Question 12 of 25 Four different sets of objects contain 4, 5, 6, and 8 objects. How many unique combinations can be formed by picking one object from each set? O A. 141 B. 23 C. 529 O D. 960​

Answer:

11x2+6x

Step-by-step explanation:

Answer: its either 21x^2 +2x or 11x^2-6x Im not sure which one is solved correctly :/

Step-by-step explanation:

8x^2+4x-6x^2+2+7x^2-2x

21x^2 +2x

or

(8x^2+4x-6x2)2+7x^2-2x

-12x^2+8x+16x^2+7x^2-2x

11x^2-6x

Answer:

2,750+170d

Step-by-step explanation:

Calculation to Enter and simplify an expression for the amount in dollars that the company is paid

First step

Let d represent numbers of day

15(100+3d)

Second step is the Expression for the food booths

25(50+5d)

Third step is Expression for the game booths

15(100+3d)+25(50+5d)

Fourth step is the Expression for both game and food booths

15*100+15*3d+25*50+25*5d

=1,500+45d+1,250+125d

Fifth step is to make use of distributive Property

1,500+1,250+45d+125d

Last step is to make use of cumulative property

(1,500+1,250)+(45d+125d)

=2,750+170d (combine like terms)

Therefore expression for the amount in dollars that the company is paid is 2,750+170d

Answer:

3rd option

Step-by-step explanation:

tanB = \(\frac{opposite}{adjacent}\) = \(\frac{AC}{BC}\) = \(\frac{2x+4}{x+3}\)

Step-by-step explanation: The mode is the number that appears most frequently in a data set. If no Number repeats at all, then there is no mode. A data set can also have multiple modes if different numbers repeat the same amount of times.

The final answer for equation x = 7/2 and x = -1.

To solve the equation, we can start by combining like terms on both sides. By adding 7x and 1 to both sides of the equation, we obtain 2x^2 - 5x - 7 = 0.

Now, we have a quadratic equation in the form ax^2 + bx + c = 0, where a = 2, b = -5, and c = -7. We can use the quadratic formula, x = (-b ± √(b^2 - 4ac)) / (2a), to find the solutions.

Plugging in the values, we get x = (-(-5) ± √((-5)^2 - 4(2)(-7))) / (2(2)).

Simplifying further, we have x = (5 ± √(25 + 56)) / 4, which becomes x = (5 ± √81) / 4.

Taking the square root of 81, we have x = (5 ± 9) / 4.

Therefore, the solutions to the equation are x = (5 + 9) / 4 and x = (5 - 9) / 4, which simplify to x = 14/4 and x = -4/4.

The final answer is x = 7/2 and x = -1.

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Answer:  The correct option is

(D) {3, 10, 17, 24, …}.

Reasoning:

 We are given to select the sequence that represents the following function with a domain of natural numbers :

The set of natural numbers is {1, 2, 3, 4, . . .}

to find the sequence, we need to substitute x = 1, 2, 3, 4, . . . in equation (i).

From equation (i), we get

Therefore, the sequence that represents the given function is {3, 10, 17, 24, …}.

Thus, option (D) is CORRECT.

Answer:

If you are talking about the shaded area, 32pi.

Step-by-step explanation:

The big semi circle is (10^2)/2pi = 50pi.

The small semi circle is (6^2)/2pi = 18pi.

50pi-18pi = 32pi

Answer:

4.25

Step-by-step explanation:

-30=4-8x

-4   -4

----

-34=-8x

/-8  /-8

----

4.25=x

Answer:

x=17/4

Decimal Form:

x=4.25

Mixed Number Form:

x= 4 1/4

explanation:

Answer:

Bill: $45.00

Tip: $9.00

Total: $54.00

Step-by-step explanation: Hope this helped!!!!!!!!!!!!!

Step-by-step explanation:

this is my answer you should mind your own business

Mean absolute deviation of the data set is equals to 180.625.

Mean absolute deviation of a data set is to find the average distance of each observation of data set  and the mean of the data set.

Mean absolute deviation = 1/n ∑ absolute value of(\(x_{i}\)  - \(x\))

\(x\) = average value of the given data set

n = total number of data set

\(x_{i}\) = data value in  given set

So,

=2052/16

= 128.25

Then

Mean absolute deviation = 2890/16

                                          = 180.625

Hence, Mean absolute deviation is 180.625.

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The probability distributions whose graphs can be approximated by bell-shaped curves are commonly known as normal distributions or Gaussian distributions.

These distributions are characterized by their symmetrical shape and the majority of their data falling within a certain range around the mean. The normal distribution is widely used in statistics and is a fundamental concept in many fields of study, including psychology, economics, and engineering. The normal distribution is also known for its many practical applications, such as predicting test scores, stock prices, and medical diagnoses. In summary, the bell-shaped curve is a useful tool in probability theory that can help us understand and make predictions about a wide range of phenomena. The probability distributions whose graphs can be approximated by bell-shaped curves are called Normal Distributions or Gaussian Distributions. They have a symmetrical shape and are characterized by their mean (µ) and standard deviation (σ), which determine the central location and the spread of the distribution, respectively.

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Answer:

Step-by-step explanation:

(a) To find the probability that it is raining when you arrive in Oneirabad on a random day, we need to use the law of total probability.

Let A be the event that it is raining, and B be the event that it is the Wet season.

P(A) = P(A|B)P(B) + P(A|B')P(B')

Given that the Wet season lasts for 1/3 of the year, we have P(B) = 1/3. The probability that it is raining during the Wet season is 3/4, so P(A|B) = 3/4.

The Dry season lasts for 2/3 of the year, so P(B') = 2/3. The probability that it is raining during the Dry season is 1/6, so P(A|B') = 1/6.

Now we can calculate the probability that it is raining when you arrive:

P(A) = (3/4)(1/3) + (1/6)(2/3)

= 1/4 + 1/9

= 9/36 + 4/36

= 13/36

Therefore, the probability that it is raining when you arrive in Oneirabad on a random day is 13/36.

(b) Given that it is raining when you arrive, we can use Bayes' theorem to calculate the probability that your visit is during the Wet season.

Let C be the event that your visit is during the Wet season.

P(C|A) = (P(A|C)P(C)) / P(A)

We already know that P(A) = 13/36. The probability that it is raining during the Wet season is 3/4, so P(A|C) = 3/4. The Wet season lasts for 1/3 of the year, so P(C) = 1/3.

Now we can calculate the probability that your visit is during the Wet season:

P(C|A) = (3/4)(1/3) / (13/36)

= 1/4 / (13/36)

= 9/52

Therefore, given that it is raining when you arrive, the probability that your visit is during the Wet season is 9/52.

(c) Given that it is raining when you arrive, the probability that it will be raining when you return to Oneirabad in a year's time depends on the season. If you arrived during the Wet season, the probability of rain will be different from if you arrived during the Dry season.

Let D be the event that it is raining when you return.

If you arrived during the Wet season, the probability of rain when you return is the same as the probability of rain during the Wet season, which is 3/4.

If you arrived during the Dry season, the probability of rain when you return is the same as the probability of rain during the Dry season, which is 1/6.

Since the season you arrived in is independent of the weather when you return, we need to consider the probabilities based on the season you arrived.

Let C' be the event that your visit is during the Dry season.

P(D) = P(D|C)P(C) + P(D|C')P(C')

Since P(C) = 1/3 and P(C') = 2/3, we can calculate:

P(D) = (3/4)(1/3) + (1/6)(2/3)

= 1/4 + 1/9

= 9/36 + 4/36

= 13/36

Therefore, the probability that it will be raining when you return to Oneirabad in a year's time, given that it is raining when you arrive, is 13/36.

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Answer:

62.5%

Step-by-step explanation:

Split the time up into 5 minute slots. That gives us 24 slots of 5 minutes.

20/5=4 of the 5 minute slots playing outside

25/5=5 of the 5 minute slots on his phone

5+4=9 out of 24 slots spent

24-9=15 slots remaining to play his instrument

15/24x100=62.5% time playing instrument

Answer:62.5%

Step-by-step explanation:

So there are 6,442,752 different license plates that can be issued under these restrictions.

There are a few different restrictions to consider when calculating the number of possible license plates that can be issued. Let's break it down step by step:

The first symbol must be a letter: There are 24 letters to choose from (all except o and i).

The second symbol must be a digit: There are 8 digits to choose from (all except 0 and 1).

The final three symbols can be either letters or digits: For each of the final three symbols, there are 24 letters and 8 digits to choose from (the same restrictions as above).

All five symbols must be chosen: We can multiply the number of choices for each symbol together to get the total number of possible license plates:

24 (choices for first symbol) * 8 (choices for second symbol) * 32,768 (choices for final three symbols, since there are 32 choices for each of the final three symbols) = 6,442,752

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Answer:

for kent it would be \(\frac{1}{5}\)

Step-by-step explanation:

The computation is shown below:

Let us assume Luannda be \(\frac{x}{1}\)

And for kent be 2x

Together they take 5 hours

So

\(\frac{x}{1} + \frac{2x}{1} = 5\ hours\\\\3x = 5\\\\x = \frac{5}{3}\)

So for kent it would be \(\frac{1}{5}\)

Check the picture below.

\(\textit{area of a rectangle}\\\\ A=Lw~~ \begin{cases} L=length\\ w=width\\[-0.5em] \hrulefill\\ w=3L+7\\ A=48 \end{cases}\implies 48=L(3L+7)\implies 48=3L^2+7L \\\\\\ 0=3L^2+7L-48\implies 0=(3L+16)(L-3) \\\\[-0.35em] ~\dotfill\\\\ 0=3L+16\implies -16=3L\implies -\cfrac{16}{3}=L \\\\[-0.35em] ~\dotfill\\\\ 0=L-3\implies 3=L~~\textit{\Large \checkmark} \\\\[-0.35em] ~\dotfill\\\\ w=3L+7\implies w=3(3)+7\implies w=16\)

notice, we didn't use the negative value of "L", because the length can't be negative.

According to the given information the expression solution are:

An equation is referred to as an identity if it has one or more variables and is true for all alternate values of the variables for which both sides of the equation are defined.

For instance,

the equation x 2 + 2 x = x(x + 2) is an identity since it holds true for all possible replacement values for x.

A conditional equation is one that holds true only for specific replacement values of the variable.

For instance, the equation 3 x + 4 = 25 is a conditional equation because it isn't true for all possible replacement values for x.

Without specifying any limitations, an equation is claimed to be an identity, but in reality, it is only an identity for replacement values for which both sides of the identity are defined.

The trigonometric expression is 9 sec2 x (1 - sin2x)

Apply Pythagorean identity

1 - sin2 x = cos2 x9 sec2 x (1 - sin2x)

= 9 sec2 x(cos2 x)

Apply reciprocal identity cosx = 1/ secx

= 9 sec2 x(1/sec2 x)

= 9

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Answer:

Let the adjacent angles of the rhombus be 2x and 3x. We know that the sum of the measures of the adjacent angles is equal to 180°. AD = DC = 3 × 36° = 108°. Hence , the angles of the rhombus are 72° , 108° , 72° and 108°.

Step-by-step explanation:

Answer:

Let the adjacent angles of the rhombus be 2x and 3x.

we know that the sum of the measures of the adjacent angles is equal to 180°.

2x+3x=180

=5x=180

=x=180/5

=x=36°

Hence,AB =BC=2×36°=72°

AD=DC=3×36°=108°

Hence,The angles of the rhombus are 72°,108°, 72°and108°.

I hope it's helpful!

First, we have to make \(w\) the subject of the equation:

\(w - 0.9 > -2.1\\w > -2.1 + 0.9\\w > -1.2\)

This shows that \(w\) is less than but not equal to \(-1.2\). So we are going to use an arrow that has a non-shaded circle. Since the symbol is the greater than symbol, or >, the arrow will point to the right. Thus, the arrow we choose will be the last arrow.

Now since we are comparing \(w\) with \(-1.2\), we place the arrow above the \(-1.2\) point. That's how he place the arrow in the number line.

Answer:

\(\displaystyle y = \frac{-2}{7}\)

Step-by-step explanation:

   To solve, we will isolate the variable.

   Given:

-12/7 = 6y

   Divide:

\(\displaystyle \frac{\frac{-12}{7} }{6} =\frac{6y}{6}\)

   Simplify the right side:

\(\displaystyle \frac{\frac{-12}{7} }{6} =y\)

   "Keep, change, flip" on the left side:

\(\displaystyle \frac{-12}{7} *\frac{1}{6} = y\)

   Multiply:

\(\displaystyle \frac{-12*1}{7*6}= y\)

\(\displaystyle \frac{-12}{42}= y\)

   Simplify and reflexive property:

\(\displaystyle y = \frac{-2}{7}\)

Answer:

bottom left and top right

Step-by-step explanation:

Given:

The arithmetic mean of three consecutive even integers is 20.

To find:

The equation that can be used to find the integers.

Solution:

Let the three consecutive even integers are x, x+2 and x+4.

We know that,

\(\tex{Mean}=\dfrac{\text{Sum of observations}}{\text{Number of observations}}\)

The arithmetic mean of three consecutive even integers is:

\(\tex{Mean}=\dfrac{x+(x+2)+(x+4)}{3}\)

It is given that, mean = 20. So,

\(\dfrac{x+(x+2)+(x+4)}{3}=20\)

Therefore, the correct option is E.

yess...??

Step-by-step explanation:

I'm doing it in my head and I'm not sure.. but I believe it is

Part (a)

Dividing by 5 yields,\(\frac{d}{5}\).

Part (b)

Oliver is 7 years older than Amira.

Answer:

Part (a)

Dividing by 5 yields,.

Part (b)

Oliver is 7 years older than Amira.

Step-by-step explanation:

Answer:

she should use a scale 8)

Step-by-step explanation:

The curve x = t^2 − 3t, y = t intersects the y-axis when x = 0, which occurs when t = 0 and t=3. is 8root2/5

When two or more lines cross each other in a plane, they are called intersecting lines. The intersecting lines share a common point, which exists on all the intersecting lines, and is called the point of intersection. Here, lines P and Q intersect at point O, which is the point of intersection.

In general, an intersection curve consists of the common points of two transversally intersecting surfaces, meaning that at any common point the surface normals are not parallel. This restriction excludes cases where the surfaces are touching or have surface parts in common.

A=∫ ​( t)(2t−2)dt

=∫ 2t ^(3/2) −2t ^(1/2)dt

=8root(2)/15

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