The sound is most likely an approximant.
The spectrogram reading shows a segment, which is a formant-like bar centered around 140 Hz.
That means it is a smooth airflow, having a relatively stable frequency. Therefore, we can say that is an approximant, which is a consonant sound that is produced by bringing two articulators close together but not to the point of complete closure, resulting in a smooth airflow.
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Find the terminal velocity of a sphere that has a mass of 600g and a radius of 30cm. Take the density of air 1.2 kg/m^3 . Report the speed in mph.
The terminal velocity of the sphere is approximately 22.68 mph.
The terminal velocity of a sphere is the constant speed at which the gravitational force pulling the sphere down is balanced by the drag force pushing the sphere up. The drag force is proportional to the velocity of the sphere, and can be calculated using the following formula:
Fd = (1/2) * rho * Cd * A * v²
where Fd is the drag force, rho is the density of the fluid (air in this case), Cd is the drag coefficient (which depends on the shape of the object), A is the cross-sectional area of the object perpendicular to the direction of motion, and v is the velocity of the object.
The gravitational force pulling the sphere down is given by:
Fg = m * g
where m is the mass of the sphere and g is the acceleration due to gravity.
At terminal velocity, the drag force is equal in magnitude to the gravitational force, so:
Fd = Fg
Substituting the expressions for Fd and Fg and solving for v, we get:
v = √((2 * m * g) / (rho * Cd * A))
where A = pi * r² is the cross-sectional area of the sphere, and r is the radius of the sphere.
Plugging in the given values, we get:
v = sqrt((2 * 0.6 * 9.81) / (1.2 * 0.47 * pi * 0.3²)) ≈ 10.13 m/s
To convert this to mph, we multiply by 2.23694:
v ≈ 22.68 mph
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7. A particle of mass 3 kg is held in equilibrium by two light unextensible strings. One string is horizontal, as shown in Figure 7.30. The tension in the horizontal string is PN and the tension in the other string is N. Find a) the value of 0 b) the value of P.
The tension in the strings are 31.47 and 19.25 N respectively.
Mass of the block, m = 3 kg
From the figure, consider the vertical components,
T₁ sin45° + T₂ sin30° = mg
(T₁/√2) + (T₂/2) = 3 x 9.8 = 29.4
Also, consider the horizontal components,
T₁ cos45° = T₂ cos30°
T₁/√2 = T₂ x√3/2
T₁ = T₂ x √3/2 x √2
So,
T₁ = 0.612T₂
Applying in the first equation,
(T₁/√2) + (T₂/2) = 29.4
(0.612T₂/1.414) + 0.5T₂ = 29.4
0.434 T₂ + 0.5 T₂ = 29.4
0.934 T₂ = 29.4
Therefore, the tension,
T₂ = 29.4/0.934
T₂ = 31.47 N
So, the tension,
T₁ = 0.612 T₂
T₁ = 0.612 x 31.47
T₁ = 19.25 N
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If the average hang time of a professional football kick is 4.4s, then determine the average maximum height.
The average highest height of a professional football kick is 189.728 m if the hang time is 4.4 seconds on average.
What is meant by hang time?A person or an object's total duration in the air after leaving the ground is known as their "hang time." From the time anything leaves the ground until it returns, it is measured.
We know,
y= gt²
Here,
y = Average maximum height
g = acceleration due to gravity
t = Average hang time
Given,
Average hang time (t) = 4.4s
Acceleration due to gravity (g) = 9.8 m/s² (assuming)
Inserting these values in the given equation,
y = gt²
= 9.8×4.4×4.4
= 189.728 m.
Hence, the average maximum height of the football is 189.728 m.
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A resistor is submerged in an insulated container of water. A voltage of 12 V is applied to the resistor resulting in a current of 1.2 A. If this voltage and current are maintained for 5 minutes, how much electrical energy is dissipated by the resistor
Explanation:
Given:
\(\Delta t = 5\:\text{min} = 300\:\text{s}\)
\(V = 12 V\)
\(I = 1.2 A\)
Recall that power P is given by
\(P = VI\)
so the amount of energy dissipated \(\Delta E\) is given by
\(\Delta E = VI\Delta t = (12\:\text{V})(1.2\:\text{A})(300\:\text{s})\)
\(\:\:\:\:\:\:\:= 4320\:\text{W} = 4.32\:\text{kW}\)
Estimate the net force needed to accelerate a 1000-kg car at 3m/s/s from rest.
FILL IN THE BLANKS.
If this force acts on this car for 4 seconds, then the car will increase its speed by ————————- m/s a second each second reaching a final speed of ————————- m/s. The distance traveled during this motion is ——————- meters.
Answer:
First Blank. 30,000
Second Blank. 12,000
Third Blank. 20.0
Explanation:
a lens with f = 50.0 cm is held 55.0 cm from an object. what is the image distance? (unit = cm)
Answer: 550 cm
Explanation:
Original equation: 1/f= 1/do + 1/di.
F=50.0 cm, and do=55.0.
Since we don't have di, we'll have to subtract do to the other side, making the equation: 1/f - 1/do= 1/di.
Doing the math, 1/f - 1/do is 0.0018181818
Then to get di by itself, you multiply both sides by di. Then you divide by 0.0018181818 to get di by itself. You then get: di= 1/0.0018181818
At that point, you just divide 1 by 0.0018181818, which will give you 550 cm
There could be simpler way, but that is just what I did to get the answer. Answer was right on Acellus
If the concentration of the reactants in a chemical reaction is increased, the rate of the
reaction usually
a. decreases.
B. increases.
C. remains the same.
Answer:
B. increases.
Explanation:
When the concentration of the reactants in a chemical reaction is increased, the rate of the reaction usually increases. This is because increasing the concentration of the reactants increases the number of collisions between reactant molecules, which increases the likelihood of a successful collision that leads to a reaction. This is known as the collision theory of chemical reactions.
Question 3. A wire 25.0cm long lies along the z-axis and carries a current of 9.00A in the +z-direction. The a magnetic field is uniform and has components Bx = -0.242T, By= -0.985, and B2=-0.336. a. Find the components of the magnetic force on the wire? b. What is the magnitude of the net magnetic force on the wire?
a.
The components of the force are Fx = 2.2163 N, Fy = -0.5445 N and Fz = 0 N
The force on a current carrying conductor in a magnetic field is given by F = iL × B where i = current = 9.00 A, L = 25.0 cmk = 0.25 mk (since the conductor is along the z-direction). B = magnetic field. Since B has component Bx = -0.242T, By= -0.985, and Bz = -0.336, B = -0.242i + (-0.985j) + (-0.336)k = -0.242i - 0.985j - 0.336)k.
So, F = iL × B
F = 9.00 A{(0.25 m)k × [-0.242Ti + (-0.985Tj) + (-0.336T)k]T}
F = 9.00 A{(0.25 m)k × (-0.242T)i + (0.25 m)k × (-0.985Tj) + (0.25 m)k × (-0.336T)k]}
F = 9.00 A{-0.0605mT)k × i + (-0.24625 mT)k × j + (-0.084 m)k × k]}
F = 9.00 A{-0.0605mT)j + (-0.24625 mT) × -i + (-0.084 mT) × 0]}
F = 9.00 A{-0.0605mT)j + (0.24625 mT)i + 0 mT]}
F = -0.5445 AmT)j + (2.21625 AmT)i + 0 AmT]}
F = -0.5445j + 2.21625i + 0 k
F = (2.2163i - 0.5445j + 0 k) N
So, the components of the force are Fx = 2.2163 N, Fy = -0.5445 N and Fz = 0 N
b.
The magnitude of the net force on the wire is 2.282 N
The net force F = √(Fx² + Fy² + Fz²)
F = √[(2.2163 N)² + (-0.5445 N)² + (0 N)²)
F = √[(4.912 N)² + 0.2964 N)² + (0 N)²)
F = √[5.2084 N)²
F = 2.2822 N
F ≅ 2.282 N
So, the magnitude of the net force on the wire is 2.282 N
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Cold water ~
has the highest density at what temperature.. ?
Answer:
The maximum density of water occurs at around 4° Celsius. The density of ice is less than liquid water, so it floats. Upon freezing, the ice density decreases by about 9%.
Explanation:
thanks for the question
If an object is accelerating at a rate of 8 m/s^2 what is the mass of the box.
See attached
Answer:
50 kg
Explanation:
fnet=ma
600-200=m8
divide both side by 8 to make m the subject of the formula Thus m=50kg
A man runs 300 m west in 60 seconds. He then runs 100m north-west in 20 seconds. What is his average velocity in meter per second?
Answer:
See below
Explanation:
Total distance = 300 + 100 = 400 meters in 60 + 20 = 80 seconds
400 m / 80 s = 5 m/s
If you are using DISPLACEMENT:
displacement = sqrt ( ( 300 + 100 cos 45)^2 + (100sin 45)^2 ) = 377.4 m
in 80 seconds 377.4 / 80 = 4.7 m/s
On which planet would you be able to jump the highest on and which planet would jump the lowest? Explain
From the mass of the given planets, let's determine the planet where you would be able to jumpp the highest on and the lanet you would jump the lowest.
The lower the mass of the planet, the lower the level of gravity, the higher the mass of the planet the higher the force of gravity will be.
Therefore, the planet with the lowest mass will be the planet you would be able to jump highest on while the lanet with the greatest mass will be the planet you would jump the lowest.
Therefore, we have from the list:
Planet with the lowest mass = Mercury = 3.301 x 10²³ kg
Therefore, Mercury is the planet you would be able to jump the highest
Planet with the greatest mass = Jupiter = 1.899 x 10²⁷ kg.
Jupiter is the planet you will jump the lowest.
ANSWER:
Planet you will jump the highest = Mercury
Planet you will jump the lowest = Jupiter.
Each of the four expansion models (recollapsing, critical, coasting, and accelerating) predict different ages for the universe, given the current expansion rate. Why is this
Answer:
This is because the age of the universe is determined by the pace of expansion in the past, and each model forecasts a different pace.
Explanation:
The age of the universe is determined by the pace of expansion in the past, and each model forecasts a different pace.
This is due to the fact that the expansion rate in the coasting model is constant and never changes. Because the cosmos is growing faster now than during the old days, recollapsing and critical models give shorter ages. According to the accelerating model, the universe is growing at a slower rate currently than in the past, implying an older age.
What is energy anything that takes up space and has mass a change in the position of an object a push or pull the ability to cause change in matter
Energy is that which has the ability to cause change in matter.
What is energy?Energy is the quantitative property that is transferred to a body or to a physical system, recognizable in the performance of work and in the form of heat and light. Energy is a conserved quantity—the law of conservation of energy states that energy can be converted in form, but not created or destroyed.
So in simple definition we can say that energy is that which has the ability to cause change in matter.
Based on the given statements we can classify them as;
anything that takes up space and has mass - matter.cause a change in the position of an object through push or pull - forcethe ability to cause change in matter - energy.Learn more about energy here: https://brainly.com/question/13881533
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A motorcycle is driven horizontally straight off a 22-m tall cliff with a speed of 65
m/s. How far from the base of the cliff will the motorcycle land?
Answer:
137.8 m
Explanation:
The following data were obtained from the question:
Height (h) = 22 m
Initial velocity (u) = 65 m/s
Horizontal distance (s) =.?
Next, we shall determine the time taken for the motorcycle to get to the ground. This can be obtained as follow:
Height (h) = 22 m
Acceleration due to gravity (g) = 9.8 m/s²
Time (t) =?
h = ½gt²
22 = ½ × 9.8 × t²
22 = 4.9 × t²
Divide both side by 4.9
t² = 22/4.9
Take the square root of both side.
t = √(22/4.9)
t = 2.12 s
Finally, we shall determine the horizontal distance travelled by the motorcycle. This is illustrated below:
Initial velocity (u) = 65 m/s
Time (t) = 2.12 s
Horizontal distance (s) =.?
s = ut
s = 65 × 2.12
s = 137.8 m
Thus, the motorcycle will land at 137.8 m away from the cliff
One ball is dropped at rest from a height of h = 65 m. At the same time, another ball is thrown upward from the ground with initial velocity v2 = 25 m/s. It takes Δt time for them to meet on the way. Defining the positive direction going upward, what is the acceleration of the two balls, a in m/s2?
If one ball is dropped at rest from a height of h = 65 m. The acceleration of the two balls is: -9.8 m/s^2 for both balls.
How to find the acceleration?Let's start by finding the time it takes for the two balls to meet. We know that the ball thrown upward starts from rest, so its initial velocity is 0 m/s. We can use the following kinematic equation:
y = v_i*t + (1/2)at^2
where y is the displacement (in this case, it is the distance between the two balls), v_i is the initial velocity, a is the acceleration, and t is the time. We can set y equal to the initial height of the dropped ball, which is h = 65 m. For the ball thrown upward, the initial position is y = 0.
For the dropped ball:
y = h = 65 m
v_i = 0 m/s
For the ball thrown upward:
y = 0
v_i = 0 m/s
Using the given information, we can solve for t:
h = (1/2)at^2
65 m = (1/2)*(-9.8 m/s^2)t^2
t = sqrt(65 m / (1/2(-9.8 m/s^2))) ≈ 3.64 s
So it takes about 3.64 seconds for the two balls to meet.
Now, we can find the acceleration of the two balls. For the dropped ball, the acceleration is simply the acceleration due to gravity, which is -9.8 m/s^2. For the ball thrown upward, the acceleration is also the acceleration due to gravity, but with a negative sign since it is moving in the opposite direction of gravity. Therefore, the acceleration of the two balls is:
a = -9.8 m/s^2 for both balls
This means that both balls experience the same acceleration due to gravity, regardless of their initial velocities.
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What is the wavelength of a wave that has a speed of 160 m/s and a period of 3.7 ms?
Answer:
160m/s
Explanation:
The speed of a wave is related to its frequency and wavelength, according to this equation:
v=f ×λ
A space station in the form of a large wheel,
356 m in diameter, rotates to provide an “artificial gravity” of 5.1 m/s2 for people
located at the outer rim.
What is the frequency of the rotational mo-
tion for the wheel to produce this effect? Answer in units of rev/min.
The frequency of the rotational motion for the wheel to produce this effect 1.62 rev/min.
What is the angular speed of the wheel?
The angular speed of the wheel is calculated by applying the formula for centripetal acceleration of the wheel.
a = v²/r = ω²r
where;
ω is the angular speed of the wheel in radian per secondsr is the radius of the wheelThe radius of the wheel = 356 m / 2 = 178 m
ω = √a/r
ω = √(5.1/178)
ω = 0.17 rad/s
The angular speed in revolution per minute is calculated as follows;
ω = 0.17 rad/s x 1 rev/2π rad x 60 s/1min
ω = 1.62 rev/min
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A 3kg cat falls out of a window that is 10m above the ground and lands
safely in the grass. Calculate the velocity at which the cat hit the ground.
Answer:
p = 30 kg·m/s
Explanation:
Sally puts on wool socks and rubs her feet on a nylon carpet. How does static electricity build up in Sally?
O When electrons from the wool socks move into the carpet, Sally and her socks gain a negative charge.
O The friction causes electrons from the wool socks to move to Sally, giving Sally a negative charge.
O Electrons from the wool socks move into the carpet, giving Sally and her socks a positive charge.
Electrons from the carpet move into the wool socks, giving Sally and her socks a positive charge.
When Sally puts on wool socks and rubs her feet on a nylon carpet, static electricity builds up through a process involving the movement of electrons. The friction between the wool socks and the nylon carpet causes electrons from the wool socks to move to the carpet, resulting in Sally and her socks gaining a negative charge.
The correct answer would be the friction causes electrons from the wool socks to move to Sally, giving Sally a negative charge.
The friction between the wool socks and the nylon carpet causes electrons from the wool socks to move to the carpet, resulting in Sally and her socks gaining a negative charge. This is due to the phenomenon known as the triboelectric effect.
The triboelectric effect occurs when two materials come into contact and then separate. During the rubbing process, the atoms in the two materials interact, causing the transfer of electrons between them. In this case, the wool socks have a greater affinity for electrons compared to the nylon carpet. As a result, electrons from the socks are transferred to the carpet, leaving the socks with a positive charge and the carpet with a negative charge.
Sally, wearing the wool socks, experiences an accumulation of excess electrons on her feet, giving her a negative charge. This excess negative charge on her body can lead to static electricity-related phenomena, such as experiencing a shock when touching a metal object or seeing her hair stand on end when near certain surfaces.
It's important to note that the movement of electrons determines the charge distribution during the triboelectric effect. In this scenario, electrons move from the wool socks to the nylon carpet, resulting in Sally and her socks gaining a negative charge.
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You preform an experiment to measure the speed of a car overtime. the data are shown in the table below. What graph shows the data from this experiment?
Answer:
C
Explanation:
Check for coordinates of the VT graph in C part. The information matches with the table.
At what distance will a 80 W lightbulb have the same apparent brightness as a 120 W bulb viewed from a distance of 40 m
Answer:
32.6mm
Explanation:
Using area of a sphere(bulb) = 4πr²
So A is proportional to radius²
So the Energy will be proportional to r²
But 120/80 = 1.5 is the energy factor so
Using
1.5/d² = 1/r²
1.5/40²= 1/r^2
r = √( 40²/ 1.5)
r = 32.6m
a heater has a power of 2500W. The heater is turned on for 180 seconds. Calculate the energy transferred by the heater
The energy transferred by the heater that has a power of 2500W and is turned on for 180s is 450,000J.
How to calculate energy?Electrical energy is the energy made available for consumption or consumed in the form of electricity or electric power.
Electrical energy can be calculated as follows:
Electrical energy = Power x Time.
The total amount of electrical energy used depends on the total power used by all electrical devices and the total time they are used in the home.
According to this question, a heater has a power of 2500W and is turned on for 180 seconds. The energy can be calculated as follows;
E = 2500W × 180s
E = 450,000J
Therefore, 450,000J is the energy transferred to the heater.
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problem 1
A train starts at rest, accelerates with constant acceleration a for 5minutes,then travels at constant speed for another 5minutes,and the decelerates with a.suppose it travels a distance of 10km in all find a
problem 2
A ball is dropped from a height of 10m.At the same time, another ball is thrown vertically upwards at an initial speed of 10m/sec.How high above the ground will the two balls collide
problem 3
find the resultant of the two velocity vectors and also, find the angle that the resultant makes with the vector
The constant acceleration of the train is 50/9 m/s².
The two balls will collide at a height of approximately 10.204 meters above the ground.
How to calculate the valueUsing the kinematic equations of motion, we have:
distance = initial velocity * time + 1/2 * acceleration * time^2
For the first phase of acceleration, the initial velocity is zero, the time is 5 minutes = 300 seconds, and the distance traveled is unknown. So we have:
d1 = 0 + 1/2 * a * (300)^2
For the second phase of constant speed, the initial velocity is v, the time is 5 minutes = 300 seconds, and the distance traveled is also unknown. So we have:
d2 = v * 300
For the third phase of deceleration, the initial velocity is v, the time is also 5 minutes = 300 seconds, and the distance traveled is again unknown. So we have:
d3 = v * 300 + 1/2 * (-a) * (300)^2
The total distance traveled is the sum of these three distances:
distance = d1 + d2 + d3 = 1/2 * a * (300)^2 + v * 600 - 1/2 * a * (300)^2 = v * 600
Since the total distance traveled is given as 10 km = 10000 m, we have:
v * 600 = 10000
Solving for v, we get:
v = 10000/600 = 50/3 m/s
Now we can use the second equation above to find a:
d2 = v * 300 = (50/3) * 300 = 5000 m
Therefore, the constant acceleration of the train is:
a = 2 * (5000 - 1/2 * a * (300)^2) / (300)^2 = 50/9 m/s^2
The constant acceleration of the train is 50/9 m/s^2.
Problem 2: The height of the first ball dropped is given as 10m. Let's assume the height of the collision point is h meters above the ground.
Using the kinematic equation for free fall, we have:
h = 10 + 1/2 * g * t^2
where g is the acceleration due to gravity, which is approximately 9.81 m/s^2, and t is the time it takes for the second ball to reach the collision point after being thrown upwards.
The initial upward velocity of the second ball is 10 m/s, and we know that at the collision point, its velocity will be zero, since it will have reached its maximum height and will be momentarily at rest before falling back down.
Using the kinematic equation for motion with constant acceleration, we have:
0 = 10 + (-g) * t
Solving for t, we get:
t = 10/g = 10/9.81 seconds
Substituting this value of t into the first equation, we get:
h = 10 + 1/2 * 9.81 * (10/9.81)^2
Simplifying, we get:
h = 10.204 m
The two balls will collide at a height of approximately 10.204 meters above the ground.
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two positive charges are placed in a vacuum.The coulomb force between the two charges is 3N.On sliding an insulator between these charges,coulomb force is reduced to 1.5N.Find the relative permitivity of this particular insulator.
The relative permittivity of the insulator is εr = 1 / 2 = 0.5.
What is the relative permitivity of this particular insulator?The relative permittivity of the insulator is calculated by applying the equation for the Coulomb force.
F = (kq²) / r²
where;
k is the electrostatic constant q is the magnitudes of the chargesr is the distance between the charges.The initial force equation becomes;
3 = (kq²) / r²
Let's denote the relative permittivity as εr.
The new force equation becomes;
1.5 = (kq² x εr) / r²
Divide the two force equations;
(3 / 1.5) = (kq²) / (kq² x εr)
2 = 1 / εr
εr = 1/2 = 0.5
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How much force must be applied to push a 1.35 kg book across the desk at constant speed if the coefficient of sliding friction is 0.30?
The magnitude of the force that must be applied to push the book across the desk is 3.97 N.
The given parameters;
mass, m = 1.35 kgcoefficient of friction, μ = 0.3The acceleration of the book across the desk is calculated as follows;
a = μg
where;
g is acceleration due to gravitya = 0.3 x 9.8
a = 2.94 m/s²
The magnitude of the force that must be applied is calculated as follows;
F = ma
F = 1.35 x 2.94
F = 3.97 N
Thus, the magnitude of the force that must be applied to push the book across the desk is 3.97 N.
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How many times more acidic is solution A with a pH of 3.4 than solution B with a pH of 8.4?
Solution A is _________ times more acidic than solution B.
(Use scientific notation. Use the multiplication symbol in the math palette as needed. Round to the nearest tenth as needed.)
Answer:
Solution A is 1 x 10⁵ times more acidic than solution B
Explanation:
The pH scale is a logarithmic scale used to express the acidity or basicity of a solution.
The values are written from 1 - 14 with 1 being the most acidic and 14 a basic solution.
Each interval is ten folds more concentrated than the next because it is a logarithmic scale.
Since the pH of A = 3.4
pH of B = 8.4
The difference = 8.4 - 3.4 = 5.0
So, Solution A is 1 x 10⁵ times more acidic than solution B
At what speed does light travel through water. n=1.33
Answer:
"In water, the speed of light is v01.33=2.26 x 108 m/s."
Explanation:
A 2.50 kg ball moving at 7.50 m/s is caught by a 70.0 kg man while the man is standing on ice. How
fast will the man / ball combination be moving after the ball is caught by the man?
Explanation:(2.5kg) (7.5) m/s +70 kg(0) =(2.5kg +70 kg (v3) 18. 75 =72.5 =v3
v3=.26m/s 2.5+70
The diagram below shows the velocity vectors for two cars that are moving
relative to each other.
45 m/s west
25 m/s east
Car 1.
Car 2
From the frame of reference of car 2, what is the velocity of car 1?
OA. 70 m/s east
B. 20 m/s west
OC. 70 m/s west
OD. 20 m/s east
SUBMIT
The velocity of the car 1 can be seen from the calculation as 20 m/s West
What is relative motion?
A coordinate system or point of view used to observe motion is known as a frame of reference. It can be used as a guide when describing an object's position, speed, and acceleration. Different frames of reference may result in various motion observations.
The relative velocity is the velocity of an object or observer as observed from a particular frame of reference.
We can see that the velocity of the car 1 is;
45 m/s - 25 m/s
= 20 m/s West
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