Putting your thumb over the end of a hose causes the water to flow out more quickly what law is it

The acceleration of the box is 0.025 m/s²

We'll begin by calculating the the frictional force

Coefficient of kinetic friction (μ) = 0.21

Mass (m) = 8 Kg

Acceleration due to gravity (g) = 10 m/s²

Normal reaction (N) = mg = 8 × 10 = 80 N

Fբ = μN

Fբ = 0.21 × 80

Frictional force (Fբ) = 16.8 N

Force (F) = 17 N

Fₙ = F – Fբ

Fₙ = 17 – 16.8

Mass (m) = 8 Kg

Net force (Fₙ) = 0.2 N

a = Fₙ / m

a = 0.2 / 8

Therefore, the acceleration of the box is 0.025 m/s²

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Using the free body diagram, let's determine the scenario the diagram illustrates.

From the free body diagram, we can see that the weight is acting on the object while the tension will be the force which supports the object.

The tension in this case, helps hang the object while the weight is the product of the mass of the object and the force of gravity acting on the object.

Tension can be defined as the pulling force transmitted through a rope or string.

Therefore, the best scenario which is represented by the free body diagram is a sign board supported by two strings.

ANSWER:

A signboard supported by

Given that both the chair and the person are affected by Earth's movement, we can deduct that both have inertia due to Earth's speed.

Answer:

A is a solid. C is a gas. In solid an liquid the particals are touching. In C, the particals have less affect on each other because they are so far apart.

Answer:

-2.6

Explanation:

it’s for Acellus

The charge with magnitude and sign is -2.6 x 10⁻⁷ C.

The field developed when a charge is moved. In this field, a charge experiences an electrostatic force of attraction or repulsion depending on the nature of charge.

Given, the electric field 1.22 m from charge is 1570 N/C, pointing

toward the charge.

The electric field and charge is related as

E = kq/r²

q = Er²/k

where k = 9 x 10⁹ N.m²/C²

Substitute the given values in the question, we have

q = 1570 x (1.22)² / 9 x 10⁹

q= 2.6 x 10⁻⁷ C.

Thus, the magnitude and sign  of charge is -2.6 x 10⁻⁷ C.

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Answer:

The answer is B) Double slit

Examples of digital signals are Computers, Digital Phones, Digital pens, etc.

Signal is defined as an electromagnetic wave that carries information through a medium. In this, the data is converted into electromagnetic signal which may be analog or digital and then sent from sender to receiver.

Signal which are discrete are known as digital signals.

Examples of digital signals are Computers, Digital Phones, Digital pens, etc.

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Answer:

Examples of digital signals are Computers, Digital Phones, Digital pens, etc.

A digital signal is a signal that represents data as a sequence of discrete values. A digital signal can only take on one value from a finite set of possible values at a given time. With digital signals, the physical quantity representing the information can be many things: Variable electric current or voltage.

Take the upward and to-the-right directions to be positive (so down and to-the-left are negative).

The vertical forces acting on the object cancel, 6 N - 6 N = 0.

The horizontal forces exert a net force of 20 N - 3 N = 17 N. This net force is positive, so it points to the right. So the answer is A.

Answer:

forever alone uwu......

Answer:

2.125 m/s^2

Explanation:

Use Newton's second law: Force equals mass times acceleration, F = ma. You know the force (51 N) and you know the mass of the mower (24 kg). Remembering that a Newton is the same as kg-m/s2, solve for acceleration:

F = ma

51 kg-m/s2 = 24 kg * a

2.125 m/s2 =a

If a net external force of 51N is extorted on a 24kg lawnmower parallel to the ground, the acceleration of the mower will be 2.125 m/s².

Given the data in the question;

Net External Force; \(F = 51N\)

Mass of the Mower; \(m = 24kg\)

Acceleration; \(a = ?\)

To determine the acceleration of the mower, we make use of the equation from the Newton's Second Law of Motion:

\(F = m\ * \ a\)

Where F is the force exerted, m is the mass and a is the acceleration.

But then, we know that; ( A newton is the same thing as  \(1 kg.m/s^2\) )

Hence, Our Net External Force; \(F = 51kg.m/s^2\)

We substitute our values into the equation to find acceleration "a"

\(51kg.m/s^2 = 24kg\ *\ a\\\\a = \frac{51kg.m/s^2}{24kg} \\\\a = 2.125 m/s^2\)

Therefore, If a net external force of 51N is extorted on a 24kg lawnmower parallel to the ground, the acceleration of the mower will be 2.125 m/s².

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Eddie Cheever, Jr achieved the fastest single lap time of 38.1 seconds at the Indianapolis 500 car race. To determine his average speed, we need to calculate the speed at which he covered the 4.0 km race track.

To find Eddie Cheever, Jr's average speed, we can use the formula: Speed = Distance / Time. In this case, the distance is given as 4.0 km, and the time taken for a single lap is 38.1 seconds.

First, we need to convert the time to hours to match the unit of distance. There are 60 seconds in a minute and 60 minutes in an hour, so we divide 38.1 by 60 twice to convert it to hours. The resulting time is approximately 0.0106 hours.

Next, we can substitute the values into the formula: Speed = 4.0 km / 0.0106 hours. By dividing 4.0 by 0.0106, we find that Eddie Cheever, Jr's average speed during that lap was approximately 377.36 km/h.

In conclusion, Eddie Cheever, Jr achieved an average speed of approximately 377.36 km/h during his fastest lap at the Indianapolis 500 car race.

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Buying or selling the Earth will go against the rights of the inhabitants of the world (humans and other living beings).

Solar influence

The relation to determine Roche limit is:

\(Roche Limit=(2.423) (Rp3) {{\sqrt[3]{\frac{D_{P} }{D_{m} } } } }\)

Here  is radius of planet and  are density of planet and moon respectively.

According to the problem,

Density of Earth, = 5.5 g/cm³

Density of Moon, = 3.34 g/cm³

Consider  be the radius of the Earth.

Substitute the suitable values in the equation (1).

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If the strong force was suddenly turned off throughout the universe, atoms would almost immediately disintegrate as the strong force is responsible for holding the nucleus of an atom together.

This would result in a release of energy as the protons and neutrons in the nucleus repel each other due to the electromagnetic force. The energy released would be so great that it would cause a massive explosion, similar to a nuclear explosion. Furthermore, the absence of the strong force would also affect the stability of neutron stars and supernovae, which rely on the strong force to maintain their structure. Overall, the absence of the strong force would result in a catastrophic and potentially apocalyptic scenario for the universe.

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The functions of the skeletal system are support, movement, production of cells and protection.

The bones, muscles, ligaments, and tendons make up a skeletal system in the human body. It serves as body's support system to enable correct movement and bodily function. The skeleton gives the entire body structural support, allowing us to sit, stand, and move freely. In addition, fragile organs the brain, heart, and lungs are safeguarded by the bones of the skull, ribs, and spinal column.

Additionally, the skeletal system makes blood cells and stores minerals. The production of these cells, and platelets all essential for immune system and blood clotting take place in the bone marrow, which is found inside numerous bones. In addition, our ability to move and engage in activities like running, jumping, and dancing is made possible by our bones working in tandem with our muscles and joints.

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The mechanical advantage that us provided due to lifting the rock is 4.

The term mechanical advantage has to do with the degree of ease that is introduced by the use of simple machines. We know that the entire purpose of a machine is to make work easier.

We also know that the mechanical advantage is the ratio of the load to the effort.

MA = Load/Effort

Load = 600 pounds

Effort = 150 pounds

MA = 600 pounds / 150 pounds

= 4

The lever offer Jeff a mechanical advantage of 4 as he lifts the rock.

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The force constant of the spring is 200.696 N/m & The height the object achieves when the spring releases its energy is 2.5087 m

The spring constant is the force needed to stretch or compress a spring, divided by the compressive or expansive distance. It's used to determine stability or instability in the spring, and therefore the system it's intended for. we know,

F = kx

Therefore,

k = F/x

We also know that the force being exerted on the spring is equal to the mass of the object. Hence, F = mg = 5.13 * 9.8 N = 50.174 N and we know compression due to the mass is 0.25m. Therefore,

K = 50.174/0.25 N/m

K = 200.696 N/m

Therefore, The Spring Constant is 200.696 N/m

On release, the spring potential energy gets converted to kinetic energy. Hence, on release, the height attained by the object is given by:

h = \(1/2 kx^{2}\)

We know that k=200.696 N/m and x=0.25 m. Therefore the height is:

h = \(1/2 (200.696 N/m)(0.25 m)^{2}\)

h = 2.5087 m

Therefore, the force constant of the spring is 200.696 N/m & The height the object achieves when the spring releases its energy is 2.5087 m

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The radius of the curve that the plane follows in making the turn is approximately 275.87 meters.

To find the radius of the curve that the plane follows in making the turn, use the relationship between the speed, radius, and time for an object moving in a circular path.

Given:

Velocity of the airplane (v) = 115 m/s

Time taken to complete the turn (t) = 15 seconds

The formula to calculate the radius (r) of the curve is:

r = v × t / (2 × π)

Substituting the given values into the formula:

r = 115 m/s × 15 s / (2 × π)

Calculating the value:

r ≈ 115 × 15 / (2 × 3.14159)

r ≈ 115 × 15 / 6.28318

r ≈ 275.8686 meters

Therefore, the radius of the curve that the plane follows in making the turn is approximately 275.87 meters.

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The weight of the truck that pulls onto a small ferryboat that is 3.70 m wide and 5.70 m long and sinks an additional 4.80 cm into the river can be calculated as follows.Step 1: Calculate the volume of water displaced by the ferryboatThe volume of water displaced by the ferryboat is given by:V = Ah.

Where:A = the area of the base of the ferryboat (which is simply the product of its width and length)h = the height to which the ferryboat sinks into the water when the truck is loaded onto it.Therefore, the volume of water displaced by the ferryboat is:V = Ah = (3.70 m × 5.70 m) × (4.80 cm/100 cm) = 1.00 m³.

Step 2:  Calculate the weight of the water displaced by the ferry boat Assuming that the density of water is 1000 kg/m³, the weight of water displaced by the ferryboat is:W = Vρwhere:ρ = the density of water = 1000 kg/m³Therefore,W = Vρ = 1.00 m³ × 1000 kg/m³ = 1000 kgStep 3: Calculate the weight of the truck.

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The emf (e) is 14 V and the internal resistance (r) is 9 ohms.

Given on the question, the battery has this condition:

Using Ohm's law, we have:

e - 0.5(5.0) = 0.5(5.0) + 0.5r (equation 1)

e - 0.25(11.0) = 0.25(11.0) + 0.25r (equation 2)

Simplifying equation 1:

e - 2.5 = 2.5 + 0.5r

e = 5 + r (equation 3)

Simplifying equation 2:

e - 2.75 = 2.75 + 0.25r

Combining equations 3 and 2:

5 + r - 2.75 = 2.75 + 0.25r

2.25 = 0.25r

r = 9

Substituting the value of r into equation 3:

e = 5 + 9

e = 14

Therefore, the emf (e) of the battery is 14 volts and the internal resistance (r) is 9 ohms.

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The vector describing the diagonals of the cube can be written as v = (1,1,1) in unit vector notation. The angle between any pair of diagonals is equal to 60°.

To find this, consider the triangle formed by the diagonals. By the Law of Cosines, the angle between two vectors is given by the formula cos(θ) = (v₁ · v₂)/(|v₁| · |v₂|). Substituting in the vectors (1,1,1) and (1,-1,1) yields cos(θ) = 0.5, so θ = 60°.

To find the vector describing the diagonals of the cube, and the angle between any pair of diagonals, consider the following:

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a) Both spheres have the same speed and both reach at the same time.

b)  Both spheres will have the same speed at the bottom of the incline.

a) consider the energy conservation and calculate the speed of each sphere

0 + mgH = 1/2mv² + 1/2 Iw² + mgy

Here,

m is mass

g is gravity

H is height

v is velocity

I is inertia

w is the angular velocity

Now potential energy will be zero at the base of the incline (y=0) and there are initial height H then take position 1 to be the top and position 2 to be the generic location.

mg(H-y) = 1/2(mv² + 2/5mr² v²/r²)

v= √(10/7 g (H-y))

So according to the solution, it is clear that velocity is not depending upon the mass or radius of the sphere. Hence both have the same speed and both reach at the same time.

b) According to the result obtained in part (a), both have the same speed at each point along the incline so both will have the same speed at the bottom of the incline.

According to the conservation of energy total kinetic energy will be bottom of the incline is equal to the potential energy at the incline. There are initial potential energy is proportional to the mass sphere so massive spheres have greater kinetic energy.

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In order to solve for angular acceleration and tension in a problem, you typically need to use Newton's second law for rotational motion. This law states that the sum of torques acting on an object equals the moment of inertia times the angular acceleration.

The torque is equal to the force times the distance from the axis of rotation.

To solve for tension, you'll need to identify all the forces acting on the object and determine the net force acting in the direction of motion. If the object is moving in a circle, you'll need to calculate the centripetal force required to keep it moving in a circle. This force is equal to the mass times the centripetal acceleration, which is equal to the radius times the square of the angular velocity.

As for your issue with the angular acceleration, it's hard to say what might be causing the problem without seeing the specific problem you're working on. However, make sure you're using the correct formula for angular acceleration (which is equal to the change in angular velocity divided by the time interval) and that you're converting units correctly.

I hope this helps! Let me know if you have any other questions.

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Answer:

1.

Distance = 0.921 meters

2.

Work = 13.9 kJ

3.

The neighbor

Double your work

Explanation:

1.

Work = Force × Distance

Distance = Work / Force

Distance = 174J /189 N

Distance = 0.921 meters

2.

Work = force × distance

Work = (613 N) (22.6 m)

Work = 13,900 J

Work = 13.9 kJ

3.

Work is a product of force and distance, expressed as W=Fd where W is work in Nm, F is applied force and d is the distance in m

Since your neighbor pushes 4 times then you just push 1m when he pushes 4m, that is an example. Also, since the neighbor only exerts half the force i.e. 0.5N then you exert full force of 1N

Work from your neighbor will be 4d*0.5F=2dF

Work from you will be dF

Clearly, 2dF=2(dF) hence the neighbor exerts double work

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About 0.1% of the initial mass of 92U235 is transformed into energy during fission. The quantity of 92U235 that must fission each day in a nuclear reactor for it to produce 200 megawatts of electricity is then: Q.

A neutron divides a uranium atom when it interacts with it during nuclear fission, releasing a significant quantity of energy in the form of heat and radiation. When a uranium atom divides, additional neutrons are also emitted. The process keeps repeating again as these neutrons keep crashing into more uranium atoms.

It is possible to utilize the energy created by the fission of uranium or plutonium to create electricity, power spacecraft, and more.

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Answer:

F = Q V X B

V X B = south X downard = East - deflection is West

Since Q is negative the deflection = West

a = F / m = Q V B / m

a = 1.6E-19 * 5*E6 * 3.5E-5 / 9.1E-31

a = 1.6 * 5 * 3.5 / 9.1 * 10^13 m/s^2 = 3.1 * 10^13 m/s^2

Answer:

Potential

Explanation:

hope this helps

Physical fitness can be defined as the “ability to carry out daily tasks with vigor and alertness, without undue fatigue, and with ample energy to enjoy leisure-time pursuits and to meet unforeseen emergencies” (Park 1989).

A) The capacitance of the spherical capacitor is 1.45 pF (picofarads), B) The radius of the inner sphere is 3.60 cm. and C) The electric field just outside the surface of the inner sphere is \(2.36 * 10^6 V/m\) (volts per meter).

To calculate the capacitance, we can use the formula C = Q/V, where Q is the charge and V is the potential difference. Plugging in the values, we get \(C = (3.20 * 10^{-9} C)/(250 V) = 1.28 * 10^{-11} F\).

However, since the capacitor is a spherical one, we need to use the formula for the capacitance of a spherical capacitor, which is \(C = (4\pi \epsilon_0)(r_1 r_2)/(r_2-r₁)\), where r₁ and r₂ are the radii of the two shells and ε0 is the permittivity of free space.

Rearranging the formula and plugging in the values, we get \(r_1 = (C/4\pi \epsilon_0)(r_2-r_1)/r_2,\) which gives us r₁ = 3.60 cm.

To calculate the electric field just outside the surface of the inner sphere, we can use the formula

E = \(\frac{Q}{4\pi\epsilon_0 r^2}\), where r is the radius of the inner sphere.

Plugging in the values, we get \(E = (3.20 * 10^{-9} C)/(4\pi\epsilon_0(0.0460 m)^2) = 2.36 * 10^6 V/m.\)

This electric field arises due to the charge on the inner sphere and induces an opposite charge on the outer shell of the capacitor.

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