Required
Momentum
The magnitude of the momentum of an object is 64 kg*m/s. If the velocity of the
object is doubled, what will be the magnitude of the momentum of the object? *
32 kg*m/s
64 kg*m/s
128 kg*m/s
256 kg*m/s

Answers

Answer 1

Answer:

C) 128 kg*m/s

Explanation:

When you double something you multiply it by 2 most of the time. 64*2=128 or you can add it 64+64=128. Hope this helps.


Related Questions

a bullet is dropped from the same height when another bullet is fired horizontally they will hit the ground

Answers

Answer:

simultaneously

Time taken to reach the ground depends on the vertical component of velocity, not horizontal component of velocity.

A certain electric dipole consists of charges + and − separated by distance , oriented along the -axis as shown in the figure. Find an expression for the magnitude of the electric field of the dipole at a point far away in the -direction, a distance away from the midpoint of the dipole. Assume that is much greater than . Enter your answer in terms of , , , and 0. I've seen one other post about this question but the answer is wrong. I'd really appreciate help on this.

A certain electric dipole consists of charges + and separated by distance , oriented along the -axis

Answers

Hi there!

Let's say we have a point 'p' placed at a distance 'r' away from the origin, where r > > d.

The electric field from the +q charge will point towards the top-right, while the electric field from the negative chart will point towards the bottom-right.

Since both charges are of the same magnitude, the y-components will cancel out. We must solve for the x-component of the electric field.

We can begin by deriving an equation for the electric field.

\(E= \frac{kq}{R^2}\)

\(R = \sqrt{(\frac{d}{2})^2 + r^2}\)

We are solving for E in the x-direction, so:
\(E_x = \frac{kq}{R^2}sin\phi\)

Substitute in the above, and:
\(sin\phi = \frac{\frac{d}{2}}{\sqrt{(\frac{d}{2})^2 + r^2}} = \frac{d}{2\sqrt{\frac{d^2}{4} + r^2}}\)

Calculate Ex for one charge:
\(E_x= \frac{kq}{\frac{d^2}{4} + r^2} * \frac{d}{2\sqrt{\frac{d^2}{4} + r^2}}\)

Simplify:
\(E_x = \frac{kqd}{2(\frac{d^2}{4} + r^2)^{3/2}}\)

There are two charges, so:
\(2E_x = E_x = 2(\frac{kqd}{2(\frac{d^2}{4} + r^2)^{3/2}}) = \frac{kqd}{(\frac{d^2}{4} + r^2)^{3/2}}\)

To find the field if r > > d, we can begin by factoring out r² from inside the parenthesis:

\(E_x = \frac{kqd}{(\frac{d^2}{4} + r^2)^{3/2}} \\ \\ =\frac{kqd}{r^3(\frac{d^2}{4r^2} + 1)^{3/2}}\)

Terms with d/r go to 0, so:
\(\frac{d}{r^3} = 0 \\ \\ \frac{d^2}{4r^2} = 0 \)

So:
\( E_x =\frac{kq(0)}{(0 + 1)^{3/2}} = \boxed{0 \frac{N}{C}}\)

**We can also think of this situation as d ≈ 0. As the 'r' increases and becomes MUCH greater than 'd', the charges appear to be right next to one another (d ≈ 0). If we plug in d = 0 into our equation:


\( E_x =\frac{kq(0)}{(\frac{0^2}{4} + r^2)^{3/2}} = 0 \frac{N}{C}\)

A certain electric dipole consists of charges + and separated by distance , oriented along the -axis

A 2000 N net force will give a car with some amount of mass an acceleration of 4 m/s2
What acceleration will the same net force give a truck whose mass is twice that of the car?

Answers

Answer:

2m/s²

Explanation:

Given parameters:

Net force on the car  = 2000N

Acceleration = 4m/s²

Unknown:

Acceleration of a car twice the mass  = ?

Solution:

Let us first find the mass of the car;

 Force  = mass x acceleration

         Mass = \(\frac{Force }{acceleration}\)  

 Mass = \(\frac{2000}{4}\)   = 500kg

 Now,

     whose mass is twice that of the car

    Mass of the new car = 2 x 500  = 1000kg

So;

  Acceleration  = \(\frac{Net force }{mass}\)  

  Acceleration  = \(\frac{2000}{1000}\)  = 2m/s²

URGENTTTT
Referring to the graph in the section header, what was his displacement between 100 and 300 seconds?


Referring to the graph in the section header, what was the runner's velocity during segment D?

URGENTTTT Referring to the graph in the section header, what was his displacement between 100 and 300

Answers

The displacement of the runner according to the graph is obtained as 250 m.

What is the displacement?

The term displacement has to do with the distance that is covered in a specified direction. The difference between distance and displacement is that displacement is a vector while distance is a scalar quantity.

Thus we bring the direction into play when we are talking about the displacement of the object. Now we have a graph that shows the displacement of the runner in the vertical axis and then shows the time that is taken in the horizontal axis.

Given the graph as we have it, we can be bale to pick out the following from the graph;

1) Displacement of the runner at 100 s = 500 m

2) Displacement of the runner at 300 s = 750 m

Therefore;

Displacement of the runner between 100 and 300 seconds;

750 m - 500 m = 250 m

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______________________________

A Stone Is Dropped Into a Deep Water Well. The Sound of The Stone Hitting The Water Is Heard After 3.4 Seconds. Determine The Depth of The Water Well.

N.B. The Correct Answer Will Receive 30 Points & The Brainliest Title.
______________________________​

Answers

A Stone Is Dropped Into a Deep Water Well. The Sound of The Stone Hitting The Water Is Heard After 3.4 Seconds. then The Depth of The Water Well is 56.6 m.

In terms of physics, sound is a vibration that travels through a transmission medium like a gas, liquid, or solid as an acoustic wave. Sound is the receipt of these waves and the brain's perception of them in terms of human physiology and psychology. Only acoustic waves with frequencies between about 20 Hz and 20 kHz, or the audio frequency range, may cause a human to have an auditory sensation. These correspond to sound waves in air with an atmospheric pressure of 17 metres (56 ft) to 1.7 centimetres (0.67 in) in wavelength. Ultrasounds are sound waves with a frequency higher than 20 kHz that are inaudible to humans. Infrasound refers to sound frequencies below 20 Hz. Animals of different species have different hearing ranges. Acceleration of the stone is 9.8 m/s²

according to kinematics,

s = ut + 1/2 at²

s =  1/2 ×9.8×3.4²

s = 56.6 m

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person a and b traveling away from each other. It takes person a 2 hours to travel a full circle, and person b 5 hours to travel a full circle. how much time will it take for a and b to meet?

person a and b traveling away from each other. It takes person a 2 hours to travel a full circle, and

Answers

Let the circumference of the circle be 10L.

A moves at 10L/2 = 5L per hour

B moves at 10L/5 = 2L per hour

Therefore it takes 10L/(5L+2L) = 10/7 hours

A cyclist rides a bicycle with a wheel radius of 0.500 m across campus. A piece of plastic on the front rim makes a clicking sound every time it passes through the fork. If the cyclist counts 320 clicks between her apartment and the cafeteria, how far has she traveled

Answers

Answer:

1500 clicks

Explanation:

Well if .5 times 320 is done then that would leave 150 then g(1) = 1² + 1 = 2 and lead to 150 being multipled to 1500 clicks

If the eggs are being thrown with the samevelocity, and the eggs have the same mass,then what else is the same between the twoeggs?

Answers

Both the eggs have the same value of velocity and the same value of mass.

As the momentum of the body in terms of mass and velocity is,

\(p=mv\)

The mass and velocity of both the eggs are the same, thus, the value of momentum for both the eggs is also the same.

The initial kinetic energy of the body is,

\(K=\frac{1}{2}mv^2\)

Thus, the kinetic energy of both the eggs also remains same.

Hence,

Which option describes the direction of thermal energy transfer in Earth's
oceans?
A. From the poles to the equator
B. From the equator to the poles
C. From the ocean floor to its surface water
D. From cool areas to warm areas

Answers

.........

Explanation:

Option B..... ...


A car with a momentum (impulse) of 20,000 kg m/s collides with a wall and comes to a rest in 0.1 seconds. How much
force is absorbed by the car (and the driver)?

Answers

Answer:

» Force is 200,000 Newtons

Explanation:

\({ \tt{force = \frac{impulse}{time} }} \\ \\ { \tt{force = \frac{20000}{0.1} }} \\ \\ { \tt{force = 200000 \: newtons}}\)

In a ballistic pendulum, a spring pushes a ball from rest. It flies through the air and sticks in the base of a pendlum that swings upwards.

Given that the ball and pendulum reach a maximum angle of 45º, the pendulum is 30 cm long, the mass of the ball is 76 g, and the mass of the pendulum is 250 g, calculate the speed of the ball after it has left the spring but before it hits the pendulum. Do not include the units in your response.

Answers

Answer: EASY BROOOOOOOOOOOOOOOOOOOOOOOOO

Take a look inside your heart

Is there any room for me?

I would have to hold my breath

'Til you get down on one knee

Because you only want to hold me

When I'm looking good enough

Did you ever fault me?

Would you ever picture us?

Every time I pull my hair out

Was only out of fear

That'd you find me ugly

And one day you'll disappear

Because what's the point of crying?

It was never even love

Did you ever want me?

Was I ever good enough?

What is revolution?
A. The motion of an object along a curved path
B. The spinning of an object on its axis
C. The orbit of a satellite around a central body
D. The motion of two objects around each other

Answers

Answer:

A. the motion of an object along a curved path

3) Four point masses 2kg, 4kg, 6kg and 9kg are placed at the corners of Square ABCD of 2cm long respectively. Find the position of centre of mass of the system from the Corner A.​

Answers

Answer:

We can find the position of the center of mass of the system by using the formula:

Xcm = (m1x1 + m2x2 + m3x3 + m4x4) / (m1 + m2 + m3 + m4)

where Xcm is the x-coordinate of the center of mass, m1, m2, m3, and m4 are the masses of the point masses, and x1, x2, x3, and x4 are their respective x-coordinates.

Similarly, we can find the y-coordinate of the center of mass using the formula:

Ycm = (m1y1 + m2y2 + m3y3 + m4y4) / (m1 + m2 + m3 + m4)

where Ycm is the y-coordinate of the center of mass, m1, m2, m3, and m4 are the masses of the point masses, and y1, y2, y3, and y4 are their respective y-coordinates.

Let's label the masses and coordinates as follows:

m1 = 2kg, x1 = 0cm, y1 = 0cm

m2 = 4kg, x2 = 2cm, y2 = 0cm

m3 = 6kg, x3 = 2cm, y3 = 2cm

m4 = 8kg, x4 = 0cm, y4 = 2cm

Substituting these values into the formulas, we get:

Xcm = (2kg x 0cm + 4kg x 2cm + 6kg x 2cm + 8kg x 0cm) / (2kg + 4kg + 6kg + 8kg) = 2cm

Ycm = (2kg x 0cm + 4kg x 0cm + 6kg x 2cm + 8kg x 2cm) / (2kg + 4kg + 6kg + 8kg) = 1cm

Therefore, the center of mass of the system is located 2cm from corner A in the x-direction and 1cm from corner A in the y-direction.

Explanation:

what is the value of pi(8.104)^2 written with correct significant numbers

Answers

Answer:206.3

Explanation:

1. A Ograph A Ograph B Ograph c Which graph represents what happens to the pressure in a tire as air is added to the tire, assuming the temperature is constant? ​

1. A Ograph A Ograph B Ograph c Which graph represents what happens to the pressure in a tire as air

Answers

Answer:

Explanation:

It's graph A because the pressure in the tire is increasing as the amount of air going into it increases. B says the pressure drops exponentially as air goes in, and C says that the pressure stays the same as air goes in. Pressure in a tire increases proportionally to the amount of air in it.

Find the work done by the gas during the following stages. (a) A gas is expanded from a volume of 1.000 L to 4.000 L at a constant pressure of 2.000 atm. (b) The gas is then cooled at constant volume until the pressure falls to 1.500 atm

Answers

Answer:

a) 607.95 J

b) 0 J

Explanation:

a) Initial volume = 1 L = 0.001 m^3

final volume = 4 L = 0.004 m^3

pressure = 2 atm = 202650 Pa     (1 atm = 101325 Pa)

work done by the gas on the environment = PΔV

P is the pressure = 101325 Pa

ΔV is the change in volume from the initial volume to the final volume

ΔV = 0.004 m^3 - 0.001 m^3 = 0.003 m^3

work done by the gas = 202650 x 0.003 = 607.95 J

b) If the gas is cooled at constant volume, then the gas does no work. For a gas to do work, there must be a change in its volume.

Therefore the work done in cooling at constant volume until pressure falls to 1.5 atm = 0 J

Type the correct answer in the box. Spell all words correctly.
Mention the term
refers to having a generalized (and biased) belief about a particular group of people.

Answers

In social psychology, a stereotype is a generalized belief about a particular category of people.

What is stereotype ?

A stereotype can be described as the accepted, condensed, and essentialist opinion  with regards to certain population.

I should be nted hat his can be related to  gender identity, race  as well as ethnicity, country,  however there are other things that an be used frequently used to stereotype groups. Stereotypes are pervasively present in both the larger social structure and culture.

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Elements and compounds are both​

Answers

Answer:

An element is a material that consists of a single type of atom. Each atom type contains the same number of protons. Chemical bonds link elements together to form more complex molecules called compounds. A compound consists of two or more types of elements held together by covalent or ionic bonds

Explanation:

Which branch of science studies how sound waves move through the air?
A. Life science
B. Physical science
C. Space science
D. Earth science

Which branch of science studies how sound waves move through the air?A. Life scienceB. Physical scienceC.

Answers

Answer:

B is the correct answer

Explanation:

just bc I said so:)

How are mass and free fall related to acceleration?

Answers

Answer:

Increasing force tends to increase acceleration while increasing mass tends to decrease acceleration. Thus, the greater force on more massive objects is offset by the inverse influence of greater mass. Subsequently, all objects free fall at the same rate of acceleration, regardless of their mass.

Explanation:

It let me answer now

Hope This Helped ;)

A ball that is attached to a string travels in a horizontal, circular path, as shown in Figure 1. At time t0 , the ball has a speed v0 . The forces exerted on the ball at t0 are represented by the free-body diagram, as shown in Figure 2. At a later time t1 , the tangential speed of the ball is increased to 2v0 . What is the magnitude of the force that the ball exerts on the string at time t1 ?

Answers

Answer:

F₁ = 4 F₀

Explanation:

The force applied on the string by the ball attached to it, while in circular motion will be equal to the centripetal force. Therefore, at time t₀, the force on ball F₀ is given as:

F₀ = mv₀²/r   --------------- equation (1)

where,

F₀ = Force on string at t₀

m = mass of ball

v₀ = speed of ball at t₀

r = radius of circular path

Now, at time t₁:

v₁ = 2v₀

F₁ = mv₁²/r

F₁ = m(2v₀)²/r

F₁ = 4 mv₀²/r

using equation (1):

F₁ = 4 F₀

Think of a book at rest on a flat leveled surface and another book (same type) that is sliding and slowing down to a complete stop on the
same surface.
a. What force(s) is on the sliding book that is not on the book at rest? Explain why.
b. If the sliding book was speeding up instead, describe how the free body diagram would be drawn differently than the book at rest.

Answers

A. Friction between the book and the table, drag from the air on the book

B. The arrow in the direction the book travels is larger than the other lines and there would also be a backwards force from the drag

What does it mean when an object is magnified?

The object appears darker.
The object appears larger.
The object appears lighter.
The object appears smaller.

Answers

Answer:

The object appears larger

Explanation:

B

as the speed of a particle approaches the speed of light, the momentum an astronaut traveling forward at 0.87c holds a meter stick in spear-like fashion. an observer at rest sees the spear's length asof the particle

Answers

as the speed of a particle approaches the speed of light, the momentum an astronaut traveling forward at 0.87c. an observer at rest sees the spear's length as of the particle  approaches infinity .

In Newtonian mechanics, momentum (more specifically linear momentum or translational momentum) is the product of the mass and velocity of an object. It is a standard mechanical quantity. It is a vector quantity, possessing a magnitude and a direction.

In the International System of Units (SI), the unit of measurement of momentum is the kilogram metre per second (kg⋅m/s), which is equivalent to the newton-second.

Newton's second law of motion states that the rate of change of a body's momentum is equal to the net force acting on it. Momentum is coordinate system dependent, but is preserved in any inertial coordinate system.

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Object 1 with mass 1=3.25 kg
is held in place on an inclined plane that makes an angle
of 40.0∘
with the horizontal. The coefficient of kinetic friction between the plane and the object is 0.535.
Object 2 with mass 2=4.75 kg
is connected to object 1 with a massless string over a massless, frictionless pulley. The objects are then released.
Calculate the magnitude
of the initial acceleration.
Calculate the magnitude
of the tension in the string once the objects are released.

Answers

The magnitude of the initial acceleration of the object is 4.2 m/s².

The tension in the string once the object starts moving is 13.65 N.

What is the  magnitude of the initial acceleration?

The magnitude of the initial acceleration of the object is calculated by applying Newton's second law of motion as follows;

F(net) = ma

m₂g - μm₁g cosθ = a(m₁ + m₂)

where;

m₁ and m₂ are the masses of the blocksg is acceleration due to gravityμ is coefficient of frictionθ is the angle of inclinationa is the acceleration

(4.75 x 9.8) - (0.535 x 3.25 x 9.8 x cos40) = a(3.25 + 4.75)

33.5 = 8a

a = 33.5/8

a = 4.2 m/s²

The tension in the string once the object starts moving is calculated as;

T = m₁a

T = 3.25 x 4.2

T = 13.65 N

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A magnet gets demagnetized when it is heated.​

Answers

Answer:

The delicate balance between temperature and magnetic domains is destabilized when a magnet is subjected to high temperatures. If a magnet is exposed to this temperature for an extended length of time or heated over its Curie temperature, it will lose its magnetism and become irreversibly demagnetized.

Explanation:

g A wheel of radius 1.2 meters initially rotates clockwise around its center with an angular speed of 10 rad/s, and it steadily increases its rate of rotation. 4 second later, the rate of rotation is 30 rad/s. What is the ratio of the angular acceleration of a point on the rim of the wheel to a point that is 0.6 meters from the center of the wheel?

Answers

Answer:

 α = 5 rad / s²

Explanation:

This is a rotational kinematics exercise.

They indicate the initial velocity wo = 10 rad / s

             w = w₀ + α t

             α = \(\frac{w-w_o }{t}\)

let's calculate

             α = \(\frac{30-10}{4}\)

             α = 5 rad / s²

The velocity, the angular relation are the same in all the points of the wheel, the velocities and linear accelerations are the ones that change

            a = α r

            v = w r

Describe 3 methods how asteroids can be deflected to protect Earth?

Answers

Answer:

atmosphere, gravitational pull, magnetic field

Explanation:

the astroids burn up in the atmosphere, gravitational pull alters the path of the astroids, and the magnanetic field deflects them of path.

2. What does SCA stand for? (1 Point) Student Conservation Association h Securities Class Action Sudden Cardiac Arrest Solar Cell Array:',)​

Answers

Answer:

sudden cardiac arrest

Explanation:

You have to lift a 15 kg object. What is your output force?
Using a lever, you push down 20 N to lift a 10 kg object.
A) Find the output force.
B) What is the input force?
C) How much does the ramp multiply your force?
You push with 10 N up a ramp to move a 40 N object to the top
of a table. By how much does the ramp multiply your force?

Answers

Answer:

Explanation:

A) The output force required to lift a 15 kg object would be equal to the weight of the object, which is given by:

Output force = Weight of object = m * g

where m is the mass of the object and g is the acceleration due to gravity. Assuming that g is equal to 9.81 m/s^2, we have:

Output force = 15 kg * 9.81 m/s^2 = 147.15 N

Therefore, the output force required to lift a 15 kg object would be 147.15 N.

B) In this case, the input force is the force that you are pushing down with the lever, which is given as 20 N.

C) The mechanical advantage of the ramp is given by the ratio of the output force to the input force. In this case, the output force is the weight of the object (40 N) and the input force is the force that you are pushing with (10 N). Therefore, the mechanical advantage of the ramp would be:

Mechanical advantage = Output force / Input force = 40 N / 10 N = 4

So, the ramp multiplies your force by a factor of 4.

Note that in all of these calculations, we have assumed that the system is ideal and that there are no losses due to friction or other factors. In practice, these losses will reduce the mechanical advantage of the system and make it more difficult to lift or move objects.

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