Q1: You place two charges a distance r apart. Then you double each charge and double
the distance between the charges. How does the force between the two charges
change?
a) The new force is twice as large.
b) The new force is half as large.
c) The new force is four times as large.
d) The new force is four times smaller.
e) The new force is the same.


(HELP HELP)

Answer:

When water freezes to form ice, the molecules would be vibrating in place rather than moving round. It is a result of a decrease in the kinetic energy of the molecules of water. It is said that the temperature and the kinetic energy of the molecules is directly proportional which means that when temperature is increased, the kinetic energy of the molecules would increase as well making the molecules move around. However for this case, when we day the system is cooled then it means the temperature is decreased which would result to the decrease of the kinetic energy of the molecules.

Using the Standard population for region, the proportionate mortality for old people in region Y is 80%. The correct answer is option  (c).

To calculate the proportionate mortality, we need to determine the number of deaths among old people in region Y and divide it by the standard population for region Y.

According to the given options, option c is the correct answer, which states that the proportionate mortality is 48/60 = 80%.

This means that out of the standard population of 60 in region Y, 48 deaths occurred among old people. This indicates a high proportionate mortality rate for the elderly population in region Y, reflecting the impact on that age group's mortality in the region.

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Answer:hey can you help me answer my question please.

Explanation:

A magnet will attract an ordinary nail or paper clip because they are made of ferromagnetic materials, which are materials that can be magnetized and are strongly attracted to magnets. When a magnet is brought near a ferromagnetic material, it creates a magnetic field within the material, causing the material to become magnetized and creating an attractive force between the two.

On the other hand, a wooden pencil is not a ferromagnetic material and is not attracted to magnets. Wood is composed mainly of non-magnetic materials such as cellulose, hemicellulose, and lignin, which are not affected by magnetic fields. Therefore, the magnet will not create a magnetic field within the pencil, and there will be no attractive force between the two.

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it would take about 21.0 seconds to bring the car to a complete stop with a force of 540 N, assuming no external factors such as air resistance or friction.

Newton's second law of motion states that the acceleration of an object is directly proportional to the force applied to it and inversely proportional to its mass. It can be expressed mathematically as F = ma, where F is the net force acting on the object, m is the mass of the object, and a is its acceleration.

We can use the equation for acceleration to solve this problem. The equation is:

a = F/m

where a is the acceleration of the car, F is the force applied to the car, and m is the mass of the car.

Using the given values, we get:

a = 540 N / 65 kg = 8.31 m/s^2

This is the acceleration of the car when the force is applied.

To find the time it takes to bring the car to a complete stop, we can use the kinematic equation:

v = v0 + at

where v is the final velocity of the car (which is zero when it comes to a complete stop), v0 is the initial velocity of the car (175 m/s in this case), a is the acceleration, and t is the time it takes for the car to come to a complete stop.

Substituting the known values, we get:

0 = 175 m/s + (8.31 m/s^2) t

Solving for t, we get:

t = -175 m/s / (8.31 m/s^2) ≈ -21.0 s

The negative sign indicates that the time is in the opposite direction of the car's motion. We know that time cannot be negative, so we discard this solution.

So, it takes approximately:

t = 175 m/s / (8.31 m/s^2) ≈ 21.0 s

to bring the car to a complete stop.

Hence, If there were no outside influences, such as air resistance or friction, the car would come to a complete stop with a force of 540 N in around 21.0 seconds.

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Option (a) is Correct. Take a look at a static electric field around a conductor at rest. then the conductor's internal electric field is exactly zero.

Electrons are free to move in a conductor. If they are subjected to a force, they will move faster in that direction. A force F = -eE acts on each free electron when a conductor is exposed to an external electric field. Electrons gain speed and accelerate in the direction that is the opposite of the field. There are no closed loops formed by electric field lines.

Because electric field lines begin with positive charge and conclude with negative charge, the assertion is accurate. A loop can never be closed since the starting and ending points of the electric field lines are different. Charges that are free to move are present in conductors. Charges in a conductor react swiftly to attain a constant state known as electrostatic equilibrium when an excess of charge is applied to the conductor or the conductor is placed in a static electric field.

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Correct Question:

Consider a conductor at rest in a static electric field. Which statement is true about how the conductor interacts with the electric field?

A. The electric field inside the conductor is exactly zero.

B. Any net charge on the conductor is distributed evenly throughout the volume of the conductor.

C. The electric field is parallel to the surface of the conductor at all points along its surface.

D. The electric field lines pass through the conductor unaffected by its presence.

Answer:

6.58×10⁻¹⁸ J

Explanation:

Applying

E = kq²/r.................. Equation 1

Where E = potential energy, q = charge on each electron, r = distance between the electron, k = coulomb's constant.

From the question,

Given: r = 3.5×10⁻¹¹ m,

Constant: q = 1.6×10⁻¹⁹ C, k = 8.99×10⁹ Nm²/C²

Substitute these values into equation 1

E = (1.6×10⁻¹⁹)²(8.99×10⁹)/(3.5×10⁻¹¹)

E = 6.58×10⁻¹⁸ J

The least wavelength in the visible range (400 nm to 700 nm) that are not present in the third-order maxima is 400 nm.

To determine the least wavelength in the visible range (400 nm to 700 nm) that is not present in the third-order maxima, we can use the formula for constructive interference in a diffraction grating:

n * λ = d * sin(θ)

where n is the order of maxima, λ is the wavelength, d is the grating spacing, and θ is the angle of diffraction. In this case, n = 3 for the third-order maxima. To find the least wavelength not present, we can set θ to its maximum value, 90 degrees. So, we have:

3 * λ = d * sin(90)

At sin(90), the value is 1. Therefore, λ = d/3. This implies that the grating spacing, d, must be smaller than 3 times the shortest visible wavelength (400 nm) to ensure that this wavelength is present in the third-order maxima. If d >= 3 * 400 nm, the shortest wavelength will not be part of the third-order maxima. So, for a diffraction grating with a spacing equal to or larger than 1200 nm, the least visible wavelength of 400 nm will not be present in the third-order maxima.

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Answer: C -- decreases with increasing altitude

Explanation:

A--g is different on other planets and objects like asteroids, etc. It is 9.8 m/s2 only on Earth

B--g acts on long distances, too, not just short

D--g is independent of the mass of the free falling object

C is correct.  The value of g decreases the higher you go in altitude

This timeline lists significant discoveries in physics and the laws of nature, including experimental discoveries, theoretical proposals that were confirmed experimentally, and theories that have significantly influenced current thinking in modern physics from 1500 to 2000.

What is definition of timeline?

A timeline is a display of a list of chronicle in chronological order. It is usually a graphic design showing a long bar tagged with dates paralleling it, and usually present day chronicle.

Timelines can use any appropriate scale representing time, suiting the subject and statements; many use a linear dimension, in which a unit of distance is equal to a set quantity of time. This timescale is incumbent on the chronicle in the timeline.

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Answer:

B. speed

Explanation:

im not sure hahahaha

Trusses are structures made up of interconnected triangles that are used to support loads. The members of the truss can either be in tension or compression, depending on the orientation of the load.

To determine the force in each member of the truss, you first need to analyze the forces acting on the entire structure. This involves drawing a free body diagram of the truss and applying the principles of statics to calculate the forces acting on each member.

Once you have determined the external forces acting on the truss, you can use the method of joints or the method of sections to analyze the internal forces in each member. In summary, determining the force in each member of a truss is a complex process that involves analyzing the external forces acting on the structure, using the method of joints or the method of sections to analyze the internal forces in each member, and determining whether the members are in tension or compression.

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Complete Question

The  complete question is shown on the first uploaded image  

Answer:

Explanation:

From the question we are told that

   The initial pressure of the gas is  \(P_1 = 1.50 \ atm\)

   The volume of the second bulb is  \(V_2 = 0.800 \ L\)

   The  final pressure of the gas is  \(P_2 = 671 \ torr = \frac{671 }{ 760} = 0.883 \ atm\)

Let the unknown volume be represented as \(V_1 = V \ L\)

Generally from Boyle's law we have that

      \(P_1 * V_1 = P_2 * V_2\)

=>   \(1.50 * V = 0.883 * 0.800\)

=>   \(V = 0.479 \ L\)

Complete Question:

A long distance runner running a 5.0km track is pacing himself by running 4.5km at 9.0km/hr and the rest at 12.5km/hr. What is the average speed?​

Answer:

Average speed = 9.7333 km/h

Explanation:

Given the following data;

To find the average speed;

First of all, we would determine the time taken to cover distance A in speed A by using the formula;

\( Time \ A = \frac {Distance \; A}{Speed \; A} \)

Substituting the values into the formula, we have;

\( Time \ A = \frac {4.5}{9.5} \)

Time A = 0.4737 hours

Total distance = distance A + distance B

5 = 4.5 + distance B

Distance B = 5 - 4.5

Distance B = 0.5 Km

Next, we would determine the time to cover distance B in speed B;

\( Time \ B = \frac {0.5}{12.5} \)

Time A = 0.04 hours

Total time = time A + time B

Total time = 0.4737 + 0.04

Total time = 0.5137 hours

Now, we would solve for the average speed;

Mathematically, the average speed of an object is given by the formula;

\( Average \; speed = \frac {total \; distance}{total \; time} \)

\( Average \; speed = \frac {5}{0.5137} \)

Average speed = 9.7333 km/h

Answer:

1. Somewhat 2.Yes

Explanation:

Answer:

C,a

Explanation:

To calculate the tensile strength (T), we need to use the formula:

T = Force/Area

In this case, we are given the peak compressive force as 2084 N. However, we need to convert this to tensile force since we want to calculate the tensile strength. Tensile force is equal in magnitude but opposite in direction to compressive force.

Therefore, T = 2084 N

Next, we need to calculate the cross-sectional area (A) of the material. Given that the diameter of the material is 1 inch, we can calculate the radius (R) as half of the diameter:

R = 1 inch / 2 = 0.5 inch

We need to convert the radius to meters since the SI unit of force is Newton (N) and the SI unit of area is square meters (m^2). Since 1 inch is equal to 0.0254 meters, we can convert the radius as follows:

R = 0.5 inch * 0.0254 meters/inch = 0.0127 meters

Now, we can calculate the cross-sectional area (A) of the material using the formula for the area of a circle:

A = π * R^2

A = 3.1416 * (0.0127 meters)^2

A ≈ 0.0005087 square meters

Finally, we can calculate the tensile strength (T) using the formula:

T = 2084 N / 0.0005087 square meters

T ≈ 4,093,981.8 N/m^2

Therefore, the tensile strength (T) is approximately 4,093,981.8 N/m^2.

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Answer:

What he said:)

Explanation:

Have an amazing day you are loved

The wavelength of the x-rays emitted when an electron beam strikes a block of copper is approximately 1.52 × 10⁻¹² m. When an electron beam strikes a block of copper, x-rays of frequency 1.97 × 10¹⁹ Hz are emitted.

To find the wavelength of these x-rays, we will use the equation: c = νλwhere c is the speed of light, ν is the frequency of the x-rays, and λ is their wavelength.

We know the frequency of the x-rays, so we can plug that into the equation: c = 3.00 × 10⁸ m/s (speed of light)ν = 1.97 × 10¹⁹ Hz (frequency of x-rays)λ = ?

We can then rearrange the equation to solve for the wavelength:λ = c/νλ = (3.00 × 10⁸ m/s)/(1.97 × 10¹⁹ Hz)λ ≈ 1.52 × 10⁻¹² m.

Thus, the wavelength of the x-rays emitted when an electron beam strikes a block of copper is approximately 1.52 × 10⁻¹² m.

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L, the number of samples, is 8, The frequency spacing in Hz is 31.25 Hz, (a) L² = 64 multiplications  using the definition of the DFT, (b) L log₂(L) = 24 multiplications, (c) 256 log₂(256) = 4096 multiplications

To find the value of L, we divide the duration of the portion of the analog signal (128 ms) by the sampling rate (8 kHz). L = (128 ms) × (8 kHz) = 8.

The frequency spacing in Hz of the computed DFT values is calculated by dividing the sampling rate by the number of points in the DFT. In this case, the DFT is a 256-point DFT, so the frequency spacing is (8 kHz) / 256 = 31.25 Hz.

The total number of required multiplications depends on the method used to compute the DFT.

(a) If the computations are done directly using the definition of the DFT, each sample needs to be multiplied by every other sample, resulting in L² multiplications. In this case, L = 8, so L² = 64 multiplications.

(b) If the L samples are first wrapped modulo 256 and then the 256-point DFT is computed, the total number of multiplications can be reduced. The wrapped samples result in periodicity, allowing for a more efficient computation. The total number of multiplications is given by L log₂(L), where L = 8. Therefore, L log₂(L) = 8 log₂(8) = 24 multiplications.

(c) If a 256-point FFT is computed of the wrapped signal, the number of multiplications is further reduced. The total number of multiplications for an FFT of size N is given by N log₂(N). In this case, N = 256, so the total number of multiplications is 256 log₂(256) = 4096 multiplications.

Therefore, the total number of required multiplications is 64 for direct computation using the DFT definition, 24 if the samples are first wrapped modulo 256 and then computed, and 4096 for a 256-point FFT of the wrapped signal.

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The number of revolutions the tire makes during this motion, assuming that no slipping occurs is 54 and the final angular speed of a tire in revolutions per second is 12.2 revolutions per second.

Given Data

Initial speed (u) = 0, Final speed (v) = 22.5 m/s, Time (t) = 8.95 s, Diameter of tire (d) = 58.6 cm = 0.586 m, Radius of tire (r) = d/2 = 0.293 m(a)

Number of revolutions the tire makes during this motion: The circumference of the tire is given as:

Circumference = πd = 3.14 x 0.586 = 1.84 m

Since there is no slipping, the distance covered by the car in 8.95 s is given by: d = ut + 1/2 at²,

Where acceleration (a) = (v - u)/t = 22.5/8.95 = 2.51 m/s²

Therefore, d = 0 x 8.95 + 1/2 x 2.51 x (8.95)² = 100 m

The number of revolutions of the tire during the motion can be given by the ratio of the distance covered by the circumference of the tire.

Revolutions = Distance covered/Circumference = 100/1.84 = 54.35 or 54 revolutions (approx.)

(b) The final angular speed of a tire in revolutions per second:

We can use the following formula to find the angular speed of the tire:

v = ωr

Where, v = final velocity, ω = angular velocity, and r = radius of the tire

So, ω = v/r = 22.5/0.293 = 76.8 rad/s

Number of revolutions per second = 76.8/2π = 12.23 or 12.2 revolutions per second (approx.)

Thus, the number of revolutions the tire makes during this motion, assuming that no slipping occurs is 54 and the final angular speed of a tire in revolutions per second is 12.2 revolutions per second.

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Answer:

The first step is to calculate the potential energy of the ball at the top of the first hill using the formula PE = mgh, where m is the mass of the ball, g is the acceleration due to gravity, and h is the height of the hill. PE = (8 kg) x (9.8 m/s^2) x (20 m) = 1568 J Next, we can use the law of conservation of energy, which states that the total energy of a closed system remains constant. This means that the potential energy at the top of the first hill must be equal to the kinetic energy at the bottom of the hill, since there is no external work done on the ball. So, using the formula KE = 1/2mv^2, where v is the velocity of the ball, we can solve for v: KE = 1

Answer:

Refer to the attachment..

Answer:

False.

Explanation:

This question refers to the rules of American Football. Thus, the line of scrimmage is an imaginary boundary that is established between both teams, to which the offensive line and the defensive line go to start the play.

In this situation, the offensive team must have 7 players in its formation, but within this some players can perform certain movements, with which it is incorrect to say that the formation cannot be modified, since it is constantly seen as some players, such as wide receivers, for example, move during scrimmage formation.

The horizontal distance (d_forearm) between the elbow and the point where the weight of the forearm acts is known as the center of mass of the forearm.

The center of mass represents the average position of the weight distribution of an object. In the case of the forearm, this point is important in biomechanics as it helps determine the force exerted by the muscles and the stability of the arm during various movements. To find the center of mass, one can use various techniques including mathematical calculations, experimental measurements, and observation of the anatomy.

Generally, the center of mass for the human forearm is located approximately at the midpoint between the elbow and the wrist, making it roughly 50% of the total length of the forearm. However, this location may vary among individuals due to differences in body proportions, muscle mass, and bone density. In summary, the horizontal distance (d_forearm) between the elbow and the point where the weight of the forearm acts is the center of mass, typically located around the midpoint of the forearm, this point plays a significant role in the biomechanics and stability of the arm during various movements.

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The electric field contributed by the polarization charges on the surface of the metal sphere at location <0, 0.03, 0> m is given by charges =  \({\left(\frac{{9 \times 10^{-8}}}{{4 \pi \varepsilon_0}}\right)} \left(\frac{{\mathbf{r}}}{{|\mathbf{r}|^3}}\right)\) N/C.

To calculate the electric field contributed by the polarization charges on the surface of the metal sphere, we can use the principle of superposition. Each polarization charge can be considered as a point charge contributing to the electric field at the given location.

The electric field created by a point charge q located at position \(\mathbf{r'} is given by \mathbf{E} = \frac{1}{{4 \pi \varepsilon_0}} \left(\frac{q}{{|\mathbf{r} - \mathbf{r'}|^3}}\right) (\mathbf{r} - \mathbf{r'})\), where \(\varepsilon_0\) is the permittivity of free space.

In this case, we have a neutral solid metal sphere, so the polarization charges only exist on its surface. Let's assume the location of a polarization charge on the surface is given by \(\mathbf{r'}\). The charge q is equal to the product of the surface charge density \(\sigma\) and the area element dA at that point, which is \(q = \sigma dA\). The direction of the electric field is given by the vector \((\mathbf{r} - \mathbf{r'})\) which points from the location of the polarization charge to the point where we want to calculate the electric field.

By integrating over the entire surface of the sphere, we can determine the total electric field contributed by all the polarization charges. In this case, since the sphere is symmetric, the electric field contributions from all points on the surface cancel out except for the ones along the x-axis. Therefore, we only need to consider the polarization charges located at <−0.2, 0, 0> m. Plugging in the values into the formula, we find that the electric field contributed by the polarization charges on the surface of the metal sphere at location <0, 0.03, 0> m is given by charges =  \({\left(\frac{{9 \times 10^{-8}}}{{4 \pi \varepsilon_0}}\right)} \left(\frac{{\mathbf{r}}}{{|\mathbf{r}|^3}}\right)\) N/C.

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Explanation:

There are 5 kinematic equations, and 5 variables.

Each question will give you 3 variables and ask you to solve for a fourth.

To determine which equation to use, look at which variable is not included in the problem.

For example, if the question does not include time, then you need to use a kinematic equation that does not have t in it.  That would be:

v² = v₀² + 2aΔx

Or, if the question does not include the final velocity, then you need a kinematic equation that does not have v in it.  That would be:

Δx = v₀ t + ½ at²

The image is approximately 9.33 cm away from the mirror, on the object's side.

To determine the image location formed by a converging mirror, we can use the mirror equation:

1/f = 1/d_o + 1/d_i

where:

f is the focal length of the mirror,

d_o is the object distance (distance of the object from the mirror), and

d_i is the image distance (distance of the image from the mirror).

In this case, the focal length (f) is given as 7 cm, and the object distance (d_o) is 4 cm.

Plugging in the values into the mirror equation:

1/7 = 1/4 + 1/d_i

To find the image distance (d_i), we can solve for it:

1/d_i = 1/7 - 1/4

1/d_i = (4 - 7) / (4 * 7)

1/d_i = -3 / 28

Taking the reciprocal of both sides:

d_i = 28 / -3

d_i ≈ -9.33 cm

The negative sign indicates that the image formed by the converging mirror is virtual and located on the same side as the object.

Therefore, the image is approximately 9.33 cm away from the mirror, on the object's side.

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To resolve an object in an electron microscope, the wavelength of the electron beam should be smaller than the size of the object being observed. This is known as the de Broglie wavelength.

The de Broglie wavelength is given by the equation:λ = h/pwhere λ is the wavelength, h is Planck's constant, and p is the momentum of the electron. The momentum of an electron is given by the equation:p = mvwhere m is the mass of the electron and v is its velocity.To obtain a smaller de Broglie wavelength, either the velocity or the mass of the electron must increase. However, increasing the velocity of the electron can lead to aberrations in the image due to diffraction effects. Therefore, the mass of the electron is typically increased by using heavier elements such as uranium as the source material.

To resolve an object in an electron microscope, the wavelength of the electron beam should be smaller than the size of the object being observed. The de Broglie wavelength can be decreased by increasing the mass of the electron, but this is limited by practical considerations. The velocity of the electron should be high enough to provide good resolution, but not so high as to cause aberrations due to diffraction effects. The de Broglie wavelength of the electron beam should be smaller than the size of the object being observed to resolve it in an electron microscope.

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