Answer:
Using the pythagoras theorem
S²=9²+4²
S²=81+16
S²=97
S=9.85km.
In finding the direction
tan□=opposite/Adjacent
=4/9
□=23.96
¤=90-23.96
=66.03 degrees
9.85, N 66.03 E
An object accelerates 3 m/s2 , when a force of 6 N acts on it. What is the object’s mass
Answer:
2 kgExplanation:
The mass of the object can be found by using the formula
\(m = \frac{f}{a} \\ \)
f is the force
a is the acceleration
From the question we have
\(m = \frac{6}{3} \\ = 2\)
We have the final answer as
2 kgHope this helps you
A boy starts at rest and slides down a frictionless slide as in the figure below. The bottom of the track is a height h above the ground. The boy then leaves the track horizontally, striking the ground a distance d as shown. Using energy methods, determine the initial height H of the boy in terms of h and d.
The initial height H of the boy can be determined by adding the height of the slide h and the horizontal distance d the boy travels after leaving the track: H = h + d.
To determine the initial height H of the boy in terms of h and d, we can use the principle of conservation of energy. The total mechanical energy of the system remains constant throughout the motion.
At the top of the slide, the boy has gravitational potential energy given by mgh, where m is the mass of the boy, g is the acceleration due to gravity, and h is the height of the slide above the ground.
As the boy slides down the slide, there is no friction or other dissipative forces, so there is no change in mechanical energy. At the bottom of the track, the gravitational potential energy is converted entirely into kinetic energy.
Therefore, we can equate the initial potential energy to the final kinetic energy:
mgh = 1/2 m\(v^{2}\),
where v is the horizontal velocity of the boy when he leaves the track.
Since the boy leaves the track horizontally, the vertical component of his velocity is zero. Therefore, we can use the relationship between horizontal distance d and horizontal velocity v:
d = vt.
Solving these equations, we can express the initial height H in terms of h and d:
H = h + d.
So the initial height H of the boy can be determined by adding the height of the slide h and the horizontal distance d the boy travels after leaving the track.G
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Electrons and protons travel from the Sun to the Earth at a typical velocity of 3.99 ✕ 10^5 m/s in the positive x-direction. Thousands of miles from Earth, they interact with Earth's magnetic field of magnitude 2.93 ✕ 10−8 T in the positive z-direction. Find the magnitude and direction of the magnetic force on a proton. Find the magnitude and direction of the magnetic force on an electron.
Therefore, the magnetic force on an electron is 1.175 x 10⁻¹⁴N in the positive y-direction.
The force experienced by a moving charge in a magnetic field is given by the Lorentz force law. Since the charge on a proton is positive and that on an electron is negative, the direction of the magnetic force experienced by each is different.In this question, we need to find the magnitude and direction of the magnetic force on a proton and an electron as they travel from the Sun to the Earth.
Let's first calculate the magnetic force on a proton:
F = qvBsinθ
where q = charge of the particle
v = velocity of the particle
B = magnetic field strength
θ = angle between the velocity of the particle and the magnetic field = 90° (since the proton is moving perpendicular to the magnetic field)
Therefore,
F = qvBsinθ
= (1.6 x 10⁻¹⁹) x (3.99 x 10⁵) x (2.93 x 10⁻⁸) x sin 90°
= 1.175 x 10⁻¹⁴ N
Direction of magnetic force on a proton:The direction of the magnetic force on a proton can be found using the right-hand rule. According to this rule, if we point the thumb of our right hand in the direction of the particle's velocity (in the positive x-direction) and the fingers in the direction of the magnetic field (in the positive z-direction), then the magnetic force will be perpendicular to both and will be in the negative y-direction.
Therefore, the magnetic force on a proton is 1.175 x 10^-14 N in the negative y-direction.
- Now, let's calculate the magnetic force on an electron:
Again using the Lorentz force law,
F = qvBsinθ
= (1.6 x 10⁻¹⁹) x (3.99 x 10⁵) x (2.93 x 10⁻⁸) x sin 90°
= -1.175 x 10⁻¹⁴ N (the negative sign indicates that the direction of the magnetic force is opposite to that of the proton)
Direction of magnetic force on an electron:Again using the right-hand rule, we can find the direction of the magnetic force on an electron. If we point the thumb of our right hand in the direction of the particle's velocity (in the positive x-direction) and the fingers in the direction of the magnetic field (in the positive z-direction), then the magnetic force will be perpendicular to both and will be in the positive y-direction.
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Part One: Defining the Problem and Sub-Problems
Choose one of the real-world problems about natural resources to research. Explain which one you chose here.
Research this problem to learn more about it. Use the research tools given in the lesson if you need help.
After you have researched the problem, explain in your own words who the problem impacts and why it is important.
List two sub-problems that are part of the bigger problem but are more manageable and solvable.
Explain how these sub-problems are related to or a direct result of the overall problem.
Part Two: Criteria, Constraints, and Prioritizations
Choose one sub-problem that you will investigate further and explain which one you chose here.
List two realistic criteria for the sub-problem.
Explain why it is important for these criteria to be met in order to solve the problem.
List two constraints for the sub-problem.
Explain why these constraints exist. (How do they limit solutions to the problem?)
Prioritization of the criteria and constraints and an explanation supporting the decisions made based on research.
Ranking Criteria or Constraint Reason for Prioritization
1
2
3
4
Part Three: Generate Solutions
List two solutions that you have generated for the chosen sub-problem.
Describe how the sub-problem can be solved, and include the research supporting each solution.
Explain how prioritization was involved in designing each solution.
Explain how both solutions to the sub-problem play a role in solving the larger problem.
List of the sources (at least three) you used for research, following the MLA style guide.
Answer:
Part One: Defining the Problem and Sub-Problems
1. Choose one of the real-world problems about natural resources to research. Explain which one you chose here.
o I chose pollution, due to the overwhelming pollution in todays day and age.
2. Research this problem to learn more about it. Use the research tools given in the lesson if you need help.
o There are 4 main types of pollution Air Pollution, Water Pollution, Soil Pollution, Noise Pollution.
o Air pollution refers to the release of harmful contaminants into the earth’s atmosphere.
o Water pollution is said to occur when toxic pollutants and particulate matter are introduced into water bodies such as lakes, rivers and seas.
o Soil pollution, also called soil contamination, refers to the degradation of land due to the presence of chemicals or other man-made substances in the soil.
o Noise pollution refers to the excessive amount of noise in the surrounding that disrupts the natural balance.
o Pollution is harmful things within an environment, that can cause decay within an environment.
3. After you have researched the problem, explain in your own words who the problem impacts and why it is important.
o It impacts the environment, people, animals, water, food, and the atmosphere. Its important to try and stop pollution to- a. make the world a cleaner place and b. stop such harmful substance from killing the environment around us.
4. List two sub-problems that are part of the bigger problem but are more manageable and solvable.
o Man made factories, cars, and garbage dumps.
o Being a litter bug (throwing trash on the ground).
5. Explain how these sub-problems are related to or a direct result of the overall problem.
o Cars create air pollution, along with factories. With being a litter bug and garbage dumps it causes soil pollution.
Part Two: Criteria, Constraints, and Prioritizations
1. Choose one sub-problem that you will investigate further and explain which one you chose here.
o Cars/fuel
2. List two realistic criteria for the sub-problem.
o Reducing fuel and oil can help fix the problem.
o Also using more electric ways to charge the car to run could be based off solar power to create a better environment.
3. Explain why it is important for these criteria to be met in order to solve the problem.
o It would create less air pollution, and could help with sickness, plants dying, and animals dying.
4. List two constraints for the sub-problem.
o Electric cars are a bit to expensive for the average person.
o People need to drive for work/travel, so they need gas for their car and due to the higher priced cars, it makes it almost impossible for this goal to be reached.
5. Explain why these constraints exist. (How do they limit solutions to the problem?)
o They exist due to the underpayment of workers and the average and below average social class. As for limiting the solutions, that is currently happening due to two oil factories shutting down raising the price on gas and limiting more gas for people. But causing more global panic/ angry people, due to not being able to receive what they need to continue their life by driving.
6. Prioritization of the criteria and constraints and an explanation supporting the decisions made based on research.
Ranking Criteria or Constraint Reason for Prioritization
1. Fuel and oil Its highly needed to run cars but causes sever pollution.
2. Prices for electric cars We could possibly have less pollution though its too expensive to afford a car that runs off electric. Because it may reduce pollution but the average paid person couldn’t afford it.
3. Under payment Within underpayment it causes more fuel and oil to be used in older cars that cant use electric charging.
4. Solar powered electric charge stations Low pollution and easily earth friendly acceptable.
Part Three: Generate Solutions
1. List two solutions that you have generated for the chosen sub-problem.
o Lowering prices on electric cars.
o Creating solar powered charge stations to reduce more pollution.
2. Describe how the sub-problem can be solved, and include the research supporting each solution.
o Lowering prices on electric cars and creating less fuel and oil providing cars could reduce pollution dramatically due to the burning fuels not polluting the air. And along with lowering car prices creating a solar energy charge station creates a more natural charge station instead of causing soil pollution with factories and under ground pipes.
3. Explain how prioritization was involved in designing each solution.
o Lowering prices on electric cars and creating less fuel and oil providing cars could reduce pollution dramatically due to the burning fuels not polluting the air.
4. Explain how both solutions to the sub-problem play a role in solving the larger problem.
o Both of my solutions would stop both soil and air pollution when it comes to cars and factories.
Sources of error could have come from friction that may result in energy losses during the collision, The gliders may not be perfectly elastic, which means that some energy may be lost during the collision
are these errors random or systematic errors?
Sources of error could have come from small amounts of friction, and glider 2 could have not been totally at rest. These errors are systematic errors.
Are these errors random or systematic?
Answer:
The first set of errors, which include friction and imperfect elasticity, are systematic errors because they arise from consistent factors that affect the measurements in a predictable way. These errors will be present in every trial of the experiment and will cause a consistent deviation from the true value.
The second set of errors, which include small amounts of friction and the initial velocity of glider 2, are also systematic errors because they arise from consistent factors that affect the measurements in a predictable way. These errors will also be present in every trial of the experiment and will cause a consistent deviation from the true value.
Explanation:
If the universe were to suddenly begin shrinking rather than continue expanding, how would it affect the cosmic microwave background radiation?
A. It would decrease in temperature.
B. It would blue-shift.
C. It would red-shift.
D. It would increase in temperature.
If the universe were to suddenly begin shrinking rather than continuing to expand, it would have a significant effect on the cosmic microwave background radiation (CMB).
The CMB is the afterglow of the Big Bang and is observed as a nearly uniform background radiation in all directions. It is thought to have been emitted when the universe was about 380,000 years old and had cooled enough for neutral atoms to form.
If the universe were to suddenly begin shrinking, the photons in the CMB would lose energy as they travel through the contracting space. This would cause the CMB radiation to shift to shorter wavelengths, which is known as blue-shifting.
Therefore, the correct answer is B. It would blue-shift.
Write a paragraph about the cartoon. Tell what he is trying to do. Will it work and why? What do you think will happen? Use the following words, static electricity, lightning, electrons, positive and negative charges.
Answer:
They are trying to jump-start a car using a kite and lightning connected to the battery. This will not work because there is no positive or negative charged side to the circuit.
Explanation:
Is the speedometer consistent throughout the 59-104 km/h range?
Yes, speedometer is consistent throughout the 59-104 km/h range. A speedometer, often known as a speed meter.
What is speedometer?A speedometer, often known as a speed meter, is a meter that calculates and shows the current speed of a moving object. They began to be offered as choices inside the beginning of the 20th century and were standard equipment starting around 1910. Nowadays, they are fitted to all motor vehicles.
Some vehicles may utilize speedometer-like instruments, but with a different method of measuring speed. For instance, boats use pit logs, whereas airplanes use airspeed indicators. Yes, speedometer is consistent throughout the 59-104 km/h range.
Therefore, yes, speedometer is consistent throughout the 59-104 km/h range.
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Answer:
yes speedometer are at a 59-104 km/h
Explanation:
have a nice day.
relation between linear and cubical expansion?
cubic expansion is 3 times the linear expansion. expressed mathematically as
\( \gamma = 3 \alpha \)
when light strikes a green opaque object the green wavelength of light is .....
1. reflected
2. absorbed
3. transmitted
while all other wavelengths of visible light are......
1. reflected
2. absorbed
3. transmitted
When light strikes a green opaque object, the green wavelength of light is absorbed, while all other wavelengths of visible light are reflected.
Why does a green object appear green to our eyes?A green object appears green to our eyes because it selectively absorbs all wavelengths of visible light except for the green wavelength of light, which is reflected back to our eyes.
When light strikes a green opaque object, the green wavelength of light is absorbed by the object. This means that the green light is not reflected or transmitted, but rather it is absorbed by the object.
What happens to the energy of the absorbed light when it is absorbed by an opaque object?When light is absorbed by an opaque object, the energy of the absorbed light is converted into other forms of energy, such as thermal energy. This is because the absorbed light energy causes the atoms in the object to vibrate, which in turn generates heat energy.
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will give brainliest pls help
Answer:
a and c
Explanation:
The saturated vapour pressure at 20°C and 8°C is 17.54mmHg and 8.05mmHg respectively. Find,
(i) Relative humidity at the room temperature.
(ii) How much mass of water should evapourate such that it saturate at 20°C (1mmHg = 133.3Pa)
1.) The relative humidity is 100 percent. 2.)To saturate the air at 20°C, 0.018g of water should evaporate.
(i) To calculate the relative humidity at room temperature, compare the amount of water vapour in the air to the maximum amount of water vapour that the air can hold at that temperature.
The saturated vapour pressure at that temperature determines the maximum amount. The relative humidity is stated as a percentage and can be calculated using the formula:
(Actual vapour pressure / Saturated vapour pressure) times 100% = Relative humidity
The saturation vapour pressure at room temperature (20°C) is 17.54mmHg. The relative humidity is 100% if the actual vapour pressure in the air equals the saturation vapour pressure.This signifies that the air has held the most water vapour it can at that temperature.
(ii) Using the ideal gas law, we can calculate the amount of water that should evaporate to saturate the air at 20°C. PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature in Kelvin, according to the ideal gas equation.
This equation can be rearranged to calculate the amount of moles of water:
n = (PV) / (RT)
We know that the required pressure is 17.54mmHg, which is equal to 2.338 kPa. We also know that the temperature is 20° C, which is 293.15 K.The volume is not specified, but we can assume it is constant and hence ignore it. The gas constant is 8.31 joules per mol-K.
n = ((2.338 kPa) / (8.31 J/mol-K * 293.15K))
To calculate the mass of water, multiply the number of moles by the molar mass of water, which is about 18.015 g/mol.
0.01796 g = 0.000997 mol * 18.015 g/mol mass of water
To saturate the air at 20°C, around 0.018g of water should evaporate.
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what were formed after the big bang theory?
Answer:
neutrons protons electrons
Explanation:
after the Big Bang, the universe was filled with neutrons, protons, electrons, anti-electrons, photons and neutrinos.
An engine draws energy from a hot reservoir with a temperature of 1250 K and exhausts energy into a cold reservoir with a temperature of 322 K. Over the course of one hour, the engine absorbs 1.37 x 105 J from the hot reservoir and exhausts 7.4 x 104 J into the cold reservoir.
1) What is the power output of this engine?
2) What is the maximum (Carnot) efficiency of a heat engine running between these two reservoirs?
3) What is the actual efficiency of this engine?
Answer:
The power output of this engine is \(P = 17.5 W\)
The the maximum (Carnot) efficiency is \(\eta_c = 0.7424\)
The actual efficiency of this engine is \(\eta _a = 0.46\)
Explanation:
From the question we are told that
The temperature of the hot reservoir is \(T_h = 1250 \ K\)
The temperature of the cold reservoir is \(T_c = 322 \ K\)
The energy absorbed from the hot reservoir is \(E_h = 1.37 *10^{5} \ J\)
The energy exhausts into cold reservoir is \(E_c = 7.4 *10^{4} J\)
The power output is mathematically represented as
\(P = \frac{W}{t}\)
Where t is the time taken which we will assume to be 1 hour = 3600 s
W is the workdone which is mathematically represented as
\(W = E_h -E_c\)
substituting values
\(W = 63000 J\)
So
\(P = \frac{63000}{3600}\)
\(P = 17.5 W\)
The Carnot efficiency is mathematically represented as
\(\eta_c = 1 - \frac{T_c}{T_h}\)
\(\eta_c = 1 - \frac{322}{1250}\)
\(\eta_c = 0.7424\)
The actual efficiency is mathematically represented as
\(\eta _a = \frac{W}{E_h}\)
substituting values
\(\eta _a = \frac{63000}{1.37*10^{5}}\)
\(\eta _a = 0.46\)
i need help i was at school in high school because i am in 9 grade a kid name summer ebby is makeing me mad she never stops talking she makes me mad and upset she says like can i ask a question or can i ask you she never stops talking what i should do if a student do not stops talking
A dog was running 10.8m/s for 61s. How far did it run in that time?
To solve using these three variables, we can use this equation:
distance = speed × timeSolving the QuestionWe're given:
Speed: 10.8 m/sTime: 61 sDistance: ?⇒ Plug the given values into the equation:
distance = speed × time
distance = 10.8 m/s × 61 s
distance = 658.8 m
AnswerThe dog ran 658.8 m in that time.
A car increases velocity from 25 m/s to 50 m/s in 5 seconds. What is the acceleration of the car?
Answer:
the acceleration of the car is 5m/s2
A large pickup truck (8,000kg) is parked in the parking lot. Does the truck have momentum?
Yes, the large pickup truck has momentum.
Momentum is a fundamental concept in physics and is defined as the product of an object's mass and its velocity. The momentum of an object is a vector quantity, meaning it has both magnitude and direction.
In this case, the truck has a mass of 8,000 kg. Even though it is parked and not in motion, it still possesses momentum. The reason for this is that momentum depends on both mass and velocity. While the truck's velocity may be zero (since it is parked), its mass is significant.
Mathematically, the momentum (p) of an object is given by the equation p = m * v, where m represents mass and v represents velocity. In this scenario, the velocity of the truck is zero, resulting in a momentum of zero. However, the mass of the truck is still present, and according to the equation, the product of zero velocity and 8,000 kg mass yields a momentum of zero.
So, although the truck is not moving and its momentum is zero, it still possesses the potential for momentum due to its mass. If the truck were to start moving, its velocity would change from zero, and momentum would come into play according to the equation mentioned earlier.
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At which position do you expect its speed to be one-half the speed at which it eventually hits the ground?
At which position do you expect its speed to be one-half the speed at which it eventually hits the ground?
Higher than the midpoint of the path.
Lower than the midpoint of the path.
At the midpoint of the path.
The point where the object's speed is one-half its final speed may located at 3/4 of the initial height of the object, the answer would be "lower than the midpoint of the path."
Assuming the object is subject to a constant acceleration due to gravity, the speed of the object at any given point can be described by the following equation:
v² = u² + 2as
Where:
v = final velocity
u = initial velocity
a = acceleration due to gravity (approximately 9.8 m/s² near the Earth's surface)
s = distance traveled
Let's suppose the object is dropped from rest at a height h above the ground. Then its initial velocity is u=0, and the equation simplifies to:
v² = 2gh
where g is the acceleration due to gravity and h is the initial height of the object.
To find the point at which the object's speed is one-half its final speed, we can set v = 1/2 * √(2gh) and solve for s:
1/2 * √(2gh) = √(2gh - 2gs)
Simplifying this equation, we get:
1/4 * 2gh = 2gh - 2gs
s = 3/4 * h
This means that the point where the object's speed is one-half its final speed is located at 3/4 of the initial height of the object. Therefore, the answer is "lower than the midpoint of the path."
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two spheres A and B are projected off the edge of a 1.0 m high table with the same horizontal velocity . sphere A has a mass of 20.g and sphere B has a mass of 10.g.
If both spheres leave the edge of the table at the same instant, sphere A will land
a. at some time after sphere B.
b. at the same time as sphere B.
c. at some time before sphere B.
d. There is not enough information to decide.
A would land before since its heavier
The IMA of the pulley shown is
2
3
1
Answer:
2 because I did this on before
At the top of the path, the horozontal velocity is___.
Answer:
the answer is A have a nice day hope I helped
A 250 kg cart starts from rest and rolls down an inclined plane from a height of 550 m. Determine its speed at a height of 125 m above the bottom of the incline. Please round to two decimal places.
Answer:
24.85 m/s.
Explanation:
PE = mgh = 250 kg x 9.81 m/s^2 x 550 m = 1,358,725 J
PE' = mgh' = 250 kg x 9.81 m/s^2 x 125 m = 308,062.5 J
PE = KE
1,358,725 J = 0.5mv^2
Solving for v, we get:
v = sqrt(2PE/m) = sqrt(2 x 1,358,725 J / 250 kg) = 59.15 m/s (rounded to two decimal places)
PE' + KE' = PE + KE
Since the cart starts from rest at the top of the incline, KE = 0. Therefore:
PE' = KE'
mgh' = 0.5mv'^2
Solving for v', we get:
v' = sqrt(2gh') = sqrt(2 x 9.81 m/s^2 x 125 m) = 24.85 m/s (rounded to two decimal places)
Therefore, the speed of the cart at a height of 125 m above the bottom of the incline is 24.85 m/s.
a group of factory requires 5 MW to operate . calculate the number of turbines needed to meet the need if the average output of each turbine is 0.5W
The number of turbines needed to meet the need if the average output of each turbine is 0.5W is 10000000 turbines
Data obtained from the questionFrom the question given above, the following data were obtained:
Total power required = 5 MW = 5 × 1000000 = 5000000 WPower per turbine = 0.5 WNumber of turbines =?How to determinethe number of turbines neededFrom the given data, we can simply determine the number of turbines needed by the factory as follow:
Number of turbines = Total power / Power per turbine
Number of turbines = 5000000 / 0.5
Number of turbines = 10000000 turbines
Therefore, the number of turbines needed by the factory is 10000000 turbines
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Given the list of items, select all that are considered to be matter:
music
heat
air
dreams
water
gasoline
love
bacteria
thoughts
From the given list of items, examples of matter include, heat, air, water, gasoline, and bacteria.
What is matter?Matter is a substance made up of various types of particles that occupies physical space and has inertia.
A matter must have mass and occupy space.
Examples of matter include the following;
heatairwatergasolinebacteriaThus, from the given list of items, examples of matter include, heat, air, water, gasoline, and bacteria.
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2. If an automobile engine delivers 3.8x10^4 Watts of power, how much time will it take for the
engine to do 6.40 x 10^5 Joules of work?
Explanation:
POWER = work / time
38 000 = 640 000 / t
t = 16.8 seconds
Find the components of vtot along the x and y axes in Figure 3.25, where = 23.0° and vtot = 7.56 m/s.
vtot, x =
m/s
vtot, y =
m/s
The component of the total velocity in the x - direction is 6.96 m/s.
The component of the total velocity in the y - direction is 2.95 m/s.
Component of the velocity in x direction
The component of the total velocity in the x - direction is calculated as follows;
v(x) = vtot cosθ
where;
vtot is total velocityv(x) is velocity in x directionv(x) = 7.56 x cos(23)
v(x) = 6.96 m/s
Component of the velocity in y - directionv(y) = vtot sinθ
v(y) = 7.56 x sin(23)
v(y) = 2.95 m/s
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g We have studied diffraction from a single slit, where light is sent through a thin opening. A similar phenomena occurs when light bends around a thin object, like a human hair. Here the width of the hair plays the role of the width of the single slit. Measurements found that when a beam of light of wavelength 632.8 nm was shone on a single strand of hair, the first dark fringe on either side of the central bright spot were 5.22 cm apart. If the screen is 1.25 meters away, how thick was this strand of hair?
Answer:
\(3.031\times 10^{-5}\ \text{m}\)
Explanation:
\(y\) = Distance between central maxima and first minimum
m = Order = 1
d = Thickness of hair
\(\lambda\) = Wavelength = 632.8 nm
L = Distance between light source and screen = 1.25 m
Width of central maximum is given by
\(2y=5.22\times 10^{-2}\\\Rightarrow y=\dfrac{5.22\times 10^{-2}}{2}\\\Rightarrow y=0.0261\ \text{m}\)
Distance between central maxima and first minimum is given by
\(y=L\tan\theta_{min}\\\Rightarrow \tan\theta_{min}=\dfrac{y}{L}\\\Rightarrow \tan\theta_{min}=\dfrac{0.0261}{1.25}\\\Rightarrow \theta_{min}=\tan^{-1}0.02088\\\Rightarrow \theta_{min}=1.1962^{\circ}\)
Since \(\theta\) is small \(\tan\theta_{min}=\sin\theta_{min}\)
\(\sin\theta_{min}=\dfrac{m\lambda}{d}\\\Rightarrow d=\dfrac{m\lambda}{\sin\theta}\\\Rightarrow d=\dfrac{1\times 632.8\times 10^{-9}}{\sin1.1962^{\circ}}\\\Rightarrow d=3.031\times 10^{-5}\ \text{m}\)
The strand of hair is \(3.031\times 10^{-5}\ \text{m}\) thick.
What characteristics determine how easily two substances change temperature? Check all that apply.
volume of the two substances in contact
amount of time the two substances are in contact
Oarea in contact between the two substances
specific heat of the material that makes up the substances
density of the two substances in contact
Answer:
The characteristics that determine how easily two substances change temperature are:
specific heat of the material that makes up the substancesarea in contact between the two substancesThe volume and density of the substances and the amount of time they are in contact do not directly affect how easily they change temperature.
Explanation:
A 2 m long wire carrying 2 A of current pointing to the right is placed in a magnetic field of 4 T directed away from you. Which direction does the force on the wire point?
A. Down
B. Up
C. Left
D. Right
Explanation:
To determine the direction of the force on the wire, we can use the right-hand rule for the cross product of two vectors. The force on the wire is given by:F = I * L x Bwhere I is the current, L is the length of the wire, and B is the magnetic field.
If we point our right-hand thumb in the direction of the current (to the right), and our fingers in the direction of the magnetic field (away from us), then our palm will point in the direction of the force.
So, using the right-hand rule, we can see that the force on the wire will be directed downward. Therefore, the correct answer is A. Down.