Ribose's OH's are all ___. a. left b. right c. up d. down

The strongest base among the given options is NH2−​.

The strength of a base is determined by its ability to accept or donate a pair of electrons. In general, a stronger base is characterized by a weaker conjugate acid, meaning it readily accepts a proton (H+). Several factors influence the strength of a base, including the stability of the conjugate acid formed after accepting a proton and the basicity of the atom or group involved.

NH2−​ (amide ion) is the strongest base among the options provided. The amide ion has a lone pair of electrons on the nitrogen atom, which can readily accept a proton to form NH3. NH3 is a weaker conjugate acid compared to the conjugate acids of the other options, such as HCl, H2O, H2S, and CH4.

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Suppose that you add 23.8 g of an unknown molecular compound to 0.250 kg of benzene. The molar mass of the unknown compound is 132.22 g/mol.

The expression for Molality of the compound can be calculated using

ΔT = i Kf m

Where,

ΔT = freezing point depression = 3.39 °C

i =  Van't Hoff factor of Benzene = 1

Kf =  constant of freezing = 5.12 °C/m

m = molality = ?

3.39 = 1 x 5.12 x m

m = 0.72 m

Number of moles of the compound is as :

Molality = moles / mass

Moles = 0.72 × 0.250

Moles = 0.18 mol

Molar mass = mass / moles

Molar mass = 23.8 / 0.18

Molar mass = 132.22 g/mol.

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1) Molecular Formula: C10H12O2

The molecular formula provides information about the number and types of atoms present in the compound. In this case, the compound contains 10 carbon atoms, 12 hydrogen atoms, and 2 oxygen atoms.

2) Infrared (IR) Spectroscopy:

IR spectroscopy is used to identify functional groups present in a compound based on the absorption of infrared radiation. The given IR peaks are at 1690 cm^−1 and 1612 cm^−1.

The peak at 1690 cm^−1 suggests the presence of a carbonyl group (C=O) in the compound. This absorption is typically observed for aldehydes, ketones, and carboxylic acids.

The peak at 1612 cm^−1 could indicate the presence of an aromatic ring or an alkene functional group. However, without additional information, it's challenging to definitively assign this peak.

3) Nuclear Magnetic Resonance (NMR):

The NMR data is incomplete, as the chemical shift (δ) and coupling constant (J) values are missing. The information provided is "1.4 (3H, t, ????)."

The chemical shift value is necessary to determine the type of proton environment, while the coupling constant provides information about neighboring protons and the connectivity in the molecule.

Overall, based on the given information, we can deduce that the compound has a molecular formula of C10H12O2 and likely contains a carbonyl group (C=O).

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Answer:

b

Explanation:

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To determine the change in volume (V) given the changes in pressure (P) and temperature (T), we need to consider the relationship described by the ideal gas law:

\(\displaystyle PV = nRT\)

Where:

To analyze the effect of changing P and T on V, we'll assume that the number of moles (n) and the ideal gas constant (R) remain constant.

If P increases by a factor of 5, we can express the new pressure as:

\(\displaystyle P_{\text{new}} = 5P\)

If T decreases by a factor of 3, we can express the new temperature as:

\(\displaystyle T_{\text{new}} = \frac{1}{3}T\)

Now, let's consider the relationship between the initial and final volumes (V and V_new):

\(\displaystyle PV = nRT\)

\(\displaystyle V = \frac{nRT}{P}\)

\(\displaystyle P_{\text{new}}V_{\text{new}} = nRT_{\text{new}}\)

\(\displaystyle V_{\text{new}} = \frac{nRT_{\text{new}}}{P_{\text{new}}}\)

Substituting the expressions for P_new and T_new, we have:

\(\displaystyle V_{\text{new}} = \frac{nR\left(\frac{1}{3}T\right)}{5P}\)

Simplifying the expression:

\(\displaystyle V_{\text{new}} = \frac{1}{15}\left(\frac{nRT}{P}\right)\)

Comparing this with the initial volume (V), we can see that:

\(\displaystyle V_{\text{new}} = \frac{1}{15}V\)

Therefore, the change in volume (V) is such that it decreases by a factor of 15.

The correct option is E. V decreases by a factor of 15.

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Answer: D. Reactions occur more slowly in the cold.​

Explanation:

The relative atomic mass of aluminium (Al) is 27, and the relative atomic mass of oxygen (O) is 16. Therefore, the relative formula mass of aluminium oxide (Al2O3) is:

(2 x 27) + (3 x 16) = 54 + 48 = 102

To calculate the percentage of aluminium in aluminium oxide, we need to determine the mass of the aluminium in the compound. Since there are two aluminium atoms in each molecule of aluminium oxide, the mass of the aluminium is:

(2 x 27) = 54

Therefore, the percentage of aluminium in aluminium oxide is:

(54 / 102) x 100% = 52.94%

So, the percentage of aluminium in aluminium oxide is approximately 52.94%.

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Answer:

True

Explanation:

Whenever something loses thermal energy, it contracts and becomes smaller.

Answer: it might be true

Explanation:

Answer:

becoz vvv is always with you

Answer:

Alkali metals have one valence electron on their outer shell. They are more stable when they have eight valence electrons so they tend to loose that one electron and obtain a full octet, therefore become stable

The compound that has ionic bonds is KBr (potassium bromide). Therefore the correct option is Option E.

Ionic bonds develop when two atoms with significantly differing electronegativities create a bond in which one atom (the metal) contributes electrons to the other atom (the non-metal). Potassium (K) is a metal in KBr, while bromine (Br) is a nonmetal. The electronegativity of K is low, whereas that of Br is high. When K and Br bond, K contributes its valence electron to Br, resulting in an ionic bond.

The other chemicals listed, on the other hand, have covalent bonding. When atoms with similar electronegativities share electrons in order to produce a more stable electron configuration, covalent bonds occur.

a. H2O has covalent bonds;

b. O2 contains covalent bonds; and

c. Ne is a noble gas that does not create bonds.

d. CO contains covalent bonds.

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Soap is potassium or sodium salts of a carboxylic acid attached to a long aliphatic chain. Detergent is the potassium or sodium salts of a long alkyl chain ending with a sulfonate group.

Answer:

Fishes undergo both asexual and sexual mode of reproduction with majority of fishes reproducing by sexual mode

Explanation:

Fishes undergo sexual reproduction. The sperm from the male fuses with the eggs of females. Some of the fishes have separate female and male sexes while some are hermaphrodites and have both testes and ovaries. Some species of fishes reproduce through parthenogenesis in which female egg develops into baby fishes without fusing with a sperm cell. Due to this, the offspring are exact copies of their mothers

To the nearest 0.1 L, you would need 0.5 L of 1.5 M NaOH solution to provide 0.75 mol of NaOH.

The molar mass of NaOH is 40 g/mol. Therefore, 0.75 mol of NaOH is equivalent to 30 g. To calculate the volume of 1.5 M NaOH needed, we can use the equation: moles = concentration x volume. Rearranging the equation, we get: volume = moles/concentration. Substituting the values, we get volume = 0.75 mol / 1.5 M = 0.5 L. Therefore, 0.5 liters of 1.5 M NaOH are needed to provide 0.75 mol of NaOH. (Word count: 94)
To calculate the volume of 1.5 M NaOH solution needed to provide 0.75 mol of NaOH, you can use the formula:
Volume (L) = moles of solute / concentration (M)
In this case, the moles of solute are 0.75 mol, and the concentration is 1.5 M. Plugging these values into the formula:
Volume (L) = 0.75 mol / 1.5 M
Volume (L) = 0.5 L
So, to the nearest 0.1 L, you would need 0.5 L of 1.5 M NaOH solution to provide 0.75 mol of NaOH.

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sodium hydroxide

cobalt (II) phosphide

lead (IV) carbonate

Magnesium fluoride

lithium sulfite

ammonium phosphate

iron (II) oxide

calcium sulfate

silver nitride

sodium sulfide

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#you can see the formula in pic for more detail writting

Mg2+ + Cl- -> MgCl2

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1. The atom that has five shells and seven valence electrons is Iodine.

The atomic number of Iodine is 53, having the electronic configuration of 2,8, 18, 18, 7. Iodine thus has 5 shells and 7 valence electrons.

2. Comparison of Ar and Cl

a) Cl has a greater force of attraction- Cl has 7 electrons in the valence shell thus to obtain the noble gas configuration it attracts the electrons.

b) Ar has greater ionization energy- Ionization energy increases along a period.

c) Ar is better at keeping its electrons- Argon is a noble gas and thus has a stable electronic configuration.

d) Ar is better at keeping its electrons- Argon is a noble gas and thus has a stable electronic configuration.

3. Comparison of N and P

a) N has the greater force of attraction- N is smaller than P thus the force of attraction is greater.

b) N has greater ionization energy- ionization energy decreases down the group.

c) N is better at keeping its electrons- due to the smaller size of nitrogen.

d) N is better at keeping its electrons- due to the smaller size of nitrogen.

1) The atom that has five shells and seven electrons is chlorine.  Chlorine has a greater force of attraction. The ionization energy is one of the periodic trends in the table.

We know that the periodic table has to do with the arrangement of the elements and the way that the elements have been arranged would have a lot to do with the chemical properties of the elements.

Let us note that elements have been arranged into groups and periods. The groups are the vertical columns while the periods are the horizontal rows that we can find in the periodic table as we can see it.

Finally;

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Answer:

12 - x = 20 - 5x

Add 5x on both sides,

12 - x + 5x = 20 - 5x

12 + 4x = 20

Subtract 12 on both sides,

12 - 12 + 4x = 20 - 12

4x = 8

Divide 4 on both sides,

4x / 4 = 8 / 4

x = 2

Hence proved.

Answer:

Explanation:

Equation (given) :

Compare the LHS and RHS :

Balanced Equation :

Answer: option c) the strongest base in aqueous solution is NaOH

Explanation:

the strongest base in aqueous solution is NaOH because strength of a base is determined by its ability to donate hydroxide ions (OH-) in solution. and NaOH dissociates completely in water to produce Na+ and OH- ions. The presence of a fully dissociated hydroxide ion makes NaOH a strong base.

While, HOC2H4OH and CH3OH are weak acids. HOC2H4OH is ethylene glycol and CH3OH is methanol are weak acid due to the presence of the   (-OH) group.

Also, NH3 (ammonia), is a weak base though it can accept H⁺ to form NH4+

Cl₂ ≤OClO₂≤ ClO₂ is the proper sequence of increasing bond angles in the following species. This is owing to the fact that in ClO₂, there are two lone pairs of electrons that oppose one another.

Causing two oxygen atoms to move in closer together and resulting in a decrease in bond angle. Therefore, the bond angle in ClO₂ is less than 118°, which is the bond angle in ClO₂ where chlorine has less electrons. ClO₂ has an angular structure. With a bond angle of 118⁰ and a Cl-O bond length of 1.47A⁰, the Cl atom is sp₂-hybridized in the angular molecule.

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Answer: How do contrasting colors affect the quality of a painting

Answer:

The answer is D.

Explanation:

I just took the test. :)

In Meselson and Stahl's experiment, DNA was centrifuged in a cesium chloride solution in order to separate the DNA molecules according to their densities.

When dissolved in water, the heavy salt cesium chloride can create a density gradient. The DNA will settle to the location in the gradient that corresponds to its density when a sample is layered on top of it and centrifuged.

By centrifuging DNA samples extracted from the bacteria grown in each medium, they were able to separate the "heavy" and "light" DNA and observe their distribution in each generation of replication, ultimately concluding that DNA replication occurs in a semi-conservative manner.

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Answer:

0.48 moles of H₂ are produced.

Explanation:

Given data:

Number of moles of H₂ produced = ?

Mass of H₂SO₄ = 47 g

Solution:

Chemical equation:

2Al + 3H₂SO₄    →    Al₂(SO₄)₃ + 3H₂

Number of moles of H₂SO₄ :

Number of moles = mass/molar mass

Number of moles = 47 g/ 98 g/mol

Number of moles = 0.48 mol

Now we will compare the moles of H₂SO₄ and  H₂

                       H₂SO₄      :        H₂

                           3           :          3

                         0.48       :        0.48

Thus, 0.48 moles of H₂ are produced.

In the volumetric flask, drain the precious liquid. Prepare the volumetric flask containing the incoming solution. -To avoid contamination, wash the volumetric flask.

A volumetric flask defines a variety of laboratory flask that has been calibrated to hold a specific volume at a particular temperature. For precise dilutions including the creation of standard solutions, volumetric flasks are usually employed.

After the last dilution, the perfect solution is fully mixed by gently shaking the flask while it stays upside down. When it is gently tossed without inverting, the stirring is insufficient. The stopper keeps the neck from breaking right away if the flask tips over.

Therefore, In the volumetric flask, drain the precious liquid. Prepare the volumetric flask containing the incoming solution. -To avoid contamination, wash the volumetric flask.

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Taking a mixed melting point is a procedure used to identify the identity of an unknown compound.

Melting point is the temperature at which a solid substance changes from its solid state to a liquid state at a constant pressure. It is a characteristic property of a substance and is often used to identify and characterize compounds.

This process involves combining the unknown compound sample with another sample of a known compound of similar structure and melting point. Both samples are then heated up, and the resulting mixture of compounds is observed as it undergoes a single melting or boiling process. If the melting point of the unknown compound is close to that of the known sample, then it can be assumed that the unknown compound is of the same structure as its partner. Alternatively, if the melting point of the mixture is lower than that of the known sample, then it indicates that the unknown sample has a different structure than the known one. By measuring the peak of the melting point curve and comparing it to the literatures documented melting points, an unknown compound can be identified.

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After considering the given data we conclude that the balanced this chemical equation will be
\(Pb(NO_{3} )_{2} (aq) + 2 NaCl (aq) - - > PbCl_{2} (s) + 2 NaNO_{3} (aq)\)

Now in order to balance this given chemical equation we have to follow the given steps
1. Start with the unbalanced equation:
\(Pb(NO_{3} )_{2} (aq) + NaCl(aq). - - > PbCl_{2} (s) + NaNO_{3} (aq)\)

2. Measure the number of atoms of each element on the reactant and product sides of the equation.
Reactant side: 1 Pb, 2 N, 6 O, 1 Na, 1 Cl
side of product : 1 Pb, 2 Cl, 2 N, 6 O, 2 Na

3. Now  balance the equation by altering the coefficients (numbers in front of the chemical formulas) as needed.
\(Pb(NO_{3} )_{2 } (aq) + 2 NaCl(aq) - - > PbCl_{2 } (s) + 2 NaNO_{3} (aq)\)

4. Now, measure the number of atoms of each element again to make sure the equation is balanced:
Reactant side: 1 Pb, 2 N, 6 O, 2 Na, 2 Cl
side of product : 1 Pb, 2 Cl, 2 N, 6 O, 2 Na

The count of atoms of each element is now equivalent on both sides of the equation.
Hence, the chemical equation is balanced and can be written as:
\(Pb(NO_{3} )_{2} (aq) + 2 NaCl (aq) - - > PbCl_{2} (s) + 2 NaNO_{3} (aq)\)

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The proton NMR spectrum of 4 isopropyl benzonitrile will have 3 signals for non-equivalent types of protons.

What are identical and incompatible protons?

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Answer:

If the weight of chemical is same so it represent that the experiment is valid.

Explanation:

If Bronwyn performed the same chemical reaction four times and she measure the weight of chemical with the help of electrical weight balance so if she find out the weight of the chemical that is produced during four experiments then we can say that the experiment is valid because the experiment was performed four times and that is enough for validation of the experiment.