The magnitude of the force exerted by the string on the fishing line weight is approximately 4.06 N.
To determine the magnitude of the force exerted by the string on the fishing line weight, we can use the centripetal force equation.
Calculate the angular velocity (ω) using the given time (T) for one revolution:
ω = 2π / T
ω = 2π / 1.3 s
ω ≈ 4.83 rad/s
Use the centripetal force equation to calculate the force (F) exerted by the string:
F = m * ω^2 * r
where m is the mass of the fishing line weight, ω is the angular velocity, and r is the length of the fishing line.
F = (0.028 kg) * (4.83 rad/s)^2 * (0.75 m)
F ≈ 0.631 N
Note: The above calculation gives the centripetal force exerted by the string on the weight.
However, we need to consider the tension in the string, which provides the force required to keep the weight in circular motion. The tension in the string is equal to the centripetal force.
Therefore, the magnitude of the force exerted by the string on the fishing line weight is approximately 0.631 N.
Note: The given mass of the fishing line weight and the length of the fishing line are used to calculate the centripetal force. The centripetal force is equal to the tension in the string, which is the force exerted by the string on the weight.
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The melting point of a pure compound is known to be 110-111°. Describe the melting behavior expected if this compound is contaminated with 5% of an impurity?
An impurity consisting of 5% total mass will lower the melting point from that of the pure compound, and it will increase the melting point range.A value of 103-107° would be consistent with this amount of impurity with the pure melting point of 110-111°; values of 100-105°, 97-100°, 102-110° are also good estimates.
Impurities will lower the melting point of a pure compound and increase the melting point range.
When an impurity is mixed with a pure substance, it lowers the melting point of the compound and expands its melting range. If a substance has a pure melting point of 110-111°C, adding a 5% impurity would cause the melting point to drop to 103-107°C, while the melting point range would broaden. It's difficult to predict the precise melting point range, but estimates such as 100-105°C, 97-100°C, and 102-110°C are all possible.
Impurities that are added to a substance have a noticeable effect on the melting point of the pure substance, which is used to evaluate the purity of the sample. The melting point of a compound is an important characteristic that chemists use to determine its identity and purity.
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What is the proper unit for gravitational potential energy?Question 16 options:gravitonsjoulesnewtonsmeters
Answer:
Joules
Explanation:
The unit for Energy is Joules, which is equal to kg m²/s².
The gravitational potential energy is calculated as:
\(Ep=\text{mgh}\)Where m is mass (kg), g is gravity (m/s²) and h is the height (m). So, the unit of the potential energy is:
\(kg\cdot\frac{m}{s^2}\cdot m=kg\cdot\frac{m^2}{s^2}=\text{Joules}\)Therefore, the answer is joules.
A student is sitting in a chair with nearly frictionless rollers. Her homework bag is in an
identical chair right beside her. The chair and the bag havera combined mass of 20 kg. The
student and her chair have a combined mass of 65 kg. If she pushes her homework bag away
from her at 0.060 m/s relative to the floor, what will be the student's velocity immediately
after the interaction ? (Show your work)
Answer:
-0.018 m/s
Explanation:
Momentum is conserved.
m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂
Both masses start at rest, so u₁ = u₂ = 0 m/s.
0 = m₁v₁ + m₂v₂
0 = (20 kg) (0.060 m/s) + (65 kg) v₂
v₂ ≈ -0.018 m/s
The final velocity of the student can be determined using momentum conservation equation. The velocity after interaction will be 0.018 m/s.
What is momentum?Momentum of a body is the product of its velocity and mass. Momentum of a moving body conserved in collision. Hence, the sum of initial momentum of the two colliding bodies is equal to the sum of their final momentum.
Both the student and bag were at rest initially and the initial momentum is zero.
The mass of the student = 20 kg
mass of bag + chair = 65 kg
velocity = 0.06 m/s
then, m1v1 + m2v2 = 0
(65 kg) v1 + (0.06 m/s × 20 kg ) = 0
v1 = 0.018 m/s
The momentum exerted on the bag is returned to the student with an equal and opposite magnitude. The velocity of the girl after interaction will be 0.018 m/s.
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Atom A has an atomic number of 19 and a mass number of 40. Atom B has an atomic number of 20 and a mass number of 40. Which of these is an accurate statement?
A) Atom A has more protons than Atom B.
B) Atom A has one less proton and one more neutron than Atom B.
C) Atom A has an extra nucleon compared to Atom B.
D) Atom A has one more proton and one more electron than Atom B
Answer:
B
Explanation:
a body weighs 400 Newton's in water. if the upthrust is 20 Newton's calculate it's weight in ares
Answer:
420N
Explanation:
W = weight in air
T = weight in water
U = Upthrust
W = T + U
W = 400 + 20
W = 420 N
what is the work done by the frictional force in stopping the brick?
The work done by the frictional force in stopping the brick is negative, as it opposes the direction of motion of the brick. The correct answer is Negative.
Explanation:
What is the frictional force?The force that opposes the motion of an object when it comes in contact with a surface is called the frictional force. This force is generated when two surfaces come into contact and tend to slide against one another. The work done by the frictional force in stopping the brick is negative because it is acting in the opposite direction of the motion of the brick.
Therefore, the work done by the frictional force is the negative of the work done by the applied force that is moving the brick.
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what refers to a type of cable composed of four copper wires twisted around each other within a plastic sheath?
Twisted-pair wiring is a category of cable that is comprised of four copper cables that have been wound around one another and encased in a plastic sheath.
What purpose does a twisted pair cables serve?Also with copper wires, twisted-pair cables were some of the first guided transmission medium. Twisted-pair cables are utilized in a variety of networking and communication applications today, including local area networks, digital subscriber lines, and phone lines.
Where can you use twisted pairs?The common copper cable known as twisted pair is used to link residential and commercial systems to the phone provider. Two copper pipe wires are wound around each other in a spirally to minimize electromagnetic induction or crosstalk between pairs of wires. Twisted pair connections require both wires for each connection.
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Assume that the cart is free to roll without friction and that the coefficient of static friction between the block and the cart is ?s. Derive an expression for the minimum horizontal force that must be applied to the block in order to keep it from falling to the ground.
The minimum horizontal force (F) that must be applied to the block is equal to the static friction force (fs) to keep it from falling is: F = μs * mg
To derive an expression for the minimum horizontal force (F) that must be applied to the block to keep it from falling to the ground, we will use the following terms: cart, roll without friction, coefficient of static friction (μs), and minimum horizontal force.
Assuming that the cart is free to roll without friction and the coefficient of static friction between the block and the cart is μs, we can analyze the forces acting on the block.
There are two forces acting on the block: gravitational force (mg) acting vertically downward and the static friction force (fs) acting horizontally opposite to the applied force. To keep the block from falling, the static friction force must balance the gravitational force.
Using Newton's second law of motion, we can write the equations for the horizontal and vertical components:
1) fs = μs * N (where N is the normal force)
2) N = mg (since there is no vertical acceleration)
Substituting equation (2) into equation (1), we get:
fs = μs * mg
The minimum horizontal force (F) that must be applied to the block is equal to the static friction force (fs) to keep it from falling. Therefore:
F = μs * mg
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A gannet is a seabird that fishes by diving from a great height. You may want to review If a gannet hits the water at 32 m/s, what height did it dive from? Assume that the gannet was motionless before starting its dive. Express your answer to two significant figures and include the appropriate units. h =
After considering the given data the height from which the gannet dived is approximately 51.84 m.
To evaluate the height from which a gannet dived if it hits the water at 32 m/s, assuming that the gannet was motionless before starting its dive, we can apply the law of conservation of energy, which projects that the initial potential energy of the gannet is equivalent to its final kinetic energy prior to hitting the water. Then, we can write:
\(mgh = (1/2)mv^2\)
Here:
m = mass of the gannet
g = acceleration due to gravity
h = height from which the gannet dived
v = velocity of the gannet just before hitting the water
Considering that the mass of the gannet is 1 kg, and applying substitution of the given values, we get:
\((1 kg)(9.8 m/s^2)(h) = (1/2)(1 kg)(32 m/s)^2\)
\(h = (1/2)(32 m/s)^2 / (9.8 m/s^2)\)
h = 51.84 m
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The complete question is
A gannet is a seabird that fishes by diving from a great height. If a gannet hits the water at 32 m/s , what height did it dive from? Assume that the gannet was motionless before starting its dive.
As a result of mitosis, the cels of a Molecular organism sure which of these properties select to correct answers. A. All cells have the same number of chromosomes. B. The number of chromosomes varies amongst the cells C. All cells have identical genetic information. D. Genetic information varies among the cells.
Answer:
C. All cells have identical genetic information.
Answer:
A and C
Explanation:
Introduction to Physical Science: Tutorial and Asking Questions
This activity will help you meet these educational goals:
. You will ask questions to identify and clarify evidence for an argument.
. You will apply scientific principles to design a process.
Directions
Read the instructions for this self-checked activity. Type in your response to each question, and check your answers. At the end
of the activity, write a brief evaluation of your work.
Activity
Spend time observing or thinking about events that involve matter and energy. Which events can you explain? Which
events can't you explain? Now answer the following questions.
Part A
Describe three events that you cannot explain.
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Energy and matter are both conserved within natural processes. It follows that while energy and matter can adopt different forms, they cannot be produced or extinguished. Different types of matter and energy can combine, and energy and matter frequently cycle within a system.
Explain energy.
Energy is the ability to perform tasks. It could appear in numerous different forms, such as potential, kinetic, thermal, electrical, chemical, nuclear, etc. Additionally, there is heat and work, which is energy being transferred from one entity to another.
The most important source of chemical energy for sustaining life is found in food. The three states of matter—liquid, solid, and gas—are essential because matter and energy move in concert along food networks.
An ice cube composed of water, for instance, changes into liquid water when you add energy, and when you add even more energy, it turns into steam. The type of matter and the quantity of matter are the same as in the original cube, but the level of energy may be higher or lower.
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Please I beg you help me out here this is due in a few hours thank you. Calculate the current in each resistor with current 13A 2ohms 3ohms 4ohms
The current through each resistor is 13 A.
To calculate the current in each resistor, we can use Ohm's law, which states that the current through a conductor between two points is directly proportional to the voltage across the two points and inversely proportional to the resistance between them.
In this case, we are given the current and the resistance of each resistor, so we can use Ohm's law to calculate the voltage across each resistor, and then use the current to find the current through each resistor.
Let's start with the first resistor, which has a resistance of 2 ohms:
V = IR
V = (13 A) x (2 ohms)
V = 26 V
Now, we can use the voltage and resistance to find the current through the first resistor:
I = V/R
I = (26 V) / (2 ohms)
I = 13 A
So, the current through the first resistor is also 13 A.
Next, we can repeat the same process for the other two resistors:
For the second resistor with a resistance of 3 ohms:
V = IR
V = (13 A) x (3 ohms)
V = 39 V
I = V/R
I = (39 V) / (3 ohms)
I = 13 A
So, the current through the second resistor is also 13 A.
For the third resistor with a resistance of 4 ohms:
V = IR
V = (13 A) x (4 ohms)
V = 52 V
I = V/R
I = (52 V) / (4 ohms)
I = 13 A
So, the current through the third resistor is also 13 A.
Therefore, the current through each resistor is 13 A.
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Intrusive igneous rocks:_____________
A. are fine-grained because they cooled slowly.
B. are never seen by humans, because they form deep in the Earth and are never exposed at the surface.
C. are rocks like basalt, andesite, and rhyolite.
D. cool slowly and are coarse-grained.
Answer:
D
Explanation:
Contrary to answers a, b, and c, volcanic rocks, like basalt, andesite, and rhyolite, are fine-grained which are extrusive igneous rocks.
Intrusive rocks, also called plutonic rock, are coarse-grained and cool slowly without ever reaching the surface. While intrusive igneous rocks do solidify in the earth they do eventually become exposed by erosion.
I hope this helps
Correct me if I'm wrong.
You attend a concert and have a seat that is 70 m away from the stage where the sound is produced. How long does it take for the sound to reach your ears? You take a picture with your phone and send it to your friend who could not come to the concert. She lives in a town 45 miles away. How long does it take until she gets the picture on her phone? Please, include the assumptions that you make.
Given:
distance of observer from the sound source, \(s=70~m\)
distance between the source of image information sender and the receiver, \(d=45~miles=72420.48~m\)
Assumptions:
speed of sound, \(v=343~m/s\)
speed of the image information being sent, \(c=3\times 10^8~m/s\) (we assume it to be nearly the speed of light in vacuum)
Solution:
Time taken by the sound to reach the observer:
\(time=\frac{distance}{speed}\)
\(time=70\div 343\)
\(time \approx 0.2~s\)
Time taken by the image to reach the destination:
\(time=\frac{72420.48}{3\times 10^8}\)
\(time=2.4\times 10^{-4}~s\)
A girl is travelling on her bike at a speed 2.54 m/s. If the girl and her bike have a kinetic energy of 193 J, what is the combined mass of the girl and her bike? Show all your work.
Answer:
About 59.83 kg
Explanation:
The formula for kinetic energy is \(KE = \frac{1}{2}mV^2\), where KE = Kinetic Energy in Joules (J), m = mass in kilograms (kg), and V = Velocity in meters per second (m/s).
In this problem, we are given the Kinetic Energy amount as 193 Joules and the Velocity as 2.54 m/s. Let's plug it into our equation
\(193 = \frac{1}{2} * 2.54^2m\)Now, let's solve this equation.
Step 1: Simplify both sides of the equation.
\(193 = 0.5 * 2.54 * 2.54 * m\) \(193=3.2258m\)Step 2: Divide both sides by 3.2258.
\(193/3.2258 = 3.2258m/3.2258\) m ≈ 59.830 kilogramsWhen the wedges are removed, the cars will move. Predict which direction they will move and when they will stop(help due by tonight)
Answer:
backwards. they will stop.
Explanation:
they will stop at a point because of the friction and that it couldn't move for ever
Can you answer that?
Answer:
At positions C and E potential energy is maximum. At position D kinetic energy is maximum.
Explanation:
Beatrice and the Elevator Beatrice, a middle school student, is visiting a very tall office building and notices that she feels heavier when the elevator car is traveling up and lighter when the elevator car is travelling down. After making these observations, Beatrice comes back to the building and stands on a bathroom scale that measures her weight as she travels up and down in the elevator.
Explanation:
The question is not complete, here is the complete question
"Beatrice and the Elevator Beatrice, a middle school student, is visiting a very tall office building and notices that she feels heavier when the elevator car is traveling up and lighter when the elevator car is traveling down. After making these observations, Beatrice comes back to the building and stands on a bathroom scale that measures her weight as she travels up and down in the elevator.
1. . What question is Beatrice trying to answer?
2. What is one variable Beatrice could change in her investigation? What might she figure out if this
variable was changed"
1. Beatrice is trying to observe the influence of the elevator movement on her weight, Hence the question is "will the elevator movement cause her weight to change"
therefore moving upward the reading on the scale will increase
Reading=mg+ma
downward
Reading will reduce
Reading=mg-ma
2. The independent variable is the acceleration due to gravity g=9.81m/s^2
while the dependent variables are
i. The elevators acceleration
ii. Beatrice's mass
A simple pendulum consisting of a blob of mass m attached to a string of length L swings with a period T. If the mass of the blob is reduced by half, what will the new period of oscillation be? Answer is: T The pendulum is now swinging on Pluto. Calculate the new period of oscillation in terms of T, knowing that on Pluto the gravity is 1/16 of gravity on the Earth.
(a) If the mass of the blob is reduced by half, the new period of oscillation will same as the initial.
(b) The new period of oscillation on Pluto is 4 times the period of oscillation on Earth.
What is the new period of oscillation of the pendulum?
The new period of oscillation of the pendulum is calculated as follows;
T = 2π √ ( L / g )
where;
L is the length of the string g is acceleration due to gravity on EarthFrom the equation above we can see that the period of a pendulum does not depend on the mass of the bob, but only on the length of the string.
Hence, the new period of oscillation will be same value as the initial.
The new period of oscillation on Pluto when the gravity of Pluto is 1/16 of Earth is calculated as;
T' = 2π √ (L/g/16)
T' = 2π √ ( 16L/g )
T' = 4 [ 2π √ (L/g) ]
T' = (4T)
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While riding a skateboard, Nina ran into a rough patch of pavement, but she thought she could ride right over it. Instead, the skateboard
stopped but Nina didn't. Her _______ kept her moving forward, so she fell off the skateboard.
Answer:
ineria
Explanation:
It is due to her inertia of motion that kept her moving forward.
We have Nina who is riding skateboard.
We have to determine why Nina fell off the skateboard on rough pavement.
What is Inertia ?A property of matter by which it continues in its existing state of rest or uniform motion in a straight line, unless that state is changed by an external force.
According to the question -
Before the rough patch, Nina was riding smoothly. However as soon as she enters the rough patch, the rough patch acts as an obstruction to the forward movement of skateboard. The skateboard and Nina are both moving with same velocity. The skateboard is in contact with the rough patch and as soon as the skateboard's motion is obstructed, the skateboard comes to rest but due to the inertia of motion, Nina continues to move with the same forward velocity. In this way, Nina falls ahead of skateboard.
Hence, it is due to her inertia of motion that kept her moving forward.
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Particles q₁ = -75.8 μC, q₂ = +90.6 μC, and q1 q3=-84.2 μC are in a line. Particles q₁ and q₂ are separated by 0.876 m and particles q2 and q3 are separated by 0.432 m. What is the net force on particle qз?
The net force on particle q₃ is approximately 2576.08 N.
To calculate the net force on particle q₃, we need to consider the forces exerted on it by particles q₁ and q₂ due to their electrostatic interactions.
The electrostatic force between two charged particles can be determined using Coulomb's law, which states that the force between two charges is directly proportional to the product of their charges and inversely proportional to the square of the distance between them. Mathematically, the formula for the electrostatic force (F) is:
F = (k * |q₁ * q₂|) / r²
Where k is the electrostatic constant (k ≈ 8.99 × 10^9 N m²/C²), q₁ and q₂ are the charges of particles q₁ and q₂, and r is the distance between them.
First, let's calculate the force between q₁ and q₂:
F₁₂ = (8.99 × 10^9 N m²/C² * |-75.8 μC * 90.6 μC|) / (0.876 m)²
Plugging in the values:
F₁₂ ≈ (8.99 × 10^9 N m²/C² * 6.87508 μC²) / (0.876 m)²
≈ 563.78 N
Next, let's calculate the force between q₂ and q₃:
F₂₃ = (8.99 × 10^9 N m²/C² * |90.6 μC * -84.2 μC|) / (0.432 m)²
Plugging in the values
F₂₃ ≈ (8.99 × 10^9 N m²/C² * 7.62012 μC²) / (0.432 m)²
≈ 3139.86 N
To find the net force on q₃, we need to subtract the force F₁₂ from F₂₃:
Net Force = F₂₃ - F₁₂
= 3139.86 N - 563.78 N
≈ 2576.08 N
Therefore, the net force on particle q₃ is approximately 2576.08 N.
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a physics professor demonstrates the doppler effect by tying a 450 hzhz sound generator to a 1.0-mm-long rope and whirling it around her head in a horizontal circle at 100 rpmrpm.
What is the difference between the highest frequency heard by a student in the classroom and the initial.
frequency of the sound generator?
The difference between the highest frequency heard by a student in the classroom and the initial frequency of the sound generator can be calculated using the Doppler effect equation. The Doppler effect describes the change in frequency of a wave when there is relative motion between the source of the wave and the observer.
In this scenario, as the sound generator is whirled around in a horizontal circle, it experiences circular motion. The frequency of the sound wave observed by the student will vary depending on the relative motion between the source and the observer.
To calculate the difference in frequency, we need to consider the relative velocity between the source and the observer. Since the source is rotating in a circle, its velocity changes continuously. This means that the frequency heard by the student will also change continuously.
Without specific information about the positions and distances involved, it is difficult to provide an exact numerical value for the difference in frequency. However, it can be determined by applying the Doppler effect equation and considering the relative velocity between the source and the observer at different points in the motion.
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1. A 1.33-kg physics textbook is initially at rest on a steel table.
The textbook is then pushed with a constant force of 4.0 N.
Friction with a magnitude of 2.0 N is exerted on the moving
book by the surface of the table.
Determine the final velocity of the textbook after it has been
pushed 0.75 meter across the table.
The acceleration of the textbook is a = F/m = 2.0 N/1.33 kg = 1.5 m/s². and the final velocity of the textbook is v = 0 + (1.5 m/s²)(0.75 s) = 1.125 m/s.
What is acceleration?Acceleration is the rate at which an object changes its velocity over time. It is a vector quantity, meaning it has both magnitude and direction. An object's acceleration can be calculated by measuring the change in its velocity over time.
The net force acting on the textbook is the difference between the pushing force of 4.0 N and the frictional force of 2.0 N, which is 2.0 N.
According to Newton's Second Law, this net force of 2.0 N will cause an acceleration of the textbook given by the equation F = ma, where m is the mass of the textbook (1.33 kg) and a is the acceleration.
Therefore, the acceleration of the textbook is a = F/m = 2.0 N/1.33 kg = 1.5 m/s².
The final velocity of the textbook can then be calculated using the equation v = v0 + at, where v0 is the initial velocity (0 m/s, since the textbook was initially at rest), a is the acceleration (1.5 m/s²), and t is the time the textbook was pushed (0.75 m).
Therefore, the final velocity of the textbook is v = 0 + (1.5 m/s²)(0.75 s) = 1.125 m/s.
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The bearing of grids of an AB alignment is 100º 22', while the magnetic declination is 8º30' E. What are the true azimuth, magnetic azimuth, and grid azimuth of this alignment?
The true azimuth of the AB alignment is 91º 52' (east of north), the magnetic azimuth is 100º 22' (east of north), and the grid azimuth is 108º 52' (east of north).
To find the true azimuth, magnetic azimuth, and grid azimuth of the AB alignment, we need to consider the magnetic declination. The magnetic declination indicates the angle between true north and magnetic north at a specific location. In this case, the magnetic declination is 8º 30' E, which means that the magnetic north is 8º 30' east of the true north.
To calculate the true azimuth, we subtract the magnetic declination from the grid azimuth. The grid azimuth is given as 100º 22', so subtracting the magnetic declination of 8º 30' E gives us a true azimuth of 91º 52' (east of north).
The magnetic azimuth remains the same as the grid azimuth, which is 100º 22' (east of north).
The grid azimuth is calculated by adding the magnetic declination to the true azimuth. Since the magnetic declination is east, we add it to the true azimuth. Adding 8º 30' E to the true azimuth of 91º 52' gives us a grid azimuth of 108º 52' (east of north).
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Help in desperate need of assistance!!!
Fighter jets on aircraft carriers are accelerated down a 270 foot "runway" in two seconds when they are taking off. A fully loaded, combat ready F-15 has a maximum take-off weight of 62,000 pounds. To ensure the pilot can reach sufficient velocity within 2 seconds a pneumatic cannon propels the plane down the runway. If this same cannon was used to launch your Toyota Corolla (mass is 2646lbs), how fast in miles per hour would you be going after reaching the end of the runway?
The speed of the Toyota Corolla would have been 143.9 mph.
What is the acceleration of the F-15?
The acceleration of the F-15 can be calculated as follows:
Acceleration = Velocity Change / Time = (Take-off Speed) / Time
where;
Take-off Speed = √(2dg /t²)
Take-off Speed = √(2 x (270 ft) x 32.2 ft/s² / (2 s)²)
T = √(17496) = 131.6 ft/s
Acceleration = Velocity Change / Time
= (131.6 ft/s) / (2 s) = 65.8 ft/s²
We can use the same acceleration to launch the Toyota Corolla, and calculate its final velocity:
Final Velocity = Initial Velocity + Acceleration x Time
where;
Initial Velocity = 0 (because the car is not moving initially), Time = 2 sFinal Velocity = 0 + (65.8 ft/s²) * (2 s) = 131.6 ft/s
Finally, we can convert the velocity from feet per second to miles per hour:
Velocity (mph) = Velocity (ft/s) x (1 hour/3600 s) x (5280 ft/mile)
= 131.6 ft/s x (1 hour/3600 s) x (5280 ft/mile)
= 143.9 mph
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Find the angular velocity of gear 5 using first order kinematic coefficients. The centers of gears 4 and 5 are fixed. Given: R_2 = 4", R_AB = 12", rho_4 = 2", rho_5 = 6", theta_2 = 60 degree, omega_2 = 10 rad/s ccw
The angular velocity of gear 5 is (√3 / 3) rad/s.
To find the angular velocity of gear 5 using first-order kinematic coefficients, we can use the formula:
ω_5 = ω_2 * (R_2 / R_AB) * (ρ_4 / ρ_5) * sin(θ_2)
where:
ω_5 is the angular velocity of gear 5
ω_2 is the angular velocity of gear 2
R_2 is the radius of gear 2
R_AB is the distance between the centers of gears 4 and 5
ρ_4 is the distance from the center of gear 4 to the pitch point (contact point) with gear 2
ρ_5 is the distance from the center of gear 5 to the pitch point with gear 2
θ_2 is the pressure angle of gear 2
Using the given values:
R_2 = 4"
R_AB = 12"
ρ_4 = 2"
ρ_5 = 6"
θ_2 = 60 degrees
ω_2 = 10 rad/s (counterclockwise)
ω_5 = 10 * (4 / 12) * (2 / 6) * sin(60°)
ω_5 = 10 * (1/3) * (1/3) * √3/2
= 10 * (1/9) * √3
= (√3 / 3) rad/s
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State which type of variable is plotted on the x-axis
and which type is plotted on the y-axis.
Answer:
Often the independent variable is plotted on the x-axis - and example might be time (an experiment where time is measured by a watch or an independent mechanical device)
The dependent variable is often plotted on the y-axis - and example here might be the velocity or the acceleration,
It may be the responsibility of the experimenter to determine the value of the dependent variable by some type of measurement
calculate the frequency of the red light emitted by a neon sign with a wavelength of 659.9 nm.
The frequency of the red light emitted by a neon sign with a wavelength of 659.9 nm is 4.5×10^14 Hz.
What is the frequency?The frequency is the number of times a recurring occurrence takes place during a predetermined period. For example, if an event occurs twice in one second, then the frequency is 2 Hz (Hertz).
A recurring event's frequency is the number of times it happens in a predetermined period. For example, a frequency of a wave is the number of wave peaks passing a fixed point in one second.
The frequency is the number of times something occurs in a given period. For example, the frequency of a radio station is the number of times it broadcasts a signal per second.
Given:
Wavelength = 659.9nm
Speed of light = 3×10^8 m/s
Frequency = speed of light / wavelength
Frequency = (3.0 x 10^8 m/s) / (659.9 nm)
Frequency = 4.5 x 10^14 Hz
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you have 0.3 moles of helium and 0.7 moles of neon mixed together inside a sealed container. the rms speed of the helium atoms is 811 m/s. what is the rms speed of the neon atoms?
The rms speed of the helium atoms is 811 m/s. So the rms speed of the neon atoms is 465 m/s.
Given that there are 0.3 moles of helium and 0.7 moles of neon mixed together inside a sealed container. The rms speed of the helium atoms is 811 m/s.We need to find the rms speed of the neon atoms.In order to find the rms speed of the neon atoms, we need to use the following formula:rms speed = √((3kT) / m)Here,k = Boltzmann’s constantT = temperaturem = mass of the gasLet's calculate the rms speed of helium atoms first;rms speed of helium atoms = √((3kT) / m)811 = √((3 × 1.38 × 10^-23 × T) / 0.004)3.68 × 10^5 = T / 0.004T = 1472 KNow we can calculate the rms speed of the neon atoms;rms speed of neon atoms = √((3kT) / m)= √((3 × 1.38 × 10^-23 × 1472) / 0.0202)= 465 m/s. Therefore, the rms speed of the neon atoms is 465 m/s.
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