Answer:
you have it correct
because when you are talking about negative the smaller number it the greater number
The inequality - 8 < - 4 is true among all the other given options.
What are inequalities and their types?
Inequality is a relation that compares two numbers or other mathematical expressions in an unequal way.
The symbol a < b indicates that a is smaller than b.
When a > b is used, it indicates that a is bigger than b.
a is less than or equal to b when a notation like a ≤ b.
a is bigger or equal value of an is indicated by the notation a ≥ b.
Given, Two points on the number line one at - 8 and one at - 4.
We know 8 > 4 therefore - 4 > - 8 Or - 8 < - 4.
The more we go toward the left of the number line the numbers are smaller and smaller.
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What are the values of x when x²+x-6 = -4?
OA. x = -4 and x = 6
OB. x = -2 and x = 1
OC. x = -3 and x = 2
OD. x = -5 and x = -6
edu
play
Answer:
0
Step-by-step explanation:
for x x^2+x-6=-4. x2+x−6=−4 x 2 + x - 6 = - 4. Step 1. Add 4 4 to both sides of the equation. x2+x−6+4=0 x 2 + x - 6 + 4 = 0.
(hope it helps!)
Find the measure of each angle indicated. Round to the nearest tenth.
The measure of the given angle , given the dimensions of the sides , is 50 degrees .
How to find the angle ?The measure of the indicated angle can be found by using Cos function because the given dimensions are the adjacent and hypotenuse measurements to the ∠ ABC .
The measure of the angle ∠ ABC will then be :
Cos ∠ ABC = 9 / 14
Cos ∠ ABC = 0. 6428571
∠ ABC = Cos ⁻ ¹ ( 0. 6428571)
∠ ABC = 49. 99
∠ ABC = 50 degrees
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PLEASEE I NEED HELP!!
Figure 3 can also be created by transforming figure 1 with a sequence of two transformations. Which statement describes a possible sequence of transformations that transforms figure 1 into figure 3?
A. a rotation 180 degrees clockwise about the origin, followed by translation 2 units to the left.
B. a rotation 90 degrees clockwise about the origin, followed by a reflection across the x-axis.
C. a rotation 180 degrees clockwise about the origin, followed by a reflection across the y-axis.
D. a rotation 90 degrees clockwise about the origin, followed by a translation 3 units to the right.
the correct answer is A. Option A describes a rotation of 180 degrees clockwise, which would result in figure 1 being upside down, and then a translation of 2 units to the left.
What is triangle?
A triangle is a three-sided polygon with three angles. It is a fundamental geometric shape and is often used in geometry and trigonometry.
To transform figure 1 into figure 3, we need to apply two transformations. We can eliminate option B because a rotation of 90 degrees followed by a reflection across the x-axis would transform figure 1 into a mirror image of figure 2, not figure 3.
Option A describes a rotation of 180 degrees clockwise, which would result in figure 1 being upside down, and then a translation of 2 units to the left. This would transform figure 1 into figure 3, so option A is a possible sequence of transformations.
Option C describes a rotation of 180 degrees clockwise followed by a reflection across the y-axis. This would transform figure 1 into a mirror image of figure 2, not figure 3.
Option D describes a rotation of 90 degrees clockwise followed by a translation of 3 units to the right. This would transform figure 1 into a position that is similar to figure 3, but the orientation of the triangle would be different.
Therefore, the correct answer is A.
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Arrange the steps in order to simplify the expression
Answer:
Step-by-step explanation:
For step explanation:
1. write the problem
2. distinguishing the neg sign
3. distributing 3
4. moving like terms next to each other through commutative property
5. Combining like terms
6. getting rid of parentheses
A race car driver won a 700 mile race with a speed of 192.9 miles per hour. Find the drivers time
9514 1404 393
Answer:
3:37:43.8
Step-by-step explanation:
The relevant relation is ...
time = distance / speed
time = (700 mi)/(192.9 mi/h) ≈ 3.628823 h
≈ 3:37:43.8 . . . . HH:MM:SS
The driver's time was about 3 hours, 37 minutes, 43.8 seconds.
_____
Additional comment
Multiply 60 minutes by the fraction of hours to get minutes.
60×0.628823 ≈ 37.729393 . . . minutes
Multiply 60 seconds by the fraction of minutes to get seconds.
60×0.729393 ≈ 43.76 . . . seconds
Intermediate values in the calculation should not be rounded. Full calculator precision should be maintained until the final answer.
20 students each rolled dice 5 times each to measure the median. Here is the data in the picture attached. What can we infer from this graph by looking at the median data?
A. when rolling a dice multiple times, the median is less likely to fall between numbers 1 and 6.
B. it's not possible to tell the likelihood of where the median is going to be when measuring probability since rolling dice is completely randomized, etc.
C. some other response
We can deduce that option A is likely to be true based on the given graph of rolling dice median data.
What is the median?The median is the value in the middle of a data set, which means that 50% of the data points have a value less than or equal to the median, and 50% of the data points have a value greater than or equal to the median.
The graph illustrates that the median value of the rolls is closer to the center of the possible outcomes (numbers 3, 4, and 5) than the extremes (numbers 1 and 6).
This implies that when rolling a dice several times, the median is less likely to fall between the numbers 1 and 6.
However, because rolling the dice is a random process, there is always a degree of uncertainty in predicting the outcomes.
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NO LINKS!! Each graph represents a relation. Determine the domain and range. 2ii
Answer:
7) Domain: (-∞, ∞)
Range: [-1, ∞)
8) Domain: (-∞, ∞)
Range: (-∞, ∞)
Step-by-step explanation:
Interval notation
( or ) : Use parentheses to indicate that the endpoint is excluded.
[ or ] : Use square brackets to indicate that the endpoint is included.
Domain & Range
The domain is the set of all possible input values (x-values).
The range is the set of all possible output values (y-values).
Question 5From inspection of the graph, the line is continuous.
The arrows either end of the line indicate that the line continues indefinitely in those directions.
Therefore, the domain of the relation is unrestricted: (-∞, ∞)
From inspection of the graph, the minimum y-value is y = -1.
The end behavior of the relation is:
\(y \rightarrow + \infty, \textsf{as } x \rightarrow - \infty\)
\(y \rightarrow + \infty, \textsf{as } x \rightarrow +\infty\)
Therefore, the range of the relation is restricted: [-1, ∞)
Question 6From inspection of the graph, the line is continuous.
The arrows either end of the line indicate that the line continues indefinitely in those directions.
Therefore, the domain of the relation is unrestricted: (-∞, ∞)
The end behavior of the function is:
\(y \rightarrow + \infty, \textsf{as } x \rightarrow - \infty\)
\(y \rightarrow -\infty, \textsf{as } x \rightarrow +\infty\)
Therefore, the domain of the relation is unrestricted: (-∞, ∞)
I. In the testing of a new production method, 18 employees were selected randomly and asked to try the new method. The sample mean production rate for the 18 employees was 80 parts per hour and the sample standard deviation was 10 parts per hour. Provide 90% confidence intervals for the populations mean production rate for the new method, assuming the population has a normal probability distribution.
Answer:
The 90% confidence interval for the mean production rate fro the new method is (75.9, 84.1).
Step-by-step explanation:
We have to calculate a 90% confidence interval for the mean.
The population standard deviation is not known, so we have to estimate it from the sample standard deviation and use a t-students distribution to calculate the critical value.
The sample mean is M=80.
The sample size is N=18.
When σ is not known, s divided by the square root of N is used as an estimate of σM:
\(s_M=\dfrac{s}{\sqrt{N}}=\dfrac{10}{\sqrt{18}}=\dfrac{10}{4.24}=2.36\)
The degrees of freedom for this sample size are:
\(df=n-1=18-1=17\)
The t-value for a 90% confidence interval and 17 degrees of freedom is t=1.74.
The margin of error (MOE) can be calculated as:
\(MOE=t\cdot s_M=1.74 \cdot 2.36=4.1\)
Then, the lower and upper bounds of the confidence interval are:
\(LL=M-t \cdot s_M = 80-4.1=75.9\\\\UL=M+t \cdot s_M = 80+4.1=84.1\)
The 90% confidence interval for the mean production rate fro the new method is (75.9, 84.1).
Can ANYONE please answer this ?
Hi dear! Can you help me to solve exercise #18 please!!!
Hello there. To solve this question, we'll have to remember some properties about dividing polynomials.
Given the polynomials, we want to evaluate the division:
\((1+3x+x^4)\div(3-2x+x^2)\)Rewriting it the way we perform long division:
We start with the higher degree terms, namely x^4 and x².
Dividing x^4 by x², we get x². Now we multiply every term from the division by this factor and subtract from the term being divided.
Now, we have a 2x³ as the higher degree term from the term being divided. Dividing it by x², we get 2x. Multiply each term of the divisor and subtract from it.
Finally, the highest degree term from the term being divided is x². Dividing it by x², we get 1. Multiply each term of the divisor and subtract it from the dividend.
Now, the highest degree term from the dividend is -x, when the highest degree term from the divisor is x². We cannot proceed with the long division anymore.
It means that we have a quotient:
\(x^2+2x+1\)And a remainder:
\(-x-2\)Notice if we rewrite it as:
\(x^4+3x^2+1=(x^2-2x+3)\cdot(x^2+2x+1)-x-2\)We have the division P(x)/D(x) written in the form:
\(P(x)=D(x)\cdot Q(x)+R(x)\)Where Q(x) and R(x) are the quotient and remainder polynomials.
calculate the perimeter of kite ABCD where AB = 29 cm and CD = 47 cm
Answer:
152 cm
Step-by-step explanation:
Perimeter of kite= 2(a+b)
P= 2(AB+CD) = 2(29+47) = 2 *(76) = 152 cm.
If something remains unclear, be free to ask questions!
2.
-6
5
-2
-1
2
0
-5
3
5
Vertex (give me the x and y coordinate):
Max or Min?:
Domain:
Range:
Zeroes (just tell me how many):
Axis of Symmetry:
Y-Intercept:
TE
What is \(\sqrt[3]{343} and \sqrt[3]{1728}\)
\( \sf \sqrt[3]{343} = 7 \\ \sf \sqrt[3]{1728} = 12\)
For the function f(x)=x+4−−−−−√
, the average rate of change to the nearest hundredth over the interval 2 ≤ x ≤ 6 is
The average rate of change of the function f(x) = √(x+4) over the interval 2 ≤ x ≤ 6 is approximately 0.29 to the nearest hundredth.
To find the average rate of change of the function f(x) = √(x+4) over the interval 2 ≤ x ≤ 6, we need to calculate the change in the function divided by the change in the input variable over that interval.
The change in the function between x = 2 and x = 6 is:
f(6) - f(2) = √(6+4) - √(2+4) = √10 - √6
The change in the input variable between x = 2 and x = 6 is:
6 - 2 = 4
So, the average rate of change of the function over the interval 2 ≤ x ≤ 6 is:
(√10 - √6) / 4
To approximate the answer to the nearest hundredth, we can use a calculator or perform long division to get:
(√10 - √6) / 4 ≈ 0.29
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PLEASE HURRY 100P I REALLY NEED THIS!!!!!
The range of the data is 30, and the interquartile range (IQR) is 15.
To create a box plot using the given data, we first need to determine the five-number summary, which includes the minimum value, the first quartile (Q1), the median (Q2), the third quartile (Q3), and the maximum value.
From the given data, we can determine the five-number summary as follows:
Minimum: 60
Q1: 70
Median (Q2): 80
Q3: 85
Maximum: 90
Now, let's create a box plot using this information:
```
| | | | |
60 |––––––––|––––––––| |
| | | | |
70 |––––––––|––––––––|––––––––|––––––––|
| | | | |
80 |––––––––|––––––––|––––––––|––––––––|
| | | | |
90 |––––––––|––––––––| |
| | | | |
------------------------------------
60 70 80 90
```
In the box plot, the line within the box represents the median (Q2), the box represents the interquartile range (IQR) from Q1 to Q3, and the lines extending from the box (whiskers) represent the minimum and maximum values. Any data points falling outside the whiskers would be considered outliers.
The range can be calculated as the difference between the maximum and minimum values:
Range = Maximum - Minimum = 90 - 60 = 30
The interquartile range (IQR) is the difference between the third quartile (Q3) and the first quartile (Q1):
IQR = Q3 - Q1 = 85 - 70 = 15
Therefore, the range of the data is 30, and the interquartile range (IQR) is 15.
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Find The Area Of The Shape Shown Below
Answer:42.55
Step-by-step explanation:
Les get the big boi out of the way first. We see that it is 3.5 by 9 and if we multiply we get 31.5. Next left triangle 2 by 2 so four but divided by 2 is 2. God so many 2's. So total is 33.5 so far. Next triangle is 2 by 5 soo 10 divided by 2 is 5. total is 38.5. Last dude in the middle. We know one side is two so we have to subtract here from the triangles which gets u the other side of 2 so 4. Total is 42.5
The Area of the Shape Shown is 42.5 square units.
What is Area of Rectangle?The area of Rectangle is length times of width.
The area of the rectangle in the given figure is
Area of rectangle=3.5×9
=31.5 square units.
The area of left side triangle is
Area of triangle=1/2×2×2
=2 square units
The area of right side triangle 1/2×5×2
=5 square units
Now the area of square =2²
=4 square units.
Now total area of figure is 31.5+2+5+4 is 42.5 square units.
Hence, the Area of the shape Shown is 42.5 square units.
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In this triangle, the product of sin B and tan C is
90°
and the product of sin C and tan B is
In this triangle, the product of sin B and tan C is\(b^2/(ac)\) , and the product of sin C and tan B is \(c^2/(ab)\).
In a right-angled triangle ABC, where angle A is 90 degrees, we have the following side lengths:
AB = c (base)
BC = a (hypotenuse)
AC = b (perpendicular)
We need to calculate the products of sin B and tan C, and sin C and tan B.
First, let's calculate sin B and tan C:
sin(B) = opposite/hypotenuse = AC/BC = b/a
tan(C) = opposite/adjacent = AC/AB = b/c
The product of sin B and tan C is sin(B) * tan(C) = (b/a) * (b/c) = \(b^2\)/(ac).
Next, let's calculate sin C and tan B:
sin(C) = opposite/hypotenuse = AB/BC = c/a
tan(B) = opposite/adjacent = AB/AC = c/b
The product of sin C and tan B is sin(C) * tan(B) = (c/a) * (c/b) = \(c^2\)/(ab).
Therefore, in the given right-angled triangle ABC, the product of sin B and tan C is\(b^2\)/(ac), and the product of sin C and tan B is \(c^2\)/(ab).
These formulas hold true for any right-angled triangle, where the base is AB, the hypotenuse is BC, and the perpendicular is AC.
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The question probable may be:
In this triangle, the product of sin B and tan C is _____ , and the product of sin C and tan B is _______.
Find the directional derivative of at the point (1, 3) in the direction toward the point (3, 1). g
Complete Question:
Find the directional derivative of g(x,y) = \(x^2y^5\)at the point (1, 3) in the direction toward the point (3, 1)
Answer:
Directional derivative at point (1,3), \(D_ug(1,3) = \frac{162}{\sqrt{8} }\)
Step-by-step explanation:
Get \(g'_x\) and \(g'_y\) at the point (1, 3)
g(x,y) = \(x^2y^5\)
\(g'_x = 2xy^5\\g'_x|(1,3)= 2*1*3^5\\g'_x|(1,3) = 486\)
\(g'_y = 5x^2y^4\\g'_y|(1,3)= 5*1^2* 3^4\\g'_y|(1,3)= 405\)
Let P = (1, 3) and Q = (3, 1)
Find the unit vector of PQ,
\(u = \frac{\bar{PQ}}{|\bar{PQ}|} \\\bar{PQ} = (3-1, 1-3) = (2, -2)\\{|\bar{PQ}| = \sqrt{2^2 + (-2)^2}\\\)
\(|\bar{PQ}| = \sqrt{8}\)
The unit vector is therefore:
\(u = \frac{(2, -2)}{\sqrt{8} } \\u_1 = \frac{2}{\sqrt{8} } \\u_2 = \frac{-2}{\sqrt{8} }\)
The directional derivative of g is given by the equation:
\(D_ug(1,3) = g'_x(1,3)u_1 + g'_y(1,3)u_2\\D_ug(1,3) = (486*\frac{2}{\sqrt{8} } ) + (405*\frac{-2}{\sqrt{8} } )\\D_ug(1,3) = (\frac{972}{\sqrt{8} } ) + (\frac{-810}{\sqrt{8} } )\\D_ug(1,3) = \frac{162}{\sqrt{8} }\)
If a = 2 and b = 3, what is the value of 2a³b2?
Answer:384
Step-by-step explanation:
first you multiply 2 times 2= 4 then 4 times 4 times 4= 64 then you multiply 3 times 2= 6 lastly you multiply 6 and 64. your welcome:)
Find the value of x and y. Select all that apply. Please show your work :) image is attached
Answer:
x = 29
y = 110°
Step-by-step explanation:
y° = (3x + 23)° => corresponding angles are congruent)
(2x + 12)° + y° = 180° => linear pair
Thus:
(2x + 12)° + (3x + 23)° = 180° => substitution
2x + 12 + 3x + 23 = 180
Add like terms
5x + 35 = 180
5x = 180 - 35
5x = 145
x = 145/5
x = 29
✔️y = (3x + 23)°
Plug in the value of x
y = 3(29) + 23
y = 110°
x(x+3)(x+3)=0
solve the equation only one answer
Answer:
0
Step-by-step explanation:
it says the answer is zero
pls help me with this
Answer:
the rule is multiply input by 25 then add 2, for example 2 x 25 = 50, 50 + 2 = 52
Step-by-step explanation:
this is because you minus 2 from the output to see the pattern from input. For example, 52 - 2 = 50 and to get from 2 to 50 you have to multiply by 25. This can be seen in the other numbers as well. Therefore the answer as a graph will be y = 25x + 2
Answer:
52 divided by 2 equal 26
102 divided by 4 equal 25.5
127 divided by 5 equal 25.4
177 divided by 7 equal 25.28
202 divided by 8 equal 25.25
Step-by-step explanation:
In one year, 30,000 sheep on his property in the next year because of the drought the farmer reduced his flock by 37% The number of sheep he has after the fall in numbers is
Answer:
11,100
Step-by-step explanation:
1% of 30,000 is 300 so if we times 300 by 37 we get 11,100
there is 11,100 sheep in 37%.
hope this helps :)
How many groups of 3/4 are in each of the following quantities?
Type your response in each box below.
1. 11/4 has __
groups of 3/4.
2. 6 1/2 has ___
groups of 3/4.
Answer:
vb\
Step-by-step explanation:
Five less than twice the sum of a number n and twelve
Three blocks are shown: Block A has mass 3 kilograms, length 8 centimeters, height 2 centimeters, and width 1 centimeters. Block B has mass 4 kilograms, length 1 centimeters, height 8 centimeters, and width 2 centimeters. Block C has mass 4 kilograms, length 8 centimeters, height 1 centimeters, and width 2 centimeters. Which statement is correct? (1 point) a Block A has the greatest density. b Block B has the least density. c The density of Block A is equal to the density of Block B. d The density of Block B is equal to the density of Block C.
Answer:
b & c
Step-by-step explanation:
for each parallel lines. you are given the measure of one angle
Answer:
The question is not complete
If 2 pounds of rib steak and 6 pounds of hamburger meat costs $12.30 and 3 pounds of rib steak and 2 pounds of hamburger meat costs $9.70, what is the cost per pound of each type of meat?
The cost per pound of rib steak is $2.40 and the cost per pound of hamburger meat is $1.25.
To find the cost per pound of each type of meat, we can set up a system of equations based on the given information.
Let's denote the cost per pound of rib steak as 'x' and the cost per pound of hamburger meat as 'y'.
From the first statement, we know that:
2x + 6y = 12.30 ---(Equation 1)
From the second statement, we know that:
3x + 2y = 9.70 ---(Equation 2)
Now we can solve this system of equations to find the values of 'x' and 'y'.
Multiplying Equation 1 by 3 and Equation 2 by 2 to eliminate the 'x' term, we get:
6x + 18y = 36.90 ---(Equation 3)
6x + 4y = 19.40 ---(Equation 4)
Subtracting Equation 4 from Equation 3, we get:
14y = 17.50
Dividing both sides by 14, we find:
y = 1.25
Substituting the value of 'y' back into Equation 1, we can solve for 'x':
2x + 6(1.25) = 12.30
2x + 7.50 = 12.30
2x = 4.80
x = 2.40
Therefore, the cost per pound of rib steak is $2.40 and the cost per pound of hamburger meat is $1.25.
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Find the 15th term of the geometric sequence 2,−8,32,...
Answer: first term (a)= 2
second term (b) = -8
common ratio (r) = -8/2 = -4
15th term = ar^ (n-1)
= 2* (-4)^ 14 =536870912
Step-by-step explanation:
Answer:
536,870,912
Step-by-step explanation:
the formula for geometric sequences is:
aₙ = a₁·\(r^{n-1}\)
where aₙ is, in this case the 15th term
r = common ratio which, in this case, is -4
a₁ = first value in the sequence
so:
a₁₅= 2(-4)^14
= 2(268,435,456)
= 536,870,912
Write x^2 - 8x + 10 in the form
(x + a)^2 + B
\(x^2-8x+10=x^2-8x+16-6=(x-4)^2-6\)