Answer:
(a) 165.46 V
(b) 7.78 A
Explanation:
(a) From the question,
Vrms = V₀/√2...................... Equation 1
Where V₀ = maximum potential difference across a lamp connected to the outlet.
make V₀ the subject of the equation.
V₀ = √2(Vrms)............... Equation 2
Given: Vrms = 117 V.
Substitute into equation 2
V₀ = (√2)(117)
V₀ = 165.46 V.
(b) Similarly,
I₀ = √2(Irms)....................... Equation 3
Given: Irms = 5.5 A
Substitute into equation 3
I₀ = (√2)(5.5)
I₀ = 7.78 A.
A small car with a mass of 800 kg is moving with a velocity of 30 m/s. What is the momentum of the car?
Required? Substitute and Solve
A. 2.67 kg-m/s
B. 24000 kg-m/s
C. 770 kg-m/s
D. 830 kg-m/s
Answer:
B. 24000 kg-m/s
Explanation:
Momentum equation: p = mv
p = 800 kg * 30 m/s = 24000 kg-m/s
Potential energy = 0 J Kinetic energy =
Answer:drfdcfrfvgtgy6hbhhbhyg vcfrfr5tgvcfrtg vcdftghegthetrgbdgtthethe3thet
Explanation:
Sdwerftyrujtnyhbvcrdefgswthyujdehrtgfyhrjfuygtdhjueyrtgehwu3y4tgrehjwheyrgdhbnsjhfgvbdnhgfdhjsdehbrvbdensdvfgreyhsdgrftyhedggrfdhsgfv
A copper sphere has a mass of (112.25 ± 0.01) g and its radius of (2.50 ±0.02) cm. Find the uncertainty in density. ( Note: the volume of the sphere is V = 4/3 π r3)
The uncertainty in the density is 1.71 g/cm^3 (±0.03)
What is the density?The density of a body is the ratio of the mass to the volume of the copper sphere. We have been given the mass of the copper sphere and its volume thus we can now find the density of the sphere.
Mass = 112.25 g
Volume = 4/3 π r^3 = 4/3 * 3.142 * (2.50)^3 = 65.5cm^3
Density = 112.25 g/65.5cm^3 = 1.71 g/cm^3
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Loose objects on the dashboard slide to the right when the car turns suddenly to the left because
Loose objects on the dashboard slide to the right when the car turns suddenly to the left because they have inertia
When loose objects are placed on the dashboard of a car, they may slide to the right when the car turns suddenly to the left. objects at rest tend to stay at rest and objects in motion tend to stay in motion. As the car turns left, there is a force pushing the loose objects to the right, and gravity alone is not strong enough to hold them in place. Therefore, the objects slide to the right due to their inertia. To prevent this, it's best to secure loose objects on the dashboard or remove them altogether to ensure safety while driving.
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K=(1/2)my^2 v?
A.) K=mv
B.) m= Kv^2
C.) v=sqrt(2k/m)
D.) none of above
Answer:
The answer is C. The explanation is below.
The electrons in a TV picture tube are accelerated from rest through a potential difference of 22 kV . Estimate the speed of the electrons after they have been accelerated by this potential difference.
To estimate the speed of the electrons after being accelerated through a potential difference of 22 kV, we can use the principle of energy conservation. The potential difference provides electrical potential energy to the electrons, which is converted into kinetic energy as they gain speed.
The kinetic energy gained by the electrons can be calculated using the formula:
KE = qV
where KE is the kinetic energy, q is the charge of an electron (approximately 1.6 x 10^-19 C), and V is the potential difference.
Given:
Potential difference, V = 22 kV = 22,000 V
Charge of an electron, q = 1.6 x 10^-19 C
Substituting the values into the formula, we have:
KE = (1.6 x 10^-19 C) x (22,000 V)
KE ≈ 3.52 x 10^-15 J
Now, we can equate the kinetic energy gained by the electrons to their kinetic energy:
KE = (1/2)mv^2
where m is the mass of an electron (approximately 9.11 x 10^-31 kg) and v is the velocity (speed) of the electrons.
Rearranging the equation, we can solve for v:
v = √((2KE) / m)
Substituting the values, we get:
v = √((2 x 3.52 x 10^-15 J) / (9.11 x 10^-31 kg))
v ≈ 6.06 x 10^6 m/s
Therefore, the estimated speed of the electrons after being accelerated through a potential difference of 22 kV is approximately 6.06 x 10^6 m/s.
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What usually result from wind and can travel hundreds of miles before they reach the shore?
Ocean waves usually result from wind and can travel hundreds of miles before they reach the shore
What are waves ?The most frequent cause of waves is wind. Surface waves, often known as wind-driven waves, are produced when surface water and wind collide. A wave crest is produced when wind continuously disturbs an ocean or lake's surface.
Water moves in a circular motion as a result of waves being created by energy travelling through it. During a wave's passage, water atoms only move in a very narrow circle. The energy for the waves comes from the wind. Ocean waves are pushed by the wind, and the energy is then released along coasts.
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8. If horizontal velocity is 5 m/s, and vertical velocity is 8 m/s, what is the
magnitude of the resultant velocity?*
O
4.9 m/s
O
3.5m/s
9.4m/s
O 13m/s
Answer:
9.4
Explanation:
magnitude is the sum of the squares.
\(\sqrt{5^2+8^2} =9.4339\\\)
If you are given horizontal and vertical components, treat those as the rise and run of a triangle, the rise of 8 with a run of 5 and you want to find the hypotenuse.
How do you find the long side of a triangle?
a person riding in an elevator stands on a metric scale. if the mass of the person is 60.0 kg and the elevator accelerates upward with an acceleration of 4.90 m/s2, what is the reading on the scale?
The reading on the scale is 882.6 N when the elevator accelerates upwards with an acceleration of 4.90 m/s².
Given that the mass of a person is 60.0 kg and the elevator accelerates upwards with an acceleration of 4.90 m/s², we have to determine the reading on the scale.
Let F be the force exerted by the scale on the person. Then, by Newton's second law of motion, the net force acting on the person is Fnet= m * a
where m = 60.0 kg is the mass of the person and a = 4.90 m/s² is the acceleration of the elevator. Hence, the net force acting on the person is given by;
Fnet = 60.0 kg * 4.90 m/s²
Fnet = 294.0 N
Therefore, the scale reading is equal to the force exerted by the scale on the person. Since the elevator is accelerating upwards, the force exerted by the scale on the person is greater than the weight of the person, which is the force of gravity acting on the person.
The force of gravity acting on the person is given by;
Fg = m * g, where g = 9.81 m/s² is the acceleration due to gravity. Hence, the force of gravity acting on the person is given by;
Fg = 60.0 kg * 9.81 m/s²Fg = 588.6 N
Therefore, the scale reading is given by the sum of the force of gravity acting on the person and the net force acting on the person;
F = Fg + Fnet
F = 588.6 N + 294.0 N
F = 882.6 N
Thus, the reading on the scale is 882.6 N when the elevator accelerates upwards with an acceleration of 4.90 m/s².
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David drove the first 6 hours of his journey at 65 km / hour and the last 3 hours of his journey at 80 km / hour . How far is the whole journey in km ?
Answer:
630 km.
Explanation:
To obtain the total distance travelled by David, we shall calculate the distance travelled in each, then sum them together.
Case 1:
Speed 1 (S₁) = 65 km / hour
Time 1 (t₁) = 6 hours
Distance 1 (d₁) =?
Speed = Distance /time
S₁ = d₁ / t₁
65 = d₁ / 6
Cross multiply
d₁ = 65 × 6
d₁ = 390 Km
Case 2:
Speed 2 (S₂) = 80 km / hour
Time 2 (t₂ ) = 3 hours
Distance 2 (d₂) =?
Speed = Distance /time
S₂ = d₂ / t₂
80 = d₂ / 3
Cross multiply
d₂ = 80 × 3
d₂ = 240 Km
Finally, we obtained the total distance travelled by David as follow
Distance 1 (d₁) = 390 Km
Distance 2 (d₂) = 240 Km
Total Distance travelled (dₜ) =?
Total distance = distance 1 + distance 2
dₜ = d₁ + d₂
dₜ = 390 + 240
dₜ = 630 km
Therefore, the total distance travelled by David is 630 km
how do humans affect the lithosphere
A 50.0 kg gorilla is sitting on the limb of a tree 4.00 meters above the ground. The gorilla jumps down from the tree limb to the ground. Use the conservation of energy to find the velocity of the gorilla just before hitting the ground.
*Help Quickly*
The velocity of the gorilla of mass 50 kg, sitting 4 meters above the ground just before hitting the ground is 8.85 m/s.
What is velocity?Velocity is the rate of change of displacement.
To calculate the velocity of the gorilla, we use the formula below
Formula:
v² = 2gh..................... Equation 1Where:
v = Velocity of the gorilla just before hitting the groundh = Height of the gorillag = Acceleration due to gravityFrom the question,
Given:
h = 4 mg = 9.8 m/s²Substitute these values into equation 1 and solve for v
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Jeffrey pulls a spring with a spring constant k = 50.0 N/m, stretching it from its rest length of 0.10 m to 0.90 m.
What is the elastic potential energy stored in the spring?
The elastic potential energy stored in the spring having a spring constant of 50.0 N/m is 16 J
How do I determine the potential energy stored in the spring?We'll begin by obtaining the extension of the spring. This is given below:
Initial length = 0.10 mNew length = 0.90 mExtension =?Extension = New length - initial length
Extension = 0.90 - 0.10
Extension = 0.80 m
Finally, we shall determine the potential energy stored by the spring. Details below
Spring constant (K) = 50.0 N/mExteension (e) = 0.80 mPotential energy stored =?PE = ½Ke²
PE = ½ × 50 × 0.8²
PE = 25 × 0.64
PE = 16 J
Thus, from the above calculations, we can conclude that the potential energy stored is 16 J
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a runner covers the last straight stretch of the race in 4 s. durning that time, he speeds up from 5 m/s to 9m/s what is the runners acceleration in this part of the race?
Answer:
The runner's acceleration was \(1\ m/s^2\)
Explanation:
Constant Acceleration Motion
It's a type of motion in which the velocity of an object changes by an equal amount in every equal period of time.
Being a the constant acceleration, vo the initial speed, vf the final speed, and t the time, the following relation applies:
\(v_f=v_o+at\)
Solving for a:
\(\displaystyle a=\frac{v_f-v_o}{t}\)
The runner speeds up from vo=5 m/s to vf=9 m/s in t=4 seconds, thus:
\(\displaystyle a=\frac{9-5}{4}\)
\(\displaystyle a=\frac{4}{4}=1\)
The runner's acceleration was \(1\ m/s^2\)
PLEASE HELP WILL GIVE BRAINLIEST
How can diversity within an ecosystem be compromised?
A.)by building structures on natural habitat areas
B.)by regulating human activity within an ecosystem
C.)by helping to maintain habitats that have been disturbed
D.)by leaving the ecosystem alone to fend for itself
How would you expect Newton’s Cradle to behave on a large planet such as Jupiter?
Claim:
Evidence:
Reasoning:
The cradle behaves different due to higher force of gravity.
The Newton’s Cradle behave differently on a large planet such as Jupiter because of the higher gravitational force as compared to the earth. We know that the ball in the cradle that we moves upward comes back to hit the other ball due to force of gravity so if the gravity is increased than the ball on the other end did not move on a certain height due to strong force of attraction and may be the motion of the Newton’s Cradle stops or very slow. The gravity of Jupiter is 2.4 times higher than earth.
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A stationary block of mass 35 Kg is suspended on a string.What is the tension in the string ?( Neglect the mass of the string)
Answer:
Tstring = 343.35 [N].
Explanation:
Since the block is in equilibrium, we can say that the sum of the forces on the Y-axis or vertical is equal to zero.
∑Fy = 0
\(T_{string}-W=0\)
where:
Tstring = tension of the string [N]
W = weight of the block [N]
And the weight can be calculated multiplying the mass of the block by the gravity acceleration.
Now replacing:
\(T_{string}=m*g\\T_{string}=35*9.81\\T_{string}=343.35[N]\)
In both experiments, what accounts for the change in pressure you observed as you changed the volume of the gas
Answer: When a gas is in a smaller volume, the molecules are more confined and bump into the walls of the flask more, thereby exerting a greater pressure.
Explanation:
Can you please help me with this physics question
Answer:
See the answers below
Explanation:
We can solve both problems using vector sum.
a)
Let's assume the forces that help the diver dive as positive downward, and the forces that oppose upward, as negative
\(F_{resultant}=100+30-85+900\\F_{resultant}=845[N]\)
The drag force is horizontal d this way in the horizontal direction we will only have the drag force that produces the water stream.
\(F_{drag}=50[N]\)
b)
Let's assume the forces that propel the rocket upwards as positive and forces like the weight of the rocket and other elements as negative forces.
\(F_{resultant}=960+7080-7700\\F_{resultant}=340 [kN]\)
As you walk to science class, you start out at a speed of 2 m/s, for a time of 120 seconds (you’re really excited to get to class). Then you see your friend and slow down to a speed of 0.5m/s for 30 seconds. You stop at your locker for 40 seconds (a speed of 0 m/s). You realize that you are about to be late so you hurry to class at a speed of 1 m/s and get to class just as the bell rings (4 minutes after your trip started). How far did you travel total?
The total travelled distance is • Speed, time and distance is one of the most common and important topics in the Mathematics or Quant section.
What is Speed?Velocity is the pace and direction of an object's movement, whereas speed is the time rate at which an object is travelling along a path. In other words, velocity is a vector, whereas speed is a scalar value.
For instance, 50 km/hr west denotes the velocity of a car whereas 50 km/hr (31 mph) denotes the speed at which it is moving down a route.
The average speed of an object is determined by dividing the distance traveled by the amount of time it takes the object to reach the distance.
Therefore, The total travelled distance is • Speed, time and distance is one of the most common and important topics in the Mathematics or Quant section.
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a person travels by car from one city to another with different constant speeds between pairs of cities. she drives for 40.0 min at 70.0 km/h, 16.0 min at 75.0 km/h, and 50.0 min at 40.0 km/h and spends 35.0 min eating lunch and buying gas.
The Average speed is 42.44 km/h ,the distance between cities is 99.02kmSpeed is the rate at which something or someone is moving.
The average speed of an object can be determined if you know the distance traveled and the time it took. Distance times speed is how speed is computed. In order to compute the units for speed, you must be aware of the units for both distance and time. Given that the distance in this example is measured in metres (m) and the duration is recorded in seconds, the units will be metres per second (m/s) For the purpose of calculating the other two, we require the other two (time, speed, or distance). To determine how long it will take to complete a journey, for example, information about the distance and speed of travel is needed.
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How many week are in .62 years?
Answer:
32.32857
Explanation:
Searched on the web
An airplane flying at 116 m/s. E, is accelerated uniformly at the rate of 9.2 m/s2, E, for 13 s. What is its final velocity in m/s?
Answer:
235.6m/s
Explanation:
you have to use one of the kinematic formulas the best that suits the question given in this case you can use v=u+at.since the time, acceleration and initial velocity have been given in the question
v=116+(9.2)13^2
v=116+119.6
=235.6m/s
I hope this helps
if a car travels 270 meters in 30 seconds then what is its average speed
Answer:
the answer is 32,400
Explanation:
I looked it up for you
The average speed denotes the average rate of speed over the extent of a trip. The average speed of a car which travels 270 meters in 30 seconds is 9m/s.
What is average speed?The average speed can be defined as the ratio of the total distance travelled by an object to the total time taken. It is a scalar quantity. It is represented by the magnitude and does not have direction. Its SI unit is m/s.
The average speed of an object help us to calculate the rate of travel time and the distance. The average speed of an object when it covers the same distance at two different speed, X and Y is:
Average speed = 2XY/ X+Y
The equation used here to calculate the average speed is:
Average speed = Total distance / Total time
Average speed = 270 m / 30 s = 9 m/s
Thus the average speed is 9 m/s.
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To understand decay in terms of half-life and to solve radioactive dating problems.Suppose a radioactive sample initially contains N0unstable nuclei. These nuclei will decay into stable nuclei, and as they do, the number of unstable nuclei that remain, N(t), will decrease with time. Although there is no way for us to predict exactly when any one nucleus will decay, we can write down an expression for the total number of unstable nuclei that remain after a time t:N(t)=N0e−λt,where λ is known as the decay constant. Note that at t=0, N(t)=N0, the original number of unstable nuclei. N(t) decreases exponentially with time, and as tapproaches infinity, the number of unstable nuclei that remain approaches zero.Part (E) Suppose that an Egyptian farmer claims to have discovered a linen burial cloth used during Egypt's Middle Kingdom some 4000 years ago. Careful analysis shows that the cloth contains 80% of the 14C that it is estimated to have originally contained. How old is the cloth? (years)
The age of the cloth material is obtained from the calculation as 1843 years .
What is the half life?We know that the half life of a radioactive isotope refers to the time that is taken for only half of the number of the original radioactive isotopes that are present to remain in the sample.
We can be able to obtain the age of the cloth by looking at the amount of the radioactive carbon -14 that is still left in the sample. How do we do that? We have to turn to a formula that says;
0.693/\(t_{\frac{1}{2} }\) = 2.303/tlog (Ao/A)
\(t_{\frac{1}{2} }\) = half life of the material
t = age of the material
Ao = amount initially present
A = Amount present at time t
Then we have;
0.693/5730 = 2.303/tlog (Ao/0.8Ao)
1.21 * 10^-4 = 0.223/t
t = 0.223/1.21 * 10^-4
t = 1843 years
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Which statement describes what the hand shows?
O When the current flows down the wire, the magnetic
field flows out on the left side of the wire and in on the
right side of the wire.
GWhen
the current flows up the wire, the magnetic field
flows out on the left side of the wire and in on the right
side of the wire.
O When the current flows down the wire, the magnetic
field flows in on the left side of the wire and out on the
right side of the wire.
O When the current flows up the wire, the magnetic field
flows in on the left side of the wire and out on the right
side of the wire.
The statement that describes what the hand shows is:
"When the current flows up the wire, the magnetic field flows in on the left side of the wire and out on the right side of the wire."
What type of energy change results when friction slows down an object.
: A plane loop of wire of area A is placed in a region where the magnetic field is perpendicular to the plane. The magnitude of B varies in time according to the expression B = B_a e^a. That is, at time t = 0 the field is B^a, and for t > 0 the field decreases exponentially in time. Find the magnetic flux the loop as a function of time. Find the induced emf in the loop as a function of time.
The induced emf in the loop as a function of time is ε(t) = a * B_a * e^(-a*t) * A.
The magnetic flux through the loop as a function of time is given by Φ = B(t) * A, where B(t) is the magnetic field and A is the area of the loop.
In this case, the magnetic field is given by B(t) = B_a * e^(-a*t), where B_a is the initial magnetic field magnitude and a is a constant.
Therefore, the magnetic flux through the loop as a function of time is Φ(t) = B_a * e^(-a*t) * A.
To find the induced electromotive force (emf) in the loop as a function of time, we use Faraday's law of electromagnetic induction, which states that the emf induced in a loop is equal to the rate of change of magnetic flux through the loop. The induced emf (ε) in the loop is given by ε = -dΦ/dt, where dΦ/dt represents the derivative of magnetic flux with respect to time.
Taking the derivative of Φ(t), we get ε(t) = -d/dt (B_a * e^(-at) * A) = a * B_a * e^(-at) * A.
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The final induced electromotive force (emf) in the loop is represented by the equation -aBₐeᵃt·A. This equation combines factors such as magnetic field strength (B), loop area (A), and exponential decay (eᵃt) to determine the emf.
Determine the induced emf?The induced emf in the loop can be calculated using the formula:
emf = -d(Φ)/dt,
where emf represents the induced electromotive force, Φ is the magnetic flux through the loop, and dt is the change in time.
In this case, the magnetic field B is given as B = Bₐeᵃt, where Bₐ is a constant and a represents a constant rate of change with respect to time.
The magnetic flux Φ through the loop can be determined by integrating the magnetic field over the enclosed area S:
Φ = ∫B·dA,
where dA represents an infinitesimal area element.
To calculate the induced emf, we differentiate the magnetic flux Φ with respect to time:
d(Φ)/dt = d/dt ∫B·dA.
Since the magnetic field B is constant over the enclosed area S, it can be taken out of the integral:
d(Φ)/dt = ∫d(B·dA)/dt.
Applying the differentiation inside the integral:
d(Φ)/dt = ∫(dB/dt)·dA.
As the magnetic field B = Bₐeᵃt, differentiating with respect to time yields:
dB/dt = aBₐeᵃt.
Substituting this expression into the equation for d(Φ)/dt:
d(Φ)/dt = ∫aBₐeᵃt·dA.
Since the magnetic field B is perpendicular to the plane, the integral simplifies to:
d(Φ)/dt = aBₐeᵃt·A,
where A represents the area of the loop.
Finally, we obtain the induced emf:
emf = -d(Φ)/dt = -aBₐeᵃt·A.
In conclusion, the induced emf in the loop is given by -aBₐeᵃt·A.
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A solid sphere and a hollow sphere, both uniform and having the same mass and radius, roll without slipping toward a hill with the same forward speed V. Which sphere will roll farther up the hill?
The solid sphere and the hollow sphere will have different rolling motions due to their different moments of inertia. The moment of inertia of a solid sphere is greater than that of a hollow sphere with the same mass and radius because the solid sphere has more mass distributed further from its axis of rotation.
As a result, the solid sphere will roll slower than the hollow sphere, but will have more rotational energy and be able to roll farther up the hill due to its greater inertia.
Therefore, the solid sphere will roll farther up the hill than the hollow sphere, even though they have the same mass and radius and are rolling with the same forward speed V.
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a -0.06 C charge is placed in a uniform electric field with a strength of 200 N/C. what is the magnitude and direction of the force on the charge
The magnitude and direction of the force on the charge is -12 N opposite the electric field
To calculate the force on a charge in an electric field, we make use of the formula below.
Formula
F = E×Q .......................... Equation 1
Where:
F = Force on the chargeE = Electric FieldQ = chargeFrom the question,
Given:
E = 200 N/CQ = -0.06 CSubstitute these values into equation 1
F = 200(-0.06)F = -12 NNote: The negative sign indicates that the force is in the direction negative of the electric field.
Hence, The magnitude and direction of the force on the charge is -12 N opposite the electric field
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Answer: A edge 202694020
Explanation: