Recently, TWA reported an on-time arrival rate of 78.4%. Assume that a later random sample of 750 flights results in 630 that are on time. If TWA were to claim that its on-time arrival rate is now higher than 78.4%, would the claim be supported at the 0.02 level of significance? Please show all 4 steps of the classical approach.

Answer:

\( 2^{2x + 2} = 2^{4x - 4} \)

Step-by-step explanation:

\( 4^{x + 1} = 16^{x - 1} \)

\( 2^{2(x + 1)} = 2^{4(x - 1)} \)

\( 2^{2x + 2} = 2^{4x - 4} \)

The center of mass of the object is located at the point (1.67 cm, 6.33 cm).

The x-coordinate of the center of mass is 1.67 cm.

To find the center of mass (COM) of the object,

x_cm = (1/M) Σmixi

y_cm = (1/M) Σmiyi

where M is the total mass of the object and the sum is over all the individual masses that make up the object.

Given the diagram and information,

Mass A = 300 g with x-coordinate 0 cm and y-coordinate 0 cm

Mass B = 200 g with x-coordinate 0 cm and y-coordinate 10 cm

Mass C = 100 g with x-coordinate 10 cm and y-coordinate 8 cm

M = 300 g + 200 g + 100 g = 600 g

x_cm = (1/M) [(300 g)(0 cm) + (200 g)(0 cm) + (100 g)(10 cm)] = 1.67 cm

y_cm = (1/M) [(300 g)(0 cm) + (200 g)(10 cm) + (100 g)(8 cm)] = 6.33 cm

The x- coordinate is,  x_cm = 1.67 cm.

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Answer:

2x

Step-by-step explanation:

You're dividing 14 multiplied by a number by 7 multiplied by a number. So you'd get 2 multiplied by a number.

Note that the parameters of the graph a and graph b are given below.

Graph A - y=2(x-1)²

See graph attached.

Graph B - y = 1/2x² + 3

Vertex: The vertex of the function is (0, 3).

Axis of symmetry: The axis of symmetry is the vertical line passing through the vertex, which is x = 0.

Y-intercept: The y-intercept is the point where the graph intersects the y-axis. It is (0, 3).

Minimum or maximum: The coefficient of x² is positive, which means the parabola opens upwards, and therefore the function has a minimum value. The minimum value is 3.

Solutions: To find the solutions or roots of the quadratic equation, we need to set y or f(x) equal to zero and solve for x.

0 = 1/2 x² + 3

Subtracting 3 from both sides, we get:

-3 = 1/2 x²

Multiplying both sides by -2, we get:

6 = -x²

Taking the square root of both sides, we get:

x = ±√(-6)

Since the square root of a negative number is not a real number, the function has no real roots.

Minimum or maximum value: The minimum value of the function is 3.

Range: The range of the function is y ≥ 3, because the function has a minimum value of 3.

Domain: The domain of the function is all real numbers, because there are no restrictions on the values of x for which the function is defined.

Stretch/Shrink/Standard: The coefficient of x^2 is positive and less than 1, which means that the graph of the function is narrower than the graph of y = x². This is an example of a standard quadratic function that has been vertically compressed by a factor of 1/2.

See graph attached.


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The measures  angles are 26, 39 and 96.

According to the triangle's "angle sum property," a triangle's angles add up to 180 degrees. Three sides and three angles, one at each vertex, make up a triangle. The sum of the interior angles in a triangle is always 180, regardless of whether it is acute, obtuse, or right.

Given:

Angles are 96, x, x+12

Now, using Angle Sum Property

96 + x + x + 12= 180

2x + 108 = 180

2x = 72

x= 26

So, the angles are 26, 39 and 96.

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Answer:

0.333 in / hr

Step-by-step explanation:

203 / 25.4

7.992 in

7.922 in / day

7.922 in / 24 hr

0.333 in / hr

The speed of the ball after one second is given as follows:

9.175 m/s.

The speed function is the derivative of the position function, which is graphed in this problem.

The position function, in meters, for a projectile's height, is given as follows:

h(t) = -4.9t² + v(0)t + h(0).

In which:

From the graph, the initial height is given as follows:

h(0) = 6.

When t = 4, h = 2.5, hence the initial velocity is obtained as follows:

2.5 = -4.9(4)² + 4v(0) + 6

4v(0) = 2.5 - 5 + 4.9(4)²

4v(0) = 75.9

v(0) = 75.9/4

v(0) = 18.975.

Then the position function is of:

h(t) = -4.9t² + 18.975t + 6.

The velocity function is the derivative of the position, hence:

v(t) = -9.8t + 18.975.

Then the velocity after one second is of:

v(1) = -9.8 + 18.975 = 9.175 m/s.

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Answer:

The converse is:

If a number is a whole number, then it is a natural number.

Step-by-step explanation:

Considering the conditional:

If a number is a natural number, then it is a whole number.

its converse is:

If a number is a whole number, then it is a natural number.

The converse is:

If a number is a whole number, then it is a natural number.

The following information should be considered:

Considering the conditional:

Its converse is:

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The cost of 1 game of laser tag and 5 games of bowling is: 160

Algebraic word problems are defined as questions that require translating sentences to equations, then solving those equations. The equations we need to write will only involve. basic arithmetic operations. and a single variable.

We are told that the bowling fans want to play just 1 game of laser tag and more than 1 game of bowling.

Thus, using the given parameters we are given is expressed as:

(25*5) + 35 = 160

Thus, they'll have enough for 5 games of bowling 1 game of laser tag and snacks.

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Given a discount of 20% and a manufacturer's coupon of $200, the price after the discount and coupon, (C ∘ D)(x), is 0.8x - 200.

A discount is an amount that reduces the price of a retail item.

Discounts are offered as rates and the discounted price is computed by multiplying the discount factor and the price.

Discount rate on offer = 20%

Discounting factor = 80% or 0.8 (100 - 20%)

Manufacturer's coupon off the price = $200

Let the price of the bureau = x

The price after the discount (discounted price) is given by D(x)

D(x) = 0.8x

The price after the coupon = C(x) = x - 200

The price after applying the discount and the coupon, (C ∘ D)(x) = 0.8x - 200

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Wilson's Warehouse sells a certain brand's bureau. They are offering a 20% discount in addition to accepting a manufacturer's coupon for $200 off. Let the price of the bureau be x. If the price after the discount is given by D(x) and the price after the coupon is C(x), find (C ∘ D)(x).

Answer:

18 is less then 23

Step-by-step explanation:

Answer:

4. Is 6 and 5. Is 8

Step-by-step explanation:

Answer:

16/40 = 40%

Step-by-step explanation:

I divided 16/40 and got 0.4,

To turn a decimal into a percentage, either multiply by 100 or move the decimal to the right 2 times.

Answer:

Step-by-step explanation:

The answer is 2.65 x 10^5.

Hope it helped you.

Plz mark me brainliest.

Answer:

b 2,557.51

Step-by-step explanation:

The simple interest formula is A = P(1+r t) then the value of t =33.2210 years.

Simple interest is a quick and simple formula for figuring out how much interest will be charged on a loan. The daily interest rate, the principle, and the number of days between payments are multiplied to calculate simple interest.

The simple interest formula is equal to

A = P(1+r t)

where, A is the Final Investment Value

P is the Principal amount of money to be invested

r is the rate of interest

t is Number of Time Periods

P = $ 3300

A = $ 10700

r = 6.75 % = 6.75 / 100 = 0.0675

substitute in the formula above

$10700 = 3300(1+0.0675 t)

simplifying the above equation, we get

Divide both sides by 3300

\($\frac{3300(1+0.0675 t)}{3300}=\frac{10700}{3300}$$\)

Simplifying the above equation, we get

\($1+0.0675 t=\frac{107}{33}$$\)

Subtract 1 from both sides

\($1+0.0675 t-1=\frac{107}{33}-1$$\)

Simplifying the above equation, we get

\($0.0675 t=\frac{74}{33}$$\)

Divide both sides by 0.0675

\($\frac{0.0675 t}{0.0675}=\frac{\frac{74}{33}}{0.0675}\)

\($t=\frac{74}{2.2275}$\)

t = 33.2210 years

Therefore, the value of t exists 33.2210 years.

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Answer:

Yes

Step-by-step explanation:

1.7a+0.3a=0.8

2a=0.8

a=0.4

a) The mean rainfall from seeded clouds exceeds 25 acre-feet is 1.99

b) As per the normal distribution, with the significance level 0.05 the rainfall is normally distributed.

c) The power of the test if the true mean rainfall is 27 acre-feet is 23.5%

d) The sample size would be required to detect a true mean rainfall of 27.5 acre-feet if we wanted the power of the test to be at least 0.9 is 28 clouds

e) The upper bound is greater than 25 acre-feet, we can support the claim that the mean rainfall from seeded clouds exceeds 25 acre-feet with a level of confidence of 99%.

a) To support a claim that mean rainfall from seeded clouds exceeds 25 acre-feet, we can perform a one-tailed hypothesis test with a significance level of α = 0.01.

Substituting the values, we get:

t = (25.96 - 25) / (4.48 / √20) = 1.99

b) To test if the rainfall is normally distributed, we can perform a normal probability plot and a Shapiro-Wilk test.

Using software, we can create a normal probability plot and perform the Shapiro-Wilk test.

The Shapiro-Wilk test also does not reject the null hypothesis that the data is normally distributed at a significance level of α = 0.05, we can assume that the rainfall data is normally distributed.

c) To compute the power of the test if the true mean rainfall is 27 acre-feet, we can perform a one-tailed hypothesis test with a significance level of α = 0.01. The null hypothesis H0 is that the mean rainfall is less than or equal to 25 acre-feet, and the alternative hypothesis Ha is that the mean rainfall is greater than 25 acre-feet.

Substituting the values, we get:

t = (25.96 - 27) / (4.48 / √20) = -1.43

Using software or a t-distribution table, we find that the probability of rejecting the null hypothesis when the true mean is 27 acre-feet is 0.235. Therefore, the power of the test is 0.235 or 23.5%.

d) To determine the sample size required to detect a true mean rainfall of 27.5 acre-feet with a power of at least 0.9, we can use power analysis.

Substituting the values, we get:

d = (27.5 - 25) / 4.48 = 0.56

Therefore, a sample size of at least 28 clouds would be required to detect a true mean rainfall of 27.5 acre-feet with a power of at least 0.9.

e) To answer the question in part (a) by constructing a one-sided confidence bound on the mean diameter, we can use a one-sided confidence interval with a level of confidence of 99%.

Substituting the values, we get:

x + tα,df * (s / √n) = 25.96 + 2.861 * (4.48 / √20) = 27.23

This means that we can be 99% confident that the true population mean rainfall from seeded clouds is greater than 27.23 acre-feet.

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If a 4-yard dumpster cost $95.00 monthly, the total cost for the year is $1,140.

The total cost for the year of the dumpster is the product of the multiplication of the monthly cost and 12.

Multiplication is one of the four basic mathematical operations, including addition, subtraction, and division.

In any multiplication, there must be the multiplicand (the number being multiplied), the multiplier (the number multiplying the multiplicand), and the product (or the result).

The monthly cost of the 4-yard dumpster = $95.00

1 year = 12 months

The total annual cost = $1,140 ($95 x 12)

Thus, using the multiplication operation, we can find that none of the options is correct as the total annual cost but $1,140.

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In the case above, the value of the overhead rate for the second quarter is $17,640.

Note that:

In the case above, for one to be able to calculate the predetermined overhead rate, a person need to divide the value of the  estimated overhead costs which is $52,500 by that of the estimated direct labor hours .

Predetermined overhead rate=Estimated overhead costs/ estimated direct labor hours

Predetermined overhead rate=$52,500/  12,500

Predetermined overhead rate=$4.20/DLH overhead rate

Hence:  $52,500/ 12,500 =   $4.20/DLH overhead rate.

Since the Overhead that was applied at standard hours was said to be allowed, then:

= $4.2 x 2,400 x 1.75

= $17,640.

Therefore, In the case above, the value of the overhead rate for the second quarter is $17,640.

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Answer:

Step-by-step explanation:

Answer:

2

Step-by-step explanation:

The solutions are:

(1/2,11/4) and (1,2)

Answer:

83%

Step-by-step explanation:

No. of questions answered correctly = 166

Total no. of questions = 200

Percentage of questions answered correctly = (166/200)*100 = 83%

Answer:

30

Step-by-step explanation:

Those prime numbers are 2, 3 and 5

2 * 3 is 6 * 5 is 30

i hope this helped, please mark Brainliest, thank you!!

Answer:

30

Step-by-step explanation:

The three smaller primes are: 2, 3, and 5

So their product is: 2 * 3 * 5 =30