Answer:
speed = 40 m/s
Explanation:
speed = frequency x wavelength
speed = 10 Hz x 4 m
speed = 40 m/s
Squared. (13-59 mod.) Four identical stars of mass M form a square that rotates around the square's center as the stars move in a common circle about that center. The square has edge length L. What is
The squared quantity is 4(2L/π)².
To calculate the quantity you're asking for, we'll first determine the distance of each star from the center of rotation. Let's assume the stars are labeled as A, B, C, and D.
The center of the square is equidistant from all four stars. Let's denote this distance as R.
Since the stars are arranged at the corners of a square, the diagonal of the square is twice the distance from a corner to the center. Therefore, the diagonal of the square has a length of 2R.
Now, let's consider the diagonal of the square as the diameter of the circle in which the stars move. The circumference of a circle is given by the formula:
C = 2πr
where C is the circumference and r is the radius of the circle.
In this case, the circumference of the circle is equal to the perimeter of the square, which is 4L. Therefore:
2πR = 4L
R = 2L/π
Now, to calculate the squared quantity you're interested in, we can find the sum of the squares of the distances of the stars from the center:
Sum = (Distance of star A)² + (Distance of star B)² + (Distance of star C)² + (Distance of star D)²
Since all four stars are equidistant from the center, we can calculate the sum as:
Sum = 4R²
Substituting the value of R we found earlier:
Sum = 4(2L/π)²
Therefore, the squared quantity you're looking for is 4(2L/π)².
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The roof on a shed is a square-based pyramid. if the base has a side length of 10 feet and the slant height of the roof is 9.4 feet, find the area of the roof.
If the base has a side length of 10 feet and the slant height of the roof is 9.4, then the area of the roof is 159.2 square feet.
To find the area of the roof, we need to determine the area of each of the four triangular faces.
We know that the base of each triangle is 10 feet, and the slant height is 9.4 feet. To find the height of the triangle, we can use the Pythagorean theorem:
h = √(slant height^2 - base length^2/4)
h = √(9.4^2 - 10^2/4)
h = √(88.36 - 25)
h = √63.36
h = 7.96 feet
Now that we know the height of the triangle, we can find the area of each face:
Area of one face = 1/2(base x height)
Area of one face = 1/2(10 x 7.96)
Area of one face = 39.8 square feet
Since there are four faces, the total area of the roof is:
Total area = 4 x 39.8
Total area = 159.2 square feet
Therefore, the area of the roof is 159.2 square feet.
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I flick the rope to create a wave with a frequency of 2 Hz and a
wavelength of 6 m.
• How fast does the wave travel down the rope?
• What is the new wavelength?
• What is the wave speed?
Answer: 1. 12 MPH 2. 36m 3. 8 Hz
Explanation:
Answer:
1. 12 MPH 2. 36m 3. 8 Hz
Explanation:
For #1, I multiplied 6 by 2, For #2 I multiplied 6 by 6 and for #3 it's 8 x 2
the value for ψ in root tissue was found to be -0.15 mpa. if you take the root tissue and place it in a 0.1 m solution of sucrose (ψ = -0.23 mpa), the net water flow would
The evaluated net water flow is 0.08 MPa under the context that 0.15 mpa is selected as the root tissue and placed it in a 0.1 m solution of sucrose ψ = -0.23 mpa.
Then water potential of root tissue = -0.15 MPa, now that of a 0.1 M solution of sucrose = -0.23 MPa. Then water potential gradient is
Δψ = ψ1 - ψ2
here
Δψ = water potential gradient,
ψ1 = water potential of root tissue
ψ2 = water potential of a 0.1 M solution of sucrose
Staging the values in the formula
Δψ = (-0.15) - (-0.23)
Δψ = 0.08 MPa
Hence, the level of sucrose solution has a lower in comparison to water potential present in the root tissue, therefore water will flow from the sucrose solution into the root tissue.
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Calculate the potential difference across a 25-Ohm. resistor if a 0.3-A current is flowing through it.
Answer:
I=0.3 A
R=25 Ohm
V=?
V=IR
0.3X25=7.5
Answer:
7.5 V
Explanation:
current × resistance = voltage
dhe ti sera
SM TOM
ORAL, cu
fut-ve, ne E
3:13
dingin Sub
5 ton as watinga
testant of town
Answer:
what does it mean
Explanation:
How can I help with your question?
Answer all questions in the spaces provided. Kalpana finds a small stone. To help her identify the type of stone, Kalpana decides to find its density. Kalpana explains why she thinks this will help. Her friend Diana disagrees. Below are their explanations. Kaplana The density will be the same, whatever the size of the stone, as long as the type of rock is the same. Bigger stones will have a higher density because they are heavier. Diana (a) Whom do you think gave the correct explanation? Give a reason. (2 marks) ******
I believe Kalpana gave the correct explanation.
The reason is that density is a property of a material that remains the same regardless of the size of the sample. Density is defined as mass divided by volume (density = mass/volume), and it is a characteristic property of a particular type of rock.
Bigger stones will indeed be heavier, but their volume will also increase proportionally, maintaining the same density value. So, the density will be the same for any size of the stone, as long as the type of rock is the same.
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complete question not found in search engine.
on the psychrometric chart, a cooling and dehumidification process appears as a line that is a.diagonal downwards to the left (sw direction)
b.Vertical downward c.Diagonal upwards to the left (NW direction) d.Horizontal to the left e.Diagonal downwards to the left (SW direction)
On the psychrometric chart, a cooling and dehumidification process appears as a line that is diagonal downwards to the left (southwest direction) .
A cooling and dehumidification process typically involves reducing the temperature and removing moisture from the air. This can be achieved through various methods such as cooling coils, condensation, or desiccants. On the psychrometric chart, the process is represented by a line that shows a decrease in both the dry-bulb temperature and the specific humidity (moisture content) of the air.
A diagonal downwards to the left (southwest direction) line on the psychrometric chart indicates a simultaneous decrease in both temperature and specific humidity. As the air is cooled, its moisture-holding capacity decreases, causing the moisture to condense or precipitate out. This results in a reduction in both temperature and humidity along the line.
Therefore, option e, diagonal downwards to the left (southwest direction), is the correct representation of a cooling and dehumidification process on the psychrometric chart.
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Three lamps with wattages of 100 watts, 250 watts, and 60 watts, are connected on a circuit. What is the total power consumed by the circuit when all lamps are operating at the rated voltage
The total power consumed by the circuit is 410 watts
Power can be described as the rate at which work is carried out in a body. It can also be described as the movement or transfer of energy from one form to another.
From the question stated above, the total power can be calculated as follows:
P1 + P2 + P3
= 100 + 250 + 60
= 410
Hence the total power in the circuit is 410 watts
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Based on this how many Carbon
Atoms would be on the products
Side
A soccer ball is moving horizontally at a speed of 4.0 m/s. It then undergoes a constant acceleration. After 8.00 s, the ball is moving at 4.8m/s. What is the ball's displacement?
Answer: 0.0 m/s
Explanation
vertical motion with negative velocity and negative acceleration
a)An example of vertical motion with positive velocity and negative acceleration is a ball thrown upwards in the presence of air resistance. b) An example of vertical motion with negative velocity and negative acceleration is a ball thrown downwards with an initial upward velocity.
(a) When a ball is thrown upwards in the presence of air resistance, it experiences a positive initial velocity but a negative acceleration due to the opposing force of air resistance. As the ball moves upward, the force of gravity acts in the downward direction, causing a negative acceleration.
The magnitude of the air resistance increases with velocity, thus creating a negative acceleration that opposes the motion. This combination of positive velocity and negative acceleration leads to a decrease in the ball's upward velocity until it reaches its highest point and begins to fall back down.
The vertical motion of the ball can be described using the following equations:
\(\[v = u - gt\]\)
where \(\(v\)\) is the final velocity, \(\(u\)\) is the initial velocity, \(\(g\)\) is the acceleration due to gravity, and \(\(t\)\) is the time. In this case, \(\(u\)\) is positive (since it is thrown upwards) and \(\(g\)\) is negative (since it acts in the opposite direction of motion).
(b) An example of vertical motion with negative velocity and negative acceleration is a ball thrown downwards with an initial upward velocity. When a ball is thrown upwards and then falls back down, it will have a negative velocity during the downward motion.
Additionally, the acceleration due to gravity is always negative as it acts in the downward direction. Therefore, in this scenario, both the velocity and acceleration are negative.
The equations to describe the motion are the same as in case (a), where \(\(u\)\) would now be negative to represent the initial upward velocity. The acceleration due to gravity \((\(g\))\) remains negative.
The negative velocity and negative acceleration cause the ball to accelerate in the downward direction until it reaches its maximum downward velocity. In both cases, the combination of velocity and acceleration determines the motion of the object in a vertical direction.
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The complete question is:
a) Give an example of a vertical motion with a positive velocity and a negative acceleration. b) Give an example of a vertical motion with a negative velocity and a negative acceleration.
The spring of a dart gun exerts a force on a 0.02 kg dart as it is launched from the gun with 4.00 J of KE. At what velocity does the dart come out of the gun?
Let's see
KE=1/2mv²m is mass and v is velocity
2KE=mv²4(2)=0.02v²8=2v²/1002v²=800v²=400v=20m/sYou have found that tides on earth are determined primarily by the position of the moon, with the sun playing only a secondary role. Why does the moon play a greater role in causing tides than the sun?.
You have found that tides on earth are determined primarily by the position of the moon, with the sun playing only a secondary role. The moon play a greater role in causing tides than the sun, because of the Sun's higher gravitational pull on Earth, the planet revolves around it. Tides, on the other hand, are brought on by variations in the gravitational pull on Earth.
Despite the fact that the gravitational pull between Earth and the Moon is weaker than the attraction between Earth and the Sun, the Moon's considerably closer proximity to Earth causes this attraction to fluctuate more widely throughout the planet.
Because of this, the Sun only has a little secondary effect on tides, which are predominantly caused by the Moon.
Stars are celestial bodies that generate their own energy through the fusing of gases. They resemble bright orbs that burn gas and produce energy. Our solar system's star, the Sun, generates energy through the fusion reaction in which helium transforms into hydrogen.
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The complete question is ''You have found that tides on Earth are determined primarily by the position of the Moon, with the Sun playing only a secondary role. Why does the Moon play a greater role in causing tides than the Sun?- Because the gravitational attraction between Earth and the Moon varies more across Earth than does the gravitational attraction between Earth and the Sun
describe how a chain reaction can be set up if the neutrons produced by one fission
strike other U-235 nuclei
A chain reaction can be set up if the neutrons produced by one fission strike other U-235 nuclei if the three neutrons produced by the fission may hit other nuclei of uranium 235, causing the process to repeat.
What is a Chain reaction?This is referred to as a chemical reaction or other process in which the products themselves promote or spread the reaction.
The products which are yielded initiate further processes of the same kind and in this scenario a chain reaction can be achieved if three neutrons produced by the fission may hit other nuclei of uranium 235 which will lead to a repetition of the process.
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which of the following is not a petroleum product
a. rayon clothing
b. a candle
c. petrochemicals
d. wool
Answer:
wool
Explanation:
Wool comes from sheep. Rayon, candles (the paraffin type) and petrochemicals all come from petroleum.
What is s = vt - 1/2at^2 used for?
Answer:
See below
Explanation:
The position or displacement (s) of a body is given by
the original velocity times time - 1/2 acceleration times time ^2
The minus sign indicates this may be a gravity acceleration (9.81 m/s^2 or 32.2 ft/s^2 ) of a free falling body
THIS equation also indicates that the INITIAL position,s is equal to zero
the full equation is more like this
sf = so + vo t + 1/2 a t^2
sf = final position so = original position vo = original velocity
What would be different about the heat of fusion & vaporization ? and why?
fusion is when solid changes it's state to liquid
and vaporization is when liquid changes it's state to gas
so the difference between fusion and vaporization is the state
What is the speed (mi/min) of a helicopter that traveled 1200 miles in 420 mins?
The distanve travelled is d=1200 miles
Time taken is t=420 miles.
The velocity is
\(v=\frac{1200}{420}=2.85\text{ miles/min}\)The velocity is 2.85 miles/min
A merry-go-round rotates at the rate of
0. 14 rev/s with an 73 kg man standing at
a point 2. 4 m from the axis of rotation.
What is the new angular speed when the
man walks to a point 1 m from the center?
Consider the merry-go-round is a solid 21 kg
cylinder of radius of 2. 4 m.
Answer in units of rad/s
The new angular speed when the man walks to a point 1 m from the center is approximately 2.416 rad/s.
To solve this problem, we can apply the principle of conservation of angular momentum. The angular momentum of the system remains constant when no external torque acts on it. The initial angular momentum of the system is equal to the final angular momentum after the man moves to a new position.
The formula for angular momentum is given by:
L = I * ω
Where:
L is the angular momentum
I is the moment of inertia
ω is the angular velocity
Given:
Initial angular velocity, ω₁ = 0.14 rev/s (convert to rad/s by multiplying by 2π)
Mass of the man, m = 73 kg
Initial distance from the axis, r₁ = 2.4 m
Mass of the merry-go-round (cylinder), M = 21 kg
Radius of the merry-go-round, R = 2.4 m
Final distance from the axis, r₂ = 1 m
First, let's calculate the initial angular momentum (L₁) of the system when the man is standing at a point 2.4 m from the axis:
L₁ = (I_m + I_c) * ω₁
Where:
I_m is the moment of inertia of the man
I_c is the moment of inertia of the merry-go-round (cylinder)
The moment of inertia for a point mass is given by:
I = m * r²
The moment of inertia for a solid cylinder about its central axis is given by:
I = (1/2) * M * R²
Substituting the values:
I_m = m * r₁²
I_c = (1/2) * M * R²
Calculating the initial angular momentum:
L₁ = (m * r₁² + (1/2) * M * R²) * ω₁
Next, let's calculate the final angular momentum (L₂) of the system when the man moves to a point 1 m from the axis:
L₂ = (I_m + I_c) * ω₂
Where:
I_m is the moment of inertia of the man (considering his new position)
I_c is the moment of inertia of the merry-go-round (cylinder)
The moment of inertia for a point mass is given by:
I = m * r²
The moment of inertia for a solid cylinder about its central axis is given by:
I = (1/2) * M * R²
Substituting the values:
I_m = m * r₂²
I_c = (1/2) * M * R²
Now, we need to determine the final angular velocity, ω₂, that makes the final angular momentum equal to the initial angular momentum:
L₂ = (m * r₂² + (1/2) * M * R²) * ω₂
Since angular momentum is conserved, we have:
L₁ = L₂
Therefore, we can equate the two expressions for angular momentum and solve for ω₂:
(m * r₁² + (1/2) * M * R²) * ω₁ = (m * r₂² + (1/2) * M * R²) * ω₂
Now, we can substitute the given values and calculate the final angular velocity (ω₂) in rad/s:
(73 kg * (2.4 m)² + (1/2) * 21 kg * (2.4 m)²) * (0.14 rev/s * 2π rad/rev) = (73 kg * (1 m)² + (1/2) * 21 kg * (2.4 m)²) * ω₂
Simplifying and solving for ω₂:
(1351.2 kg·m²) * (0.14 rev/s * 2π rad/rev) = (73 kg * 1 m² + 25.2 kg·m²) * ω₂
189.1632 kg·m²·rad/s = (73 kg * 1 m² + 25.2 kg·m²) * ω₂
189.1632 kg·m²·rad/s = (73 kg * 1 m² + 25.2 kg·m²) * ω₂
ω₂ = 189.1632 kg·m²·rad/s / (73 kg * 1 m² + 25.2 kg·m²)
ω₂ ≈ 2.416 rad/s
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"What is the change in angular speed when a man walks from the center to a point 1 m away, if the initial angular speed is unknown but the final angular speed is approximately 2.416 rad/s?"
Which of the following would cause the greatest increase in the entropy of an iron rod?
Holding the rod against a magnet.
Inserting the rod into molten iron
The rod into molten iron would cause the greatest increase in the entropy of an iron rod. Entropy is a measure of the disorder or randomness in a system. the rod against a magnet because the former would lead to a greater increase in randomness and disorder in the system.
This increases the disorder and randomness in the system, leading to an increase in entropy. On the other hand, holding the rod against a magnet would not cause a significant increase in entropy because the molecules in the rod would still be in a relatively ordered state. The magnetic field of the magnet would cause the electrons in the rod to align in a particular direction, but this alignment would not lead to a significant increase in disorder. In summary, inserting the rod into molten iron would cause a greater increase in entropy compared to holding the rod against a magnet because the former would lead to a greater increase in randomness and disorder in the system.
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A vector has components A x = 7.6 m and A y = 15.9 m. What is the angle (in degrees that vector makes with the x-axis?
Answer:
θ = 64.5º
Explanation:
To find the angles of a vector with respect to some axis of a coordinate system, the tangent function is used.
tan θ = \(\frac{y}{x}\)
where y is the opposite leg and x is the adjacent leg
in this case the angle is
θ = tan⁻¹ \(\frac{A_y}{A_x}\)
let's calculate
θ = tan⁻¹ \(\frac{15.9}{ 7.6}\)
θ = tan⁻¹ 2.09
θ = 64.5º
this angle is with respect to the positive pâté of the x axis
Somebody plz answer both these questions correclty thanks!!!!!
(WILL MARK BRAINLIEST) promise :)
:D
Answer:
Which questions do you need help on?
When studying atoms, scientists can ignore the ______ force between charged particles that make up the atoms because it is many millions of times smaller than other forces in the atom. Gravitational Constant Normal Fricitional
Answer:
A) Gravitational
Explanation:
Correct on Edge 2021 Test
When studying atoms, scientists can ignore the gravitational force between charged particles that make up the atoms because it is many millions of times smaller than other forces in the atom.
What is gravitational force?The gravitational force is a type of force has ability to attract any two objects with mass. Gravitational force tries to pull two masses towards each other .
Electric force is the force on the particle is defined as the application of the force field of one particle on another particle. It is a type of virtual force.
When studying atoms, scientists can ignore the gravitational force between charged particles that make up the atoms because it is many millions of times smaller than other forces in the atom.
Hence, gravitational is the correct option for the blank.
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Explain how the unbalanced force acting on a cyclist changes as
they accelerate and they are cycling at a constant speed
As a result, a constant speed means that there are equal and opposite forces acting on it. The phrase "consistent speed and direction" is preferable.
How can an unbalanced force alter an object's speed?Because of unequal power or strength delivered to one side of an item, an imbalanced force causes a change in motion, speed, direction, or movements. In the situation of unbalanced forces, one side has more energy than the other, despite the fact that opposing sides have forces working against them.
How is the bicycle being affected by an unbalanced force?The force of friction generated by a bicycle's tyres against the road is larger than the force of friction generated by the air in opposition. The bicycle advances.
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What is the average force of gravitation between Mars and the Sun?
\(1.65 * 10^2^1 N\) is the average force of gravitation between Mars and the Sun. So, the correct option is C.
What is the Gravitational force?Gravitational force is defined as the fundamental interaction which causes mutual attraction between all things that have mass or energy.
The magnitude of the gravitational force between two objects is given by the equation:
\(F=G\frac{m_1m_2}{r^2}\)
where,
\(G= 6.67* 10^-^1^1 m^3 kg^-^1 s^-^2\) is the gravitational constant
\(m_1, m_2\) are the masses of the two objects
r is the separation between them
For the above given information,
\(m_1= 1.99* 10^3^0 kg\) is the mass of the Sun
\(m_2= 6.39* 10^2^3 kg\) is the mass of Mars
\(r= 229* 10^6 km = 229* 10^9 m\) is the average distance between the Mars-Sun
By putting the value we can find the gravitational force:
\(F= (6.67 * 10^-^1^1)\frac{(1.99* 10^3^0) (6.39* 10^2^3)}{(2.29*10^9)^2}\)
\(F= 1.62* 10^2^1 N\)
Thus, \(1.65 * 10^2^1 N\) is the average force of gravitation between Mars and the Sun. So, the correct option is C.
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Your question is incomplete, most probably the complete question is:
What is the gravitational force between Mars and the sun?
\(7.43 * 10^3^0 N\)\(1.79 * 10^2^6 N\)\(1.65 * 10^2^1 N\)\(3.76 * 10^3^2 N\)It is possible for a fault to have a N-S strike and an East dip False True
True, it is possible for a fault to have a north-south (N-S) strike and an eastward dip.
Faults can have various orientations and dips depending on the tectonic forces and geological conditions in a particular region. The strike refers to the direction of the fault line on the Earth's surface, while the dip indicates the angle at which the fault plane is inclined from the horizontal. Therefore, a fault can have any combination of strike and dip, including an N-S strike and an eastward dip.
Faults are geological fractures where movement has occurred, and their orientations can vary. A fault with a north-south (N-S) strike means it extends in that direction horizontally. The dip refers to the angle of the fault plane from the horizontal. So, it is possible for a fault to have an N-S strike and an eastward dip.
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Formula for conservation of internal kinetic energy (works for elastic collisions) is: ΣKEi=ΣKEf (use 1/2mv^2 for each object in the system) TRUE OR FALSE
The given statement "Formula for conservation of internal kinetic energy (works for elastic collisions) is: ΣKEi=ΣKEf (use 1/2mv² for each object in the system)" is TRUE because the initial kinetic energy of the system is equal to the final kinetic energy of the system.
What's the formula for conservation of internal kinetic energyThe formula for conservation of internal kinetic energy states that the initial kinetic energy of a system is equal to the final kinetic energy of the same system in an elastic collision.
This formula can be expressed as ΣKEi=ΣKEf, where ΣKEi is the sum of the initial kinetic energy of all objects in the system, and ΣKEf is the sum of the final kinetic energy of all objects in the system.
In this formula, the mass and velocity of each object in the system are taken into account using the formula 1/2mv² for kinetic energy.
It is important to note that this formula only works for elastic collisions, where there is no loss of kinetic energy due to friction or other forces.
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A group of students were investigating the force of gravity. They began by dropping a foam ball from a height of 3 meters into a bucket of sand. The ball hit the sand in 0.306 seconds. They dropped additional balls of approximately the same diameter, but of different masses. Here is the data they collected. Based on this experiment and the collected data, what would their conclusion be?
A) Gravitational attraction is dependent on the mass of an object.
B) The greater the mass of the object the greater the acceleration due to gravity and the faster it will fall.
C) Mass does not affect the speed of falling objects assuming there is only the force of gravity acting on the objects.
D) Mass becomes a factor affecting the speed of a falling object when the object is dropped a great distance from the surface of the Earth.
Answer:B
Explanation:
The force of gravitation depends on the mass of the object. As the mass increases, the speed of the falling object also increases because it experience more gravitational pull from earth. Thus, option D is correct.
What is gravitational force?Gravitational force is a kind of force by which an object attracts other objects into its center of mass. We are all standing on the ground because of the gravitational pull of earth.
Gravitational force is directly proportional to the mass of the objects and inversely proportional to the distance from the surface. Therefore, the force exerted by earth on massive body is greater than that on a light body.
Here, the ball with greater mass hit the ground with less time compared to the one with less mass. Hence, the mass becomes a factor affecting the speed of a falling object when the object is dropped a great distance from the surface of the earth. Thus, the massive body will be pulled more by earth.
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A student is making some changes to a circuit he built. He connected a battery to a circuit that contained a light bulb. He decided to change the light bulb to a higher resistance, but he wanted to keep the current the same. What will he need to do?
A. Increase the voltage by adding a battery with greater volts.
B. It is impossible to change your resistance and keep the current the same.
C. Keep the same exact set up as he originally made.
D. Decrease the voltage by adding a bigger battery with more volts, so the current an flow the same.
Answer:
B
Explanation:
Makes more sense if you want to keep the current the same>
Answer:
a
Explanation:
thats what i put ithink its wrong tho