Q5). A rock is thrown horizontally at 8 ms¹ off a 100 m high cliff. Calculate a) how long it takes to hit the ground; (2 marks) I​

Answers

Answer 1

Answer:

(a) 4.52 seconds

Explanation:

(a) How long it takes to hit the ground:

We can use the formula: h = 1/2 * g * t^2 where h is the height of the cliff, g is the acceleration due to gravity (9.8 m/s^2) and t is the time it takes to hit the ground.

Rearranging the formula, we get: t = sqrt(2h/g).

Plugging in the values, we get: t = sqrt(2*100/9.8) = 4.52 seconds.

(b) Impact velocity:

We can use the formula: v = u + at where v is the final velocity, u is the initial velocity (8 m/s), a is the acceleration due to gravity (-9.8 m/s^2) and t is the time it takes to hit the ground.

Plugging in the values, we get: v = 8 - 9.8*4.52 = -43.96 m/s.

The negative sign indicates that the velocity is in the opposite direction to the initial velocity.

(c) How far out from the cliff it lands:

We can use the formula: d = ut + 1/2 * a * t^2 where d is the distance travelled, u is the initial velocity (8 m/s), a is the acceleration due to gravity (-9.8 m/s^2) and t is the time it takes to hit the ground.

Plugging in the values, we get: d = 8*4.52 + 1/2 * -9.8 * 4.52^2 = 176.8 meters.

So, the answers are: (a) 4.52 seconds (b) -43.96 m/s (c) 176.8 meters

Answer 2

Answer:

Explanation:

Lets evaluate the time it takes to hit the ground.

In this example the rock is in free-fall. Since the rock is thrown horizontally, its initial horizontal velocity has no effect on its time of flight or vertical motion.

We can use this motion equation to solve this example.

\(\sf h=\dfrac{1}{2} gt^2\)

Where

\(\sf h\) is the height

\(\sf g\) is the acceleration due to gravity

\(\sf t\) is the time

Lets solve for \(\sf t\).

Combine \(\sf \frac{1}{2}\) and \(\sf gt^2\).

\(\sf h=\dfrac{gt^2}{2}\)

Multiply both sides of the equation by 2.

\(\sf 2h=gt^2\)

Divide both sides of the equation by \(\sf g\).

\(\sf \dfrac{2h}{g}=t^2\)

Take the square root of both sides to eliminate the exponent.

\(\sf \sqrt\sf \dfrac{2h}{g}} =t\)

Now we have an equation to evaluate time.

Numerical Evaluation

In this example we are given

\(\sf v_{0x}=8\\y_0=100\\g=9.81\)

Substituting our values into the equation yields

\(\sf \sqrt\sf \dfrac{2*100}{9.81}} =t\)

\(\sf \sqrt\sf \dfrac{200}{9.81}} =t\)

\(\sf 4.5152364=t\)

Rounding to the nearest hundredth leaves us with

\(\sf t=4.51\)

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Related Questions

Explain in your own words what is the fourth commandment.

Answers

the fourth commandment is to remember my Sabbath day which is to not do any labor on the 7th day which is Sunday.

Explanation:

hope this helps I don't know if you meant from the Bible or not.

Answer:

From Wikipedia, the free encyclopedia. The Fourth Commandment of the Ten Commandments may refer to: "Remember the sabbath day, to keep it holy", under the Philonic division used by Hellenistic Jews, Greek Orthodox and Protestants except Lutherans, or the Talmudic division of the third-century Jewish Talmud

Explanation:

I hope this helps

PLEASE GIVE ME BRAINLEST  i really need this

Select ALL the
correct answers.
Which two examples describe ways that corporations can give large donations to presidential candidates?
A corporation leader makes
direct payment to the candidate.
A corporation creates another company to accept candidate contributions
A corporation collects moneys from its employees to contribute to
A corporation contributes to a Super PAC that
a PAC
accepts contributions
for a candidate,
Reset
Next

Answers

Answer: Hope this helps ;) don't forget to rate this answer !

Explanation:

There are two correct answers:

A) A corporation leader makes direct payment to the candidate.

D) A corporation contributes to a Super PAC that a PAC accepts contributions for a candidate.

Option A describes a scenario where a corporation directly donates money to a presidential candidate, which is allowed as long as it is done within the limits set by campaign finance laws.

Option D describes a scenario where a corporation donates money to a Super PAC, which is a type of political action committee that can accept unlimited donations from individuals, corporations, and other organizations. The Super PAC can then use the money to support or oppose a particular candidate, but it is not allowed to coordinate directly with the candidate or the candidate's campaign.

I hope this helps! Let me know if you have any other questions.

will there be a mega tsunami like in the movie tidal wave from 2009?​

Answers

I really hope not but maybe it is possible
Maybe, hope not, ..hi

9. Which of these tissues hold bones together at movable joints? O ligaments O cartilage O tendons O disks​

Answers

Answer:

The tissue that holds bones together at movable joints is ligaments. Ligaments are strong, fibrous connective tissues that connect bones to other bones, providing stability and limiting excessive movement at the joints. They help to maintain the proper alignment and function of the joints while allowing for controlled movement.

Explanation:

The tissue that holds bones together at movable joints is ligaments. Ligaments are strong, fibrous connective tissues that connect bones to other bones, providing stability and limiting excessive movement at the joints. They help to maintain the proper alignment and function of the joints while allowing for controlled movement.

Answer:

The answer is ligaments!

Explanation:

Hope this helps!! :)

A Ping-Pong ball is shot into a circular tube that is lying flat (horizontal) on a table-top.
Figure attached.

When the Ping-Pong ball exits the tube, which path will it follow in the figure?
d
a
c
b
e

Answers

Answer:

e

Explanation:

A light elastic string, of natural length g metres and modulus mg N, has one end attached to a fed point O, and the other end attached to a particle of mass m kg. If the particle hangs in equilibrium vertically below O, what will the extension in the string be? Give your answer in metres to 1 decimal place.

The particle from the previous question is dropped from a point § metres directly below O and enters into simple harmonic motion centred on the equilibrium point once the string is under tension. If the equation of motion when under tension is › = -n?, where x is the displacement from the
equilibrium position, then find the constant n.

In the previous question, how long after it is dropped does the particle enter simple harmonic motion? Give your answer in seconds.

What is the amplitude of the simple harmonic motion in the previous two questions? Give your answer in metres to 2 decimal places.

How long does it take the particle in the previous three questions to come to instanteous rest for the first time? Give your answer in seconds to 2 decimal places.

A light elastic string, of natural length g metres and modulus mg N, has one end attached to a fed point

Answers

The extension in the string when the particle hangs in equilibrium is e = mg/k. The constant n in the equation of motion is n = (2π/T)²m. The time it takes for the particle to enter simple harmonic motion is t = √(2§/g).

To find the extension in the string when the particle hangs in equilibrium, we need to consider the forces acting on the particle. The weight of the particle is mg, acting vertically downward. The tension in the string exerts an equal and opposite force, mg, to balance the weight. Since the particle is in equilibrium, the total force acting on it is zero.When the particle is dropped from a point below O, it will stretch the string due to its weight. Let's denote the extension of the string as e. The tension in the string will now be greater than mg because it needs to support the weight of the particle and provide the necessary centripetal force for the simple harmonic motion.The extension in the string is given by Hooke's law: F = kx, where F is the force, k is the modulus of the string, and x is the extension. In this case, the force is the tension in the string, and the extension is e. Thus, we have mg = ke. Rearranging the equation, we get e = mg/k.

To find the constant n in the equation of motion, › = -n?, we can use the fact that the period of simple harmonic motion is given by T = 2π√(m/k), where m is the mass of the particle and k is the spring constant. Comparing this with the equation of motion, we see that ω² = n/m. Since ω = 2π/T, we can substitute ω in terms of T and solve for n: n = (2π/T)²m.

To determine when the particle enters simple harmonic motion, we need to find the time it takes for the string to reach its equilibrium position. Since the particle is dropped from a point § meters below O, it will accelerate towards the equilibrium position due to the tension in the string. The time taken for this free-fall motion can be calculated using the equation of motion for constant acceleration: § = ½gt². Solving for t, we get t = √(2§/g).The amplitude of the simple harmonic motion is equal to the maximum displacement from the equilibrium position. In this case, the maximum displacement is equal to the initial dropped distance, § meters.To determine the time it takes for the particle to come to instantaneous rest for the first time, we need to find the time period of the simple harmonic motion. The time period, T, is given by T = 2π√(m/k). To find the time it takes to come to rest, we need to consider half of the time period, T/2.The amplitude of the simple harmonic motion is equal to the initial dropped distance, § meters. The time it takes for the particle to come to instantaneous rest for the first time is T/2, where T is the time period of the simple harmonic motion.

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The radius of curvature is smaller at the top than on the sides so that the downward centripetal acceleration at the top will be greater than the acceleration due to gravity, keeping the passengers pressed firmly into their seats. What is (a) the speed of the roller coaster at the top of the loop (in m/s) if the radius of curvature there is 13.0 m and the downward acceleration of the car is 1.50 g, and (b) the minimum speed necessary for the coaster to complete the loop without falling off the track?

Answers

the answer for the speed of the roller coaster at the top of the loop is v = 14.8 m/s

the minimum speed necessary for the coaster to complete the loop without falling off the track is 11.3 m/s.

Explanation to the Roller Coaster Speed Calculation

(a) To find the speed of the roller coaster at the top of the loop, we can use the equation for centripetal acceleration: a = v^2/r. We know that the radius of curvature is 13.0 m and the downward acceleration of the car is 1.50 g (where g is the acceleration due to gravity, approximately 9.8 m/s^2).

So, we can rearrange the equation to solve for v: v = sqrt(ar)

Plugging in the values, we get: v = sqrt(1.5g * 13m)

v = sqrt(22.5 * 9.8)

v = sqrt(219.5)

v = 14.8 m/s

(b) To find the minimum speed necessary for the coaster to complete the loop without falling off the track, we can use the same equation for centripetal acceleration, but this time we will use the minimum value of a that will keep the car on the track, which is equal to the acceleration due to gravity (g).

So, we can rearrange the equation to solve for v: v = sqrt(ar)

Plugging in the values, we get: v = sqrt(g * 13m)

v = sqrt(9.8 * 13m)

v = sqrt(127.4)

v = 11.3 m/s

So the minimum speed necessary for the coaster to complete the loop without falling off the track is 11.3 m/s.

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Two long straight wires each carry a current I out of the figure toward the viewer (Figure 1) .
I O o 4
o 1
o 2 o 5
o 3
I O o6
Part A
Mark the points in which the magnetic field is zero.
Check all that apply.
Check all that apply.
O 6
O 2
O 1
O 5
O 4
O 3

Answers

Part A Mark the points in which the magnetic field is zero.The points in which the magnetic field is zero are O 2 and O 4.

A magnetic field is a force field that is created by a magnet or a moving electric charge. It is characterized by the direction of the field lines, which show the direction of the magnetic force at a given point, and the magnitude of the field, which is determined by the strength of the magnet or the amount of electric charge. Magnetic fields are used in a variety of applications, including in electric motors, generators, and MRI machines. They can also be found in natural phenomena such as the Earth's magnetic field.

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light has a frequency of about 6 x1014 Hz.

Answers

Answer:

The visible light frequency is 400 THz to 700 THz, approximately. A THz is a Terahertz, which is a unit of frequency equal to one trillion Hertz.

what are
the the ten disadvantages of friction

Answers

These are some frictional disadvantages: Overheating caused by friction consumes energy. Money is spent on both reducing resistance and

What does friction mean?

A force called friction keeps two objects from slamming into or rolling over one another. While friction force, such the traction needed to walk without slipping, may be helpful, they can also present a sizable degree of impediment to motion.

Why does Friction arise?

Friction is caused by flaws on the surfaces that are in touch. Even for the finest materials include minute imperfections, and these flaws produce friction when two surfaces come into contact. As the defects get worse, the friction gets worse.

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A microphone is attached to a spring that is suspended from the ceiling, as the drawing indicates. Directly below on the floor is a stationary 440-Hz source of sound. The microphone vibrates up and down in simple harmonic motion with a period of 2.0 s. The difference between the maximum and minimum sound frequencies detected by the microphone is 2.1 Hz. Ignoring any reflections of sound in the room and using 343 m /s for the speed of sound, determine the amplitude of the simple harmonic motion.

Answers

Answer:

\(0.261\ \text{m}\)

Explanation:

\(\Delta f\) = Change in frequency = 2.1 Hz

\(f\) = Frequency of source of sound = 440 Hz

\(v_m\)= Maximum of the microphone

\(v\) = Speed of sound = 343 m/s

\(T\) = Time period = 2 s

We have the relation

\(\Delta f=2f\dfrac{v_m}{v}\\\Rightarrow v_m=\dfrac{\Delta fv}{2f}\\\Rightarrow v_m=\dfrac{2.1\times 343}{2\times 440}\\\Rightarrow v_m=0.8185\ \text{m/s}\)

Amplitude is given by

\(A=\dfrac{v_m T}{2\pi}\\\Rightarrow A=\dfrac{0.8185\times 2}{2\pi}\\\Rightarrow A=0.261\ \text{m}\)

The amplitude of the simple harmonic motion is \(0.261\ \text{m}\).

an electric kettle takes 2kw at 240v. Calculate the current and the resistance of the heating element

Answers

The power output is given 2000 watt and voltage is 240 v. Then the current through the heating element is 8.3 A and the resistance is 29 ohms.

What is power ?

The power used by an object is the rate of its work done or energy. It is the energy divided by time. The power output in a circuit is the product of the potential difference V and current I.

P = I V

Given,

P = 2 kw = 2000 W

v = 240 V.

Then I = P/v

I = 2000 w/240 v = 8.3 A.

According to Ohm's law, voltage v is the product of the current and resistance through the material.

hence,

V = I R

then, R = V/I

R = 240 V/8.33 A

  = 29 Ω.

Therefore, the current and resistance through the heating element are 8.3 A and 29 ohms respectively.

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Two balls collide – one heavy and one light. Why will the light one roll farther back than the heavy one?

Answers

Answer:

During a collision, some of the ball's energy is converted into heat. As no energy is added to the ball, the ball bounces back with less kinetic energy and cannot reach quite the same height. The heavy ball, on the other hand, is left behind with little energy and does not move much.

2. What is the missing piece for the energy transformation for a flashlight? *
Chemical > Electrical > BLANK
& Thermal

Answers

The missing piece for the energy transformation for a flashlight is "Light" or "Radiant" energy. Chemical > Electrical > light & Thermal

What is meant by energy transformation?

Energy transformation is also known as energy conversion. It is the process of changing energy from one form to another. In physics, energy is a quantity that provides capacity to perform work or moving or provides heat.

The complete energy transformation for a flashlight is as :

Chemical (stored in the battery) > Electrical (when the battery powers the bulb) > Light/Radiant (when the bulb emits light) & Thermal (some of the energy is lost as heat due to resistance in the bulb and the circuit).

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A sample of The halflife of the substance is 21 minutes the number of atoms remaining underway. radioactive Substances has 812X1020 atom Determine the number of atoms remaining

Answers

After 42 minutes, there are 203 x \(10^{20\) atoms remaining of the radioactive substance.

To determine the number of atoms remaining after a certain amount of time has passed, we can use the formula for radioactive decay:

N(t) = N0 * \((1/2)^{(t / T)\),

where:

N(t) = number of atoms remaining at time t,

N0 = initial number of atoms (812 x  \(10^{20\) atoms),

T = half-life of the substance (21 minutes), and

t = time that has passed.

Let's calculate the number of atoms remaining after a given time.

Suppose the time passed is t = 42 minutes (twice the half-life).

N(t) = 812 x  \(10^{20\) * \((1/2)^{(42 / 21)\)

N(t) = 812 x  \(10^{20\) * \((1/2)^2\)

N(t) = 812 x  \(10^{20\) * 1/4

N(t) = 203 x  \(10^{20\) atoms.

So, after 42 minutes, there are approximately 203 x \(10^{20\) atoms remaining of the radioactive substance.

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Fill in the blank. The is the largest part of the brain.

Answers

Answer:

the largest part of the brain is cerebrum

Explanation:

my mom is a doctor so i think thats what she said

Use Newton’s Law of Universal Gravitation and Newton’s Second Law to
Find g = acceleration due to gravity
Show g is independent of mass

Answers

By equating the two forces, acceleration due to gravity g is obtained which is independent of mass

What is Newton’s Second Law ?

The law state that the rate of change of momentum is directly proportional to the force applied.

From Newton’s Second Law, Force F = mg. And from Newton’s Law of Universal Gravitation, Force F = GMm/r²

Where m is the mass of the satellite or the body revolving round the earth.

Equate the two forces.

mg = GMm/r²

The two m cancelled out leaving

g = GM/r²

Where

g = Acceleration due to gravityM = Mass of the earthG = Universal gravitational constantr = Distance between them.

Therefore, since the mass of the satellite m has cancelled out, acceleration due to gravity g is independent of mass.

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What is the magnetic force on a proton that is moving at 3.8 x 10^7 m/s up through a magnetic field that is 0.72 T and pointing toward you?

Answers

The force is F = B q v = 0.72 x 1.6x 10^-19 x 3.8 x 10 ^7 = .... N
The force will be at 90 degrees to both the motion of the proton and the magnetic field.

Answer:

4.4 x 10^-12 N right

Explanation:

Mountain Ecosystems Assignment Answer each question below in complete sentences.1) Identify a predator from an Ethiopian Highlands ecosystem. How else can this animal be classified in terms of feeding relationships? What is its prey? How else can its prey animal be classified in terms of feeding relationships? Identify a predator from a Himalayan Mountain ecosystem. How else can this animal be classified in terms of feeding relationships? What is its prey? How else can its prey animal be classified in terms of feeding relationships?

Answers

An example of a a predator in the Ethiopian Highlands ecosystem is the

Wolf.The wolf is a carnivore which acts as a predator to other smaller

animals in the ecosystem.

What is a Prey?

Preys are mostly smaller animals in which the predators feed on for food.

They are usually herbivores and primary consumers in the ecosystem.

Examples of Preys include:

RodentsDeerBison etc.

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19. Assume this process is 10% efficient, how much work is done by the gas expanding into the atmosphere?

Answers

The amount of work done by the gas is proportional to the pressure and the change in volume, as well as the efficiency of the process. If the pressure and volume are known, the work done by the gas can be calculated by multiplying these values by the efficiency of the process.

The amount of work done by a gas when it expands is proportional to the change in volume, pressure, and temperature. According to the first law of thermodynamics, the energy of a closed system is conserved, so the work done by the expanding gas is equal to the energy transferred from the gas to the environment in the form of work. Therefore, the work done by the gas is equal to the change in energy of the system. Assume that the process is 10% efficient. Then, only 10% of the energy available to the system is converted into work. This means that the remaining 90% of the energy is lost to the environment in the form of heat. As a result, the amount of work done by the gas expanding into the atmosphere is given by the formula

W = E x η, where W is the work done by the gas, E is the energy available to the system, and η is the efficiency of the process. The energy available to the system is determined by the difference between the internal energy of the gas before and after the expansion. The internal energy of a gas is determined by its temperature, pressure, and volume.

Assuming that the temperature and pressure are constant, the change in internal energy is proportional to the change in volume. Therefore, the energy available to the system is equal to the product of the pressure and the change in volume: E = P x ΔV, where P is the pressure of the gas and ΔV is the change in volume during the expansion. Substituting this equation into the formula for work, we get W = P x ΔV x η.

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Explain why driving less can decrease the amount of carbon dioxide in the air.

Answers

Carbon dioxide is a greenhouse gas that is released into the atmosphere through various human activities, including the burning of fossil fuels. When fossil fuels are burned, they release large amounts of carbon dioxide into the air, which can trap heat and contribute to climate change.

Driving less can decrease the amount of carbon dioxide in the air because it reduces the amount of fossil fuels that are burned. When people drive less, they use less fuel, which means that fewer fossil fuels are burned and less carbon dioxide is released into the atmosphere.

In addition, driving less can also encourage the use of alternative forms of transportation, such as public transportation, biking, or walking. These forms of transportation typically emit less carbon dioxide than cars, which can further reduce the amount of carbon dioxide in the air.

Overall, driving less is an effective way to decrease the amount of carbon dioxide in the air, which can help to combat climate change and protect the environment.

A cat jumps horizontally from a 3.2 meter shelf at a velocity of 7m/s. How far from the base of the shelf does the cat land? At what velocity does the cat land? (Magnitude and Direction).

Answers

Refer to the photo taken.
A cat jumps horizontally from a 3.2 meter shelf at a velocity of 7m/s. How far from the base of the shelf

what dose current equal?

Answers

There is a basic equation in electrical engineering that states how the three terms relate. It says that the current is equal to the voltage divided by the resistance or I = V/R. This is known as Ohm's law.

Hope this helps! :)

What is the force on a 1,250 kg elevator that is in free fall at 9.8 m/s²? Ignore air
resistance, round your answer to the nearest tenth and use appropriate units.

Answers

Answer:

\(\boxed{12250N}\)

Explanation:

Assuming we disregard air resistance, the only force acting on the elevator will be its weight.

\(F \implies w=m\cdot g\)

where:

\(F=\) force

\(w=\) weight

\(m=\) mass → 1250kg

\(g=\) gravity acceleration  → 9.8m/s^2

Then:

\(F= 1250kg \cdot 9.8m/s^2\\F=12250 kg\cdot m/s^2= 12250N\)

Hope it helps.

\(\text{-B$\mathfrak{randon}$VN}\)

Pls answer when u can

Pls answer when u can

Answers

Answer:

I believe the answer is C. 1 and 3

Explanation:

I'm 100% sure that 1 is correct, from what I remember learning.

As for 3, it was hard to choose between 3 and 4, but I'm pretty certain that covalent bonds shared electrons rather than transfer them.

Hope this helps you, please let me know if it was correct :D

QUESTION 23
How much electric energy will be used by a 115 V, 60 W Eghtbulb in one minute
69.
2215
5800
6900)
*
Xpwe-

Answers

Answer:

E = 3600 J

Explanation:

Given that,

Voltage, V = 115 V

Power of electric bulb, P = 60 W

We need to find the electric energy used in 1 minute. The electric energy use is given by :

\(E=P\times t\\\\E=60\ W\times 60\ s\\\\E = 3600\ J\)

Hence, the electrical energy is 3600 J.

A 2800-lbm car climbs a 1160 ft. long uphill road which is inclined at 15o (to the horizontal) and covers the distance in 12 sec. Determine the power required if the car covers the distance (a) at constant velocity, (b) from an initial velocity, at the bottom of the hill, of 10 mph to a final velocity of 50 mph at the top of the hill and (c) from an initial velocity of 45 mph to a final velocity of 15 mph. Neglect the effects of friction and wind resistance.

Answers

Answer:

a) P = 70054.3 W,  b)  P = 18820 W,  c)   P = 14116.7 W

Explanation:

Power is defined as work per unit of time

         P = W / t = F x / t

         P = F v

a) in this case the velocity is constant, let's use the equilibrium relation to find the force.

Let's set a reference system with the x axis parallel to the plane

           

        F - Wₓ = 0

         F = Wₓ

with trigonometry let's decompose the weight

        sin θ = Wₓ / W

        Wₓ = W sin θ

         

          F = W sin 15

          F = 2800 sin 15

          F = 724.7 lb

we look for the speed, as it rises with constant speed we can use the relations of uniform motion

          v = x / t

          v = 1160/12

          v = 96.67 ft / s

we calculate the power

          P = 724.7 96.67

          P = 70054.3 W

b) In this case, the speed of the vehicle changes during the ascent, so we use the relationship between work and the change in kinetic energy

           W = ΔK

           W = ½ m v_f² - ½ m v₀²

   let's reduce to the SI system

           v₀ = 10 mph (5280 ft / 1 mile) (1h / 3600 s = 14.67 ft / s

           v_f = 50 mph (5280 ft / 1 mile) (1 h / 3600s) = 73.33 ft.s

           

 mass :         m = w / g

           W = ½ 2800/32 (73.33² - 14.67²)

           W = 225841 J

we calculate the average power

           P = W / t

           P = 225841/12

           P = 18820 W

c) we repeat the previous procedure

          v₀ = 45 mph = 66 ft / s

          v_f = 15 mph = 22 ft / s

          W = ½ 2800/32 (22² - 66²)

          W = -169400 J

         

          P = W / t

          P = 169400/12

          P = 14116.7 W

What is friction and weight and what is hooks law

Answers

Answer:

Hooke's law states that the applied force F equals a constant k times the displacement or change in length x, or F = kx. ... Hooke's law describes the elastic properties of materials only in the range in which the force and displacement are proportional.

Explanation:

Each value measured in nature has a number value, called its magnitude, and
a dimension, or
Answer here

Answers

Answer:

yassssssssssssssssssssssssssssssssssssss

Explanation:

a kite is a 150 feet high and 200 feet of string are out. if the kite starts drifting away horizontally at the rate of 4 miles an hour how fast is a string being paid out at the start​

Answers

Answer:

Let z = 200 ft and y = 150 ft

Also since 60 mph = 88 ft/sec then 4 mph = 88/15 = 5.87 ft.sec

Now   x^2 + y^2 = z^2

x dx/dt + y dy/dt = z dz/dt       differentiate wrt t

Or x dx/dt = z dz/dt    since dy/dt = zero

x = (200^2 - 150^2)^1/2 = 132.3 ft

dz/dt = x / z * dx/dt = 132.3 / 200 * 5.87 = 3.88 ft/sec

Other Questions
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