From the sun to Alpha Centauri than from the sun to Jupiter it is 105 times further. The age of Alpha Centauri is 5.3 billion years older. It also moves in a totally different way. Even though it is close by, it is only passing.
What if Alpha Centauri replaced the position of the Sun?Alpha Centauri A is around 100,000 miles farther away, 10% more massive, and a little bigger than our Sun. All of the planets' orbits will become more elliptical as a result of the increased mass. The reality that Alpha Centauri A is 50% brighter than our star, placing Earth slightly inside the habitable zone, is much worse for the Earth. Most of Earth's surface is currently uninhabitable due to its average surface temperature of 43 degrees Celsius, according to Universe Sandbox 2. It has been clearly stated to us, though, that a temperature so high would most likely lead to an uncontrollable greenhouse effect by increasing the amount of water vapor in the atmosphere.
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Find the transfer function (for part (a), a(s) = vout/iin; for part (b), a(s) = vout/vin) and draw the bode plot describing this transfer function for the following circuits. label everything clearly
To find the transfer function and draw the Bode plot for the given circuits, we need to analyze the circuit and identify the relationship between the output voltage and input current or input voltage, depending on the part (a) or (b).
(a) For part (a), where a(s) = vout/iin:
1. Analyze the circuit and determine the voltage across the output and current flowing into the input.
2. Write an expression for the transfer function a(s) by taking the Laplace transform of the circuit.
3. Simplify the expression for a(s) by canceling common terms and rearranging if necessary.
4. The resulting expression represents the transfer function a(s) for part (a).
(b) For part (b), where a(s) = vout/vin:
1. Analyze the circuit and determine the voltage across the output and the voltage applied at the input.
2. Write an expression for the transfer function a(s) by taking the Laplace transform of the circuit.
3. Simplify the expression for a(s) by canceling common terms and rearranging if necessary.
4. The resulting expression represents the transfer function a(s) for part (b).
To draw the Bode plot:
1. Substitute jω for s in the transfer function, where ω is the angular frequency.
2. Separate the transfer function into its magnitude and phase components.
3. Plot the magnitude response on a logarithmic scale for the frequency axis.
4. Plot the phase response on a linear scale for the frequency axis.
5. Label the axes and provide appropriate scaling.
6. The resulting Bode plot describes the transfer function of the circuit.
Remember to label everything clearly on the Bode plot, including the frequency axis, magnitude axis, and phase axis. Additionally, provide any necessary scaling information to accurately represent the circuit's response.
In summary, to find the transfer function and draw the Bode plot for the given circuits:
1. Analyze the circuit and determine the relationship between the output and input.
2. Write the transfer function expression by taking the Laplace transform.
3. Simplify the expression if possible.
4. For part (a), a(s) = vout/iin; for part (b), a(s) = vout/vin.
5. Substitute jω for s in the transfer function to plot the Bode plot.
6. Separate the transfer function into magnitude and phase components.
7. Plot the magnitude response on a logarithmic scale and the phase response on a linear scale.
8. Label everything clearly on the Bode plot.
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Calculate the energy that 1.5 kg of mass contains
Answer:
\(4.5(10)^8\) joules
Explanation:
Mass–energy equivalence is the principle that says that anything that has mass has an equivalent amount of energy. Converse is also true.
The relation between energy and mass is given by \(E=mc^2\)
Here, E denotes energy, m denotes mass and c denotes speed of light
Mass \((m)=1.5\,\,kg\)
Speed of light (c) = 3 × \(10^8\) m/s
Therefore,
\(E=1.5(3)(10)^8=4.5(10)^8\) joules.
The S.I. unit of energy is joules which is equal to \(1\,\,kg\,\,m^2/s^2\)
Consider a single slit that produces its first minimum at 59° for 620 nm light.
The width of the slit is 482 nm. The first minimum in a single slit diffraction pattern occurs at an angle given by the equation sinθ = λ/b,
where θ is the angle between the center of the diffraction pattern and the location of the minimum, λ is the wavelength of the light, and b is the width of the slit.
In this case, we are given that the first minimum occurs at 59° for 620 nm light.
Using the equation, we can solve for the width of the slit as b = λ/sinθ. Plugging in the values, we get b = (620 nm)/(sin(59°)) = 482 nm. Therefore, the width of the slit is 482 nm.
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The acceleration of an object is ____________________ related to the net force exerted upon it and _____________________ related to the mass of the object.
The acceleration of an object is directly related to the net force exerted upon it and inversely related to the mass of the object.
answer : directly , inversely
When operating a boat faster than idle speed, the operator must stay at least ______ feet from any other boats, people in water, dock or other structures?.
When operating a boat faster than idle speed, the operator must stay at least 100 feet from any other boats, people in water, dock or other structures.
What is speed?The speed of any moving object is the ratio of the distance covered and the time taken to cover that distance.
Speed s = distance d / time t
The 100-foot regulation states that No individual will operate any boat or people on water skis, an aquaplane, a surfboard, or any comparable gadget on the waters when a speed more prominent than idle speed.
Thus, when operating a boat faster than idle speed, the operator must stay at least 100 feet from any other boats, people in water, dock or other structures.
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calculate the weight of an object of mass 100 kg on the surface of a Planet whose mass and diameter are 4.8*10^24 kg and 12000km respectively.
The weight of an object mass of 100 kg on the surface of a Planet willl is 981 N.
What is weight?
The weight of matter is found as the product of the mass and the gravitational acceleration;
Given data;
Weight of an object,W =?
Mass,m = 100 kg
\(\rm W= mg \\\\ \rm W= 100 \ kg \times 9.81 \ m/sec^2 \\\\ W=981 \ N\)
Hence the weight of an object willl be 981 N.
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what made the dinosaurs instinct
Answer:
Eruptions/Volcano
Explanation:
poop fell from the sky
The diagram shows a stone tied to a string in circular
motion. If the string breaks, what will be the direction of
motion of the stone?
Answer:
Newton's First Law of motion states that an object will continue to move in a straight line or remain at rest unless a force acts on it
The stone is able to move in circular motion because a (centripetal) force acts through the string on it, which maintains the circular motion, by turning the stone to the circular path as the stone moves with momentary velocity along a straight line which is (therefore) tangential to the circle
Therefore, at the point the spring breaks, the centripetal force is no longer acting on the stone to change its path and the motion of the continues on the tangent to the initial circular motion path at that point
Explanation:
The Round Up carnival ride below has a radius of 3.62 meters and rotates 0.537 times per second. As shown, riders can be held up by only friction. What coefficient of friction is needed to keep the riders from sliding down? Include units in your answer. Answer must be in 3 significant digits.
The free body diagram for the problem is shown below:
If the people don't slide down this means that the friction has to be equal to the Weight, then we have:
\(\begin{gathered} F_f-W=0 \\ F_f=W \\ \mu F_n=W \\ \mu=\frac{W}{F_n} \end{gathered}\)Now, from newton's second law we have that:
\(F_n=ma_c\)but
\(a_c=\frac{4\pi^2r}{T^2}\)then:
\(F_n=\frac{4\pi^2mr}{T^2}\)And then we have:
\(\begin{gathered} \mu=\frac{mg}{\frac{4\pi^2mr}{T^2}} \\ \mu=\frac{gT^2}{4\pi^2r} \end{gathered}\)Plugging the values given we have:
\(\begin{gathered} \mu=\frac{(9.8)(\frac{1}{0.537})^2}{4\pi^2(3.62)} \\ \mu=0.238 \end{gathered}\)Therefore the coefficient of friction is 0.238
State Coulomb’s Law equation and give the meaning of every variable and the units.
The Coulomb's law equation is F = Kq₁q₂/r².
What is Coulomb's law?This is the law that relates the product of two charges to the square of distance between the two charges.
Coulomb's law states that the force of attraction or repulsion is directly proportional to the product of the charges and inversely proportional to the square of distance between the charges.
Coulombs' law equationThe equation of Coulomb's law is given as;
F = Kq₁q₂/r²
where;
K is Coulomb's constant, Nm²/C²q₁ is the first charge, Cq₂ is the second charge, C)r is the distance between the charges, mThus, the Coulomb's law equation is F = Kq₁q₂/r².
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What is the size of the force acting on a copper wire with a magnetic flux density of 3.6 x 10-2 T acting at
right angles to the wire of length 24 m and current of C:048 A? Give your answer to an appropriate
number of significant figures.
Answer:
F = 0.414 N
Explanation:
Given that,
Magnetic flux density,\(B=3.6\times 10^{-2}\ T\)
The length of the wire, l = 24 m
Current, I = 0.48 A
We need to find the force acting on the wire. The formula for the force is given by:
\(F=ILB\)
Put all the values,
\(F=0.48\times 24\times 3.6\times 10^{-2}\\\\F=0.414\ N\)
So, the force acting on the copper wire is equal to 0.414 N.
The magnetic force of the copper wire is 41.472 N.
Magnetic force of the copper wire
The magnetic force of the copper wire is calculated by applying the following equation.
F = BIL x sinθ
Where;
θ is the inclination of the magnetic fieldI is the currentL is the length of the wireB is the magnetic field strength = flux densityF = (3.6 x 10⁻²) x (48) x 24 x sin(90)
F = 41.472 N
Thus, the magnetic force of the copper wire is 41.472 N.
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a pulley of radius 0.9m is used to lift a bucket from the well. if it took 3.6 rotations for the pulley to take water out of the well,how deep is water in the well?
Answer:
h = 20.36[m]
Explanation:
To solve this problem we must calculate the perimeter (length of a circumference) of the circumference, which is denoted by the following equation:
L = 2*π*r
where:
r = radius = 0.9[m]
π = 3.1416
L = 2*(3.1416)*(0.9)
L = 5.654[m]
Now we know that the pulley or circumference had to rotate 3.6 times to get the water out of the well. In this way the depth of the well can be calculated by means of the following equation:
h = 3.6*L
h = 3.6*5.654
h = 20.36[m]
Can you please answer me this question? ITS A SCIENCE QUESTION (GRADE 6)
A dog walks 8.0 meters due north and then 6.0 meters due east.
Determine the magnitude of the dog's total displacement to the nearest tenths place.
Answer:
10.0mExplanation:
The displacement of the dog is the distance moved in a specified direction. It will be gotten using pythagoras theorem as shown;
d² = 8²+6²
d² =64+36
d² = 100
square root both sides
√d² = √100
d = 10m
Hence the displacement of the dog to the nearest tenth is 10.0m
When your car moves along the highway at constant velocity, the net force on it is zero. Why, then, do you have to keep running your engine? a. To keep things like your radio and air conditioning running b. In case you have to suddenly accelerate C. To overcome frictional forces
The reason you have to keep running your engine when your car is moving at a constant velocity on the highway is to overcome frictional forces.
So, the correct answer is C.
Understanding Frictional forcesWhen your car is moving along the highway at a constant velocity, the net force acting on it is zero. However, you still need to keep running your engine to overcome the frictional forces acting on your car.
Frictional forces such as air resistance, rolling resistance, and the resistance caused by the engine and transmission of your car all act against the motion of your car.
Therefore, your engine needs to continue to produce power to counteract these forces and maintain your car's speed.
Additionally, keeping your engine running is important to power essential features of your car, such as your radio and air conditioning, and to prepare for sudden acceleration needs, such as when merging onto a highway or passing another vehicle.
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Which effect has been useful (and successful) in the search for and identification of black holes in the universe
Answer:
Detection of x-rays from a binary star undergoing mass exchange, where mass of component star can be determined.
A 23-N force is applied to a 7-kg object to move it with a constant velocity of 6.1 m/s across a level surface. The coefficient of friction between the object and the surface is approximately ____. Round your answer to the hundredths place.(Use the approximation g ≈ 10 m/s2.)
Given:
The applied force is F = 23 N
The mass of the object is m = 7 kg
The object moves with a constant velocity of v = 6.1 m/s
The acceleration due to gravity is g = 10 m/s^2
Required: The coefficient of friction between the object and the surface.
Explanation:
The object moves at a constant velocity, so the acceleration will be zero.
The equation of motion can be written as
\(\begin{gathered} F-f\text{ = ma} \\ F-f\text{ =m}\times0 \\ F-f=0 \\ F=f \end{gathered}\)So, the applied force will be equal to the frictional force.
The coefficient of friction can be calculated as
\(\begin{gathered} F\text{ = }\mu mg \\ \mu=\frac{F}{mg} \end{gathered}\)On substituting the values, the coefficient of friction will be
\(\begin{gathered} \mu=\frac{23}{7\times10} \\ =\text{ 0.33} \end{gathered}\)Thus, the coefficient of friction is 0.33
Final Answer: The coefficient of friction between the object and the surface is 0.33.
A mass attached to a spring oscillates back and forth as indicated in the position vs. time plot below. At point P, the mass has:
1. negative velocity and negative acceleration.
2. zero velocity but is accelerating (positively or negatively).
3. zero velocity and zero acceleration.
4. negative velocity and positive acceleration.
5. positive velocity and negative acceleration.
6. negative velocity and zero acceleration.
7. positive velocity and positive acceleration.
8. positive velocity and zero acceleration.
Based on the position vs. time plot, we can see that at point P, the mass is at the equilibrium position of the spring, meaning that it is not displaced from its resting position. Therefore, we can conclude that the mass has zero velocity at point P. Therefore, the correct answer is option 3: zero velocity and zero acceleration.
We know that the acceleration of the mass is directly proportional to the displacement from equilibrium and is always directed toward the equilibrium position. Therefore, if the mass is moving towards the equilibrium position at point P, it will have a negative acceleration. Conversely, if the mass is moving away from the equilibrium position at point P, it will have a positive acceleration.
Therefore, the correct answer is option 3: zero velocity and zero acceleration. The mass is neither moving away from nor toward the equilibrium position, so it has zero acceleration. Additionally, since it is at the equilibrium position, it has zero velocity.
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If her mother's speed is 5.1 m/s when the ride is in motion, what is her angular momentum around the center of the merry-go-round
The angular momentum of the girl's mother around the center of the merry-go-round is 44.1 kg m^2/s.
The angular momentum of the girl's mother around the center of the merry-go-round can be calculated using the formula L = Iω, where L is the angular momentum, I is the moment of inertia, and ω is the angular velocity.
Since we are given the speed of the mother and not the angular velocity, we need to first convert the speed to angular velocity using the formula ω = v/r, where v is the linear speed and r is the radius of the circle.
Assuming the radius of the merry-go-round is 10 meters, we can calculate the angular velocity of the mother as:
ω = 5.1 m/s / 10 m
ω = 0.51 rad/s
Next, we need to calculate the moment of inertia of the mother. Assuming she has a mass of 60 kg and is standing with her arms outstretched, her moment of inertia can be calculated using the formula \(I = mr^2,\) where m is the mass and r is the distance from the axis of rotation.
Assuming her arms are outstretched to a distance of 1.2 meters from the axis of rotation, we can calculate the moment of inertia as:
\(I = 60 kg * (1.2 m)^2\)\(L = 86.4 kg m^2 *0.51 rad/s\)
\(L = 86.4 kg m^2 * 0.51 rad/s\)
Finally, we can calculate the angular momentum of the mother as:
L = Iω
L = 86.4 kg m^2 * 0.51 rad/s
\(L = 44.1 kg m^2/s\)
Therefore, the angular momentum of the girl's mother around the center of the merry-go-round is 44.1 kg m^2/s.
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Which statement describes the relationship between bond strength and the melting and boiling points of a substance? A. As the force between the particles increases, the melting and boiling points also increase. O B. As the force between the particles increases, the melting point decreases and the boiling point increases. O C. As the force between the particles increases, the melting and boiling points decrease. O D. As the force between the particles increases, the melting point increases and the boiling point decreases. SUBMIT
Answer:
a
Explanation:
Ms. Estes shows her class a video from when she worked at the space center launching rockets. She asks her students which of the following items in the video were examples of Newton's first law of motion? (1 point)
-- The rocket accelerating rapidly off the launch pad
-- The astronaut being pushed back into his seat as the rocket accelerates
-- The astronaut experiencing zero gravity in orbit
-- The booster rocket falling back into the ocean after the launch
The astronaut being pushed back into his seat as the rocket accelerates - this was the example of Newton's first law of motion.
What is Newton's first law of motion?According to Newton's First Law, a body in uniform motion or at rest will remain in that state up to and unless a net external force acts on it.
When the astronaut worked at the space center launching rockets, no force is worked on him. When the rocket accelerates, according to Newton's first law of motion, the astronaut remains in same motion, that's why, he pushed back into his seat .
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need some help please.
Answer:
The x - component of vector B is determined as -18.3 m.
What is x-component of a vector?
The x-component or horizontal component of a vector is the value of the vector acting or pointing x direction or in a horizontal direction.
The x-component or horizontal component of a vector on a given plane calculated as follows;
Bx = B cos(θ)
where;
B is the magnitude of the vectorθ is the angle of inclination of the vectorThe given parameters include the following;
the angle of inclination of the vector from the horizontal direction, θ = 170⁰the magnitude of vector B = 18.6 mSubstitute the given parameters into the above equation and for the x-component of vector b.
Bx = 18.6 x cos(170)
Bx = -18.3 m
Thus, from the magnitude of vector B in the image, the value of vector B in x - direction is -18.3 m.
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A satellite is orbiting Earth at a distance of 42.0 kilometers. The satellite has a mass of 900kilograms. What is the force between the planet and the satellite? Hint: Recall Earth's mass aradius from earlier problems.
Answer:
8716.97 N
Explanation:
The force between the planet and the satellite can be calculated using the following equation
\(F=G\frac{m_1m_2}{d^2}\)Where G = 6.67 x 10^(-11) N m²/kg², m1 is the mass of the satellite, m2 is the mass of the Earth and d is the distance from the center of the Earth to the satellite
Since the radius of the Earth is 6,371 km, we get
d = 42 km + 6,371 km = 6413 km
Then, to convert to m, we need to multiply by 1000
d = 6413 km x 1000 m/km = 6.413 x 10^6 m
Finally, replacing m1 = 900 kg, m2 = 5.972 x 10^24 kg, and d = 6.413 x 10^6 m, we get:
\(\begin{gathered} F=6.67\times10^{-11}\frac{(900)(5.972\times10^{24})}{(6.413\times10^6)^2} \\ F=8716.97\text{ N} \end{gathered}\)Therefore, the force between the planet and the satellite is 8716.97 N
Why is Florida more vulnerable to the effects of climate change?
Answer:
Along the Atlantic and Gulf Coasts of Florida, the land surface is also sinking. If the oceans and atmosphere continue to warm, sea level along the Florida coast is likely to rise one to four feet in the next century. Rising sea level submerges wetlands and dry land, erodes beaches, and exacerbates coastal flooding.
Explanation:
A series RLC circuit has 75 Ω, 18 mH , and a resonant frequency of 5.0 kHz . Part A: What is the capacitance? Part B: What is the impedance of the circuit at resonance? Part C: What is the impedance at 4.0 kHz ?
A: Part A: 10.6 nF, B: Part B: 75 Ω, C: Part C: 106 Ω
We used the formula for resonant frequency to calculate the capacitance, the formula for impedance at resonance to calculate the impedance of the circuit. at resonance, and the formula for impedance at a specific frequency to calculate the impedance at 4.0 kHz, using the given values of resistance, inductance, and resonant frequency.
Part A: The capacitance can be calculated using the formula for resonant frequency:
f0 = 1 / (2 * pi * sqrt(L * C))
where f0 is the resonant frequency, L is the inductance, and C is the capacitance. Solving for C, we get:
C = 1 / (4 * pi^2 * L * f0^2)
Substituting the given values, we get:
C = 3.37 nF
Part B: At resonance, the impedance of the circuit is purely resistive and can be calculated using the formula:
Z = R
where R is the resistance of the circuit. Substituting the given value, we get:
Z = 75 Ω
Part C: At a frequency of 4.0 kHz, the impedance of the circuit can be calculated using the formula:
Z = sqrt(R^2 + (Xl - Xc)^2)
where R is the resistance, Xl is the inductive reactance, and Xc is the capacitive reactance. The inductive reactance can be calculated using the formula:
Xl = 2 * pi * f * L
and the capacitive reactance can be calculated using the formula:
Xc = 1 / (2 * pi * f * C)
Substituting the given values, we get:
Xl = 452.39 Ω
Xc = 58.98 Ω
Z = 96.84 Ω
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Julie sits on a swing. Her free-body diagram is shown. A free body diagram with 2 force vectors. The first vector is pointing downward, labeled F Subscript g Baseline = negative 265 N. The second vector is pointing upward, labeled F Subscript N Baseline = 265 N. The vectors are the same length. The net force on Julie is N.
Based on the given information, we can conclude that the net force on Julie is zero N. This is because the upward force (labeled as F_N) is equal in magnitude to the downward force due to gravity (labeled as F_g), and they act in opposite directions. Mathematically, we can express this as:
Net force = F_N - F_g = 265 N - (-265 N) = 530 N
Since the net force is equal to 530 N in the upward direction and there are no other forces acting on Julie in the horizontal direction, she will remain in a state of rest or uniform motion (i.e., swinging back and forth at a constant speed).
This is an example of balanced forces, where the forces acting on an object are equal in magnitude and opposite in direction, resulting in a net force of zero N and no acceleration of the object.
Answer:
0
Explanation:
What is the average acceleration during the time interval 0 seconds to 10 seconds?
A. 0.5 meters/second?
B. 1 meter/second
C. 2 meters/second?
D. 3 meters/second?
Answer:
yea its D .
Explanation:
Explain a situation where chemical energy is transformed into light and heat energy.
Answer:
fire
Explanation:
burning the the oil
a a Imagine a basketball bouncing. As it is moving up, does it have a positive or a negative acceleration? Why?
Answer:
moving up positive acceleration
Explanation:
when moving up as you bounce the ball
the speed changes gradually increasing so according to the equation
acceleration =[speed change ] ÷ period when speed change is positive acceleration is also positive , and an greater value
example speed changes 5m/s within 2 seconds throwing the ball upward
(these are assuming values to explain)
acceleration is 5/2 = + 2.5 m/s^2
so this is an positive acceleration
if negative we call deceleration
When a basketball is bouncing and moving up, it has a negative acceleration.
Acceleration is the rate of change of velocity with respect to time. If the velocity of the basketball is increasing in the upward direction as it bounces, the acceleration is directed downward (negative). This might seem counterintuitive at first, but it is essential to understand that acceleration is a vector quantity, which means it has both magnitude and direction.
When the basketball moves upward during its bounce, its velocity is slowing down due to the opposing force of gravity. As it moves against gravity, the magnitude of its velocity decreases until it reaches the highest point (apex) of its bounce, where its velocity momentarily becomes zero. At the apex, the basketball changes direction and starts moving downward, and its velocity increases in the downward direction.
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A beam of white light is incident on a thick glass plate with parallel sides, at an angle between 0°and 90° with the normal. Which color emerges from the other side first?A) redB) violetC) greenD) None of the given; all colors emerge at the same time.
The correct answer to the question is D) None of the given; all colors emerge at the same time when the beam of white light is incident on a thick glass plate with parallel sides at an angle of 0° with the normal.
When white light enters a thick glass plate, it undergoes refraction, which means the light waves change direction and speed as they move through the glass. This causes the different colors of the spectrum to separate, with red being the least refracted and violet being the most refracted.
The angle at which the light enters the glass plate determines how much it is refracted, with greater angles causing more refraction. As a result, the color that emerges first from the other side of the glass plate will depend on the angle of incidence.
At an angle of 0°, the light will not be refracted at all and all colors will emerge at the same time. As the angle increases, the colors will start to separate and the order in which they emerge will be: red, orange, yellow, green, blue, indigo, and violet.
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The answer is B) violet. When white light enters a thick glass plate at an angle, it undergoes refraction and separates into its constituent colors. This is because different colors have different violets and Wavelength therefore bend at different angles. The color with the shortest wavelength, which is violet, bends the most and emerges first from the other side of the glass plate.
B) violet
When a beam of white light is incident on a thick glass plate at an angle between 0° and 90° with the normal, the light is refracted, and colors separate due to dispersion. Violet light has the shortest wavelength and is refracted more than the other colors, causing it to emerge from the other side of the glass first.
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