Properties and Uses of Unsaturated Hydrocarbons

Project: Communicating Design Details

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Answer:

pure hydrogen is a pure substance even though it consists of many different types of molecules. what makes it pure substance is that it is free from contamination.

Answer:

The energy of a ruby laser that produces red light with a wavelength of 5.00 × 10^-7 m is 3.98 × 10^-19 J.

Explanation:

The energy of a photon is given by the formula E = hf where h is Planck’s constant and f is the frequency of the photon. The frequency of the photon can be calculated using the formula f = c/λ where c is the speed of light and λ is the wavelength of the photon.

Substituting the given values, we get:

f = c/λ = 3.00 × 10^8 m/s / 5.00 × 10^-7 m = 6.00 × 10^14 Hz

E = hf = (6.626 × 10^-34 J s) × (6.00 × 10^14 Hz) = 3.98 × 10^-19 J

Therefore, the energy of a ruby laser that produces red light with a wavelength of 5.00 × 10^-7 m is 3.98 × 10^-19 J.

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Given: Volume of solution, V = 10 mLConcentration of solution, C = 0.5 mol/L.

With this, we can convert the volume from mL to L by dividing it by 1000. Therefore,V = 10 mL = 10/1000 L = 0.01L. Now, we can use the formula: n = C x V where,n = number of moles C = concentration of solutionV = volume of solution. Plugging in the values, we get,n = 0.5 mol/L x 0.01 L= 0.005 mol. In chemistry, mole is defined as a unit for measuring amount of substance. The symbol used for mole is 'mol'. This unit helps to express the number of particles in a sample of substance. For instance, one mole of a substance contains 6.022 x 10²³ particles of that substance.A solution is a homogeneous mixture of two or more substances. The concentration of a solution refers to the amount of solute present per unit volume of the solution. It is usually expressed in moles per litre (mol/L) or molarity.

Molarity is defined as the number of moles of solute present in one litre of solution. It is given by the formula:M = n/Vwhere,M = molarity of the solutionn = number of moles of solute presentV = volume of the solution in litresIn the given question, we are given the volume of solution and its concentration. Therefore, we can use the formula:M = n/Vto find the number of moles of HCl present in 10 mL of a solution with a concentration of 0.5 mol/L. There are 0.005 moles of HCl present in 10 mL of a solution with a concentration of 0.5 mol/L.

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The net Ionic equation for the reaction is

Ag⁺+ Cl⁻→ AgCl

Steps for writing net ionic equation:

Balanced Chemical equation:

AgNO₃(aq) + NaCl(aq) → AgCl(s) + NaNO₃(aq)

Splitting

Ag⁺ + NO³⁻ + Na⁺ + Cl⁻ → AgCl + Na⁺ + NO³⁻

Net Ionic Equation

Ag⁺+ Cl⁻→ AgCl

Na⁺ and NO³⁻ are spectator ions, hence they are not included in the net ionic equation. Because it exists in solid form, AgCl cannot be separated into ions.

Therefore, net ionic equation is

Ag⁺+ Cl⁻→ AgCl

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kinetic energy kkkkkkkkkk

Answer:

Explanation:We first calculate the heat released:

Specific heat = 3.21 kJ/kgK

Heat released = heat absorbed by calorimeter

Heat absorbed = mcΔT

= 1.9 x 3.21 x 4.542

= 27.7 kJ

Now, we calculate the moles of hexane present:

Moles = mass / Mr

moles = 0.58 / (12 x 6 + 14)

= 0.0067

Heat of combustion = 27.7 / 0.0067 kJ/mol

ΔH(combustion) = 4,134.3 kJ / mol

Answer:

2S02 + O2 ---> 2SO3

Its balanced now as Reactants = Products.

Answer:

This equation is a double reaction

Explanation:

I hope this is the answer

Answer:

ca(OH)2 is the base and CaCI2 is the salt

Explanation:

The gram formula mass of sodium sulfide is 78.04 g/mol.

Sodium sulfide is a chemical compound with the formula Na₂S, which is a type of salt. It is white in color, water-soluble, and deliquescent. It has a pungent odor similar to hydrogen sulfide due to its tendency to hydrolyze. The compound is a common source of hydrogen sulfide, which is a highly toxic gas. This substance is frequently utilized in various industries as a reducing agent.

The gram formula mass is the sum of the gram atomic masses of each atom in the formula for a compound. To determine the gram formula mass of sodium sulfide, you need to find the atomic masses of each element that make up the compound. The formula for sodium sulfide is Na₂S.

Here's how to calculate the gram formula mass of sodium sulfide:

Add the atomic mass of Na and atomic mass of S; atomic mass of Na is 22.99 g/mol, and atomic mass of S is 32.06 g/mol, so:

Na₂S = 2 Na + S= 2 (22.99 g/mol) + 32.06 g/mol= 45.98 g/mol + 32.06 g/mol = 78.04 g/mol

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Answer:

A small positively charged nucleus surrounded by revolving negatively charged electrons in fixed orbits

Answer:

Geologists commonly consider faults to be active if there has been movement observed or evidence of seismic activity during the last 10,000 years. Active faulting is considered to be a geologic hazard - one related to earthquakes as a cause.

Explanation:

Plz mark brainliest thanks

Answer:

what

Explanation:

a. The number of grams of sodium oxide produced by 100 g Na would be 134.85 grams while the amount produced by 60 g oxygen would be 232.5 grams.

b. The mass of excess reactant left over at the conclusion of the reaction would be 24.624 grams of oxygen.

The unbalanced equation goes thus: \(Na + O_2 -- > Na_2O\)

First, we need to balance the equation of the reaction. This balanced equation is written as:

\(4 Na + O_2 -- > 2Na_2O\)

From the equation:

With 100 g Na:

Mole = 100/23

        = 4.35 moles

Equivalent mole of \(Na_2O\) = 4.35/2

                                          = 2.175 moles

Mass of 2.175 moles of \(Na_2O\) = 2.175 x 62

                                                 = 134.85 grams

Thus, 134.85 grams of \(Na_2O\) will be produced with 100g of Na.

With 60 g of oxygen:

Mole = 60/32

        = 1.875 moles

Equivalent moles of \(Na_2O\) = 1.875 x 2

                                           = 3.75 moles

Mass of 3.75 moles \(Na_2O\) = 3.75 x 62

                                           = 232.5 grams.

Thus, 232.5 grams of \(Na_2O\) will be produced with 60 g of oxygen.

To get the excess reactant:

Mole of 100 g Na = 4.35 moles

Mole of 60 g oxygen = 1.875 moles

Mole ratio of Na to oxygen = 4:1

Thus the excess reactant is oxygen.

Actual amount of oxygen = 4.35/4

                                           = 1.0875 moles

Excess mole of oxygen = 1.857 - 1.0875

                                       = 0.7695 moles

Mass of excess oxygen = 0.7695 x 32

                                       = 24.624 grams

Thus, the mass of the excess reactant left over after the conclusion of the reaction is 24.624 grams of oxygen.

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The combustion of methane, CH4, releases 890.4 kJ/mol. That is, when one mole of methane is burned, 890.4 kJ are given off to the surroundings. This means that the products have 890.4 kJ less than the reactants.

Combustion of one mole or 16 g of methane gas releases 810 kJ of heat energy. Thus, heat released by the combustion of 22.4 g of methane is 1134 kJ.

Combustion of a substance is its reaction with atmospheric oxygen producing carbon dioxide and water. Combustion of hydrocarbons gases takes places easily and can be burned easily for fuels.

The chemical equation of combustion of methane is written below:

\(\rm CH_{4} + 2O_{2} \rightarrow CO_{2} + 2H_{2}O\)

This is an exothermic process and heat is released from the reaction system.

The heat released by the combustion of one mole of methane is 810 kJ.

molar mass of methane = 16 g/mol

no.of moles in 22.4 g = 22.4/16 = 1.4 g

Thus, heat released by 1.4 moles = 1.4 ×810 kJ =1134 kJ.

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In a TLC experiment, the compound with the larger Rf value will elute faster. In the case of naphthalene and 1-bromonaphthalene, the 1-bromonaphthalene will elute faster and have a larger Rf value.

This is because 1-bromonaphthalene is more polar than naphthalene. Polar compounds have a stronger attraction to the polar stationary phase (such as the silica gel in TLC plates) and will interact more with it, resulting in a lower Rf value.

Naphthalene, on the other hand, is less polar and will have a weaker interaction with the stationary phase, allowing it to travel further and have a higher Rf value.

The polarity of a compound is determined by the presence of functional groups or atoms that create an uneven distribution of charge or electronegativity. In this case, the bromine atom in 1-bromonaphthalene increases its polarity compared to naphthalene, leading to a stronger interaction with the stationary phase.

In summary, the 1-bromonaphthalene will elute faster in a TLC experiment and have a larger Rf value compared to naphthalene due to its higher polarity resulting from the presence of a bromine atom.

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The solubility product is 4n³.

The equilibrium constant for a solid's dissolving into an aqueous solution is called the solubility product constant. It is represented as K(sp).

A solution is said to be saturated when it has dissolved all of the solutes it can. At a certain temperature, no additional solute can dissolve in a saturated solution.

Consider the equilibrium for a saturated PbCl₂ aqueous solution.

PbCl₂(s) ⇄⇄ Pb₂ (aq) + 2Cl⁻ (aq)

The equilibrium constant for the dissociation reaction of the PbCl₂ solution is:

K(sp) = [Pb²⁺] [Cl⁻]²

Now, [Pb²⁺] = n mol/L

In the solution, there is one-mole Pb²⁺ and two moles of Cl⁻ .

Therefore,

[Cl⁻] = 2n mol/L

So, the equilibrium constant for the dissociation reaction will be:

K(sp) = [Pb²⁺] [Cl⁻]²

K(sp) = n × (2n)²

K(sp) = n × 2n × 2n

K(sp) = 4n³

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0.05104 kcal/g is the calorific value of potato chips

Let the calorific value of potato be H cal/g

so, the heat of potato chips is 2.5g × H =2.5H

The specific heat of water is 1 cal g⁻1 °C⁻¹

The heat of water = 31.9 g × 1 cal g⁻1 °C⁻¹ ( 21.3-17.3)°C

                              = 31.9 × 4 cal

                              = 127.6 cal

hence, 2.5H = 127.6 cal

H = 127.6/2.5 = 51.4 cal/g = 0.05104 kcal/g

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Yes, it is the right response. Although the elements are imaginary, they resemble actual elements .Nomenclature is an organism name system used in biological classification.

The Latin words nomen (name) and calare (to call) are the source of the word nomenclature. Both the Latin word nomenclatura and the English word nomenclator, which also denotes a source or broadcaster of names, relate to a list of names.

Nomenclature is an organism name system used in biological classification. Genus & species names, two Latinized nouns drawn from numerous sources, serve as indicators of the species whereby the creature belongs.

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Dimethylsulfoxide has the formula C2H6SO.Therefore, the correct answer is option D: 25.4.

Option D.

To determine the mass percent of carbon in this compound, we need to calculate the molar mass of the compound first. Molar mass is the sum of the atomic masses of all the atoms in the molecule. We can use the periodic table to obtain the atomic masses. For this compound, the molar mass will be:2 (atomic mass of carbon) + 6 (atomic mass of hydrogen) + 32 (atomic mass of sulfur + 16 (atomic mass of oxygen) = 78 g/molNext, we need to determine the mass of carbon in one mole of the compound. We can do this by multiplying the number of carbon atoms by the atomic mass of carbon. In this case, there are 2 carbon atoms in one mole of the compound. Therefore, the mass of carbon in one mole of the compound is:2 (number of carbon atoms) x 12.01 (atomic mass of carbon) = 24.02 g/molFinally, we can calculate the mass percent of carbon in dimethylsulfoxide using the formula:mass percent of carbon = (mass of carbon / total molar mass) x 100%Substituting the values we obtained:mass percent of carbon = (24.02 g/mol / 78 g/mol) x 100% = 30.77%Rounding to three significant figures gives us a final answer of 30.7%.

Option D.

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Answer:

(a) (i) All the elements of a group have similar chemical properties because they have the same no. of valence electrons in their outermost shell. (ii) All the elements of a period have different chemical properties because they have different no. of valence electrons in their atoms.

The intermolecular forces between HCl molecules consist of dipole-dipole attractions and hydrogen bonding. So the correct option is b.  Dipole-dipole attractions and hydrogen bonding

HCl is a polar molecule due to the electronegativity difference between hydrogen and chlorine, resulting in a partial positive charge on hydrogen and a partial negative charge on chlorine. This polarity leads to dipole-dipole attractions between neighboring HCl molecules, where the positive end of one molecule is attracted to the negative end of another.

In addition to dipole-dipole attractions, hydrogen bonding occurs in HCl molecules. Hydrogen bonding involves a hydrogen atom bonded to an electronegative atom (in this case, chlorine) and a lone pair of electrons on another electronegative atom. This type of bonding is stronger than regular dipole-dipole interactions and occurs when hydrogen bonds with oxygen, nitrogen, or fluorine atoms in neighboring molecules.

Therefore, the correct answer is b. Dipole-dipole attractions and hydrogen bonding, as both these intermolecular forces contribute to the overall interactions between HCl molecules.

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Wascana Chemicals should use emissions reduction technologies to reduce the amount of sulphur dioxide emitted during paint production.

To comply with the Ministry of Environment's directive, Wascana Chemicals, a paint manufacturer, needs to reduce the amount of sulphur dioxide released during paint production. This can be accomplished through the use of emissions reduction technology, such as scrubbers, catalytic converters, or gasification systems.Scrubbers are devices that use a wet process to remove pollutants from gas streams. The gas stream is forced through a scrubbing solution that traps pollutants, including sulphur dioxide.Catalytic converters, on the other hand, use a chemical process to transform pollutants into less harmful substances. Gasification systems convert solid or liquid materials into a gas, which can be combusted to generate energy.

In conclusion, to comply with the Ministry of Environment's emissions reduction regulations, Wascana Chemicals should consider implementing one or more emissions reduction technologies such as scrubbers, catalytic converters, or gasification systems to reduce the amount of sulphur dioxide emitted during paint production.

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Answer:

gas

Explanation:

at Standard Temperature and Pressure Carbon monoxide (CO), carbon dioxide (CO2) and nitrogen dioxide (NO2) exist as gases

Option C is correct

Covalent compounds are compounds that are characterized by strong Intra-molecular bonds and they are solids as they have higher molecular weights

But when compounds like Carbon monoxide (CO), carbon dioxide (CO2), and nitrogen dioxide (NO2) are formed with low molecular weight covalent bonds They exist as gases

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from google, so I think the answer to that question is the second one

Ground state electronic configuration of chloride ion =1s² 2s² 2p⁶ 3s² 3p⁶.

To determine the ground-state electron configuration for the chloride ion (Cl-), we start with the neutral chlorine atom (Cl) and add one additional electron to represent the extra negative charge.

The electron configuration of a neutral chlorine atom is: 1s² 2s² 2p⁶ 3s² 3p⁵.

Now, let's add one more electron to represent the extra negative charge of the chloride ion:

1s² 2s² 2p⁶ 3s² 3p⁶.

Therefore, the ground-state electron configuration for the chloride ion (Cl-) is: 1s² 2s² 2p⁶ 3s² 3p⁶.

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That 1500 kJ of energy were transferred to water at 20.0°C. Heat capacity (c) for liquid water is 4.18 J/g C​. mass of water could be brought to the boiling point is 4485 g.

given that :

heat energy = 1500 kJ

heat capacity , c = 4.18 J/g °C

initial temperature = 20.0°C

boiling of water ,final temperature = 100 °C

Q = mcΔT

m = Q / (cΔT)

m = 1500 / ( 4.18 × ( 100 °C - 20 °C )

m = 1500 / 334.4

m = 4.485 kg = 4485 g

Thus, That 1500 kJ of energy were transferred to water at 20.0°C. Heat capacity (c) for liquid water is 4.18 J/g C. ​mass of water could be brought to the boiling point is 4485 g.

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Answer:

the answer is O²- hopefully