saturn exerts a much greater force on the moon Pan than Pan exerts on saturn. true or false

Answer:

broiling

Explanation:

placing it would be that

Answer:

a)     I = 10⁻² W / m², b)   β = 104.8 db

Explanation:

a) For this exercise we use the definition of decibels

           β = 10 log \(\frac{I}{I_o}\)

where I and Io are the intensities produced and the sound threshold

I₀ = 10⁻¹² W / m²

            log \frac{I}{I_o} =   β / 10

            I = Io \(10^{\beta /10}\)

let's calculate

            I = 10⁻¹²   \(10^{100/10}\)

            I = 10⁻² W / m²

b) each toad produces the same sound for which the total intensity is

            I_total = 3 I

            I_total = 3 10⁻² W / m²

expressed in decibels

           β = 10 log (\(\frac{3 \ 10^{-2} }{10^{-12} }\))

           β = 104.8 db

The toadfish make sue of the resonance on the closed system tube to make a very loud noise and fish tube is the bladder which us used for amplifying the sounds. The sound level of the creatures has been taken as 100DB.

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Answer:

0.12 mm ; 140.50 rad/m ; 628.32 rad/sec ; +

Explanation:

Given the wave equation of the form :

y(x, t) = ym sin(kx ± ωt)

Mas per unit length (u) = 5 g/cm = (5÷1000)kg / 0.01m) = 0.005kg/0.01m = 0.5kg/m

Tension, T = 10 N

Amplitude, A = 0.12 mm

Frequency, F = 100 Hz

Comparing with the general wave equation :

y = Asin(kx ± ωt)

A = amplitude = ym = 0.12 mm

2.) k = 2π / λ

Recall :

v = fλ

v = sqrt(T/u) = sqrt(10/0.5) = sqrt(20) = 4.472

λ = v/ f = 4.472 / 100 = 0.04472

Hence,

k = (2 * π) / 0.04472

k = 140.50 rad/m

3.) Angular frequency, ω

ω = 2πf = 2 * 3.14 * 100 = 628.32 rad/sec

4.) sign is +ve

Direction of wave propagation as given is in the negative x axis

Answer:

 p₀ = 0 , 0 = pactor + p_proyectal

Explanation:

The total moment of the actor and projectile before the shot is zero since both are at zero speed

         p₀ = 0

after the shot the moment is

        \(p_{f}\) = P_actor + P_proyecta

        P₀ = p_{f}

system is formed by the actor plus the projectile

        0 = pactor + p_proyectal

       p_proyectil = - p _actor

See fly momentum before and pulse shot is zero.

In the part after the shot the moment of the two parts is different from zero, but since they go in the opposite direction their sum gives zero,

The initial momentum of the 25 kg object is 25 kg * 12 m/s = 300 kgm/s. After the collision, the momentum of the 25 kg object is 25 kg * 8 m/s = 200 kgm/s. According to the conservation of momentum, the momentum lost by the 25 kg object is equal to the momentum gained by the box. Therefore, the resulting momentum of the box is 300 kgm/s - 200 kgm/s = 100 kg*m/s.

Answer:

0.14 J

Explanation:

The maximum velocity is the amplitude times the angular frequency.

vmax = Aω

ω = vmax / A

ω = (3.2 m/s) / (0.06 m)

ω = 53.3 rad/s

For a spring-mass system:

ω = √(k / m)

ω² = k / m

k = ω²m

k = (53.3 rad/s)² (0.050 kg)

k = 142 N/m

The elastic potential energy is:

EE = ½ kx²

EE = ½ (142 N/m) (0.044 m)²

EE = 0.14 J

It as dangerous to be hit by the gun as by the bullet because of the following;

(A) The butt distributes the recoil force over an area much larger than that of the bullet.

(B) The rifle has a much lower speed than the bullet.

The principle of conservation of linear momentum states that in an isolated system, the total momentum of the system is conserved.

That is the sum of the initial momentum is equal to the sum of the final momentum.

momentum of the gun = momentum of the bullet

Mu = mU

where;

If the forward momentum of a bullet is the same as the backward momentum of the gun, the speed of the gun will be smaller than the speed of the bullet since the mass of the gun is bigger than mass of the bullet.

We cannot conclude on the kinetic energy, since it depends on both mass and velocity.

Finally, the butt distributes the recoil force over an area much larger than that of the bullet, since the butt has a larger surface area and will hit more surface area than the bullet.

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Answer:

B.lenses bounce light from their surface, mirrors do not

We have the next information

m=120 kg

l=17.4m

θ=5.5°

T=8.37s

Then for the speed

For A is the amplitude and omega is the angular speed

We substitute

ANSWER

Maximum speed 1.25 m/s

The experimental value of the expression due to gravity through the experiment will come out to be 8.41u, the error in the value has Accord because of air friction.

Acceleration due to gravity is a form of acceleration that is exercised by the gravitational pull of the earth its value is fixed at the surface n is equal to 9.8u.

Aries composed of molecules and their food when an object passes through air strikes the a molecules they are molecules according to Newton's third law strike back at the object therefore reducing its speed. This force by the molecule is known as air friction.

The setup of the given experiment consists of:

A bob of mass m

A stopwatch with high accuracy

An inch tape

A speedometer

Experiment is conducted in the following manner:

Using Newton's first law of motion

i.e. v = u + a × t  

Where,

u is initial velocity

v is final velocity

a is acceleration due to gravity

t is time taken to cover distance

From the data given v = 16.82m/s

t is 2 seconds

Substituting value in Newton's first law of motion we get

Value of acceleration due to the gravity = 8.41

Therefore, The experimental value of the expression due to gravity through the experiment will come out to be 8.41u, the error in the value has Accord because of air friction.

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Answer:

It would be 90

Explanation:looked it up

The value of the unknown resistance is approximately 44750 Ω.

In a balanced Wheatstone bridge, the ratio of the resistances in the two arms of the bridge is equal to the ratio of the resistances in the other two arms. That is:

R1/R2 = R3/R4

where R1, R2, R3, and R4 are the resistances in the four arms of the bridge.

In this problem, the resistances in three of the arms of the bridge are all exactly 500 Ω. Let the resistance in the fourth arm (the unknown resistance) be denoted by R. The voltage across the galvanometer is zero in a balanced Wheatstone bridge, so the current through the galvanometer is also zero.

Using Ohm's law, the current through the entire circuit is given by:

I = V/(R1 + R2 + R3 + R4)

where V is the voltage of the battery, and R1, R2, R3, and R4 are the resistances in the four arms of the bridge.

The voltage drop across the 500 Ω resistances is given by:

V_500 = (500/(500+500+R)) * V

The voltage drop across the unknown resistance R is also given by:

V_R = (R/(500+500+R)) * V

Since the voltage across the galvanometer is zero, the current through the unknown resistance R is equal to the current through the 80 Ω galvanometer. Using Ohm's law, we can write:

I_R = V_R/R = I_galvanometer = 0.08 μA

Substituting the expressions for the voltages and the current into the equation for the total current, we get:

V/(500+500+500+R) = 0.08 μA

Solving for R, we get:

R = (V/0.08 μA) - 1500 Ω

Substituting the given values, we get:

R = (3.7 V)/(0.08 μA) - 1500 Ω

R = 46250 Ω - 1500 Ω

R = 44750 Ω

Therefore, the value of the unknown resistance is approximately 44750 Ω.

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a. His average velocity would be 1.11m/s2

b. His average speed would be 2.05m/s

Velocity of a particle is its speed and the direction in which it is moving.

It can also be described as the instantaneous rate of change of the particle's distance traveled, and the direction in which the distance is changing. The SI units of the speed is the metre per second squared (m/s2). It is a vector quantity, hence is has magnitude and direction.

Speed is a scalar quantity which tells how fast an object is moving, regardless of its direction. The SI units of the speed is the metre per second (m/s). It is a scalar quantity and has only magnitude with no direction.

From the question;

Velocity = displacement/time

displacement = 40 km (4000m)

time = 60 mins (3600s)

Velocity = 4000/3600

Velocity = 1.11m/s2

Speed = total distance covered/total time

Speed = (40km + 20km + 20km) / (60mins + 5 mins)

Speed = (4000m + 2000m + 2000m) / (65mins)

Speed = (8000m/3900s)

Speed = 2.05m/s

Hence, his average velocity is 1.11m/s2 and speed 2.05m/s.

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The electron number cannot be used instead because electrons can be removed from or added to an atom (option C)

The element of an atom is determined by its proton count, while the electron count can exhibit variability. Take, for instance, a sodium atom, which encompasses 11 protons and 11 electrons. However, it has the capacity to relinquish one electron, transforming into a sodium ion housing only 10 electrons.

This occurs due to the relatively loose binding of electrons to the nucleus, enabling their removal through the influence of an electric field or alternative mechanisms.

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Did anyone get an answer for this??

I. The resistance which is needed to generate a current of 0.25 Ampere in the ceiling fan is 480 Ohms.

II. Since current is inversely proportional to the resistance in the electrical circuit, an increase in the current (larger currents) flowing into the electrical circuit of the ceiling fan would cause the resistance to decrease in magnitude at medium and high speeds.

Given the following data:

To calculate the resistance needed to generate that current, we would apply Ohm's law:

Ohm's law states that at constant temperature, the current flowing through an electrical circuit is directly proportional to the voltage (potential difference) applied across the two terminals of the electrical circuit and inversely proportional to the resistance in the electrical circuit.

Mathematically, Ohm's law is given by the formula;

\(V=IR\)

Where;

Making R the subject of formula, we have:

\(R =\frac{V}{I}\)

Substituting the given parameters into the formula, we have;

\(R=\frac{120}{0.25}\)

Resistance, R = 480 Ohms

Since current is inversely proportional to the resistance in the electrical circuit, an increase in the current (larger currents) flowing into the electrical circuit of the ceiling fan would cause the resistance to decrease in magnitude at medium and high speeds.

In conclusion, the larger the current, the lower the resistance would be at both medium and high speeds.

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\({\underline{\tt{Answer 1}}}\)

For a fixed pulley alone, the resistance force is equal to the effort force, and the mechanical advantage is 1. When a movable pulley is added to the fixed pulley, the resistance force is reduced by half, the effort force is reduced, but the distance the effort force must be applied over is doubled. The mechanical advantage for a fixed and movable pulley is 2, and the slope of the line for each pulley represents the mechanical advantage.

\({\underline{\tt{Answer 2}}}\)

The work output for the pulleys is equal to the weight of the object multiplied by the distance it was lifted. The work input is equal to the force applied to the rope multiplied by the distance it was pulled. Since the weight of the object and the force applied to the rope are equal, the work output is equal to the work input. However, the pulleys allow the force to be applied over a greater distance, which means that less force is required to lift the object, but the force must be applied over a longer distance.

\({\underline{\tt{Answer 3}}}\)

Pulleys allow the effort force to be reduced while increasing the effort distance, and they allow the resistance force to be reduced while increasing the resistance distance. The advantages of using pulleys include the ability to lift heavy objects with less effort, the ability to change the direction of the force, and the ability to increase the distance that the force can be applied over.

If a third movable pulley were added to the pulley system, the mechanical advantage would be increased. Specifically, the mechanical advantage would be equal to 3, since the resistance force would be divided by three and the effort force would be equal to one-third of the resistance force.

Answer:

The relationship between the resistance force and the effort force for the fixed pulley alone is that they are equal in magnitude.

Explanation:

The relationship between the resistance force and the effort force for the fixed pulley alone is that they are equal in magnitude. In other words, the effort force needed to lift a certain weight is the same as the weight itself. However, when a movable pulley is added to the fixed pulley, the resistance force is halved compared to the effort force. This means that the effort force required to lift a certain weight is only half of the weight itself. The mechanical advantage of a pulley system can be determined by the slope of the line on a force vs. distance graph. The steeper the slope, the greater the mechanical advantage. In this case, the mechanical advantage is higher for the system with the movable pulley compared to the fixed pulley alone, as the slope is steeper for the former.

The work output relates to the work input for the pulleys based on the principle of work conservation. In an ideal scenario with no energy losses, the work input should be equal to the work output. However, due to friction and other factors, there might be some energy losses in the pulley system, resulting in a slightly lower work output compared to the work input.

Pulleys provide a mechanical advantage by reducing the amount of effort force required to lift a heavy object. As more pulleys are added, the mechanical advantage increases further. With respect to changes in effort force and effort distance compared to resistance force and resistance distance, pulleys allow for a trade-off between the two. By applying a smaller effort force over a longer distance, a greater resistance force can be overcome over a shorter distance. This is advantageous as it enables the lifting of heavy loads with less effort. Adding a third movable pulley would further increase the mechanical advantage, making it easier to lift heavier objects with even less effort force.

The acceleration of skateboard on road A will be 7.74 \(m/s^{2}\)

The acceleration of skateboard on road B will be 3.87 \(m/s^{2}\)

The acceleration of skateboard on road C will be 9.68 \(m/s^{2}\)

force = mass * acceleration

mass1 = 62 kg

force1 = 480 N

acceleration1 = force / mass

                     = 480 / 62 = 7.74 \(m/s^{2}\)

mass2 = 62 kg

force2  = 240 N

acceleration 2  = 240 / 62 = 3.87  \(m/s^{2}\)

mass 3 = 62 kg

force 3  = 600 N

acceleration 3  = 600 / 62  = 9.68  \(m/s^{2}\)

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To solve the given problems, we'll use the principles of work-energy and conservation of energy. Let's address each question one by one:

(1) What is the work done by Chris on the box when the speed of the box reaches 2.1 m/s?

The work done by Chris on the box is equal to the change in the box's kinetic energy. Since the box starts from rest, the initial kinetic energy is zero. The final kinetic energy can be calculated using the formula:

Kinetic energy = (1/2) * mass * velocity^2

Plugging in the values:

Mass of the box (m) = 53 kg

Final velocity (v) = 2.1 m/s

Kinetic energy = (1/2) * 53 kg * (2.1 m/s)^2

Calculate the value of the kinetic energy, which represents the work done by Chris on the box.

(2) What is the speed of the box when it reaches the bottom of the slope (Point B in the diagram)?

To determine the speed at the bottom of the slope, we'll use the principle of conservation of energy. The total mechanical energy of the box is conserved as it moves from the top to the bottom of the slope.

The initial potential energy at the top of the slope is converted into kinetic energy at the bottom of the slope, neglecting any energy losses due to friction.

Potential energy at the top = m * g * h1

Where:

Mass of the box (m) = 53 kg

Acceleration due to gravity (g) = 10 m/s^2

Height difference between floors (h1) = 3.2 m

Calculate the initial potential energy.

The final kinetic energy at the bottom is given by:

Kinetic energy at the bottom = (1/2) * m * v^2

Where:

Mass of the box (m) = 53 kg

Velocity at the bottom (v) = ?

Equating the initial potential energy to the final kinetic energy, solve for v to find the speed of the box at the bottom of the slope.

(3) To what speed does the box slow down when it reaches the bottom of the ramp to the pickup truck?

Since the ramp connecting the first floor to the bed of the pickup truck is frictionless, there is no external force doing work on the box. Thus, the mechanical energy of the box is conserved as it moves from the bottom of the slope to the bottom of the ramp.

Using the same principle of conservation of energy, equate the final kinetic energy at the bottom of the slope to the initial potential energy at the bottom of the ramp.

Potential energy at the bottom of the ramp = m * g * h2

Where:

Mass of the box (m) = 53 kg

Acceleration due to gravity (g) = 10 m/s^2

Height difference between the first floor and the truck bed (h2) = 0.90 m

Calculate the potential energy at the bottom of the ramp.

Equating the potential energy at the bottom of the ramp to the final kinetic energy, solve for the speed of the box at the bottom of the ramp.

(4) What is the speed of the box when it reaches the bed of the pickup truck?

Since the ramp connecting the first floor to the truck bed is frictionless, there is no external force doing work on the box. The mechanical energy of the box is conserved as it moves from the bottom of the ramp to the truck bed.

Using the same principle of conservation of energy, equate the final potential energy at the bottom of the ramp to the final kinetic energy at the truck bed.

Potential energy at the truck bed = m * g * h

Answer:

I'm pretty sure its c

Hope you get a good grade-

The arcsine of 1 is 90 degrees, the critical angle is 90 degrees.the minimum depth (measured to the top of the Batbox) is equal to the height of the Batbox.

To determine the minimum depth of the Batbox below the surface of the water for Batman to remain hidden from the Joker, we need to consider the principle of total internal reflection. When light travels from a medium with a higher refractive index to a medium with a lower refractive index, it can undergo total internal reflection if the angle of incidence exceeds the critical angle. In this case, the light traveling from water (refractive index nw = 1.333) to the Batplastic (refractive index np = 1.333) can undergo total internal reflection at the interface between the two.

To calculate the minimum depth, we need to find the critical angle. The critical angle can be determined using the formula:

Critical angle = arcsin(np/nw)

Given:

Refractive index of water, nw = 1.333

Refractive index of Batplastic, np = 1.333

Calculating the critical angle:

Critical angle = arcsin(1.333/1.333)

Critical angle = arcsin(1)

Since the arcsine of 1 is 90 degrees, the critical angle is 90 degrees.

To ensure that Batman remains hidden, the Batbox should be placed at a depth below the surface of the water such that the light undergoes total internal reflection. In this case, the minimum depth is determined by the height of the Batbox. Therefore, the minimum depth (measured to the top of the Batbox) is equal to the height of the Batbox. However, the specific height of the Batbox is not provided in the question, so it cannot be determined without additional information.

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Answer:

-2.3 × 10^-9 Coulombs(C).

Explanation:

So, we are given the following data or information or parameters that is going to help us to solve the problem effectively and efficiently;

=> " the shuttle's potential is typically changed by -1.4 V during one revolution. "

=> " Assuming the shuttle is a conducting sphere of radius 15 m".

So, in order to estimate the value for the charge we will be making use of the equation below:

Charge, C =( radius × voltage or potential difference) ÷ Coulomb's law constant.

Note that the value of Coulomb's law constant = 9 x 10^9 Nm^2 / C^2.

So, charge = { 15 × (- 1.4)} / 9 x 10^9 Nm^2 / C^2.

= -2.3 × 10^-9 Coulombs(C).

Scientists seek to acquire knowledge and understanding of the real world through the formulation, testing, and evaluation of scientific hypotheses (Option C).

Scientific hypotheses are explanations about questions of the real world that can be used to test them by using the scientific method, i.e., by testing them to confirm or reject their assumptions through experimental and observation procedures.

Therefore, with this data, we can see that a scientific hypothesis is formulated and tested by using the scientific method in order to confirm or reject its assumptions and thus build scientific knowledge.

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Answer:

Scientific hypothesis

Explanation:

Answer:

10N to the left side towards you

Explanation:

The net force is the resultant force that acts on a body.

Force is a push or pull on a body.    

 Push to left side  = 25N

 Pull to the right  = 15N

Net force  = Push to left side   -  Pull to the right  = 25N  - 15N

 Net force  = 10N to the left side towards you

The net force is therefore 10N to the left side towards you

Answer:

Hola

Explanation:

espero que te ayude gracias por los puntod

The displacement x = -0.098 m

The maximum potential energy of the block  = 0.049 J

The maximum kinetic energy of the block = 0.075 J

The maximum velocity of the block  = 0.73 m/s

The velocity of the block at a distance of half the amplitude.= 0.60 m/s

To solve this problem, we will use the equations of motion for a mass-spring system.

The frequency of oscillation is given by:

f = 1/2π * √(k/m)

where

f is the frequency of oscillation, k is the spring constant, and

m is the mass of the block.

The force exerted by the spring is given by:

F = -kx

where

F is the force,

k is the spring constant, and

x is the displacement from the equilibrium position.

a. To find the displacement x, we can use the force equation:

1.0 N = -kx

using the equation for frequency:

1.2 Hz = 1/2π * √(k/0.28)

Solving for k, we get:

k = (1.2*2π)^2 * 0.28

k = 10.17 N/m

Now we can solve for x:

1.0 N = -(10.17 N/m) * x

x = -1.0 N / (10.17 N/m)

x = -0.098 m

b. The maximum potential energy of the block occurs at the maximum displacement from equilibrium, which we can find using the displacement x we just calculated:

= (1/2)kx^2 = (1/2)(10.17 N/m)(-0.098 m)^2 = 0.049 J

c. The maximum kinetic energy of the block occurs at the equilibrium position, where the velocity is maximum:

K_max = (1/2)mv^2

We can find the velocity using the frequency and the displacement:

v_max = 2πf * |x| = 2π(1.2 Hz)(0.098 m) = 0.73 m/s

Plugging in the values,

K_max = (1/2)(0.28 Kg)(0.73 m/s)^2 = 0.075 J

d. The maximum velocity = 0.73 m/s

e. To find the velocity of the block at a distance of half the amplitude, we can use the conservation of energy:

K_max + U_max = (1/2)kx^2 + (1/2)mv^2

At half the amplitude, the displacement is x/2:

K_max + U_max = (1/2)k(x/2)^2 + (1/2)mv^2

Solving for v, we get:

v = √[(K_max + U_max - (1/2)k(x/2)^2)/(1/2)m]

Plugging in the values, we get:

v = √[(0.075 J + 0.049 J - (1/2)(10.17 N/m)((-0.098 m)/2)^2)/(1/2)(0.28 Kg)]

v = 0.60 m/s

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Answer:

1122.8

Explanation:

12.73 kg x 9.8 m/s^2 x 9m

=1122.786

Rounded=1122.8