. Rural Speed Limits Rural speed limits for some states are indicated below. 60 mph 65 mph 70 mph 75 mph 1 17 15 7 Send data to Excel Choose one state at random. Find the probabilities of the following. Enter your answers as simplified fractions or decimals rounded to 3 decimal places. Part 1 of 3 (a) 60 or 65 miles per hour P (60 mph or 65 mph)

Answer:

A) 16 mm

just took the test

Answer:

16

Step-by-step explanation:

The required answer is  Mario should jump at least 17.1 units high to get over the barrel and avoid the oil fire.

Explanation:-

To determine how high Mario must jump to get over the barrel, we need to find the diameter of the barrel's bottom. We can do this by using the circumference value provided:

1. Recall the formula for the circumference of a circle: C = π * D, where C is the circumference and D is the diameter.
2. Plug in the given circumference: 53.40703 = π * D
3. Solve for D: D = 53.40703 / π
4. Calculate D: D ≈ 17

To determine how high Mario must jump to get over the barrel, we need to know the height of the barrel.  The circumference of the bottom of the barrel only tells us the distance around the circular base of the barrel, not the height.  we cannot calculate the height that Mario must jump to clear the barrel
Now that we know the diameter of the barrel, we can assume the height Mario must jump to be slightly more than the diameter to clear the barrel safely. Therefore, Mario should jump at least 17.1 units high to get over the barrel and avoid the oil fire.

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The distributed computation (e, →) is said to be consistent if all computations lead to the same result, regardless of the order in which the steps are performed.

Let g and h be consistent cuts of a distributed computation (e, →).

We must demonstrate that g ∪ h and g ∩ h are also consistent cuts of (e, →).

Let R be the set of events that are in both g and h. If we remove R from either g or h, we get a consistent cut since the removed events cannot cause a change in the outcome.

By removing R from both g and h, we obtain two new consistent cuts: g − R and h − R.

Thus, we can write:g = (g − R) ∪ R and h = (h − R) ∪ R. Since (g − R) and (h − R) are consistent cuts, it follows that their union, g ∪ h, is also a consistent cut. I

f we let S be the set of events that are in both g and h, then we can write:g = (g ∩ h) ∪ (g − S) and h = (g ∩ h) ∪ (h − S).

Again, (g − S) and (h − S) are consistent cuts, so their intersection, g ∩ h, is also a consistent cut.

Therefore, if g and h are consistent cuts of a distributed computation (e, →), then so are g ∪ h and g ∩ h.

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Answer:

2q

Step-by-step explanation:

The product of multiple quantities is basically multiplying them together so our answer is 2 * q or 2q.

When we add or subtract fractions, we always have to make sure that all the fractions involved have a common denominator.

We're given:

To find the fraction representing the remaining time, subtract \(\dfrac{1}{6}\) from \(\dfrac{2}{3}\):

\(\dfrac{2}{3}-\dfrac{1}{6}\)

⇒ Make both denominators the same; multiply \(\dfrac{2}{3}\) by \(\dfrac{2}{2}\) to change its denominator to 6:

\(= \dfrac{4}{6}-\dfrac{1}{6}\\\\= \dfrac{3}{6}\)

⇒ Simplify the fraction:

\(= \dfrac{1}{2}\)

Therefore, \(\dfrac{1}{2}\) the hour remained.

\(\dfrac{1}{2}\) the hour remained

Answer:185

Step-by-step explanation:the answer is 185 because you have to add

The true statements are (A) 30×400 ml equal the total number of milliliters for 30 bowls of soup

(B) 30 bowls of soup hold 12,000 ml, which is same as 12 Litres

(C) Noah can multiply the number of bowls of soup by 1,000 to find the number of litres

(D) If each family member has 2 bowls of soup , Noah need to make 24 litres of soup

There are 30 people and each person is served soup in a 400 ml bowl, so the total amount of soup needed is 30 × 400 ml = 12,000 ml.

Option A is true

30 bowls of soup hold 30 × 400 ml = 12,000 ml, which is the same as 12 litres (since 1 litre = 1,000 ml).

Option B is true

Since 1 litre = 1,000 ml

Noah can multiply the number of bowls of soup by 1,000 to find the number of litres.

For example, 30 bowls of soup hold 12,000 ml = 12 litres.

Option C is true

If each family member has 2 bowls of soup, then the total amount of soup needed is

30 × 2 × 400 ml

= 24,000 ml, which is 24 litres (since 1 litre = 1,000 ml).

Option D is true.

Noah needs to make 24 litres of soup, and each pot contains 6 litres of soup.

Therefore, he would need to make 24 ÷ 6 = 4 pots of soup to serve each family member 2 bowls of soup.

Option E is false.

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Noah is making soup for a family reunion of 30 people. Each pot he makes contains 6 liters of soup. He uses bowl that 400mL to serve the soup to his family

Select all the true statements

(A) 30×400 ml equal the total number of milliliters for 30 bowls of soup

(B) 30 bowls of soup hold 12,000 ml, which is same as 12 Litres

(C) Noah can multiply the number of bowls of soup by 1,000 to find the number of litres

(D) If each family member has 2 bowls of soup , Noah need to make 24 litres of soup

(E) Noah would need to make 2 pots of soup for each family member to have 2 bowls of soup

The value of the surface integral g for g = xyz over the hemisphere x^2 + y^2 + z^2 = 4 is zero.

To evaluate the surface integral g = xyz over the hemisphere x^2 + y^2 + z^2 = 4, we need to parameterize the surface and calculate the integral.

The equation x^2 + y^2 + z^2 = 4 represents a hemisphere centered at the origin with a radius of 2. We can parameterize this surface using spherical coordinates.

Let's use the spherical coordinates:

x = 2sinθcosφ

y = 2sinθsinφ

z = 2cosθ

To evaluate the surface integral, we need to calculate the surface area element dS in terms of the spherical coordinates. The surface area element in spherical coordinates is given by dS = |(∂r/∂θ) x (∂r/∂φ)| dθ dφ, where r = (x, y, z) is the position vector.

The position vector r in terms of spherical coordinates is:

r = (2sinθcosφ, 2sinθsinφ, 2cosθ)

Calculating the partial derivatives, we find:

∂r/∂θ = (2cosθcosφ, 2cosθsinφ, -2sinθ)

∂r/∂φ = (-2sinθsinφ, 2sinθcosφ, 0)

Taking the cross product of ∂r/∂θ and ∂r/∂φ, we get:

(2cosθcosφ, 2cosθsinφ, -2sinθ) x (-2sinθsinφ, 2sinθcosφ, 0) = (-4sin^2θcosφ, -4sin^2θsinφ, -4sinθcosθ)

The magnitude of this cross product is |(-4sin^2θcosφ, -4sin^2θsinφ, -4sinθcosθ)| = 4sinθ.

Therefore, dS = 4sinθ dθ dφ.

Now we can set up the integral:

∫∫g · dS = ∫∫(xyz) · (4sinθ dθ dφ)

Integrating with respect to θ first, we get:

∫[0,π]∫0,2π · (4sinθ dθ dφ)    

Since g = xyz, the integral becomes:    

∫[0,π]∫0,2π · (4sinθ dθ dφ) = ∫[0,π]∫0,2π dθ dφ

However, upon observing the integrand, we can see that it is an odd function with respect to θ. Since we are integrating over the entire hemisphere symmetrically, the integral of an odd function over a symmetric domain is always zero.

Therefore, the value of the surface integral g = xyz over the hemisphere x^2 + y^2 + z^2 = 4 is zero.    

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The quadratic function that models the path of the second kick is given by:

y = -2/125(x - 25)² + 10.

The equation of a quadratic function, of vertex (h,k), is given by the following rule:

y = a(x - h)² + k

In which the coefficients are explained as follows:

For the first kick, the equation is:

y = -1/40(x - 25)² + 15.

Meaning that the ball reached a maximum height of yards after an horizontal distance of 25 yards.

For the second kick, the horizontal distance is the same, but the maximum height if 5 yards less, that is, of 10 yards, hence the vertex is:

(h,k) = (25, 10).

Hence the equation is:

y = a(x - 25)² + 10.

After 50 yards, the ball hits the ground, hence the leading coefficient a is found as follows:

0 = a(50 - 25)² + 10

625a = -10

a = -10/625

a = -2/125

Hence:

y = -2/125(x - 25)² + 10.

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Answer:

3

Step-by-step explanation:

a tangent to a circle makes right angle with the radius at that point ( here the point is B)

thus,

ABC is a right angled triangle

By Pythagoras theorem :-

By Pythagoras theorem :-AC² = AB² + BC²

(r + 2)² = 4² + r²

r² + 4 + 4r = 16 + r²

subtracting r² from both sides and taking 4 common

4(1 + r) = 16

diving both sides by 4

1 + r = 4

r = 3 units

The value of r is,

⇒ r = 3 units

The Pythagoras theorem states that in a right triangle, the square of the hypotenuse is equal to the sum of the square of the other two sides.

Given that;

AB is tangent to circle C.

Now,

By Pythagoras theorem, we get:-

AC² = AB² + BC²

(r + 2)² = 4² + r²

r² + 4 + 4r = 16 + r²

subtracting r² from both sides and taking 4 common

4(1 + r) = 16

diving both sides by 4

1 + r = 4

r = 3 units

Thus, The value of r is,

⇒ r = 3 units

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To show that the general term of the quadratic number pattern is given by \(tn = n^2 + 4n - 12\) , we need to find a quadratic expression that fits the given pattern.

Let's examine the given sequence: -7, 0, 9, 20. We notice that each term is increasing by a certain amount.

First, let's find the differences between consecutive terms:
0 - (-7) = 7
9 - 0 = 9
20 - 9 = 11

We observe that the differences between consecutive terms are not constant, so this indicates that the sequence is not linear.

To determine if the sequence follows a quadratic pattern, let's find the second differences:
9 - 7 = 2
11 - 9 = 2

The second differences are constant, which suggests a quadratic pattern.

Now, let's find the quadratic expression. We know that the general term of a quadratic sequence can be written as \(tn = an^2 + bn + c\), where a, b, and c are constants to be determined.

Using the given terms, we can form three equations:

1.\(For n = 1: -7 = a(1)^2 + b(1) + c\)
2. \(For n = 2: 0 = a(2)^2 + b(2) + c\)
3.\(For n = 3: 9 = a(3)^2 + b(3) + c\)

Simplifying these equations, we get:
1. a + b + c = -7
2. 4a + 2b + c = 0
3. 9a + 3b + c = 9

Solving this system of equations, we find a = 1, b = 4, and c = -12.

Therefore, the general term of the quadratic number pattern is given by\(tn = n^2 + 4n - 12\).

The general term of the quadratic number pattern is \(tn = n^2 + 4n - 12\).

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Answer:

28 meters

Step-by-step explanation:

We measure altitude with respect to the sea level. The height of mount Everest 8,848 with sea level. Height at sea level is 0 m , it is assumed to be the reference. In this question because the sea bird is 28 meters above the surface of the ocean its elevation will be same as 28 m.  Hence we can say that the elevation of the sea bird will be 28 meters.  

Answer:

8 I think so 60 and ..

9. I think 5

Answer:

a_48000cm^3

b_48000000mm^3

Step-by-step explanation:

first of all, let's find the base area:

Ab=((b+B)h)/2=((10cm+30cm)20cm)/2=400cm^2

then, to find the volume, we need to multiplicate the base area to the height of the prism:

V=Ab*H=400cm^2*120cm=48000cm^3=48000000mm^3

1.92%   is the probability .

Describe probability using an example?

The probability of an event is the ratio of the size of the event space to the size of the sample space.  

The size of the sample space is the total number of possible outcomes  

The event space is the number of outcomes in the event you are interested in.  

so  

Let

x------> size of the event space

y-----> size of the sample space  

so

  P = x/y

Find out the probability that the first student selected will be left-handed

we have

 x = 6

 y = 40

substitute

 P = 6/40

Simplify

P = 3/20

the probability that the second student selected will be left-handed

we have

    x = 6 - 1  = 4

y = 40 -1 = 39

substitute

 P = 5/39

the probability that the 2 students selected will both be left-handed

Multiply the probabilities

   P = 3/20(5/39)  = 15/780

Convert to percentage

Multiply by 100

15/780 * 100 = 1.92%

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Answer: Times 5

Step-by-step explanation:

Answer:

Hey there. Heres ur answer

Fifth degree polynomials are also known as quintic polynomials. Quintics have these characteristics:

One to five roots.

Zero to four extrema.

One to three inflection points.

The mean of a data-set is obtained as the sum of all observations in the data-set divided by the number of observations in the data-set, which is also called the cardinality of the data-set.

Considering the midpoint rule from the histogram, we have that:

Hence the mean is calculated as follows:

Mean = (5 x 10 + 10 x 30 + 20 x 50 + 5 x 70)/(5 + 10 + 20 + 5)

Mean = 42.5 minutes.

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Yes, given explanation is correct.if the calculated test statistic is less than -1.645 then the null hypothesis can be rejected.

For test the claim that the proportion of people who smoke is less than 22.5%.

A one-tailed test of hypothesis can be used. Specifically, a one-sample z-test for a proportion can be used where:

Null hypothesis: p ≥ 0.225 (the proportion of people who smoke is equal to or greater than 22.5%)

Alternative hypothesis: p < 0.225 (the proportion of people who smoke is less than 22.5%)

The test statistic for the one-sample z-test for a proportion is calculated as:

z = (p - P0) / √[(P0 × (1 - P0)) / n]

where p is the sample proportion, P0 = the hypothesized proportion under the null hypothesis and n = The sample size.

If the calculated test statistic falls in the rejection region which is determined by the chosen significance level (e.g., alpha = 0.05) then the null hypothesis can be rejected and it can be concluded that there is evidence to support the claim that the proportion of people who smoke is less than 22.5%.

For a one-tailed test with alpha = 0.05, the critical value is -1.645.

Hence, if the calculated test statistic is less than -1.645 then the null hypothesis can be rejected.

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Answer:

519

Step-by-step explanation:

Let's assume that the scores for the national verbal proficiency test follow a normal distribution.

Mean score (μ) = 500

Standard deviation (σ) = 75

According to a Z-score table, the score for the 60th percentile is roughly z = 0.253

For any score "x", the z-score is given by:

\(Z=\frac{X-\mu}{\sigma}\)

For z = 2.53:

\(0.253=\frac{X-500}{75}\\X=519\)

The raw score to the 60th percentile is 519.

The most appropriate sampling plan for estimating the proportion of all adults in the medium-sized town who favor a tax increase to support the local school system is D) a random sample of 100 people from an alphabetical list of all adults who live in the town.

A random sample is needed to ensure that each member of the population has an equal chance of being included in the sample. Among the given options, a random sample of 100 people from an alphabetical list of all adults who live in the town is the most appropriate because it is a representative sample of the entire population of adults in the town.

The other options have potential sources of bias, as follows:

A random sample of 250 names from the local phone book may exclude people who do not have a phone or whose numbers are unlisted.

A random sample of 200 parents whose children attend one of the local schools may be biased towards those who have children in the school system, which may not accurately represent the views of all adults in the town.

A sample consisting of 500 people from the city who take an online survey about the issue may only capture the opinions of those who have access to the internet and are willing to participate in the survey, which may not represent the views of all adults in the town.

A random sample of 300 homeowners in the town may be biased towards those who own homes, which may not represent the views of all adults in the town.

Therefore, a random sample of 100 people from an alphabetical list of all adults who live in the town is the most appropriate sampling plan for estimating the proportion of all adults in the medium-sized town who favor a tax increase to support the local school system. So d is correct option.

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Answer:

For knowing the mode arrange it ascending order

83,88,90,95,96,97,98,98,98,100

The number over here occur the most is 98 so the mode of the following grade is 98

Hope this helps you

Answer: A.)

Step-by-step explanation:

1,296.

Answer:

I think the answer is 36

Part a: The volume of such base would appear to be larger than it was if the bubble was already let go before the titration's equivalence point.

Part b: There would be no impact if the bubble had already been let go after the equivalent point.

For the stated condition-

An air bubble was present in the buret tip as the student started his part II titration. Unnoticed bubble release occurred at some point in the titration.

The inaccuracy in his titration findings that the bubble would've have made if:

Part a: If the bubble had burst before the titration's equivalence point, the base's volume would have appeared larger than it originally was, having the base seem stronger than it is, and changing calculations.

Part b: There would be no impact if the bubble had already been let go after the equivalent point.

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False. It can be concluded that the faster a motor vehicle is traveling at the time of a crash, the more severe the injuries to the driver are

While the information states that there is a moderate positive correlation between the speed of the motor vehicle and the severity of injuries, correlation does not imply causation. Therefore, it cannot be concluded that the faster a motor vehicle is traveling at the time of a crash, the more severe the injuries to the driver are. Correlation simply indicates that there is a relationship between the two variables, but other factors may also be influencing the severity of injuries.

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Answer:

The area is 45 inches

Step-by-step explanation:

L×W=A

Answer:

g^-1(x)=1/4x+1/10

Step-by-step explanation:

y=4x-2/5

x=4y-2/5

4y-2/5=x

20y-2=5x

20y=5x+2

y=1/4x+1/10

g^-1(x)=1/4x+1/10