Question 1 (1 point)
Does the Equation Mat below represent the equation 3x - 4 = x + 6?
-
True or False

(a) The domain closed and bounded.

(b) The domain bounded.

(c) The domain closed.

(d) The domain bounded.

(e) The domain closed and bounded.

(f) The domain closed and bounded.

In this question, we have been given some domains.

We need to check which domains are closed and which are bounded.

A domain of function is said to be closed if the region R contains all boundary points.

A bounded domain is nothing but a domain which is a bounded set.

(a) {(x,y)∈R2:x^2+y^2≤1}

The domain of x^2+y^2≤1 contains set of all points (x, y) ∈R2

so, the domain closed and bounded.

(b) {(x,y)∈R2:x2+y2<1}

The domain of x^2+y^2 < 1 contains set of all points (x, y) ∈R2

so, the domain is bounded.

(c) {(x,y)∈R2: x ≥ 0}

The domain of x ≥ 0 is R2 - {x < 0}

So, the domain is closed.

(d) {(x, y) ∈ R2 : x > 0,y > 0}

The domain is R2 - {(x, y) ≥ 0}

So, the domain is bounded.

(e) {(x, y) ∈ R2 : 1 ≤ x ≤ 4, 5 ≤ y ≤ 10}

The domain is closed and bounded.

(f) {(x,y)∈R2:x>0,x^2+y^2≤10}

The domain is closed and bounded.

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Answer:

Hello! answer: 85

Step-by-step explanation:

Formula for square area: base × height

Formula for triangle area: base × height ÷ 2

6 × 5 = 30 30 ÷ 2 = 15 since theres 4 triangles I just multiply by 4 get all the triangles area so...

15 × 4 = 60 now the square is just 5 × 5 so... 5 × 5 = 25 now we just add these up for the answer so... 60 + 25 = 85 therefore the surface area is 85 hope that helps!

Answer:

Step-by-step explanation:

Answer:

its b or if its not its d

Step-by-step explanation:

Answer:

-9

Step-by-step explanation:

First rewrite the equation as:

-3 + (-6) <- (we can do that because of additive inverse)

Then just add -3 and -6 to get -9

The area under the curve over [2,5] is 24.

Given function is f(x) = 2xIntervals [2, 5] is given and it is to be divided into subintervals.

Let us consider n subintervals. Therefore, width of each subinterval would be:

$$
\Delta x=\frac{b-a}{n}=\frac{5-2}{n}=\frac{3}{n}
$$Here, we are using right-hand end point. Therefore, the right-hand end points would be:$${ c }_{ k }=a+k\Delta x=2+k\cdot\frac{3}{n}=2+\frac{3k}{n}$$$$
\begin{aligned}
\therefore R &= \sum _{ k=1 }^{ n }{ f\left( { c }_{ k } \right) \Delta x } \\&=\sum _{ k=1 }^{ n }{ f\left( 2+\frac{3k}{n} \right) \cdot \frac{3}{n} }\\&=\sum _{ k=1 }^{ n }{ 2\cdot\left( 2+\frac{3k}{n} \right) \cdot \frac{3}{n} }\\&=\sum _{ k=1 }^{ n }{ \frac{12}{n}\cdot\left( 2+\frac{3k}{n} \right) }\\&=\sum _{ k=1 }^{ n }{ \frac{24}{n}+\frac{36k}{n^{ 2 }} }\\&=\frac{24}{n}\sum _{ k=1 }^{ n }{ 1 } +\frac{36}{n^{ 2 }}\sum _{ k=1 }^{ n }{ k } \\&= \frac{24n}{n}+\frac{36}{n^{ 2 }}\cdot\frac{n\left( n+1 \right)}{2}\\&= 24 + \frac{18\left( n+1 \right)}{n}
\end{aligned}
$$Take limit as n → ∞, so that $$
\begin{aligned}
A&=\lim _{ n\rightarrow \infty  }{ R } \\&= \lim _{ n\rightarrow \infty  }{ 24 + \frac{18\left( n+1 \right)}{n} } \\&= \boxed{24}
\end{aligned}
$$

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Given function f(x) = 2x. The interval is [2,5]. The number of subintervals, n is 3.

Therefore, the area under the curve over [2,5] is 21.

From the given data, we can see that the width of the interval is:

Δx = (5 - 2) / n

= 3/n

The endpoints of the subintervals are:

[2, 2 + Δx], [2 + Δx, 2 + 2Δx], [2 + 2Δx, 5]

Thus, the right endpoints of the subintervals are: 2 + Δx, 2 + 2Δx, 5

The formula for the Riemann sum is:

S = f(c1)Δx + f(c2)Δx + ... + f(cn)Δx

Here, we have to find a formula for the Riemann sum obtained by dividing the interval [2.5] subintervals and using the right hand endpoint for each ck. The width of each subinterval is:

Δx = (5 - 2) / n

= 3/n

Therefore,

Δx = 3/3

= 1

So, the subintervals are: [2, 3], [3, 4], [4, 5]

The right endpoints are:3, 4, 5. The formula for the Riemann sum is:

S = f(c1)Δx + f(c2)Δx + ... + f(cn)Δx

Here, Δx is 1, f(x) is 2x

∴ f(c1) = 2(3)

= 6,

f(c2) = 2(4)

= 8, and

f(c3) = 2(5)

= 10

∴ S = f(c1)Δx + f(c2)Δx + f(c3)Δx

= 6(1) + 8(1) + 10(1)

= 6 + 8 + 10

= 24

Therefore, the Riemann sum is 24.

To calculate the area under the curve over [2, 5], we take the limit of the Riemann sum as n → ∞.

∴ Area = ∫2^5f(x)dx

= ∫2^52xdx

= [x^2]2^5

= 25 - 4

= 21

Therefore, the area under the curve over [2,5] is 21.

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Answer:

We can see the two triangles ABC and EDC are similar and their sides are proportional.

4 to 8, 6 to 12, 5 to 10

You could say,

1. ABC ~ EDC -- SSS criterion

2. ∠A = ∠E -- CPCTC

3. AB || ED -- Alternate Interior Angles Converse

I hope you understand....

Mark me as brainliest....

Thanks...

After 14 days, you will have approximately $2.4414 invested in the stock market.

The amount you will have invested after 14 days can be calculated using the geometric sequence formula. The formula for the nth term of a geometric sequence is given by:

an = a1 x \(r^{(n-1)\)

Where:

an is the nth term,

a1 is the first term,

r is the common ratio, and

n is the number of terms.

In this case, the initial investment is $20,000, and each day the investment loses half of its value, which means the common ratio (r) is 1/2. We want to find the value after 14 days, so n = 14.

Substituting the given values into the formula, we have:

a14 = 20000 x\((1/2)^{(14-1)\)

a14 = 20000 x \((1/2)^{13\)

a14 = 20000 x (1/8192)

a14 ≈ 2.4414

Therefore, after 14 days, you will have approximately $2.4414 invested in the stock market.

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The amount you will have invested after 14 days is given as follows:

$2.44.

A geometric sequence is a sequence of numbers where each term is obtained by multiplying the previous term by a fixed number called the common ratio q.

The explicit formula of the sequence is given as follows:

\(a_n = a_1q^{n-1}\)

In which \(a_1\) is the first term of the sequence.

The parameters for this problem are given as follows:

\(a_1 = 20000, q = 0.5\)

Hence the amount after 14 days is given as follows:

\(a_{14} = 20000(0.5)^{13}\)

\(a_{14} = 2.44\)

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Answer:

I know it's hard for you because she had buns remaining and not bums

do follow me

Answer:

288

Step-by-step explanation:

x- 5/9x= 128

4/9x=128

x=128*9/4

x= 288

Answer:

The ball reaches 44 ft above the ground after 4 sec.

Step-by-step explanation:

Set h(t)=-16t^2+300 equal to 44 feet and solve for time, t.  Indicate exponentiation with " ^ "

-16t^2 + 300 = 44 becomes

-16t^2 + 256 = 0, or 16t^2 = 256.  Then, taking the square root of both sides, we get:

4t = 16, or t = 4 sec.  The ball reaches 44 ft above the ground after 4 sec.

The ball will take 4 seconds.

A quadratic equation, or simply "quadratics," is a polynomial equation with a degree of two as its highest. This is how it is expressed:

a x² + b x + c = 0 where x is the unknown variable and the constant terms are a, b, and c.

Given equation of height h(t) = -16t² + 300...…..(1)

where h is height in feet and t is time in seconds,

and height at t = 0 is 300 feet

when ball is 44 feet above ground then time is,

put h = 44 in equation 1

44 = -16t² + 300

16t² = 300 - 44

t² = 256/16

t = √16

t = 4

Hence time taken by ball is 4 seconds.

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Part A:

The new deck will be a 4:5 scaled version of the original deck. This means that every dimension of the new deck will be 4/5 times the corresponding dimension of the original deck.

The original deck has a base of 15 feet and a height of 9 feet.

The new deck will have a base of (4/5) * 15 = 12 feet and a height of (4/5) * 9 = 7.2 feet.

Therefore, the dimensions of the new deck are 12 feet for the base and 7.2 feet for the height.

Part B:

To find the area of the original deck, we use the formula for the area of a triangle:

Area = (1/2) * base * height = (1/2) * 15 * 9 = 67.5 square feet.

To find the area of the new deck, we use the same formula with the new dimensions:

Area = (1/2) * 12 * 7.2 = 43.2 square feet.

Therefore, the area of the original deck is 67.5 square feet, and the area of the new deck is 43.2 square feet.

Part C:

The ratio of the areas is:

Area of new deck / Area of original deck = 43.2 / 67.5

Simplifying this fraction, we get:

Area of new deck / Area of original deck = 8 / 15

The scale factor is 4/5, which simplifies to 8/10 or 4/5.

Comparing the ratio of the areas to the scale factor, we see that:

Area ratio / Scale factor = (8/15) / (4/5) = (8/15) * (5/4) = 1

Therefore, the ratio of the areas is equal to the scale factor. This makes sense since the area of a triangle is proportional to the square of its dimensions. In this case, the scale factor is applied to both the base and the height, so the area ratio is equal to the scale factor squared, which is 16/25.

Answer:

Step-by-step explanation:

Part A: To find the dimensions of the new deck, we need to scale the base and height of the original deck by a factor of 4:5.

Scaling factor = 4/5

New base = 15 * (4/5) = 12 feet

New height = 9 * (4/5) = 7.2 feet

Therefore, the dimensions of the new deck are 12 feet for the base and 7.2 feet for the height.

Part B: The area of the original deck can be found by using the formula for the area of a triangle:

Area = (1/2) * base * height = (1/2) * 15 * 9 = 67.5 square feet.

The area of the new deck can also be found using the same formula:

Area = (1/2) * base * height = (1/2) * 12 * 7.2 = 43.2 square feet.

Part C: The ratio of the areas of the two decks can be found by dividing the area of the new deck by the area of the original deck:

Ratio of areas = (43.2 / 67.5) ≈ 0.64

The scale factor is 4:5 or 0.8.

Comparing the ratio of areas to the scale factor:

Ratio of areas / scale factor = (0.64 / 0.8) = 0.8

The ratio of the areas divided by the scale factor is equal to 0.8, which makes sense since the scale factor is the factor by which the dimensions were scaled up, and the ratio of areas tells us how much the area was scaled up.

correct option is d. -4x⁵+7x⁴-x³+3x²+10x+14. The leading coefficient is -4.

The given polynomial is -x³+10x-4x⁵+3x²+7x⁴+14.

To write the polynomial in standard form, we write the terms in decreasing order of their exponents i.e. highest exponent first and lowest exponent at last.-4x⁵+7x⁴-x³+3x²+10x+14

Hence, the correct option is d.

-4x⁵+7x⁴-x³+3x²+10x+14. The leading coefficient is -4.

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Answer:

yep i am very tireddddfdf

Answer:

YEAAA I'm like super tired for no reason, even though I really didn't do anything today :/

Answer:

with what you didnt put a question anywhere

The area of the triangle is 19.5 square units.

To find the area of the triangle, we can use the formula:

Area = (1/2) * base * height

where the base and height are the distance between two of the vertices of the triangle. We can choose any two vertices to use as the base and height, as long as we use the same units for both. Let's choose (-3,2) and (6,-2) as our base.

The distance between (-3,2) and (6,-2) can be found using the distance formula:

d = \(\sqrt((6 - (-3))^2 + (-2 - 2)^2)\)
d = \(\sqrt(81 + 16)\)
d = \(\sqrt(97)\)

Now we need to find the height of the triangle. The height is the perpendicular distance from the third vertex (3,5) to the line containing the base (-3,2) and (6,-2). We can use the formula:

height = \(|Ax + By + C| / \sqrt(A^2 + B^2)\)

where A, B, and C are the coefficients of the line in the standard form Ax + By + C = 0, and x and y are the coordinates of the third vertex. We can find the coefficients of the line by using the two points (-3,2) and (6,-2):

A = 2 - (-2) = 4
B = (-3) - 6 = -9
C = 6*(-2) - (-3)*2 = -18

Now we can plug in the values to find the height:

height = \(|4*3 - 9*5 - 18| / \sqrt(4^2 + (-9)^2)\)
height = \(39 / \sqrt(97)\)

Finally, we can plug in the base and height to find the area:

Area = \((1/2) * \sqrt(97) * (39 / \sqrt(97))\)
Area = 19.5

Therefore, the area of the triangle is 19.5 square units.

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Answer:

Step-by-step explanation:

r=6.7

The original recipe had 0.9 cups of bananas.

Using only fresh ingredients, strawberry banana smoothie is a simple, nutritious dish. It is creamy, sweet, nutritious, and dairy- or dairy-free can be used to make it. The ideal summertime smoothie. Putting the strawberries, frozen banana, milk, and yoghurt in a blender and mixing until smooth and creamy is all that is required to make it.

Cups of strawberries = 1.75

No. of cups added of banana = 1/2

                                            = 0.5

No. of cups of banana smoothie have = 14.

The original recipe had = 1.4 - 0.5

                                   = 0.9

Hence, the original recipe had 0.9 cups of bananas.

Correct Question :

to make a strawberry banana smoothie, a recipe calls for 1.75 cups of strawberries and some bananas. to make the recipe taste more like banana, 1/2 cup more banana was added to the blender. the smoothie now has 1.4 cups of bananas. how many cups of bananas were in the original recipe?

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Answer:

72

Step-by-step explanation:

A person can read 24 pages in 1/3 hour.  There are 3 * 1/3 hours in 1 hour.

So, the person can read 24 * 3 = 72 pages in one hour.

Answer: 236 inches

Step-by-step explanation:

To find the total length, all we have to do is add together the mixed fractions. First, let's change the mixed fractions to improper fractions.

\(98\frac{1}{4}=\frac{393}{4}\)

\(39\frac{1}{2}=\frac{79}{2}\)

\(\frac{393}{4} +\frac{393}{4} +\frac{79}{2}\)         [make sure denominator is the same]

\(\frac{393}{4} +\frac{393}{4} +\frac{158}{4}\)        [add]

\(\frac{944}{4}\)                           [divide]

\(236\)

Now, we know that the total length is 236 inches.

Answer:

maybe 223 degrees

Step-by-step explanation:

Answer:

\(\huge \boxed{{10x^2 + 12x \mathrm{\ units^2 }} }\)

Step-by-step explanation:

area of shaded region = area of whole rectangle - area of unshaded region

Area of a rectangle is length × width.

A = 5x(3x+2) - (x(5x-2))

Expand brackets.

A = 15x² + 10x -(5x² - 2x)

Distribute negative sign.

A = 15x² + 10x - 5x² + 2x

Combine like terms.

A = 10x² + 12x

The answer would be 28

Answer:

8/(2/7)=(8×7)/2=4×7=28

Step-by-step explanation:

Time=distance/speed

67÷110

=36' 32sec

Answer:  February is the month that serves as the counterexample.

Step-by-step explanation: February has 28 days most years, 29 days in a leap year. So it is an an example that disproves the statement that all months have at least 30 days.

\(\dfrac{5-i}{4+3i}=\dfrac{(5-i)(4-3i)}{(4+3i)(4-3i)}=\dfrac{20-15i-4i-3}{16+9}=\dfrac{17-19i}{25}=\dfrac{17}{25}-\dfrac{19}{25}i\)

a b c d e f g h I love you will you marry me

Therefore, visually interpreting histograms can be a powerful tool for data analysis, but it is important to be aware of their strengths and limitations.

Histograms are an effective way to display data graphically. They are used to show how often certain values or ranges of values appear in a data set. Visual interpretation of histograms has many strengths and limitations. Some of the strengths of visually interpreting histograms are that they are easy to read and understand, they provide a clear picture of how the data is distributed, and they can help identify outliers or gaps in the data. However, some of the limitations of visually interpreting histograms are that they can be influenced by the number of bins chosen, the way the data is grouped, and the choice of the scale used. Therefore, it is important to carefully consider these factors when interpreting a histogram. In conclusion, visually interpreting histograms can be a powerful tool for data analysis, but it is important to be aware of their strengths and limitations.

Therefore, visually interpreting histograms can be a powerful tool for data analysis, but it is important to be aware of their strengths and limitations.

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The results of the three cases are listed below:

In this problem we find three cases of composition between two functions, each of which has to be evaluated. The definition of the composition between the two functions f and g is presented below:

f ° g (x) = f( g(x) )                 (1)

Where x is the input variable of the composite function.

In other words, the input of the function f is the output of the function g.

Now we proceed to find the expressions of the each of the two cases:

Case 1

g ° f (x) = g( f(x) )

g ° f (x) = 4 · (2 · x + 2) - 3

g ° f (x) = 8 · x + 8 - 3

g ° f (x) = 8 · x + 5

Case 2

h ° g (- 3 · x) = h [g (- 3 · x)]

h ° g (- 3 · x) = 3 · [4 · (- 3 · x) - 3]

h ° g (- 3 · x) = 3 · (- 12 · x - 3)

h ° g (- 3 · x) = - 36 · x - 9

Case 3

f ° g (- 3) = f( g(- 3) )

f ° g (- 3) = 3 · [2 · (- 3) + 1] + 1

f ° g (- 3) = 3 · (- 5) + 1

f ° g (- 3) = - 15 + 1

f ° g (- 3) = - 14

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