Q8 The figure 3 below shows a metallic ball passing through a ring before being heated.

(a) Describe how the particles inside the ball are moving at the start of experiment.

(b) When the ball is heated using a Bunsen burner, it no more passes through the ring. Explain, in terms of particles, why the ball does not pass through the ring after being heated.

(c) Define radiation.

Answer:

\(magnetite\)

\(hope \: helps...\)

"Fluid intelligence involves being able to think and reason abstractly and solve problems. This ability is considered independent of learning, experience, and education. Examples of the use of fluid intelligence include solving puzzles and coming up with problem-solving strategies."  

- Verywell Mind

Answer:

  L₀ = L_f ,  K_f < K₀

Explanation:

For this exercise we start as the angular momentum, with the friction force they are negligible and if we define the system as formed by the disk and the clay sphere, the forces during the collision are internal and therefore the angular momentum is conserved.

This means that the angular momentum before and after the collision changes.

Initial instant. Before the crash

        L₀ = I₀ w₀

Final moment. Right after the crash

        L_f = (I₀ + mr²) w

we treat the clay sphere as a point particle

how the angular momentum is conserved

       L₀ = L_f

       I₀ w₀ = (I₀ + mr²) w

       w = \(\frac{I_o}{I_o + m r^2}\)   w₀

having the angular velocities we can calculate the kinetic energy

starting point. Before the crash

        K₀ = ½ I₀ w₀²

final point. After the crash

        K_f = ½ (I₀ + mr²) w²

sustitute

        K_f = ½ (I₀ + mr²)  ( \(\frac{I_o}{I_o + m r^2}\)   w₀)²

        Kf = ½  \(\frac{I_o^2}{ I_o + m r^2}\)   w₀²

we look for the relationship between the kinetic energy

        \(\frac{K_f}{K_o}\)=   \(\frac{I_o}{I_o + m r^2}\)

       \(\frac{K_f}{K_o } < 1\)

      K_f < K₀          

we see that the kinetic energy is not constant in the process, this implies that part of the energy is transformed into potential energy during the collision

Answer:

1) 327

2) 3

3) 109

------------

now I'm not 100% sure #4-6 are correct, but if 4 is right then 5 and 6 are, too.

4) 1074

5) 1074 + 109t

6) 2382

Explanation:

Answer:

B

Explanation:

The enzime's active site bindes to the substrate.... when an enzime binds to a substrate it forms a enzime-substrate complex

When an enzyme and a substrate interact at an active site, the products are bound irreversibly. Therefore, option B is correct.

Enzymes can be described as proteins that act as biological catalysts by accelerating reactions. The enzymes may act on the molecules called substrates, and the enzyme changes the substrates into different molecules known as products.

All metabolic processes require enzyme catalysis to occur at rates fast enough to sustain life. Metabolic pathways will depend upon enzymes to catalyze each step.

Enzymes catalyze more than 5,000 biochemical reaction types. Enzymes enhance reaction rates by lowering their activation energy. Some enzymes make their conversion of substrate to product occurs.

Enzymes are much larger than substrates, they can have 62 amino acid residues to over 2,500 residues in the animal fatty acid synthase. The catalytic site is located next to binding sites where residues are oriented to the substrates. The catalytic site and binding site compose the active site.

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Answer:

write something like after the spacecraft launched all of the potential energy transformed into kinetic energy causing the spacecraft to go at an abnormal spped.

Explanation:

Answer:

the answer is b

Explanation:

The earthquake would occur 13 minutes before 10:05 a.m. which will be at 9.52 am.

The p-waves travel with a constant velocity of 7 km/s

The time can be calculated by using the formula

t = d / v

where

T1 =  10:05 a.m

d is the distance they take to travel from the epicenter

v is the speed of the p-waves

On average, the speed of p-waves is

v = 7 km/s

d = 5600 km (given)

Substituting the values in the formula;

t = d / v

t = 5600 ÷ 7

t = 800 seconds

Converting into minutes,

t = 800 ÷ 60

t = 13.3

≈ 13 mins

T1 -  13 mins = T2

10:05 - 13 mins = 9.52 am

It means the earthquake occurred prior 13 minutes, that is at 9.52 am.

Therefore, the earthquake occurred at 9.52 am.

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A current of a 6 flows through a light bulb for 12 s. The total charge that passes through the light bulb during the given time is 72 coulombs.

To calculate the total charge that passes through the light bulb, we need to use the formula Q = I * t, where Q represents the charge in coulombs, I represents the current in amperes, and t represents the time in seconds.

Step 1: Identify the known values:

Current (I) = 6 amperes

Time (t) = 12 seconds

Step 2: Calculate the charge using the formula:

Q = I * t

Step 3: Substitute the known values into the formula:

Q = 6 amperes * 12 seconds

Q = 72 coulombs

Therefore, the total charge that passes through the light bulb during the given time is 72 coulombs.

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Answer:

B is correct. Electrons are added to the rod.

Explanation:

Because the fur lose electrons to the rode and because positively charged while the rod because negative

Resultant force direction = 11.08 degrees counter-clockwise from the positive x-axis.

In order to address this issue, we must first divide these forces into their corresponding x and y components, which we must then combine to determine the final force.

Given the magnitude of force (F1) = 32kN

The angle of direction (θ1) = 30°

F1x = -32k x cos(30°) = -27.7kN

F1y = -32 x sin(30°) = -16kN

Given a triangle, let cos(θ) = 5/13 = 0.99 then θ = 67.3°

The magnitude of force F2 = 26kN

The angle of direction (θ2) = 0.99°

F2x = -26 x cos(67.3°) = 10.03kN

F2y = 26 x sin(67.3°) = 23.9kN

Frx = F1x + F2x = -37.73kN

Fry = F1y + F2y = 7.9kN

Let the resultant force = Fr then,

Fr^2 = Frx^2 + Fry^2

Fr^2 = (-37.73)^2 + (7.9)^2

Fr = √1423.55+62.41 = √1485.96 = 38.5kN

Hence the resultant force = 38.5kN

θ = tan^-1(Fry/Frx) = tan^-1(7.9/-37.73) = -11.08°

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Answer: A : 250 is the answer

B; The frequency of a wave is the number of complete oscillations (cycles) made by the wave in one second.

Instead, the wavelength is the distance between two consecutive crests (highest position) or 2 troughs (lowest position) of the wave.

In this problem, we are told that the leaf does two full up and down bobs: this means that it completes 2 full cycles in one second. Therefore, its frequency is

where  is called Hertz (Hz). So, the correct answer is

Explanation:

#Wavespeed

#1

\(\\ \rm\Rrightarrow v=\nu\lambda=500(3)=1500m/s\)

#2

\(\\ \rm\Rrightarrow v=2(0.4)=0.8m/s\)

#Wavelength

#1

\(\\ \rm\Rrightarrow \lambda=\dfrac{v}{\nu}=\dfrac{3}{2}=1.5m\)

#2

\(\\ \rm\Rrightarrow \lambda= \dfrac{1450}{40000}=0.03625m\)

#Frequency

\(\\ \rm\Rrightarrow \nu=\dfrac{v}{\lambda}=\dfrac{8}{20}=0.4Hz\)

#2

\(\\ \rm\Rrightarrow \nu=\dfrac{3\times 10^8}{15\times 10^{-2}}=0.2\timee 10^{10}=2\times 10^9Hz\)

If the dog walked at a constant speed the whole way, the graph of the dog's position versus time would be a straight line. This is because the dog's velocity (which is the derivative of position with respect to time) would be constant, and the acceleration (which is the derivative of velocity with respect to time) would be zero.

A straight line on a position-time graph indicates that the object is moving at a constant velocity. The slope of the line would be equal to the velocity of the dog.

If the graph is a horizontal line, it would indicate that the dog is at rest. If the line slopes upward, the dog is moving in the positive direction (for example, to the right in a position-time graph), and if the line slopes downward, the dog is moving in the negative direction.

In all, A constant speed means a constant velocity and the line is a straight line with a particular slope.

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Answer:

1. Atomic number

2. element symbol

3. element name

4. atomic mass

5 and 6 are the same as the diagram above... just rewrite using data

Answer:

The speed and direction of the tangled players is 2.89 m/s towards right.

Explanation:

Given;

mass of the player heading right, m₁ = 40 kg

initial velocity of the player heading right, u₁ = 9.0 m/s

mass of the player heading left, m₂ = 50 kg

initial velocity of the player heading left, u₂ = -2.0 m/s

let the speed of the tangled players = v

Apply the law of conservation of linear momentum;

m₁u₁ + m₂u₂ = v(m₁ + m₂)

(40 x 9) + (50 x - 2) = v(40 + 50)

360 - 100 = v(90)

260 = v(90)

v = 260 / 90

v = 2.89 m/s (towards right, since it is in position direction)

Therefore, the speed and direction of the tangled players is 2.89 m/s towards right.

Answer:

Explanation:

a ) Restoring force in special spring F = k x³

let it is stretched by length l and it is further stretched by dl .

work done on spring in stretching by dl

= F dl

= k l³ dl

work done in stretching by A

= ∫k l³ dl between limit 0 to A

= k [ l⁴ / 4 ] between limit 0 to A

= k A⁴ / 4 ;

b )

Let v be the maximum speed attained ,

kinetic energy of mass = potential energy of spring

1/2 M v² = k A⁴ / 4

v² = kA⁴ / 2

v = A² √( k/2 )

c ) Let the required displacement be d .

potential energy = k d⁴ / 4

at displacement d , potential energy and kinetic energy are equal so potential energy = 1 /2 of total potential energy = 1/2 x k A⁴ / 4

= k A⁴ / 8

So

k A⁴ / 8  = k d⁴ / 4

\(d = A\times ( \frac{1}{2} )^\frac{1}{4}\)

Answer:

Option(A) is the correct answer to the given question .

Explanation:

Firstly we have to find the corresponding weight of sphere ,cone,cube ,pyramid respectively .

\(Weights\ of\ sphere\ =\ 0.9*3\\= 2.7g \\Weight \ of \ cone\\=\ 0.7*4\\= 2.8g, \\Weight \ of\ cube\ \\=\ 0.4*6\\= 2.4g,\\Weight\ of\ pyramid = \0.6*5\\= 3g\)

As We see that the weight of pyramid is high then cone then sphere then cube

Therefore Resistance order is  pyramid, cone, sphere, cube  .

So Option(A) is correct answer .

Answer:

All magnets have two poles: the North Pole and the South Pole.

Magnets attract ferromagnetic materials such as iron, nickel, and cobalt.

The magnetic force of a magnet is stronger at its poles than in the middle.

A freely suspended magnet always points in North-South direction.

Hope this helps

Answer:

D

Explanation:

plz plz this answer is good i hope

The Falcon 9 rocket is so important in today's space exploration world because It's a reusable rocket and has saved money by being reused over 60 times already.

option D.

The Falcon 9 rocket, is developed by SpaceX, and it holds  a significant importance in today's space exploration world due to several key features and achievements, and some of the importance include the following;

From the given options, we can conclude that the Falcon 9 rocket is so important in today's space exploration world because It's a reusable rocket and has saved money by being reused over 60 times already.

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The temperature of the air mass when it has risen to a level at which atmospheric pressure is only 8.70×10⁴ Pa is approximately 14.3°C.

Using the ideal gas law, we can write: PV = nRT, where P is the pressure, V is the volume, n is the number of moles of gas, R is the gas constant, and T is the absolute temperature. Since the mass of air is not changing, we can write: PV = constant.

Applying this to the situation where the air mass rises to a level where the pressure is 8.70×10⁴ Pa, we get:

Dividing the second equation by the first and using the fact that γ=Cp/Cv=1.40 for air, we get:

Solving for T2, we get:

Thus, the temperature of the air mass when it has risen to a level at which atmospheric pressure is only 8.70×10⁴ Pa is approximately 14.3°C.

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Answer:

(a) The resistance of 25m of wire is 3 ohms

(b) the length of this wire that has resistance 22 ohms is 183.33 m

Explanation:

Given;

resistivity of the wire, ρ = 0.12 ohms per meter

(a) The resistance of 25m of wire is calculated as follows;

\(R = \rho L\\\\R = 0.12 \ \frac{ohms}{m} \times 25\ m\\\\R = 3 \ ohms\)

(b) the length of this wire that has resistance 22 ohms is calculated as;

\(L = \frac{R}{\rho} \\\\L = \frac{22 \ ohms }{0.12 \ ohms/m} = 183.33 \ m\)

The density of the second liquid is 0.812 g/cm³

To calculate the density of the second liquid, we need to use the principle of displacement. The mass of the liquid can be found by subtracting the mass of the empty density bottle from the mass of the bottle filled with the liquid. Therefore, the mass of the liquid is:

mass of liquid = mass of bottle + liquid - mass of empty bottle

mass of liquid = 39.84g + x - 18.00g

where x is the mass of the liquid.

We can now use the density formula, which is:

density = mass/volume

The volume of the liquid is equal to the volume of the density bottle that is filled with the liquid, which can be calculated by subtracting the volume of the empty bottle from the volume of the bottle filled with the liquid. Therefore, the volume of the liquid is:

volume of liquid = volume of bottle filled with liquid - volume of empty bottle

We can now substitute this expression into the density formula to get:

density of liquid = mass of liquid / (volume of bottle filled with liquid - volume of empty bottle)

We know that the density of water is 1000 kg/m³, which is equal to 1 g/cm³. We can use this to find the volume of the liquid by dividing the mass of water by its density:

volume of water = mass of water / density of water

volume of water = 44.00g / 1 g/cm³

volume of water = 44.00 cm³

Now, we can calculate the volume of the density bottle filled with the second liquid by using the principle of displacement:

volume of bottle filled with liquid = volume of water - volume of liquid

volume of bottle filled with liquid = 44.00 cm³ - (39.84g - 18.00g) / 1 g/cm³

volume of bottle filled with liquid = 44.00 cm³ - 21.84 cm³

volume of bottle filled with liquid = 22.16 cm³

Finally, we can substitute these values into the density formula to get:

density of liquid = x / 22.16 cm³

Solving for x, we get:

x = density of liquid x 22.16 cm³

Substituting x back into the mass equation, we get:

mass of liquid = 39.84g + (density of liquid x 22.16 cm³) - 18.00g

Solving for the density of the liquid, we get:

density of liquid = (mass of liquid - 21.84g) / 22.16 cm³

Substituting the given values, we get:

density of liquid = (39.84g - 21.84g) / 22.16 cm³ = 0.812 g/cm³

In conclusion, the density of the second liquid is 0.812 g/cm³. This value is less than the density of water, which means that the second liquid is less dense than water and will float on top of water.

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AnswerAmontons's law. If the temperature is increased, the average speed and kinetic energy of the gas molecules increase. ... If the gas volume is decreased, the container wall area decreases and the molecule-wall collision frequency increases, both of which increase the pressure exerted by the gas (Figure 1).:

Explanation:

The child's speed at the lowest point is 5.42 m/s.

At the highest point of the swing, the child is momentarily at rest and has only potential energy. At the lowest point, the child has only kinetic energy.

Using the conservation of mechanical energy, we can write:

Potential energy at highest point = Kinetic energy at lowest point

mgh = (1/2)mv²

where m is the mass of the child, g is the acceleration due to gravity, h is the height of the swing at the highest point, and v is the speed of the child at the lowest point.

First, we need to find the height of the swing at the highest point. Since the swing is supported by two chains, the height of the swing at the highest point is half the length of the chains:

h = (1/2)3.00 m = 1.50 m

Next, we can solve for the child's speed at the lowest point:

mgh = (1/2)mv²

40.0 kg * 9.81 m/s² * 1.50 m = (1/2) * 40.0 kg * v²

588 J = 20.0 kg * v²

v² = 29.4 m²/s²

v = 5.42 m/s

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A concave mirror forming a larger, virtual image is the best interpretation of the ray diagram shown.

By splitting a hollow sphere into parts, painting the external surface, and using the internal surface as the reflecting surface, a mirror can be created. These mirrors are concave mirrors.

Light converges at a single point when it strikes and reflects back from the concave mirror's reflecting surface. The term "converging mirror" is occasionally used to describe it because of this. When the concave mirror is placed very close to the object, a magnified, upright, and virtual picture can be obtained. However, as the distance between the item and the mirror grows, the size of the picture diminishes, producing a genuine and inverted image instead. A little image may be created by the concave mirror.

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1) The force acting on the object during the time interval 0-3 seconds is 1/3 N.

2) The force acting on the object during the time interval 6-10 seconds is -0.5 N.

3) There is no time interval in which no force acts on the object.

(i) Force acting on the object in time interval 0-3 seconds. Force acting on the object is equal to the product of its mass and acceleration, i.e.,F = ma.

In the given velocity-time graph, the acceleration of the object can be determined by determining the slope of the velocity-time graph from 0 to 3 seconds.

Slope = (change in velocity) / (change in time)= (20-0) / (3-0) = 20/3 m/s^2

Acceleration, a = slope= 20/3 m/s^2

Mass of the object, m = 50 g = 0.05 kg

∴ Force acting on the object, F = ma= 0.05 × 20/3= 1/3 N.

Therefore, the force acting on the object during the time interval 0-3 seconds is 1/3 N.

(ii) Force acting on the object in time interval 6-10 seconds. Similar to the first question, the force acting on the object in time interval 6-10 seconds can be determined by determining the acceleration of the object during this time interval.

The slope of the velocity-time graph from 6 seconds to 10 seconds can be determined as follows:

Slope = (change in velocity) / (change in time)= (-20-20) / (10-6) = -40/4= -10 m/s^2 (negative sign indicates that the object is decelerating)

Mass of the object, m = 50 g = 0.05 kg

∴ Force acting on the object, F = ma= 0.05 × (-10)= -0.5 N.

Therefore, the force acting on the object during the time interval 6-10 seconds is -0.5 N.

(iii) Time interval in which no force acts on the object. There is no time interval in which no force acts on the object. This is because, as per Newton's first law of motion, an object will continue to remain in a state of rest or uniform motion along a straight line unless acted upon by an external unbalanced force.In other words, if the object is moving with a constant velocity, there must be a force acting on the object to maintain its motion.

Therefore, there is no time interval in which no force acts on the object.

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