Reasoning : The equation below describes a proportional relationship between x and y. What is the
constant of proportionality? Use pencil and paper. Explain why your answer is called the "constant of
proportionality."
y = 7.87x

Answer:

2  3

Step-by-step explanation:

Answer:

$10.95

Step-by-step explanation:

85% = 0.85

We take

73 - (73 x 0.85) = $10.95

So, the price of the item after the reduction is $10.95

Answer:

We have the system of equations:

y = -2*x

y = 2*x + 4.

To solve it by graphing, you need to graph both lines and see in which point the lines intersect each other.

You can see it in the image below. (blue is y = 2*x + 4, and green is y = -2*x)

We also can calculate the solution with math, let's do that:

y = -2*x

y = 2*x + 4.

We can replace the first equation in the second one, to get:

-2*x = 2*x + 4

Now let's solve this for x

-2*x -2*x = 4

-4*x = 4

x = 4/-4 = -1

Evaluating this in one of the equations we get:

y = -2*-1 = 2

Then the solution is the point (-1, 2), exactly what we can see in the graph.

Answer:

4+1=5(0+1)

Step-by-step explanation:

The formula is y2-y1=slope(x2-x1)

Find the slope by using the formula y2-y1/x2-y1.

The form which should be used when you know the slope of a line and one of the points on the line is: d. point-slope form.

The point-slope form can be defined as an equation which is used when the slope of a line and one of the points on this line is known.

Mathematically, the point-slope form of a line is given by:

y - y₁ = m(x - x₁)

Where:

In conclusion, you should use the point-slope form when you know the slope of a line and one of the points on the line is given.

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Answer:

b

Step-by-step explanation:

Answer:

j

Step-by-step explanation:

No, the conditions for inference are not met. The Large Counts Condition is not satisfied because the number of successes (6) is less than 10.

To determine if the conditions for inference are met in this scenario, we need to consider a few key conditions: the 10% condition, the randomness condition, and the Large Counts Condition.

The 10% condition: This condition states that the sample size should be no more than 10% of the population size. In this case, the sample size is 10 (the number of times the penny was spun), and we don't have information about the population size. However, since the proportion of times the penny lands tails up is not likely to be affected by the sample size of 10, we can assume that the 10% condition is met.

The randomness condition: This condition requires that the sample is randomly selected from the population. If the student followed the instructions and spun the penny 10 times, recording the number of times it landed tails side up, and there was no bias in the way the spins were performed, we can assume that the randomness condition is met.

The Large Counts Condition: This condition is related to the number of successes and failures in the sample. It states that both the number of successes and failures should be at least 10. In this case, the student recorded 6 tails side up out of 10 spins. Since 6 is less than 10, the Large Counts Condition is not met.

Based on these conditions, we can conclude that the conditions for inference are not fully met. The 10% condition and the randomness condition are likely met, but the Large Counts Condition is not satisfied. This means that we should be cautious when making inferences about the true proportion of tails up based on this sample. It may not be appropriate to construct a confidence interval or perform statistical inference in this case due to the violation of the Large Counts Condition.

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Answer:

Therefore, the Panthers had a better overall record for the season, with a total of 212 points earned compared to the Cowboys' total of 173 points.

Step-by-step explanation:

To compare the measures of center, we can calculate the mean and median points earned by each team:

Panthers: Mean = 212/15 = 14.13 points, Median = 14 points

Cowboys: Mean = 173/15 = 11.53 points, Median = 10 points

Based on these calculations, we can see that the Panthers have a larger mean value of about 14.13 points compared to the Cowboys' mean value of about 11.53 points. However, the median value for both teams is less useful for comparison since they are only one point apart. Therefore, we can conclude that the Panthers had the better overall record for the season based on both the total points earned and their larger mean value.

So, the answer is Panthers; they have a larger mean value of about 14.8 points (Option C is incorrect as the mean value of Panthers is approximately 14.13 and not 14.8).

\((\stackrel{x_1}{-5}~,~\stackrel{y_1}{13})\qquad (\stackrel{x_2}{-2}~,~\stackrel{y_2}{r}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{\textit{\large rise}} {\stackrel{y_2}{r}-\stackrel{y1}{13}}}{\underset{\textit{\large run}} {\underset{x_2}{-2}-\underset{x_1}{(-5)}}} ~~ = ~~\stackrel{\stackrel{\textit{\small slope}}{\downarrow }}{ -3 }\implies \cfrac{r-13}{-2+5}=-3\implies \cfrac{r-13}{3}=-3 \\\\\\ r-13=-9\implies r=4\)

A) There are 100 * 99 * 98 * 97 ways to award the prizes, since there are 100 choices for the first prize, 99 choices for the second prize, 98 choices for the third prize, and 97 choices for the fourth prize..

What is the combinatorics?

Combinatorics is a branch of mathematics that deals with counting and arranging objects, such as numbers, sets, and permutations.

B) If the person holding ticket 47 wins the grand prize, there are 99 * 98 * 97 ways to award the remaining prizes, since there are 99 choices for the second prize, 98 choices for the third prize, and 97 choices for the fourth prize.

C) If the person holding ticket 47 wins one of the prizes, there are 100 * 99 * 98 * 97 ways to award the prizes.

D) If the person holding ticket 47 does not win a prize, there are 99 * 98 * 97 * 96 ways to award the prizes, since there are 99 choices for the first prize, 98 choices for the second prize, 97 choices for the third prize, and 96 choices for the fourth prize.

E) If the people holding tickets 19 and 47 both win prizes, there are 98 * 97 * 96 * 95 ways to award the remaining prizes, since there are 98 choices for the third prize, 97 choices for the fourth prize, 96 choices for the fifth prize, and 95 choices for the sixth prize.

F) If the people holding tickets 19, 47, 73, and 97 all win prizes, there are 96 * 95 * 94 * 93 ways to award the remaining prizes, since there are 96 choices for the fifth prize, 95 choices for the sixth prize, 94 choices for the seventh prize, and 93 choices for the eighth prize.

G) If none of the people holding tickets 19, 47, 73, and 97 wins a prize, there are 96 * 97 * 98 * 99 ways to award the prizes, since there are 96 choices for the first prize, 97 choices for the second prize, 98 choices for the third prize, and 99 choices for the fourth prize.

H) If the grand prize winner is a person holding ticket 18, 47, 73, or 97, there are 3 * 99 * 98 * 97 ways to award the remaining prizes, since there are 3 choices for the grand prize winner (18, 47, or 73), and 99 choices for the second prize, 98 choices for the third prize, and 97 choices for the fourth prize.

I) If the people holding tickets 19 and 47 win prizes, but the people holding tickets 73 and 97 do not win prizes, there are 98 * 97 * 96 * 95 ways to award the prizes, since there are 98 choices for the first prize, 97 choices for the second prize, 96 choices for the third prize, and 95 choices for the fourth prize.

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The correct answer is A: 600 <= money <= 2822.4.

This represents the range of possible values that Pankaj's accumulated money could fall into, given the specified conditions of the 3% interest rate compounded weekly for a maximum of 2 years. The lower bound, 600, represents the initial deposit amount, while the upper bound, 2822.4, represents the maximum amount of money Pankaj could earn after 2 years, assuming that interest is compounded every week.

Answer:

Check the attached image

Answer:

so

2×4.57 = (3V/2pi)^1/3

Volume is approximately = 1600

The equations are written in ascending order of steepness as below

C) y = -x

D) y = (1/2)x

B) y = 2x

F) y = 1.5x

A) y = 4x

E) y = 5x

To order the lines in ascending order of steepness, we want to examine the slopes of each line.

The slope of a line represents how steeply it rises or falls as we circulate alongside the x-axis.

The slopes of the given functions are:

A) 4

B) 2

C) -1

D) half

E) 5

F) 1.5

Therefore, the lines in ascending order of steepness are:

C) y = -x

D) y = (1/2)x

B) y = 2x

F) y = 1.5x

A) y = 4x

E) y = 5x

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Answer:

that is the answer

Step-by-step explanation:

Answer:

Step-by-step explanation:

whoop

Answer:

MEEEE

Step-by-step explanation:

AHHHH

Step-by-step explanation:

It is important to know that the diagonals of a rhombus are PERPINDICUALR bisectors of each other .   Opposite angles are equal and adjacen angles sum to 180 degrees .

Then remember alternate angles are equal  and there are 180 degrees inside of a triangle .....then you should be able to solve these...here is the first one

Answer:

$17

Step-by-step explanation:

20% of 85 is 17

Answer:

about 403.1 miles

Step-by-step explanation:

262 miles is 65% of the distance to the grandmother's house. Let d be that distance.

\(.65d = 262\)

\(d = 403.1\)

The distance from Ken's house to his grandmother's house is about 403.1 miles.

Answer:

The expression for this would be 4÷5

Step-by-step explanation:

Since we already know that the fraction bat is equal to division, we would know that 4/5 would be equivalent to 4÷5.

The calculated measure of t from the given equation is 15 degrees

From the question, we have the following parameters that can be used in our computation:

10

to

25°

When expressed properly, we have

10° + t° = 25°

Evaluate the like terms

So, we have

t° = 15°

Hence, the value of t° is 25°

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The rectangular crate will be able to carry a maximum of 27 boxes

The crate carries a shape of a cuboid which can be said to be a rectangle in three-dimensional side. To solve this problem, we have to find the volume of the crate and then the volume of the box and divide the volume of the crate by the volume of box.

The volume of a cuboid = L * W * H

This can be calculated as V = 24 * 18 * 15 = 6480cm³

The volume of the box = 8 * 6 * 5 = 240cm³

Number of boxes that can fit in the cuboid = 6480 / 240

Number of boxes = 27 boxes

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Answer:

$37623.04

Step-by-step explanation:

The formula we'll use for this is the simple interest formula, or:

\(I=p*r*t\)

Where:

P is the principal amount, $1088.00.

r is the interest rate, 839.5% per year, or in decimal form, 839.5/100=8.395.

t is the time involved, 4....year(s) time periods.

So, t is 4....year time periods.

To find the simple interest, we multiply 1088 × 8.395 × 4 to get that:

The interest is: $36535.04

Usually now, the interest is added onto the principal to figure some new amount after 4 year(s),

or 1088.00 + 36535.04 = 37623.04.

Answer:

41 meters

Step-by-step explanation:

\(\frac{31}{64}\) = \(\frac{19.8}{x}\)

31x = (19.8)(64)

31x = 1267.2  Divide both sides by 31 and round

x = 41

A salary slip for the month of March 2023 with information given below.

Salary Slip - March 2023

Employee Details:

Name: [Employee Name]

Employee ID: [Employee ID]

Designation: [Employee Designation]

Earnings:

Basic Salary: [Basic Salary]

House Rent Allowance (HRA): [HRA]

Dearness Allowance (DA): [DA]

Incentive: [Incentive]

Total Earnings: [Total Earnings]

Deductions:

Provident Fund (PF): [PF]

Insurance: [Insurance]

Loss of Pay (LOP): [LOP]

Total Deductions: [Total Deductions]

Net Pay: [Net Pay]

Breakdown:

Basic Salary: 50% of CTC (18L) = [Basic Salary]

HRA: 20% of Basic Salary = [HRA]

DA: 12% of Basic Salary = [DA]

Incentive: 75% of target completion = [Incentive]

Total Earnings = Basic Salary + HRA + DA + Incentive = [Total Earnings]

PF: 12% of Basic Salary = [PF]

Insurance: Rs. 2500 = [Insurance]

LOP: [LOP]

Total Deductions = PF + Insurance + LOP = [Total Deductions]

Net Pay = Total Earnings - Total Deductions = [Net Pay]

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Answer:

Step-by-step explanation:

Answer:

f (x)>6 this is answer

Step-by-step explanation:

because f (x)= +6

Answer:

its C on edg

Step-by-step explanation:

follow my ifunny "dankmemehistory"

Answer:

6.4

Step-by-step explanation:

First add 10 to 22 to get 32

Then divide 32 by 5 to get x

Using the sum and difference formula and trigonometric identities the value of tanθ and cosθ are cos(11π/12) = (-√6 + √2) / 4 and tan(11π/12) = 0 respectively.

The identity tan(α + β) = (tanα + tanβ) / (1 - tanα * tanβ) may be used to calculate tan using the sum method.

Here, we have θ = 11π/12, so we need to express it as the sum of two angles.

In this problem, we are given θ = 11π/12 and we can use the sum of two angles.

11π/12 = π/6 + 5π/6

putting the value of α = π/6 and β = 5π/6.

The sum formula of the tangent becomes;

tan(11π/12) = tan(α + β) = (tanα + tanβ) / (1 - tanα * tanβ)

Let's put in the values of α and β:

tan(11π/12) = (tan(π/6) + tan(5π/6)) / (1 - tan(π/6) * tan(5π/6))

The tangent of π/6 and 5π/6 will have values as;

tan(π/6) = √3/3

tan(5π/6) = -√3/3

Let's put in these values into the sum formula;

tan(11π/12) = (√3/3 + (-√3/3)) / (1 - (√3/3 * (-√3/3)))

tan(11π/12) = 0 / (1 - (-3/9))

= 0 / (1 + 1/3)

= 0 / (4/3)

= 0

Therefore, tan(11π/12) = 0.

Part B;

Using difference formula, the value of cosθ can be expressed using the trigonometric identity

cos(α - β) = cosα * cosβ + sinα * sinβ

Since we are given θ = 11π/12;

Let's express this as the difference of two angles

11π/12 = 3π/4 - π/6

Putting the value α = 3π/4 and β = π/6.

Using the difference formula for cosine;

cos(11π/12) = cos(α - β) = cosα * cosβ + sinα * sinβ

Let's plug in the values of α and β

cos(11π/12) = cos(3π/4 - π/6) = cos(3π/4) * cos(π/6) + sin(3π/4) * sin(π/6)

The known values of cosine and sine for 3π/4 and π/6 are;

cos(3π/4) = -√2/2

cos(π/6) = √3/2

sin(3π/4) = √2/2

sin(π/6) = 1/2

Plugging these values into the difference formula;

cos(11π/12) = (-√2/2 * √3/2) + (√2/2 * 1/2)

cos(11π/12) = -√6/4 + √2/4

Combining like terms:

cos(11π/12) = (-√6 + √2) / 4

Therefore, cos(11π/12) = (-√6 + √2) / 4.

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