Problem 1 A train started from rest and was in motion with constant acceleration of 0.50 for 25 s. How far did it go? (5 points) Problem 2 A light plane must reach a speed of 35 for takeoff on 250 m r

Answer:

9.8 m/s

Explanation:

Distance Traveled = 98 m

Total Time = 10 s

Average Speed = Total Distance/Total Time

= 98/10

= 9.8 m/s

Hope this helped...

Answer:

7.5 N/m

Explanation:

Potential energy of a spring can be calculated using below formula

Potential energy= 1/2kx^2

potential energy = 60 J

X= displacement = 4 m

K= spring constant=?

Substitute the values we have

60= 1/2 × K × 4^2

60= 1/2 × K × 16

60= K × 8

K= 7.5 N/m

Hence, the spring constant of the spring is 7.5 N/m

The centre of mass of the region is bounded by y=9-x^2 y=5/2x, and the z-axis is (3.5, 33/8). Formulae used to find the centre of mass are as follows:x bar = (1/M)*∫∫∫x*dV, where M is the total mass of the system y bar = (1/M)*∫∫∫y*dVwhere M is the total mass of the system z bar = (1/M)*∫∫∫z*dV, where M is the total mass of the systemThe region bounded by y=9-x^2 and y=5/2x, and the z-axis is shown in the attached figure.

The two curves intersect at (-3, 15/2) and (3, 15/2). Thus, the total mass of the region is given by M = ∫∫ρ*dA, where ρ = density. We can assume ρ = 1 since no density is given.M = ∫[5/2x, 9-x^2]∫[0, x^2+5/2x]dAy bar = (1/M)*∫∫∫y*dVTherefore,y bar = (1/M)*∫[5/2x, 9-x^2]∫[0, x^2+5/2x]y*dA= (1/M)*∫[5/2x, 9-x^2]∫[0, x^2+5/2x]ydA...[1].

The limits of integration in the above equation are from 5/2x to 9-x^2 for x and from 0 to x^2+5/2x for y.To evaluate the above integral, we need to swap the order of integration. Therefore,y bar = (1/M)*∫[0, 3]∫[5/2, (9-y)^0.5]y*dxdy...[2].

The limits of integration in the above equation are from 0 to 3 for y and from 5/2 to (9-y)^0.5 for x.Substituting the values and evaluating the integral, we get y bar = (1/M)*[(9-5/2)^2/2 - (9-(15/2))^2/2]= (1/M)*(25/2)...[3].

Also, the x coordinate of the center of mass is given by,x bar = (1/M)*∫∫∫x*dVTherefore,x bar = (1/M)*∫[5/2x, 9-x^2]∫[0, x^2+5/2x]x*dA= (1/M)*∫[5/2x, 9-x^2]∫[0, x^2+5/2x]xdA...[4].

The limits of integration in the above equation are from 5/2x to 9-x^2 for x and from 0 to x^2+5/2x for y.To evaluate the above integral, we need to swap the order of integration. Therefore, x bar = (1/M)*∫[0, 3]∫[5/2, (9-y)^0.5]xy*dxdy...[5].

The limits of integration in the above equation are from 0 to 3 for y and from 5/2 to (9-y)^0.5 for x.

Substituting the values and evaluating the integral, we get x bar = (1/M)*[63/8]= (1/M)*(63/8)...[6]Thus, the centre of mass of the region is bounded by y=9-x^2 y=5/2x, and the z-axis is (3.5, 33/8).

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In luminosity classification, it is observed that fat stars tend to have skinny spectral lines. This phenomenon suggests a correlation between the width of spectral lines and the luminosity of a star.

Luminosity classification is a method used to categorize stars based on their brightness and energy output. Spectral lines are dark or bright lines that appear in a star's spectrum, representing specific wavelengths of light emitted or absorbed by different elements in the star's atmosphere. The width of these lines can provide valuable information about a star's physical properties.

The observation that fat stars have skinny spectral lines implies that stars with higher luminosity tend to exhibit narrower lines in their spectra. This correlation can be attributed to the characteristics of fat stars, which generally have higher temperatures and stronger gravitational forces compared to their less luminous counterparts. These factors lead to a higher degree of ionization and higher densities in the stellar atmosphere, resulting in narrower spectral lines. Therefore, the width of spectral lines can serve as an indicator of a star's luminosity, with fat stars showing narrower lines compared to less luminous stars.

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Answer:

The lost mass is converted to energy according Einstein's equation:

E = m c^2

where m is the mass converted to energy and c is the speed of light

Explanation:

Δy = v₀ t + ½ at²

Δy = (0 m/s) (7.0 s) + ½ (-9.8 m/s²)(7.0s)²

= -34.3

The most likely correct about the three stars is: They do not have the same initial mass.

The Chandrasekhar limit is established at a mass where the gravitational field's self-attraction cannot be balanced by the pressure from electron decay.  The limit that has been established these days is 1.39 solar mass.

Hence,  stars of average masses ends by forming white dwarf or neutron star but massive stars ends their life by forming black hole. Hence, They do not have the same initial mass.

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The mirror's magnification is -0.307, which indicates that the image is inverted, and its focal length is 2.0 m. The picture's separation from the mirror is 2.61 m.

Mirror radius: R = 4.0 meter's

Mirror's focal length is equal to

focal length = R/2,

focal length = 4.0/2 m, and f = 2.0 m.

The man is 1.85 meter's tall.

Do = 8.5 meter's separates the subject from the mirror.

The distance between the picture and the mirror is di

1/di = 1/2.0-1/8.51

di = 1/0.382

di = 2.61m.

The picture is produced on the same side of the mirror as the item because the image distance is positive, hence the image will be accurate.

The magnification is negative thus the picture created is inverted.

magnification = -di/do = - 2.61/8.5 = -0.307.

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Taking into account the definition of calorimetry,  the final temperature of the silver and water is 11.84 °C.

Calorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.

Sensible heat is defined as the amount of heat that a body absorbs or releases without any changes in its physical state (phase change).

So, the equation that allows to calculate heat exchanges is:

Q = c× m× ΔT

where:

In this case, you know:

Replacing in the expression to calculate heat exchanges:

For silver: Qsilver= 240 \(\frac{J}{kgC}\)× 0.5 kg× (Final temperature of silver - 250 C)

For water: Qwater= 4180 \(\frac{J}{kgC}\) × 1 kg× (Final temperature of water - 5 C)

If two isolated bodies or systems exchange energy in the form of heat, the quantity received by one of them is equal to the quantity transferred by the other body. That is, the total energy exchanged remains constant, it is conserved.

Then, the heat that the silver gives up will be equal to the heat that the water receives. Therefore:

- Qsilver = + Qwater

And the final temperature of the silver is equal to the temperature of the water (Final temperature of silver= Final temperature of water= Final temperature). Then:

- 240 \(\frac{J}{kgC}\)× 0.5 kg× (Final temperature - 250 C)= 4180 \(\frac{J}{kgC}\) × 1 kg× (Final temperature - 5 C)

Solving:

- 120 \(\frac{J}{C}\)× (Final temperature - 250 C)= 4180 \(\frac{J}{C}\)× (Final temperature - 5 C)

120 \(\frac{J}{C}\)× (250 C - Final temperature) = 4180 \(\frac{J}{C}\)× (Final temperature - 5 C)

120 \(\frac{J}{C}\)×250 C - 120 \(\frac{J}{C}\)×Final temperature = 4180 \(\frac{J}{C}\)×Final temperature - 4180 \(\frac{J}{C}\)×5 C

30,000 J - 120 \(\frac{J}{C}\)×Final temperature = 4180 \(\frac{J}{C}\)×Final temperature - 20,900 J

50,900 J= 4300 \(\frac{J}{C}\)×Final temperature

50,900 J÷ 4300 \(\frac{J}{C}\)= Final temperature

11.84 °C= Final temperature

Finally,  the final temperature of the silver and water is 11.84 °C.

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Answer:

Explanation:

2) From F=ma

Force =15×40=600N or kgm/s2

3)From the same equation making acceleration the subject of the formula will give

a=f÷m

=24÷4=6m/s2

4)m=f÷a

=45÷15=3kg

The force required to keep the crate moving with constant velocity would be 1,775 N.

Frictional force: f = k * N where k is the coefficient of kinetic friction and N is the normal force.

In this case, the normal force is equal to the weight of the crate, which is N = m * g where m is the mass of the crate and g is the acceleration due to gravity.

At an angle of 30° above the horizontal, the force required to move the crate is

 F = (m * g) / cos(30°)

And the frictional force acting in the opposite direction is given by f = k * N .

Therefore, the force required to keep the crate moving with constant velocity is

 F = f + (m * g) / cos(30°)= k * N + (m * g) / cos(30°)= k * m * g + (m * g) / cos(30°)

Substituting k = 0.20, we get:

F = (0.20 * m * g) + (m * g) / cos(30°)F = (0.20 * 100 kg * 9.81 m/s²) + (100 kg * 9.81 m/s²) / cos(30°)F ≈ 1,775 N

Therefore, the force required to keep the crate moving with constant velocity is 1,775 N.

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Answer:

15.6 degrees

Explanation:

The distance over which the force acts on the box, given that 70 N is applied to the 10 Kg box is 3.125 m

We'll begin by obtaining the acceleration of the box. Details below:

Net force = mass × acceleration

40 = 10 × acceleration

Divide both sides by 10

Acceleration = 40 / 10

Acceleration = 4 m/s²

Finally, we shall determine the distance. Details below

v² = u² + 2as

5² = 0² + (2 × 4 × s)

25 = 0 + 8s

25 = 8s

Divide both side by 8

s = 25 / 8

s = 3.125 m

Thus, we can conclude that the distance covered is 3.125 m

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(a)The frequency of the broadcast is 1.2 × 10⁻¹⁰ Hz.

(b) It is a FM radio station.

(a) The wavelength of electromagnetic radiation = 1 quarter mile

                                                                                 = 0.25 mi

 ∴ Wavelength = Speed of light / Frequency

     λ = v / f

     f = v / λ

       = (299792.458 m/s ) / 0.25 mi

       = 1199169.832 Hz

       = 1.2 × 10⁻¹⁰ Hz

Therefore, the frequency of the broadcast is 1.2 × 10⁻¹⁰ Hz.

(b) The station is FM as it ranges in a higher spectrum from 88 to 108 MHz. (OR) 1200 to 2400 bits per second. The signal that is going to be sent in FM modulates the frequency of a radio wave known as the "carrier" or "carrier wave." The phase and amplitude stay constant.

Compared to AM, FM is less prone to interference. However, physical obstructions have an impact on FM broadcasts. Due to its greater bandwidth, FM has better sound quality. twice the result of the frequency variation and the modulating signal frequency.

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Answer:

The answer is 0.920g cm^-3

Density can be computed from the ratio of mass and volume. The standard unit of density is kg/m³.

The density is given as:
ρ = mass/ volume

Convert density from kg/m³ to g/m³:

Density in g/m³ = Density in kg/m³ × 1000 g/kg

Density in g/m³ = 920 kg/m³ ×  1000 g/kg

Density in g/m³ = 920,000 g/m³

Convert from g/m³ to g/cm³:

Density in g/cm³ = Density in g/m³ / (100 cm/m)³

Density in g/cm³ = 920,000 g/m³ / 1,000,000 cm³

Density in g/cm³ = 0.92 g/cm³

Hence, the density of ice  920 kg m³ in g/cm³ is equal to 0.92 g/cm³.

The density is calculated from mass and volume.

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Answer:

the answer is sea stacks and arches

The correct answer is B. The system did 800 J of work.

ΔU = Q - W

we are given that ΔU = 600 J and Q = 1400 J.

W = Q - ΔU

W = 1400 J - 600 J

W = 800 J

Thermal energy is a type of energy that is related to the temperature of a system or object. It is a form of kinetic energy that results from the movement of particles in a substance. The faster the particles move, the higher the temperature and the greater the thermal energy of the substance.

In physics, thermal energy is often associated with heat transfer between two objects that are at different temperatures. This transfer of energy can occur through conduction, convection, or radiation. For example, when you touch a hot stove, the thermal energy from the stove is transferred to your hand, causing a sensation of heat.

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Answer:

Yes, they do. When two different materials are rubbed together, there is a transfer of electrons from one material to the other material. This causes one object to become positively charged and the other object to become negatively charged.

Explanation:

hope this helps

Answer:

a) zero.

Explanation:

If the charge of an atom is neutral, then that means it has neither a negative charge nor a positive charge. So, it would have a charge of 0.

Hope this helps!

Answer:

m1 * m2) / r^2)

Where F is the gravitational force, G is the gravitational constant (6.67 x 10^-11 N*m^2/kg^2), m1 and m2 are the masses of the two objects, and r is the distance between them.

In this case, the mass of the satellite is 2300 kg and the mass of Earth is 5.97 x 1024 kg. The distance between the satellite and Earth's surface is 5400 m.

Plugging these values into the formula, we get:

F = (6.67 x 10^-11 N*m^2/kg^2) * ((2300 kg * (5.97 x 1024 kg)) / (5400 m)^2)

F = (6.67 x 10^-11 N*m^2/kg^2) * ((136510000000000 kg^2) / (291600 m^2))

F = 3.34 x 10^-4 N

Therefore, the gravitational force between the satellite and Earth is approximately 3.34 x 10^-4 N.

Answer:

22487.9N

Explanation:

Any two objects of sufficient mass experience a gravitational pull or force between them that is dependant on their masses and how far away they are from each other. The formula for the gravitational force between two objects is:

\(F=G\frac{m_{1} m_{2} }{r^{2} }\)

where F is the gravitational force, G is the gravitational constant (equal to 6.67x\(10^{-11}\)), \(m_{1}\) and \(m_{2}\) are the masses of the two objects and r is the distance between their centres.

We know the satellite is 5400m above the earth surface, but we need to know the distance between their centres, not between their surfaces. To do this, we usually add the radius of each object to the distance between their surfaces, but since the satellite's radius is likely so small that it's negligible, we can just add Earth's radius, which is 6,371 km:

5400+6371000=6376400m

We know the value fo G because it's a constant, we are given the masses of the earth and the satellite (5.97x\(10^{24}\)kg and 2300kg respectively), and we now know the distance between their centres (6376400m). Now we can sub these values into our formula to find the gravitational force:

\(F=G\frac{m_{1} m_{2} }{r^{2} }\)

\(F=(6.67*10^{-11} )\frac{(2300) (5.96*10^{24} ) }{6376400^{2} }\)=22487.89596N

Answer: FRANCE

Explanation:

Answer:

France

Explanation:

UK has 15 nuclear power plants and 2 under construction whereas France has 56 in operation and 1 under construction  

Answer:

yes it's communication

A ball rolls down an inclined plane, starting from rest. if the total time it takes to reach the end of the inclined plane is t, how much time has elapsed when it is halfway down the incline 0.5t

An inclined plane is a straightforward device with a sloping surface that is used to lift heavy objects. When friction is taken into account, the force needed to move an object up an incline is less than the weight being raised. The needed force is closer to the real weight the higher the slope or incline.

The inclined plane is the most basic of all simple machines because nothing needs to move for it to function. In order to save effort, you have to move objects farther when using an inclined plane. A variety of techniques can be used to create an inclined plane. It can be as simple as a log leaning against a tree in the woods or a piece of wood placed on the edge of a stair.

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When trying to establish economical hauling, hauling distance is usually the most important factor to consider. Hauling distance refers to the  point of origin and the destination of the goods being transported.

The farther the distance, the higher the cost of transportation, as it requires more time, fuel, and resources to haul the goods. While other factors such as hauling time, means of hauling, and what is being hauled can also impact the cost and efficiency of transportation, the distance typically has the most significant impact on the overall cost. Therefore, it is crucial to consider the hauling distance when trying to establish an economical hauling plan. To minimize the cost of transportation, various strategies can be employed, such as optimizing the routing to reduce the distance traveled, utilizing more efficient means of transportation, such as rail or water transport, and using technology to improve logistics and reduce waste. Ultimately, the goal of establishing an economical hauling plan is to minimize transportation costs while ensuring that goods are delivered safely, reliably, and on time. By prioritizing hauling distance and utilizing efficient transportation strategies, businesses can achieve a more cost-effective and sustainable transportation plan.

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