Problem 2.4b: Sketch double sided and single sided amplitude and phase spectra of the following. First find the fundamental frequency \( f_{0} \). Be sure to label the vertical axes with Amplitude, an

Answer:

4 m/

Explanation:

Velocidad = Distancia ÷ Tiempo

Si la distancia recorrida es de 40m y el tiempo que le llevó a hacerlo es de 10s. Entonces:0

V = 40m/10s

=4m/

Answer:

Explanation:

The average speed of the car can be found by using the formula

\(v = \frac{d}{t } \\ \)

d is the distance

t is the time taken

From the question we have

\(v = \frac{139.2}{3.8} \\ = 36.63157...\)

We have the final answer as

Hope this helps you

Answer:

70.3 kg

Explanation:

The MASS will be the same on the moon as on earth....but the eight is different

gravity of moon =   gravity of earth/6 = 9.81 / 6    m/s^2

F = ma

F/a = m  = 115 N / ( 9.81/6  m/s^2) = 70.3 kg mass

Answer:

Explanation:

Given:

g = 9.8 m/s²

g₁ = g / 6 = 9.8 / 6 ≈ 1.6 m/s²

F = 115 N

____________

m - ?

m  = F / g₁

m = 115 / 1,6 ≈ 71.9  kg

Answer: The answer is A- Low Tide

Explanation:

The difference in tension in terms of m and g is given by T_b - T_t = 2mg

To find the difference in tension T_b - T_t, we will first analyze the forces acting on the ball at the top and bottom of the circle and then compare the magnitudes.
1. At the top of the circle:
- The tension force T_t is acting downward.
- The gravitational force mg is also acting downward.
The net force at the top is the sum of these forces:
F_t = T_t + mg
2. At the bottom of the circle:
- The tension force T_b is acting upward.
- The gravitational force mg is acting downward.
The net force at the bottom is the difference of these forces:
F_b = T_b - mg
Since the total mechanical energy is conserved, we can equate the centripetal forces acting on the ball at the top and bottom of the circle:
\(m(v_t^2) / L = m(v_b^2) / L\)
As we can see, the mass m and length L cancel out:
\(v_t^2 = v_b^2\)
Now we can relate the forces to the centripetal acceleration:
At the top: \(F_t = m(v_t^2) / L\)
At the bottom: \(F_b = m(v_b^2) / L\)Substituting the expressions for F_t and F_b, we get:
\(T_t + mg = m(v_t^2) / L\)
\(T_b - mg = m(v_b^2) / L\)
Since \(v_t^2 = v_b^2\), we can set the centripetal forces equal to each other:
m(v_t^2) / L = m(v_b^2) / L
Now subtract the equation for the forces at the top from the equation for the forces at the bottom:
(T_b - mg) - (T_t + mg) = 0
Simplifying the equation, we get:
T_b - T_t = 2mg
So, the difference between the magnitude of the tension in the string at the bottom relative to that at the top of the circle is 2mg.

To learn more about tension https://brainly.com/question/15589506

#SPJ11

(a) The centripetal force required for the child to stay on the playground merry-go-round is 400 N.

(b) The centripetal force required for the child to stay on the amusement park merry-go-round is 0.38 N.

(c) The centripetal force required for the playground merry-go-round is greater than the child's weight, while the centripetal force required for the amusement park merry-go-round is much smaller than the child's weight.

(a) To determine the centripetal force required to keep the child on the playground merry-go-round, we can use the formula

Fc = mv^2 / r

Where Fc is the centripetal force, m is the mass of the child, v is the velocity of the merry-go-round, and r is the radius of the merry-go-round.

First, we need to convert the rotational speed from revolutions per minute to radians per second

35.0 rev/min = 35.0 x 2π/60 rad/s = 3.67 rad/s

Substituting the given values into the formula, we get

Fc = (23.0 kg) x (3.67 m/s)^2 / 3.00 m

Fc = 400 N

Therefore, the child must exert a centripetal force of 400 N to stay on the playground merry-go-round.

(b) For the amusement park merry-go-round, we can use the same formula

Fc = mv^2 / r

However, this time we need to use the rotational speed of 3.00 rev/min, which is equivalent to

3.00 rev/min = 3.00 x 2π/60 rad/s = 0.314 rad/s

Substituting the given values into the formula, we get

Fc = (23.0 kg) x (0.314 m/s)^2 / 7.00 m

Fc = 0.38 N

Therefore, the child needs to exert a centripetal force of 0.38 N to stay on the amusement park merry-go-round.

(c) To compare each force with the child's weight, we need to find her weight first

w = mg

Where w is the weight, m is the mass, and g is the acceleration due to gravity (9.81 m/s^2).

Substituting the given mass, we get

w = (23.0 kg) x (9.81 m/s^2)

w = 226 N

For the playground merry-go-round, the centripetal force of 400 N is greater than the child's weight of 226 N, which means the force is sufficient to keep her on the merry-go-round.

Learn more about centripetal force here

brainly.com/question/14249440

#SPJ4

The distance a penny travelled before reaching the water surface is 19.6 m. Consider the acceleration of the penny as 9.8 m / s^2.

What is acceleration?

Acceleration is the rate of change of the velocity with respect to the time taken. it is a vector quantity which is seen as moving faster or happening quickly. The standard unit is metre per second squared.

The distance or depth of the well can be calculated as,

d = ut + at^2 / 2

where d = depth of the well, u = initial velocity, t = time for reaching the water, a = acceleration of the penny.

d = (0 x 2) + 0.5 (9.8) (2)^2 = 19.6 m

Therefore, the stone falls for 19.6 m when it travels for 2 seconds before hitting the water when the acceleration is 9.8 m/s^2.

To learn more about acceleration click on the given link https://brainly.com/question/460763

#SPJ4

a. Does the spool cross the finish line before, after, or at the same instant as the block? Explain: Since the strings are pulled with the same constant tension, the spool and the block will start moving at the same time and will cover the same distance. Therefore, they will cross the finish line at the same instant.

b. Consider the following dialogue between two students:

Student: "I think that there's the same amount of work done on block and spool as they both move the same distance."

Student 2: "I disagree. I think that the hand pulling the spool does more work than the hand pulling the block since the string unwinds as the spool is pulled."

In this scenario, student 2 is correct. The work done on the spool is greater than the work done on the block because the spool unwinds as it is pulled, which means that more energy is required to move the spool a given distance than to move the block a given distance. Therefore, the spool will cross the finish line after the block.

c. When each crosses the finish line, is the total kinetic energy of the spool greater than, less than, or equal to that of the block? Explain:

The total kinetic energy of an object is equal to its mass times its velocity squared. Therefore, the total kinetic energy of the spool is greater than the total kinetic energy of the block since the spool is moving faster than the block.

d. When each crosses the finish line, is the translational kinetic energy of the spool greater than, less than, or equal to that of the block? Explain:

The translational kinetic energy of an object is equal to its mass times its velocity. Therefore, the translational kinetic energy of the spool is greater than the translational kinetic energy of the block since the spool is moving faster than the block.  

Learn more about distance

https://brainly.com/question/31713805

#SPJ4

Since this is a circular motion, we know that the we have a centripetal acceleration; we know that this type of acceleration always points towards the center of the circle. This means that the acceleration is represented by the vectors that point towards the center. Looking at them we notice that at point Z the acceleration is pointing to the right.

Therefore, the object is accelerating to the right at Z

Answer:

b

Explanation:

i guessed annd got it right

Answer:

Reaction B involves a greater change and a change in element identity.

Explanation:

The average electric current in the lightning will be 8 × \(10^{-17}\) A

The lightning conductors are long metal strips running from the spike end of a conductor on the top of a building to the earth. They are used to prevent buildings from destruction when struck by thunder or lightning.

Given that a lightning strike can transfer as much as electrons from the cloud to the ground. if the strike lasts 2ms, to calculate the average electric current in the lightning, we will first consider the charge released.

one charge = 1.6 × \(10^{-19}\) C

Average current I = Q/t

Where

Substitute all the parameters into the formula

I = 1.6 × \(10^{-19}\) C ÷ 2 × \(10^{-3}\)

I = 8 × \(10^{-17}\) A

Therefore, the average electric current in the lightning will be 8 × \(10^{-17}\) A

Learn more about Lightning here: https://brainly.com/question/3183045

#SPJ1

The bowling ball experiences the greater magnitude impulse during the collision since it is initially at rest and is given the momentum of the small ball which has a speed of 5m/s.

The impulse of the bowling ball can be calculated using the equation impulse = change in momentum = mvf - mvi, where m is the mass of the bowling ball, vf is its final velocity, and vi is its initial velocity.

Since the bowling ball is initially at rest (vi = 0), the impulse can be calculated as mvf = m(5m/s) = 5m^2/s. The impulse of the small ball can be calculated in the same way, giving an impulse of 5m^2/s. Therefore, the bowling ball experiences a greater magnitude impulse during the collision.

For more questions like Impulse click the link below:

https://brainly.com/question/16980676

#SPJ4

Using Runge-Kutta 2nd order Heun's method, the speed (w) at t = 0.8s is approximately 0.0081.

Given:

Voltage input (V) = 30V

Initial speed (w) = 0

Step size (h) = 0.4s

Time at which speed is to be determined (t) = 0.8s

We need to determine the speed (w) at t = 0.8s using Heun's method.

We have k₁ = f(t₁, W₁) = 0.02 + 0.06w₁ (using the given equation)

At t = 0 and w = 0 (initial conditions), we have:

k₁ = 0.02 + 0.06(0) = 0.02

We have k₂ = f(t₁ + h, w₁ + k₁h) = 0.02 + 0.06(w₁ + 0.02h)

So, at t = 0.4s and w = 0 (initial conditions), we have:

k₂ = 0.02 + 0.06(0.02 * 0.4) = 0.02 + 0.00048 = 0.02048

So, W₂ = w₁ + (k₁ + k₂)(h/2)

   = 0 + (0.02 + 0.02048)(0.4/2)

   = 0.04048(0.2)

   = 0.008096

Therefore, using Runge-Kutta 2nd order Heun's method, the speed (w) at t = 0.8s is approximately 0.0081.

Learn more about the Runge-Kutta method here:

https://brainly.com/question/32093981

#SPJ4

The complete question is:

The speed of a motor supplied with a voltage input of 30V, assuming the system is without damping, can be expressed as 30 = (0.02)+(0.06)w dt If the initial speed is zero and a step size of h = 0.4 s, determine the speed w at t = 0.8 s by using the Runge-Kutta 2nd order Heun's method. Heun's method: Wi+1=W₁ = w₁ + (-/-^₁ + = -K ₂ ) h where, k₁ = f(t₁, W₁) and k₂ = f(t₁ + h, w₁ + k₁h), the speed (w) at t = 0.8s is approximately 0.0081.

Answer:

88N

Explanation:

m = 9kg

a = 9.8m/s²

F = ma = 9 × 9.8

F = 88N

The separation between the charges is approximately equal to 1.7 x 10⁻³ m.

Given data:Charge 1 = +14 μC,Charge 2 = +45 μC,Electrostatic force = 3.1 N.

We need to find separation between the charges.Let’s start by calculating the electrostatic force using Coulomb’s law.

Coulomb’s law states that the electrostatic force between two point charges is directly proportional to the product of the charges and inversely proportional to the square of the distance between them.

Mathematical expression for Coulomb's law:

Force = kQ1Q2 / r².

Here,k = Coulomb constant = 9 x 10⁹ Nm²/C²

Q1 = +14 μC

Q2 = +45 μC

F = 3.1 N.

We need to find distance r.

Force = kQ1Q2 / r²,

3.1 = 9 x 10⁹ * 14 * 45 / r²,

3.1 r² = 9 x 10⁹ * 14 * 45,

r² = 2.83 x 10¹²,

r = √(2.83 x 10¹²),

r = 1.68 x 10⁻³ m.

r = 1.68 x 10⁻³ m

≈ 1.7 x 10⁻³ m.

The separation between the charges is approximately equal to 1.7 x 10⁻³ m.

The separation between the charges is approximately equal to 1.7 x 10⁻³ m.

To know more about Coulomb’s law visit:

brainly.com/question/506926

#SPJ11

The image height on the detector will change by a factor of 2 if you change from a 50-mm-focal-length lens to a 100-mm-focal-length lens and refocus.

The magnification of a lens is given by the ratio of the image height to the object height. Since the object height remains the same, the change in magnification is solely determined by the change in focal length.

The magnification of a lens is given by the formula:

Magnification = - (image distance / object distance).

Since we are only interested in the ratio of image heights, we can ignore the negative sign.

For the 50-mm lens, the magnification is:

Magnification1 = 50 mm / object distance.

For the 100-mm lens, the magnification is:

Magnification2 = 100 mm / object distance.

Taking the ratio of the two magnifications:

Magnification2 / Magnification1 = (100 mm / object distance) / (50 mm / object distance) = 100 mm / 50 mm = 2.

Therefore, the image height on the detector changes by a factor of 2 when switching from a 50-mm-focal-length lens to a 100-mm-focal-length lens and refocusing.

To learn more about magnification refer to the link:

brainly.com/question/556195

 #SPJ11

Can u please give a question to answer

Answer:

100m/s

Explanation:

speed of wave=frequency × wave length

=10 × 10

=100m/s

Answer:

100 m/s

Explanation:

Formula :

Solving using the given values :

Answer:

Stars appear to move in the sky because earth rotates on its axis.

Explanation:

Stars appear to move in the sky because of Earth's rotation on its axis. As Earth rotates, it creates the illusion that the stars are moving in the opposite direction across the sky. This movement is similar to how objects appear to move past us when we are driving down the road. The stars themselves do not actually move, but our perspective from Earth makes it seem as though they are. This movement, along with the changing position of the sun, creates the patterns and movements that we see in the sky throughout the day and night.

a) The momentum of trolley A before the collision is (2 kg) * (5 m/s) = 10 kg*m/s.

b) The momentum of trolley A after the collision is (2 kg) * (2 m/s) = 4 kg*m/s.

c) The kinetic energy of trolley A before the collision is 1/2 * (2 kg) * (5 m/s)^2 = 25 J.

d) The kinetic energy of trolley A after the collision is 1/2 * (2 kg) * (2 m/s)^2 = 2 J. And the kinetic energy of trolley B after the collision is 1/2 * (3 kg) * (2 m/s)^2 = 3 J.

e) The amount of kinetic energy that is unaccounted for is the difference between the initial kinetic energy of trolley A and the final kinetic energy of trolley A and trolley B. This is 25J - (2J + 3J) = 20 J.

It's important to note that the total momentum of the system is conserved during the collision, meaning that the momentum of trolley A before the collision is equal to the total momentum of trolley A and B after the collision. Also the total kinetic energy of the system is not conserved during the collision as some of the energy is transferred to internal energy of the system and other forms of energy.

Answer:

If this is what your asking?

Explanation:

The concept of time is self-evident. An hour consists of a certain number of minutes, a day of hours and a year of days. ... Time is represented through change, such as the circular motion of the moon around Earth. The passing of time is indeed closely connected to the concept of space

The maximum potential energy stored in the spring is 0.018 J. It is given that the force F (in N) and the displacement x (in m) of the springs and we are asked to use Hooke’s law to compute the potential energy stored in the spring U (in J) and then compute the vectors of the spring constants and the potential energies using MATLAB.

Computing the spring constant k from the given data: We know that F = kx ⇒ k = F/x. Here, F and x are vectors: F = [14, 18, 8, 9, 13] N and x = [0.013, 0.020, 0.009, 0.010, 0.012] m. We can compute k as follows: k = F./x = [14/0.013, 18/0.020, 8/0.009, 9/0.010, 13/0.012] kN/mk = [1076.92, 900, 888.89, 900, 1083.33] N/m (rounded off to 2 decimal places)2.

Computing the potential energy stored in the spring U from the given data: We know that U = (1/2)kx². We can compute U as follows: U = (1/2)k.*x² = [(1/2)1076.92(0.013)², (1/2)900(0.020)², (1/2)888.89(0.009)², (1/2)900(0.010)², (1/2)1083.33(0.012)²] JU = [0.009, 0.018, 0.004, 0.005, 0.007] J (rounded off to 3 decimal places).

Determining the maximum potential energy using the max function: We can determine the maximum potential energy using the max function as follows: maxU = max(U) = 0.018 J. Therefore, the maximum potential energy stored in the spring is 0.018 J.

To know more about potential energy, refer

https://brainly.com/question/24933254

#SPJ11

Answer:

V= 125volts

Explanation:

R =25ohms

I = 5 amp

V = ?

t = 36seconds

V = IR

V = 5× 25

V= 125volts

Q = It

Q = 5×36

Q = 180 coulombs

Q is the amount of charge.

Answer:

R+h=R and g=GM/R^2

Explanation:

gravitational energy is potential energy stored in an object based on its distance from the Earth

Answer:

100Ns

Explanation:

find velocity and then plug into momentum formula momentum=(velocity)(mass)

Answer:

5,000 kg-m/s going south

Explanation:

Since you're only given mass and height, not velocity. You have to find velocity first. The equation for velocity is v=2gh. We know gravity is 10 since it's given & height is also given which is 125m. After doing the math, it's 2,500. Now that you have velocity, you can plug velocity into the formula for momentum which is p=mv. 2.0 times 2,500 = 5,000 kg-m/s going south.

Hello..!

The first law of thermodynamics relates work and transferred heat exchanged in a system through a new thermodynamic variable, internal energy. This energy is neither created nor destroyed, only transformed.

We can think of gas as a thermodynamic system, all because gases can work and absorb heat, and then they can turn all that into energy.

The formula for the change in energy is given by the first law of thermodynamics expressed as:

\( \: \: \: \: \: \: \: \: \: \: {\boxed{\boxed{ \sf\large \rm \Delta U = Q - W }}}\)

Being:

Problem:

A gas receives from an external thermal source an amount of heat equal to 1000 J. This energy, in addition to producing heating in the gas, causes its expansion, with consequent performance of work equivalent to 600 J. What was the change in the internal energy of the gas? gas?

Data:

Now adding the data in the formula to find the energy change:

\( \sf\large \rm \Delta U = 1000J - 600J\)

\( \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \sf{\boxed{\boxed{\large \rm \Delta U = 400 J}}}\)

\(\begin{gathered}\rule{7cm}{0.01mm}\\\texttt{Good studies! :D}\\\rule{7cm}{0.01mm}\end{gathered}\)

The pressure over the diver at a depth of 10 m in the ocean is 100,450 Pa. It is important to note that this pressure is in addition to the atmospheric pressure and may have adverse effects on the diver if not managed properly.

The pressure over the diver at a depth of 10 m in the ocean can be calculated using the formula: pressure = density x gravity x depth. Here, the density of the seawater is given as 1025 kg/m3 and the depth of the diver is 10 m. The acceleration due to gravity is 9.8 m/s2.
So, pressure = 1025 x 9.8 x 10 = 100,450 Pa.
Scuba divers use specialized equipment like pressure gauges and dive computers to monitor and control their exposure to pressure underwater. Additionally, they must follow safety guidelines and decompression procedures to avoid decompression sickness, a potentially life-threatening condition caused by the formation of gas bubbles in the bloodstream due to rapid changes in pressure.

To learn more about atmospheric pressure, refer:-

https://brainly.com/question/13407492

#SPJ11

The object will rotate through 16.00 revolutions in the next 5.00s if it rotates through 8.00 revolutions in the first 2.50s.

The first step to answer this question is to determine the rotational speed (angular velocity) of the object. To do this, we use the formula:

Angular velocity = number of revolutions / time

So, the angular velocity of the object is given by:

Angular velocity = 8.00 revolutions / 2.50 s

Angular velocity = 3.20 revolutions per second

Now, we can use this angular velocity to determine the number of revolutions the object will rotate through in the next 5.00 s. To do this, we use the formula:Number of revolutions = angular velocity x time

So, the number of revolutions the object will rotate through in the next 5.00 s is given by:

Number of revolutions = 3.20 revolutions per second x 5.00 s

Number of revolutions = 16.00 revolutions

Therefore, the object will rotate through 16.00 revolutions in the next 5.00 s.

More on angular velocity: https://brainly.com/question/20355237

#SPJ11

Answer:

1) 2.388ohms

2) R1 3.36A

R2 1.682A

R3 2.88A

R4 2.16A The current has 5.048A over all

3) Voltage in R1 is 3.36v

Voltage in R4 is 8.63v

Explanation:

1. Each of the resistance R1 and R2 are in parallel in series combination with R3 and R4 so we calculate

R1 and R2 which is 1×2÷(1+2)= 0.6667ohms

R3 and R4 which is 3×4÷( 3+4)= 1.71ohms

so the equivalent resistance is 0.667+ 1.71= *2.377ohms*

2. The overall current = voltage source ÷ total resistance

= 12÷ 2.377= 5.048Amps

so current in every resistor will be

current in 1ohms will be (2÷3)×5.048= 3.36Amps

current in 2ohms will be (1÷3)×5.048= 1.68Amps

current in 3ohms will be (4÷7)×5.048= 2.88amps

current in 4ohms will be (3÷7)× 5.048= 2.16amps

3. voltage in R1 is 0.667ohms × 5.048amps= 3.36v

voltage in R4 is 1.71ohms × 5.048amps= 8.63v

Frictional forces between a liquid and the walls of a pipe can convert kinetic energy into thermal energy, leading to a drop in pressure within the pipe due to the decrease in force being applied to the walls.

Frictional forces between the liquid and the walls of a pipe can lead to the conversion of kinetic energy into thermal energy. This can have an effect on the pressure of the liquid within the pipe. Specifically, when the liquid loses kinetic energy due to friction, the pressure within the pipe drops. This drop in pressure can be attributed to the fact that as the liquid loses kinetic energy, its molecules move more slowly, thus decreasing the amount of force that is being applied to the walls of the pipe. As a result, the pressure within the pipe decreases.

In summary, frictional forces between a liquid and the walls of a pipe can convert kinetic energy into thermal energy, leading to a drop in pressure within the pipe due to the decrease in force being applied to the walls.

For more such questions on Frictional forces.

https://brainly.com/question/30280752#

#SPJ11