Profit and Loss
b) Mrs. Shrestha sold a 'Palpali Dhaka Topi' for Rs 858 and made a profit of 1
Find her buying price of the 'Dhaka Topi'. How much is her actual profit?​

Answers

Answer 1

Mrs. Shrestha's buying price of the Dhaka Topi was Rs. 780 and her actual profit was Rs. 78.

Given, Mrs. Shrestha sold a 'Palpali Dhaka Topi' for Rs 858 and made a profit of 10%.

Now, S.P = Rs. 858

Profit% = 10%

As, Profit% = Profit/C.P×100

Profit% = (S.P - C.P)/C.P×100

10 = (858 - C.P)/C.P×100

C.P = (858 - C.P)×10

C.P = 8580 - 10C.P

11 C.P = 8580

C.P = 780

Also, Profit = S.P - C.P

Profit = 858 - 780

Profit = 78

Hence, Mrs. Shrestha's buying price of the Dhaka Topi was Rs. 780 and her actual profit was Rs. 78.

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Related Questions

Write your answer as a coordinate (x,y)

Find the midpoint between the given pairs of points.

(10,8) (14,-6)

Answers

5,4 6, -3/3


Mekddkdjdjdndndm

Answer:

(12,1)

Step-by-step explanation:

(10+14)/2 and (8+-6)/2

= (12,1)

Simplify the expression.
-2³

Answers

Answer:

-8

Step-by-step explanation:

A confectionery company mixes three types of toffees to form one kilogram " toffee packs. the pack is sold at rs. 17. the three types of toffees cost rs.20, rs. 10, rs. 5 per kg. resp. the mixture must contain atleast 300 gms of first type. also weight of first two types must be at least be equal to weight of third type. find the optimal mix for maximum profit.answer

Answers

The maximum profit is 6 and it is obtained when we mix 0.6 kg of type A, 0 kg of type B, and 0.4 kg of type C.

The optimal mix for the maximum profit can be found as follows:

The company mixes three types of toffees, A, B, and C. Let the weights of type A, B, and C be a, b, and c kg, respectively. Let us assume that we are making 1kg of toffee pack. Therefore, the weight of type C should be 1 - (a + b) kg. Also, the mixture must contain at least 300 gms of type A i.e a >= 0.3 kg

Also, the weight of the first two types (A and B) must be at least equal to the weight of type C, i.e a + b >= c. This condition can also be written as a + b - c >= 0

Let us now calculate the total cost of making 1kg of toffee pack.

Cost = 20a + 10b + 5c

If the pack is sold at Rs. 17, then the profit per 1kg of toffee pack is by

Profit = Selling Price - Cost = 17 - (20a + 10b + 5c)

Now we have the following linear programming problem:

Maximize P = 17 - (20a + 10b + 5c)

Subject to constraints: a + b + c = 1 (since we are making 1kg of toffee pack)

a >= 0.3a + b - c >= 0a, b, c >= 0

We can use the simplex method to solve this linear programming problem. However, to save time, we can solve it graphically. The feasible region is as follows:

We can see that the corner points of the feasible region are: (0.3, 0, 0.7), (0.6, 0, 0.4), (0, 0.5, 0.5), and (0, 1, 0).

Let us calculate the profit at each of these corner points. For example, at the point (0.3, 0, 0.7), we have a = 0.3, b = 0, and c = 0.7. Therefore, the profit is

P = 17 - (20(0.3) + 10(0) + 5(0.7)) = 3.5

Similarly, we can calculate the profit at the other corner points as well. The corner point (0.3, 0, 0.7) gives a profit of 3.5

Corner point (0.6, 0, 0.4) result in a profit of 6

Corner point (0, 0.5, 0.5) results in a profit of 5

Corner point (0, 1, 0) gives a profit of 3

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28) A pilot of a helicopter is searching for an
injured hiker. While flying at an altitude
of 1500 feet, the pilot sees smoke at an
angle of depression of 14°. Assuming that
the smoke is a distress signal from the
hiker, what is the helicopter's horizontal
distance to the hiker? Round to the nearest
foot.

Answers

After answering the provided question, we can conclude that Therefore, trigonometry the helicopter's horizontal distance to the hiker is approximately 388 feet.

what is trigonometry?

The study of the relationship between triangle wall lengths and angles is known as trigonometry. The topic first emerged in the Hellenistic era, around the third century BC, because of the utilization of geometry in astronomical studies. The branch of mathematics known as precise methods deals with certain quaternion functions and about there potential applications in computations. There are six commonly used trigonometric functions in trigonometry. Sine, cosine, tangent, buying new furniture, secant, and cosecant are their person names and acronyms (csc). The study of triangle properties, specially those of right triangles, is known as trigonometry. As a result, geometry is really the study of the properties of all geometric shapes.

We can use trigonometry to solve this problem. Let's start by drawing a diagram:

             Hiker

               /|

              / |

             /  | 1500 ft

            /   |

           /θ   |

          /     |

         /14°   |

        /_______|

     Helicopter

We are looking for the horizontal distance between the helicopter and the hiker, which we can call x. We know the altitude of the helicopter (1500 ft), and we know the angle of depression (14°).

From the diagram, we can see that:

tan(14°) = x / 1500

We can solve for x:

x = 1500 * tan(14°)

x ≈ 387.7 ft

Therefore, the helicopter's horizontal distance to the hiker is approximately 388 feet.

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view what's attached

view what's attached

Answers

Step-by-step explanation:

when numbers are negative, the bigger the number looks the smaller it is therefore

-6 is smaller than -5

but 6 is bigger than 5

however, the numbers are;

-5.99, -3, -6, -5.9, -1, -5.999, -5 ,2

I need help solving for volume and rounding to a whole number

I need help solving for volume and rounding to a whole number

Answers

The volume of a cone is given by the following formula:

\(V=\frac{\pi r^2h}{3}\)

where r represents the radius of the cone and h represents the height.

The height of our cone is 18 in. and the diameter is also 18 in.

The radius is equal to half diameter, therefore, the radius of our cone is:

\(r=\frac{d}{2}=\frac{18}{2}=9\)

Then, using those values on the formula, we have:

\(V=\frac{\pi\cdot9^2\cdot18}{3}=486\pi=1526.81403...\approx1527\)

The volume of this cone is 1527 in³.

How does the graph of y = 3^xcompare to the graph of y = 3^-x?
A. The graphs are the same.
B.The graphs are reflected across the x-axis.
C. The graphs are reflected across the y-axis.​

Answers

Answer:

C

Step-by-step explanation:

The graphs are reflected across the y-axis.

How does the graph of y = 3^xcompare to the graph of y = 3^-x? A. The graphs are the same. B.The graphs

Can someone help me find the range of this please?

Can someone help me find the range of this please?

Answers

the range of the graph is simply the region that it covers vertically, well, from the picture we can see the graph goes down down down to -2 vertically, makes an U-turn and goes back up, the arrowheads mean it keeps on going to infinity, so vertically the graph never goes below -2, so its range is just from -2 up to infinity, or in interval notation [ -2 , +∞ ).

Find the limit, if it exists,
Lim (x, y) -> (0, 0) xy/(√x^2+y^2)
to examine lim (x, y) → (0, 0) xy/(√x^2+y^2), first approach (0, 0) along the x-axis. on this path, all points have _________

Answers

The limit of xy/(√\(x^2+y^2\)) as (x, y) approaches (0, 0) does not exist.

On the x-axis, all points have y = 0. Therefore, the expression xy/(√\(x^2+y^2\)) reduces to 0/|x|, which is equal to 0 for x ≠ 0 and undefined at x = 0.

Next, let's approach (0, 0) along the y-axis. On this path, all points have x = 0. Therefore, the expression xy/(√\(x^2+y^2\)) reduces to 0/|y|, which is equal to 0 for y ≠ 0 and undefined at y = 0.

Since the limit of the expression along the x-axis and y-axis are different, the limit at (0, 0) does not exist.

To prove this, we can also use polar coordinates.

Let x = r cosθ and y = r sinθ, then the expression becomes:

lim (r, θ) -> (0, 0) \(r^2\) cosθ sinθ / r

which simplifies to:

lim (r, θ) -> (0, 0) r cosθ sinθ

This limit does not exist, as the value of r cosθ sinθ depends on the angle θ. For example, when θ = 0, r cosθ sinθ = 0, but when θ = π/4, r cosθ sinθ = \(r^2\)/2.

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To find the limit, if it exists, of Lim (x, y) → (0, 0) xy/(√x^2+y^2), we first examine the limit as we approach (0, 0) along the x-axis. When we follow this path,it helps to analyse the limit.

On the x-axis, y=0 for all points. Therefore, the limit can be examined as lim (x, 0) → (0, 0) x(0)/(√x^2+0^2). Simplifying, we get lim (x, 0) → (0, 0) 0/|x|. As we approach 0 from both positive and negative sides of the x-axis, the denominator |x| approaches 0. However, the numerator remains 0. Thus, the limit is 0. Therefore, all points on the x-axis approach 0 as we approach (0, 0).

that is,  Lim (x, y) → (0, 0) x(0)/(√x^2+0^2) = Lim (x, y) → (0, 0) 0/(√x^2)

As x approaches 0, the numerator is always 0, while the denominator is |x|. Thus, the limit along the x-axis is:

Lim (x, y) → (0, 0) 0/|x| = 0

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please help i’ll give brainlest and lots of points !!

please help ill give brainlest and lots of points !!

Answers

you should repost i’ll try and answer then

asnwer aswer answer answer plz ASWER ANSWER ANSWER ANSWERR PLZ ANSWEER I NEED ANSWER PLZZZZZ!!!! i need help HELP!!!

The lowest point on earth surface is the shore of the dead se, elevation -1,344.99 meters. the highest point, the summit of mount everest is 30,380.42 meter above the dead sea. what is the elevation at the summit of mount everest.

Answers

Answer:

29,035.43 meters

Step-by-step explanation:

What we know:

- The elevation of the shore of the Dead Sea is -1,344.99 meters.

- The summit of Mt. Everest is 30,380.42 meters above the Dead Sea.

So, we just add the two values.

30,380.42 + (-1,344.99)

We can rewrite this as 30,380.42 - 1,344.99 since adding a negative is the same as subtracting that number.

And we get 29,035.43 meters as the elevation or height of Mt. Everest.

Which ordered pair are solutions to the inequality y - 3x < -8?

Select each correct answer.

(0, -9)
(5, 4)
(-3, -2)
(1, -5)
(2, -1)

Answers

The ordered pair that is a solution to the inequality y - 3x < -8 is given as follows:

(0, -9).

How to verify if an ordered pair is a solution to the inequality?

We replace the ordered pair into the inequality, then verify if it reaches an identity or a contradiction.

In this problem, the inequality is:

y - 3x < -8.

For the first ordered pair, given by (0, -9), we have that:

-9 - 3(0) < - 8

-9 < -8

Which is a true statement, hence it is a solution.

For the second ordered pair, given by (5,4), we have that:

5 - 3(4) < -8

5 - 12 < -8

-7 < -8

Which is false, hence this is a not a solution.

For the third ordered pair, given by (-3,-2), we have that:

2 - 3(-3) < -8

2 + 9 < -8

11 < -8

Which is false, hence this is a not a solution.

For the fourth ordered pair, given by (1,-5), we have that:

1 - 3(-5) < -8

1 + 15 < -8

16 < -8

Which is false, hence this is a not a solution.

For the fifth ordered pair, given by (2,-1), we have that:

-1 - 3(2) < -8

-1 - 6 < -8

-7 < -8

Which is false, hence this is a not a solution.

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How do I simplify 2234993.75% out of 100%

Answers

The computation of 2234993.75% out of 100% will bring about value of - 22348.9375

How to calculate the percentage?

From the information given, we are told to simplify 2234993.75% out of 100%. It should be noted that to simplify 2234993.75% will be:

= 2234993.75% / 100

= 22349.9375

On the other hand, 100% simply means 1. Therefore, 2234993.75% out of 100% will be:

= 1 - 22349.9375

= - 22348.9375

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Help please i dint get it pls answer

Help please i dint get it pls answer

Answers

Answer: 7%

(Hope this is right.)

Step-by-step explanation:

Let's solve this using the information we have and an equation.

Shane: $32,000 - (Given)

Theresa: 18,000+14x, if x=1,160 - (Given)

---------------------------------------------------------------

Step two: (Theresa) 14(1,160) =16,240 (Algebra)

Step three: (Theresa) 18,000+16,240=34,240 (Algebra, given.) - cost of Theresa's car.

---------------------------------------------------------------

Finally,

They're asking for how much more she paid for her car as a percentage of what Shane paid.

34,240-32,000=2,240 and

2,240/32,000=0.07

0.07x100=7

Answer 7% more than what Shane paid.

Which equations are true for x = –2 and x = 2? Select two options

x2 – 4 = 0
x2 = –4
3x2 + 12 = 0
4x2 = 16
2(x – 2)2 = 0

Answers

The equations that are true for x = –2 and x = 2 are x^2 - 4 = 0 and 4x^2 = 16

Equations and expressions

Given the solution to a quadratic equation to be -2 and 2, the equation is expressed as:

(x-(-2))(x -2) = 0
(x+2)(x - 2) = 0

Expand

x^2 - 2x + 2x - 4 = 0

x^2 - 4 = 0

Hence the equations that are true for x = –2 and x = 2 are x^2 - 4 = 0 and 4x^2 = 16

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Find the first quartile (Q1) of the data set below.
{99, 88, 88, 91, 92, 100}
89.5
0 95.5
O 88
0.99

Answers

I think it would be 88

a packing machine in a candy factory is supposed to put 16.0 ounces of chocolate-covered raisins in each bag. to verify that the machine is working correctly, a random sample of 41 bags is taken, and found to contain an average of oz. of candy, with sample standard deviation oz. does this indicate that the average amount of candy dispensed by the machine is different (either way) from 16.0 ounces? use .

Answers

If the random sample of 10 bags is taken to check the working ; then the average amount of candy dispensed by the machine is less than 16 ounces .

In the question ,

it is given that ,

a random sample of 10 bags is taken to verify that the machine is working fine ,

the mean amount of candy dispensed is = 15.887 oz ,

the standard deviation of the sample is = 0.1304 oz .

we have to check whether the average amount of candy dispensed by machine is different from 16.0 oz .

So , H₀ : μ = 16 v/s  H₁ : μ < 16

the test statistic(t) will be =

t = (mean - average)/(σ/√n)

= (15.887 - 16)/(0.1304/√10)

= -0.113/0.0412361

Simplifying further ,

we get ;

= -2.7403  .

|t| = 2.7403

Now t(critical value) at n - 1= 9 degree of freedom and α = 0.05 .

So , t₉,₀.₀₅ = 1.833

Now , Since the t value calculated (2.7403) is greater than t critical (1.833)

we reject the H₀ and accept H₁ .

Therefore , The average amount of candy dispensed by the machine is less than 16 ounces .

The given question is incomplete , the complete question is

A packing machine in a candy factory is supposed to put 16.0 ounces of chocolate-covered raisins in each bag. to verify that the machine is working correctly, a random sample of 10 bags is taken, and found to contain an average of 15.887 oz. of candy, with sample standard deviation 0.1304 oz. does this indicate that the average amount of candy dispensed by the machine is different (either way) from 16.0 ounces ?

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Find f. f '(t) = sec(t)(sec(t) + tan(t)), − π/2 < t < π/2 , f (π/4)= −2

Answers

We used integration to find the function f given \(f'(t) = sec(t)[sec(t) + tan(t)]\), \(-\pi /2 < t < \pi /2\)  and \(f(\pi /4) = -2\). The solution is \(f(t) = tan(t) + ln|sec(t) + tan(t)| - 3 - ln(2)\).

To find the function f given f'(t), we need to integrate f'(t) with respect to t. In this case, we have:

\(f'(t) = sec(t)[sec(t) + tan(t)]\)

We can simplify this expression by using the identity \(sec^2(t) = 1 + tan^2(t)\)to get:

\(f'(t) = sec^2(t) + sec(t)tan(t)\)

We can then integrate f'(t) to obtain f(t):

\(f(t) = \int [sec^2(t) + sec(t)tan(t)] dt\)

Using the identity \(\int sec^2(t) dt = tan(t) + C\), we can simplify the integral to:

\(f(t) = tan(t) + ln|sec(t) + tan(t)| + C\)

To find the value of C, we use the initial condition \(f(\pi /4) = -2\):

\(-2 = tan(\pi /4) + ln|sec(\pi /4) + tan(\pi /4)| + C\)

-2 = 1 + ln(2) + C

C = -3 - ln(2)

Therefore, the solution to the initial value problem is:

\(f(t) = tan(t) + ln|sec(t) + tan(t)| - 3 - ln(2)\)

In summary, we used integration to find the function f given \(f'(t) = sec(t)[sec(t) + tan(t)]\), \(-\pi /2 < t < \pi /2\)  and \(f(\pi /4) = -2\). The solution is \(f(t) = tan(t) + ln|sec(t) + tan(t)| - 3 - ln(2)\).

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Write the equation of the line in y = mx + b form.
I need help

Write the equation of the line in y = mx + b form.I need help

Answers

wouldn’t it be y=-4x+1
Answer:  y = -4x+1

========================================================

Explanation:

The two points on this line are (-1,5) and (0,1)

Let's use the slope formula

m = (y2-y1)/(x2-x1)

m = (1-5)/(0-(-1))

m = (1-5)/(0+1)

m = -4/1

m = -4

The slope is m = -4

If we started at (-1,5) and moved down 4 and to the right 1, then we arrive at (0,1). The motion "down 4, right 1" is directly tied to the slope -4 since -4 = -4/1 = rise/run

The y intercept is b = 1 since this is the location where the graph crosses the y axis.

With m = -4 and b = 1, we go from y = mx+b to y = -4x+1

Aaron had $22 to spend on 4 beakers for his science class. After buying them, Aaron had $2 left. How much did each of the beakers cost?

Answers

Answer:4

Step-by-step explanation:22-4=18-4=14-4=10-4=6=2

If x = -5 and y = 2x^2,
then y = ?

Answers

Answer:

y = 50

Step-by-step explanation:

y = 2x^2

Let x= -5

y = 2(-5)^2

Power first

y = 2(25)

Then multiply

  = 50

Oliver grew 12 plants with 3 seed packets. How many seed packets does Oliver need to have a total of 16 plants in his backyard? Assume the relationship is directly proportional. seed packets

Answers

Answer: He needs 5 total seed packs.

Step-by-step explanation:

12 divided by 3 is 4 so it's 4 per one seed pack and you need 16. So, you have 12 and you need 16 so it's just one more.

every morning, laura practices shooting basketball free throws. she doesn't shoot a fixed amount, instead she keeps shooting free throws until she makes 12. suppose laura is an 82% free throw shooter. let x be how many free throws laura will miss tomorrow morning. then x has a negative binomial distribution. what is a trial? [ select ] what is a success? [ select ] how many successes are required? r

Answers

The probability of Laura missing 3 free throws before making 12 is approximately 0.0037 or 0.37%.
The basketball free throw.

A success would be considered when Laura makes a free throw.

A failure would be when Laura misses a free throw.
The negative binomial distribution is a probability distribution that calculates the probability of obtaining a certain number of failures before a specified number of successes occur.

The specified number of successes is 12, and the number of failures is represented by the variable x.
To calculate the probability of x failures, we need to know the probability of a single failure.

Since Laura is an 82% free throw shooter, the probability of her missing a free throw is 18%.
We can use the formula for negative binomial distribution to determine how many failures are required before 12 successes are achieved.

The formula is:
\(P(X = x) = (r+x-1)C(x) \times p^r \times (1-p)^x\)
Where:
P(X = x) is the probability of having x failures before achieving 12 successes
r is the number of successes required (in this case, 12)
p is the probability of a single success (in this case, 0.82)

\((r+x-1)C(x)\)is the combination of r+x-1 choose x

For example, if we want to find the probability of Laura missing 3 free throws before making 12, we will plug in x = 3, r = 12, p = 0.82 into the formula:

\(P(X = 3) = (12+3-1)C(3) \times 0.82^1^2\times (1-0.82)^3\)
\(P(X = 3) = 14C3 \times 0.082^1^2 \times 0.18^3\)
\(P(X = 3) = 364 \times 0.000018 \times 0.005832\)
P(X = 3) = 0.000037
Overall, the trial in this scenario is each individual attempt at a free throw, the success is making a free throw, and 12 successes are required before the shooting session is considered complete.

The negative binomial distribution is used to calculate the probability of obtaining a certain number of failures before achieving the specified number of successes.

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'x' follows a negative binomial distribution with 'r' being 12 successes.

In this scenario, a trial refers to each individual attempt at shooting a free throw. A success is when Laura successfully makes a free throw. To achieve her goal of making 12 free throws, she needs to have 11 successes (since she will miss on the final attempt). Therefore, r = 11.

In this context, a "trial" refers to each individual attempt Laura makes to shoot a basketball free throw. A "success" is when Laura makes a free throw (hits the basket), while a "failure" (not mentioned in the question) would be when Laura misses a free throw. Since Laura keeps shooting free throws until she makes 12, the number of successes required, denoted as 'r', is 12.

Therefore, 'x' follows a negative binomial distribution with 'r' being 12 successes.

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b) What is the measure of ZE? Explain how you know. (1 point)​

Answers

i cant give you a answer because there is no other problems

the percentile normally signifies the average ranking or average performance a. 25th b. 50th c. 75th d. 95th

Answers

Step-by-step explanation:

50 th percentile means 50% are above and 50% are below.....this is the peak of the Bell Curve

Given m || n, find the value of x and y.
X =
y =
(6x-2)(3x+2)
m
n

Given m || n, find the value of x and y.X =y =(6x-2)(3x+2)mn

Answers

Answer:

x = 20

y = 62

Step-by-step explanation:

Angles on a straight line sum to 180°:

⇒ (6x - 2)° + (3x + 2)° = 180°

⇒ 6x - 2 + 3x + 2 = 180

⇒ 6x + 3x - 2 + 2 = 180

⇒ 9x = 180

⇒ 9x ÷ 9 = 180 ÷ 9

⇒ x = 20

Vertical Angles Theorem

When two straight lines intersect, the opposite vertical angles are congruent.

⇒ y° = (3x + 2)°

⇒ y = 3x + 2

⇒ y = 3(20) + 2

⇒ y = 60 + 2

⇒ y = 62

Please help ASAP help me with this please ASAP

Please help ASAP help me with this please ASAP

Answers

Answer:

x = 19√3

y = 38

Step-by-step explanation:

x/19 = cot 30° = √3

x = 19√3

sin 30° = 19/y

1/2 = 19/y

y = 38

Question Four The Teaching Excellence and Library Department at Botho University carried out a survey to find out the time spent in the library by the university community. A random sample of 200 members was taken and the average time spent in the library was computed to be 30 minutes. From this case, find:

a) the population of interest (2 marks)

b) the sample (2 marks)

c) whether 30 minutes is a parameter or statistic, justify your answer. (2 marks)

MICROECONOMICS

Answers

(a)The population of interest is the entire university community at Botho University. (b)The sample is the random sample of 200 members. (c)The average time spent in the library, which is 30 minutes, is a statistic because it is computed from the sample and represents a characteristic of the sample, not the entire population.

a) The population of interest in this case would be the entire university community at Botho University. It includes all members of the university community who could potentially spend time in the library.

b) The sample in this case is the random sample of 200 members that was taken from the university community. It represents a subset of the population of interest and is used to make inferences about the larger population.

c) In this case, 30 minutes is a statistic, not a parameter.

A statistic is a value calculated from a sample that describes some characteristic of the sample. In this case, the average time spent in the library, which is 30 minutes, was computed from the sample of 200 members. It represents the average time spent in the library by the sampled members.

On the other hand, a parameter is a value that describes a characteristic of the population. Since the average time spent in the library is based on the sample and not the entire population, it cannot be considered a parameter.

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HELP ASAP basic algebra

HELP ASAP basic algebra

Answers

Answer B go=x3 - 3 is the correct answer

Answer:

G(x) = x^3 - 3

Step-by-step explanation:

I'd used desmos


A piece of wood is 0.9 metres long.
It is cut into three unequal pieces.
The first piece is 0.2 metres longer than the second piece.
The third piece is 23 hundredths of a metre shorter than the second piece.
How long is each piece of wood?

Answers

Answer:

The length of the first piece is 0.51 m

The length of the second piece is 0.31 m

The length of the third piece is 0.28 m

Step-by-step explanation:

The question is a simultaneous equation with word problem

The total length of the wood = 0.9 m

The number of pieces the wood is cut into = 3

The length of the first piece = 0.2 m + The length of the second piece

The length of the third piece = The length of the second piece - 0.23 m

Let "y" represent the length of the second piece, let "x" represent the length of the first piece, and let "z" represent the length of the third piece, we have;

x = 0.2 + y...(1)

z = y - 0.23...(2)

x + y + z = 0.9...(3)

Therefore, by substitution, we have;

0.2 + y + y + y - 0.23 = 0.9

3·y - 0.03 = 0.9

3·y = 0.9 + 0.03 = 0.93

y = 0.93/3 = 0.31

y = 0.31

The length of the second piece = y = 0.31 m

From equation (1), we have;

x = 0.2 + y = 0.2 + 0.31 = 0.51

x = 0.51

The length of the first piece = x = 0.51 m

From equation (2), we have;

z = y - 0.23

z = 0.51 - 0.23 = 0.28

z = 0.28

The length of the third piece = z = 0.28 m.

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