Put the following metals in order of reactivity.

Iron, potassium, copper, zinc, lead, calcium, magnesium, sodium, gold



Most reactive



















Least reactive



Complete the equations

metal + oxygen → …………………….

metal + water → ……………………. + …………………….

metal + acid → ……………………. + …………………….

What is formed when magnesium burns in air?

…………………….…………………….…………………….…………………….

What happens when copper is put into a beaker of water?

…………………….…………………….…………………….…………………….

How do you test for hydrogen gas?

…………………….…………………….…………………….…………………….

What is formed when sodium reacts with hydrochloric acid?

…………………….…………………….…………………….…………………….

How should metals more reactive than carbon be extracted from their ores?

…………………….…………………….…………………….…………………….

Why is gold used in jewelry?

…………………….…………………….…………………….…………………….

What is the rule for displacement reactions?

…………………….…………………….…………………….…………………….

Tick which reactions would happen



copper

Magnesium

zinc

copper sulfate







Magnesium

sulfate







Zinc Sulfate









Using the reactions from Q10. Choose 1 reaction you’ve ticked and explain why it happens. Choose 1 reaction you haven’t ticked and explain why it doesn’t happen.

…………………….…………………….…………………….…………………….

…………………….…………………….…………………….…………………….

…………………….…………………….…………………….…………………….

…………………….…………………….…………………….…………………….

Write word and symbol equations for the first reaction from Q11.

…………………….…………………….…………………….…………………….

…………………….…………………….…………………….…………………….

Answer:

133.20 kJ

Explanation:

The heat of fusion for water is  3.33 x 10^5 J/kg.

(400g)*(1 kg/1000g)*(3.33 x 10^5 J/kg) = 133200 J, or 133.20 kJ for 400g

The correct option from the given statements concerning mixtures is (d) more than one correct response.

The statement (a) "The composition of a homogeneous mixture cannot vary" is incorrect as the composition of a homogeneous mixture can vary. For example, a mixture of salt and water is homogeneous and its composition can vary depending on the amount of salt and water mixed in it.

The statement (b) "A homogeneous mixture can have components present in two physical states" is correct. Homogeneous mixtures are mixtures that are uniform throughout their composition, meaning that there is no visible difference between the components of the mixture. For example, a mixture of ethanol and water is homogeneous and its components are present in two physical states (liquid and liquid).

The statement (c) "A heterogeneous mixture containing only one phase is an impossibility" is incorrect. A heterogeneous mixture is a mixture where the components are not evenly distributed and the mixture has different visible regions or phases. However, it is possible for a heterogeneous mixture to contain only one phase. For example, a mixture of oil and water is heterogeneous but can have only one phase.

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The binding of the amino acid in aminoacyl-tRNA involves the formation of an ester bond.  Option b

Aminoacyl-tRNA is a complex molecule that plays a crucial role in protein synthesis. It consists of a tRNA molecule covalently linked to an amino acid. The amino acid is attached to the 3' end of the tRNA molecule through an ester bond.

An ester bond is formed between the carboxyl group (-COOH) of the amino acid and the hydroxyl group (-OH) of the ribose sugar at the 3' end of the tRNA molecule. This ester bond is also referred to as an ester linkage. The formation of the ester bond is catalyzed by the enzyme aminoacyl-tRNA synthetase.

The ester bond in aminoacyl-tRNA is essential for protein synthesis. During translation, the aminoacyl-tRNA molecule carries the specific amino acid to the ribosome, where it is incorporated into the growing polypeptide chain. The ester bond is later hydrolyzed, releasing the amino acid for further use in protein synthesis.

In summary, the binding of the amino acid in aminoacyl-tRNA involves the formation of an ester bond between the carboxyl group of the amino acid and the hydroxyl group of the ribose sugar in the tRNA molecule.

Option b

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If you begin with 0.053 grams of cinnamaldehyde (132.2 g/mol) and obtain 0.077 grams of product (206.28 g/mol) , then the percent yield of the reaction is approximately 93.2%.

The percent yield is a measure of the efficiency of a chemical reaction, calculated as the actual yield (the amount of product obtained experimentally) divided by the theoretical yield (the amount of product that would be obtained if the reaction proceeded perfectly), expressed as a percentage.

To calculate the theoretical yield, we need to determine the number of moles of cinnamaldehyde and product involved in the reaction, using their respective molecular weights:

moles of cinnamaldehyde = mass / molecular weight = \(\frac{0.053}{132.2} = 0.000401\)

moles of product = mass / molecular weight \(= \frac{0.077}{206.28} = 0.000374\)

Based on the balanced chemical equation for the reaction, we can see that one mole of cinnamaldehyde should react with one mole of product, assuming the reaction goes to completion. Therefore, the theoretical yield of product is:

theoretical yield = moles of cinnamaldehyde = 0.000401 mol

Now we can calculate the percent yield using the formula:

percent yield = (actual yield / theoretical yield) x 100%

Substituting the given values, we get:

percent yield \(= \frac{0.000374}{0.000401} * 100\)

percent yield = 93.2%

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Answer:

pioneer species, soil formation, plant growth

Explanation:

The events of succession after a volcano erupted in the proper order include pioneer species being visible. The pioneer species such as algae and Moss are usually found on rocks and dead matter.

After sometime the soil starts to form through weathering activities which then gives rise to and supports the growing of plant species.

A) The pH of a 0.75 M acetic acid solution, CH3COOH, Ka = 1.8 x 10⁻⁵: The pH is 2.92.

B) The calculated pH of a 0.75 M diethylamine solution, (CH3CH2)2NH, Kb = 7.1 x 10⁻⁴: The pH is 13.71

C) The hydronium ion concentrations can be represented as [H3O+]. the ratio of the hydronium ion concentrations in each solution is 1.59 x 10⁻¹¹.

A) The pH of a 0.75 M acetic acid solution, CH3COOH, Ka = 1.8 x 10⁻⁵: Firstly, we have the formula for Ka:

Ka = ([H3O+][CH3COO-]) / [CH3COOH]

We need to calculate [H3O+] and [CH3COO-].

Let us represent [H3O+] as x and [CH3COO-] as y.

Let [CH3COOH] be

0.75-x: [H3O+][CH3COO-] / [CH3COOH] = 1.8 x 10⁻⁵x

y / (0.75-x) = 1.8 x 10⁻⁵

x = [H3O+]

pH = - log[H3O+]

pH = - log (1.21 x 10⁻³)

The pH is 2.92.

B) The calculated pH of a 0.75 M diethylamine solution, (CH3CH2)2NH, Kb = 7.1 x 10⁻⁴:Given that Kb = 7.1 x 10⁻⁴.We know that

pKb + pKa = pKw (at 25°C)

Now, we have pKa, which is equal to -log Ka. Let us calculate pKa:

pKa = - log(1.8 x 10⁻⁵)

pKa = 4.74

pKw = 14

pKb = pKw - pKa = 14 - 4.74 = 9.26

Let us now use the formula for Kb:

Kb = [BH⁺][OH⁻] / [B]

Kb = [CH3CH2NH3⁺][OH⁻] / [CH3CH2NH2]

Let us represent [CH3CH2NH3⁺] as x and [OH⁻] as y.

Let [CH3CH2NH2] be 0.75-x.

Therefore, we have:

[CH3CH2NH3⁺][OH⁻] / [CH3CH2NH2] = 7.1 x 10⁻⁴x

y / (0.75-x) = 7.1 x 10⁻⁴

y = [OH⁻]

pOH = -log [OH⁻]

pOH = -log (3.53 x 10⁻³)

The pOH is 2.45.Using the formula

pH + pOH = pKw:

2.92 + 2.45 = 14 - pH + pOH2.

92 + 2.45 = 14 - pH + 11.559.37 - 11.55 = pH

pH = - log(1.93 x 10⁻¹⁴)

The pH is 13.71

C) The hydronium ion concentrations can be represented as [H3O+]. In a 0.75 M acetic acid solution:

[H3O+] = 1.21 x 10⁻³

In a 0.75 M diethylamine solution:

[H3O+] = 1.93 x 10⁻¹⁴

The ratio of the hydronium ion concentrations in each solution is:

1.93 x 10⁻¹⁴ / 1.21 x 10⁻³ = 1.59 x 10⁻¹¹.

Therefore, the ratio of the hydronium ion concentrations in each solution is 1.59 x 10⁻¹¹.

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a) The BOD5 of the wastewater can be calculated as follows:

Initial DO - Final DO = BOD5
9.0 mg/l - 4.0 mg/l = 5.0 mg/l (BOD5)
b) The ultimate carbonaceous BOD can be estimated by assuming that all the BOD has been utilized. Therefore, it is equal to the BOD5 value.
Ultimate carbonaceous BOD = BOD5 = 5.0 mg/l
c) The amount of BOD remaining after 5 days can be calculated as follows:
Initial DO - DO after 5 days = BOD remaining
9.0 mg/l - 2.0 mg/l = 7.0 mg/l (BOD remaining after 5 days)
d) To estimate the reaction rate constant k, we can use the first-order rate equation:
BODt = BOD5 * e^(-kt)
where BODt is the BOD remaining at time t, and e is the base of the natural logarithm.
Using the data at day 30:
2.0 mg/l = 5.0 mg/l * e^(-k*30)
k = 0.0461 (1/day)
Therefore, the estimated reaction rate constant k is 0.0461 (1/day).
A BOD test was conducted using a mixture of 30 mL wastewater and 270 mL dilution water, with a nitrification inhibitor added. The initial DO was 9.0 mg/L.
a) The BOD5 of the wastewater is calculated by subtracting the DO after 5 days (4 mg/L) from the initial DO (9.0 mg/L), resulting in a BOD5 of 5 mg/L.
b) The ultimate carbonaceous BOD can be determined by subtracting the DO after 30 days (2 mg/L) from the initial DO (9.0 mg/L), giving a value of 7 mg/L.
c) The amount of BOD remaining after 5 days can be determined by subtracting the BOD5 from the ultimate carbonaceous BOD (7 mg/L - 5 mg/L), which equals 2 mg/L.
d) To estimate the reaction rate constant k (1/day), more data points are needed. Based on the information provided, a reliable estimation of k cannot be made.

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Answer:

I think it's metabolism

Hope this helps

Answer:

I HOPE THE ABOVE INFORMATION WILL HELP YOU A LOT.

Answer:

Volume of the rock, V = 2 mL

Explanation:

It is given that,

Water filled in a graduated cylinder is 3 mL

She  then drops a small rock into the cylinder and the water  level rises to the 5 mL mark

We need to find the volume of the rock.

The volume of the rock is equal to the difference in volume mark. So,

V = 5 mL - 3 mL

V = 2 mL.

Answer:

K Only

Explanation:

Pretty sure that we only use Kelvin Scale in gas laws as it provides us with the absolute temperature, this is because in gas laws we are also concerned with motion of particles i.e. kinetic energy and we only use kelvin because 0K means 0 kinetic energy (we cannot do the same using other units)

Answer: from what i can tell it looks like a heterogeneous mixture

Explanation:

heterogeneous is multiple different components, homogenous includes only the same component

An engineer might need to consider this when designing a heating/cooling system for a home in a cooler climate are Operating Environment, Size Matters, Available Power, and Filtration.

The design might differ for a house found in a warmer climate as the inside environment of buildings will be impacted by a warmer climate, which will also impair the longevity of building materials. A larger requirement for cooling will result from hotter summers. The word "HVAC" refers to the many systems that are employed in both residential and commercial structures for the purpose of heating, cooling, and transferring air between indoor and outdoor areas.

These are the systems that keep you cozy and toasty during the winter and cool and energized during the summer. The three essential elements of heating and cooling systems are a source of hot or cold air, a device for transferring the heated or cooled air into your living space, and a way to control the temperature in your home.

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The pressure of the 5.0-liter container containing 3.0 moles of gas at a temperature of 0 degrees Celsius is approximately 13.8 atm.

To calculate the pressure of the gas in the given scenario, we can use the ideal gas law equation:

PV = nRT

Where:

P is the pressure of the gas,

V is the volume of the container (5.0 liters),

n is the number of moles of gas (3.0 moles),

R is the ideal gas constant (0.0821 L·atm/mol·K),

T is the temperature in Kelvin.

First, we need to convert the temperature from Celsius to Kelvin:

0 degrees Celsius + 273.15 = 273.15 Kelvin.

Now we can substitute the values into the ideal gas law equation:

P * 5.0 L = 3.0 mol * 0.0821 L·atm/mol·K * 273.15 K.

Simplifying the equation:

P = (3.0 * 0.0821 * 273.15) / 5.0.

Calculating the expression:

P ≈ 13.8 atm.

Therefore, the pressure of the 5.0-liter container containing 3.0 moles of gas at a temperature of 0 degrees Celsius is approximately 13.8 atm.

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No..since research can take different format

Answer:

Mechanical energy

Explanation:

Given that,

Potential energy of an object is given by :

P = mgh

The kinetic energy of an object is given by :

\(K=\dfrac{1}{2}mv^2\)

Where

m is mass

h is height

v is velocity of the object

The sum of potential and kinetic energy is equal to total energy or the mechanical energy.

Hence, if air resistance is negligible, the sum total of potential and kinetic energies of a freely falling body is equal to mechanical energy.

Answer:

Explanation:

Molecular weight of Be(OH)₂ = 43 .

One mole contains 2 atoms of oxygen . Atomic weight of oxygen is 16 so 2 atoms will have mass of 32 u .

So 43 g of Be(OH)₂ contains 32 g of oxygen .

100 g of Be(OH)₂ contains 32 x 100/ 43  g of oxygen

= 32 x 100/ 43  g of oxygen

= 74.42 % .

Explanation:

\(v = vdm \times n\)

Vdm=22.4dm.

mole(n)=4 mol

therefore the total volume

\(v = 22.4 \times 4 \\ v = 89.6dm\)

Answer:

The study of movement, distribution and quality of water.

Explanation:

They measure the properties of bodied of water, such as the volume of and stream flow.

Answer: aint no way you really put positive but anywya um on the benefits side, fracking increases economic activity, employment, income and housing prices. But, it also brings more truck traffic, increases in crime and potential health impacts possibly due to air and/or water pollution.

use his but put it in your own words

Explanation: yes

1-I can be a little more specific- we do NOT have enough evidence that fracking, as most induced earthquakes are not directly caused by hydraulic fracturing. Even though fracking can release many harmful gases such as methane, it cannot cause seismic waves

2-Research reveals that fracking increases regulated contaminants found in drinking water, but not enough to trigger regulatory violations. However, fracking can affect our underwater stores, mostly through the harmful gases like methane that can contaminate the water and have negative effects on people who drink it.

3- Because fracking releases a massive amount of harmful gases, the community can experience negative effects such as toxic air and health issues. (You should probably support the con sides as there are little reasons fracking is good)

4-Fracking has negative effects on the atmosphere. In fact, there are very little pros about fracking. It release harmful gases into the air, which can further increase the intoxication the air has.

5-Oil and gas development is primarily regulated under multiple federal environmental and public health laws. These laws apply to drilling and hydraulic fracturing from unconventional sources. However, fracking, despite its limitations, still affects the environment.

Answer:

a weighing balance, a measuring cylinder, a spatula, a beaker/flask, and a stirrer

Explanation:

The lab apparatus that would be needed to prepare a solution of sodium chloride would be a weighing balance, a measuring cylinder, a spatula, a beaker/flask, and a stirrer.

The weighing balance would be used to weigh out the required amount of sodium chloride. The beaker or flask would be placed on the weighing balance and its weight zeroed. The spatula would then be sued to take out the sodium chloride from its container into the beaker till the required amount is reached. The measuring cylinder would then be used to measure out the required volume of water which would be added to the salt in the beaker. The stirrer would then be used to stir the mixture in order for the salt to dissolve.

There are 1.145 x 10^23 hexane molecules in 25.0 mL of hexane.

To calculate the number of molecules of hexane in 25.0 mL of hexane, we need to convert the volume to the amount of substance using the density of hexane.

The formula to convert from volume (in mL) to mass (in g) is:

mass = volume x density

mass of hexane = 25.0 mL x 0.6548 g/mL = 16.37 g

Next, we can use the molar mass of hexane (C6H14) to convert the mass of hexane to moles:

moles of hexane = mass of hexane / molar mass of hexane

The molar mass of hexane is:

(6 x atomic mass of carbon) + (14 x atomic mass of hydrogen)

= (6 x 12.01 g/mol) + (14 x 1.01 g/mol)

= 86.18 g/mol

moles of hexane = 16.37 g / 86.18 g/mol = 0.1903 mol

Finally, we can use Avogadro's number to convert from moles of hexane to the number of hexane molecules:

number of hexane molecules = moles of hexane x Avogadro's number

where Avogadro's number is 6.022 x 10^23 molecules/mol.

number of hexane molecules = 0.1903 mol x 6.022 x 10^23 molecules/mol

= 1.145 x 10^23 hexane molecules

Therefore, there are 1.145 x 10^23 hexane molecules in 25.0 mL of hexane.

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Thus, the electrons in CO2 are delocalized because they are distributed over the three atoms of the molecule.

Out of the following molecules/ions, CO2 will exhibit delocalized pi (π) bonding.

The given molecules/ions are O2, CO2, CoCl2, and O3 (oz).

Delocalized pi (π) bonding refers to bonding that occurs over three or more atoms instead of two atoms in a molecule. The electrons that participate in delocalized pi (π) bonding are delocalized, which means they are not restricted to a single bond between two atoms.

Carbon dioxide (CO2) will exhibit delocalized pi (π) bonding because it is a planar molecule in which the two π bonds are distributed over three atoms. Carbon is the central atom of CO2, and each oxygen atom is attached to the carbon atom via double bonds.

Carbon dioxide has two double bonds between the carbon and oxygen atoms, with each double bond having a π bond and a σ bond. Because the carbon atom has four valence electrons, it forms two double bonds with two oxygen atoms and has two lone pairs of electrons. Thus, the electrons in CO2 are delocalized because they are distributed over the three atoms of the molecule.
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To find the actual amount of reactants that are needed to get a desired amount of product, you would need the balanced chemical equation for the reaction, the molar mass of the reactants and products, and the desired amount of product.

When balancing a chemical equation, coefficients are added to ensure that the same number of atoms of each element is present on both sides of the equation. This means that the coefficients represent the number of moles of each reactant and product that are involved in the reaction. Therefore, the balanced chemical equation is essential for determining the stoichiometry of a reaction, which is the study of the quantitative relationships between reactants and products in a chemical reaction. Once the balanced chemical equation is known, the molar mass of each reactant and product is needed to convert between mass and moles. Molar mass is the mass of one mole of a substance, which is found by adding up the atomic masses of all the atoms in a molecule. For example, the molar mass of water (H2O) is 18.015 g/mol because it contains two hydrogen atoms with a molar mass of 1.008 g/mol each and one oxygen atom with a molar mass of 15.999 g/mol.

To determine the actual amount of reactants needed to produce a desired amount of product, the stoichiometry of the reaction is used to calculate the theoretical yield, which is the maximum amount of product that can be obtained from a given amount of reactant. The theoretical yield is found by using the balanced chemical equation to determine the mole ratio between the reactants and products and then multiplying by the amount of limiting reactant present. The limiting reactant is the reactant that is completely consumed in a reaction, limiting the amount of product that can be formed. To determine the limiting reactant, the amounts of each reactant are compared using their molar masses and the mole ratio from the balanced chemical equation. The reactant that produces the least amount of product is the limiting reactant.
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The molarity of a solution is calculated by dividing the number of moles of solute by the volume of the solution in litres.
Therefore, the molarity of the H₂CO solution is 13.30 mol/L.

In this case, we have 5.50 L of a 13.3 M H₂CO solution. To find the molarity, we need to calculate the number of moles of H₂CO and divide it by the volume of the solution.

The formula weight of H₂CO is 30.03 g/mol. To convert from molarity to moles, we multiply the molarity by the volume in liters:

13.3 mol/L × 5.50 L = 73.15 mol

So we have 73.15 moles of H₂CO in 5.50 L of solution.

Finally, to find the molarity, we divide the number of moles by the volume of the solution:

73.15 mol ÷ 5.50 L = 13.30 mol/L

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The flaw in Regina’s plan is that the time frame is unrealistic (option B).

Goal setting involves the development of an action plan designed in order to motivate and guide a person or group toward a goal, which is a result that one is attempting to achieve.

Effective goal setting lets you measure progress, overcome procrastination and visualize your dreams. However, setting goals is said to be effective when it is done in an adequate time frame.

According to this question, Regina identifies her goal and hastily writes it down as follows: I will make an A on my English literature term paper that is due next week.

This goal, although is great, is unlikely to be met because of the time frame. One cannot get an excellent result in something that lacks adequate preparation, which includes adequate time.

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