Real estate suggests that 90% of homes for sale have garages (let it be an event A), 15% have swimming pools (let it be an event B), and 10% have both features: a garage and a pool. a) What is the probability that a home selected at random has at least one feature (either a garage, or a pool, or both features)?​

Answer:

Step-by-step explanation:

Y=5x

Answer:

2nd one

Step-by-step explanation:

Answer:

F

Step-by-step explanation:

is the answer because when u solve u get that answer u get your ratio and then multiply and divide that's how u get your answer

The ratio of boys to  girls on the bus is 1/2

Given that the ratio of boys to girls on a bus is 4 to 5, this can be written as  4:5

If 1 girl and  2 boys get off the bus, the number of boys to girls will be (4-2):(5-1)

Hence the ratio of boys to  girls on the bus is 1/2

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Answer:

4 more monkeys

Step-by-step explanation:

9:12 can be simplified to

3:4

since he is adding one more group of gorillas he needs to add one more group of monkeys as well to keep the ratio that same

now its

12:16

Answer:

He will need to buy 3

Step-by-step explanation:

Whatever happens to the gorillas happens to the monkey's.

If im wrong can someone please explain.

The required answers for part (a) and (b) are  ASA, SAS and SSS and the value of x is 262.80 units.

The sine law is used to calculate the sides and angles of a triangle. It states that the ratio of the sides and the angles opposite to it are equal.

It can be written a/SinA = b/SinB = c/SinC.

The given problem can be solved as,

(a) In order to apply law of sines at least one angle should be known.

In ASA and SAS this criteria is justified.

(b) When none of the angles are given, there can be more than one solution.

Which implies the case of SSS.

(c) In the given triangle angle ∠C can be found as,

⇒∠C = 180 - (98.4 + 24.6) = 57°.

Now apply the law of sines to obtain x as follows,

x/sin(57°) = a/sin(98.4°)

The value of a is given as 310.

⇒ x/sin(57°) = 310/sin(98.4°)

⇒ x = 262.80.

Hence, the value of x is found as 262.80 units.

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The missing diagram of the triangle is attached here.

Answer:

X > -11/10

Step-by-step explanation:

that log4x=2log16x. (ii)Show that log x=3logb³ x. (iii) Show that log₂x=(1+log₂3)logix

The percentage population increase from 2001 to 2011 is 50%.

To calculate the percentage population increase from 2001 to 2011, you need the population figures for both years. Let's assume the population in 2001 was 100,000 and in 2011 it was 150,000.

The formula to calculate the percentage increase is:

Percentage Increase = ((New Value - Old Value) / Old Value) * 100

Plugging in the values:

Percentage Increase = ((150,000 - 100,000) / 100,000) * 100 = (50,000 / 100,000) * 100 = 0.5 * 100 = 50%

Therefore, the percentage population increase from 2001 to 2011 is 50%.

Please note that the actual population figures for the respective years need to be used in the calculation to obtain an accurate result. The example above is for illustrative purposes.

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The graph of h(x) = (x-1)^2 - 9 is a U-shaped parabola that opens upwards, with the vertex at (1, -9), and it extends indefinitely in both directions.

The function h(x) = (x-1)^2 - 9 represents a quadratic equation. Let's analyze the different components of the equation to understand the behavior of the graph.

The term (x-1)^2 represents a quadratic term. It indicates that the graph will have a parabolic shape. The coefficient in front of the quadratic term (1) implies that the parabola opens upwards.

The constant term -9 shifts the graph downward by 9 units. This means the vertex of the parabola will be at the point (1, -9).

Based on this information, we can draw the following conclusions:

The graph will be a U-shaped curve with the vertex at (1, -9).

The vertex represents the minimum point of the parabola since it opens upward.

The parabola will be symmetric with respect to the vertical line x = 1 since the coefficient of the quadratic term is positive.

The graph will extend indefinitely in both directions.

To accurately plot the graph, you can choose several x-values, substitute them into the equation to find the corresponding y-values, and then plot the points on the graph. Alternatively, you can use graphing software or calculators that can plot the graph of the equation for you.

Remember to label the axes and indicate the vertex at (1, -9) to provide a complete representation of the graph of h(x) = (x-1)^2 - 9.

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Answer: D

Step-by-step explanation:

24*4=96 Which is D

Answer:

A)x=-8 B)x=3

Step-by-step explanation:

A)-3x+10=34   -3x+10-10=34-10   -3x/-3=24/-3 x=-8

B) 13x-4=11x+10-8   13x-4+4=11x+10-8+4  13x-11x=11x-11x+6  2x/2=6/2   x=3

Answer:

start at zero make a small inclined line to 10 then keep the line straight to 60

A polynomial function f(x) of degree 3 with given zeros, 2, -3 , 5 and condition f(3)=6 is given by f(x) = -1/2 (x-2)(x+3)(x-5).

Degree of the polynomial function is equal to 3.

Zero's of the polynomial function is equal to 2, -3 , 5 .

And f(3) = 6

If 2, -3, and 5 are zeros of f(x), then we can write function as,

f(x) = a(x-2)(x+3)(x-5)

where a is some constant.

To determine the value of a, we can use the fact that f(3) = 6.

Substituting x = 3 into the equation above, we get,

f(3) = a(3-2)(3+3)(3-5)

     = -12a

Here we have,

f(3) = 6, so we can set these two expressions equal to each other and solve for a,

⇒ -12a = 6

⇒ a = -1/2

Now we can substitute this value of a back into the equation for f(x) that we found earlier,

⇒ f(x) = -1/2 (x-2)(x+3)(x-5)

Therefore, a polynomial function f(x) of degree 3 with zeros 2, -3, 5, and f(3) = 6 is equal to f(x) = -1/2 (x-2)(x+3)(x-5).

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Answer:

the ans is 252................

Answer:

Refer to step-by-step

Step-by-step explanation:

Prove the following, \(\lim_{x \to \ 2} 2^{x}=4\), \(\lim_{z \to \ -1} 3^{x}=\frac{1}{3}\), and \(\lim_{x \to \ 1} e^{x-1} = 1\).

For part f:

Plug in the value of the limit, 2,

\((2)^{2} =4\)

Thus we proved the limit.

For part g:

Plug in the value of the limit, -1,

\(3^{(-1)}\)=>\(3^{-1}\)=>\(\frac{1}{3^{1} }=\frac{1}{3}\)

Thus we proved the limit.

For part h:

Plug in the value of the limit, 1,

\(e^{(1)-1}\)=>\(e^{1-1}\)=>\(e^{0}=1\)

Thus we proved the limit.

To answer this question we need to remember that:

and that a permutation is defined as:

Then, in this case we have:

Therefore, we have that:

The Expression x^2 - 6x + 9 when x = 2 + i   is -2i

To evaluate the expression x^2 - 6x + 9 when x = 2 + i, we substitute the value of x into the expression:

(2 + i)^2 - 6(2 + i) + 9

Simplifying the first term, we get:

(2 + i)^2 = 2^2 + 2(2)(i) + i^2 = 4 + 4i + i^2

Since i^2 = -1, we can substitute that in and simplify further:

(2 + i)^2 = 4 + 4i - 1 = 3 + 4i

Now we substitute this into the original expression:

(2 + i)^2 - 6(2 + i) + 9 = (3 + 4i) - 6(2 + i) + 9

Simplifying further, we get:

= 3 + 4i - 12 - 6i + 9

= 0 - 2i

= -2i

Therefore, the value of x^2 - 6x + 9 when x = 2 + i is -2i.

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Answer:

C. 1/4

Step-by-step explanation:

Line pass A(-2,-1) and B(2,0)

slope = Δy/Δx = (0 - (-1)) / (2 - (-2)) = 1/4

Answer:

the answer is C

Step-by-step explanation:

slope formula:

\( \frac{y2 - y1}{x2 - x1} \)

(1) take two coordinates from the graph

i/ (2,0)

x1 = 2

y1 = 0

ii/ (6,1)

x2 = 6

y2 = 1

(2) substitute the values into the formula

\( \frac{1 - 0}{6 - 2} \)

\( \frac{1}{4} \)

Answer:

Probability     No. of pies          Cost       Revenue      Profit

0.5                        100               500           300            -200

0.25                      150               500           450            -50

0.25                      200              500            600           100

Step-by-step explanation:

We are given that  The owner believes that on 50% of the days she sells 100 pies.

So, Probability of selling 100 pies = 0.5

On another 25% of the days she sells 150 pies

So, Probability of selling 150 pies = 0.25

She sells 200 pies on the remaining 25% of the days

So, Probability of selling 200 pies = 0.25

We are given that the owner bakes 200 pies each day at a cost of $2.50 each.

So, Cost per day =\(200 \times 2.50 =500\)

Probability     No. of pies          Cost

0.5                        100               500

0.25                      150               500

0.25                      200              500

Now we are given that  she sells the pies for $3 each

So, SP of 100 pies =\(3 \times 100 = 300\)

SP of 150 pies = \(150 \times 3 = 450\)

SP of 200 pies = \(200 \times 3 = 600\)

Probability     No. of pies          Cost       Revenue      Profit

0.5                        100               500           300            -200

0.25                      150               500           450            -50

0.25                      200              500            600           100

The probability that the song will be played on exactly 2 days out of 5 days is approximately 0.164.

To find the probability that a particular song is played exactly 2 days out of 5 days at radio station WMZH, we can use the binomial probability formula.

The binomial probability formula is given by P(x) = C(n, x) * p^x * (1-p)^(n-x), where P(x) is the probability of x successful outcomes, n is the number of trials, p is the probability of a successful outcome on a single trial, and C(n, x) represents the binomial coefficient, which is the number of ways to choose x items from a set of n items.

In this case, we want to find the probability of the song being played exactly 2 days out of 5 days, so x = 2, n = 5, and p = 3/8.

Using the formula, we have:

P(2) = \(C(5, 2) * (3/8)^2 * (1 - 3/8)^(^5^-^2^)\)

C(5, 2) = 5! / (2! * (5-2)!) = 10

P(2) = 10 * (3/8)^2 * (5/8)^3

P(2) ≈ 0.164 (rounded to three decimal places)

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453.46

Step-by-step explanation:

398.50/7.25=54.96

398.50+54.96=453.46

probability of an event can never be negative

ok hola bro graicas por los punto                            qui    :

Answer:

12.5

Step-by-step explanation:

(7.5+2.5)x2.5/2

Answer:

12.5 units ^2

Step-by-step explanation:

This figure is a trapezoid

The area of a trapezoid is given by

A = 1/2 (b1+b2) *h

where b1 and b2 are the lengths of the bases and h is the height

A = 1/2 ( 2.5+ 7.5) *2.5

   = 1/2 ( 10) * 2.5

   =12.5 units ^2

Step-by-step explanation:

The ONE  solution to this system of two lines is the point where the two lines cross   at   (1,4)

Answer:

3

Step-by-step explanation

Q and R are already given to you so you just have to look

The correct order which shows the standard deviations of the data sets A,B and C in order from greatest to least is C, B, A.

Suppose that

\(x_i; \: \: i = 1,2, ... ,n\) are n data values for the given data set.

Then we have: Variance as,

\(\sigma^2 = \dfrac{\sum_{\forall x_i} (x_i - \overline{x})^2}{n}\)

As standard deviation is the positive root of variance, thus,

\(\sigma = \sqrt {\dfrac{\sum_{\forall x_i} (x_i - \overline{x})^2}{n}}\)

If its sample, we divide by n-1 instead of n

Use data sets A, B, and C to answer the question that follows.

The mean of the set A is,

\(\overline{x}_A=\dfrac{25+24+ 25+ 22+ 21+23+ 1}{7}=20.143\)

Similarly, the mean of set B and C is,

\(\overline{x}_B=\dfrac{20+ 23+ 25+ 21+ 24+ 22+ 60}{7}=27.857\\\overline{x}_C=\dfrac{20+21+ 20+ 22+ 20+ 24+ 99}{7}=32.286\)

The standard deviation of the set A is,

\(\sigma_A = \sqrt {\dfrac{(25-20.143)^2+(24-20.143)^2......+(1-20.143)^2}{7}}\\\sigma_A = 7.936\)

Similarly, the standard deviation of set B and C is,

\(\sigma_B = \sqrt {\dfrac{(20-27.857)^2+(23-27.857)^2......+(60-27.857)^2}{7}}= 13.217\\\sigma_C = \sqrt {\dfrac{(20-32.286)^2+(21-32.286)^2......+(99-32.286)^2}{7}}= 27.27\)

The value of standard deviation of set C is the highest while set A is lowest.

Thus, the correct order which shows the standard deviations of the data sets A,B and C in order from greatest to least is C, B, A.

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Answer:

y = ¼x

Step-by-step explanation:

The slope-intercept form is y = mx + b where m = slope, and b = y-intercept.

In order to transform the given equation into its slope-intercept form, isolate the y by dividing both sides by 4:

4y = x

\(\frac{4y}{4} = \frac{1*x}{4}\)

y = ¼x + 0, or simply, y = ¼x.

\( \rm \int \frac{(x - {x}^3 {)}^{ \frac{1}{3} } }{ {x}^{4} } dx \\ \)

can be written as:-

\( \rm\int{\frac{- \frac{x^{3}}{3} + \frac{x}{3}}{x^{4}} d x} \\ \)

\( \rm = {\int{\frac{1 - x^{2}}{3 x^{3}} d x}} \\ \)

\( \rm = {\left(\frac{\displaystyle \rm\int{\frac{1 - x^{2}}{x^{3}} d x}}{3}\right)} \\ \)

\( = \rm \frac{{\displaystyle \rm\int{\left(- \frac{1}{x} + \frac{1}{x^{3}}\right)d x}}}{3} \\ \)

\( = \rm \frac{{\left( \displaystyle \rm\int{\frac{1}{x^{3}} d x} - \int{\frac{1}{x} d x}\right)}}{3} \\ \)

\( \rm \red{- \frac{\int{\frac{1}{x} d x}}{3} + \frac{\color{red}{\int{\frac{1}{x^{3}} d x}}}{3}=- \frac{\int{\frac{1}{x} d x}}{3} + \frac{\color{red}{\int{x^{-3} d x}}}{3}=- \frac{\int{\frac{1}{x} d x}}{3} + \frac{\color{red}{\frac{x^{-3 + 1}}{-3 + 1}}}{3}=- \frac{\int{\frac{1}{x} d x}}{3} + \frac{\color{red}{\left(- \frac{x^{-2}}{2}\right)}}{3}=- \frac{\int{\frac{1}{x} d x}}{3} + \frac{\color{red}{\left(- \frac{1}{2 x^{2}}\right)}}{3}} \\ \)

\( \rm\int{\frac{- \frac{x^{3}}{3} + \frac{x}{3}}{x^{4}} d x} = - \frac{\ln{\left(\left|{x}\right| \right)}}{3} - \frac{1}{6 x^{2}}+C \\ \)

Simplify the integrand:

\(\dfrac{\left(x-x^3\right)^{\frac13}}{x^4} = \dfrac{\left(x^3 \left(\frac1{x^2}-1\right)\right)^{\frac13}}{x^4}= \dfrac{x \left(\frac1{x^2} - 1\right)^{\frac13}}{x^4} = \dfrac{\left(\frac1{x^2}-1\right)^{\frac13}}{x^3}\)

Substitute y = 1/x² - 1 and dy = -2/x³ dx :

\(\displaystyle \int \frac{\left(\frac1{x^2}-1\right)^{\frac13}}{x^3} \, dx = -\frac12 \int y^{\frac13} \, dy \\\\ = -\frac12 \times \frac34 y^{\frac43} + C \\\\ = \boxed{-\frac38 \left(\frac1{x^2}-1\right)^{\frac43} + C}\)