Problem 1: A box rests on a horizontal surface. You apply a force on the box of F= 100 N at an angle, 0, below the horizontal and it slides at a constant velocity. The friction force that acts on the box is: Multiple Choice : 1) 100 Newtons. 2) less than 100 Newtons. 3) greater than 100 Newtons. у F 0 m y. X

Answers

Answer 1

On a horizontal surface, a box is perched. The box glides at a constant speed when you apply a force of 100 N at an angle of 0 below the horizontal. Less than 100 N of frictional force is exerted on the box.

A box is moving steadily at 0.55 m/s down an incline slope. All forces operating on this container must result in a vector that points. None of the alternatives above. A extremely thin rope is used to drop a bucket at a steady descending speed. The rope's tension must match the weight of the bucket. If the box is subjected to a force F with an angle p as illustrated,what is the smallest value of below which, regardless of the, the box will not move; A 55.0-kg box is positioned horizontally. The box and the surface have a static friction coefficient of 0.300. What must be put to the box horizontally in order for it to begin.

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Related Questions

(a) what energy is released in the - decay of 99mo, given its mass is 98. 907711 u?

Answers

The energy released in the β⁻ decay of ⁹⁹Mo is zero.

To calculate the energy released in the β⁻ decay of ⁹⁹Mo, we need to determine the change in mass (Δm) and then use the equation E = Δm * c², where c is the speed of light.

In this case: mass of ⁹⁹Mo (m) = 98.907711 u

Mass of ⁹⁹Mo in kg = 98.907711 u * (1.66 × 10⁻²⁷ kg/u) ≈ 1.64 × 10⁻²⁵ kg

Next, we determine the mass of the decay product, which is ⁹⁹Tc (technetium). The mass of ⁹⁹Tc is approximately 99 u.

Mass of ⁹⁹Tc in kg ≈ 99 u * (1.66 × 10⁻²⁷ kg/u) ≈ 1.64 × 10⁻²⁵ kg

Now we can calculate the change in mass:

Δm = (Mass of ⁹⁹Mo in kg) - (Mass of ⁹⁹Tc in kg)

Δm ≈ (1.64 × 10⁻²⁵ kg) - (1.64 × 10⁻²⁵ kg) = 0

Since Δm is zero, it means that there is no change in mass during the β⁻ decay of ⁹⁹Mo.

Finally, we can calculate the energy released:

E = Δm * c² = 0 * (3.00 × 10⁸ m/s)² = 0

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What is the speed of a wave that has a wavelength of 0.579 m, an amplitude of 0.733 m, and frequency of 4.00 Hz?0.145 m/s6.91 m/s2.93 m/s2.32 m/s

Answers

v(speed) = wavelenght x frequency

v = 0.579 m x 4 hz = 2.32 m/s


What is the density of ocean water if 308.19g fills a 300mL container?

Answers

Answer:

Density = 1027.3 [kg/m3]

Explanation:

To solve this problem we must use the concept of density which is defined as the relationship between mass and volume, which can be determined by the following equation.

density = m/v

m = mass = 308.19 [gramm] = 0.30819 [kg]

v = volume = 300 [mL] = 0.3 [Lt] = 0.0003 [m3]

density = (0.30819/0.0003)

density = 1027.3 [kg/m3]

What is the maximum speed when the conditions are mass =450 kg, initial height= 30 m, and the roller coaster is initially at rest?

A. 30 m/s
B. 24.2 m/s
C. 93.9 m/s
D. 132, 300 m/s

Answers

Answer:

B. 24.2 m/s

Explanation:

Given;

mass of the roller coaster, m = 450 kg

height of the roller coaster, h = 30 m

The maximum potential energy of the roller coaster  due to its height is given by;

\(P.E_{max} = mgh\\\\PE_{max} = 450 *9.8*30\\\\PE_{max} = 132,300 \ J\)

\(P.E_{max} = K.E_{max} \ (law \ of \ conservation\ of \ energy)\)

\(K.E_{max} = \frac{1}{2}mv_{max}^2\\\\ v_{max}^2 = \frac{2K.E_{max}}{m}\\\\ v_{max}^2 = \frac{2*132300}{450}\\\\ v_{max}^2 =588\\\\v_{max} = \sqrt{588}\\\\ v_{max} = 24.2 \ m/s\)

Therefore, the maximum speed of the roller coaster is 24.2 m/s.

Answer:

1. 24.2 m/s

2. 20.4 m

3. 22.5 m/s

4. 109,375 J

5. It is easy to calculate new scenarios.

Explanation:

5/5 on the Maximum Energy Quick Check

If the block in the picture has an acceleration of 5 m/s2, what would be the block's mass?

If the block in the picture has an acceleration of 5 m/s2, what would be the block's mass?

Answers

Answer:

0.4 Kg

Explanation:

From the question given above, the following data were obtained from the question:

Acceleration (a) of block = 5 m/s²

Force in the right direction (Fᵣ) = 3 N

Force in the left direction (Fₗ) = 5 N

Mass (m) of block =...?

Next, we shall determine the net force acting on the block. This can be obtained as follow:

Force in the right direction (Fᵣ) = 3 N

Force in the left direction (Fₗ) = 5 N

Net force (Fₙ) =?

Fₙ = Fₗ – Fᵣ

Fₙ = 5 – 3

Fₙ = 2 N

Thus the net force acting on the block is 2 N to the left.

Finally, we shall determine the mass of the block as follow:

Acceleration (a) of block = 5 m/s²

Net force (Fₙ) = 2 N

Mass (m) of block =...?

Net force (Fₙ) = mass (a) × acceleration (a)

Fₙ = m × a

2 = m × 5

Divide both side by 5

m = 2/5

m = 0.4 Kg

Therefore, the mass of the block is 0.4 Kg

Which is not a cell theory ?

A: All non - living things are made of cells

B: All cells come from pre - existing cells

C: Cells are the basic unit of structure and function of all living things

Answers

The answer is c hope it is right
Um it is most definitely not letter C.
It’s actually letter A.

Variation #1: Create analytical maps of historical ownership, paved areas for cars, parks & natural amenities. areas,community Street Design
• Streets are public space, just like parks. How do we measure who a street is designed for?

Answers

Analytical maps can be created to depict historical ownership, paved areas for cars, parks, natural amenities, and community street design. Streets, being public spaces, require measurement to determine their intended beneficiaries.

Analytical maps offer a valuable tool for visualizing and understanding various aspects of urban planning. By creating maps that showcase historical ownership patterns, paved areas designated for cars, locations of parks and natural amenities, and community street design, it becomes easier to assess the distribution of resources and infrastructure within a city.

In this context, streets hold a significant role as public spaces. They are not solely meant for vehicular traffic but should also prioritize the needs and activities of pedestrians, cyclists, and the wider community. Analyzing street design through mapping can help evaluate whether streets are primarily designed to cater to cars or if they accommodate a balanced and inclusive approach that considers the needs of all users.

To achieve equitable urban environments, it is crucial to assess the intended beneficiaries of street design and identify any discrepancies or biases in the allocation of public space. By utilizing analytical maps, planners, policymakers, and communities can have a clearer understanding of the current state of street design and work towards creating more people-centric and sustainable cities.

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Help with both a and b please

Help with both a and b please

Answers

Explanation:

a.)

Reactants : CO2 (carbondioxide) + H2O (water)

Products : O2 (oxygen) + C6H12O6 (glucose)

b.)

Reactants: Na ( Solid Hydrogen) + H2O (water)

Products: H2 (hydrogen gas) + NaOH (sodium hydroxide)

Using the side lengths of △pqr and △stu, which angle has a sine ratio of four-fifths? ∠p ∠q ∠t ∠u

Answers

∠p has a sine ratio of four-fifths.

The answer is option A.

Trigonometric Ratios are defined because the values of all the trigonometric features are based totally on the fee of the ratio of sides in a right-angled triangle. The ratios of sides of a right-angled triangle with recognition of any of its acute angles are referred to as the trigonometric ratios of that particular perspective.

The six trigonometric ratios are sine (sin), cosine (cos), tangent (tan), cotangent (cot), cosecant (cosec), and secant (sec).

In geometry, trigonometry is a department of mathematics that offers the sides and angles of a right-angled triangle. Therefore, trig ratios are evaluated with admire to aspects and angles.

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Answer: A

Explanation: Angle P

Calculate the grams of solute prepare each of the following solution.
1. 1.0 L of 6.0 M N
a
O
H
solution
2. 7.0 L of a 0.70 M C
a
C
l
2
solution
3. 175 mL of a 3.05 M N
a
N
O
3
solution

Answers

To calculate the grams of solute for each solution, we need to use the formula: grams of solute = moles of solute × molar mass of soluteFor 1.0 L of 6.0 M NaOH solution:To find the moles of NaOH, we multiply the molarity by the volume in liters:

moles of NaOH = 6.0 M × 1.0 L = 6.0 moles

The molar mass of NaOH is approximately 22.99 g/mol + 16.00 g/mol + 1.01 g/mol = 40.00 g/mol (rounded to two decimal places).

grams of NaOH = 6.0 moles × 40.00 g/mol = 240.00 grams

For 7.0 L of 0.70 M CaCl2 solution:

Moles of CaCl2 = 0.70 M × 7.0 L = 4.90 moles

The molar mass of CaCl2 is approximately 40.08 g/mol + (2 × 35.45 g/mol) = 110.98 g/mol (rounded to two decimal places).

grams of CaCl2 = 4.90 moles × 110.98 g/mol = 543.10 grams

For 175 mL of 3.05 M NaNO3 solution:

Since the volume is given in milliliters, we need to convert it to liters by dividing by 1000:

Volume = 175 mL ÷ 1000 = 0.175 L

Moles of NaNO3 = 3.05 M × 0.175 L = 0.53375 moles

The molar mass of NaNO3 is approximately 22.99 g/mol + 14.01 g/mol + (3 × 16.00 g/mol) = 85.00 g/mol (rounded to two decimal places).

grams of NaNO3 = 0.53375 moles × 85.00 g/mol = 45.43 grams (rounded to two decimal places)

Therefore, the grams of solute for each solution are:

240.00 grams

543.10 grams

45.43 grams

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Where electrons are held or stored​

Answers

Answer:

Held

~Hope it Helps!~

A brick of mass 6 kg hangs from the end of a spring. When the brick is at rest, the spring is stretched by 7 cm. The spring is then stretched an additional 2 cm and released. Assume there is no air resistance. Note that the acceleration due to gravity, g, is g

Answers

The total mechanical energy of the system is 0.24 times the acceleration due to gravity, g.

We can use Hooke's Law and the principles of conservation of energy.
First, let's calculate the spring constant, k.

Hooke's Law states that the force exerted by a spring is directly proportional to the displacement from its equilibrium position. In this case, the force is equal to the weight of the brick, which is mg, where m is the mass of the brick and g is the acceleration due to gravity.
The spring is stretched by 7 cm when the brick is at rest, we can write the equation as:
k * 0.07 = 6 * g
Simplifying the equation, we find:
k = (6 * g) / 0.07
Now, let's find the potential energy of the spring when it is stretched an additional 2 cm. The potential energy of a spring can be calculated using the formula:
U = (1/2) * k * x^2
where U is the potential energy, k is the spring constant, and x is the displacement from the equilibrium position.
Plugging in the values, we get:
U = (1/2) * ((6 * g) / 0.07) * (0.02)^2
Finally, we can calculate the total mechanical energy of the system, which is the sum of the potential energy and the gravitational potential energy of the brick. The gravitational potential energy is given by:
E = m * g * h
where E is the mechanical energy, m is the mass of the brick, g is the acceleration due to gravity, and h is the height from which the brick is released.
Since the brick is at rest when the spring is stretched by 7 cm, the height h is equal to the additional displacement of the spring, which is 2 cm.
Therefore, the total mechanical energy is:
E = (6 * g * 0.02) + (6 * g * 0.02)
Simplifying the equation, we find:
E = 0.24 * g
So, the total mechanical energy of the system is 0.24 times the acceleration due to gravity, g.

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how can we realize that light travel in straight line ?​

Answers

Answer:

It can be seen from the operation of pin-hole camera, formation of shadows and eclipse.

Explanation:

The phenomenon of light traveling in a straight line is known as rectilinear propagation of light.

One this evidence can be seen from the operation of pin-hole camera, which depends on rectilinear propagation of light

Also two natural effects that result from the rectilinear propagation of light are the formation of Shadows and Eclipse.  

How does a person’s nutritional needs change with an increase in activity to gain muscle mass?

Answers

Answer:

Dietary carbohydrates provide the body with energy for tough workouts and replenish energy stores in muscles in the form of glycogen.

Explanation:

A fisherman sitting on the end of a pier notices that 6 wave crests pass him in 3 seconds. What is the frequency of the waves?.

Answers

Answer:

2 Hz

Explanation:

f = frequency

n = wave crest

t = time

f = n/t → f = 6/3 = 2

Explain what is weight? How is it different from
mass?

Answers

Answer:

The difference between mass and weight is that mass is the amount of matter in a material, while weight is a measure of how the force of gravity acts upon that mass. Mass is the measure of the amount of matter in a body. Mass is denoted using m or M.

Explanation:

Answer:

he mass is essentially "how much stuff" is in an object. Weight = There is a gravitational interaction between objects that have mass. If you consider an object interacting with the Earth, this force is called the weight.

Explanation:

Your mass is the same no matter where you go in the universe; your weight, on the other hand, changes from place to place.

In any thermodynamic system that deals with the transfer of thermal energy, which of thefollowing is the most ideal state for that system?

In any thermodynamic system that deals with the transfer of thermal energy, which of thefollowing is

Answers

Thermodynamics can be said to be a branch of Physics which involves the transfer of heat and other energy forms.

Thermal energy is the energy possesed by a system due to its temperature.

In thermodynamics, during the transfer of thermal energy, energy is wasted due to entryopy. And entropy is the measure of disorder of a system.

Therefore, in amy thermodynamic system that deals with the transfer of thermal energy, the most ideal state for that system is Entropy

ANSWER:

A. Entropy

Which guideline best reflects how private information should be protected when using social networks? All social media users are screened and safe to engage with. Protect your private information by setting your account to private and only adding people you actually know. Only share your passwords with close friends that you trust. It is safe to share personal information with companies on social networking sites.

Answers

Answer:

hescorrect i just took the test and that was the awnser

Explanation:

if u need i can give the other awnsers

Answer:

(A. 1.) Protect your private information by setting your account to private and only adding people you actually know.

Explanation:

Which guideline best reflects how private information should be protected when using social networks?

a plane accelerates from 4 m/s/s for 28.7 s until it finally lifts on the ground. Assuming the plane started from the rest, what was the planes displacement before takeoff?

Answers

There were 1647 before liftoff. 38 m moving planes.

A Straight Line Motion is defined as?

An object is considered to be in motion if its location throughout time changes in relation to its surroundings. It is the gradual change in an object's location. The only kind of motion that exists is linear motion.

Which three motion equations are there?

The three equations are as follows: S = ut + 12at2, v = u + at, v2 = u + 2as.

The airplane's initial speed is U=0 m/s.

The plane accelerates at a 4 m/s rate.

with a time stamp of 28.7 seconds.

Distance traveled using the formula S=ut+a

⇒ S=0(28.7)+0.5(4) (4)

=1647.38 ~ 1647m

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A conducting wire is carrying current directly up in external magnetic field perpendicular to wire. What direction of magnetic field allows this wire to levitate

Answers

The direction of the magnetic field that allows a conducting wire to levitate is a magnetic field pointing directly downward.

When a conducting wire carries current and is placed in an external magnetic field, it experiences a force known as the Lorentz force. The Lorentz force on a current-carrying wire is given by the equation:

F = I * L * B * sin(theta)

Where:

- F is the force on the wire

- I is the current flowing through the wire

- L is the length of the wire

- B is the strength of the magnetic field

- theta is the angle between the wire and the magnetic field

For the wire to levitate, the force on the wire should be equal to the force due to gravity, but in the opposite direction. In other words, the upward force on the wire should counterbalance the downward force of gravity.

Since the current in the wire is flowing directly upward, the force on the wire due to the external magnetic field should also be pointing directly downward to achieve levitation. This means that the magnetic field should be perpendicular to the wire and pointing directly downward.

To allow a conducting wire carrying current directly up to levitate, the external magnetic field must be perpendicular to the wire and pointing directly downward.

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A small object is placed in front of a concave mirror gives real image and image is 4 times the object. When the object is moved towards the mirror, a virtual image of same magnification is formed. Find the focal length of the mirror.

Answers

The focal length of the mirror, when the object is moved towards it and a virtual image is formed is calculated to be -4u/3.

We know that,

magnification, m =      height of image, v        

                                 height of the object, u

given in the question, m = 4

as the mirror is concave, thus:

v= -4u

Now, by using the mirror formula:

1/(-f) = 1/ v + 1/u    

(as the image formed is virtual, the focal length of the mirror will be negative)

1/(-f) = 1/(-4u) + 1/u

-1/f = 3/4u

f= -4u/3

Concave mirrors create both physical and virtual images. When the concave mirror is put very close to the object, a virtual and enlarged image is generated; as the distance between the item and the mirror increases, the size of the image decreases, and genuine images are formed. These real-world photographs can be displayed on a screen. The concave mirror's focal point and center of curvature are located in front of the mirror.

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A feather is falling towards the ground at a constant speed. Of the forces listed, identify which act upon the feather.

Answers

Answer:

Gravitational force

Explanation:

Gravitational force is what is making the feather go down. It's pushing the feather down, without the Gravitational force, the feather would have been going up, and not down. Just like us. Gravitational force is what keeps us humans from floating ( unless ur an alien jklol), So yeah Gravitational force is the force that acts upon the feather to fall towards the ground at a constant speed.

Btw, u never listed the forces here just ....

Hope this helped!

A feather is falling towards the ground at a constant speed. Forces act upon the feather is gravitational force.

What is force?

A force is an effect that can alter an object's motion according to physics. An object with mass can change its velocity, or accelerate, as a result of a force. An obvious way to describe force is as a push or a pull. A force is a vector quantity since it has both magnitude and direction.

When body is falling the net acceleration that objects get as a result of the combined action of gravity and centrifugal force is known as the Earth's gravity, or g. It is a vector quantity  

A feather is falling towards the ground at a constant speed. Forces act upon the feather is gravitational force.

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2 Calculate the mass of a car that hits a wall, during an accident, with a force of 961 N and an acceleration of 31m/s2. (4D) (F = m * a) *

Answers

Answer: 31kg

Explanation:

(F=mxa)

Rearranged

M=f÷a

961÷31=31

As shown in the figure below, Jenna rushes 30 m toward her truck. She notices she forgot her jacket and
returns back to the house. Her total travel time is 75 s.
30 m
30 m
What is Jenna's average velocity over the 75 s period?​
What is Jenna's average speed over the 75 s period?

Answers

Answer:

Average Velocity: 0

Average Speed 0.8

Explanation:

Velocity - (30-30)/75 = 0

Speed - (30+30)/75 = 0.8

Consider that the wind speed profile at the Earth's surface can be didactically represented as the flow profile of a fluid between two infinite parallel plates separated by a distance 2h, where the upper plate has velocity V0 and the pressure gradient between two points along the x axis is nonzero. You are then asked (a) to derive a expression for the velocity profile of this flow, assuming that the flow is laminar (1D) and permanent. Then determine (b) for what pressure gradient is the flow between the plates and zero. Tip: Take as the system origin the axis that passes through the middle of the parallel plates.

Answers

Expression for the velocity profile of flow: In fluid mechanics, Hagen–Poiseuille equation is used to calculate the flow of laminar and Newtonian fluids in circular tubes.

The equation was derived independently by Gotthilf Hagen and Jean Léonard Marie Poiseuille in 1839 and 1840 respectively.

It is given by;

\(Q=πr4∆P8ηLQ=πr4∆P8ηL\)

Where Q is the flow rate, r is the radius of the tube, ∆P is the pressure gradient along the tube, η is the viscosity of the fluid, and L is the length of the tube.

The velocity profile of the flow can be derived as follows:

For a fluid between two infinite parallel plates separated by a distance of 2h, with the upper plate having velocity V0, the pressure gradient between two points along the x-axis is nonzero.

Consider a fluid element of thickness δy at a distance y from the lower plate.

Due to the viscous forces between the layers of fluid, it will be affected by the velocity of the adjacent layer.

the fluid element is subjected to a shear force due to the velocity gradient,\(dV/dy.\)

The magnitude of the shear force is given by

\(τ=μ(dV/dy)τ=μ(dV/dy),\)

where μ is the coefficient of viscosity of the fluid.

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two basic types of friction include?

Answers

static friction and kinetic friction
static:when two surfaces aren’t moving
kinetic:objects in motion
According to “Live Science.com” it states, “There are two main types of friction, static friction and kinetic friction. Static friction operates between two surfaces that aren't moving relative to each other, while kinetic friction acts between objects in motion.”

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A car is moving from rest and attained a velocity of 80 m/s. Calculate the acceleration of the car after 5 s?

Answers

Answer:

400 m/s

Explanation:

If it is moving at a velocity of 80 m/s from rest, then after 5 s it would be at 400 m/s.

80 x 5 = 400

A 19.7 kg sled is pulled with a 42.0 N force at a 43.0° angle, across ground where μ₁ = 0.130.
What is the normal force on the sled?

Answers

The following information is provided in the problem: A sled with a weight of 19.7 kg is pulled with a force of 42.0 N at an angle of 43.0° across ground where μ₁ = 0.130. We need to find out the normal force that is exerted on the sled.

Let us examine each of the forces acting on the sled.The weight of the sled is equal to its mass multiplied by the acceleration due to gravity. Therefore, the weight of the sled is:mg = 19.7 kg x 9.8 m/s² = 193.06 N.The force exerted on the sled can be divided into two components: one that is parallel to the ground and one that is perpendicular to the ground.The force parallel to the ground is:F₁ = 42.0 N x cos(43.0°) = 30.56 N.The force perpendicular to the ground is:F₂ = 42.0 N x sin(43.0°) = 28.30 N.The frictional force is equal to the coefficient of friction multiplied by the normal force. Therefore, we need to find the normal force on the sled in order to calculate the frictional force. Since the sled is not accelerating vertically, the normal force is equal to the weight of the sled plus the force perpendicular to the ground. Therefore, N = mg + F₂N = 193.06 N + 28.30 N = 221.36 N.The frictional force is:Fr = μ₁ x NFr = 0.130 x 221.36 N = 28.77 N.Thus, the normal force exerted on the sled is 221.36 N.

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1. The Coulomb force between two charges q1 and q2 at separation r in air is F. If half of the separation is filled with medium of dielectric constant 9, what will be the value of new coulomb force? 2.There are two large parallel metallic platesP1 and P2 carrying surface charge densities σ1 and σ2(σ1> σ2) respectively, placed at some distance d apart in vacuum. Determine the work done by the electric field in moving a point charge q from P1 to P2 along a line a (a

Answers

Answer:

Explanation:

1 )

F = k q₁q₂ / r² where k = 9 x 10⁹

So force F₁ =  \(\frac{kq_1q_2}{(\frac{r}{2}+\frac{\sqrt{9} r}{2})^2 }\)

= \(\frac{kq_1q_2}{(\frac{r}{2}+\frac{3 r}{2} )^2 }\)

= k q₁q₂ /4 r²

F₁  =  F / 4

2 ) Electric field due to charge density σ

= σ / ε₀

So net electric field between the plates

=   ( σ₁ - σ₂ )  / ε₀

Force on charge  q

=  ( σ₁ - σ₂ ) q   / ε₀

work done = force x displacement

=  ( σ₁ - σ₂ ) x q x d   / ε₀

If a plane lands on a runway and takes 10.4s to come to a complete stop at the end of the runway... how fast was it going as it started to land and what was its acceleration rate (this will be a negative number)? The distance traveled was 1400m

Answers

Explanation:

Given:

Δx = 1400 m

v = 0 m/s

t = 10.4 s

Find: v₀ and a

Δx = ½ (v + v₀) t

1400 m = ½ (0 m/s + v₀) (10.4 s)

v₀ = 269 m/s

Δx = vt − ½ at²

1400 m = (0 m/s) (10.4 s) − ½ a (10.4 s)²

a = -25.9 m/s²

Other Questions
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