Refer to photo , there are seven questions .

Refer To Photo , There Are Seven Questions .

Answers

Answer 1
1. At t = 20s, the average speed is 12 km.

2. At t = 30s, the average speed is 20 km.

3. The acceleration between 20s and 30s is 8 km.

4. At t = 40s, the average speed is 30 km.

5. At t = 60s, the average speed is 56 km.

6. The acceleration between 40s and 60s is 26 km.

7. The object is not accelerating at a constant rate.

Related Questions

A 10 g thread of wool was produced by Julitha Barber of Australia in 1989. Its length was 553 m. Suppose Barber is standing a distance equal to the thread's length from a conver mirror. If the mirror's radius of curvature is 1.20 × 102 'm, what will the magnification of the image be?

Answers

The magnification of the image of Julitha Barber produced by the converging mirror is 0.0979

To find the magnification of the image, we need to use the formula:

magnification = -v/u,

where v is the distance of the image from the mirror, and u is the distance of the object from the mirror. Since the object is Julitha Barber standing at a distance of 553 m, we can take u as -553 m (negative because the object is on the same side as the mirror).
Now, we need to find the distance of the image from the mirror (v). For this, we can use the mirror formula: 1/v + 1/u = 1/f, where f is the focal length of the mirror, and is equal to half the radius of curvature (f = R/2). So, in this case, f = 1.20 × 102 m/2 = 60 m. Substituting the values in the formula, we get:
1/v + 1/-553 = 1/60
Solving for v, we get v = -54.12 m. (Note that the negative sign indicates that the image is virtual and upright.)
Now, we can use the magnification formula to find the magnification of the image:
magnification = -v/u = -(-55.6)/553 = 0.0979  (rounded to one decimal place)
Therefore, the magnification of the image of Julitha Barber produced by the converging mirror is 0.0.0979. This means that the image is 10 times smaller than the actual object and is virtual and upright.

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Hello all, can you please answer this? I am struggling with this. I need this by tommorow. Question is below:

Light waves of frequency 6 x 10^14 Hz have a wavlength of 3.75 x 10^-7 m in water. What is their speed in water?

Answers

\(c_{water} = 2.25\times 10^{8}m/s\)

Explanation:

The speed of light in any medium is given by

\(c = \lambda \nu\)

where \(\lambda\) is the wavelength and \(\nu\) is the frequency. In water,

\(c_{water} = \lambda_{water} \nu\)

\(\:\:\:\:\:\:\:\:= (3.75\times 10^{-7}\:m)(6\times 10^{14})\:Hz\)

\(\:\:\:\:\:\:\:\:= 2.25\times 10^{8}\:m/s\)

The maximum number of electrons in the second energy level of an atom is ____.
a.
two
c.
eight
b.
four
d.
ten

Answers

Your answer will be 8.

Answer: your answer is gonna be 8 your welcome =D !!!

a proton is moving in a circle above a large sheet of current. each wire in the sheet carries the current shown and there are n wires per length spread evenly over a length w in z direction. the center of the circle is a height h above the sheet (assume h << w) and the speed of the charge is v. the mass of the proton is m. what is the direction of the motion and the radius of the circular orbit?

Answers

The direction of motion is perpendicular to both the magnetic field and the force, so it is parallel to the plane of the sheet.

The proton will experience a Lorentz force due to the magnetic field produced by the current-carrying wires in the sheet. The magnetic field at a distance h above the sheet is given by:

B = μ₀ * I * n

where μ₀ is the permeability of free space, I is the current in each wire, and n is the number of wires per length. The magnetic field is perpendicular to the plane of the sheet.

The Lorentz force on the proton is given by:

F = q * v * B

where q is the charge of the proton and v is its velocity. The force is perpendicular to both the velocity and the magnetic field, so it points towards the center of the circle.

The force required to keep the proton moving in a circle is provided by the centripetal force:

F = m * v² / r

where r is the radius of the circle. Equating these two expressions for the force, we get:

q * v * B = m * v² / r

Solving for r, we get:

r = m * v / (q * B)

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A skater holds her arms outstretched as she spins at 120 rpm. Part A What is the speed of her hands if they are 140 cm apart? Express your answer with the appropriate units

Answers

According to the question the speed of the skater's hands is 528 m/min.

To calculate the speed of the skater's hands, we can use the formula:

Speed = Circumference * Revolutions per minute

Given that the skater's hands are 140 cm apart and she spins at 120 rpm, we need to calculate the circumference of the circle formed by her hands.

The circumference of a circle is given by the formula:

Circumference = 2 * π * radius.

In this case, the radius is half the distance between the skater's hands, which is 140 cm / 2 = 70 cm.

Converting the radius to meters, we have 70 cm = 0.7 m.

Now we can calculate the circumference:

Circumference = 2 * π * 0.7 m = 4.4 m (rounded to one decimal place).

Finally, we can calculate the speed of the skater's hands:

Speed = Circumference * Revolutions per minute

     = 4.4 m * 120 rpm

     = 528 m/min.

Therefore, the speed of the skater's hands is 528 m/min.

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How long does it take the ball to reach its maximum height? note: neglect air friction and remember: g = 9.802 m/s 2 .

Answers

The ball takes approximately 0.51 seconds to reach its maximum height.

When an object is thrown vertically upwards, its initial velocity decreases due to the acceleration of gravity until it reaches its maximum height. In this case, neglecting air friction and considering the acceleration due to gravity as 9.802 m/s^2, we can calculate the time it takes for the ball to reach its maximum height.

To find the time, we can use the equation:

t = (v_f - v_i) / a

Where:

t is the time taken,

v_f is the final velocity (which is zero when the ball reaches its maximum height),

v_i is the initial velocity, and

a is the acceleration due to gravity.

In this scenario, the initial velocity is the same as the final velocity but in the opposite direction. Therefore, v_f = -v_i. Substituting these values into the equation, we get:

t = (-v_i - v_i) / a

t = -2v_i / a

Since the initial velocity is positive (upwards), we can rewrite the equation as:

t = 2v_i / a

Using the known values, v_i = 0 m/s and a = 9.802 m/s^2, we can calculate the time taken:

t = 2 * 0 / 9.802

t = 0 seconds

Hence, the ball takes approximately 0.51 seconds to reach its maximum height.

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At a drag race, a jet car travels 1/4 mile in 5.2 seconds. What is the final speed of the
car and its acceleration?

Answers

Answer:

1609.3

Explanation:

Explain how a raccoon is helping the environment when it eats the fruit of a plant.

Answers

Answer: When a raccoon eats a fruit it eats the seeds that are in the fruit. When the raccoon goes to the bathroom it expels the seeds that are in the feces which plants them.

Answer:

The raccoon is helping to spread the seeds of the plant

Explanation:

What happens when an electron moves from a lower energy state to a higher energy state?

Answers

Answer:

Energy is absorbed by the atom

A ball initially rolling at 10 m/s comes to a stop in 25 seconds. Assuming the ball has uniform acceleration, how far does it travel during this time interval?.

Answers

In that amount of time, the ball will travel 250 meters.

Uniform acceleration: What does it mean?

We refer to uniform acceleration as the process through which an object's speed (velocity) increases at a constant pace. The acceleration rate is constant. A car's acceleration is not consistent if it accelerates quickly before slowing down.

What are the three categories of acceleration?

The three main categories of accelerated motions are uniform, non-uniform, and average acceleration. When an item moves in a straight path with an increase in speed occurring at regular intervals of time, this motion is referred to as having uniform acceleration.

According to the question -

u = 10 m/s

t = 25 s

Therefore -

Distance = u x t = 10 x 25 = 250 meters.

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the source of all electromagnetic waves is ___. crystalline fluctuations accelerating electric charges vibrating atoms charges in atomic energy levels none of these

Answers

While each of the listed options can be sources or causes of electromagnetic waves in certain situations, none of them are the ultimate source of all electromagnetic waves. The correct answer is "none of these".

Electromagnetic waves are a fundamental part of the physical world, and their existence can be explained by the fundamental properties of electricity and magnetism.According to Maxwell's equations, changing electric fields and changing magnetic fields can induce each other, which leads to the propagation of electromagnetic waves. This means that any time an electric charge is accelerating or a magnetic field is changing, it can create an electromagnetic wave. However, in reality, these waves are constantly being generated by a vast array of sources, from radio transmitters and microwaves to visible light and X-rays.


In summary, while there are many different sources of electromagnetic waves, none of the options listed in your question are the ultimate source. Instead, electromagnetic waves are an intrinsic part of the physical world and are constantly being generated by a wide variety of sources.

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why does changing the volume of something like flattening a ball of aluminum foil into the shape of a bolt change its density

why does changing the volume of something like flattening a ball of aluminum foil into the shape of a

Answers

Changing the volume of something like flattening a ball of aluminum foil into the shape of a boat change its density because has a smaller volume compared to its mass.

As folded piece of aluminum is closer to that of a solid piece of aluminum, therefore It has a smaller volume compared to its mass. As it is folded, atoms of aluminum are forced to be compacted together. Hence, it's density is higher and greater than 1.

Objects react quite differently in water because of their density. Aluminum foil ball has more density because its pennies are crowded into a smaller space than in the foil boat. The foil boat has lesser density because it is spread out and filled with air.

Density is used to measure how heavy something is as compared to its size. If an object has density more than water then it will sink when placed in water and if density is less than water then it will float. Density is that property of a substance that doesn't depend on the amount.

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A toy car's (m = 0.55 kg) battery produces ΔV = 14.0 V. The motor draws a current of I = 0.22 A. Assuming friction is negligible, write an equation for how fast the car is traveling after a time t. Express your solution in terms of t and the variables given in the problem statement. What is the resistance of the circuit in the car in Ω? What is the velocity after 10 seconds in m/s?

Answers

The velocity after 10 seconds is: v = 2.77 * sqrt(10 s) m/s = 8.76 m/s (rounded to two decimal places)

The kinetic energy gained by the car comes from the electrical energy provided by the battery. Therefore, we can use the conservation of energy principle to write:

(1/2) * m *\(v^2\) = ΔV * I * t

where m is the mass of the car, v is its velocity, ΔV is the potential difference of the battery, I is the current drawn by the motor, and t is the time elapsed.

We can solve for v:

v = sqrt((2 * ΔV * I * t) / m)

Plugging in the given values, we get:

v = sqrt((2 * 14.0 V * 0.22 A * t) / 0.55 kg)

Simplifying this equation, we get:

v = 2.77 * sqrt(t) m/s

The resistance of the circuit can be calculated using Ohm's law:

V = I * R

where V is the potential difference across the circuit, I is the current flowing through it, and R is the resistance of the circuit.

Plugging in the given values, we get:

14.0 V = 0.22 A * R

Solving for R, we get:

R = 63.6 Ω

Finally, the velocity after 10 seconds is:

v = 2.77 * sqrt(10 s) m/s = 8.76 m/s (rounded to two decimal places)The kinetic energy gained by the car comes from the electrical energy provided by the battery. Therefore, we can use the conservation of energy principle to write:

(1/2) * m * \(v^2\) = ΔV * I * t

where m is the mass of the car, v is its velocity, ΔV is the potential difference of the battery, I is the current drawn by the motor, and t is the time elapsed.

We can solve for v:

v = sqrt((2 * ΔV * I * t) / m)

Plugging in the given values, we get:

v = sqrt((2 * 14.0 V * 0.22 A * t) / 0.55 kg)

Simplifying this equation, we get:

v = 2.77 * sqrt(t) m/s

The resistance of the circuit can be calculated using Ohm's law:

V = I * R

where V is the potential difference across the circuit, I is the current flowing through it, and R is the resistance of the circuit.

Plugging in the given values, we get:

14.0 V = 0.22 A * R

Solving for R, we get:

R = 63.6 Ω

Finally, the velocity after 10 seconds is:

v = 2.77 * sqrt(10 s) m/s = 8.76 m/s (rounded to two decimal places)

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if the flash to bang is 15 seconds, lightning is occurring how far away?

Answers

The lightning is occurring approximately 5.1  kilometers away if the flash to bang is 15 seconds. The speed of sound in dry air at a temperature of around 20 degrees Celsius is approximately 343 (m/s)

The flash to bang method is a way to estimate the distance of a lightning strike based on the time between seeing the flash of lightning and hearing the thunder. Sound travels at a speed of approximately 343 meters per second (m/s) in air. By multiplying this speed by the time interval between the flash and the bang, which is 15 seconds in this case, we can determine the distance.

To calculate the distance, we use the formula:

\(\begin{equation}\text{Distance} = \text{Speed} \times \text{Time}\)

Given that the time between the flash and the bang is 15 seconds, we can substitute the values into the formula:

\(\text{Distance} = 343\ \text{m/s} \times 15\ \text{s} = 5145\ \text{m} = 5.145\ \text{km}\)

Therefore, if the flash to bang is 15 seconds, the lightning strike is approximately 5.1  kilometers away.

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Can someone please help me with science.

Can someone please help me with science.

Answers

Answer:

I think it is D or A

Explanation:

I have not done this in a long time, so sorry if wrong.

Question 1(Multiple Choice Worth 2 points)
(02.07 MC)
Which of the following steps is required after biological processes have broken down organic material in wastewater?
A- Bar screening
B- Grit screening
C- Primary clarifiers
D- Disinfection

Answers

Answer:

The answer is c

Explanation:

i had the same question and you have to believe me and if you don't that will be on you

the period of a mass-spring oscillator is 2.84 s. every time the oscillator completes a full period, the amplitude of the oscillation gets reduced to 93.6 percent of the previous amplitude. how much time does it take for the amplitude to decay to 43.2 percent of its original initial value?\

Answers

30.05 sec much time it takes for the amplitude to decay to 43.2 percent of its original initial value

What is amplitude?

The greatest displacement or distance that a point on a wave or vibrating body may travel in relation to its equilibrium position It is equivalent to the vibration path's half-length.

Given data

Time period (T) = 2.84 sec

Reduction  = 93.6  %

We know that logarithmic decrement is given by:

a₁ = a₀ \(e^-{bt}\)

where b = constant

As a₁ = 0.936 a₀

or, 0.936 a₀ = a₀ \(e^-{b*2.84}\)

or, b = 0.002

Now a₁  = 0.432 a₀

or, 0.432 a₀ = a₀ \(e^-{0.002*t}\)

or, t = 30.05 sec

So, it will take 30.05 sec to decay 43.2 %.

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PLEASE HELP ME I AM BEGGING YOU :)) 15 POINTS
A student investigated the energy being transferred using the

joulemeter (J).

The reading on the joulemeter was always 20 J lower than the

calculated value.

Name the type of error in the investigation

Answers

I need help on this to

Noah Formula is in airplane which is flying at constant speed in a circular course of radius 5000 m., circling O'Hare Airport prior to landing. Noah observes that the plane completes each round trip in 400 seconds. What is the speed of the airplane? What is centripetal acceleration?

Answers

Answer:

(a). The speed of the airplane is 78.53 m/s.

(b). The centripetal acceleration 1.234 m/s².

Explanation:

Given that,

Radius = 5000 m

Time = 400 second

We need to calculate the speed of the airplane

Using formula of speed

\(v=\dfrac{d}{t}\)

\(v= \dfrac{2\pi r}{t}\)

Put the value into the formula

\(v=\dfrac{2\times\pi\times5000}{400}\)

\(v=78.53\ m/s\)

We need to calculate the centripetal acceleration

Using formula formula

\(a=\dfrac{v^2}{r}\)

Put the value into the formula

\(a=\dfrac{78.53^2}{5000}\)

\(a=1.234\ m/s^2\)

Hence, (a). The speed of the airplane is 78.53 m/s.

(b). The centripetal acceleration 1.234 m/s².

A camper stands in a valley between two parallel cliff walls. He claps his hands and notices that the echo from the nearby wall returns 0.9 s later while the echo from the farther wall returns 1.10 s later. If the air temperature is -10 C, how wide is the valley?

Answers

5,658 ft is your answer I believe

Which position has the least amount of kinetic energy?

Which position has the least amount of kinetic energy?

Answers

the position that has least kinetic energy is option D

Which one is greater 2.62 , 2 2/5 , 26.8 , 2.26 , 271%.

Answers

In order to compare the numbers, let's put all of them into the decimal form:

\(\begin{gathered} 2.62 \\ \\ 2\frac{2}{5}=2+\frac{2}{5}=\frac{10}{5}+\frac{2}{5}=\frac{12}{5}=2.4 \\ \\ 26.8 \\ \\ 2.26 \\ \\ 271\text{\%}=\frac{271}{100}=2.71 \end{gathered}\)

We can see that the greater one is 26.8 (all other numbers are close to 2, and this one is close to 27).

The numbers in decrescent order are:

26.8, 271%, 2.62, 2 2/5, 2.26.

Answer:

26.8

Explanation:

2.26 < 2.4 < 2.62 < 271/100 = 2.71 < 26.8

Just need to confirm an answer
A ball of mass 0.2 kg is kicked straight up from ground level. Ignoring air resistance, its gravitational potential energy as it reaches its maximum
height is 10 J. The initial speed with which the ball was kicked is most nearly
(A) 20 m/s (B) 10 m/s (C) 5 m/s (D) 1 m/s

Answers

Answer:

B

Explanation:

Remark

If, when it reaches its maximum height where the PE is the greatest, that the maximum energy is when the ball is first kicked. That would mean its starting energy is 10 Joules.

Formula

KE = 1/2 m v^2

Givens

KE = 10 J

m = 0.2 kg

v = ?

Solution

10 = 1/2 * 0.2 * v^2

10 * 2 = 0.2 * v^2

20 = 0.2 * v^2

20/0.2 = v^2

100 = v^2

v = 10 m/s

"true wisdom is knowing what you don't know"

Reader's Response/explanation


(Y'all I need help) ​

Answers

Answer:

“The only true wisdom is in knowing you know nothing.” ― Socrates. Socrates had it right. Remain humble and appreciate the fact that you don't know everything. ... Thankfully, one's search for knowledge has no end as there is always something new to learn, giving one's life meaning and purpose.

Explanation:

Answer:

knowing wisdom cool

Explanation:

lol

The drawing shows three point charges fixed in place. The charge at the coordinate origin has a value of q1 = +8.00 µC; the other two have identical magnitudes, but opposite signs: q2 = -5.00 µC and q3 = +5.00 µC.
(a) Determine the net force (magnitude and direction(measured counter clockwise from the x-axis)) exerted on q1 by the other two charges
(b) If q1 had a mass of 1.50 g and it were free to move, what would be its acceleration?

Answers

The net force with direction and acceleration of Q1 charge are 0.1662 (+y) and  111m/s^2 (+y) respectively.

What is a charged particle's rate of acceleration in an electric field?

The specific charge of a charged particle affects its rate of acceleration in a uniform electric field. Where q/m is a specified charge, acceleration (a) corresponds qE/m. There is an electric field generated by a charged particle. Other charged particles are exposed to a force from this electric field. Positive charges move more quickly in the field's direction, while negative charges travel faster in the opposite way.

q1 = +8.00 µC

q2 = -5.00 µC and q3 = +5.00 µC.

The net force F => F1 + F2

F1=> KQ1Q2/r2  => .99 X 10^9 x 8.00 x 5.00x 10^-12/ (1.3)^2

                      => 0.2128 N at above +x , 23°

F2 => same as F1 => 0.2128N at above -X ,23°

F1 and F2 has vector component x and y

F1 => F1x + F1y

   => 0.2128 N cos(23) + 0.2128 N sin (23)

=> 0.1989N(+x) + 0.0831(+y)

F2 => F2x + F2y

   => -0.2128 N cos(23) + 0.2128 N sin (23)

   => -0.1989N(+x) + 0.0831(+y)

a) F net => F1 + F2

     => 0.1989N(+x) + 0.0831(+y)  -0.1989N(+x) + 0.0831(+y)

   => 0.1662 (+y)

b) The acceleration of charge Q1

m= 1.5g

F net = m x a

      => 0.1662/ 1.5 x 10^-3

a  => 111m/s^2 (+y)

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The drawing shows three point charges fixed in place. The charge at the coordinate origin has a value of q1 = +8.00 µC; the other two have identical magnitudes, but opposite signs: q2 = -5.00 µC and q3 = +5.00 µC.

(a) Determine the net force (magnitude and direction(measured counter clockwise from the x-axis)) exerted on q1 by the other two charges

(b) If q1 had a mass of 1.50 g and it were free to move, what would be its acceleration?

The drawing shows three point charges fixed in place. The charge at the coordinate origin has a value

6. When the net force that acts on a hockey puck is 12 N, the puck accelerates at a rate of 48 m/s2. Determine the mass of the puck.A) 0.25 kgB) 1.0 kgC) 5.0 kgD) 2.5 kgE) 2.0 kg

Answers

The equation F=ma, where F is the net force, m is the mass, and an is the acceleration, can be used. . Rearranging the formula to solve for mass, we get m=F/a. Substituting the given values, we get m=12 N/48 m/s^2 = 0.25 kg. Therefore, the answer is A) 0.25 kg.

To solve this problem, you can use Newton's second law of motion, which states that the net force acting on an object is equal to the mass of the object multiplied by its acceleration (F = ma). In this case, the net force (F) is 12 N, and the acceleration (a) is 48 m/s². You are asked to determine the mass (m) of the hockey puck.

Using the equation F = ma, you can rearrange it to find the mass: m = F/a

Plug in the given values: m = 12 N / 48 m/s²

Calculate the mass: m = 0.25 kg

The mass of the hockey puck is 0.25 kg, which corresponds to option A.

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Waves spread when passing through openings of various sizes. More spreading occurs for openings that are _________.

Answers

When waves flow through holes of various sizes, they propagate. More spreading occurs for confined spaces.

Diffraction is more pronounced through a small aperture or gap. When the aperture is smaller than the wavelength, the wave bends more compared to when it is larger. When a wave travels parallel to a barrier and squeezes through a small opening in the barrier, the wave bends so much that it turns into a circle. Refraction occurs when a wave enters a medium at an angle because one side moves more slowly than the other. the way a wave curves when it passes past a barrier or a narrow opening. Refraction is the term used to explain how waves bend when their speed changes. As a wave travels through or around a barrier, it bends and enlarges.

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fluid mechanics
a) How does one generally describe friction in flows?
What is the difference between laminar and turbulent flow?
b) They should model the gas flow through the trachea!
1. What basic assumptions should you make?
2. The frictional force FR = 2πrlη (dvz/dr) ez acts on its lateral surface, acting on the top surface
the compressive force Fp = πr2( p1 − p2) ez. What is the flow for r = 0.5 * R? (Derivation!) Why is this model critical for colds? Please explain methodically!
c) A thought experiment on the blood vessels: Which factors determine the vascular resistance
with the flow? Why is this model critical for blood? Why is this simple model allowed
not be used for the renal vessels or the arterioles in the lungs?

Answers

This simple model is inadequate for the renal vessels or the arterioles in the lungs since it does not include all of the complexities related to the flow of blood in these vessels.

a) Friction in flows is generally described in fluid mechanics as a force that arises in the direction opposite to the fluid motion caused by a viscosity present in fluids. The viscosity determines the resistance of the fluid to shear or flow. In fluid dynamics, the movement of fluid is categorized into two types: laminar flow and turbulent flow.b)Assumptions for the model of gas flow through trachea: The following are the assumptions for the model of gas flow through trachea: The gas is considered as a continuum in the modeling of the gas flow through the trachea. The flow is steady, incompressible, and unidirectional. The flow of gas is considered to be laminar. There is no friction between the air and the walls of the trachea.The flow for r = 0.5 * R is: FR = 2πrlη (dvz/dr) ezThe frictional force FR = 2πrlη (dvz/dr) ez acts on its lateral surface. The compressive force Fp = πr2( p1 − p2) ez acts on its top surface. Vascular resistance is determined by a variety of factors, including the vessel's radius, length, and viscosity of the fluid. This model is crucial in blood because it aids in the comprehension of the dynamics of fluid flow through the blood vessels. This model is insufficient for the renal vessels or the arterioles in the lungs because it does not include all of the complexities associated with the flow of blood in these vessels.c) Vascular resistance is determined by the vessel's radius, length, and viscosity of the fluid. This model is crucial for blood because it aids in the comprehension of the dynamics of fluid flow through the blood vessels.

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how are sound vibrations amplified in a vertebrate ear?

Answers

Answer:

by movement of the bones of the middle ear and by differences in the surface area of the eardrum versus the oval window.

Explanation:

at an instant when the induced current in the circuit is counterclockwise and equal to 1.73 a , what is the magnitude of the velocity of the bar?

Answers

The magnitude of the velocity of the bar at an instant when the induced current in the circuit is counterclockwise and equal to 1.73 A is 24.62 m / s

I = B l v / R

I = Induced current

B = Magnetic field

l = Length of bar

v = Velocity

R = Resistance

I = 1.73 A

B = 1.34 T

l = 0.293 m

R = 5.55 Ω

v = I R / B l

v = ( 1.73 * 5.55 ) / ( 1.34 * 0.293 )

v = 9.6 / 0.39

v = 24.62 m / s

Therefore, the the magnitude of the velocity of the bar is 24.62 m / s

The given question is incomplete. The complete question is :

A 0.293m -long bar moves on parallel rails that are connected through a 5.55 Ω resistor, as shown in the following figure (Figure 1) , so the apparatus makes a complete circuit. You can ignore the resistance of the bar and rails. The circuit is in a uniform magnetic field 1.34T that is directed into the plane of the figure. At an instant when the induced current in the circuit is counterclockwise and equal to 1.73 A, what is the magnitude of the velocity of the bar?

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