A wave with a wavelength of 4.0 m moves with a speed of 2.0 m/s will have frequency of 0.5 Hz.
Given,
The wavelength of the wave, λ = 4.0 m
Speed of the wave, v = 2.0 m/s
Frequency of the wave can be calculated as;
ν =v/λ
= 2/4
=1/2 Hz
Or, 0.5 Hz
Hence, the frequency of the wave will be 0.5 Hz.
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Someone please help!!! I dont understand this at all.
The ions are;
S^2- Gained 2 electrons
Li^+ - Lost one electron
Al^3+ - Lost 3 electrons
Cl^- gained one electron
Sr^2+ Lost two electrons
P^3- gained 3 electrons
How are ions formed?As an atom or molecule acquires or loses one or more electrons, ions are created. Protons and neutrons make up the positively charged nucleus of an atom, which is encircled by negatively charged electrons. An atom typically has a neutral charge because the amount of electrons and protons in it equals one.
The balance between the negatively charged electrons and positively charged protons is upset when an atom receives or loses an electron, creating an ion with a positive or negative charge.
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Select whether the argument is an example of a deductive or an inductive argument:
If he comes back, then it's probably because he wants your money. There he is. He wants your money.
a inductive
b. deductive
The radius of the circular path of an ion in a mass spectrometer is given by r=1/B √2Vaccelm/q. Use this equation to explain how a mass spectrometer is able to separate ions of different masses.
The mass spectrometer separates ions of different masses by utilizing the relationship between the strength of the magnetic field, the accelerating voltage, the charge-to-mass ratio of the ions, and the resulting radius of the circular path
What is the mass spectrometer?From the formula in the question;
B is a symbol for the magnetic field's intensity as it is applied to the mass spectrometer.
The accelerating voltage used to move the ions is called Vaccelm.
The charge of the ion, specifically its charge-to-mass ratio (q/m), is represented by the letter q.
The mass spectrometer may selectively alter the radius of the circular route for various ions by varying the magnetic field's intensity (B). This makes it possible to spatially segregate ions with various masses based on their various radii. The ions' locations and masses can then be measured using detectors placed along the journey.
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What is one danger that astronauts would face going to the moon, visiting the moon, or returning to Earth?
How does a balanced equation illustrate the Law of Conservation of Mass?
The balanced equation illustrates the Law of Conservation of Mass as the mass of the products must be equal to the mass of the reactants.
The law of conservation of mass is always obeyed by a chemical equation that is balanced. This law states that the mass of the products must be equal to the mass of the reactants in order for the law to be valid. It is possible to determine whether or not a reaction is balanced by determining whether or not the number of moles of atoms across both ends of the chemical process is equivalent. If the number of moles is the same on both sides the total mass will also be the same.
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A mouse of mass 200 g falls 100 m down a vertical mine shaft and lands at the bottom with a speed of 8.0 m/s. During its fall, how much work is done on the mouse by air resistance?
The work done on the mouse by air resistance is equal to 196 Joules.
Given the following data:
Mass = 200 grams to kg = 0.2 kg.
Distance = 100 meters.
Scientific data:
Acceleration due to gravity = 9.8 \(m/s^2\)
How to calculate work done.In Science, work done is generally calculated by multiplying force and the vertical distance or displacement experienced by an object.
Mathematically, work done is given by the formula:
\(Work\;done = force \times displacement = mgh\)
Substituting the given parameters into the formula, we have;
\(Work\;done = 0.2 \times 9.8 \times 100\)
Work done = 196 Joules.
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Brent’s doctor recommended that he avoid hot baths while he and his wife are trying to have a child. Why did the doctor most likely make this recommendation?
Exposing the testicles to high temperatures could lead to problems
with maintaining erections.
Exposing the testicles to high temperatures could lead to problems
with producing sperm.
Exposing the testicles to high temperatures could lead to problems
with ejaculating.
Exposing the testicles to high temperatures
Answer:
Exposing the testicles to high temperatures could lead to problems
with producing sperm.
Explanation:
got it correct on the edge unit test review
Brent's doctor most likely recommended that he avoid hot baths because exposing the testicles to high temperatures could lead to problems with producing sperm.
What is sperm?The sperm is the male reproductive cell that is produced in the testes and stored in the epididymis.
The testicles (testes) of the male is located outside the body as the temperature of the body is too high for the viability of the sperm.
Therefore, exposing the testicles to high temperatures could lead to problems with producing sperm.
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1) A squirrel falls from a tree. After a brief rest, the squirrel begins to accelerate until it reaches a velocity of
5.8 m/s. If the squirrel ran a total of 15 m, what would be its acceleration ?
In the figure below, the net external force on the 30 kg mower is stated to be 52 N.
If the force of friction opposing the motion is 18 N, what force F (in N) is the person exerting on the mower? (Enter the magnitude.)
Suppose the mower is moving at 1.5 m/s when the force F is removed. How far (in m) will the mower go before stopping?
The mower will travel approximately 0.62 meters before coming to a stop.
What is velocity?Velocity is a vector quantity that describes the rate of change of an object's position with respect to time, and it includes both the speed and direction of motion. In other words, velocity is a measure of how fast an object is moving and in what direction it is moving.
To find the force F exerted by the person on the mower, we must apply Newton's second law of motion, which states that an object's net force is equal to its mass multiplied by its acceleration:
F_net = m × a
where F_net is the net force, m is the mass of the object, and a is the acceleration.
In this case, the net external force is given as 52 N, and the force of friction opposing the motion is 18 N. So, the force F exerted by the person on the mower is:
F = F_net - F_friction
F = 52 N - 18 N
F = 34 N
Therefore, the person is exerting a force of 34 N on the mower.
Now, to find how far the mower will go before stopping, we can use the equation for constant acceleration:
d = (v_f² - v_i²) / (2a)
where d is the distance traveled, v_f is the final velocity (which is zero in this case), v_i is the initial velocity (1.5 m/s), and a is the acceleration.
The acceleration can be calculated by dividing the net force (F_net) by the mass of the mower (m):
a = F_net / m
a = 52 N / 30 kg
a = 1.73 m/s²
Now, we can plug in the values to get the distance traveled:
d = (0 - 1.5²) / (2 × 1.73)
d = 0.62 m
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What impact does your family have on air pollution? Find out how much carbon dioxide your family’s car releases.
a. First find out how many gallons of gasoline your family’s car holds when the tank is full. (Often this is stated somewhere in the owner’s manual.)
b. Estimate how many gallons of gasoline are used each week by your family. You can do this by finding out how many times a week gasoline is put in the car and about how many gallons is put in each time.
c. Now calculate how many pounds of carbon dioxide are emitted each week by your family’s use of the car. How many pounds are emitted each month? Each year?
My family car has a tank size of 19 gallons, and it is fueled twice a week at about 8 gallons each time. It's yearly carbon emission is about 16,254 pounds per year.
The family car's emissionTo estimate the weekly gasoline consumption, we multiply the number of refills (2) by the amount of gasoline added each time (8 gallons):
Therefore weekly gasoline consumption 2 refills/week at 8 gallons per refill = 16 gallons/week
c. The emission factor for carbon dioxide is approximately 19.55 pounds per gallon.
Therefore, to obtain the weekly emissions,
Multiply the weekly gasoline consumption 16 gallons by the emission factor of carbon dioxide 19.55 pounds per gallon.
Weekly carbon dioxide emissions is 16 gallons/week * 19.55 pounds/gallon
= 312.8 pounds/week
Monthly emissions: Multiply the weekly emissions 312.8 pounds by the number of weeks in a month approximately 4.35) to get the monthly carbon dioxide emissions
Monthly carbon dioxide emissions is 312.8 pounds per week * 4.35 weeks per month
≈ 1,359 pounds/month
Yearly emissions: Multiply the weekly emissions 312.8 pounds by the number of weeks in a year approximately 52 to get the yearly carbon dioxide emissions.
Yearly carbon dioxide emissions is 312.8 pounds per week * 52 weeks per year
≈ 16,254 pounds/year
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what 2 things keep windows from shattering?
video- Mechanical Universe: Resonance
Two things that keep windows from shattering are the strength of the glass and the ability of the window frame to dampen vibrations.
What is the shattering of windows?The strength of the glass is important because it determines how much force the glass can withstand before it breaks. Modern windows are typically made of tempered glass, which is treated with heat to make it stronger and more resistant to shattering.
The ability of the window frame to dampen vibrations is also crucial because glass is prone to resonance, which is a phenomenon that occurs when an object is subjected to vibration at its natural frequency.
If the frequency of the vibration matches the natural frequency of the glass, the glass can begin to vibrate and eventually shatter. To prevent this, window frames are designed to be sturdy and to dampen vibrations, which helps to prevent the glass from vibrating and shattering.
In summary, both the strength of the glass and the ability of the window frame to dampen vibrations are important factors that help to prevent windows from shattering.
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2. A car is traveling a road that includes two sides of a rectangle with the
sides a and b with a constant speed. What is the speed if the
magnitude of the average velocity of the car is v?
The speed of the car in terms of the average velocity is \(\frac{v(a+ b) }{\sqrt{a^2 + b^2} }\)
The given parameters;
length of each side of the triangle = a and baverage velocity = vThe average velocity of the car is defined as the rate of change of displacement.
\(average \ velocity = \frac{displacement}{time}\)
The displacement of the car along the rectangle is obtained by applying Pythagoras theorem to calculate the diagonal of the rectangle ;
c² = a² + b²
\(c = \sqrt{a^2 + b^2}\)
\(v= \frac{\sqrt{a^2 + b^2} }{t} \\\\t = \frac{\sqrt{a^2 + b^2} }{v}\)
The speed of the car is defined as the rate of change of distance.
\(speed = \frac{distance}{time}\)
The distance around the 2 sides of the rectangle is calculated as;
Distance = a + b
\(speed = \frac{a+b}{t}\)
\(speed = \frac{v(a+ b)}{\sqrt{a^2 + b^2} }\)
Thus, the speed of the car is \(\frac{v(a+ b) }{\sqrt{a^2 + b^2} }\)
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A carousel is (more or less) a disk of mass, 15,000 kg, with a radius of 6.14. What torque must be applied to create an angular acceleration of 0.0500 rad/s^2?round to 3 significant figures
(Plssss help me im suffering from severe brainrot)
To calculate the torque required to create an angular acceleration, we can use the formula:
Torque = Moment of Inertia × Angular Acceleration
The moment of inertia of a disk can be calculated using the formula:
Moment of Inertia = (1/2) × Mass × Radius^2
Given:
Mass = 15,000 kg
Radius = 6.14 m
Angular Acceleration = 0.0500 rad/s^2
First, calculate the moment of inertia:
Moment of Inertia = (1/2) × Mass × Radius^2
Moment of Inertia = (1/2) × 15,000 kg × (6.14 m)^2
Next, calculate the torque:
Torque = Moment of Inertia × Angular Acceleration
Torque = Moment of Inertia × 0.0500 rad/s^2
Now, let's plug in the values and calculate:
Moment of Inertia = (1/2) × 15,000 kg × (6.14 m)^2
Moment of Inertia ≈ 283,594.13 kg·m^2
Torque = 283,594.13 kg·m^2 × 0.0500 rad/s^2
Torque ≈ 14,179.71 N·m
Rounding to three significant figures, the torque required to create an angular acceleration of 0.0500 rad/s^2 is approximately 14,180 N·m.
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Acceleration of 1.5 ms expressed in km /hr2?
Question 3 The weight is oscillating on the spring. The equilibrium position of the object is x=2m, the amplitude of the oscillations is 0.2 m. If we look at the object's oscillations, it will be in the equilibrium position at times t-Os and t=2s. a. What function in general describes oscillations of the object? b. Is this function shifted in any of the directions? C. Is the function squeezed or stretched along y axis? d. Is the function squeezed or stretched along x direction? What is the equation describing position of the object in time? e. What is the equation describing position of the object in time?
a. The function that describes the oscillations of the object can be described using a sinusoidal function.
b. Yes, the function is shifted in the x-direction.
c. No, the function is not squeezed or stretched along the y-axis.
d. No, the function is not squeezed or stretched along the x-direction. The equation describing the position of the object in time can be expressed as :x(t) = A * cos(ωt + φ)
e. x(0) = A * cos(ω * 0 + φ) = 2 is the equation describing position of the object in time.
a. The function that describes the oscillations of the object can be described using a sinusoidal function. A common function used to represent oscillatory motion is the cosine function or the sine function. In this case, since the object is in the equilibrium position at t=0 and t=2s, we can use the cosine function to describe its oscillations.
b. Yes, the function is shifted in the x-direction. The equilibrium position of the object is at x=2m, which means the function is shifted 2 units to the right along the x-axis.
c. No, the function is not squeezed or stretched along the y-axis. The amplitude of the oscillations remains constant at 0.2 m.
d. No, the function is not squeezed or stretched along the x-direction. The period of the oscillations remains constant, indicating that the function is not compressed or stretched along the x-axis.
The equation describing the position of the object in time can be expressed as follows:
x(t) = A * cos(ωt + φ)
Where:
- x(t) represents the position of the object at time t.
- A is the amplitude of the oscillations (0.2 m in this case).
- ω is the angular frequency, given by ω = 2π / T, where T is the period of oscillation.
- φ is the phase constant, representing the initial phase of the oscillation.
e. To determine the equation describing the position of the object in time, we need to find the values of ω and φ. Since the object is in the equilibrium position at t=0 and t=2s, we can use this information to determine the values.
At t=0, the object is in the equilibrium position, so we have:
x(0) = A * cos(0 + φ) = 2
At t=2s, the object is in the equilibrium position again, so we have:
x(2) = A * cos(2ω + φ) = 2
Now,
At t=0, we have:
x(0) = A * cos(ω * 0 + φ) = 2
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A thin half ring with a radius of R = 10 cm is uniformly charged with a linear density of = 1 Mikrokulon/m and located in a vacuum. Determine the force F of interaction between the half ring and a point charge q = 20 nC located at the center of curvature. (don't use chatgpt please)
Answer:
Explanation:
F = k * q * lambda * R * π * (1 - √2/2)
Substituting the given values of q, lambda, R, and k, we get:
F = (9 x 10^9 N*m^2/C^2) * (20 x 10^-9 C) * (1 x 10^-6 C/m) * (0.1 m) * π * (1 - √2/2)
F ≈ 8.58 x 10^-4 N
Therefore, the force of interaction between the half ring and the point charge is approximately 8.58 x 10^-4 N.
The gravitational attraction between two objects increases if
Answer:
they are closer!!
Explanation:
Hope this helped!! :D
Data:
Depth Velocity Wavelength
(meters) (km/h) (km)
7000 943 282
4000 713 213
2000 504 151
200 159 48
50 79 23
10 36 10.6
Predict the tsunami speed for the following ocean depths:
a. 8000 meters __________________________
b. 3500 meters ___________________________
c. 70 meters _____________________________
d. 5 meters _______________________________
a. The speed of the tsunami at ocean depth of 8000 m is 1,019.66 km/h.
b. The speed of the tsunami at ocean depth of 3500 m is 660.75 km/h.
c. The speed of the tsunami at ocean depth of 70 m is 89.66 km/h.
d. The speed of the tsunami at ocean depth of 5 m is 30.625 km/h.
Speed of the tsunami at the given depths
The speed of the tsunami is calculated from method of extrapolation or interpolation as shown below;
Speed at 8000 meters8000 m -------- ?
7000 m -------- 943 km/h
4000 m -------- 713 km/h
(8000 - 7000)/(7000 - 4000) = (? - 943)/(943 - 713)
0.3333 = (? - 943)/230
230(0.3333) = ? - 943
76.66 = ? - 943
? = 1,019.66 km/h
Speed at 3500 m4000 m ---------- 713 km/h
3500 m ---------- ?
2000 m ----------- 504 km/h
(4000 - 3500)/(4000 - 2000) = (713 - ?) / (713 - 504)
0.25 = (713 - ?) /209
0.25(209) = 713 - ?
52.25 = 713 - ?
? = 660.75 km/h
Speed at 70 m200 m ------ 159 km/h
70 m --------- ?
50 m ------- 79 km/h
(200 - 70)/(200 - 50) = (159 - ?)/(159 - 79)
0.8667 = 159 - ? / 80
80(0.8667) = 159 - ?
69.336 = 159 - ?
? = 89.66 km/h
Speed at 5 meters50 m ------- 79 km/h
10 m --------- 36 km/h
5 m ---------- ?
(50 - 5)/(50 - 10) = (79 - ?)/(79 - 36)
1.125 = 79 - ?/43
43(1.125) = 79 - ?
48.375 = 79 - ?
? = 30.625 km/h
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Please help me out! I will pay real money to whoever solves this
Answer:
I KNOW THE ANSWER IT WILL COST 30$
Explanation:
What are some guidelines for preventing quackery and fraud when shopping? Select
all that appy.
Select 4 correct answer(s)
Be suspicious of a sales pitch that promises results too good to be true.
Be wary of advisors who sell products.What are some guidelines for preventing quackery and fraud when shopping? Select
all that appy.
Select 4 correct answer(s)
-Be suspicious of a sales pitch that promises results too good to be true.
-Be wary of advisors who sell products. -Don’t do any research before shopping. -Be cautious of mail-order and internet sales. -Be wary of product claims. -If a celebrity or athlete promotes it-it must be good
The steps/guidelines for preventing quackery and fraud when shopping are :
Be suspicious of a sales pitch that promises results too good to be trueBe cautious of mail-order and internet sales Be wary of product claims Be wary of advisors who sell products What is Quackery and FraudQuackery involves the claim of knowledge and provision of a fake and dishonest service to unsuspecting customers or clients and this is very common in medicine.
Fraud is the false representation of a material or service in order to cause loss of money or pain to an unsuspecting client or customer. some steps to prevent fraud are as follows :
If a sales pitch is too good to be true one should keep off from such product/service.when making internet sales and mail-order customers should be careful as there are a lot of imposters on the internet.Hence we can conclude that The steps/guidelines for preventing quackery and fraud when shopping are as listed above
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Pleaseee helppp!!! Due in 10 minutes and I’m clueless
HELP PLEEAAAASSSEEEEEEE What is the definition of net force?
Answer:
the sum of all force being applied to an object.
Explanation:
Suppose a 118kg watermelon is held 5m above the ground before sliding along a frictionless ramp to the ground. How high above the ground is the watermelon at the moment it's kinetic energy is 4,610J
This question involves the concepts of kinetic energy, potential energy, and the law of conservation of energy.
The watermelon is "1.02 m" above the ground.
The total energy of the watermelon can be found by its potential energy at the highest point:
Total Energy = mgh
where,
m = mass = 118 kgg = 9.81 m/s²h = height = 5 mTherefore,
Total Energy = (118 kg)(9.81 m/s²)(5 m)
Total Energy = 5787.9 J
LAW OF CONSERVATION OF ENERGYNow, according to the law of conservation of energy, at the given point:
Total Energy = Kinetic Energy + Potential Energy
5787.9 J = 4610 J + mgh'
\(h'=\frac{5787.9\ J-4610\ J}{(118\ kg)(9.81\ m/s^2)}\)
h' = 1.02 m
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The circuit diagram below represents four resistors connected to a 12-volt potential source. What is the current in the circuit?8.6 A0.5 A2.0 A24 A
The current in the circuit is 0.5 A..
Given data:
The voltage of the battery is V=12 V.
The resistances are,
\(\begin{gathered} R_1=4\text{ }\Omega \\ R_2=6\text{ \Omega} \\ R_3=8\text{ \Omega} \\ R_4=6\text{ }\Omega \end{gathered}\)The voltage of the battery is V=12 V.
The equivalent resistance of the given series connection of resistances can be calculated as,
\(\begin{gathered} R=R_1+R_2+R_3+R_4 \\ R=4+6+8+6 \\ R=24\text{ }\Omega \end{gathered}\)Applying the Ohm's law to calculate the current in the circuit as,
\(\begin{gathered} V=IR \\ (12)=I(24) \\ I=0.5\text{ A} \end{gathered}\)Thus, the current in the circuit is 0.5 A.
6. In the diagram below, A is a vector of magnitude 35 cm; B is a vector of magnitude 13 cm. If tan a = 4/3 and tan ß = 5/12, a. write A and B in terms of î and ĵ b. Show that A + B makes an angle of 45° to the x-axis.
Answer:
A = 21 î + 28 ĵ
B = 12 î + 5 ĵ
Explanation:
a.
To write A and B in terms of î and ĵ, we need to use the trigonometric ratios and the vector notation
According to the diagram, we have:
tan a = 4/3 tan ß = 5/12
Using the identity tan θ = opposite/adjacent, we can find the x and y components of A and B.
For A, we have:
x component = 35 cos a y component = 35 sin a
Using tan a = 4/3, we can find cos a and sin a by using Pythagoras’ theorem:
cos a = 3/5 sin a = 4/5
Therefore, the x and y components of A are:
x component = 35 cos a = 35 (3/5) = 21 y component = 35 sin a = 35 (4/5) = 28
Using the vector notation, we can write A as:
A = 21 î + 28 ĵ
Similarly, for B, we have:
x component = 13 cos ß y component = 13 sin ß
Using tan ß = 5/12, we can find cos ß and sin ß by using Pythagoras’ theorem:
cos ß = 12/13 sin ß = 5/13
Therefore, the x and y components of B are:
x component = 13 cos ß = 13 (12/13) = 12 y component = 13 sin ß = 13 (5/13) = 5
Using the vector notation, we can write B as:
B = 12 î + 5 ĵ
b.
To show that A + B makes an angle of 45° to the x-axis, we need to find the resultant vector R and its angle θ with the x-axis.
To find R, we can use the vector addition rule :
R = A + B R = (21 î + 28 ĵ) + (12 î + 5 ĵ) R = (21 + 12) î + (28 + 5) ĵ R = 33 î + 33 ĵ
To find θ, we can use the inverse tangent function :
tan θ = y component / x component tan θ = 33 / 33 tan θ = 1
θ = tan^-1(1) θ = 45°
Therefore, A + B makes an angle of 45° to the x-axis.
A ball at the end of a string of length 2m rotates at a constant speed in a horizontal circle. It makes 7 rev/s.
What is the period of the ball’s motion? Answer in units of s.
second part
What is the frequency of the motion? Answer in units of Hz.
third part
What is the ball’s angular velocity? Answer in units of rad/s.
The time period of the ball’s motion will be 0.14 seconds
The frequency of the motion will be 7 Hz
The ball’s angular velocity will be 43.96 rad/second
given
a) frequency = 7 rev / s = 7 Hz
time period = 1 / frequency
= 1 / 7 = 0.14 seconds
The period of the ball’s motion will be 0.14 seconds
b) The frequency will be 7 Hz
c) The ball’s angular velocity = 2 * π * f
= 2 * 3.14 * 7 = 43.96 rad/second
The ball’s angular velocity will be 43.96 rad/second
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At present, NASA is planning a mission to Europa, to try and assess its habitability. An argument might also be made for Enceladus, however. Let's imagine you had to pick one of those moons to send an uncrewed (i.e. robotic) mission to. The spacecraft will probably orbit the giant planet (Jupiter in the case of Europa, Saturn in the case of Enceladus), and make many flybys of the moon you're studying. Which moon would you pick, and why?
Answer:
Jupiter
Explanation:
For this space trip, the distance to the planet must be taken into account, so Because Jupiter is much closer it should be the correct choice
.
It must also be taken into account that Saturn has a series of rings, for which the ship has a probability of colliding with one of these in one of its turns, therefore taking this into account, Jupiter must also be chosen.
what current flows through the 75 ohm resistor in the circuit below?
The current that flows through the 75 ohm resistor in the circuit shown below is 0.12A.
How to calculate current?The current flowing through a circuit can be calculated using the Ohm's law equation as follows;
V = IR
Where;
V = voltage (V)I = current (A)R = resistance (ohm)According to this question, a circuit is shown in the above image. A 75 ohm resistor is given alongside a voltage of 9V. The current can be calculated as follows;
9 = I × 75
I = 0.12A
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What are the three major types of severe weather? Describe at least two characteristics of each type
Answer:
High winds, hail, excessive precipitation, and wildfires are forms and effects of severe weather, as are thunderstorms, downbursts, tornadoes, waterspouts, tropical cyclones, and extratropical cyclones. Regional and seasonal severe weather phenomena include blizzards (snowstorms), ice storms, and duststorms.
Explanation:High winds- wind speeds as low as 23 knots (43 km/h) may lead to power outages when tree branches fall and disrupt power lines. Once wind exceed 135 knots (250 km/h) within strong tropical cyclones and tornadoes, homes completely collapse, and significant damage is done to larger buildings. Total disruption occurs once wind exceeds 175 knots (324 km/h)
Tornado- Typically look like a narrow funnel reaching from the clouds to the ground. Their wind speed goes from 65 to 250 miles per hour.
"An extreme weather condition in which we face the high speed wind in combination with heavy snow."
As for any blizzard has the normal wind speed of about 40 mph, and the visibility range reduces to less then 500 ft.
Answer: High winds, hail, excessive precipitation, and wildfires are forms and effects of severe weather, as are thunderstorms, downbursts, tornadoes, waterspouts, tropical cyclones, and extratropical cyclones. Regional and seasonal severe weather phenomena include blizzards (snowstorms), ice storms, and duststorms.
Explanation:
What is the weight of a 356 kg crate
W=mg
Explanation:
use the formula and substitute the value