Revlew Millikan's Photoelectric Experiment Robert A. Mlkan (1868 1953). although best known for his "oil-drop experiment," which measured the charge of an electron, also perfomed pioneering research on the photoelectric effect. In experiments on lithium, for example, Millikan observed a maximum kinetic energy of 0.550 eV when electrons were ejected with 433.9-nm light. When light of 253.5 m was used, he observed a maximum kinetic energy of 2.57 eV.
Part A What is the work function,W, for lithium, as determined from Milikan's results? Express your answer to three significant figures and include appropriate units.
Part B What maximum kinetic energy do you expet illikan found when he used light with a wavelength of 362.4 TIm? Express your answer to three significant figures and include appropriate units Value Units

Answer:

Rayleigh scattering

Explanation:

The blue color of the sky is due to a phenomenon called Rayleigh scattering. When sunlight enters the Earth's atmosphere, the shorter blue wavelengths of light are scattered more than the other colors by the tiny molecules of nitrogen and oxygen in the air. This causes the blue light to be redirected in many different directions, making the sky appear blue to our eyes. The other colors of light are scattered as well, but to a lesser extent, which is why the sky appears blue instead of a mixture of all colors. This effect is also the reason why the sun appears more yellow, orange or red during sunrise or sunset, when its light has to travel through more of the Earth's atmosphere before reaching our eyes, causing the shorter blue wavelengths to be scattered even more, leaving behind the longer wavelengths of light.

Answer:

radiation

Explanation:

The distance travelled by the car after the brake was applied is 125 m.

The distance travelled by the car is calculated by applying the following kinematic equation as shown below.

Mathematically, the distance travelled by the car at the given average speed is calculated as;

s = [ ( v + u ) / 2 ] t

where;

The distance travelled by the car is calculated as;

s = [ ( 0 + 25 m/s ) / 2 ] ( 10 s )

s = 125 m

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Answer:

the driver does 29,400 J of work in pushing the car to the gas station.

Explanation:

To find the amount of work done by the driver, we need to know the force applied by the driver and the distance the car is moved.

The force applied by the driver is given as 140 N, and the distance the car is moved is given as 210 m.

Work done can be calculated using the formula:

W = F * d * cos(θ)

where W is the work done, F is the force applied, d is the distance moved, and θ is the angle between the force and the displacement. Since the force and displacement are in the same direction, θ = 0, and the cosine of 0 is 1.

So,

W = F * d * cos(θ) = 140 N * 210 m * 1 = 29,400 J

Answer:

The value is \(\mu_k  =  \frac{3}{4} *  tan(\theta )\)

Explanation:

Generally the net force acting on the smooth block is mathematically represented as

       \(F  =  mgsin (\theta )\)

Here this force also represented as

     \(F =  ma\)

So

     \(ma  =  mgsin (\theta )\)

=>  \(a =  g sin(\theta )\)

Generally from  kinematic equation

    \(s =  ut  + \frac{1}{2} a t_1^2\)

   before the sliding the block was at rest so  u =  0 m/s

     \(s =  \frac{1}{2} a t_1^2\)

=>  \(s =  \frac{1}{2} (g sin(\theta )) t^2\)

=>   \(t_1 =  \sqrt{\frac{2s}{gsin(\theta )} }\)    

Generally the net force acting on the rough block is mathematically represented as    

     \(F  = mgsin(\theta )  - F_f\)

Here \(F_f\) is the frictional  force acting on the block which is mathematically represented as

      \(F_f  =  \mu_k  *  mg *  cos (\theta)\)

So

    \(F  = mgsin(\theta )  -  \mu_k  *  mg *  cos (\theta) \)

generally this net force is mathematically represented as

      \(F =  ma\)

=>  \( ma  = mgsin(\theta )  -  \mu_k  *  mg *  cos (\theta) \)

=> \(a = gsin(\theta ) - \mu_k * cos (\theta )\)  

Generally from  kinematic equation

    \(s =  ut  + \frac{1}{2} a t_2^2\)

   before the sliding the block was at rest so  u =  0 m/s

     \(s =  \frac{1}{2} a t_2^2\)

=> \(s =  \frac{1}{2} [gsin(\theta ) - \mu_k * cos (\theta )} t^2\)

= > \(t_2  =  \sqrt{\frac{2s}{gsin(\theta ) - \mu_k cos(\theta )} }\)

From the question we are told that

      \(t_2  =  2 t_1\)

\(\sqrt{\frac{2s}{gsin(\theta ) - \mu_k cos(\theta )} } = 2 * \sqrt{\frac{2s}{gsin(\theta )} }\)

Squaring both sides  

   \(\frac{1}{sin(\theta ) -  \mu_k cos(\theta )}  =  \frac{2}{sin(\theta)}\)

=> \(sin(\theta) =  4sin(\theta ) -  4\mu_k cos(\theta )\)

=> \(4\mu_k cos(\theta ) =  3sin(\theta )\)

=>  \(\mu_k  =  \frac{3}{4} * \frac{sin(\theta )}{ cos(\theta )}\)

=>  \(\mu_k  =  \frac{3}{4} *  tan(\theta )\)

The energy lost to friction and air resistance is 186 J.

option B.

The energy lost to friction and air resistance is calculated from the change in the mechanical energy of the pendulum.

The initial potential energy of the pendulum at the initial position is calculated as;

PEi = mghi

where;

P.Ei = 12 kg x 9.8 m/s² x 20 m

P.Ei = 2,352 J

The final kinetic energy of the pendulum is calculated as follows;

K.Ef = 0.5 x 12 kg x (19 m/s)²

K.Ef = 2,166 J

ΔE = 2,166 J - 2,352 J

ΔE = -186 J

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equal in magnitude but opposite in direction

Answer:

cobina

Explanation:

me 2

Answer:

An internal-combustion engine goes through four strokes: intake, compression, combustion (power), and exhaust. As the piston moves during each stroke, it turns the crankshaft.

Answer:

The engine will not work causing no movement in the wheels .

Explanation:

Remember the four stroke combustion cycle powers the wheels and if one of these parts do not work, then the car will not move .

Yes, momentum, like velocity, has a direction, and is a vector. (even though it isn't mentioned very often in these high-school problems).  

Its direction is the same as the direction of the velocity that it's made of.

But the statement is a bit sloppy . . . It's true that momentum has a direction just like velocity has.  But neither of them involves "a force".

Velocity is a direction with a SPEED.

Momentum is a direction with a product of (mass) x (velocity).  

Answer:

a

Explanation:

a push or a pull that occurs when an object interacts with another object or field.

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Pitch 0.396, solid height 12 turns, number of active turns 1.755 Spring rate is 1.08N/3, force is 81.9N and the stress in the spring is 3.85Kspi

The term "force" has a specific meaning in science. At this point, describing a force as a push or a pull is perfectly appropriate. A strength is not something an item "has in it" or that it "contains." One thing experiences a force from another. There are both living things and non-living objects with in concept of a force.

Force: Force is just a physical factor that alters or has the potential to alter an object's state of motion or motion and its form. Newton is the SI unit of force.

(a) Pitch, solid height, number of active turns

\(N_{t}\)= 12.5 coils

pitch = 4.75/12

=0.396

The ends are squared  along 1/4 turns on each end

\(N_{a}\)= 12.5-0.5

=12 turns

Solid height: solid stack is 13 wire diameter

\(L_{s}\)= 13(0.135) = 1.755

(b) Spring rate

\(K=\frac{d^{2}c }{8D^{3}N_{a} }\)

\(= \frac{3.4^{4}*78.6*10^{3} }{8*46.6^{3}*12 }\)

\(= 1.08 N/3\\\) or 6.08 uof/in

(c) Force

\(F_{v}=K(L_{0}- L_{1} =1.08 (12.-44.2)\\ =81.9N or 18.2 Lbf\)

(d) c= D/d = 1.865/0.135 = 13.81

\(K_{b}=\frac{4(13.81)+2}{4(13.81)-3} = 1.096\)

\(T_{s}-K_{B} = \frac{8F_{D} }{nd^{3} } = 1.096 * \frac{8(18.2)(1.865)}{(0.135^{3} )}=3.85 Kpsi\)

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1) The force acting on the object during the time interval 0-3 seconds is 1/3 N.

2) The force acting on the object during the time interval 6-10 seconds is -0.5 N.

3) There is no time interval in which no force acts on the object.

(i) Force acting on the object in time interval 0-3 seconds. Force acting on the object is equal to the product of its mass and acceleration, i.e.,F = ma.

In the given velocity-time graph, the acceleration of the object can be determined by determining the slope of the velocity-time graph from 0 to 3 seconds.

Slope = (change in velocity) / (change in time)= (20-0) / (3-0) = 20/3 m/s^2

Acceleration, a = slope= 20/3 m/s^2

Mass of the object, m = 50 g = 0.05 kg

∴ Force acting on the object, F = ma= 0.05 × 20/3= 1/3 N.

Therefore, the force acting on the object during the time interval 0-3 seconds is 1/3 N.

(ii) Force acting on the object in time interval 6-10 seconds. Similar to the first question, the force acting on the object in time interval 6-10 seconds can be determined by determining the acceleration of the object during this time interval.

The slope of the velocity-time graph from 6 seconds to 10 seconds can be determined as follows:

Slope = (change in velocity) / (change in time)= (-20-20) / (10-6) = -40/4= -10 m/s^2 (negative sign indicates that the object is decelerating)

Mass of the object, m = 50 g = 0.05 kg

∴ Force acting on the object, F = ma= 0.05 × (-10)= -0.5 N.

Therefore, the force acting on the object during the time interval 6-10 seconds is -0.5 N.

(iii) Time interval in which no force acts on the object. There is no time interval in which no force acts on the object. This is because, as per Newton's first law of motion, an object will continue to remain in a state of rest or uniform motion along a straight line unless acted upon by an external unbalanced force.In other words, if the object is moving with a constant velocity, there must be a force acting on the object to maintain its motion.

Therefore, there is no time interval in which no force acts on the object.

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It would take approximately 546 days for the decay rate of the sample of this radioactive isotope to fall to 0.58 of its initial rate.

1. The decay rate of a radioactive isotope is proportional to the number of radioactive atoms present in the sample at any given time.

2. The decay rate can be expressed as a function of time using the formula: R(t) = R₀ * \(e^{(-\lambda t\)), where R(t) is the decay rate at time t, R₀ is the initial decay rate, λ is the decay constant, and e is the base of the natural logarithm.

3. The half-life of a radioactive isotope is the time it takes for half of the radioactive atoms in a sample to decay. In this case, the half-life is given as 210 days.

4. Using the half-life, we can find the decay constant (λ) using the formula: λ = ln(2) / T₁/₂, where ln(2) is the natural logarithm of 2 and T₁/₂ is the half-life.

5. Substituting the given half-life into the formula, we have: λ = ln(2) / 210.

6. Now, we need to find the time it takes for the decay rate to fall to 0.58 of its initial rate. Let's call this time "t".

7. Using the formula for the decay rate, we can write: 0.58 * R₀ = R₀ * e^(-λt).

8. Simplifying the equation, we get: 0.58 = \(e^{(-\lambda t\)).

9. Taking the natural logarithm of both sides, we have: ln(0.58) = -λt.

10. Substituting the value of λ from step 5, we get: ln(0.58) = -(ln(2) / 210) * t.

11. Solving for t, we have: t = (ln(0.58) * 210) / ln(2).

12. Evaluating the expression, we find: t ≈ 546.

13. Therefore, it would take approximately 546 days for the decay rate of the sample of this radioactive isotope to fall to 0.58 of its initial rate.

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Answer:

jjjjjjjjjjjjjjjj

Explanation:

From the histogram given, there were at approximately 7 downloads between 3pm and 4pm . This can be derived by counting the rows in that time period.

A histogram is a graph that depicts the frequency distribution of a few data points from a single variable.

Histograms frequently divide data into "bins" or "range groups" and count the number of data points that belong to each of those bins.

Histograms are frequently used to depict the key properties of data distribution in a handy format. It is especially beneficial when working with huge data sets (more than 100 observations). It can aid in the detection of uncommon observations (outliers) or gaps in the data.2

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Answer:

The concentrations of the reactants and the products. The temperature of the system. The partial pressures of the gases involved (if any)

Explanation:

You're going to use the constant acceleration motion equation for velocity and displacement:

(V)final² = (V)initial²+2a(dx)

Given:

a=0.500m/s²

dx=6.32 m

(V)intial=0m

(V)final= UNKNOWN

(V)final= 2.51396m/s

The indicated features from top to bottom:

It is called a spiral galaxy because it looks like a spinning windmill when viewed from above or below. The Sun is in one of the spiral arms about 25,000 light-years away from the center of the galaxy.

Our solar system is in a galaxy called the Milky Way which is tightly packed with 100 to 400 billion other stars many of which have planets of their own. The Milky Way got its name because it looks like a stream of spilled milk across the sky. An elliptical galaxy is a type of galaxy with an almost featureless image that is nearly elliptical and smooth.

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Answer:

Explanation:  the key diffrence that exists between kinetic energy and potential energy is that form of mechanical energy which is stored within an oblect ready to be released as and when needed to do some  work while kinetic energy that has been released and is associated with the body in motion

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Answer:

See below

Explanation:

Mechanical energy is the energy that is possessed by an object due to its motion (KInetic) or due to its position (potential energy)

Mechanical energy = Kinetic energy + potential energy

   KE can be totally or partially converted to PE and vica versa....the total ME will remain the same .

Answer:

C  Particles in a gas have more energy than particles in a liquid.

Explanation:

Answer:

add molecules

(a) The angular speed of the kite is 1.1 rad/s or 10.5 rpm

(b) The cost of operating a 60-W light bulb for 3 days is $0.38.

The angular speed is calculated as follows;

ω = √(F / (mr))

where;

ω = √(0.85 N / (0.35 kg x 2.0 m))

ω = 1.1 rad/s

The angular speed in rpm is calculated as;

ω = 1.1 rad/s x 1rpm/2π x 60s/1min

ω = 10.5 rpm

(b) Power is the rate at which energy is consumed, and it is given by the formula:

P = E / t

where;

E = P x t

E = 60 W x 3 days x 24 hours/day x 3600 s/hour

E = 15,552,000 J

In kW · h;

=  15,552,000 J / (1000 W/kW x 3600 s/h)

=  4.32 kWh

The cost of this energy can be calculated as;

Cost =  4.32 kWh x $0.088/kW h

Cost  = $0.38

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Answer:

5.67 m/s

Explanation:

The speed of a wave can be calculated as the distance traveled by the wave divided by the time taken:

Speed = Distance/Time

In this case, the distance traveled by the wave is the length of the pool, which is 17 m. The time taken by the wave to travel this distance is 3 seconds.

So, the speed of the wave can be calculated as:

Speed = 17 m/3 s

Speed = 5.67 m/s

Therefore, the speed of the water wave in the 17 m long pool is 5.67 m/s.

The magnitude of the resultant vector to round the answer to the nearest tenth, we look at the digit in the hundredth's place. If this digit is 5 or greater, we round up. If it is less than 5, we round down.

In the study of physics, we use vectors to represent quantities that have both direction and magnitude. It is often the case that we want to add two or more vectors together to obtain a single vector that represents the net result of these additions. The process of adding two or more vectors together is known as vector addition.The magnitude of the resultant vector is the length of the line that represents it on a scale drawing.

When we add two or more vectors together, the resultant vector is the vector that represents the net result of these additions. To find the magnitude of the resultant vector, we use the Pythagorean theorem, which states that the square of the hypotenuse of a right triangle is equal to the sum of the squares of the other two sides.

In the case of vector addition, the hypotenuse is the resultant vector, and the other two sides are the component vectors. If we have two vectors a and b, the magnitude of the resultant vector is given by the following equation:|R| = √(ax2 + bx2)where R is the resultant vector, a and b are the component vectors, and x is the angle between the vectors.

For example, if the answer is 12.345, we would round it to 12.3.

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The Children's Health Insurance Program (CHIP) is designed to provide low-cost health coverage to children in families that receive Medicare.

Hence option D is correct.

The Children's Health Insurance Programme (CHIP) offers medical care to children under the age of 18 whose parents earn too much to qualify for Medicaid but not enough to pay for private coverage. CHIP was enacted by Congress during the Clinton administration in 1997.

The Children's Health Insurance Programme (CHIP) is a federal healthcare programme in the United States that is handled and designated differently by each state. For example, New York's programme is known as Child Health Plus, whereas Arkansas' programme is known as ARKids.

The federal government distributes matching funding to each state, similar to how Medicaid operates.

Hence option D is correct.

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The half-life of hypothetical element  technetium-99 is 210,936 years.

Half-life of the hypothetical element From the graph provided in the question, the half-life of the hypothetical element can be obtained by finding the time taken for the element to reduce to half its original quantity. Here, it can be seen from the graph that the quantity of the element reduces from 40 to 20 on day 4. Therefore, the half-life of the hypothetical element is 4 days.2. Time taken for a sample to decay from 100 grams to 25 gramsIf the half-life of a given substance is 65 days, then the quantity of the substance reduces to half every 65 days. From 100 grams to 50 grams, it takes one half-life cycle. From 50 grams to 25 grams, it will take another half-life cycle.

Therefore, it will take two half-life cycles, which is 2 × 65 = 130 days, for a 100-gram sample of the substance to decay until there is only 25 grams of the radioactive material remaining.3. Half-life of a sample that decays from 200 grams to 50 grams in 60 minutesIt is given that the sample of radioactive isotopes takes 60 minutes to decay from 200 grams to 50 grams. To find the half-life, we need to determine how many times the sample has lost half of its mass, which tells you how many half-life cycles have occurred.At 30 minutes, the sample reduces to half its original quantity, which is 100 grams. At 45 minutes, it reduces to 50 grams, which is half of 100 grams. Therefore, it takes two half-life cycles to reduce from 200 grams to 50 grams in 60 minutes. Hence, the half-life of the isotope is 15 minutes.4. Half-life of technetium-99 that decays from 500.0 g to 62.5 g in 639,000 yearsIt is given that a 500.0 g sample of technetium-99 decays to 62.5 g of technetium-99 remaining in 639,000 years. We can use the half-life formula to find the half-life of technetium-99.t1/2 = (t × log2) / log(N0 / Nt) Where,t1/2 = half-life of the substanceN0 = initial quantity of the substance Nt = quantity of the substance left after time t (in years)t = time (in years)From the given data,t1/2 = (639000 × log2) / log(500.0 / 62.5)t1/2 = 210,936 years.

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Since focal length cannot be negative for a converging lens, we take the positive value: f ≈ 41 cm Option C

To determine the focal length of the lens, we can use the lens formula, which relates the object distance (u), image distance (v), and focal length (f) of a lens. The lens formula is given by:

1/f = 1/v - 1/u

In this case, the object distance (u) is 25 cm and the image distance (v) is 64 cm. We can substitute these values into the lens formula to solve for the focal length:

1/f = 1/v - 1/u

1/f = 1/64 cm - 1/25 cm

To simplify the equation, we can find a common denominator:

1/f = (25 - 64) / (64 * 25)

1/f = -39 / (64 * 25)

Now, we can invert both sides of the equation to solve for the focal length:

f = (64 * 25) / -39

f ≈ -41.03 cm

Since focal length cannot be negative for a converging lens, we take the positive value:

f ≈ 41 cm

Therefore, the correct answer is option C) 41 cm.

It's important to note that in the lens formula, distances are measured with respect to the lens, with positive values indicating distances on the opposite side of the incident light. The negative value obtained for the focal length indicates that the lens is a converging lens, as expected. Option C

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