Sean is drinking a slushy as fast as he can. The amount of slushy left in the cup (in milliliters) as a function of time (in seconds) is graphed. How long did it take Sean to finish the slushy?

______ seconds ​

Answer:

B) (6, 17)

Step-by-step explanation:

y = 3x - 1

To find a solution to the equation

Let x = 6

y = 3*6 -1

y = 18-1

y = 17

One possible solution is ( 6,17)

This is choice B

From the given information, total surplus in a market is equal to the sum of consumer surplus and producer surplus.

Consumer surplus is the difference between the highest price a consumer is willing to pay for a good or service (the "reservation price") and the actual price they pay. Producer surplus is the difference between the lowest price a producer is willing to accept for goods or services and the actual price they receive.

When a market is in equilibrium, the price and quantity are such that the quantity demanded equals the quantity supplied. At this point, total surplus is maximized, since all trades that benefit both consumers and producers have taken place. The total surplus represents the net benefit to society from the production and consumption of the good or service in the market.

In other words, total surplus is the sum of the gains from trade that accrue to consumers and producers in the market, and it represents the difference between the value that buyers and sellers place on the good or service and the resources that were actually used to produce it.

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Hi there!

\(\huge\boxed{-10}\)

f(x) = -2x - 3

Plug in 0 for "x" to solve for f(0):

f(0) = -2(0) - 3

f(0) = -3

Since the question is asking you to evaluate f(0) - 7, simply subtract:

-3 - 7 = -10.

Randy needs 8 loads.

To find the answer on the question we have to follow the method of multiplication and division .

A washing machine can hold \(\frac{3}{4}\) kg of laundry in each load.

\(\frac{3}{4}\) kg of laundry is equal to 1 load.

\(\frac{3}{4}\) kg of laundry =  1 load

1 kg of laundry  =  \(\frac{1 * 4}{3}\) load ( following the method of division )

1 kg of laundry = \(\frac{4}{3}\) load

Randy has 6kg of laundry.

So, 1kg of laundry i.e \(\frac{4}{3}\) load is to be multiplied by 6.

6kg of laundry = \(\frac{4 * 6}{3}\) load ( following the method of multiplication)

                         = 8 loads

Hence, Randy needs 8 loads.

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The negative correlation coefficient of -0.73 between consumption of vitamin A and the cancer rate of a particular type of cancer suggests that as vitamin A consumption increases, the cancer rate tends to decrease.

A correlation coefficient measures the strength and direction of the linear relationship between two variables.

In this case, a correlation coefficient of -0.73 indicates a negative correlation between consumption of vitamin A and the cancer rate.

Interpreting this correlation, it can be inferred that there is an inverse relationship between the two variables. As consumption of vitamin A increases, the cancer rate tends to decrease.

However, it is important to note that correlation does not imply causation.

It would be incorrect to conclude that consuming more vitamin A causes this type of cancer. Correlation does not provide information about the direction of causality.

Other factors and confounding variables may be involved in the relationship between vitamin A consumption and cancer rate.

To establish a causal relationship, further research, such as experimental studies or controlled trials, would be necessary. These types of studies can help determine whether there is a causal link between vitamin A consumption and the occurrence of this particular cancer.

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Answer:

6x+9

(2x+3)3

you would distribute 3 into 3 and 2x to get...

6x+9

Therefore, the partial derivatives are: ∂f/∂x = 12xy^2 log(x^2 y^2), ∂f/∂y = 12x^2y log(x^2 y^2).

To find the partial derivatives ∂f/∂x and ∂f/∂y of the given function f(x, y) = 3(x^2 y^2) log(x^2 y^2), we differentiate the function with respect to x and y, treating the other variable as a constant.

∂f/∂x:

We use the product rule and the chain rule to differentiate f(x, y) with respect to x:

∂f/∂x = 3(2xy^2 log(x^2 y^2)) + 3(x^2 y^2)(1/x)(2xy^2) log(x^2 y^2)

= 6xy^2 log(x^2 y^2) + 6xy^2 log(x^2 y^2)

= 12xy^2 log(x^2 y^2)

∂f/∂y:

Again, we use the product rule and the chain rule to differentiate f(x, y) with respect to y:

∂f/∂y = 3(x^2)(2y log(x^2 y^2)) + 3(x^2 y^2)(1/y)(2y) log(x^2 y^2)

= 6x^2y log(x^2 y^2) + 6x^2y log(x^2 y^2)

= 12x^2y log(x^2 y^2)

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Answer:

47°

Step-by-step explanation:

92-45=47

No, we would not expect about 95% of the samples to have their variances within 0.008 of 0.009.

The variance of a normal distribution with mean μ and variance σ^2 is given by σ^2, which in this case is equal to (0.004)^2 = 0.000016.

The variance of the sample means, on the other hand, is given by σ^2/n, where n is the sample size. In order for about 95% of the samples to have variances within 0.008 of 0.009, we would need the sample size to be approximately equal to:

n ≈ σ^2 / (0.008 - 0.009)^2 = 62500

This means that we would need very large samples for this to be true. However, if the sample size is relatively small, then the distribution of sample means will not necessarily be normal and the Central Limit Theorem may not apply.

In that case, the distribution of sample variances will not necessarily follow the same pattern as the distribution of the population variance, and it may not be possible to make predictions about the sample variances based on the population parameters.

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Answer:

Miracle can cut 3 small rectangles from large rectangular piece of paper.

Step-by-step explanation:

We are given that

Area of rectangular piece of paper=\(0.15 m^2\)

Area of small rectangular piece of paper=\(500 cm^2\)

We have to find the maximum number of rectangles she can cut .

We know that

\(1 cm^2=\frac{1}{10000}m^2\)

Using the value then we get

\(500 cm^2=\frac{500}{10000}=0.05 m^2\)

Now,  number of small rectangles can be cut

=\(\frac{Area\;of\;large\;rectangle}{Area\;of\;small\;rectangle}\)

Number of small rectangles can be cut =\(\frac{0.15}{0.05}\)

Number of small rectangles can be cut =3

Hence, Miracle can cut 3 small rectangles from large rectangular piece of paper.

The specific gravity of the combined product is 1.22

Specific gravity is the ratio of the density of a substance to the density of some substance (such as pure water) taken as a standard when both densities are obtained by weighing in air.

Given,

The total quantity of portion= 50 ml

Specific gravities of the three syrups = 1.10,1.25 and 1.32

Then,

The specific gravity of the combined product= \(\frac{1.10+1.25+1.32}{3}\)

= 1.22

Hence, the specific gravity of the combined product is 1.22.

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Answer:

2

Step-by-step explanation:

Answer:

y=100x+25

Step-by-step explanation:

I'm assuming you need an equation for this.

the answer is y = 100x + 25 or 25(4x+1)

Answer:

The right option is option e.T-shaped.

Step-by-step explanation:

The molecular geometry or shape of clf3 is T-shaped. It acquires such shape because of presence of two lone pairs which take equatorial position and there are greater repulsions. The hybridisation is sp3d and it has 2 lone pairs

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Option e) T-shaped

The shape or molecular geometry  of ClF₃ is T-shaped. It acquires such a shape due to the presence of two lone pairs in the equatorial position and has greater repulsion. The hybrid is sp³d and it has 2 lone pairs.

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The parameter estimate is statistically different from zero when the absolute value of the t-statistic is greater than the critical value associated with the desired level of significance.

In hypothesis testing, the t-statistic is calculated by dividing the parameter estimate by its standard error. The t-statistic measures the number of standard errors the parameter estimate is away from the null hypothesis value (usually zero).

If the absolute value of the t-statistic is greater than the critical value, it means that the parameter estimate is significantly different from zero at the chosen level of significance. In other words, there is evidence to reject the null hypothesis and conclude that the parameter is not equal to zero.

The specific critical value depends on the desired level of significance and the degrees of freedom associated with the t-distribution. If the absolute value of the calculated t-statistic exceeds the critical value, it indicates that the parameter estimate is statistically significant and significantly different from zero.

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A. The probability that one selected subcomponent is longer than 122 cm can be found by calculating the area under the normal distribution curve to the right of 122 cm. We can use the z-score formula to standardize the value and then look up the corresponding probability in the standard normal distribution table.

z = (122 - μ) / σ = (122 - 100) / 5.6 = 3.93 (approx.)

Looking up the corresponding probability for a z-score of 3.93 in the standard normal distribution table, we find that it is approximately 0.9999. Therefore, the probability that one selected subcomponent is longer than 122 cm is approximately 0.9999 or 99.99%.

B. To find the probability that the mean length of three randomly selected subcomponents exceeds 122 cm, we need to consider the distribution of the sample mean. Since the sample size is 3 and the subcomponent lengths are normally distributed, the distribution of the sample mean will also be normal.

The mean of the sample mean will still be the same as the population mean, which is 100 cm. However, the standard deviation of the sample mean (also known as the standard error) will be the population standard deviation divided by the square root of the sample size.

Standard error = σ / √n = 5.6 / √3 ≈ 3.24 cm

Now we can calculate the z-score for a mean length of 122 cm:

z = (122 - μ) / standard error = (122 - 100) / 3.24 ≈ 6.79 (approx.)

Again, looking up the corresponding probability for a z-score of 6.79 in the standard normal distribution table, we find that it is extremely close to 1. Therefore, the probability that the mean length of three randomly selected subcomponents exceeds 122 cm is very close to 1 or 100%.

C. If we want to find the probability that all three randomly selected subcomponents have lengths exceeding 122 cm, we can use the probability from Part A and raise it to the power of the sample size since we need all three subcomponents to satisfy the condition.

Probability = (0.9999)^3 ≈ 0.9997

Therefore, the probability that if three subcomponents are randomly selected, all three of them have lengths that exceed 122 cm is approximately 0.9997 or 99.97%.

Based on the given information about the normal distribution of subcomponent lengths, we calculated the probabilities for different scenarios. We found that the probability of selecting a subcomponent longer than 122 cm is very high at 99.99%. Similarly, the probability of the mean length of three subcomponents exceeding 122 cm is also very high at 100%. Finally, the probability that all three randomly selected subcomponents have lengths exceeding 122 cm is approximately 99.97%. These probabilities provide insights into the performance of the automatic machine in terms of producing longer subcomponents.

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Step-by-step explanation:

5miles=8km

so, x miles=32km

8x=160

x= 160÷8

=20miles

Answer:

I'm not completely sure, but I hope this helps.

Answer:

355.68

Step-by-step explanation:

741 x 0.48 = 355.68

To complete the proof, we need to provide reasons for each statement. Here is a step-by-step explanation:

Proof:
Statements                              Reason
a. LK ≅ NM, KJ ≅ MJ               a. Given
b. LK + KJ = NM + MJ              b. Segment Addition Postulate (Def. of congruent segments)
c. LK + KJ = NJ                          c. Substitution Property of Equality (NK ≅ NJ)
d. LK + KJ = LJ + KJ                 d. Substitution Property of Equality (LJ ≅ LJ)
e. LK = LJ                                      e. Subtraction Property of Equality
f. LJ = NJ                                      f. Substitution Property of Equality

Explanation:
a. We are given that LK is congruent to NM and KJ is congruent to MJ.
b. By the Segment Addition Postulate, the sum of LK and KJ is equal to the sum of NM and MJ.
c. Since NK is congruent to NJ (LJ ≅ NJ), we can substitute NJ for NK.
d. Since LJ is congruent to LJ (reflexive property of congruence), we can substitute LJ for LJ.
e. By the Subtraction Property of Equality, we can subtract KJ from both sides of the equation to isolate LK.
f. Finally, by the Substitution Property of Equality, we can replace LJ with NJ, as LK is congruent to NJ.

Therefore, we have proved that LJ is congruent to NJ.

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Considering that the data has no outliers, the mean of 1.8 inches should be used to describe the center of the data represented in this line plot.

It depends if the data-set has outliers or not:

- If it does not have outliers, the mean should be used.

- If it has, the median should be used.

The dot plot gives the number of times each measure appears. Since there is no outliers, that is, all values are close, the mean should be used. It is given by:

Mean = [(3 * 0) + (3 * 1) + (1 * 2) + (1 * 3) + (1 * 4) + (1 * 6)]/(3 + 3 + 1 + 1 + 1 + 1)

Mean = 18/10

Mean = 1.8

The mean of 1.8 inches should be used to describe the center of the data represented in this line plot.

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Answer:

90

Step-by-step explanation:

Answer: 17

Step-by-step explanation:

Step 1.) Vertical angles are opposite angles. That would mean that 120=4k+52

Step 2.) Now that you have the equation, 120=4k+52, you must isolate k.

Step 3.) First subtract 52 from both sides. 120-52=4k-52. That would get you 68=4k.

Step 4.) The final step would be to divide both sides by 4 in order to isolate k. 68/4=4k/4. That would get you 17=k or k=17.

Therefore, the answer is 17 degrees.

3/2=1.5 hour=5400 second

Hope it helps you

Answer:

5,400 seconds.

we have shown that cos 2x tan x = 2 sin x cos x sin x tan x for all values of x.

How to solve the question?

To prove that cos 2x. tanx = 2 sin x cos x sin x tanx for all values of x, we can start with the following trigonometric identities:

cos 2x = cos²x - sin² x (1)

tan x = sin x / cos x (2)

Substituting equation (2) into the right-hand side of the expression to be proved, we get:

2 sin x cos x sin x tan x = 2 sin²x cos x / cos x

= 2 sin² x

Using equation (1), we can express cos 2x in terms of sin x and cos x:

cos 2x = cos² x - sin² x

= (1 - sin²x) - sin²x

= 1 - 2 sin²x

Substituting this into the left-hand side of the expression to be proved, we get:

cos 2x tan x = (1 - 2 sin² x) sin x / cos x

= sin x / cos x - 2 sin³ x / cos x

Using equation (2), we can simplify the first term:

sin x / cos x = tan x

Substituting this back into the previous equation, we get:

cos 2x tan x = tan x - 2 sin³ x / cos x

We can then multiply both sides by cos x to eliminate the denominator:

cos 2x tan x cos x = sin x cos x - 2 sin³x

Using the double-angle identity for sine, sin 2x = 2 sin x cos x, we can rewrite the left-hand side:

cos 2x sin x = sin 2x / 2

Substituting this and simplifying the right-hand side, we get:

sin 2x / 2 = sin x cos x - sin³x

= sin x (cos x - sin² x)

Finally, using equation (1) to substitute cos²x = 1 - sin²x, we get:

sin 2x / 2 = sin x (2 sin²x - 1)

= sin x (2 sin² x - sin²x - cos²x)

= sin x (sin² x - cos² x)

= -sin x cos 2x

Therefore, we have shown that cos 2x tan x = 2 sin x cos x sin x tan x for all values of x.

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The ending balance in accumulated other comprehensive income on December 31, 2019, is $10,200 (credit balance).

To determine the ending balance in accumulated other comprehensive income on December 31, 2019, we need to analyze the changes in comprehensive income and other comprehensive loss. The net income of $12,000 and other comprehensive loss of $3,000 (net of tax) for the year ended December 31, 2020, indicate that the comprehensive income for the year is $9,000 ($12,000 - $3,000).

The ending balance in accumulated other comprehensive income can be calculated by adding the comprehensive income for the year to the beginning balance in accumulated other comprehensive income. Given that the ending balance on December 31, 2020, is $6,800 (credit balance), we can derive the beginning balance in accumulated other comprehensive income on December 31, 2019, by subtracting the comprehensive income for the year ($9,000) from the ending balance on December 31, 2020. Therefore, the ending balance in accumulated other comprehensive income on December 31, 2019, is $10,200 (credit balance).

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ok

1.- Convert 1 m to mm

1 m ------------------ 100 cm 10 mm ------ 1 cm

there are 10 x 100 = 1000 mm in a meter

2.- Convert 35 cm into mm

10 mm -------------- 1 cm

x -------------- 35 cm

x = (35 x 10) / 1

x = 350 mm

3.- Total = 1000 + 350 = 1350 mm

The answer is H. 1350 mm

If Armer Brown used and equal number of each bag then there will be 21 bags.

What is algebraic expression?

When we use numbers and words to solve a mathematical problem, we are using algebraic expressions.

Let's say that Armer Brown used x bags holding 20 oranges, y bags holding 10 oranges, and z bags holding 5 oranges. We know that he harvested 245 oranges, so we can write an equation:

20x + 10y + 5z = 245

We also know that he used an equal number of each bag, so we can write another equation:

x = y = z

We can use the second equation to substitute y and z with x:

20x + 10x + 5x = 245

Simplifying this equation, we get:

35x = 245

Dividing both sides by 35, we get:

x = 7

So he used 7 bags holding 20 oranges, 7 bags holding 10 oranges, and 7 bags holding 5 oranges.

In total, he used: 7 + 7 + 7 = 21 bags.

Therefore, There will be 21 bags.

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