Q5- The size of a wind turbine rotor (diameter in m) is 5 m. Assume that the air density is p =1.225 kg/m³, Cp = 16/27 for efficiency n = 1, wind velocity 4 m/s. a) Find the electrical power in a steady wind (at hub height) of 4 m/s. b) Find the electrical power for n = 0,65. 24 h/day, 1,9 TL/kWh). respectively. An engineer thought c) Assume the turbine is working under this condition all month. Estimate monthly energy production. d) Calculate the monthly saving (produced energy price) (30 days/month, e) The initial and salvage cost of this turbine is 20000 TL and 10000 TL, to select a bigger radius turbine with initial cost and salvage cost of this turbine is 50000 TL and 20000 TL, respectively. It's estimated to produce 20% more energy annually. Compare the two cases for i=10%, n=10 year with annual cost analysis method. FPR.in = = $ [a+y=1] = $ * Fax FSR (1 i)^ R=S R( )=P()× FPR + Operating cost-Profits ( ) -S( ) × FSR f) Find the annual CO₂ footprint reduction for lowest cost case. (Electric 500 g/kWh)
Answers
a) The electrical power in a steady wind (at hub height) of 4 m/s is given as follows:
Given diameter of wind turbine rotor = d = 5 mAir density = p = 1.225 kg/m³Efficiency of turbine = n = 1Coefficient of power = Cp = 16/27Wind velocity = V = 4 m/sThe cross-sectional area swept by the turbine, A = πd²/4 = 19.63 m²The power captured by the turbine is given by:
P = (1/2) x p x A x V³ x Cp = (1/2) x 1.225 x 19.63 x (4)³ x 16/27= 15.456 kWb) The electrical power for n = 0.65 is given as follows Efficiency of turbine, n = 0.65The power captured by the turbine is given by:
P = (1/2) x p x A x V³ x Cp = (1/2) x 1.225 x 19.63 x (4)³ x 0.65= 10.03 kW24 h/day, 1,9 TL/kWh = 24 x 1.9 = 45.6 TL/kWhc) The monthly energy production is estimated to be given byMonthly energy production = 30 days x 24 hours/day x 15.456 kW = 11,155.84 kWh
d) The monthly saving (produced energy price) is calculated as follows Monthly saving = Monthly energy production x 45.6 TL/kWh= 11,155.84 x 45.6= 509,797.5 TL The initial and salvage cost of the first turbine is as follows:
Initial cost of first turbine = 20,000 TLSalvage cost of first turbine = 10,000 TL.
The initial and salvage cost of the second turbine with 20% more energy production annually is as follows:
Initial cost of second turbine = 50,000 TLSalvage cost of second turbine = 20,000 TLThe cost of the first turbine with i = 10% for n = 10 years is calculated as follows:R = 1 - (1+i)^-n = 0.647At the end of ten years, the salvage value of the first turbine is given as follows:Salvage value = S = 10,000 The equivalent uniform annual cost, EAC1 is given as:EAC1 = P(A/F,i,n) + S(A/P,i,n)where A/F, i, n = 0.163EAC1 = 20,000(0.163) + 10,000(0.105) = 4,450 TL.Yearly energy production from the first turbine = 11,155.84 kWhThe cost of the second turbine with i = 10% for n = 10 years is calculated as follows:
R = 1 - (1+i)^-n = 0.647At the end of ten years, the salvage value of the second turbine is given as follows:Salvage value = S = 20,000The equivalent uniform annual cost, EAC2 is given as:EAC2 = P(A/F,i,n) + S(A/P,i,n)where A/F, i, n = 0.163EAC2 = 50,000(0.163) + 20,000(0.105) = 10,725 TLYearly energy production from the second turbine = 1.2 x 11,155.84 = 13,387.008 kWh.The cost of energy production is the sum of the equivalent uniform annual cost and the operating cost. The operating cost of the turbine is zero. The cost of energy production from the first turbine is given by:
Cost of energy production from the first turbine = EAC1/11,155.84= 0.398 TL/kWhThe cost of energy production from the second turbine is given by:Cost of energy production from the second turbine = EAC2/13,387.008= 0.802 TL/kWhThe first turbine is the better option since the cost of energy production is lower than that of the second turbine.e) The annual CO₂ footprint reduction for the lowest cost case is calculated as follows:
CO₂ emissions from conventional sources = 500 g/kWhThe CO₂ footprint reduction is given by:CO₂ footprint reduction = Annual energy production x CO₂ reduction factorAnnual energy production = 11,155.84 kWhCO₂ reduction factor = (1000 g/kg) / (1 kg/1000 Wh) x 500 g/kWh= 0.5 kg/kWhCO₂ footprint reduction = 11,155.84 x 0.5= 5,577.92 kg CO₂/annumAbout WindWind is the movement of air from areas of high pressure to areas of low pressure. The formation of wind direction occurs due to differences in air pressure in two different places. Wind flows from places with high air pressure to places with low air pressure. What is the difference between wind and air? Wind is air that moves or blows at a certain speed, while air is a mixture of gases that are on the surface of the earth. So it can be said simply that wind is moving air, while air is wind that covers the earth.
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Related Questions
You push on a car and it doesn't move. What is true about inertia in this case?
a) The inertia is changing
b) The inertia of the car is too great
c) the inertia of the person is equal to the car
d) There is no inertia because there isn't any movement
Answers
Answer:
the answer is D
Explanation:
inertia is movement
Calculate the orbital period of a satellite circling the Earth at an altitude of 3500 km. Answer to the nearest minute. Show your work.
Answers
The orbital period of the satellite circling the Earth at an altitude of 3500 km is 163 minutes
How do i determine the orbital period?The orbital period for the satellite circling the Earth at an altitude of 3500 km can be obtained as follow:
Altitude = 3500 kmRadius of earth = 6400 KmSemi-major axis (a) = Radius + Altitude = 6400 + 3500 = 9900 Km = 9900 × 1000 = 9900000 mGravitational constant (G) = 6.67×10¯¹¹ Nm²/Kg²Mass of earth (M) = 5.987×10²⁴ KgOrbital period (T) = ?T² = (4π² / GM) × a³
T² = [(4 × 3.14²) / (6.67×10¯¹¹ × 5.987×10²⁴)] × 9900000³
Take the square root of both sides
T = √[((4 × 3.14²) / (6.67×10¯¹¹ × 5.987×10²⁴)) × 9900000³]
T = 9789.15 s
Divide by 60 to express in minutes
T = 9789.15 / 60
T = 163 minutes
Thus, we can conclude that the orbital period of the satellite is 163 minutes
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A 20.0-kg cannon ball is fired from a cannon with a muzzle speed of 100 m/s at an angle of 20.0° with the horizontal. Use the conservation of energy principle to find the maximum height reached by ba
Answers
A 20.0 kg cannonball is fired from a cannon with a muzzle speed of 100 m/s at an angle of 20.0°. Using conservation of energy, the maximum height reached by the cannonball is approximately 510.2 meters.
A cannon ball weighing 20.0 kg is launched from a cannon with an initial velocity of 100 m/s at an angle of 20.0° above the horizontal.
To determine the maximum height reached by the cannonball using the conservation of energy principle, we consider the conversion of kinetic energy into gravitational potential energy.
Initially, the cannonball has only kinetic energy, given by the equation KE = (1/2)mv², where m is the mass and v is the velocity.
At the highest point of its trajectory, the cannonball has no vertical velocity, meaning it has no kinetic energy but possesses gravitational potential energy, given by the equation PE = mgh, where h is the height and g is the acceleration due to gravity (approximately 9.8 m/s²).
Using the conservation of energy, we equate the initial kinetic energy to the maximum potential energy:
(1/2)mv² = mgh
Canceling the mass and rearranging the equation, we find:
v²/2g = h
Plugging in the given values, we have:
(100²)/(2*9.8) = h
Simplifying the equation, we find:
h ≈ 510.2 m
Therefore, the maximum height reached by the cannonball is approximately 510.2 meters.
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If a ray makes an angle of 20° with the mirror then its angle of incidence is ____.
Answers
70 degrees
90 - 20 since angle of incidence is the complement of the angle it strikes with.
If 15 kW of power from a heat reservoir at 500 K is input into a Carnot cycle heat engine with an efficiency of 37%, what is the power output
Answers
The power output of the Carnot cycle is 5.55 kW.
Given:
Power input = 15 kW
Efficiency = 37% = 0.37
Heat reservoir temperature, T1 = 500 K
To find:
Power output of the Carnot cycle,
P2 Formula: The efficiency of Carnot cycle is given by
η = (T1 − T2) / T1
where T1 is the temperature of the high-temperature reservoir and T2 is the temperature of the low-temperature reservoir.
Using this formula, we can rearrange it to find T2 as follows:
T2 = T1 − ηT1
Now, the power output of the Carnot cycle is given by
P2 = ηP1
where P1 is the power input into the cycle.
Substituting the values in the above equations,
T2 = 500 − 0.37 × 500 = 500 − 185 = 315 KP2 = 0.37 × 15 = 5.55 kW
Therefore, the power output is 5.55 kW.
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A sound wave has a frequency of 1.5 Hz while traveling at a speed of 50 m/s. What is the wavelength?
Answers
Answer:
33.3m
Explanation:
Recall that for a regular wave, the relationship between, wavelength, frequency and velocity (speed) is given by :
v = fλ,
where:
v = velocity (speed) of the wave = 50m/s
f = frequency of the wave = 1.5 Hz
λ = wavelength (we are asked to find this)
simply substitute the given values into the equation:
v = fλ
50 = 1.5 λ,
λ = 50/1.5
λ = 33.3m
What is the scientific saying/principle that explains why a hammer and a screwdriver, both made of steel, are used for different tasks?
Answers
Hammer and screwdriver perform different tasks because they are both simple machines.
A machine is simply a device that can be used to perform a task. This machine can be any physical system or device designed to perform a specific task.
The efficiency of the machine describes the easy with which each machine or tool is able to use input power to overcome a task.
Machines are designed to overcome a particular task with little effort in order to increase its efficiency.
Hammer and screwdriver, are both examples of simple machines.
Thus, Hammer and screwdriver perform different tasks because they are both simple machines.
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What is the distance between two objects if one (a 185,000 kg object) experiences a gravitational force of 0.00200 N due to a 225,000 kg object
Answers
Using the gravitational force, the mass of item 1 and object 2, and the Newton's law of gravity calculator, one may calculate the distance between two objects.
How is gravitational distance determined?g = GM/r2, where M is the Earth's mass, r is its radius (or the distance from the Earth's center to where you are standing), and G is the gravitational constant. The gravitational constant is G (without the subscripts), while the speed of light is c.
How is the gravitational force between two objects calculated?By applying Newton's equation, we can accomplish this quite easily: forcegravity is defined as G M m2 separation. Suppose that you weigh 60 kilograms and your colleague weighs 70 kilograms. The center-to-centre distance, r, is 1 m, and the gravitational constant, G, is 6.67 10 -11 newtons square meter kilogram-2.
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2. Look again at the image. Let's now assume that it depicts a girl hugging her father before he
leaves for a tour of duty overseas. How could you use science to study the impact of her father's
departure on her family? (2 points)
Answers
Assume for the moment that it shows a young child embracing her mother before he departs for a tour of service abroad. How would you employ science to analyse her effects.
What subjects does science study?What in physics is an energy?
The definition of energy is ability to do work," which is the capacity to apply a force that causes an item to move. organismal biology the study of sentient creatures Social science is the study of people and society.
How does science benefit you as a learner?photo of How might science be used for research,Students who study science get the chance to learn more about how and how things work. Children can learn about the environment they live in through science.
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Answer: The science I would use to study the impact of the father’s departure from her family would be interpretive sociology.
Explanation: The reason I chose this science is because it focuses on the cause of people’s actions.
As a woman holding her breath swims deeper and deeper beneath the water'r surface, her density ____.
Answers
As a woman holding her breath swims deeper and deeper beneath the water's surface , her density increases.
The density of an object is defined as its mass per unit volume. When a woman holds her breath and dives deeper into the water, the pressure increases as the depth increases. As a result, the volume of air in her lungs decreases, which in turn decreases her overall volume. However, her mass remains constant. Since her density is defined as mass per unit volume, her density increases as her volume decreases, making it easier for her to sink to greater depths.
The density of a human body is slightly less than the density of water, which means that humans tend to float in water. However, when a person holds their breath and swims deeper, the pressure of the water increases, which compresses the person's body slightly and decreases the volume of air in the lungs. This decrease in lung volume reduces the buoyancy force acting on the person's body and makes them more dense, causing them to sink deeper in the water. Additionally, the increased pressure also compresses the body tissues and fluids, which can further increase the person's density. This is why it is important for divers to wear buoyancy compensators or carry weights to help them control their depth while diving.
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What is pitch?
O A measure of the speed of sound
O The highness or lowness of sound
O A characteristic of light
Answers
Answer:
The second one
Answer:
The highness or lowness of sound
Explanation:
8
If you put 100 carbon atoms in a box. How many carbon atoms remain after 2 half-lives or
11460 years? (you might need to review half-lives to answer this question) *
(1 Point)
100 atoms
50 atoms
25 atoms
12 atoms
Answers
Answer:
25 atoms
Explanation:
840 inches to cm show work pls
Answers
A bullet of mass 0.01kg is fired with velocity of [230,0]m/s in to a sack of sand of mass 9.99kg which is swinging from rope. At the moment the bullet hits, the sack has a velocity of [0,0.2]m/s. Workout the velocity of bullet of the sack.
Answers
Answer:
The velocity of the bullet and the sack after the bullet hits the sack is [0.2,0.2] m/s.
Explanation:
To calculate the velocity of the bullet and the sack after the bullet hits the sack, we can use the equation:
vf = (m1 * v1 + m2 * v2) / (m1 + m2)
Plugging in the values given in the question, we get:
vf = (0.01 kg * [230,0] m/s + 9.99 kg * [0,0.2] m/s) / (0.01 kg + 9.99 kg)
Solving for vf, we get:
vf = [0.2, 0.2] m/s
Therefore, the velocity of the bullet and the sack after the bullet hits the sack is [0.2,0.2] m/s.
The initial and final momentum of a body will be conserved during collision. From this concept, the final velocity of the bullet and sack is 2.5 m/s.
What is momentum?Momentum is the product of mass and velocity of a body. During a collision of two bodies, the sum of initial momentum of the two bodies will be equal to the sum of their final momentum.
Given that, mass of bullet = 0.01 Kg
velocity = 2300 m/s
mass of sand sack = 9.99 Kg
velocity = 0.2 m/s
Then sum of initial momentum = (0.01 kg × 2300 m/s) + (9.99 kg × 0.2 m/s) = 24.9 kg m/s.
The final momentum of the combined mass = (9.99 kg + 0.01 kg) v = 24.9 Kg m/s
Thus, final velocity v = 24.9 / ( (9.99 kg + 0.01 kg) = 2.5 m/s
Therefore, the velocity of the bullet and sack after the collision will be 2.5 m/s.
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POSSIBLE POINTS: 1
A 8 Kg block is pulled across a frictionless surface in a straight line to the left with a horizontal force of 3 N to the left for a distance of 2 m. How
much work does the pulling force do on the block? (Include correct units with your answer).
W = FAd
Answers
The work done by the pulling force on the block is 6 joules (J).
What is the work done by a force on an object?The work done by a force on an object is given by the formula:
W = F d cos(θ)
where W is the work done, F is the force applied, d is the displacement of the object, and θis the angle between the force and the displacement vectors.
As per the question, the angle between the force and displacement vectors is zero degrees, since the force and displacement are in the same direction. Therefore, the cosine of theta is 1.
The force applied is 3 N to the left, and the displacement is 2 m to the left.
Therefore, we have:
W = 3 N × 2 m × cos(0) = 6 J
So, the work done by the pulling force on the block is 6 joules (J).
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Derive the following equations for uniformly accelerated motion by graphical method. a) Velocity -time relation b) Position - time relation 3) Position – velocity relation.
Answers
Answer:
a) velocity - time realation
that graph's gradient gives the uniform acceleration
the best time for digging clams (when the low tide is extra low) is during the time of the
Answers
The best time for digging clams, specifically when the low tide is extra low, is during the time of the spring tide.
A spring tide occurs when the Sun, Moon, and Earth align in a straight line, creating a combined gravitational pull that leads to exceptionally high high tides and exceptionally low low tides. This alignment happens during the new moon and full moon phases.
During a spring tide, the tidal range is at its maximum, which means the difference between high tide and low tide is the greatest. The extra-low low tide exposes more of the shoreline, making it an ideal time for clam digging as it provides greater access to the areas where clams are buried in the sand or mud.
It's important to note that the timing of low tides, including extra low tides, varies depending on the specific location and local tidal patterns. Checking tide charts or consulting local authorities can provide accurate information about the best time for clam digging in a particular area.
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on an icy day your worry about parking your car in a driveway
Answers
I need help, what are the steps to solve this , I don’t understand
Answers
If the coefficient of static friction between your sneakers and the ground is 0.800, what is the largest angle incline you could stand on without slipping?
Answers
Answer:
the answer is 71.61°
Explanation:
sorry if im wrong
at terminal velocity what will be relationship between drag force and driving force
Answers
Answer:
The answer to this question is given below in this explanation section.
Explanation:
"relationship between drag force and driving force"
The velocity at any time during the flight depends on the corresponding acceleration of the vehicle and the balance of forces acting of the vehicle.Forces acceleration and velocity are all vector quantities having both a magnitude and a direction.When describing the motion of an object caused by forces,one must account for both the magnitude and direction.The forces present during coasting flights are the drag and the weight.The weight is constant is magnitude and is always directed toward the center of earth.The magnitude of the drag change the square of the velocity.During ascent the drag is in the same direction as the weight .But during descent the drag opposes the weight.
For the descending rocket the next vertical external force F is equal to the difference between the drag D and the weight W:
F=D-W
The impetus power or energy behind something in motion,as in he was clearly the driving force in the new administration This term transfer the force that sets in motion an engine or vehicle to other enterprises.Gravity is the driving force for an object falling towards the ground.
A skate boarder relies on the ground pushing on the sole of her shoe to drive her skateboard along.
It is nighttime, and you dropped your goggles into a swimming pool that is 3.0m deep. If you hold a laser pointer 1.0m directly above the edge of the pool, you can illuminate the goggles if the laser beam enters the water 2.0m from the edge. How far are the goggles from the edge of the pool
Answers
Answer:
The distance of the goggle from the edge of the pool is 4.726 m
Explanation:
The given information are;
The depth of the swimming pool = 3.0 m deep
The height of the laser pointer above the swimming pool edge = 1.0 m
The distance from the pool edge the laser pointer enters the water = 2.0 m
The angle between the pool and the laser = ∅ = tan⁻¹(1/2) = 26.57°
Therefore, the angle of incidence to the vertical \(\theta_i\), = θ - ∅ = 90 - 26.57° = 63.43°
By Snell's law we have;
The ratio of the sin of the angle of incidence to the sin of the angle of refraction is a a constant equal to the ratio of the refractive indices as follows;
\(\dfrac{sin (\theta_i)}{sin (\theta_r} =\dfrac{n_r}{n_i}\)
Where:
\(n_r\) = Refractive index of the refractive medium which is water = 1.33
\(n_i\) = Refractive index of the incidence medium which is air = 1.00
Therefore;
\(\theta_r = sin^{-1} \left (\dfrac{n_i \times sin (\theta_i)}{n_r} \right) = sin^{-1} \left (\dfrac{1\times sin (63.43)}{1.33} \right) = 42.26 ^{\circ}\)
We have that tan(\(\theta_r\)) = (Distance of the goggles from the point directly above the point of incidence of the beam)/(The water depth)
tan(42.26) = (The horizontal distance of the goggles from the point of incidence of the laser on the water surface)/(3.0)
∴ The horizontal distance of the goggles from the point of incidence of the laser on the water surface = 3.0 × tan(42.26) = 2.726 m
The distance of the goggle from the edge of the pool = The horizontal distance of the goggles from the point of incidence of the laser on the water surface + The distance from the edge of the water surface the laser enters the water
The distance of the goggle from the edge of the pool = 2.726 + 2 = 4.726 m
The distance of the goggle from the edge of the pool = 4.726 m.
i have a few questions
multipe choice
8) Kinetic energy is the energy of ________.
9)The potential energy of an object depends on its ________ and its height.
10) The law of ________ of energy states that energy can be neither created nor destroyed, but it can change its form.
11) Stored energy is called ________ energy.
12) When you move your hand or foot, your body has converted potential energy into ________ energy.
13) When coasting while roller skating, you eventually stop due to ________.
please and thank you
Answers
Energy refers to the ability or capacity to do work. Energy can be of various types as follows:
Mechanical energy (kinetic or potential)Electrical energyLight energySolar energyHeat energyKinetic energy is energy possessed by an object because of its motion while potential energy is energy possessed by an object because of its position or its condition.
The law of conservation of energy states that energy cannot be created nor destroyed but can only be transformed i.e. converted from one form to another.
Friction is a force that resists the relative motion or tendency to such motion of two bodies in contact.
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Describe how an oil spill could affect the aquaculture and fishing industries.
Answers
A lever of length 1m has been used to lift a load of 600N by applying an effort of 200N. If load is at 20cm from fulcrum, calculate mechanical advantages, velocity ratio and efficiency
solve numerical problem
Answers
Answer:
1) The Mechanical Advantage of the lever is 3
2) The velocity ratio of the lever is 4
3) The efficiency of the lever is 75%
Explanation:
A lever is a simple machine that is used to lift a heavy load with a little effort or force
The mechanical advantage is the ratio of the force output to the force input
The given parameters of the lever are;
The length of the lever = 1 m
The weight of the load (force output), \(F_r\) = 600 N
The effort applied (force input), \(F_e\) = 200 N
1) The Mechanical Advantage, MA of the lever is given as follows;
\(MA = \dfrac{F_r}{F_e} = \dfrac{600 \ N}{200 \ N} = 3\)
The Mechanical Advantage, MA of the lever = 3
2) The velocity ratio, V.R., is the ratio of the distance moved by the effort, \(L_e\), to the distance moved by the load, \(L_r\)
For the lever, we have;
The distance of the load from the fulcrum, \(L_r\) = 20 cm = 0.2 m
Therefore, we have;
The distance of the effort from the fulcrum, \(L_e\) = 1 m - 0.2 m = 0.8 m
From which we have;
\(V.R.= \dfrac{L_e}{L_r} = \dfrac{0.8 \ m}{0.2 \ m} = 4\)
The velocity ratio of the lever = 4
3) The efficiency, η, is given as follow;
\(\%Efficiency, \, \eta = \dfrac{M.A.}{V.R.} \times 100 = \dfrac{3}{4} \times 100 = 75\%\)
The efficiency of the lever is 0.75 or 75%.
Explanation:
The length of the lever = 1 m
The weight of the load (force output), F_rF
r
= 600 N
The effort applied (force input), F_eF
e
= 200 N
1) The Mechanical Advantage, MA of the lever is given as follows;
MA = \dfrac{F_r}{F_e} = \dfrac{600 \ N}{200 \ N} = 3MA=
F
e
F
r
The length of the lever = 1 m
The weight of the load (force output), F_rF
r
= 600 N
The effort applied (force input), F_eF
e
= 200 N
1) The Mechanical Advantage, MA of the lever is given as follows;
MA = \dfrac{F_r}{F_e} = \dfra
=
200 N
600 N
=3
The Mechanical Advantage, MA of the lever = 3
2) The velocity ratio, V.R., is the ratio of the distance moved by the effort, L_eL
e
, to the distance moved by the load, L_rL
r
For the lever, we have;
The distance of the load from the fulcrum, L_rL
r
= 20 cm = 0.2 m
Therefore, we have;
The distance of the effort from the fulcrum, L_eL
e
= 1 m - 0.2 m = 0.8 m
From which we have;
V.R.= \dfrac{L_e}{L_r} = \dfra
The distance of the load from the fulcrum, L_rL
r
= 20 cm = 0.2 m
Therefore, we have;
The distance of the effort from t
V.R.= \dfrac{L_e}{L_r} = \dfrac{0.8
L
e
=
0.2 m
0.8 m
=4
The velocity ratio of the lever = 4
3) The efficiency, η, is given as follow;
\%Efficiency, \, \eta = \dfrac{M.A.}{V.R.} \times 100 = \dfrac{3}{4} \times 100 = 75\%%Efficiency,η=
V.R.
M.A.
×100=
4
3
×100=75%
The efficiency of the lever is 0.75 or 75
For each beaker, determine how much the temperature changed in the first 100 seconds and how much it changed between 500 and 600 seconds. Compare this to the temperature difference between the beakers at the start of each interval. Value0–100 s interval500–600 s intervalBeaker A temperature changeBeaker B temperature changeTemperature difference between Beaker A and Beaker B at 0 seconds. Temperature difference between Beaker A and Beaker B at 500 seconds
Answers
Calculate the temperature change in each beaker during the course of the first 1 min and the next 500 to 600 seconds. Comparing this to
What does temperature in physics actually mean?
Many people have an obsession with checking a forecast to find out the day's temperature. The average kinetic energy of each molecule in a substance is measured by its temperature. Despite the fact that the two variables are closely related, it differs from heat.
What distinguishes an object's energy from its temperature?
As was mentioned, an object's energy is extensive while its temperature is intense. The block may still be hotter even if the liquid has more energy. (2) "Two things with equal heat in thermal equilibrium" improper use of heat. Energy is transferred by heat. Heat does not 'exist' in an object.
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Once the object hits the water, the forces are balanced and the object will stop. Support your answer with reasoning.
Answers
S.E.A.L Certified Answer ↓↓↓
FALSE...
Explanation:
Once the box hits the water, the forces are balanced (50 N down and 50 N up). However, an object in motion (such as the box) will continue in motion at the same speed and in the same direction. When the box strikes the water, it stops accelerating; yet it does not stop moving
Because:
Once the object hits the water, the forces are balanced and the object will stop. Support your answer with reasoning.
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Infrared telescopes are usually placed on high-flying airplanes or on satellites in space __________
Answers
Answer:
In order to improve visibility
Explanation:
Infrared telescopes are made using infrared cameras that contain infrared detectors which are solid-state and are maintained at very cold (cryogenic) temperatures
Infrared radiation is absorbed by water vapor which is present in the Earth's atmosphere, leading to the limitation of the use of infra red telescopes at high altitudes such as mountains, high flying planes or satellites
during which stage of sleep does most dreaming occur
A. REM
B. stage 4
C. stage 2
D. stage1
Answers
Answer: the answer is A
Explanation:
What happens to the gravitation force between two objects that are 15 m apart, when one of them moves 3 m closer? (1 point).
Answers
Answer: The gravitation force between two objects that are 15 m apart, when one of them moves 3 m closer then it increases by a factor of 1 9/16.
Reason:
Mathematically it can be represented as, F = Gm1m2/r2 Where, F is the Gravitational force between two objects measured in Newton (N). G is the Universal Gravitational Constant with a value of 6.674 × 10-11 Nm2kg-2.
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