predict which member of the following group is most soluble in water. 4-methylcyclohexanol phenol cyclohexanol

The order of the reaction with respect to a is 2.

Let's understand this in detail:

1. In chemistry, the term rate refers to the speed of a reaction or the speed at which a reaction takes place. The symbol "r usually denotes it."

2. A factor is a numerical quantity that indicates how often one quantity is greater than another. For example, if quantity A is ten times greater than quantity B, we say that quantity A is a factor of ten greater than quantity B.

3. In chemistry, the term order refers to the power of the concentration of reactants in the rate law equation that governs the rate of a chemical reaction. The symbol "n usually represents it."

4. The reaction rate between a and b increases by a factor of 100 when the concentration of a is increased tenfold. So, 100 = (r2/r1) (10)^n

Rearranging the above equation, we get:r2 = 100 × r1 = (10^2) × r1

Putting the value of r2 in the rate law equation, we get: 100 × r1 = k[A]^n [B]^m

When the concentration of a is increased tenfold, the factor by which the reaction rate increases is 100. Therefore, the order of the reaction with respect to a can be calculated as follows:

r2/r1 = (10)^n= 100/1= (10^2)

Therefore, n = 2. Hence, the order of the reaction with respect to a is 2.

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In a TLC experiment, the compound with the larger Rf value will elute faster. In the case of naphthalene and 1-bromonaphthalene, the 1-bromonaphthalene will elute faster and have a larger Rf value.

This is because 1-bromonaphthalene is more polar than naphthalene. Polar compounds have a stronger attraction to the polar stationary phase (such as the silica gel in TLC plates) and will interact more with it, resulting in a lower Rf value.

Naphthalene, on the other hand, is less polar and will have a weaker interaction with the stationary phase, allowing it to travel further and have a higher Rf value.

The polarity of a compound is determined by the presence of functional groups or atoms that create an uneven distribution of charge or electronegativity. In this case, the bromine atom in 1-bromonaphthalene increases its polarity compared to naphthalene, leading to a stronger interaction with the stationary phase.

In summary, the 1-bromonaphthalene will elute faster in a TLC experiment and have a larger Rf value compared to naphthalene due to its higher polarity resulting from the presence of a bromine atom.

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Answer:

A group is a vertical column of elements on the periodic table whereas a period is a horizontal row of elements on the periodic table.

Answer:

sorry bro I Don't understand

Answer:

C₂H6

Explanation:

Among the given options, the formula A) C₂H6 represents a hydrocarbon (specifically, ethane). Option A

A hydrocarbon is a compound that consists of only carbon and hydrogen atoms. It is important to identify the formula that represents a hydrocarbon among the given options:

A) C₂H6: This formula represents ethane, which is a hydrocarbon. Ethane consists of two carbon atoms bonded together with single bonds and six hydrogen atoms.

B) C₂H5OH: This formula represents ethanol, which is not a hydrocarbon. Ethanol contains a hydroxyl group (-OH), indicating the presence of oxygen in addition to carbon and hydrogen atoms. It is an alcohol, not a hydrocarbon.

C) C₂H5Cl: This formula represents ethyl chloride, which is not a hydrocarbon. Ethyl chloride contains a chlorine atom (Cl) in addition to carbon and hydrogen atoms. It is a haloalkane, not a hydrocarbon.

D) C₂H6O: This formula represents ethanol, which, as mentioned before, is not a hydrocarbon. Ethanol contains an oxygen atom (O) in addition to carbon and hydrogen atoms. It is an alcohol, not a hydrocarbon.

Among the given options, the formula A) C₂H6 represents a hydrocarbon (specifically, ethane). It consists only of carbon and hydrogen atoms, making it a suitable representation of a hydrocarbon.

In summary, the formula C₂H6 (option A) represents a hydrocarbon, while the other options contain additional elements (oxygen or chlorine) that make them non-hydrocarbon compounds. Option A

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If 50 g of potassium nitrate is added to 100 g of water at 30 degrees Celcius, 30 gram of potassium nitrate will not dissolve.

A solubility curve is a curve that is produced when the amount of solute that dissolves in a given volume of solvent is plotted against the temperature of the solution formed.

A solubility curve can be used to predict the amount of a given solute that will dissolve in a given amount of solvent at a particular temperature.

The solubility curve of potassium nitrate is shown in the attachment.

At 30°C, the solubility of potassium nitrate is 20 g/100 g of water.

Hence, the amount of potassium nitrate that will remain undissolved when 50 g of it is added to 100 g of water at 30°C will be:

Amount left undissolved = 50 - 20 g

Amount left undissolved = 30

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Ethanol, propane, and butane are all examples of fuels that contain chemical energy. This chemical energy is stored within the molecules of the fuel and can be released during a chemical reaction, such as combustion, to produce heat and/or light energy.

When ethanol, propane, or butane is burned, the chemical bonds between the atoms within the molecule are broken, releasing energy in the form of heat and light. This energy can then be harnessed for various purposes, such as heating buildings or powering vehicles. Overall, the energy content of a fuel depends on the specific molecules it contains and their chemical structures.

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Answer:

c, driving a car

Explanation:

got it right :)

have a nice day!~

Answer:

C. Our eating habits

Hope that helps.

The pyrrole side chain of histidine has a pKa of 6.04. If the pKa values of the carboxyl and a-amino groups are 1.83 and 9.33, respectively, then the net charge on histidine at a pH of 5.0 is +1.

How do we determine the net charge of a molecule?

We can determine the net charge of a molecule by subtracting the total number of negatively charged groups from the total number of positively charged groups.

The amino acid histidine has three groups with pKa values that are important for calculating the net charge at a particular pH. These three groups are as follows:- The carboxyl group, which has a pKa of 1.83.- The α-amino group, which has a pKa of 9.33.- The imidazole side chain, which has a pKa of 6.04.The structure of histidine is given below:

The net charge of histidine at a pH of 5.0 can be calculated by considering each of the ionizable groups.

At pH 5.0, the carboxyl group (pKa = 1.83) is fully protonated (COOH), the α-amino group (pKa = 9.33) is fully deprotonated (NH2), and the imidazole side chain (pKa = 6.04) is partially protonated (NH+).

So, the net charge is the sum of the charges of all ionizable groups. We can see that one of the nitrogen atoms in the imidazole ring of histidine can accept a proton at a pH below its pKa of 6.04. At a pH of 5.0, the pyrrole side chain of histidine will be protonated (NH+).Therefore, at pH 5.0, the net charge on histidine is +1.

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Answer:

D or A

But I do know...

It's because new strains of the virus are constantly appearing and evolving, so the vaccine must change along with them.

Answer:

secondary colours:orange, green and purple.

Answer:

The answer is chlorine

Explanation:

Answer:

green colour is the diffusion of nickel

blue is the sulphate solution

The concentration of original HydroChloric Acid or HCl we say, would be 0.102 M in the starting of Titration.

As the Acid-Base reacts to form water and salts this is an acid-base neutralization displacement reaction.

The reaction goes like :

NaOH + HCl ==> H2O + NaCl

As the reaction shows, that one mole of NaOH reacts with one mole of HCl which means these species react mole to mole and form one mole of Water and one mole of Salt.

Since we're titrating 24.16 ml of 0.106 M NaOH with 25 ml of HCl, the equation balances for 1 : 1 so, we can calculate the concentration of HCl using the following equation :

\(M_{NaOH} * V_{NaOH} = M_{HCl} * V_{HCl}\)

24.16 * 0.106 = x * 25

=> x = 0.102 M

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The factors that affects the emisison energy are the molecular structure and the chemical composition.

Within a molecule, a molecule's atoms can be arranged and bound in precise ways that can affect how energetically dense they are. varying molecules can have varying emission energies because their electronic transitions are connected with different energy levels.

The emission energies of a sample can vary depending on the types of atoms and elements present. For instance, different elements have distinctive emission spectra because of the specific energy levels that go along with their electronic transitions.

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Answer:

300mL

Explanation:

To obtain the volume of water added, let us calculate the volume of the diluted solution.

Data obtained from the question include:

Molarity of stock solution (M1) = 0.15mol/L

Volume of stock solution (V1) = 600mL

Molarity of diluted solution (M2) = 0.1mol/L

Volume of diluted solution (V2) =..?

The volume of the diluted solution can be obtained as follow:

M1V1 = M2V2

0.15 x 600 = 0.1 x V2

Divide both side by 0.1

V2 = 0.15 x 600 / 0.1

V2 = 900mL.

Therefore the volume of the diluted solution is 900mL.

Finally, we can obtain the volume of the water added by calculating the difference in the volume of the diluted solution and that of the stock solution. This is illustrated below:

Volume of stock solution (V1) = 600mL

Volume of diluted solution (V2) = 900mL

Volume of water added =...?

Volume of water added = V2 – V1

Volume of water added = 900 – 600

Volume of water added = 300mL

Therefore, the volume of water added is 300mL

The total pressure of the mixture is 65.5 kPa.

According to Dalton's Law of Partial Pressure,

The partial pressure of gas = Mole fraction of gas × Total pressure

Total Pressure = Sum of all the gases partial pressures

The number of moles of methane is,

\(Moles \: of \: methane \: (16 g/mol) = 337 \: mg \times \frac{1 g}{1000 mg} \times \frac{ 1 mol}{16 g }\)

= 0.021 mols

The moles of methane are 0.021 mols.

The number of moles of the argon,

\(Moles \: of \: argon (40 g/mol) = 148 \: mg \times \frac{ 1 g}{1000 mg } \times \frac{ 1 mol}{40 g} \)

= 0.003 mols

The number of moles of argon is 0.003 mols.

The number of moles of nitrogen is,

\(Moles \: of \: nitrogen (28 g/mol) = 296 \: mg \times \frac{ 1 g}{1000 mg} \times \frac{ 1 mol/}{28 g}\)

= 0.010 mols

The number of moles of nitrogen is 0.010 mols.

The total number of moles is,

= 0.021 + 0.003 + 0.010

= 0.034 mols

\(Mole \: fraction = \frac{ Moles \: of \: solute }{Total \: number \: of \: moles \: of \: soulte \: and \: solvent}\)

\( = \frac{ 0.010 }{ 0.034} \)

= 0.29

\(0.29 \: P _{total} = 19 \: kPa \)

\( P _{total} = \frac{ 19 \: kPa }{0.29}\)

= 65.5 kPa

Therefore, the total pressure of the mixture is 65.5 kPa.

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Answer:

See explanation

Explanation:

Ga is in group 13 hence it must loose three electrons to form Ga^3+ in order to achieve the noble gas configuration because it has three electrons on its outermost shell.

O is in group 16 hence it must accept two electrons in order to attain the noble gas configuration to form O^2- since oxygen has six electrons on its outermost shell.

Br in group 17 has seven electrons in its outermost shell hence it must form Br^- (gain one electron) in order to attain the noble gas configuration.

P in group 15 must accept three electrons and form P^3- in order to attain the noble gas configuration since it has five electrons on its outermost shell.

S is in group 16 hence it must accept two electrons in order to attain the noble gas configuration to form S^2- since sulphur has six electrons on its outermost shell.

Mg in group 2 has two electrons on its outermost shell and must loose both to attain the noble gas configuration forming Mg^2+.

Al is in group 13 hence it must loose three electrons to form Al^3+ in order to achieve the noble gas configuration because it has three electrons on its outermost shell.

Se is in group 16 hence it must accept two electrons in order to attain the noble gas configuration to form Se^2- since selenium has six electrons on its outermost shell.

Lithium is in group 1 and must loose its only outermost electron in order to attain the noble gas configuration to form Li^+.

Rb is in group 1 and must loose its only outermost electron in order to attain the noble gas configuration to form Rb^+.

As in group 15 must accept three electrons and form As^3- in order to attain the noble gas configuration since it has five electrons on its outermost shell.

I in group 17 has seven electrons in its outermost shell hence it must form I^- (gain one electron) in order to attain the noble gas configuration.

Answer:

To much to put so it is in the short picture that will help.

Given parameters:

duration of fall  = 6s

Unknown:

Speed of the rock before it hits the ground  = ?

Solution:

To solve this problem, we apply one of the appropriate motion equations;

           V = u + gt

Where V is the final velocity

           u is the initial velocity

           t is the time taken

           g is the acceleration due to gravity  = 9.8m/s²

The initial velocity is 0;

     So;

              V = gt

Input the parameters and solve for V;

                V = 9.8 x 6  = 58.8m/s

The velocity before hitting the ground is 58.8m/s

On the basis of periodic trends, the element in each pair has the higher first ionization energy is:

a. S

b. Sb

c. N

d. O

Ionization energy refers to the energy required to remove one electron from a neutral atom, forming a positively charged ion. Generally, ionization energy tends to increase from left to right across a period and decrease from top to bottom within a group in the periodic table. Based on these trends, we can determine which element in each pair has the higher first ionization energy:

a. Al or S:

Aluminum (Al) is a metal, while sulfur (S) is a non-metal. Metals generally have lower ionization energies compared to non-metals. Therefore, sulfur (S) would have a higher first ionization energy than aluminum (Al).

b. As or Sb:

Both arsenic (As) and antimony (Sb) are non-metals, and they are located next to each other in the same group (Group 15) of the periodic table. As we move down the group, ionization energy generally decreases. Therefore, antimony (Sb) would have a higher first ionization energy than arsenic (As).

c. N or Si:

Nitrogen (N) and silicon (Si) are also located next to each other in the same group (Group 14) of the periodic table. Similarly, as we move down the group, ionization energy generally decreases. Therefore, nitrogen (N) would have a higher first ionization energy than silicon (Si).

d. O or Cl:

Oxygen (O) and chlorine (Cl) are located in different periods and groups. However, oxygen is in Group 16, while chlorine is in Group 17 of the periodic table. Moving from left to right across a period, ionization energy generally increases. Therefore, oxygen (O) would have a higher first ionization energy than chlorine (Cl).

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Fluorine (F), oxygen (O) and nitrogen (N) are more electronegative as compared to carbon.

Hence, the correct options are options a, b and c.

Electronegativity is basically the chemical property that elaborates the tendency of a particular atom atom or a particular functional group to attract the electrons toward itself. The electronegativity of a particular atom is affected by both its atomic no. as well as the distance between its valence electrons and the charged nuclei.

Fluorine has the oxidation number of -1 and has a very small size due to which it is the most electronegative element in the modern periodic table. The electronegativity of oxygen and nitrogen is greater as compared to carbon as they have greater tendency to attract electrons while carbon has a stable state and therefore it is difficult for it to gain 4 electrons.

--The given question is incomplete, the complete question is

"Which atoms would you consider more electronegative than carbon? Mark all that apply:

a. F

b. O

c. N

d. H"--

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The major difference between potassium channel and the nuclear pore complex is that potassium channel is a single protein but nuclear pore complex is made of large number of different proteins.

A nuclear pore is a component of the vast protein complex known as a nuclear pore complex, which spans the nuclear envelope, the double membrane that encloses the nucleus of eukaryotic cells.

A vertebrate cell's nuclear envelope contains roughly 1,000 nuclear pore complexes (NPCs), while the exact amount varies depending on the cell type and stage of the life cycle. The 110 megadalton (MDa) human nuclear pore complex (hNPC) is a structure. Nucleoporins are the proteins that make up the nuclear pore complex (NPC), which is made up of 34 different nucleoporin proteins and at least 456 different protein components.

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A strong sharp signal at 1715 cm-1 on an FTIR spectrum indicates the presence of a carbonyl functional group.

An FTIR spectrum provides information about the types of functional groups present in a molecule. A strong, sharp signal at 1715 cm-1 is indicative of the presence of a carbonyl functional group, which is characterized by the C=O bond stretching vibration. A carbonyl functional group is present in compounds such as aldehydes, ketones, carboxylic acids, and esters. The position of the carbonyl group in a molecule can also be determined by analyzing the FTIR spectrum.

For example, in an aldehyde, the carbonyl group will be located at the end of the carbon chain, while in a ketone, the carbonyl group will be located within the carbon chain. Therefore, by analyzing the FTIR spectrum of a sample, the type and location of the carbonyl functional group can be identified, which provides valuable information about the sample's chemical structure and properties.

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The notation for the enthalpy of the solution is ∆Hsol. The correct answer is option ∆Hsol.

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