Primary pollutants (NO, VOCs) reacting with oxygen and water vapor in sunlight produces ozone and NO2 known as _________.
a) acidic rain
b) volatile organic
c) compounds (VOCs)
d) photochemical smog
e) industrial smog
Answers
Primary pollutants (NO, VOCs) reacting with oxygen and water vapor in sunlight produce ozone and NO₂, known as photochemical smog. The option D is correct answer.
When primary pollutants such as nitrogen oxide (NO) and volatile organic compounds (VOCs) react with oxygen and water vapor in the presence of sunlight, they form secondary pollutants including ozone (O₃) and nitrogen dioxide (NO₂), which are characteristic of photochemical smog.
Photochemical smog is a type of air pollution that occurs in urban areas with high levels of vehicle emissions and industrial activities. It is characterized by the presence of ozone, nitrogen dioxide, and other secondary pollutants.
The reaction process involves the sunlight-initiated oxidation of primary pollutants, primarily NO and VOCs, leading to the formation of ozone and NO₂. These reactions occur in the lower atmosphere and are enhanced by the presence of sunlight, hence the term "photochemical" smog.
Ozone (O₃) is a harmful gas at ground level and can cause respiratory issues and other health problems. Nitrogen dioxide (NO₂) is a reddish-brown gas that contributes to the brownish color associated with photochemical smog. Together, these pollutants contribute to the formation of the characteristic haze and unpleasant odor associated with photochemical smog.
The formation of photochemical smog is a complex process influenced by factors such as temperature, sunlight intensity, and the concentration of primary pollutants in the atmosphere. Hence, the correct answer is option D.
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Related Questions
Malik analyzed three samples to test which element was a metalloid. The table shows his results. A 7-column table with 3 rows. The first column titled element has entries A, B, C. The second column titled lustrous has entries yes, no, yes. The third column titled brittle has entries no, yes, yes. The fourth column titled how it reacts has entries base, acid, acid or base. The fifth column titled boiling point (degrees C) has entries not observed, negative 34. 04, not observed. The sixth column titled melting point (degrees C) has entries 97. 72, not observed, 1413. 85. The seventh column titled electrical conductivity has entries high, very low, medium. Which element (A, B, or C) is most likely a metalloid?.
Answers
Element B exhibits the most characteristics associated with metalloids. It is non-lustrous, brittle, shows amphoteric behavior, has intermediate melting and boiling points, and has very low electrical conductivity. Therefore, Element B is most likely a metalloid.
Element A: It is lustrous (yes), which is characteristic of metals. It is not brittle (no) and reacts with bases, suggesting metallic behavior. The boiling point is not observed, but the melting point is relatively low at 97.72 degrees Celsius. However, the electrical conductivity is not provided, so we cannot make a definitive conclusion about its classification.Element B: It is non-lustrous (no) and brittle (yes), indicating non-metallic characteristics. It reacts with both acids and bases, suggesting amphoteric behavior, which is commonly associated with metalloids. The boiling point is not observed, and the melting point is also not observed, indicating intermediate values. The electrical conductivity is very low, which is another characteristic of metalloids.Element C: It is lustrous (yes), suggesting metallic properties. It is brittle (yes), which is not typical of metals but can be seen in some metalloids. It reacts with acids, indicating non-metallic behavior. The boiling point is not observed, and the melting point is relatively high at 1413.85 degrees Celsius. The electrical conductivity is medium, which aligns with both metals and metalloids.Learn more about the metalloids here:
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The bomb that destroyed the murrah federal office building in oklahoma city in april 1995 was constructed from ordinary materials: fertilizer (ammonium nitrate) and fuel oil (a mixture of long-chain hydrocarbons, similar to decane, c10h22).
Answers
The standard enthalpy change of the explosive reaction is -11408 kJ/mol.
The standard enthalpy change of the reaction can be calculated using the enthalpy of formation values of the reactants and products.
The enthalpy of the formation of ammonium nitrate (NH4NO3) is -393.5 kJ/mol, the enthalpy of the formation of the fuel oil (C10H22) is -249.7 kJ/mol, the enthalpy of the formation of oxygen (O2) is 0 kJ/mol.
The enthalpy of the formation of nitrogen (N2) is 0 kJ/mol, the enthalpy of the formation of water (H2O) is -285.8 kJ/mol, and the enthalpy of the formation of carbon dioxide (CO2) is -393.5 kJ/mol.
The equation for the explosive reaction is 3NH4NO3(s)+C10H22(l)+14O2(g)>3N2(g)+17H2O(g)+10CO2(g). Therefore, the standard enthalpy change of the reaction can be calculated using the following equation:
ΔH = [3(-393.5) + (-249.7) + (14*0) + (3*0) + (17*-285.8) + (10*-393.5)] - [3(-393.5) + (-249.7) + (14*0)]
ΔH = -11408 kJ/mol.
Therefore, the standard enthalpy change of the explosive reaction is -11408 kJ/mol.
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The complete question is attached below.
which of the following is not one of the forms of vitamin a in your body and in food listed in the video? a.retinol b.retinoic acid c.retinal d.retinase e.retinyl esters
Answers
Retinase. Vitamins don't help to raise how many calories or how much energy the human body needs.
What three forms does vitamin A come in?Dietary supplements that contain vitamin A are often preformed vitamin A in the form of retinyl acetate or retinyl palmitate, provitamin A in the form of beta-carotene, or a combination of preformed and provitamin A.
What variations of vitamin A are there in the body?Preformed vitamin A (retinol, retinyl esters) and provitamin A carotenoids like alpha- and beta-carotene that are converted to retinol are the two main forms of vitamin A in the human diet. Animal products, fortified meals, and vitamin supplements are sources of preformed vitamin A.
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wgat would haooeb ti ag abd ck us solid sodiun chloride is added to a saturated solution of silver chloride
Answers
According to the equilibrium law, this should move the AgCl equilibrium to the left (i.e., favor the reverse reaction) until the system finds equilibrium once more. This will increase the concentration of Cl-(aq) ions in the solution.
The following equilibrium is established by an AgCl solution that is saturated:
Ag+(aq) + Cl- =>AgCl(s) (aq)
NaCl will entirely separate into ions when added to the solution:
Na+(aq) + Cl=> NaCl(s) (aq)
According to the equilibrium law, this should move the AgCl equilibrium to the left (i.e., favor the reverse reaction) until the system finds equilibrium once more. This will increase the concentration of Cl-(aq) ions in the solution.
What is seen is that as an AgCl precipitate forms, both [Ag+] and [Cl-] will decrease.Because part of the Ag ions precipitated out, the [Ag+] in the new system will be lower than it was in the original saturated solution, while the [Cl-] ions will be higher (because you added more when you added NaCl). There will have been some precipitation of that excess Cl-, but not all of it. The result will be the same as the Ksp of AgCl if these new ion concentrations are entered into the Ksp equation.
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the question you are looking for is
What would happen to the Ag+ and Cl- concentrations if solid NaCl were dissolved in a saturated solution of AgCl in water?
Examine the reaction. NH4OH(aq) →H2O(l) + NH3(g)
What coefficients will balance the equation?
A) 1, 1, 1
B) 3, 3, 4
C) 2, 1, 2
D) 1, 2, 2
Answers
Answer: A. 1,1,1
Explanation:
The coefficients that will balance the equation; NH4OH(aq) →H2O(l) + NH3(g), is 1, 1, 1, because it proves the total number of atoms of each element on the LHS and RHS of the equation are equal, hence balanced.
LHS RHS
N = 1 1
H = 5 5
O = 1 1
when a compound donates (loses) electrons, that compound becomes blank. such a compound is often referred to as an electron donor.target 1 of 6 2. when a compound accepts (gains) electrons, that compound becomes blank. such a compound is often referred to as an electron acceptor.target 2 of 6 3. in glycolysis, the carbon-containing compound that functions as the electron donor is blank.target 3 of 6 4. once the electron donor in glycolysis gives up its electrons, it is oxidized to a compound called blank.target 4 of 6 5. blank is the compound that functions as the electron acceptor in glycolysis.target 5 of 6 6. the reduced form of the electron acceptor in glycolysis isblank.target 6 of 6
Answers
when a compound donates (loses) electrons, that compound becomes Oxidized. such a compound is often referred to as an electron donor.
when a compound accepts (gains) electrons, that compound becomes Reduced. such a compound is often referred to as an electron acceptor.
in glycolysis, the carbon-containing compound that functions as the electron donor is Glucose.
once the electron donor in glycolysis gives up its electrons, it is oxidized to a compound called Pyruvate
5. NAD⁺ is the compound that functions as the electron acceptor in glycolysis.
6. the reduced form of the electron acceptor in glycolysis is NADH
A substance is said to be oxidized when it loses electrons, loses hydrogen, or receives oxygen.
However, the opposite happens with reduction. In other words, when a substance gains electrons, gains hydrogen, or loses oxygen, it is said to be reduced.
A substance that itself is reduced to oxidize another substance is called an oxidizing agent. Redox reactions occur simultaneously. That is, when one substance is oxidized, only another substance is reduced.
During glycolysis, the six-carbon compound glucose (C6H12O6) loses electrons and is finally converted to a three-carbon compound known as pyruvate (CH3COCOOH). In this process, an oxidant called NAD+ receives electrons and is itself reduced to NADH.
The chemical formula for glucose is C6H12O6, while the chemical formula for pyruvate is CH3COCOOH. Looking at their chemical formulas, it is easy to see that glucose has lost hydrogen compared to pyruvate. That means that glucose has been oxidized. Glucose has 12 hydrogens for 6 carbons, but pyruvate has only 4 hydrogens for 3 carbons. This means that glucose was oxidized in the process because the molecule produced, pyruvate, has relatively few hydrogens.
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Fill in the blank to correctly identify the relative melting points for the fatty acid pairs indicated:(a) Myristate (14:0) has a higher/ lower or equal melting point than stearate (18:0).(b) Palmitate (16:0) has a higher /lower/equal melting point than palmitoleate [cis 16:1(Δ9)].(c) α-Linolenate [cis 18:3(Δ9,12,15)] has a higher/lower/equal melting point than oleate [cis 18:1(Δ9)].
Answers
(a) Myristate (14:0) has a higher melting point than stearate (18:0).
(b) Palmitate (16:0) has a higher melting point than palmitoleate [cis 16:1(Δ9)].
(c) α-Linolenate [cis 18:3(Δ9,12,15)] has a lower melting point than oleate [cis 18:1(Δ9)].
In general, the melting point of a fatty acid is influenced by its chain length, degree of unsaturation, and the cis/trans configuration of the double bonds. Shorter chain lengths tend to have lower melting points than longer chain lengths due to decreased intermolecular forces. Saturated fatty acids (without double bonds) generally have higher melting points than unsaturated fatty acids due to increased intermolecular interactions. Within unsaturated fatty acids, increasing the degree of unsaturation (more double bonds) tends to decrease the melting point. Additionally, cis double bonds introduce kinks in the fatty acid chain, preventing close packing and further lowering the melting point.
Using this information, we can make the following conclusions:
(a) Myristate (14:0) has a higher melting point than stearate (18:0). This is because stearate has a longer chain length than myristate, resulting in stronger intermolecular forces and a higher melting point.
(b) Palmitate (16:0) has a higher melting point than palmitoleate [cis 16:1(Δ9)]. The presence of a cis double bond in palmitoleate introduces a kink in the chain, reducing intermolecular interactions and lowering the melting point compared to the saturated palmitate.
(c) α-Linolenate [cis 18:3(Δ9,12,15)] has a lower melting point than oleate [cis 18:1(Δ9)]. α-Linolenate has more double bonds (three) compared to oleate (one), introducing more kinks in the chain and reducing intermolecular interactions. This leads to a lower melting point for α-linolenate.
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If 50 g of potassium nirate is added to 100 g of water at 30degreet celcius how many gram of potassium nirate will not dissolve
Answers
If 50 g of potassium nitrate is added to 100 g of water at 30 degrees Celcius, 30 gram of potassium nitrate will not dissolve.
What is a solubility curve?A solubility curve is a curve that is produced when the amount of solute that dissolves in a given volume of solvent is plotted against the temperature of the solution formed.
A solubility curve can be used to predict the amount of a given solute that will dissolve in a given amount of solvent at a particular temperature.
The solubility curve of potassium nitrate is shown in the attachment.
At 30°C, the solubility of potassium nitrate is 20 g/100 g of water.
Hence, the amount of potassium nitrate that will remain undissolved when 50 g of it is added to 100 g of water at 30°C will be:
Amount left undissolved = 50 - 20 g
Amount left undissolved = 30
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ernest rutherford developed an experiment that showed protons can pass through gold atoms untouched and/or un-deflected. sometimes the protons were deflected by something, but this did not happen too often. most of the atoms pass straight through. his experiment changed the way scientists viewed the structure of an atom. what conclusion did rutherford draw from his experiment?
Answers
Rutherford conclusion was: Inside of the gold atom consists of empty spaces.
Rutherford theorized that atoms have their charge concentrated in a very small nucleus.
This was famous Rutherford's Gold Foil Experiment: he bombarded thin foil of gold with positive alpha particles (helium atom particles, consist of two protons and two neutrons).
Rutherford observed the deflection of alpha particles on the photographic film and notice that most of alpha particles passed straight through foil.
That is different from Plum Pudding model, because it shows that most of the atom is empty space.
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I need help ASAP pls
Answers
Given the standard enthalpy changes for the following two reactions
Given the standard enthalpy changes for the following two reactions:
(1) 2C(s) + 2H2(g)C2H4(g)...... ΔH° = 52.3 kJ
(2) 2C(s) + 3H2(g)C2H6(g)......ΔH° = -84.7 kJ
what is the standard enthalpy change for the reaction:
(3) C2H4(g) + H2(g)C2H6(g)......ΔH° = ?
Answers
The standard enthalpy change for reaction (3) is 117.1 kJ.
The standard enthalpy change for reaction (3) can be calculated by using the enthalpy changes of reactions (1) and (2) and applying Hess's Law.
To do this, we need to manipulate the given equations so that the desired reaction (3) can be obtained.
First, we reverse reaction (1) to get the formation of C2H4(g) from C2H6(g):
C2H4(g)C2H6(g) ΔH° = -52.3 kJ
Next, we multiply reaction (2) by 2 and reverse it to obtain 2 moles of C2H6(g) reacting to form 3 moles of H2(g):
2C2H6(g)2C(s) + 3H2(g) ΔH° = 169.4 kJ
Now, we add the two modified equations together:
C2H4(g)C2H6(g) ΔH° = -52.3 kJ
2C2H6(g)2C(s) + 3H2(g) ΔH° = 169.4 kJ
When adding these equations, the C2H6(g) on the left side cancels out with the C2H6(g) on the right side, leaving us with the desired reaction (3):
C2H4(g) + H2(g)C2H6(g) ΔH° = -52.3 kJ + 169.4 kJ = 117.1 kJ
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Why is it important to plants and animals that photosynthesis occurs?
Answers
if an object has a density of 0.5 g/ml and it is placed in a solution with a density of 2.5 g/ml, what percent of the object will be submerged?
Answers
The percent of the object submerged in the solution is 20%, determined by comparing the densities of the object and the solution.
To determine the percent of the object that will be submerged, we can compare the densities of the object and the solution.
The percent of the object submerged can be calculated using the formula:
Percent submerged = (Density of object / Density of solution) * 100
In this case, the density of the object is 0.5 g/ml and the density of the solution is 2.5 g/ml. Substituting these values into the formula:
Percent submerged = (0.5 g/ml / 2.5 g/ml) * 100 = 0.2 * 100 = 20%
Therefore, 20% of the object will be submerged in the solution.
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Which of the chemicals in the following chemical reaction is the acid?
HCO3- + H20 -->CO3^2- +H30+
A.) HCO3-
B.) co3²-
C.) H30+
D.) H20
Answers
A) HCO3- , carbonic acic
Why is light helpful? You can just give one reason
Answers
Answer:
to give off positive vibes <3
Explanation:
a solution made from ethanol (c2h5oh) and water is 2.68 m. how much c2h5oh is contained per 297 g of water?
Answers
The solution contains 2.68 m (mol/L) of C2H5OH (ethanol) per 297 g (mL) of water. To calculate the amount of C2H5OH (ethanol) contained per 297 g of water, you need to use the molar mass of C2H5OH (ethanol). The molar mass of C2H5OH is 46 g/mol.
Therefore, the amount of C2H5OH (ethanol) contained in 297 g (mL) of water is:
2.68 m (mol/L) x 46 g/mol = 123.28 g/L (or 123.28 g/mL)
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A sample of what was thought to be gold was removed from a mine in San Francisco during the gold rush. After analysis, it was determined that it was actually fool's gold, or pyrite. The sample contained 17.6 grams of iron and 103 grams of sulfur. What is the percentage composition of each element in pyrite?
Answers
Answer:
14.594% Iron and 85.406% Sulfur
Explanation:
103g (S) + 17.6g (Fe) = 120.6g total mass
103/120.6 × 100 = 85.406% Sulfur
17.6/120.6 × 100 = 14.594% Iron
Calculate the volume of an object with dimensions measuring: 3.0cm x 4.0cm x 1.0cm
Answers
Answer:
12cm^3
Explanation:
Just multiply each of the given dimension.
= 3.0 × 4.0 × 1.0
= 3 × 4 × 1
= 12
Answer:
12cm cubed
Just multiply 3, 4, and 1
Na2O + H2O => NaOH *
Your answer
Balancing equations only the coefficient ratios
Answers
Answer:
1, 1, 2
Explanation:
You need to have the same amount of atoms of everything element on both the products and reactants side
Reactants:
Na=2
O=2
H=2
Products:
Na=2
O=2
H=2
A refrigeration system reaches operational balance when the number of vapor molecules that condense into liquid equals the number of vapor molecules that the compressor pumps into the condenser.
a. True
b. False
Answers
In refrigeration, the refrigerant is a substance that absorbs heat from the surrounding and dissipates it to produce cooling. The correct option is a. True.
What is thermal balance?
The thermal balance in a refrigeration system is achieved when the system has reached a stable state, that is, the amount of heat absorbed by the refrigerant is equal to the heat rejected by the refrigeration system. During the compression process, the refrigerant is compressed and pumped into the condenser where it undergoes condensation, i.e., it changes from a gas to a liquid by releasing heat.
In the condenser, the refrigerant rejects the heat that it absorbed in the evaporator and releases it to the surrounding. The condensation process reduces the number of vapor molecules in the refrigerant, which leads to an increase in the number of liquid molecules.
Therefore, the number of vapor molecules that condense into liquid equals the number of vapor molecules that the compressor pumps into the condenser. This is because the compressor has to maintain a constant flow of refrigerant in the refrigeration system to achieve thermal balance.
Hence, the statement is a) true.
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hii pls help me!!
even if u know how to do one, it's okk
anything helps
Answers
Explanation:
a) HNO2(aq) = HNO3(aq) + H2O(l) +NO(g)
b) SoCl2 (l) + H2O (l) = So2(g) + 2HCl(aq)
c) CH4 (g) + 2O2(g) = Co2 (g) + 2H2O(g)
d) 3CuO(s) + 2NH3 (g) = 3Cu(s) + 3H2O (l) + N2(g)
A sample of an ideal gas at 1.00 atm and a volume of 1.73 L was placed in a weighted balloon and dropped into the ocean. As the sample descended, the water pressure compressed the balloon and reduced its volume. When the pressure had increased to 70.0 atm, what was the volume of the sample
Answers
Answer:
Volume is 0.0247L
Explanation:
This question involves the use of Boyle's law which states that the volume of a given mass of gas is inversely proportional to it's pressure provided that temperature remains constant.
Mathematically,
v = k/p
K = VP
P1V1 = P2V2 = P3V3 = .........=PnVn
V = volume
p = pressure
Data;
P1 =1.0atm
V1 = 1.73L
P2 = 70atm
V2 = ?
P1V1 = P2V2
V2 = P1V1 / P2
V2 = (1.0×1.73)/70
V2 = 0.0247L
The volume of the sample is 0.0247L
Choosing location in supply chain is
1) one of the main strategic decisions
2) Depending on demand & supply forecasting
3) Aggregate planning & inventory management
4) All of the above.
Answers
Choosing location in supply chain is 4) All of the above.
Choosing location in the supply chain is one of the main strategic decisions that organizations have to make, itt depends on various factors such as demand and supply forecasting, aggregate planning, and inventory management. An appropriate location enables the firms to provide quality goods and services at the right time and place. The location strategy should consider several factors such as proximity to suppliers, customers, labor availability, transportation, etc.The location decision is important for the success of a business as it affects the cost of production, customer service, and market responsiveness. When a location is chosen, it affects the transportation and inventory cost.
Therefore, firms should consider the tradeoffs between the inventory carrying cost and the transportation cost when choosing a location. For instance, a firm may decide to locate closer to the customers to reduce the transportation cost but will have to incur higher inventory carrying cost due to the storage facilities. Hence, organizations need to carefully choose the best location in the supply chain that meets the needs of their customers and ensures their long-term success. Hence, the correct option is 4) All of the above.
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Which, if any, of the following aqueous mixtures would be a buffer system?
A. HSO4–, HSO3–
B. H2CO3, HCO3–
C. H2PO4–, HCO3–
D. CH3COOH, NaH2PO4
E. None of these choices are correct.
Answers
The correct answer is B. H2CO3, HCO3–.
A buffer system is a solution that can resist changes in pH when small amounts of acid or base are added to it. It consists of a weak acid and its conjugate base (or a weak base and its conjugate acid) in roughly equal concentrations.
In option B, H2CO3 (carbonic acid) is a weak acid, and HCO3– (bicarbonate ion) is its conjugate base. When a small amount of acid is added to this solution, the bicarbonate ion can accept the excess hydrogen ions, preventing a significant change in pH. On the other hand, when a small amount of base is added, the carbonic acid can release additional hydrogen ions, maintaining the pH within a certain range.
Options A, C, and D do contain weak acids and their conjugate bases, but the concentrations are not roughly equal. In option A, HSO4– (bisulfate ion) is a weak acid, but HSO3– (sulfite ion) is not its conjugate base. In option C, H2PO4– (dihydrogen phosphate ion) is a weak acid, but HCO3– is not its conjugate base. In option D, CH3COOH (acetic acid) is a weak acid, but NaH2PO4 (sodium dihydrogen phosphate) is not its conjugate base.
Therefore, the only correct choice is B. H2CO3, HCO3–, as it contains a weak acid and its conjugate base in approximately equal concentrations, making it a buffer system.
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Is this mixture homogeneous or heterogeneous?
Answers
Answer: it is an heterogeneous mixture
Explanation: it is heterogeneous mixture because the particles in it are not well scattered which causes layers to form in the mixture
Which element would you expect to be more reactive: phosphorus (P) or fluorine (F)
Answers
Answer:
Fluorine
Explanation:
Fluorine is the most electronegative element because it has 5 electrons in it's 2P shell.
Fluorine is the most reactive nonmetal and the most electronegative element in the periodic table, and hence it is the strongest oxidizing agent. Therefore, fluorine is more reactive than phosphorus.
What is fluorine ?The chemical element fluorine has an atomic number of 9 and the symbol F. The lightest halogen, it is an extremely poisonous, pale yellow diatomic gas under normal conditions. It is exceedingly reactive and reacts with all other elements, except the light inert gases, making it the most electronegative reactive element.
Of all the halogens, fluorine has the smallest atomic size. The nuclear attraction is therefore highest for the furthest electrons. Fluorine is the most reactive of the halogens.
Due to the angular strain in the P4 molecule, where the angles are only 60 degrees, white phosphorus is less stable and hence more reactive than the other solid phases under typical circumstances. White phosphorus is far more reactive than red phosphorus.
Thus, fluorine is more reactive than phosphorus.
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What location is 90 degrees away from the equator?
A) The south pole
B) Polaris
C) Both A & B
D) The north pole
Answers
Each parallel measures one degree north or south of the Equator, with 90 degrees north of the Equator and 90 degrees south of the Equator
Hope this helps!
In double replacement reactions, why will two metals not combine with each other when products are
formed?
A metals form negative ions and like charges attract
B metals form positive ions and like charges do not attract
Cmetals form negative ions and like charges do not attract
D metals form positive ions and like charges attract
Answers
In double replacement reactions, two metals not combine with each other when products are formed because, metals form negative ions and like charges attract. Therefore, option A is correct.
What is metal ?A metal is a substance that exhibits a shiny appearance when freshly processed, polished, or shattered, and conducts electricity and heat rather well. Generally speaking, metals are malleable and ductile.
We use the (s) symbol for solid because salt is an insoluble substance that will not dissolve in water. The silver, fluoride, potassium, and chloride ions would have effectively moved to a new location if there had been no precipitate formation, but they would still be floating around as ions. In this instance, nothing happens.
When two ionic compounds exchange ions and create two new ionic compounds, this is known as a double replacement reaction.
Thus, option A is correct.
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A sample of water is heated from 10 °C to 50 °C using 286 J of energy. What is the mass of water that was heated? help
Answers
Answer:
Mass of water == 1.71 g
Explanation:
Given data:
Initial temperature of water = 10°C
Final temperature of water = 50°C
Energy absorbed = 286 J
Mass of water = ?
Solution:
Specific heat capacity:
It is the amount of heat required to raise the temperature of one gram of substance by one degree.
Specific heat capacity of water is 4.18 J/g.°C
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
ΔT = 50°C - 10°C
ΔT = 40°C
by putting values,
286 J = m × 4.18 J/g.°C × 40°C
286 J = m × 167.2 J/g
m = 286 J / 167.2 J/g
m = 1.71 g
A ballon filled with helium a pure substance or a mixture?
Answers
Answer:
Balloon filled with helium is not a mixture because the gas in it consists of solely helium atoms.
Explanation:
Explanation:
An element is a pure substance as well, because if we fill up a balloon with just helium gas, it will only contain helium atoms.