In July, the total sales of album x are:

Outlet A  = 14

Outlet B = 7

Outlet C = 2

In August, the total sales of album x are:

Outlet A  = 12

Outlet B = 5

Outlet C = 16

Add both sales

A = 14 + 12 = 26

B = 7 + 5 = 12

C = 2 + 16 = 18

26 (in outlet A) is greater than 12 and 18

Hence, outlet A sold the greatest number of copies of album x in July and August

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Answer:

Outlet D

Step-by-step explanation:

they sold 28 of album x

outlet a only sold 26

Answer: 3902.4633

Step-by-step explanation: 3902.46 from deltamath

Answer:

the number is 49

Step-by-step explanation:

please mark me brainly please!!!

Answer: The first answer choice

AKA: y = -1.74x + 46.6

Step-by-step explanation:

Answer: No, your friend is not correct. If the problem was addition, then yes it would equal the same answer, but with subtraction, the answers will be different.

Step-by-step explanation:

Answer:

I am assuming the 8:15 was a typo and was actually supposed to be a 8:14. Anyways, they are equivalent because they all make 4:7 when simplified.

Step-by-step explanation:

4:7 = itself at this point, as they don't have numbers that can simplify each other on both sides, unless you are looking for a decimal answer.

8:14 = 4:7 <- You can divide the 8 and 14 by two. 8 divided by 2 is four, and 14 divided by 2 is 7.

16:28 = 4:7 <- You can divide the 16 and the 28 by four. 16 divided by 4 is 4, and 28 divided by 4 is 7.

20:35 = 4:7 <- You can divide both sides by 5. 20 divided by 5 is 4, and 35 divided by 5 is 7.

Since 3n² + 6n is both O(n² log n) and Ω(n² log n), we can conclude that it is indeed Θ(n² log n).

To prove that 3n² + 6n is in Θ(n² log n), we need to show both the upper and lower bounds.

First, we will prove the upper bound by showing that 3n² + 6n is O(n² log n). This means we need to find constants c and n₀ such that 3n²+ 6n ≤ c(n² log n) for all n ≥ n₀.

Let's simplify the expression 3n² + 6n:

3n² + 6n ≤ 3n² + 6n² (for n ≥ 1, since n is always positive)

            = 9n²

Now, we can set c = 9 and n₀ = 1. For all n ≥ 1:

3n² + 6n ≤ 9n² (which is the same as c(n²))

           ≤ 9n² log n

Therefore, we have shown that 3n² + 6n is O(n² log n), satisfying the upper bound.

Next, we will prove the lower bound by showing that 3n² + 6n is Ω(n² log n). This means we need to find constants c and n₀ such that 3n²+ 6n ≥ c(n² log n) for all n ≥ n₀.

Let's simplify the expression 3n² + 6n:

3n² + 6n ≥ 3n² (for n ≥ 1, since n is always positive)

            = 3n² log n

Now, we can set c = 3 and n₀ = 1. For all n ≥ 1:

3n² + 6n ≥ 3n² log n (which is the same as c(n² log n))

Therefore, we have shown that 3n² + 6n is Ω(n² log n), satisfying the lower bound.

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The width of the interval would be = Wider

The probability of making an error will be = Smaller

According to the question,

The actual interval to be constructed = 90%

The interval constructed otherwise = 95%

The formula for the width of the confidence interval will be,

W = 2 x CV x \(\frac{\alpha }{\sqrt{n} }\)

Considering,

n = sample size

\(\alpha\) = standard deviation

CV = critical value

Considering the below table,

Confidence level z,

    90%           1.64

    95%           1.96

    99%           2.58

So the confidence level of 95% will be more than 90%.

Therefore,

The width of the interval would be = Wider

The probability of making an error will be = Smaller

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Answer:

$2,202

Step-by-step explanation:

If the car decreases in value 20% per year, that means that the car is only worth 80% of its value for the next year.

80% can be written as .80.

Multiply the value of the car by .80 6 times.

8400 multiplied by .80 = 6720

6720 multiplied by .80 = 5376

repeat this sequence 4 more times to come to an answer of 2,202

Answer:

Mary would have to work 5 hours to afford a mobile phone.

Step-by-step explanation:

$15-$4.25= $10.75 that Mary would need to save.

2.15 x 5= 10.75

Answer:

\( \huge{ \boxed{ \bold{ \tt( \: 0 \: ,5 \: )}}}\)

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☞ First, Let's explore about Midpoint :

Midpoint of the segment simply means middle point of a line segment. Formula of Midpoint :

\( \boxed{ \sf{(x _{ \: m \: } ,\: y_{m}) = ( \frac{x_{1} + x_{2}}{2} ,\: \frac{y_{1} + y_{2}}{2} )}}\)

where ,

The Midpoint Formula is used to find the exact center point between two defined points in a line segment.  The Midpoint formula is quite simple , so you should easily be able to remember it. It won't matter which point you pick to be the 'first" point you plug in. Just make sure that you're adding both an x to an x and a y to a y. Hence, keep in mind , in order to find the midpoint of a line segment, the first step is to add both ' x - co-ordinates' and divide it by 2 and then the second step is to add both ' y - co-ordinates ' and divide it by 2.

Now, Let's solve it!

☯ Question :

☯ Step - by - step explanation :

Let P ( x , y ) divide the line joining the points A ( - 2 , 7 ) and B ( 2 , 3 ). Now, let :

Apply midpoint formula , then plug the values and lastly simplify it :

\( \sf{ midpoint \: = \: ( \frac{x _{ \: 1 \: } + x _{ \: 2 \: }}{2} ,  \: \frac{y_{ \: 1 \: } + y _{ \: 2\: }}{2} })\)

➺ \( \sf{midpoint = ( \frac{ - 2 + 2}{2},  \: \frac{7 + 3}{2} )}\)

➺ \( \sf{midpoint = ( \frac{0}{2} ,  \: \frac{10}{2} )}\)

➺ \( \boxed{ \sf{ midpoint = ( \: 0 \: , 5})}\)

Hence , The midpoint of the segment with the end points A ( - 2 , 7 ) and B ( 2 , 3 ) is ( 0 , 5 ) .

Hope I helped!

Have a wonderful time ッ

~TheAnimeGirl ♡

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Answer:

C

Step-by-step explanation: