Rebecca and her dad went ice-fishing this winter. They caught 18 total fish, including 13 yellow perch. If on the last day of the trip, Rebecca randomly selected 15 fish to donate to fishermen who hadn't caught any fish that day, what is the probability that exactly 11 of the chosen fish are yellow perch? Write your answer as a decimal rounded to four decimal places .

There is a 1/4 or 25% chance that Jamal will end up with tails on the coin and an even number on the die when he rolls the die and tosses the coin.

The probability of rolling an even number on the die is 3/6 or 1/2, since there are three even numbers (2, 4, 6) out of the six possible outcomes. Similarly, the probability of getting tails on the coin is 1/2 since there are two possible outcomes, heads or tails. To find the probability of both events happening simultaneously, we need to multiply the probabilities of each event. Thus, the probability of getting tails on the coin and an even number on the die is:

P(tails and even) = P(tails) × P(even)

= 1/2 × 1/2

= 1/4

Therefore, there is a 1/4 or 25% chance that Jamal will end up with tails on the coin and an even number on the die when he rolls the die and tosses the coin.

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Answer:

\(\sf 1. \quad \dfrac{3}{8}\)

\(\sf 2. \quad \dfrac{7}{24}\)

Step-by-step explanation:

Spinner 1 is divided into 6 congruent sections.

There are 3 red sections, 2 blue sections and 1 yellow section.

Therefore, the probability of spinning each of the three colors is:

    \(\bullet \quad \sf P(R_1)=\dfrac{3}{6}=\dfrac{1}{2}\)

    \(\bullet \quad \sf P(B_1)=\dfrac{2}{6}=\dfrac{1}{3}\)

    \(\bullet \quad \sf P(Y_1)=\dfrac{1}{6}\)

Spinner 2 is divided into 3 sections of differing sizes.

The red section is half of the spinner. The blue and yellow sections are quarters of the spinner.

Therefore, the probability of spinning each of the three colors is:

    \(\bullet \quad \sf P(R_2)=\dfrac{1}{2}\)

    \(\bullet \quad \sf P(B_2)=\dfrac{1}{4}\)

    \(\bullet \quad \sf P(Y_2)=\dfrac{1}{4}\)

If each spinner is spun once, then:

The probability that both spinners both show red is:

\(\sf P(R_1)\;and\;P(R_2)=\dfrac{1}{2} \times \dfrac{1}{2}=\dfrac{1}{4}\)

The probability that both spinners both show blue is:

\(\sf P(B_1)\;and\;P(B_2)=\dfrac{1}{3} \times \dfrac{1}{4}=\dfrac{1}{12}\)

The probability that both spinners both show yellow is:

\(\sf P(Y_1)\;and\;P(Y_2)=\dfrac{1}{6} \times \dfrac{1}{4}=\dfrac{1}{24}\)

Therefore, the probability that both spinners show the same colour is:

\(\sf P(R_1\;\&\;R_2)\;or\;P(B_1\;\&\;B_2)\;or\;P(Y_1\;\&\;Y_2)=\dfrac{1}{4}+\dfrac{1}{12}+\dfrac{1}{24}=\dfrac{9}{24}=\dfrac{3}{8}\)

If each spinner is spun once, the probability of getting a red from spinner 1 and a blue from spinner 2 is:

\(\sf P(R_1)\;and\;P(B_2)=\dfrac{1}{2} \times \dfrac{1}{4}=\dfrac{1}{8}\)

The probability of getting a blue from spinner 1 and a red from spinner 2 is:

\(\sf P(B_1)\;and\;P(R_2)=\dfrac{1}{3} \times \dfrac{1}{2}=\dfrac{1}{6}\)

Therefore, the probability of getting a red-blue combination is:

\(\sf P(R_1\;\&\;B_2)\;or\;P(B_1\;\&\;R_2)=\dfrac{1}{8}+\dfrac{1}{6}=\dfrac{7}{24}\)

Let's denote the amount Jolene invested at 3 percent interest as 'x' dollars. Since she put twice as much in the lower-yielding account, the amount she invested at 9 percent interest would be '2x' dollars.

To calculate the interest earned from each account, we'll use the formula: Interest = Principal × Rate × Time.

For the 3 percent interest account:

Interest_3_percent = x × 0.03

For the 9 percent interest account:

Interest_9_percent = 2x × 0.09

We know that the total annual interest is $3120, so we can set up the equation:

Interest_3_percent + Interest_9_percent = 3120

Substituting the above equations, we have:

x × 0.03 + 2x × 0.09 = 3120

Simplifying the equation:

0.03x + 0.18x = 3120

0.21x = 3120

Dividing both sides of the equation by 0.21:

x = 3120 / 0.21

x = 14857.14

Therefore, Jolene invested approximately $14,857.14 at 3 percent interest and twice that amount, $29,714.29, at 9 percent interest.

Answer:

Step-by-step explanation:

X is the amount invested at 6%

Y is the amount invested at 9%

0.06X + 0.09Y = 4998

X = 2Y

0.06(2Y) + 0.09Y  = 4998

.12Y + 0.09Y = 4998

0.21Y = 4998

21Y = 499800

Y = 499800/21 = 23800

So X = 2*23800 = 47600

$47,600 is invested at 6% and $23800 is invested at 9%

Answer:

a. 1

b. 7

c. -4

Step-by-step explanation:

a. 5 + (-4)

= 5 - 4

= 1

b. -9 + 16

= 7

c. 10 + (-14)

= 10 - 14

= - 4

If you further explanation how it come then please tell.

Answer:

0.35

Step-by-step explanation:

Answer: 12/50

Step-by-step explanation: convert all of them to decimals.

Answer:

Step-by-step explanation:

1*(8^3) + 1*(8^2) + 3*(8^1) + 0*(8^0) = 600

The slope can be calculated as the quotient between the difference in the y-coordinates of two points, and the difference in the x-coordinates of the same two points.

We pick any 2 known points, like (0,2) and (5,4).

We calculate the slope as:

Answer:

The slope is m=2/5=0.4

The expression that represents the number of reams of paper the company produced during the second year is 4.704 × 10¹⁰. The correct option is D. 4.704 × 10¹⁰

From the question, we are to determine the expression that represents the number of reams of paper the company produced during the second year

From the given information,

During the first year of operation,

The company produced 8.4 × 10⁹ reams of paper

And

During the second year,

the company produced 5.6 times the number of reams of paper that it produced during the first year.

Thus,

The number of reams of paper the company produced during the second year = 5.6 × 8.4 × 10⁹ reams of paper

The number of reams of paper the company produced during the second year = 47.04 × 10⁹ reams of paper

= 4.704 × 10¹ × 10⁹ reams of paper

= 4.704 × 10¹⁰ reams of paper

Hence, the expression that represents the number of reams of paper the company produced during the second year is 4.704 × 10¹⁰. The correct option is D. 4.704 × 10¹⁰

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Answer: A

Step-by-step explanation: 107 is larger than 30

The endpoints of AB are (2, 5) and (-4, 7). So the coordinates of the midpoint are (-1, 6).

These are the specified parameters:

AB are (2, 5) and (-4, 7)

Here,

x₁ = 2 and y₁ = 5

x₂ = -4 and y₂ = 7

The coordinates of the midpoint

= ((x₁ + x₂)/2 , (y₁ + y₂)/2)

= ((2 + (-4))/2 , (5 + 7)/2)

= (-2/2 , 12/2)

= (-1, 6)

So the coordinates of the midpoint of segment AB are (-1, 6).

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The solution to the equation -2(x + 3) = -6 is x = 0.

To simplify the expression 5t + 7 + 8b, we can combine like terms.

There are two like terms in the expression: 5t and 8b.

Combining the like terms gives us:

5t + 8b + 7

Therefore, the simplified form of the expression 5t + 7 + 8b is 5t + 8b + 7.

Regarding the equation -2(x + 3) = -6:

To solve this equation, we can follow these steps:

Distribute the -2 to the terms inside the parentheses:

-2 * x + (-2) * 3 = -6

This simplifies to:

-2x - 6 = -6

Move the constant term to the right side by adding 6 to both sides of the equation:

-2x = 0

Divide both sides of the equation by -2 to isolate the variable x:

x = 0 / -2

Simplifying the right side of the equation gives us:

x = 0

The solution to the equation -2(x + 3) = -6 is x = 0.

The simplified expression 5t + 7 + 8b remains as 5t + 8b + 7, and the solution to the equation -2(x + 3) = -6 is x = 0.

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To find a particular solution of the non-homogeneous equation and the general solution of the equation, we can use the method of variation of parameters.

First, let's find the Wronskian of the homogeneous solutions y1(x) and y2(x):

W(y1, y2) = | y1 y2 |

| y1' y2' |

We have y1(x) = sin(x) / √x and y2(x) = cos(x) / √x. Differentiating these functions, we get:

y1'(x) = (cos(x) / √x - sin(x) / (2√x^3))

y2'(x) = (-sin(x) / √x - cos(x) / (2√x^3))

Substituting these values into the Wronskian:

W(y1, y2) = | sin(x) / √x cos(x) / √x |

| (cos(x) / √x - sin(x) / (2√x^3)) (-sin(x) / √x - cos(x) / (2√x^3)) |

Expanding the determinant:

W(y1, y2) = (sin(x) / √x) * (-sin(x) / √x - cos(x) / (2√x^3)) - (cos(x) / √x) * (cos(x) / √x - sin(x) / (2√x^3))

Simplifying:

W(y1, y2) = -1 / (2√x)

Now, we can find the particular solution using the variation of parameters formula:

y_p(x) = -y1(x) * ∫(y2(x) * g(x)) / W(y1, y2) dx + y2(x) * ∫(y1(x) * g(x)) / W(y1, y2) dx

Here, g(x) = 3x√xsin(x). Substituting the values:

y_p(x) = -((sin(x) / √x) * ∫((3x√xsin(x)) * (-1 / (2√x))) dx + (cos(x) / √x) * ∫((3x√xsin(x)) / (2√x)) dx

Simplifying the integrals:

y_p(x) = -(∫(-3sin^2(x)) dx) + (∫(3xcos(x)sin(x)) dx)

Integrating:

y_p(x) = 3/2 (xsin^2(x) - cos^2(x)) - 3/2 (xcos^2(x) + sin^2(x)) + C

Simplifying:

y_p(x) = 3x(sin^2(x) - cos^2(x)) + C

The general solution of the equation is given by the sum of the homogeneous solutions and the particular solution:

y(x) = C1 * (sin(x) / √x) + C2 * (cos(x) / √x) + 3x(sin^2(x) - cos^2(x)) + C

where C1, C2, and C are arbitrary constants.

Answer:

Let's assume that the total number of students in the school is "x". We can create a proportion to estimate how many students would choose the aquarium based on the given information:

Number of students who chose aquarium / Total number of students in the school = Percentage of students who chose aquarium / 100

We can plug in the values we know:

80 / x = p / 100

where "p" is the percentage of students who would choose the aquarium if the entire school were surveyed.

We can solve for "x" by cross-multiplying and simplifying:

8000 = px

x = 8000 / p

Now, we need to estimate the value of "p". We can do this by finding the average percentage of students who chose the aquarium, science center, planetarium, and farm:

(80 + 60 + 30 + 40) / x = (210 / x) = Average percentage of students who chose an attraction

This tells us that, on average, 210 out of every "x" students would choose one of the attractions. We can estimate that a similar percentage of the entire school would choose the aquarium:

p / 100 = 80 / 210

p = 38.1

So, we can estimate that approximately 38.1% of the students in the whole school would choose the aquarium. To find the estimated number of students who would choose the aquarium, we can plug in this value for "p" in our original proportion:

80 / x = 38.1 / 100

Cross-multiplying and solving for "x", we get:

x = 209.71

Rounding to the nearest whole number, we can estimate that approximately 210 students in the whole school would choose the aquarium.

Step-by-step explanation:

Answer:

The teacher surveyed a total of:

80 + 60 + 30 + 40 = 210 students.

If we assume that the sample of 210 students surveyed is representative of the entire population of 1000 students at Lake Middle School, we can use the relative frequency of students choosing the aquarium in the sample to estimate the number of students in the whole school who would choose the aquarium.

The relative frequency of students choosing the aquarium in the sample is:

80/210 = 0.38

This means that approximately 38% of the students in the sample chose the aquarium.

To estimate the number of students in the whole school who would choose the aquarium, we can multiply the relative frequency by the total number of students at the school:

0.38 x 1000 = 380

Therefore, the teacher can estimate that approximately 380 students out of 1000 at Lake Middle School would choose the aquarium for a field trip.

The probability that you select a Jack given that it is a Club P(Jack∣Club) is 1/13.

The probability that you select a Club given that it is a Jack is P(Club∣Jack) is 1/4.

The probability that you select a card that is NOT a Jack given that it is NOT a Club,P(NotJack∣NotClub) is 47/38

The probability that you select a card that is NOT a Club given that is it NOT a Jack is 38/47

The probability that you select a Jack given that it is a Club P(Jack|Club):

There are 4 Jacks in a deck (one for each suit), and since we are given that the selected card is a Club, we only need to consider the 13 cards in the Club suit.

So, the number of favorable outcomes is 1 (the Jack of Clubs), and the total number of possible outcomes is 13 (the number of cards in the Club suit)

P(Jack|Club) = 1 / 13

The probability that you select a Club given that it is a Jack

P(Club|Jack):

P(Club|Jack) = Number of favorable outcomes / Total number of possible outcomes

P(Club|Jack) = 1 / 4

The probability that you select a card that is not a Jack given that it is not a Club

P(NotJack|NotClub):

The number of cards that are not Jacks is 52 - 4 = 48 (since there are 4 Jacks in the deck), and the number of cards that are not Clubs is 52 - 13 = 39 (since there are 13 cards in the Club suit).

P(NotJack|NotClub) = Number of favorable outcomes / Total number of possible outcomes

P(NotJack|NotClub) = (48 - 1) / (39 - 1)

=47/38

P(NotClub|NotJack) = (39 - 1) / (48 - 1)

=38/47

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The additive inverse of [14/15*(-25/28)]+[2/3*6/7] is 1

You should be aware that the additive inverse of a number is the number that, when added to a, yields zero and the multiplicative inverse is the  reciprocal for a number

The given fractions are

[14/15*(-25/28)]+[2/3*6/7]

Let us solve it in parts

= 14/15*-15/28

=-392/420

The multiplicative inverse is

-392/420 *420/-392 =1

The second fraction is

[2/3*6/7]

The additive inverse is

12/21 -12/21 = 0

Therefore the additive inverse is 1+0 = 1

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The transformation from the graph of f(x) = x to the graph of g(x) = (1/9)·x -2, is a rotation and a translation. The correct option is therefore;

The transformation are a rotation and a translation

A translation transformation is a transformation in which there is a displacement of all points on the preimage figure in a specified direction.

The transformation from f(x) = x to f(x) = (1/9)·x - 2, includes a slope reduction by a factor of (1/9), or rotating the graph of f(x) = x in the clockwise direction, and a translation of 2 units downwards, such that the y-intercept changes from 0 in the parent function, f(x) = x to -2 in the specified function f(x) = (1/9)·x - 2, therefore, the translation includes a rotation clockwise and a translation downwards by two units

The correct option is the second option; The transformation are a rotation and a translation

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Answer:

An equation is basically a way to show a relationship of variables (x,y,a,b, etc) and numbers.

Step-by-step explanation:

Answer:

Shown by explanation.

Step-by-step explanation:

An equation shows a relationship between variables and other factors by defining the variables that are dependent and independent and how these dependent variables are related to the independent variables, this is usually as a result of a prescribed experiment where the relationship of this variables are investigated.

Also remember conditions that favour this experiment must be taken into consideration. And the experiment must always be performed under such conditions.

Answer:

The answer is C because DC = BA and DA = CB (given) and AC = CA (reflexive property).

The equation that represents the condition is m° + 66° + m° = 120°. Then the value of m is 27°.

When two lines intersect, then their opposite angles are equal. Then the equation is given as,

m° + 66° + m° = 120°

Simplify the equation for m, then the value of 'm' is calculated as,

m° + 66° + m° = 120°

2m° = 120° - 66°

2m° = 54°

m° = 27°

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Answer:

140-5x

Step-by-step explanation:

x would be the number of minutes

for eg, after 1 min, the temperature of the steak would be 140-5(1) = 135

not sure how to explain this, but its basically the start temperature - change

Answer:

4yd

144

Step-by-step explanation:

because 4yd is greater than 144

15 -differences between gymnosperms and angiosperms:

16-

17- Uniform acceleration is a change of equal velocity in equal interval of tine.

Non- Uniform acceleration is a change of unequal velocity in equal interval of time.

18- Three equation of motion:

the answer is 15 because it is in the middle

Answer:

Step-by-step explanation:

Median is the middle term of the data set.

Median = 15

13 , 13 , 13 , 15 , 15 , 16 , 16 , 17 , 17

Simplifying this equation, we get:

8 + 4k + 4k + 6 = 30

8k + 14 = 30

8k = 16

k = 2

Therefore, the value of k is 1.

In mathematics, a polynomial is an expression consisting of variables (usually represented by x), coefficients, and non-negative integer exponents, which are combined using the operations of addition, subtraction, and multiplication. For example,

\(3x^2 + 2x - 1\)

is a polynomial with three terms, or a "trinomial," where the variable x is raised to the powers of 2 and 1, and the coefficients are 3, 2, and -1.

The degree of a polynomial is the highest power of the variable in the expression. For example, the polynomial above has a degree of 2, since the highest power of x is 2.

Polynomials are used in many areas of mathematics, including algebra, calculus, and geometry, and are used to model many real-world phenomena.

We can use the remainder theorem, which states that if a polynomial f(x) is divided by (x - a), then the remainder is equal to f(a). In this case, we know that when the polynomial\(l x^3 + kx^2 + 2kx\) + 6 is divided by (x - 2), the remainder is 30. So, we can set up the following equation:

\(x^3 + kx^2 + 2kx + 6 = (x - 2)q(x) + 30\)

where q(x) is the quotient when. \(x^3 + kx^2 + 2kx + 6\) is divided by (x - 2). We don't need to know what q(x) is, since we're only interested in finding k.

Now, let's substitute x = 2 into the equation above:

\(2^3 + k(2^2) + 2k(2) + 6 = (2 - 2)q(2) + 30\)

Simplifying the left-hand side, we get:

\(8 + 4k + 4k + 6 = 30\)

\(16k = 16\)

\(k = 1\)

OR

8 + 4k + 4k + 6 = 30

8k + 14 = 30

8k = 16

k = 2

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The correct options are;

a. The variables x and y also have a correlation close to 1 .

b. A scatterplot of the variables log x and y shows a strong nonlinear pattern .

The correlation is a measurement of a dependence between 2 variables. If the logarithm of the correlation function shows a linear tendency, it because the correlation between x and y shows a exponential tendency.

This mean that x and y are non linear correlated, but them are correlated.

For this type of data is used a non linear correlation technique know it as logarithm correlation.

Option c is incorrect because random patterns have a correlation value close to 0, which is not the case.

So ,

The correct options are;

a. The variables x and y also have a correlation close to 1

b. A scatterplot of the variables log x andy shows a strong nonlinear pattern

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Answer:

Step-by-step explanation:

Using the remainder theorem we get:

\(f(-2)=-5\),  \(f(1)=4\), and \(f(-1)=0\)

So we get

\(f(-2)=(-8)(p-1)+4p-2q+r=-5\)

                 \(-8p+8+4p-2q+r=-5\)

                              \(-4p-2q+r=-13\)  \((a)\)

\(f(1)=(p-1)+p+q+r=4\)

                       \(2p+q+r=5\)               \((b)\)

\(f(-1)=-(p-1)+p-q+r=0\)

                                 \(-q+r=-1\)    \((c)\)

We need to solve (a), (b) and (c) simultaneously to find p,q, and r.

from \((c)\)  \(r=q-1\). Sub this into (a) and (b):

\(-4p-2q+(q-1)=-13 \rightarrow -4p-q=-12\)    \((d)\)

      \(2p+q+(q-1)=5 \rightarrow q=3-p\)              \((e)\)

Sub (e) into (d) we get

\(-4p-(3-p)=-12 \rightarrow p=3\)

Sub \(p=3\) into \((e) \rightarrow q=0\)

Sub  \(p=3,q=0\) into \((c) \rightarrow r=-1\)

SOLUTION: \(p=3,q=0,r=-1\)    

So \(f(x)=2x^3+3x^2-1\)

by dividing (x+1) into f(x) we get  (I am not showing working for this division)

\(f(x)=(x+1)(2x^2+x-1)\)

\(\rightarrow f(x)=(x+1)(2x-1)(x+1)\)