round your answer to one decimal place 109.918

The percentage of jerseys that were medium-sized jerseys is 35.71%

What is Percentage?

A percentage is a number or ratio expressed as a fraction of 100. It is often denoted using the percent sign, %

Given data ,

Total number of jerseys the football team has = 28 jerseys

Total number of jerseys that were medium sized = 10

So ,

Percentage of jerseys that were medium sized =
( Total number of jerseys that were medium sized / Total number of jerseys ) x 100

Percentage of jerseys that were medium sized = ( 10 / 28 ) x 100

= ( 5 / 14 ) x 100

= 7.14285 x 5

= 35.71 %

Therefore , the percentage of jerseys that were medium sized = 35.71%

Hence , the percentage of jerseys that were medium-sized jerseys is 35.71%

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the function is (5)(-10)

Answer:

5 movies

Step-by-step explanation:

Let x denotes number of movies that need to be ready each month for the total fees to be the same from either company.

Monthly membership fee charged by a video store = $7.50

Amount charged to rent each movie = $1.00

So,

total amount charged by the first store = \(7.50+(1)x=7.50+x\)

Monthly membership fee charged by another video store = $0

Amount charged to rent each movie = $2.50

So,

total amount charged by another store = \(0+2.50(x)=2.50x\)

To find number of movies that need to be ready each month for the total fees to be the same from either company,

solve \(7.50+x=2.50x\)

\(7.50+x=2.50x\\7.50=2.50x-x\\7.50=1.50x\\x=\frac{7.50}{1.50}\\ =5\)

Starting with 110mg of a radioactive substance, after 21 hours, 55mg remains. Using the exponential decay model, after 31 hours,  39.3mg of the substance will remain.

We can use the formula for exponential decay, which is:

N(t) = N0 * e^(-λt)

where:

N0 is the initial amount of the substance

N(t) is the amount remaining after time t

λ is the decay constant

To solve for λ, we can use the fact that after 21 hours, 55 mg remains:

55 = 110 * e^(-λ*21)

Simplifying:

0.5 = e^(-λ*21)

Taking the natural logarithm of both sides:

ln(0.5) = -21λ

Solving for λ:

λ = ln(0.5) / (-21) ≈ 0.033

Now we can use this value of λ to find the amount remaining after 31 hours:

N(31) = 110 * e^(-0.033*31) ≈ 39.3 mg

Therefore, approximately 39.3 milligrams of the substance will remain after 31 hours.

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a) To find the marginal cost, we need to find the derivative of the total cost function with respect to the rate of output (Q).

TC = 100Q - Q² + 0.3Q³

Marginal cost (MC) = dTC/dQ

= d/dQ(100Q - Q² + 0.3Q³)

= 100 - 2Q + 0.9Q²

To find the average cost, we need to divide the total cost by the rate of output (Q).

Average cost (AC) = TC/Q

= (100Q - Q² + 0.3Q³)/Q

= 100 - Q + 0.3Q²

b) To find the rate of output that results in minimum average cost, we need to find the derivative of the average cost function with respect to Q. Then, we set it equal to zero and solve for Q.

AC = 100 - Q + 0.3Q²

dAC/dQ = -1 + 0.6Q

= 0-1 + 0.6Q

= 00.6Q

= 1Q

= 1/0.6Q

≈ 1.67

Therefore, the rate of output that results in minimum average cost is approximately 1.67.

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The quadratic equation that represents the solution is F: p(x) = x² - 49.

The term "quadratic" refers to functions where the highest degree of the variable (in this example, x) is 2. A quadratic function's graph is a parabola, which, depending on the sign of the leading coefficient a, can either have a "U" shape or an inverted "U" shape.

Algebra, geometry, physics, engineering, and many other branches of mathematics and science all depend on quadratic functions. They are used to simulate a wide range of phenomena, including population dynamics, projectile motion, and optimisation issues.

Given that the solution of the quadratic function are x = -7 and x = 7 thus we have:

p(x) = (x + 7)(x - 7)

Solving the parentheses we have:

p(x) = x² - 7x + 7x - 49

Cancelling the same terms with opposite sign we have:

p(x) = x² - 49

Hence, the quadratic equation that represents the solution is F: p(x) = x² - 49.

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Clarence should poll at least 573 students to create a 98% confidence interval has an error bound of at most 4%.

To estimate the sample size needed to create a 98% confidence interval with an error bound of at most 4%, we need to use the following formula:

\(n = [z^2 \times p \times (1 - p)] / e^2\)

where:

n is the sample size we want to estimate

z is the z-value for the desired level of confidence (98% in this case), which is 2.33 (the closest value in the table is 2.326)

p is the estimated proportion of students who live more than three miles from the school,  we don't know yet

e is the maximum error bound, which is 4% or 0.04

To estimate p, we can use a pilot study or a previous survey if available. If not, we can use a conservative estimate of 0.5, which maximizes the sample size needed.

Plugging in the values, we get:

\(n = [(2.326)^2 \times 0.5 \times (1 - 0.5)] / 0.04^2\)

n ≈ 572.19

Rounding up to the nearest integer, we get a sample size of 573.

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Answer:

answer in the link below if you have any questions let me know

Answer:

≈ 0.14

Step-by-step explanation:

The average rate of change of f(x) in the closed interval [ a, b ] is

\(\frac{f(b)-f(a)}{b-a}\)

Here [a, b ] = [ - 1, 3 ] , then

f(b) = f(3) = \(\sqrt[3]{3+3}\) = \(\sqrt[3]{6}\) ≈ 1.817

f(a) = f(- 1) = \(\sqrt[3]{-1+3}\) = \(\sqrt[3]{2}\) ≈ 1.260 , then

average rate of change = \(\frac{1.817-1.260}{3-(-1)}\) = \(\frac{0.557}{4}\) ≈ 0.14 ( to the nearest hundredth )

Statistical analyses are least likely to be found in a (D) qualitative research.

Therefore, statistical analyses are least likely to be found in a (D) qualitative research.

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The electron domain charge cloud geometry of \(BrF_5\) is trigonal bipyramidal.

To determine the electron domain charge cloud geometry of \(BrF_5\), we need to examine the number of electron domains around the central atom (Br).

\(BrF_5\) consists of one central bromine atom (Br) surrounded by five fluorine atoms (F). Each bond and lone pair of electrons represents an electron domain.

In \(BrF_5\), there are five bonding pairs (Br-F) and no lone pairs around the central bromine atom. Therefore, the total number of electron domains is five.

Based on this information, the electron domain charge cloud geometry of \(BrF_5\) is trigonal bipyramidal.

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Answer: standard form: 2.3x 10⁴

               expanded form: 23.082

Answer:

+sqrt(29)

Step-by-step explanation:

Note that the change in x (horizontal leg) is 8 - 6, or 2, and that the change in y (vertical leg) is |2 - 7|, or 5.  According to the Pythagorean Theorem, the length of the hypotenuse of the right triangle created here is:

distance = +sqrt(2^2 + 5^2), or +sqrt(29)

Answer:

72.5mph

Step-by-step explanation:

There is an easy way to work this. Divide the miles he drove by 2 so that you know how much he drove in 1/5 hours.

29/2= 14.5miles driven in 1/5 hours

Now, just multiply that number by 5 so that you know how many miles he drove in 5/5 hours (one full hour).

14.5*5= 72.5miles

For a survey of community related to build a police substation in their nearby, from binomial distribution the probability that the number favoring the substation is more than 12 is 0.398.

We have a survey related to community view regarding building a police substation in their nearby. Let X be an event for favouring the building a police substation in their nearby. The

Probability of community favored building a police substation in their neighborhood = 80% = 0.80

Total number of selected citizens = 15

We have to determine the probability that the number favoring the substation is more than 12. Using Binomial probability distribution, P( X = x) = ⁿCₓ pˣ( 1- p)⁽ⁿ⁻ˣ⁾

where, p --> probability of success

x -> number of success

n -> total number of trials

here, n = 15, p = 0.80, x = 12, substitute all known values in above formula, P( X >12) = P( X= 13) + P( X = 14) + P(X = 15)

= ¹⁵C₁₃ 0.8¹³(0.2)² + ¹⁵C₁₄ 0.8¹⁴(0.2)¹ + ¹⁵C₁₅0.8¹⁵ 0.2⁰

= 0.231 + 0.132 +0.035

= 0.398

Hence, the required probability is 0.398.

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The equivalent expressions of \(x^3\) are\(\frac{(x ^ 6)}{(x ^ 3)}\)and \(\frac{(x^{-3}) }{(x^{-6}) }\), the expressions \(\frac{(x^{30}) }{(x^{10})}\) and \(\frac{(x ^ 4) ^ 2)}{x ^ 2}\) are not equivalent to \(x^3\).

What are equivalent expressions?

Equivalent expressions are different algebraic expressions that have the same value when evaluated for a particular set of variables.

The equivalent expressions  \(x^3\) are:

\(\frac{(x ^ 4) ^ 2)}{x ^ 2}\) : This expression can be simplified as follows:

=\(\frac{(x ^ 4) ^ 2)}{x ^ 2}\)

= \(\frac{(x ^ 8)}{(x ^ 2) }\)

=\(x^{8-2}\)

= \(x^6\)

\(\frac{(x ^ 6)}{(x ^ 3)}\) : This expression can be simplified as follows:

=\(\frac{(x ^ 6)}{(x ^ 3)}\)

= \(x^{6-3}\)

=\(x^3\)

\(\frac{(x^{30}) }{(x^{10})}\) : This expression can be simplified as follows:

=\(\frac{(x^{30}) }{(x^{10})}\)

=\(x^{30-10}\)

=\(x^{20}\)

\(\frac{(x^{-3}) }{(x^{-6}) }\) : This expression can be simplified as follows:

=\(\frac{(x^{-3}) }{(x^{-6}) }\)

=\(x^{-3-(-6)}\)

=\(x^{-3+6}\)

=\(x^{3}\)

Therefore, the equivalent expressions of \(x^3\) are\(\frac{(x ^ 6)}{(x ^ 3)}\)and \(\frac{(x^{-3}) }{(x^{-6}) }\) , the expressions \(\frac{(x^{30}) }{(x^{10})}\) and \(\frac{(x ^ 4) ^ 2)}{x ^ 2}\) are not equivalent to \(x^3\).

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Answer:

Step-by-step explanation:

Answer:

No association

Step-by-step explanation:

This type of data is usually random; think about it, how could what gender person you are affect how you survive? Children may have a higher chance, but that's primarily based on health. Women is about 3/4 and men about 1/4.

Hope this helps.

If we want to know how much money will be in the account Bob is 18 years old, we can substitute x = 18 into the function:

A(18) = 500 × (1.06)¹⁸

To describe the amount of money in Bob's account when he is x years old, we can use exponential growth with the given annual growth rate of 6%.

Let A(x) represent the amount of money in the account when Bob is x years old.

We know that initially, when Bob was born, $500 was put into the account.

So, we have:

A(0) = $500

Since the account grows annually by 6%, we can express the growth rate as 1 + 6% = 1 + 0.06

= 1.06 (including the initial amount).

For each year that passes, the account grows by a factor of 1.06.

We can define the exponential growth function as:

A(x) = 500 × (1.06)ˣ

In this function, x represents the number of years since Bob was born, and A(x) gives us the amount of money in the account at that age.

Calculating this value will give us the amount of money in the account at that age.

Function assumes continuous compounding of interest and does not take into account any additional deposits or withdrawals made during the period.

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Answer: 10/12 0r 5/6

Step-by-step explanation:

The y-intercept of the line represented by the equation is; 60.

It follows from the task content that the y-intercept of the line represented by the equation is to be determined.

On this note, we must recall that the y-intercept of an equation is the value of y when x = 0.

Therefore, we have;

-60 (0) + 2y - 120 = 0

2y = 120

y = 60.

Hence, the y-intercept of the line represented by the equation is; 60.

Consequently, it can be inferred that the Ernesto is wrong in his evaluation of the y-intercept as 30.

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Answer:

Yes

Step-by-step explanation:

12²=144

16²=256

20²=400

Since 144+256=400, 12, 16, and 20 can form a right triangle

By using Pythagoras theorem AB^2+BC^2=CA^2

12^2+16^2=20^2

144+ 256=200

yes 12in, 16in and 20in forms a triangle

Answer:

0

Step-by-step explanation:

-1-3 = -4

-(-9) = + 9

-4 + 9 = 5

5 + (-5) = 5-5

5-5 = 0

Answer:

x = 8 is the answer

Step-by-step explanation:

2:4 = x : 16

x = 8

Answer: 8

Step-by-step explanation:

given:

2:4=x:16

2×16= 4x

32/4 = x

x=8

Answer:

3744:\p=11756.16 m^2

Step-by-step explanation:

\( {12}^{2} \pi(18 + 9) - {4}^{2} \pi \times 9 = 3744\pi \: \: {m}^{2} \)

Answer:

-25

Step-by-step explanation:

C=5p+125

-125=5p

-125/5=p

-25=p

Therefore, p= -25

The solution of the equation 3z minus 2 is equal to 46 is 16.

The given equation '3z minus 2 is equal to 46' can be written as

    3z - 2  =   46

Now solving for z because the value of z will give the required solution of the given equation. So now finding the z from the equation:

   3z = 46  + 2

   3z =  48

   z = 48/3

   z = 16

The value of the z is 16 which represents the solution of the given equation i.e 3z minus 2 is equal to 46.

Therefore it is concluded that the solution of the equation 3z minus 2 is equal to 46 is 16.

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The two-columns method can be used to prove that the triangles ΔABC and ΔADC are congruent (ΔABC ≅ ΔADC), by completing the included table as follows;

Step \({}\)                          Statement                  \({}\)              Reason

1  \({}\)                              \(\overline{AD}\) ≅ \(\overline{AB}\)   \({}\)                            

 \({}\)                                \(\overline{AB}\) ⊥ \(\overline{BC}\)          \({}\)                        Given

\({}\)                                  \(\overline{AD}\) ⊥ \(\overline{DC}\)                                

2. \({}\)                ΔABC and ΔADC are right Δs              Definition

3. \({}\)       \(\overline{AC}\) is the hypotenuse side of the right Δs   Definition

4.     \({}\)                         \(\overline{AC}\) ≅ \(\overline{AC}\)                                   Reflexive property

5. \({}\)                          ΔABC ≅ ΔADC                            HL congruency rule

Congruent triangles are triangles in which the lengths of the three sides of each triangle are the same measure with the lengths of the three sides of the triangle with which they are congruent.

The details of the reasons used to prove the congruency of the triangles ΔABC and ΔADC, are presented as follows;

Definition of right triangles

A right triangle is a triangle that has an interior angle of 90°. The angle formed between two perpendicular lines is 90°.

The sides \(\overline{AB}\) and \(\overline{BC}\) of the triangle ΔABC are perpendicular, thereforte, the angle ∠B is 90°

Similarly, the sides \(\overline{AD}\) and \(\overline{DC}\) are perpendicular, therefore, the measure of the angle D, m∠D is 90°

Therefore, the triangles ΔABC and ΔADC are right triangles

Hypotenuse side of a right triangle

The hypotenuse side of a right triangle is the side linking the perpendicular sides and facing the 90° angle

HL congruency rule

The Hypotenuse-Leg (HL) congruency rule states that if the hypotenuse side and a leg of a right triangle are congruent to a hypotenuse side and a leg of a right triangle, the two right triangles are congruent.

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Answer:

B)

a + c = 7

9a + 4c = $43

Step-by-step explanation:

There're 7 tickets which were bough in total. Two different types of tickets, one which represented children, the other for adults. The adult ticket is represented by a and is 9 dollars. The children's ticket is represented by c and is 4 dollars.

Have a nice April Fool's XD.

We assume that with a linear relationship between two variables, for any fixed value of x, the observed residuals follows a normal distribution.

This assumption is based on the Central Limit Theorem, which states that when the sample size is large enough, the distribution of sample means will be approximately normal, regardless of the shape of the underlying population distribution.

In the case of a linear relationship between two variables, we can assume that the residuals (the difference between the observed y values and the predicted values based on the linear regression model) follow a normal distribution with mean 0 and constant variance. This assumption is important because it allows us to use statistical methods that rely on normality, such as hypothesis testing and confidence intervals.

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An Endure chosen randomly the likelihood of any battery lasting longer than 550 hours is 10.56%.

These steps are used to determine the Z score:

z = (x - μ)/σ

As mentioned in question-

x > 550 and μ = 500, σ = 40:

z = 550 - 500 / 40

z = 1.25

Obtain the p-value from normal distribution chart,

P(z > 1.25) = 1 - P(z < 1.25)

P(z > 1.25) = 1 - 0.8944

P(z > 1.25) = 0.1056

Thus, an Endure chosen at random the likelihood of any battery lasting longer than 550 hours is 10.56%.

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