[SCREENSHOT INCLUDED] Which of the following is the best estimate of f '(2) based on this table of values?

when two angles are complementary, we can find the measure of one angle by subtracting the measure of the other angle from 90 degrees. In this case, if one angle measures 49.0 degrees, the other angle measures 41.0 degrees.

When two angles are complementary, it means that the sum of their measures is equal to 90 degrees. In this case, if one of the angles is given as 49.0 degrees, we can find the measure of the other angle by subtracting the given angle from 90 degrees.

To calculate the measure of the other angle, we subtract 49.0 degrees from 90 degrees. This can be done by taking away 49.0 degrees from the whole 90 degrees.

Subtracting 49.0 degrees from 90 degrees gives us 41.0 degrees.

So, the measure of the other angle is 41.0 degrees.

In summary, when two angles are complementary, we can find the measure of one angle by subtracting the measure of the other angle from 90 degrees. In this case, if one angle measures 49.0 degrees, the other angle measures 41.0 degrees.

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The value of p is equal to 76 when q is equal to 4

Given :

If p is inversely proportional to the square of q

when y is inversely proportional to x then \(y=\frac{k}{x}\)

given that p is inversely proportional to the square of q. the equation becomes

\(p=\frac{k}{q^2}\)

when p is 19 the value of a is 8

Replace the values and find out q

\(p=\frac{k}{q^2}\)

\(22=\frac{k}{8^2}\)

\(22=\frac{k}{64}\)

Multiply both sides by 64

k=1216

Now we find out p when q is 4

Replace k value and q value to find out p

\(p=\frac{k}{q^2}\)

\(p=76\)

The value of p is equal to 76 when q is equal to 4

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Answer:

P = 88.

Step-by-step explanation:

P = k/q^2

22 = k/ 8^2

k = 22 * 64 = 1408.

So P = 1408/q^2

When q = 4:

P = 1408/4^2

q = 88

The Matlab & Simulink model consists of a Clock block to generate a time signal, a Gain block to multiply the time signal by 2, and a Differential Equation block to solve the given differential equation. The Scope block is used to visualize the behavior of the variable x over time.

To construct a Matlab & Simulink model for the given mathematical model, we can use Simulink's Differential Equation block and a Clock and Gain block. Here's a step-by-step guide:

1. Open Simulink in Matlab.

2. Drag and drop a Clock block from the Simulink Library Browser into the model.

3. Drag and drop a Gain block from the Simulink Library Browser into the model.

4. Double-click on the Gain block and set the Gain value to 2.

5. Drag and drop a Differential Equation block from the Simulink Library Browser into the model.

6. Double-click on the Differential Equation block and enter the equation `d²x + 3 + 4*x + 6 = 5*cos(2*t)`.

7. Connect the output of the Clock block to the input of the Gain block, and the output of the Gain block to the input of the Differential Equation block.

8. Connect the output of the Differential Equation block to a Scope block from the Simulink Library Browser.

9. Run the simulation.

The Scope block will show the behavior of the value of x over time according to the given mathematical model.

In conclusion, The Clock block provides the independent variable t, and the Differential Equation block evaluates the given equation to compute the value of x. The simulation shows the dynamic response of x as influenced by the equation and the time signal.

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Answer:

56 i think

Step-by-step explanation:

8 × 4

4 × 6

then add them together

Answer:

56 un²

Step-by-step explanation:

10 un × 8 un = 80 un²

10 un - 4 un = 6 un

8 un - 4 un = 4 un

6 un × 4 un = 24 un²

80 un² - 24 un² = 56 un²

Answer:

ready-steady paint

Step-by-step explanation:

if he needs 12 tins, and purchased from paint -O  mine, he would spend (12/3) X 7.50 = 4 x 7.50 = £30

from ready steady, he can buy 4 for £11. he needs 12.

so he will spend (12/4) X 11 = 3 X 11 = £33. but he can get 15% off. 15% off is the same as multiplying by 0.85.

33 X 0.85 = £28.05.

so he his better purchasing from ready steady paint

ANSWER:

The cosine and sine values are reversed.

STEP-BY-STEP EXPLANATION:

We can rewrite the function as follows:

In this case, then it would be:

What it means is that the error was that it was wrong when calculating the cosine and the sine, it has the values inverted

The answer to this question is less coping strategies.

What are coping strategies?

Coping strategies are ways through which an individual gains some control over their emotions

Yes research has proved that the   Younger adults use more coping strategies than Older adults because now a days so methods for coping strategies like Cigerrate, alcohol, drugs etc things are easily being available to them and they use that to overcome their emotions

where as older adults have already seen most of their life so they are less likely to use these things to overcome their emotions

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The slope of the equation is 25 and it represents a monthly membership charge and the y-intercept of the equation is 50 and it represents the charges of a one-time fee for a gym.

A gym charges a one-time fee of $50 and a monthly membership charge of $25 the total cost c of being a member of the gym is given by

c (t) = 50 + 25t

where c is the total cost you pay after being a member for t months.

The slope of the equation is 25 and it represents a monthly membership charge.

The y-intercept of the equation is 50 and it represents the charges of a one-time fee for a gym.

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Step-by-step explanation:

please complete your question

To convert 4 hours and 45 minutes to a fraction, we need to first convert the minutes to hours by dividing by 60 and then add the result to the 4 hours.

4 hours and 45 minutes = 4 + 45/60 hours = 4 + 0.75 hours

Now, we can write this as a fraction by expressing the decimal part as a fraction:

4 + 0.75 = 4 + 3/4 = (4*4 + 3)/4 = 19/4

Therefore, 4 hours and 45 minutes is equal to 19/4 when expressed as a fraction in simplest form.

The answer is (B) 4 3/4.

Answer:

3

Step-by-step explanation:

Answer:

1/2

Step-by-step explanation:

cotangent is the reciprocal of a tangent

tanθ = 2

cotθ = 1/2

The solution to the equations are x = 3 and no solution in the set, respectively

Question 1

The equation is given as:

5x - 6 = 9

The replacement set is given as

{0,1, 2, 3, 4}

So, we replace the variables using the elements in the replacement set

When x = 0, we have

5(0) - 6 = 9

- 6 = 9 -- false

When x = 1, we have

5(1) - 6 = 9

- 1 = 9 -- false

When x = 2, we have

5(2) - 6 = 9

4 = 9 -- false

When x = 3, we have

5(3) - 6 = 9

9 = 9 -- true

Hence, the value of the equation is x = 3

Question 1

The equation is given as:

8x + 4 = 5x - 6

The replacement set is given as

{2, 3, 4, 5}

So, we replace the variables using the elements in the replacement set

When x = 2, we have

8(2) + 4 = 5(2) - 6

20 = 4 -- false

When x = 3, we have

8(3) + 4 = 5(3) - 6

28 = 9 -- false

When x = 4, we have

8(3) + 4 = 5(4) - 6

28 = 14 -- false

When x = 5, we have

8(5) + 4 = 5(5) - 6

44 = 19 -- false

Hence, the value of the equation is not in the solution set

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There isn't an obvious question to this problem but with the given we can assume what is to be asked. I think we are to find the total cost of a certain poultry seasoning. The poultry seasoning would have a total weight of 4+2=6 ounces. The total cost will then have to be 4(4) + 2(3) = 22 dollars. 

Answer:

D. 6

Step-by-step explanation:

Got it correct on edg2020

Answer:

The answer is " E'F' and EF are equal in length".

Step-by-step explanation:

By rotating that through some degree, a revolution is some kind of rigid transformation, which creates an image of the very same shape and size. There will be two main properties of the rotation:

In each line, the segment is rotated counterclockwise 180 degrees around the origin to form E'F, that's why the above given choice is correct.

Answer:

The answer is " E'F' and EF are equal in length

Step-by-step explanation:

Answer:

-10/7

Step-by-step explanation:

w - 5 = 8w + 5

w - 8w = 5 + 5

-7w = 10

w = - 10/7

Answer:

Step-by-step explanation:

To solve this equation, group like terms together:  'w' terms on the right and constants on the left:

-10 = 7w.  Then:

w = -10/7 (exact) or w ≈ 1.43

Answer:

The plumber would earn $190 in 5 hrs and 30 mins

Step-by-step explanation:

- We know the plumber worked from 2:30-8:00 which is 5 hrs and 30 min [5.5 hrs]

- We know the plumber charges the client $80 for the call and $20/hr for the work

1. I multiplied $20 x 5.5= $110+80=$190

or you could just do 100 x 5.5 [but it would it work since the plumber is charging per hour]

Have a great day, hope this helped <3

Answer:

equation: y = 32000 - 2000x

0 = 32000

1 = 30000

2 = 28000

3 = 26000

4 = 24000

Step-by-step explanation:

The descending height every minute will be,

32,000 feet

30,000 feet

28,000 feet

26,000 feet

24,000 feet

In mathematics, expression is defined as the relationship of numbers, variables, and functions using mathematical signs such as addition, subtraction, multiplication, and division.

0 minutes into the descent:

y = 32,000 feet

1 minute into the descent:

y = 32,000 - 2,000(1) = 30,000 feet

2 minutes into the descent:

y = 32,000 - 2,000(2) = 28,000 feet

3 minutes into the descent:

y = 32,000 - 2,000(3) = 26,000 feet

4 minutes into the descent:

y = 32,000 - 2,000(4) = 24,000 feet

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There are 4,608 different ways that the class can elect a president, vice president, and secretary.

To find the number of different ways that a class of 18 students can elect a president, vice president, and secretary, we will use the formula for permutations, which is given by -

nPk = n! / (n - k)!

where n is the total number of items and k is the number of items to be selected in a specific order.

In this case, we are given n = 18 students and k = 3 positions.

Thus, the number of different ways to elect a president, vice president, and secretary will be -

18P3 = 18! / (18 - 3)! = 18! / 15! = 18 x 17 x 16 = 4,608

Therefore, there are 4,608 different ways that the class can elect a president, vice president, and secretary.

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The proof for the  identity for the given cross product is verified.

To prove that the cross product is not associative, we are given that there exist u, v, and w such that

u × (v × w) ≠ (u × v) × w.

For this exercise, we will choose

u = i,

v = j, and

w = k.

Using these values, we have:

i × (j × k) = i × (-i)

= -j(i × j) × k

= k × k

= 0

Since -j is not equal to 0, u × (v × w) is not equal to (u × v) × w.

Thus, we have shown that the cross product is not associative.

Now, let's prove Theorem 17.7.

We can use the vector triple product identity, which states that

a × (b × c) = b(a · c) - c(a · b).

Using this identity, we have:

a × (b × c) + b × (c × a) + c × (a × b) = [b(a · c) - c(a · b)] + [c(b · a) - a(b · c)] + [a(c · b) - b(c · a)]

= 0

This completes the proof of Theorem 17.7.

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The length of the midsegment of trapezoid ABCD is 6.23 units.

In this question, we have been given a trapezoid ABCD with vertices A(0,0), B(2, 5), C(3, 5) and D(8, 0)

We need to find the length of the midsegment of trapezoid.

We know that the length of the midsegment is one-half the sum of the lengths of the bases.

The length of base AB,

AB = √(2 - 0)² + (5 - 0)²

AB = √4 + 25

AB = √29

AB = 5.38

The length of base CD would be,

CD = √(8 - 3)² + (0 - 5)²

CD = √5² + (-5)²

CD = √25 + 25

CD = 5√2

So, the length of the midsegment would be,

l = 1/2[(5.38 + 5√2)]

l = 6.23

Therefore, the length of the midsegment of trapezoid ABCD is 6.23 units.

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The solution to the provided differential equation with the initial condition y(0) = 5 and u as a step change of unity is y = -2

The provided differential equation is: \(\[\frac{{dy}}{{dt}} = y + 2u\]\) with the initial condition: y(0) = 5 where u is a step change of unity.

To solve this differential equation, we can use the method of integrating factors.

First, let's rearrange the equation in the standard form:

\(\[\frac{{dy}}{{dt}} - y = 2u\]\)

Now, we can multiply both sides of the equation by the integrating factor, which is defined as the exponential of the integral of the coefficient of y with respect to t.

In this case, the coefficient of y is -1:

Integrating factor \(} = e^{\int -1 \, dt} = e^{-t}\)

Multiplying both sides of the equation by the integrating factor gives:

\(\[e^{-t}\frac{{dy}}{{dt}} - e^{-t}y = 2e^{-t}u\]\)

The left side of the equation can be rewritten using the product rule of differentiation:

\(\[\frac{{d}}{{dt}}(e^{-t}y) = 2e^{-t}u\]\)

Integrating both sides with respect to t gives:

\(\[e^{-t}y = 2\int e^{-t}u \, dt\]\)

Since u is a step change of unity, we can split the integral into two parts based on the step change:

\(\[e^{-t}y = 2\int_{{-\infty}}^{t} e^{-t} \, dt + 2\int_{t}^{{\infty}} 0 \, dt\]\)

Simplifying the integrals gives:

\(\[e^{-t}y = 2\int_{{-\infty}}^{t} e^{-t} \, dt + 0\]\)

\(\[e^{-t}y = 2\int_{{-\infty}}^{t} e^{-t} \, dt\]\)

Evaluating the integral on the right side gives:

\(\[e^{-t}y = 2[-e^{-t}]_{{-\infty}}^{t}\]\)

\(\[e^{-t}y = 2(-e^{-t} - (-e^{-\infty}))\]\)

Since \(\(e^{-\infty}\)\) approaches zero, the second term on the right side becomes zero:

\(\[e^{-t}y = 2(-e^{-t})\]\)

Dividing both sides by \(\(e^{-t}\)\) gives the solution: y = -2

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The CPA Practice Advisor reports that the mean preparation fee for federal income tax returns was 261. Use this price as the population mean and assume the population standard deviation of preparation fees is 120.

We need to find the probability of selecting a random sample of 20 tax returns and a standard deviation of the sample preparation fees of 50 or less.

We use the central limit theorem that states that, regardless of the shape of the population, the sampling distribution of the sample means approaches a normal distribution with mean μ and standard deviation

σ/√n

where μ is the population mean, σ is the population standard deviation, and n is the sample size.

Therefore, we have:

\(\mu = 261\]\\sigma = $120\]\\n = 20\]\)

\(S.E.= \frac{\sigma}{\sqrt{n}}\\S.E =\frac{\ 120}{\sqrt{20}}\\S.E =26.83\)

The probability of selecting a random sample of 20 tax returns and a standard deviation of the sample preparation fees of 50 or less is given by:

\(P(Z < \frac{X - \mu}{S.E})\]\)

where X is the sample mean, μ is the population mean, and S.E is the standard error of the mean.

To calculate the probability, we standardize the distribution of the sample means using the z-score formula, i.e.,

\(\[z = \frac{X - \mu}{S.E} = \frac{\50 - \261}{\26.83} = -7.91\]\)

Therefore, the probability of selecting a random sample of 20 tax returns and a standard deviation of the sample preparation fees of 50 or less is zero because the z-score is less than the minimum z-score (i.e., -3.89) that corresponds to the probability of selecting a random sample of 20 tax returns and a standard deviation of the sample preparation fees of 50 or less.

Thus, it is impossible to obtain such a sample.

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The factors of the polynomial f (x) = x^5 - 7x - 22x³ + 44x² - 104x + 288 that is true for f (9) = 0 are (x - 9) and (x⁴ + 2x³ - 4x² + 8x - 32).

The factor theorem states that: if p(x) is divisible by x - a if and only if p(a)=0.

The polynomial expression x^5 - 7x - 22x³ + 44x² - 104x + 288 and f (9) = 0, then x - 9 = 0 is a factor. Applying long division as follows;

x^5 divided by x equals x⁴

x - 9 multiplied by x⁴ equals x^5 - 9x⁴

subtract x^5 - 9x⁴ from x^5 - 7x - 22x³ + 44x² - 104x + 288 will result to 2x⁴ - 22x³ + 44x² - 104x + 288

2x⁴ divided by x equals 2x³

x - 9 multiplied by 2x³ equals 2x⁴ - 18x³

subtract 2x⁴ - 18x³ from 2x⁴ - 22x³ + 44x² - 104x + 288 will result to -4x³ + 44x² - 104x + 288

-4x³ divided by x equals -4x²

x - 9 multiplied by -4x² equals -4x³ + 36x²

subtract -4x³ + 36x² from -4x³ + 44x² - 104x + 288 will result to 8x² - 104x + 288

8x² divided by x equals 8x

x - 9 multiplied by 8x equals 8x - 72x

subtract 8x - 72x from 8x² - 104x + 288 will result to - 32x + 288.

-32x divided by x equals -32

x - 9 multiplied by -32 equals -32x + 288

subtract -32x + 288 from- 32x + 288 will result to a remainder 0(zero).

We can then conclude the factors (x - 9) and (x⁴ + 2x³ - 4x² + 8x - 32) are the product of linear factors for the polynomial f (x) = x^5 - 7x - 22x³ + 44x² - 104x + 288 that makes it zero.

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Answer:

24

Step-by-step explanation:

The total number of students in the three sections is 36 + 40 + 48 = 124.

To find the maximum number of students in each row, we need to divide the total number of students by the number of rows, rounded down to the nearest integer.

Let's call the maximum number of students in each row "x". Then, we can write the equation:

x * n = 124

To find the maximum value of x, we need to find the maximum value of n such that the result of x * n is less than or equal to 124.

Starting with n = 1, we can increment n and calculate x for each value of n until x * n is greater than 124.

For n = 1, x * n = 124, so x = 124.

For n = 2, x * n = 62, so x = 62.

For n = 3, x * n = 41, so x = 41.

For n = 4, x * n = 31, so x = 31.

For n = 5, x * n = 24.8, which is not an integer, so we round down to 24.

Therefore, the maximum number of students in each row is 24, with a total of 5 rows.

Answer:

Step-by-step explanation:

Let's call the maximum number of students in each row "r". To find this value, we need to divide the total number of students by the number of rows. To ensure that all the students can fit into the rows, the number of students in each section must be divisible by the number of rows.

First, we find the least common multiple (LCM) of the number of students in each section, which will be the total number of students if we arrange them in the same number of rows. The LCM of 36, 40, and 48 is 240.

Next, we divide the LCM by the number of students in each section to find the number of rows:

r = LCM / 36 = 240 / 36= 6.67 (rounded down to 6)

So, the maximum number of students that can be in each row is 24

The mass of salt in the tank at time t.

dS/dt = 10 - S/400

S(0) = 100 grams

The solution is S(t) = 4000 - 3900\(e^{\frac{-t}{400}}\)

A tank holds water V(0) = 4000 liters in which salt S(0) = 100 grams.

So dS/dt = S(in) - S(out)

S(in) = 1 × 10 = 10 gram/liters

S(out) = S/V × 10 = 10S/V gram/liters

V = V(0) + q(in) - q(out)

V = 4000 + 10t - 10t

V = 4000 liters

dS/dt = 10 - 10S/V

dS/dt = 10 - 10S/4000

dS/dt = 10 - S/400

Now given; S(0) = 100.

Here, p(t) = 1/400, q(t) = 10

\(\int p(t)dt = \int\frac{1}{400}dt\)\(\int p(t)dt = \frac{1}{400}t\)

\(\mu=e^{\int p(t)dt}\)

\(\mu=e^{\frac{t}{400}}\)

So, S(t) = \(\frac{\int\mu q(t)dt+C}{\mu}\)

S(t) = \(\frac{\int e^{\frac{t}{400}} \cdot10dt+C}{e^{\frac{t}{400}}}\)

S(t) = \(e^{\frac{-t}{400}} \left({\int e^{\frac{t}{400}} \cdot10dt+C}\right)\)

S(t) = \(e^{\frac{-t}{400}} \left({10\times\frac{e^{\frac{t}{400}}}{1/400} +C}\right)\)

S(t) = \(e^{\frac{-t}{400}} \left({4000\times{e^{\frac{t}{400}} +C}\right)\)

Now solving the bracket

S(t) = 4000 + \(e^{\frac{-t}{400}}\)C.....(1)

At S(0) = 100

100 = 4000 + \(e^{\frac{-0}{400}}\) C

100 = 4000 + \(e^{0}\) C

100 = 4000 + C

Subtract 4000 on both side, we get

C = -3900

Now S(t) = 4000 - 3900\(e^{\frac{-t}{400}}\)

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The complete question is:

A tank holds 4000 liters of water in which 100 grams of salt have been dissolved. Saltwater with a concentration of 1 grams/liter is pumped in at 10 liters/minute and the well mixed saltwater solution is pumped out at the same rate. Write initial the value problem for:

The mass of salt in the tank at time t.

dS/dt =

S(0) =

The solution is S(t) =

Answer:

81pi

Step-by-step explanation:

You are asking yourself the area of pi*r^2 could with r as 9. pi*9^2. solve and you get 81pi :D

Answer:

"In the equation from part D of question 1, variable s is no longer in the equation. So, the variable s can have any value and the equation will still hold true."

Step-by-step explanation:

That was edmentums sample answer so its 100% correct.

Answer:

18

Step-by-step explanation:

If she catches 6 pop flies in 5 games, that averages to 1.2 pop flies per game.

So if you multiply 1.2 by 15 you get 18 pop flies per game.

Answer:

18

Step-by-step explanation:

She catches 6 pop flies each 5 games she plays. (5x3=15)

6x3=18