rank the following elements by electron affinity, from most positive to most negative ea value. flourine, oxgen, antimony, rubidium, krypton

The strong electrolytes among the given choices are HCl, HC2H3O2, and KCl.

In the given options, HCl and KCl are both ionic compounds. They contain a cation (H+ or K+) and an anion (Cl-). When these compounds dissolve in water, the ions get separated and move freely in the solution. Therefore, HCl and KCl completely dissociate into ions and are strong electrolytes.

On the other hand, HC2H3O2 (acetic acid) and NH3 (ammonia) are weak electrolytes. They partially dissociate into ions and also exist in the molecular form in the solution. Therefore, they are not strong electrolytes. In conclusion, HCl, HC2H3O2, and KCl are the strong electrolytes among the given choices.

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Answer:

Rule 1. The element with the lower group number is written first in the name; the element with the higher group number is written second in the name. Exception: when the compound contains oxygen and a halogen, the name of the halogen is the first word in the name.

Explanation:

When naming binary covalent compounds, the element listed first will be the one that is lower in group number.

Covalent compounds versus ionic compounds are the two groups into which chemical compounds are often divided. Ionic compounds are composed of atoms or molecules that have gained or lost electrons, causing them to become electrically charged.

Covalent or molecular compounds often emerge from the interaction of two nonmetals. By sharing electrons, the elements combine to create a compound, producing and electrically neutral molecule. When naming binary covalent compounds, the element listed first will be the one that is lower in group number.

Therefore, when naming binary covalent compounds, the element listed first will be the one that is lower in group number.

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Answer:

Group 12

Explanation:

Group 12 is also called a transition metal group. This group in the periodic table lies in between the groups or tables. These metals are classified as the transition metal in the table.

These metals are found from the group number 3 to 12. In the periodic table, These transition elements are ductile and malleable. These metal conduct heat and electricity.

These elements are generally called dense and less to react to the alkaline metal. Iron, copper-silver, gold is the most important transition metal.

Answer:

Group 11

Explanation:

Pf

Answer:

jsjdhiefjcbjajrjrjwbxjuq ueei1udj

221 grams is the mass of oxygen gas is consumed in a reaction that produces 4.60 mol sulfur dioxide

The given question is incomplete as it lacks a chemical reaction, however, the chemical reaction is :

Hydrogen sulfide gas burns in oxygen to produce sulfur dioxide and water vapor.

\(2H_2S(g)+3O_2(g)\rightarrow 2SO_2(g)+2H_2O(g)\)

Explanation:

Given:

The chemical reaction:

\(2H_2S(g)+3O_2(g)\rightarrow 2SO_2(g)+2H_2O(g)\)

To find:

Mass of oxygen gas consumed in a reaction to produce 4.60 moles of sulfur dioxide gas.

Solution:

The moles of sulfur dioxide gas produced =4.60 mol

\(2H_2S(g)+3O_2(g)\rightarrow 2SO_2(g)+2H_2O(g)\)

According to a chemical reaction, 2 moles sulfur dioxide is obtained from 3 moles of oxygen gas, then 4.60 moles of sulfur dioxide will be obtained from:

\(=\frac{3}{2}\times 4.60mol=6.9\text{ mol of }O_2\)

Mass of 6.9 moles of oxygen gas:

\(6.9 mol\times 31.998 g/mol=220.79 g\approx 221 g\)

221 grams is the mass of oxygen gas is consumed in a reaction that produces 4.60 mol sulfur dioxide.

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Explanation:

We have to balance the following equation:

__ H₂O + __ F₂ -------> __ HF + __ O₂

First we have to determine the number of atoms of each element that we have on both sides of the equation.

__ H₂O + __ F₂ -------> __ HF + __ O₂

O: 1 O: 2

H: 2 H: 1

F: 2 F: 1

We have 2 atoms of O on the right side and 1 atom of O on the left side. To balance the O atoms we can change the coefficient for H₂O and write a 2 in front of it.

2 H₂O + __ F₂ -------> __ HF + __ O₂

O: 2 O: 2

H: 4 H: 1

F: 2 F: 1

Then we have 4 atoms of H on the left and 1 atom of H on the right side of the equation. We can change the coefficient for HF to balance the H atoms.

2 H₂O + __ F₂ -------> 4 HF + __ O₂

O: 2 O: 2

H: 4 H: 4

F: 2 F: 4

And finally we have 2 atoms of F on the left and 4 atoms of F on the right. We can change the coefficient for F₂ and write a 2 there.

2 H₂O + 2 F₂ -------> 4 HF + __ O₂

O: 2 O: 2

H: 4 H: 4

F: 4 F: 4

The equation is balanced.

Answer: 2 H₂O + 2 F₂ -------> 4 HF + O₂

The most obvious difference in the 1H NMR spectrum between two unknown compounds will depend on a variety of factors, including their structures, functional groups, and the conditions under which the spectrum was recorded.

It is impossible to determine the most obvious difference in the 1H NMR spectrum between two unknown compounds without additional information about their structures. The 1H NMR spectrum provides information about the hydrogen atoms in a molecule, including their chemical environments and their coupling to other nearby hydrogen atoms. However, the spectrum can vary widely depending on the specific arrangement of atoms in the molecule, as well as factors such as temperature and solvent used. For example, if one of the unknown compounds is a simple alkane and the other is a more complex compound with multiple functional groups, the most obvious difference in the 1H NMR spectrum might be the number and complexity of the peaks in the spectrum. The alkane would have a simple, single peak corresponding to the hydrogen atoms in the molecule, while the more complex compound would have multiple peaks corresponding to the different types of hydrogen atoms present in the molecule. Alternatively, if the two unknown compounds are structural isomers (i.e., they have the same molecular formula but different arrangements of atoms), the most obvious difference in the 1H NMR spectrum might be the number and position of the peaks corresponding to the different types of hydrogen atoms in each isomer. In this case, the two spectra might look very similar but differ in subtle ways that require careful analysis to distinguish.

In summary, the most obvious difference in the 1H NMR spectrum between two unknown compounds will depend on a variety of factors, including their structures, functional groups, and the conditions under which the spectrum was recorded.

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Explanation:

Density = mass / volume

ρ = 640 g / (4 cm)³

ρ = 10 g/cm³

Balancing the equation :

KOH(aq) + HBr(aq) --> KBr(aq) + H2O(l)

This is the balanced chemical reaction because it follows the following ionic reaction:

H ^(aq)+ + Br^(aq)- + K^+(aq) + OH ^- (aq) → K^+(aq) + Br^-(aq) + H2O (l)

Explanation:

No, that would be incorrect

Answer:

There arre two main parts of the atom, the nucleus and the orbital rings. The three subatomic particles are contained in each of these, the proton and neutron together in the nucleus and the electrons orbiting in the rings.

Answer: 519.4

Explanation:

Im taking the same class and just answered the exact question

Answer:

Barium Chloride + Aluminum Sulfate = Barium Sulfate + Aluminum Chloride

Explanation:

Hopefully this helps you!!

Don't be afraid to correct me if i'm wrong! :)

The answer is that the chemical reaction is exothermic, meaning it releases energy in the form of heat.

This is because the total enthalpy (heat content) of the products is lower than that of the reactants. This means that the products have less stored energy than the reactants, and the difference is released as heat. An explanation for this could be that the reaction involves breaking stronger bonds in the reactants and forming weaker bonds in the products, which requires less energy overall.


This is characteristic of an exothermic reaction, in which heat is released to the surroundings. In contrast, an endothermic reaction would have a higher enthalpy for the products compared to the reactants, meaning that energy is absorbed from the surroundings during the reaction.

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Answer:

Hydrogen burns in oxygen to form water. The flame is almost colourless. Mixtures of hydrogen and oxygen (or hydrogen and air) can be explosive when the two gases are present in a particular ratio, so hydrogen must be handled very carefully.

The answer to your question is:

Answer:

A. Particles are parked closely together in an organized way and maintain their size, shape and volume.

Explanation:

These are some characteristics of a solid;

✨Thanks!!!!❤✨

Answer:

destroyed.

transferred.

Explanation:

hehe

Answer:

Your answer would be destroyed and Transferred.

Explanation:

The reason why is because energy is never created or destroyed because it is just transferred to different forms of energy. Suich as a ball at the top of a hill. It's not moving, so it has potential energy, (potential energy is energy that is stored) and let's say that some wind comes through and gives that ball a push, so now the ball is moving and is going downhill. now the ball has kinetic energy because it was transferred to a moving energy from a stored energy.

Answer:

Colony

Explanation:

The relationships between the quantum numbers we could find the results for which configuration corresponds to excited states are:

  c) The 3s electron is excited to the 4s level  \(1s^2 2s^2 2p^6 3s^1\)

  d) The 3s electron is excited to the 3p level \(1s^2 2s^2 2p^6 3s^2 3p^4\)

The distribution of electrons in atoms must comply with the relationships between quantum numbers, which are discrete values:

The most used nomenclature is to write the state is:

           \(n l^{electrons}\)  

Let's analyze how many electrons fit in each state in the table we have the values

The spin quantum number allows only two electrons in each sublevel ml

State  n   l        ml        Total electrons

  1s     1   0         0                   2

 2s     2  0         0                   2

 2p    2   1       -1.0, + 1             6

 3s     3  0          0                   2

 3p     3  1        -1.0, + 1             6  

 3d     3  2   -2,-1,0, + 1, + 2    10  

Let's apply these rules to each configuration shown

a)  \(1s^22s^22p^63s^1\)

Levels n = 1 and 2 have their maximum number of electrons

At level n = 3 there is an electron and it is the last level. So this atom is in its ground state

b)  \(1s^22s^22p^63s^23p^4\)  

Levels 1 and 2 are full

Level 3 has the sublevel s full and the sublevel p has 4 electrons and there are no higher levels, therefore the atom is in its ground state

c) 1s²2s²2p⁶ ​​3s¹ 3p⁶ 3d¹⁰ 4s²

Levels 1 and 2 are full

Level 3 has sublevel s with one electron not full

Sublevel p has 6 electrons its maximum

                        sublevel d has 10 electrons its axiom

The last level has 2 electrons, one of the configuration of the atom and others that have been excited since the coming 3s

Consequently this configuration corresponds to an excited state

d) 1s² 2s²2p⁶ 3s 3p⁶

Levels 1 and 2 are full

Level 3 sub-level s has one electron

The subvening p has 6 electrons

As the sublevel s is incomplete, one of its electrons must have been excited to the sublevel 3p

Consequently this excited state.

In conclusion, using the relationships between the quantum numbers, we were able to find the results for which configuration corresponds to excited states  are:

     c) The 3s electron is excited to the 4s level  \(1s^2 2s^2 2p^6 3s^1\)

     d) The 3s electron is excited to the 3p level \(1s^2 2s^2 2p^6 3s^2 3p^4\)

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Answer:

The term niche, when used in the science of ecological biology, is used to define an organism's role in an ecosystem. Not only does its niche include the environment that a given organism lives in, but it also includes the organism's "job" in that environment.

Answer:

a niche is an area within an ecosystem in which a particular group of organisms live in.

If the color of the solution changes to purple after adding the biuret reagent, it indicates the presence of proteins (yes). If the color remains blue, it indicates the absence of proteins (no).

When performing a biuret test to determine the presence of proteins, you will observe the color of the solution after adding the biuret reagent to different samples. Here's a step-by-step explanation:

1. Prepare three samples: water (control), filtrate, and casein.
2. Add the biuret reagent to each sample.
3. Observe the color of each solution after a few minutes.

The color change you should look for is from blue to purple. If the solution turns purple, it indicates the presence of proteins.

- For the water (control) sample, you should not expect any color change since it does not contain proteins.
- For the filtrate sample, the color change depends on whether there are proteins present in the filtrate.
- For the casein sample, you should expect the solution to turn purple because casein is a protein.

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Hey can u give me brainliest and thanks

The correct option is D, I = 3H; II = 4H; III = 4H protons are represented by each signal. Signal I: 0.9 ppm, integration = 3.3 Signal II: 1.4 ppm, integration = 2.2 Signal III: 3.5 ppm, integration = 2.2.

A proton is a subatomic particle that is found in the nucleus of an atom. It has a positive charge and, along with neutrons, makes up the atomic nucleus. Protons are one of the building blocks of matter, and their number determines an element's atomic number and chemical properties.

Protons are made up of two "up" quarks and one "down" quark, held together by the strong force. The strong force is one of the four fundamental forces of nature and is responsible for binding the protons and neutrons in the nucleus. The proton's positive charge also plays a crucial role in determining the behavior of atoms and molecules, as it interacts with the electrons in the outer shell of an atom.

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Complete question: -

There are three signals (listed below as I, II, and II) in the 'H NMR spectrum of a compound with the molecular formula C6H140. For each of the three signals, the chemical shift and relative integration value are provided. How many protons are represented by each signal? Signal I: 0.9 ppm, integration = 3.3 Signal II: 1.4 ppm, integration = 2.2 Signal III: 3.5 ppm, integration = 2.2

A. I = 3H; II = 2H; III = 2H

B. I = 6H; II = 2H; III = 2H

C. I = 6H; II = 4H; III = 4H

D. I = 3H; II = 4H; III = 4H

Answer:

See explanation

Explanation:

Period 3 elements include; Na, Mg, Al, Si, P,S,Cl and Ar

Across the period, the chlorides of the elements change from solid to gas. The chlorides of metals are solid while the chlorides of non metals are gaseous.

Also, the chlorides become more volatile across the period. The formulas of the chlorides change from MCl to MCl2 to MCl3 to MCl4, MCl5 and MCl6 respectively across the period where M is a period 3 element.

The pH of the solutions of chlorides of period 3 elements change from neutral to acidic across the period. The pH of the chlorides of metals are neutral while the chlorides of the nonmetals usually yield acid solutions.

The oxidation reduction reaction are given below.

Oxidation half reaction:

Zn° →Zn² + 2e-

Reduction half reaction:

2Mn^5 +4e^- → 2Mn^2+

Belo w are the oxidation and reduction reaction of the common alkaline batteries to produce electricity.

Oxidation half reaction:

Zn° →Zn² + 2e-

Reduction half reaction:

2Mn^5 +4e^- → 2Mn^2+

To balance the overall reaction, we need to multiply each half reaction by appropriate coefficients to ensure that the electrons cancel out.

Here is the balance overall reaction.
2Zn° + 2Mn^5 → 2Zn² + 2Mn²+

The balanced equation shows that in alkaline batteries, zinc metal is oxidized to form zinc ion, while manganese ions are reduced to manganese(II) ions. The oxidation reduction reaction    generate an electric current as a result of the flow of electrons.

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Answer:

3s orbital

Explanation:

3s is the outermost orbital of magnesium and it loses electron from it, it doesnt even have 4f, 5p or 3d orbitals.

Explanation:

Magnesium representation : 1s²2s²2p⁶3s².

therefore, to become Mg2+ ion Magnesium losses electron from its 3s orbital to form 1s²2s²2p⁶.

therefore option C is correct.

hope this helps you.

The estimated value of the solubility product constant (Ksp) for silver iodide (AgI) is approximately 3.55 x 10^39.

How to estimate the value of the solubility product constant (Ksp) for silver iodide (AgI)?

To estimate the value of the solubility product constant (Ksp) for silver iodide (AgI), we can use the Nernst equation and the given standard reduction potentials. The overall reaction for the dissolution of AgI can be written as follows:

AgI(s) ⇌ Ag+(aq) + I-(aq)

The reduction half-reaction for the formation of Ag(s) from Ag+(aq) is:

Ag+(aq) + e- → Ag(s) (Reduction half-reaction)

The oxidation half-reaction for the formation of I-(aq) from I2(aq) is:

1/2 I2(aq) + e- → I-(aq) (Oxidation half-reaction)

By combining these two half-reactions, we can construct the overall reaction and determine the value of Ksp for AgI.

AgI(s) ⇌ Ag+(aq) + I-(aq)

To find the value of Ksp, we need to calculate the equilibrium constant (K) using the Nernst equation:

K = [Ag+(aq)]/[I-(aq)]

Using the standard reduction potentials given, we can calculate the overall standard cell potential (E°cell) for the reaction:

E°cell = E°(Ag+(aq)/Ag(s)) + E°(I2(aq)/I-(aq))

E°cell = (0.7996 V) + (0.5355 V)

E°cell = 1.3351 V

Next, we can use the relationship between the standard cell potential and the equilibrium constant:

E°cell = (0.0592 V/n) * log(K)

Where n is the number of electrons involved in the overall reaction. In this case, n = 2 since two electrons are involved in the overall reaction.

Substituting the values:

1.3351 V = (0.0592 V/2) * log(K)

Simplifying:

2.6702 = 0.0296 * log(K)

Taking the antilogarithm:

K = antilog(2.6702/0.0296)

K = antilog(90.203)

K ≈ 3.55 x 10^39

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Answer: There are 14.152 molecules in 42.3 g sample of water, \(H_{2}O\).

Explanation:

According to the mole concept, 1 mole of every substance contains \(6.022 \times 10^{23}\) atoms.

As mass of water (molar mass = 18 g/mol) is given as 42.3 g. Therefore, moles of water are as follows.

\(No. of moles = \frac{mass}{molar mass}\\= \frac{42.3 g}{18 g/mol}\\= 2.35 mol\)

Hence, molecules of water are calculated as follows.

\(2.35 \times 6.022 \times 10^{23} molecules\\= 14.152 molecules\)

Thus, we can conclude that there are 14.152 molecules in 42.3 g sample of water, \(H_{2}O\).