Question 20 (1 point)
The chemical formula for glucose, a simple sugar, is CH1206. The formula for ethanol is CzH60. What
accounts for the differences in these compounds?

Explanation:

1) Complete combustion of propane gives carbon dioxide gas and water vapors.

The balanced chemical equation is given as:

\(C_3H_8(g)+5O_2(g)\rightarrow 3CO_2(g)+4H_2O(g)\)

Number of carbon atoms on reactant side = 3

Number of hydrogen atoms on reactant side = 8

Number of oxygen atoms on reactant side = 10

Number of carbon atoms on the product side = 3

Number of hydrogen atoms on the product side = 8

Number of oxygen atoms on the product side = 10

On both the sides numbers, all elements remained the same which indicates that matter remains conserved during the course of a chemical reaction.

2) Incomplete combustion of propane gives carbon dioxide gas, carbon monoxide gas, and water vapors.

The balanced chemical equation is given as:

\(2C_3H_8(g)+9O_2(g)\rightarrow 4CO_2(g)+2CO(g)+8H_2O(g)\)

Number of carbon atoms on reactant side = 6

Number of hydrogen atoms on reactant side = 16

Number of oxygen atoms on reactant side = 18

Number of carbon atoms on the product side = 6

Number of hydrogen atoms on the product side = 16

Number of oxygen atoms on the product side = 18

On both the sides numbers, all elements remained the same which indicates that matter remains conserved during the course of a chemical reaction.

The average atomic mass of this element is 12.0107 amu.Therefore, the average atomic mass of this element is 12.0107 amu.

To find the average atomic mass, we need to take into account the abundance and mass of each isotope. We can use the following formula:

Average atomic mass = (abundance of isotope 1 x mass of isotope 1) + (abundance of isotope 2 x mass of isotope 2)

Plugging in the values given in the question, we get:

Average atomic mass = (0.0107 x 13) + (0.9893 x 12)
Average atomic mass = 0.1391 + 11.8716
Average atomic mass = 12.0107 amu

Therefore, the average atomic mass of this element is 12.0107 amu.

To calculate the average atomic mass of an element with two stable isotopes, you need to multiply the mass of each isotope by its abundance (in decimal form) and then add the results together. Here's the calculation:

Isotope 1: 13 amu * 0.0107 = 0.1391
Isotope 2: 12 amu * 0.9893 = 11.8716

Average atomic mass = 0.1391 + 11.8716 = 12.0107 amu

So, the average atomic mass of this element is 12.0107 amu.

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Answer:

Sources of nitrate that can enter your well include fertilizers, septic systems, animal feedlots, industrial waste, and food processing waste.

Answer:

C

Explanation:

It's the amount of products you get compared to all the reactants you use. It's kind of like economy in that it's profit, and the higher the atom economy the more products/profit you have.

Answer:

C.) The measure of how much of the reactants end up as products in a chemical reaction.

Explanation:

I got it right on founders edtell.

The flask will have the greatest number of collisions per second with the walls of the container is Flask A: CO at 760 torr and 0 °C.

The Collision of the molecules with the wall of the container will be  depend on the pressure. Therefore, the flask with the highest pressure have the greatest no of the collisions. As flask A has the highest pressure of 760 torr, Therefore, the flask A has the greatest number of the collusions per second with the walls of the container.

Thus the flask A with CO gas will have the greatest number of collisions per second with the walls of the container.

This question is incomplete, the complete question is :

Consider three identical flasks filled with different gases.

Flask A: CO at 760 torr and 0 °C

Flask B: N₂ at 250 torr and 0 °C

Flask C: H₂ at 100 torr and 0 °C

which flask will have the greatest number of collisions per second with the walls of the container?

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An oxide of an unknown element r, contains 46. 0 g of r and 16. 0 g of oxygen. If the formula of the metal oxide is r2o, then what is the molar mass of the metal r is 23g.

Given,

 an unknown metal r, contains 46. 0 g of r and 16. 0 g of oxygen.

   which means that the

 weight of oxygen = 16 g

 weight of metal r = 46 g

we have to find the molar mass of metal r..

Now,

  the formula of the compound is r₂O.

which means that the valency of unknown metal is 1.

Now,

  according to the formula of compound,

there is 1 atom of oxygen and 2 atoms of metal r

Hence,

 If in compound there is 16 g of oxygen...

 so ,

2 atoms of compound r weighs 46g

1 atom of r weighs 23g

Hence molar mass of the compound is 23g . And the name of the element is Na i.e Sodium.

Thus, from the above conclusion we can say that, A sample of an oxide of an unknown metal r, contains 46. 0 g of r and 16. 0 g of oxygen. If the formula of the metal oxide is r2o, then what is the molar mass of the metal r is 23g.

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False. For all atoms of the same element, the 2s orbital is not larger than the 1s orbital.

The size or spatial extent of an atomic orbital is primarily determined by its principal quantum number (n). The larger the principal quantum number, the greater the average distance of the electron from the nucleus, resulting in larger orbitals. In this case, the 2s orbital has a larger principal quantum number (n = 2) compared to the 1s orbital (n = 1), which might lead to the misconception that the 2s orbital is larger.

However, in terms of size, the 1s orbital is actually smaller than the 2s orbital. This is because the 1s orbital is closer to the nucleus, experiencing a stronger attraction and resulting in a smaller spatial distribution compared to the 2s orbital. The 2s orbital, being in a higher energy level and having a larger average distance from the nucleus, occupies a larger volume of space.

In summary, the 2s orbital is larger than the 1s orbital in terms of spatial extent and volume.

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Answer:

C: Warm water is denser than cold water

An alkene is formed from a dehydration reaction.

An alkene is formed from a dehydration reaction. Dehydration involves the loss of water from a molecule. In this case, we have compound A as shown in the image attached to this answer.

The dehydration is carried by the use of the reagents pocl3 and pyridine. Let us recall that the dehydration would occur at the point where the HOH would depart. The entire reaction is shown in the image attached.

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The balanced equation for the neutralization of hydrochloric acid with aluminum hydroxide is, 3HCl(aq) + Al(OH)₃(s) → AlCl₃(aq) + 3H₂O(l).

The neutralization reaction between hydrochloric acid (HCl) and aluminum hydroxide (Al(OH)₃) can be represented by the following balanced chemical equation,

3HCl(aq) + Al(OH)₃(s) → AlCl₃(aq) + 3H₂O(l)

In this equation, the hydrochloric acid (HCl) is in the aqueous state (indicated by "(aq)"), meaning it is dissolved in water. The aluminum hydroxide (Al(OH)₃) is in the solid state (indicated by "(s)"). When the acid and base react, they form aluminum chloride (AlCl₃) in the aqueous state and water (H₂O) in the liquid state.

This reaction is an example of a neutralization reaction, where an acid and a base react to form a salt and water. The aluminum hydroxide acts as a base, as it can accept hydrogen ions (H+) from the acid, and neutralize the acid. The resulting solution will have a neutral pH, indicating that the acid has been neutralized.

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Answer : The initial concentration of HI and concentration of HI at equilibrium is, 0.27 M and 0.386 M  respectively.

Solution :  Given,

Initial concentration of H_2 and I_2 = 0.11 M

Concentration of H_2 and I_2 at equilibrium = 0.052 M

Let the initial concentration of HI be, C

The given equilibrium reaction is,

    H_2(g)+I_2(g)\rightleftharpoons 2HI(g)

Initially               0.11   0.11            C

At equilibrium  (0.11-x) (0.11-x)   (C+2x)

As we are given that:

Concentration of H_2 and I_2 at equilibrium = 0.052 M  = (0.11-x)

The expression of K_c will be,

K_c=\frac{[HI]^2}{[H_2][I_2]}

54.3=\frac{(C+2(0.058))^2}{(0.052)\times (0.052)}

By solving the terms, we get:

C = 0.27 M

Thus, initial concentration of HI = C = 0.27 M

Thus, the concentration of HI at equilibrium = (C+2x) = 0.27 + 2(0.058) = 0.386 M

10,000 lbm/hr is the mass flow rate of the stream as a whole. Benzene (C6H6) and toluene are two organic substances that enter a separation column (C7H8).

The correct option is d.

In order to make polystyrene, benzene, a colorless liquid with a distinct odor, is primarily used. It is incredibly toxic, a known carcinogen, and leukemia has been related to exposure to it.

Benzene is a typical chemical used in industry.

internal combustion engines are fuelled by a derived mixture of highly combustible liquid hydrocarbons. The vast bulk of gasoline is used in automobile engines. infrastructure for blending as well as refining petroleum products.

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Atomic number equals the number of protons or electrons. Atomic mass equals the number of protons and neutrons

Answer:

C

Explanation:

35-32 = 3

Answer:

5 feet 5 inches

Explanation:

I ft=12in

? =65in

65/12. =5.5

5feet and 5 inches

Answer:

the answer is liquid.

Explanation:

Answer: 18

Explanation:hope this help

Answer:

7.5 gm left

Explanation:

Bismuth-210 has a half life of 5 days

15 days is 15/5 = 3 half lives

since half the amount is left in 5 days or 1 half life

(1/2) x (1/2) x (1/2) the staring amount would be left in

3 half lives. so 1/8 is left

(1/8) x 60.0 = 7.5 gm left

Answer:

A. 1,4-dimethylbenzene

Explanation:

The compound CH,CH;CH,CH3 is a benzene derivative with two methyl groups attached to the benzene ring. The positions of the methyl groups on the ring are indicated by the numbers 1 and 4, which correspond to the carbon atoms at the end of the two double bonds in the benzene ring. This compound is therefore 1,4-dimethylbenzene. The other options listed are not correct because they contain the wrong number or type of substituents on the benzene ring.

The value of "n" in the hydrate formula CuSO4 * nH2O is 5.

To determine the value of "n," we need to calculate the molar ratio between the released water and the hydrate copper(II) sulfate.

First, we need to convert the mass of water released to moles. The molar mass of water (H2O) is approximately 18.015 g/mol. Therefore, 5.051 g of water is equal to 5.051 g / 18.015 g/mol ≈ 0.2804 mol.

Next, we calculate the molar ratio between water and copper(II) sulfate. The molar mass of copper(II) sulfate (CuSO4) is approximately 159.609 g/mol. From the balanced chemical equation, we know that one mole of copper(II) sulfate is associated with "n" moles of water.

Assuming that the molar ratio is 1:1 between CuSO4 and H2O, we can set up the following equation:

0.2804 mol H2O = 14.00 g CuSO4 * (1 mol H2O / (159.609 g CuSO4 * n))

By rearranging the equation, we can solve for "n":

n = 14.00 g CuSO4 / (159.609 g CuSO4/mol) = 0.0877 mol

Since "n" represents the number of water molecules, it must be a whole number. Therefore, the closest whole number to 0.0877 is 5.

Therefore, the value of "n" in the hydrate formula CuSO4 * nH2O is 5.

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Answer:

The answer is

Explanation:

The density of a substance can be found by using the formula

\(density = \frac{mass}{volume} \\\)

From the question

mass of block = 10 g

volume = final volume of water - initial volume of water

volume = 25 - 20 = 5

volume = 5 mL

The density of the block is

\(density = \frac{10}{5} \\ \)

We have the final answer as

Hope this helps you

Answers

condensed structure:

CH₃(CH₂)₃CH₃

molecular formula:

C₅H₁₂

IUPAC name:

pentane

Answer: Reflectors use a mirror to collect the light, whilst refractors use a lens while, Refractor telescopes require a large lens at the front to direct the incoming light to the lens.

To make an E9 mixture 8657.14 gal of E7 should be mixed with 3000 gal of E10

Given to us is the amount of ethanol in the E10 mixture is 10% of 3000 gallons:

Ethanol in E10 = 10% × 3000 gal = 0.10 × 3000 gal = 300 gal

To solve this problem, we can set up an equation based on the amount of ethanol in each mixture.

Let x represent the amount of E7 mixture (in gallons) that needs to be added to the E10 mixture to obtain the desired E9 mixture.

The amount of ethanol in the E7 mixture is 7% of x gallons:

Ethanol in E7 = 7% ×  gal = 0.07 × gal

The resulting E9 mixture will contain 9% ethanol of the total volume of 3000 + x gallons:

Ethanol in E9 = 9% × (3000 + x) gal = 0.09 × (3000 + x) gal

According to the problem, the resulting E9 mixture contains 906 gallons of ethanol:

Ethanol in E9 = 906 gal

Now we can set up the equation:

Ethanol in E10 + Ethanol in E7 = Ethanol in E9

300 gal + 0.07x gal = 906 gal

Subtracting 300 gal from both sides:

0.07x gal = 606 gal

Dividing both sides by 0.07:

x = 606 gal / 0.07

x = 8657.14

Therefore, approximately 8657.14 gallons of E7 mixture should be mixed with 3000 gallons of E10 to make an E9 mixture.

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Complete question: Ethanol fuel mixtures have "E" numbers that indicate the percentage of ethanol in the mixture by volume. For example, E10 is a mixture of 10% ethanol and 90% gasoline. How much E7 should be mixed with 3000 gal of E10 to make an E9 mixture?

The standard potential for the given galvanic cell is +1.06 V.

To calculate the standard potential for the given galvanic cell, we need to determine the individual reduction potentials of the half-reactions and then subtract the potential of the anode (where oxidation occurs) from the potential of the cathode (where reduction occurs).

Given reduction half-reaction potentials:

Ag+(aq) + e^− → Ag(s): E∘ = +0.80 V

Ni2+(aq) + 2e^− → Ni(s): E∘ = -0.26 V

Since we have the reduction potentials for both half-reactions, we can directly calculate the standard potential for the cell:

E∘(cell) = E∘(cathode) - E∘(anode)

= E∘(Ag+(aq) + e^− → Ag(s)) - E∘(Ni2+(aq) + 2e^− → Ni(s))

E∘(cell) = +0.80 V - (-0.26 V)

= +1.06 V

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Using the masses of reactants and products the balanced chemical equations are:

a)C₃H₈ + 5O₂ ⇒ 3CO₂ + 4H₂O

b) C₂H₅OH  + 3O₂ ⇒ 2CO₂ + 3H₂O

c) C₁₄H₃₀ ⇒ C₇H₁₆ + C₃H₈ + 2C₂H₄(cracking)

Equations are balanced when they have the same number of each element on both the reactant and product sides. Equations need to be balanced in order to express the conservation of mass rule appropriately.

To balance chemical equations, stoichiometric coefficients for the reactants and products are necessary. Because a chemical equation must adhere to the rules of conservation of mass and constant proportions, the reactant and product sides of the equation must have an equal number of atoms of each element.

Long chain hydrocarbons, also known as kerogens, are complex chemical molecules that can be broken down into lighter, simpler molecules by a process called cracking. It results from the dissolution of carbon-carbon bonds. The presence of a catalyst and temperature are two elements that have a significant impact on the catalyst rate.

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