Answer:
ans is a .attention
plsssssssssssss mark meeee brainlist
Explanation:
Air is expanded in a polytropic process with n = 1.2 from 1 MPa and 400°C to 110 kPa in a piston?cylinder device. Determine the final temperature of the air.
Select one:
a. 466 C
b. 123.6 C
c. 193 C
d. 290 C
The final temperature of the air is (c) 193°C.
Explanation:-
Given,
The initial pressure, P1 = 1 MPa
The initial temperature, T1 = 400 °C
The final pressure, P2 = 110 kPa
The polytropic exponent, n = 1.2
We need to determine the final temperature of the air.
Solution:
For the polytropic process with a given polytropic exponent n, the work done can be given as;
W = P1V1 (1 - n) / (n - 1) [1 - (P2 / P1) ((n - 1) / n)] -------------- [1]
Where,V1 = (mRT1) / P1 ------------- [2]
V2 = (mRT2) / P2 ------------- [3]
Combining equations [2] and [3], we get;
V2 / V1 = P1 / P2 * T2 / T1T2
= T1 (V2 / V1) * (P2 / P1) --------------- [4]
Now, substituting equation [2] into equation [1],
we get;
W = (mRT1) / P1 * (1 - n) / (n - 1) [1 - (P2 / P1) ((n - 1) / n)]
Also, substituting equation [4] into equation [1],
we get;
W = (mR T1) / P1 (1 - n) / (n - 1) [1 - (P2 / P1) ((n - 1) / n)]T2
= T1 (1 - n) / n [1 - (P2 / P1) (n - 1)] ------------ [5]
where m is the mass of the gas and R is the gas constant.
For air, the value of R is 0.287 kJ/kg.K.
Substituting the values in equation [5],
we get;T2 = 400 × (1 - 1.2) / 1.2 [1 - (110 / 1000) (1.2 - 1)]
= -220.34 K (-53.81°C)
However, the final temperature of the air cannot be negative.
Therefore, the process must be irreversible or isothermal.
Thus, the option (c) 193°C is the correct answer.
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Two cars are rounding curves. Both cars are traveling at a constant speed of 25 miles per hour. Car A is rounding a very sharp curve and car B is rounding a gradual curve. Which of the following are true regarding the motion of the cars?
A. Car A and B have the same acceleration because they have the same speed.
B. Car A and B have the same acceleration because they have the same velocity.
C. Car A and B both have zero acceleration because their speeds are not changing.
D. Car A is accelerating more than car B because it is changing direction at a faster rate.
Add an explanation please!!
Answer:
d
Explanation:
would you expect your experimental measurements of 8 to be more precise if you used a tuning fork with large f or small f? explain.
The precision of an experimental measurement is determined by the smallest possible increment of the measuring instrument. In the case of a tuning fork, the frequency of the fork is the quantity being measured.
If a tuning fork with a larger frequency (f) is used, the resulting oscillations will be more rapid, and the time period between successive oscillations will be shorter. Therefore, measuring the frequency of a high-frequency tuning fork requires a more precise measurement of time. This could lead to a less precise measurement of the frequency because measuring short time intervals accurately can be challenging.
On the other hand, if a tuning fork with a smaller frequency (f) is used, the resulting oscillations will be slower, and the time period between successive oscillations will be longer. Measuring the frequency of a low-frequency tuning fork is less sensitive to small variations in time measurements. Therefore, using a low-frequency tuning fork may result in more precise measurements of the frequency.
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you place a 7/50 kg television set on a spring scale. if the scale reads 78.4 n, what is the acceleration due to gravity at that location?
The acceleration due to gravity is 9.8 m/s^2.
What is gravity?
In mechanics, gravity—also known as gravitation—is the constant force of attraction that pulls all matter together. It has no impact on determining the internal characteristics of common matter because it is by far the weakest known force in nature. In contrast, it governs the structures as well as evolution of stars, galaxies, as well as the entire cosmos through its extensive and universal action, which affects the trajectories of objects in the solar system and throughout the universe. All objects on Earth have a weight, or a gravitational pull downward, proportional to their mass, which is a result of the mass of the planet. The acceleration that gravity gives to objects falling freely serves as a gauge of its strength. The acceleration of gravity at Earth's surface is approximately 9.8 metres (32 feet) per second for every second.
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How does newton’s three laws of motion explain how any type of rockets work?
Newton's laws explain how rockets work by providing a framework for understanding how they generate thrust through the burning of fuel, which creates an equal and opposite reaction, propelling the rocket forward.
Newton's three laws of motion are crucial to understanding how any type of rocket works. Here's how each of the laws applies to rockets:
1. Newton's First Law: The Law of Inertia: An object at rest tends to stay at rest, and an object in motion tends to stay in motion with a constant velocity, unless acted upon by an external force.
This law is important because it explains how rockets can overcome the force of gravity and achieve lift-off. When a rocket is sitting on the launchpad, it is at rest. But when the rocket engines ignite, they produce a force that propels the rocket forward. As the rocket moves, it gains momentum and continues to move forward with a constant velocity, even as it encounters the force of gravity pulling it back down towards Earth.
2. Newton's Second Law:The Law of Acceleration: The acceleration of an object is directly proportional to the force applied to it and inversely proportional to its mass.
This law explains how rockets can generate the necessary thrust to achieve escape velocity and leave Earth's gravitational pull. The rocket engines produce a force, or thrust, that propels the rocket forward. As the force of the thrust increases, the acceleration of the rocket also increases, allowing it to overcome the force of gravity and achieve lift-off. The mass of the rocket also plays a crucial role, as a lighter rocket requires less force to achieve the same acceleration as a heavier rocket.
3. Newton's Third Law: The Law of Action and Reaction: For every action, there is an equal and opposite reaction.
This law explains how rockets can generate thrust by expelling mass in the opposite direction. The rocket engines work by expelling a stream of hot gases out of the back of the rocket at a high velocity. According to Newton's Third Law, for every action (the expulsion of the gases), there is an equal and opposite reaction (the forward thrust of the rocket). This reaction force propels the rocket forward and allows it to overcome the force of gravity and achieve lift-off.
In summary, Newton's laws of motion provide the foundation for understanding how rockets work. By generating thrust through the expulsion of mass, rockets are able to achieve lift-off and overcome the force of gravity to reach space.
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Which action would help reduce global warming?- Eat less red meat so fewer cattle need to be raised.- Ride a bicycle rather than walk to school.- Clear more forests to produce more farmland.- Use more fertilizers to increase crop production.
Eating less red meat so fewer cattle need to be raised would help reduce global warming.
What are the precautions to reduce by global warming?The production of red meat, particularly beef, is a major contributor to greenhouse gas emissions. Cattle produce methane, a potent greenhouse gas, and the production of feed for cattle also requires large amounts of energy, water and land. Additionally, the clearing of forests for grazing land and feed production also contributes to carbon emissions.
Riding a bicycle rather than walking to school would also help reduce global warming because it would decrease the amount of CO2 emissions produced by cars and other vehicles.
Clearing more forests to produce more farmland and using more fertilizers to increase crop production would not help to reduce global warming, as the clearing of forests causes a release of stored carbon into the atmosphere and the use of fertilizers and pesticides also has an environmental impact.
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PLEASE HELP! DUE IN 30 MINS! 50 POINTS!The questions that were cut off at the bottom were: What rule of magnetism is illustrated by the lines of the iron filings in Step 12?
What rule of magnetism is illustrated by the lines of the iron filings in Step 15?
Why was glass or plastic used to separate the filings from the magnets in the experiments?
Did the glass or plastic stop the passage of the magnetic lines of force?
Did the iron filings almost or completely bridge the open end of the horseshoe magnet?
The lines of iron fillings will be attracted towards the poles of the magnet on the paper. The fillings gets sticked on the magnet. The glass or plastic will stop the passage of the magnetic lines of force .
What are magnetic field lines ?Magnetic field lines are lines of force generated by a strong magnetic field. For a bar magnet, the magnetic south pole and north pole are having stronger magnetic fields than the middle part.
When magnetically susceptible materials comes in contact with a magnet they gets attracted to the poles of the magnet. The fields lines of the material gets aligned parallel to the applied field.
Some materials such as paper and glass are not showing magnetic properties. Hence, they can stop the passage of magnetic field lines. If we place a glass or paper in between the poles of a two magnets, they will stick to the glass from both ends due to the attraction to the opposite pole.
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Suppose an electron is incident at an angle θ0 as shown in the figure between two plates that create a uniform electric field.
The path is symmetrical, so even when electrons exit, the angle goes out at the same θ0 and almost passes by the upper plate.. How much is θ0? The corner effect is ignored. (Hint: Put the electric field as E, length as L, and spacing as d, and first obtain the result with the letter, then substitute the number at the end.)
The angle θ0 at which the electron is incident between the two plates, we can use the relationship θ0 = arctan(E * L / (2d)).
determine the angle θ0 at which the electron is incident between the two plates, we can consider the forces acting on the electron due to the electric field.
The electric field between the plates is directed from left to right. The force experienced by the electron due to the electric field is given by the equation:
F = q * E
where F is the force, q is the charge of the electron, and E is the electric field strength.
Since the electron is negatively charged, it experiences a force in the opposite direction to the electric field. This force will cause the electron to accelerate in the opposite direction.
When the electron enters the region between the plates:
The force due to the electric field will act on the electron in the opposite direction to its initial motion, causing it to decelerate. The electron will follow a curved path due to this deceleration.
When the electron exits the region between the plates:
The force due to the electric field will act on the electron in the same direction as its final motion, causing it to accelerate. The electron will follow a curved path due to this acceleration.
Since the situation is symmetrical, the angle at which the electron exits the region between the plates will be the same as the angle at which it enters.
We need to determine the angle θ0 at which the electron enters the region between the plates.
Consider a small portion of the path between the plates and assume that the electric field is constant within this small region.
In this small region, the net force acting on the electron can be expressed as:
F_net = F_electric - F_centrifugal
where F_electric is the force due to the electric field, and F_centrifugal is the centrifugal force.
The force due to the electric field can be calculated as:
F_electric = q * E
The centrifugal force can be calculated as:
F_centrifugal = m * \(v^2 / r\)
where m is the mass of the electron, v is its velocity, and r is the radius of the curved path.
The electron is moving in a curved path, the net force acting on it is responsible for the centripetal force required to maintain this curved path.
Setting the net force equal to the centripetal force, we have:
F_electric - F_centrifugal = m * \(v^2 / r\)
Substituting the expressions for F_electric and F_centrifugal, we get:
q * E - m * v^2 / r = m * \(v^2 / r\)
Simplifying the equation, we have:
q * E = 2 * m * \(v^2 / r\)
Since the electron enters and exits the region between the plates with the same speed v, we can simplify further:
q * E = 2 * m *\(v^2 / r\)
The forces acting on the electron when it enters the region between the plates:
The force due to the electric field is acting in the opposite direction to the initial motion, causing deceleration.
The centrifugal force is acting in the same direction as the initial motion, opposing the deceleration.
For the electron to enter the region between the plates, the force due to the electric field must be greater than the centrifugal force.
We have:
q * E > m * \(v^2 / r\)
Since the electron is moving perpendicular to the electric field, the electric force can be expressed as:
q * E = q * (V/d)
where V is the voltage between the plates, and d is the spacing between the plates
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The flow of electric charge that is equal to one coulomb per second is an ampere. Is this true or false?
Ampere:
Ampere is the unit of electric charge or also known as electric current.
It is defined as the flow of electric charge equal to one coulomb per second.
The symbol used for ampere is "A"
Therefore, we can conclude that the given statement is true.
"The flow of electric charge that is equal to one coulomb per second is an ampere"
derive the equation for circular motion,a=rw^2, where a is the centripetal acceleration w is the angular velocity and r the radius of the circle (B) (i) the moon orbits the earth in a circle of radius 400000km. considering only these two objects, state what force act on the moon and explain how newton third law of motion applies to the system. (ii) find the time for one complete revolution of the moon about the earth.
Answer: It takes the moon 27.3 days to complete one revolution around the earth.
Explanation:
(i) The force that acts on the moon is the gravitational force between the moon and the earth, given by the equation F = G * (m1 * m2) / r^2, where G is the gravitational constant, m1 and m2 are the masses of the earth and the moon, respectively, and r is the distance between the two objects. According to Newton's third law of motion, for every action there is an equal and opposite reaction. In this case, the earth pulls the moon towards it with the gravitational force, and the moon exerts an equal and opposite force on the earth.
(ii) To find the time for one complete revolution of the moon about the earth, we can use the equation T = 2π * √(r^3 / (G * M)), where T is the period of revolution, r is the radius of the orbit, G is the gravitational constant, and M is the mass of the earth. Plugging in the given values, we get:
T = 2π * √(400,000 km^3 / (G * M))
T = 2π * √(400,000,000,000 m^3 / (6.67 × 10^-11 Nm^2/kg^2 * 5.97 × 10^24 kg))
T = 2π * √(67,000,000,000,000 s^2)
T = 27.3 days
So, it takes the moon 27.3 days to complete one revolution around the earth.
If you were on a rocket traveling at 99.9% of the speed of light: if someone felt like 1 year had passed on earth how much time would have passed for you in the rocket?
What is the first law of thermodynamics deals?
The first law of thermodynamics, also known as the law of conservation of energy, states that energy cannot be created or destroyed, only transformed from one form to another.
This law applies to all physical systems and is a fundamental concept in the field of thermodynamics. The first law can be expressed mathematically as:
ΔE = Q - W
where ΔE is the change in internal energy of a system, Q is the heat added to the system, and W is the work done by the system. The internal energy of a system represents the total amount of thermal, kinetic, and potential energy that is stored within it.
The first law of thermodynamics is a key principle in understanding the behavior of energy in physical systems. For example, it helps explain why energy must be input into a system to increase its temperature, and why energy is lost in the form of heat and work as a result of changes in a system's state. Additionally, the first law of thermodynamics is a critical component of many applications, such as engines, power plants, and other heat-based technologies, where energy must be converted from one form to another in order to perform useful work.
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6. Explain that alpha, beta, and gamma radiation produce different amounts and kinds of damage
in matter and describe the effects of each kind of radiation on living things.
Alpha radiation causes localized damage, beta radiation can penetrate skin and cause cell damage, and gamma radiation can penetrate deeply and cause widespread damage throughout the body.
The effects of each kind of radiation on living things depend on factors such as the dose, duration of exposure, and sensitivity of the tissues or organs involved.
Alpha, beta, and gamma radiation are three types of ionizing radiation that differ in their ability to penetrate matter and the kind of damage they produce.
Alpha radiation consists of helium nuclei (two protons and two neutrons) and has low penetration power. However, due to their size and positive charge, alpha particles can cause significant damage when they interact with matter. They can ionize atoms and disrupt molecular structures. In living organisms, alpha radiation can be highly damaging if inhaled or ingested, as it can deposit its energy in a small area and cause severe tissue damage, leading to cell death or mutation.
Beta radiation consists of fast-moving electrons or positrons. Beta particles have higher penetration power compared to alpha particles, but they are still stopped by a few millimeters of material. Beta radiation can cause ionization and can penetrate the outer layers of the skin. In living organisms, beta radiation can damage cells, increase the risk of cancer, and cause skin burns if exposed for a prolonged period.
Gamma radiation is a form of electromagnetic radiation with high energy and no mass or charge. Gamma rays have excellent penetration power and can pass through most materials. They can cause ionization and damage to cells and DNA. Gamma radiation poses a significant risk to living organisms as it can penetrate the body and cause widespread damage, leading to tissue destruction, cell death, and an increased risk of cancer.
In summary, alpha radiation causes localized damage, beta radiation can penetrate skin and cause cell damage, and gamma radiation can penetrate deeply and cause widespread damage throughout the body. The effects of each kind of radiation on living things depend on factors such as the dose, duration of exposure, and sensitivity of the tissues or organs involved.
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Comets are typically ?
a.) chunks of ice that begin to vaporize if they pass close to the sun.
b.) slushy mixtures of liquid and ice.
c.) gaseous bodies from which some of the gas is pushed out by the sun to form a long tail.
d.) chunks of rock that are generally a few tens of kilometers in diameter.
??? i appreciate those that help!!! <3
p.s. this subject is astronomy it just doesnt have it as a subject option nor a science option....
Answer:
the answer is a) chunks of ice that begin to vaporized if they pass close to the sun
A large raindrop the type that lands with a definite splat--has a mass of 0.014 g and hits your roof at a speed of 8.1 m/s.a. What is the magnitude of the impulse delivered to your roof? Express your answer with the appropriate units.b. If the raindrop comes to rest in 0.37 ms, what is the magnitude of the force of the impact? Express your answer with the appropriate units.
The impulse delivered to the roof is -0.115 Ns and the magnitude of the force of the impact is -31.17 kN.
a. Impulse is defined as the product of the force acting on an object and the time over which the force is applied. In this case, the impulse delivered to the roof is the product of the force acting on the raindrop and the time it takes for the raindrop to come to a stop after hitting the roof. Since we don't know the time of impact, we can use the impulse-momentum theorem which states that the impulse of a force acting on an object is equal to the change in momentum of the object.
The impulse delivered to the roof is given by J = Δp = pf - pi
The initial momentum of the raindrop is given by pi = m * vi = 0.014g * 8.1 m/s = 0.115 Ns
Since the final velocity of the raindrop is zero (it comes to rest), the final momentum is zero. Therefore, the impulse delivered to the roof is J = pf - pi = 0 Ns - 0.115 Ns = -0.115 Ns
b. To find the force of the impact we can use the equation: F = J/t
where F is the force of the impact, J is the impulse delivered to the roof, and t is the time it takes for the raindrop to come to a stop after hitting the roof.
We have that t = 0.37 ms = 0.00037 s
So F = J/t = -0.115 Ns / 0.00037 s = -31167.57 N or -31.17 kN
Here, the negative sign of the force tells us that the force is opposite to the direction of motion, which means that the force is acting to stop the motion of the raindrop.
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g A man has polydactyly; an autosomal dominant trait. His hands and feet all have extra digits. His daughter and wife both have the normal number of fingers and toes. What is the probability that their next child will have polydactyly
The probability that their next child will have polydactyly is 50%.
How likely is it that their next child will have polydactyly?Polydactyly is an autosomal dominant trait, which means that if a parent has the trait, there is a 50% chance of passing it on to their child. In this case, the man has polydactyly, indicating that he carries the gene for extra digits. However, his daughter and wife do not have polydactyly, suggesting that they do not carry the gene.
When determining the probability of their next child having polydactyly, we consider that the man has a 50% chance of passing on the gene to each child. The daughter and wife, who do not carry the gene, do not affect the likelihood of polydactyly in the next child.
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You did 100 j of work to move a 10 n object. How far did you move the object
\(w = fdcos( \alpha )\)
where w is the work done.where f is the force in newton.where d is the displacement.and a is the angle between the force and the displacement.\(w = fdcos(0)\)
\(100 = 10d \times 1\)
\( \frac{10d}{10} = \frac{100}{10} \)
\(displacement = 10 \: meters\)
Look at the diagram. The electricity supplier charges 14p per unit. How much did this electricity cost over the 24 hour period
Total units
31487-3146323unitsCost°
14(23)$322PLOT A GRAPH OF L AGAINST T² AND DETERMINE THE SLOPE
The measured value of g is determined by the slope of the time period T² vs. l graph (acceleration due to gravity).
Time period the amount of time that a behavior lasts or a condition persists. Depending on the type of activity or situation under consideration, it may be measured in seconds or in millions of years.
the duration T as determined by the formula T = 2π √(l/g). The pendulum's length, l, is indicated here.
The result of squaring both sides is T² = 4π² l/g
42 and g are constants, thus
⇒ T² = ml
The slope of the T² vs l graph in this case is m. The slope's value is m = 4π²/g
We can determine the value of g from the slope of the graph by substituting π = 10 in the equation above.
g = 40/m
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A rock is thrown straight upward. Neglect air resistance. What is the direction of its acceleration as it is rising?a. The acceleration is zerob. Downward c. Upward
Neglecting air resistance the direction of acceleration of a rock thrown straight upward is upward.
The acceleration of the rock as it is rising is upward. This is due to the force of gravity acting on the rock, which is constantly pulling it down toward the ground. As the rock moves upward, the force of gravity is still pulling it down, so the acceleration of the rock is also in the downward direction. However, since the rock is moving upwards, the acceleration is in the opposite direction of the force of gravity, so the acceleration of the rock is actually upward.
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How many seconds would it take a boat to accelerate from 13 m/s to 26 m/s over a distance of 1.25 km?
Time taken by the boat to accelerate is 1 min 4 s.
How to calculate the time taken?V\(f_{2}\) - V\(o_{2}\) = 2 a X ,
a = Vf2 - Vo2 / 2 X
= (26 m/s)2 -(13m/s)2 / 2(1250m)
= 507 m2/s2 / 2.5 m = 0.203 m/s2
Solve for time using the equation with acceleration known.
Vf = at + Vo ,
t = Vf - Vo / a = 26m/s -13m/s/ 0.203 m/s2
= 64 s
= 1 min 4 s
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Two duck hunters are seated back-to-back in a boat. How large is the zone-of-fire for each hunter?
180 degrees
135 degrees
90 degrees
45 degrees
Answer:
180 because it's half of a full rotation before they shoot the other person.
If there is 3.4 m3 of methane gas in a container with a pressure of 18.9 atm and the container expands until the methane has a pressure of 2.2 atm, what is the final volume of the methane? Temperature is constant at 305 K. A. 12.23 m3 B. 141.37 m3 C. 29.21 m3 OD. 2.53 m3
Answer:
C. 29.21 m³
Explanation:
Given the following data;
Initial volume, V1 = 3.4 m³Initial pressure, P1 = 18.9 atmFinal pressure, P2 = 2.2 atmTo find the final volume, we would use Boyle's law;
Boyles states that when the temperature of an ideal gas is kept constant, the pressure of the gas is inversely proportional to the volume occupied by the gas.
Mathematically, Boyles law is given by;
PV = K
\( P_{1}V_{1} = P_{2}V_{2} \)
Making V2 the subject of formula, we have;
\( V_{2} = \frac {P_{1}V_{1}}{P_{2}} \)
Substituting the values into the formula, we have;
\( V_{2} = \frac {18.9 * 3.4}{2.2} \)
\( V_{2} = \frac {64.26}{2.2} \)
Final volume, V2 = 29.21 m³
What name did marie curie give to the process by which materials give off rays capable of fogging photographic plates?
The study of radioactivity by Marie Curie marked a significant turning point in the realm of physics and had a significant influence on scientific knowledge. Now let's get into the specifics.
"Radioactivity" is the term Marie Curie coined to describe the phenomenon whereby materials emit radiation that can fog photographic plates. During her uranium investigation in 1896, she made this discovery. This game-changing discovery opened the door for more research into and comprehension of radioactivity, which resulted in important developments in the field of nuclear physics.
Marie Curie's research on radioactivity served as a springboard for additional nuclear physics research and has profound ramifications for other fields of science and medicine. It resulted in improvements in our knowledge of atomic structure, the creation of radiation therapy for the treatment of cancer, and the eventual exploitation of nuclear energy.
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A 40-N force acts on an 80-kg object, initially moving at 20 m/s. How far will the object travel in the next five seconds?
Answer:
106.25 m
Explanation:
Acceleration a = force / mass
= 40 / 80 = 0.5 m /s²
initial velocity u = 20 m /s
a = 0.5 m /s²
time t = 5 s
displacement s = ?
s = ut + 1/2 a t²
= 20 x 5 + .5 x .5 x 5²
= 100 + 6.25
= 106.25 m .
The archer’s other hand is pushing the bow with the same force of 120 N. This force acts on a larger area than the force in (i). State whether the pressure on this hand is greater than, the same as or less than the pressure on the fingers holding the string. Give reason for your answer.
Answer:
The pressure the hand is less than the pressure on the fingers holding the string
Explanation:
The force with which the archer is pushing against the bow = 120 N
The area on which the force acts on the hand > The area the force acts on the fingers
Pressure = Force/Area
Pressure ∝ 1/Area
The larger the area, the lesser the pressure
The pressure acting on the hand which exerts the force with a larger area is less than the pressure on the finger which exerts the same force on a smaller area
The correct option is therefore;
The pressure the hand is less than the pressure on the fingers holding the string
A toroidal solenoid of square cross-section is made with inner and outer radii of 3.0 and 4.0 cm. How many turns of wire are necessary to obtain a self-inductance of 1.15 H
To find the number of turns of wire necessary to obtain a self-inductance of 1.15 H for a toroidal solenoid of square cross-section with inner and outer radii of 3.0 and 4.0 cm, we can use the formula for the self-inductance of a toroidal solenoid:
L = μ₀N²πr² / (2πr + πd)
where L is the self-inductance, N is the number of turns of wire, r is the mean radius (the average of the inner and outer radii), d is the cross-sectional diameter (in this case, equal to the side length of the square cross-section), and μ₀ is the permeability of free space (4π x 10^-7 H/m).
Plugging in the given values, we get:
1.15 = (4π x 10^-7)(N²π(0.035+0.04)²) / (2π(0.04) + π(0.01))
Simplifying, we get:
1.15 = 1.053 x 10^-6 N²
Solving for N, we get:
N = √(1.15 / 1.053 x 10^-6) ≈ 1093 turns
Therefore, approximately 1093 turns of wire are necessary to obtain a self-inductance of 1.15 H for the given toroidal solenoid.
To find the number of turns of wire necessary for a toroidal solenoid with a square cross-section, inner radius of 3.0 cm, outer radius of 4.0 cm, and a self-inductance of 1.15 H, we can use the formula for the self-inductance of a toroidal solenoid:
L = (μ₀ * N² * A * h) / (2 * π * R)
where:
L = self-inductance (1.15 H)
μ₀ = permeability of free space (4π × 10⁻⁷ H/m)
N = number of turns of wire (unknown)
A = cross-sectional area of the solenoid (square cross-section)
h = height of the solenoid (which is the difference between the outer and inner radii, 4.0 cm - 3.0 cm = 1.0 cm)
R = average radius of the solenoid (which is the average of the inner and outer radii, (3.0 cm + 4.0 cm) / 2 = 3.5 cm)
First, convert the measurements from cm to meters:
h = 1.0 cm * 0.01 m/cm = 0.01 m
R = 3.5 cm * 0.01 m/cm = 0.035 m
Rearrange the formula to solve for N:
N = sqrt((2 * π * R * L) / (μ₀ * A * h))
Since A is not provided, you will need the value of the square cross-sectional area to calculate the exact number of turns (N). Once you have that value, plug it into the formula, and solve for N.
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A car travels at a speed of 55 km/hr and slows down to 10 km/hr in 20 seconds. What is the acceleration?
a) -2.25 km/h/s
b) 2.25 km/h/s
c) 3.5 km/h/s
d) -3.5 km/h/s
Answer:
b
Explanation:
Two cars are moving along a stright line in the same direction with a velocity of 25 km/h and 30 km/h respectively. find the velocity of car a relative to car b
Answer:
Explanation:
V = Vb - Va = 30 - 25 = 5 km/h
what is the another name ffo
Answer:
sorry buh I don't get the question