Prana has a savings account and a chequing

account with a total balance of $85.

His parents doubled the amount in each

account and the new total balance is $170.

How much money does Prana have in each

account?

Answer:

  B. On Monday, Huang withdraws $30 from a bank account. On Friday, he deposits $30 into the account.

Step-by-step explanation:

You want to identify the situation that results in 0 net change.

To make zero, we can add opposite values.

  A  +10 -15 = -5 . . . not zero

  B  -30 +30 = 0 . . . . the situation of interest

  C  -25 -25 = -50 . . . not zero

  D  15 -10 = 5 . . . not zero

Choice B describes a situation with a net change of zero.

__

Additional comment

One needs to be careful with banking. Withdrawing $30 from an account that has less than $30 in it may result in an overdraft charge, causing the net change to be the amount of that overdraft charge. We'd rather see this scenario described as deposing $30 before the $30 withdrawal is made.

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Answer: Rational number

So the total number of 40-kilogram crates that can be loaded into the shipping container is x < 355

Let x be the number of 40-kilogram crates that can be loaded into the shipping container. We can write the following inequality:

40x + 10800 < 25000

This inequality states that the total weight of the crates (40x) plus the weight of the other shipments (10800 kilograms) must be less than the maximum weight that can be loaded into the container (25000 kilograms).

Solving for x, we get:

40x < 25000 - 10800

40x < 14200

x < 355

So the total number of 40-kilogram crates that can be loaded into the shipping container is x < 355.

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Answer:

12

Step-by-step explanation:

20*2= 40 cookies per hour,

she is working 6 hours so she sells 240 cookies total

240-(38*6) = 12

Nadya bakes 20 cookies every half hour. Vasil sells 38 cookies per hour. 12 cookies that are left unsold and if they work from 6:00 am till noon.

The unitary method is a method for solving a problem by the first value of a single unit and then finding the value by multiplying the single value.

Nadya bakes 20 cookies every half hour. Vasil sells 38 cookies per hour.

We need to find many cookies that are left unsold and if they work from 6:00 am till noon.

20 x 2= 40 cookies per hour,

she is working 6 hours so she sells 240 cookies

The total

= 240 - (38 x 6)

= 12

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==========================================================

Explanation:

The term "zero" is the same as "root".

The root of f(x) is found by replacing f(x) with 0 and solving for x.

f(x) = 4x-20

0 = 4x-20

0+20 = 4x

20 = 4x

4x = 20

x = 20/4

x = 5

The root of f(x) is 5. If you plugged in x = 5, then you'll land on f(5) = 0.

Your teacher then wants to know what value of k will have g(x) get the same root of 5. In other words, we need to find k that will allow g(5) = 0.

We'll replace g(x) with 0 and plug in x = 5. Solving for k leads to...

g(x) = -0.5x+k

0 = -0.5*5+k

0 = -2.5+k

0+2.5 = k

2.5 = k

k = 2.5

k = 5/2

Answer:

C

Step-by-step explanation:

To find the zero of f(x) , let f(x) = 0 , that is

4x - 20 = 0 ( add 20 to both sides )

4x = 20 ( divide both sides by 4 )

x = 5 ← is the zero of f(x)

To find the zero of g(x) , let g(x) = 0 , that is

- \(\frac{1}{2}\) x + k = 0 ( multiply through by 2 to clear the fraction )

- x + 2k = 0 ( subtract 2k from both sides )

- x = - 2k ( multiply both sides by - 1 )

x = 2k ← is the zero of g(x)

Equating the 2 zeros

2k = 5 ( divide both sides by 2 )

k = \(\frac{5}{2}\) → C

Regarding the exponential function y = 3(2)^x, we have that:

An exponential function is defined as follows:

y = ab^(x/n).

In which the parameters are defined as follows:

The function for this problem is given as follows:

y = 3(2)^x.

Hence the parameters are given as follows:

At x = 3, the numeric value of the function is obtained as follows:

y = 3 x 2^3

y = 3 x 8

y = 24.

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Answer:y =  y = -7x

Step-by-step explanation: y - 14 = -7(x - (-2))

y - 14 = -7x - 14

Answer: y=2x+4 for parallel and y=-1/2x+1 1/2

Step-by-step explanation: you need to do an equation using the slope which you can find by using y2-y1/x2-x1

from there you have to use y-y1=m(x-x1)

Answer:

1-nonlinear

2-linear

3-linear

4-6.2

5-C

Step-by-step explanation:

You need to find 84% of 4200 to get the amount of students.  First change the percent to a decimal, and multiply 0.84 x 4200.

There were 3528 total students at the theater.

Answer: inverse variation; k = 2

Step-by-step explanation:

y = k/x graph (inverse variation)

lets just plug 1 into x,

x = 1, y = k / 1 = k

in the graph. y = 2 when x = 1,

=> k = 2

Answer: D

Step-by-step explanation: An inverse variation of two variable in which if one of the variable increases, then the other variable decreases at the same rate.

The area of the circle is 201 m².

So, the area of the circle:

We know that 4a = 2πr, now calculate r as follows:

Rounding off: 8m

Area of circle:

Rounding off: 201 m²

Therefore, the area of the circle is 201 m².

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The intersection of both intervals i.e., the interval [0, −4] and the inequality is valid for all values of k belonging to the interval [0, −4].

The statement is written as: 2k + 6 ≥ 12 / (2 + 2k)

The first step is to simplify the right-hand side of the equation: 12 / (2 + 2k) = 6 / (1 + k)

Thus the given inequality becomes:2k + 6 ≥ 6 / (1 + k)

Now, multiplying both sides of the inequality by 1 + k,

we get :2k(1 + k) + 6(1 + k) ≥ 6

We can further simplify the above inequality by expanding the brackets: 2k² + 2k + 6k + 6 ≥ 62k² + 8k ≥ 0

We can then factorize the left-hand side of the inequality:2k(k + 4) ≥ 0

Thus, either k ≥ 0 or k ≤ −4 are possible. The inequality 2k + 6 ≥ 12 / (2 + 2k) is valid for all values of k belonging to the interval [−4, 0] or to the interval (0, ∞).

Hence, we have to consider the intersection of both intervals i.e., the interval [0, −4]. Therefore, the inequality is valid for all values of k belonging to the interval [0, −4]. The above explanation depicts that Twice and number, k, added to 6 is greater than or equal to the quotient of 12 and 2 added to the number, k doubled for all values of k belonging to the interval [0, −4].

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To find the value of the daily salary (X) such that 25% of the daily salaries are greater than X, we need to find the corresponding z-score using the standard normal distribution.

First, we convert the given percentage to a z-score. Since we want the upper 25% (greater than X), the corresponding z-score is the value that leaves 25% in the lower tail. Using a standard normal distribution table or a calculator, the z-score corresponding to 25% is approximately 0.674.

Next, we use the formula for z-score conversion: z = (X - μ) / σ, where μ is the mean and σ is the standard deviation. Plugging in the given values, we have 0.674 = (X - 70) / 10.

Solving for X, we get X = 0.674 * 10 + 70 = 6.74 + 70 = 76.74.

Rounding to one decimal place, the value of the daily salary X is approximately 76.7 JD. Therefore, option 3, 76.7 JD, is the correct answer.

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Answer:

100

Step-by-step explanation:

if you are doing this you need to do 50x2 which in this case equals = 100

Answer:

false

Step-by-step explanation:

Answer:

I guess its 0.4

Step-by-step explanation:

Divide 2by 5

Answer:

\textcolor{#B14BA5}{5x}\textcolor{#B14BA5}{-5x}-10

5

−

5

−

1

0

-10

−

1

0

Answer:

Step-by-step explanation:

5x^2 - 5x - 10

factor out the 5

5 (x^2 - x -2 )

note how the 5 doesn't make any difference for our question.

now use  FOIL , know it?

First, Outside, Inside,  Last

(X ± ? ) * ( X ± ? )

we want that above form.  

(X+1) * (X - ? )

hmm

(X+1) * (X -2)  

that looks like it would work

now just put the 5 back on

5*{(X+1)*(X-2)}

there it is  :)

Given information:Position of a particle moving along the x-axis varies in time according to the expression x = 3t², where x is in meters and t is in seconds.

To determine the position at the following times. a. t = 3.30 s, b. t = 3.30 s + Δt xf and c. Evaluate the limit of Δx/Δt as Δt approaches zero to find the velocity at t = 3.30 s. a. To find the position when t = 3.30 s, substitute t = 3.30 s in x = 3t².x = 3t² = 3(3.30)² = 32.67 metersTherefore, the position at t = 3.30 s is 32.67 meters.

b. To find the position when t = 3.30 s + Δt, substitute t = 3.30 s + Δt in x = 3t².x = 3t² = 3(3.30 s + Δt)² = 3(10.89 + 6.6Δt + Δt²) = 32.67 + 19.8Δt + 3Δt²Therefore, the position when t = 3.30 s + Δt is 32.67 + 19.8Δt + 3Δt².c. Velocity is given by Δx/Δt.Δx/Δt = [x(t + Δt) - x(t)]/ΔtBy substituting the given values, we have;Δx/Δt = [x(3.30 + Δt) - x(3.30)]/Δt= [3(3.30 + Δt)² - 3(3.30)²]/Δt= 19.8 + 6ΔtTaking the limit of Δx/Δt as Δt → 0, we have;Δx/Δt = 19.8 + 6(0)Δt = 19.8Therefore, the velocity at t = 3.30 s is 19.8 m/s.

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Ground-state electron configuration of gas-phase Co²+ is [Ar] 3d⁷. Answer: (E) [Ar] 3d⁷.Explanation: First of all, we need to find the electron configuration of Cobalt (Co).

The electron configuration of Cobalt (Co) is 1s²2s²2p⁶3s²3p⁶4s²3d⁷.Now, we can remove the electrons to get the electron configuration of gas-phase Co²+ .Co: 1s²2s²2p⁶3s²3p⁶4s²3d⁷Co²+: 1s²2s²2p⁶3s²3p⁶3d⁷The full electron configuration of Co²+ will be [Ar] 3d⁷. Therefore, the answer is (E) [Ar] 3d⁷.

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Answer:

Step-by-step explanation:

To be honest I would help but I can't. Although the question looks familiar

The answer is ,  the Taylor series (centered at c=0) for the function f(x) = e^(4x) is given by:

\($$\large f(x) = \sum_{n=0}^{\infty} \frac{4^n}{n!}x^n$$\)

The Taylor series expansion is a way to represent a function as an infinite sum of terms that depend on the function's derivatives.

The Taylor series of a function f(x) centered at c is given by the formula:

\(\large f(x) = \sum_{n=0}^{\infty} \frac{f^{(n)}(c)}{n!}(x-c)^n\)

Using the definition of Taylor series to find the Taylor series (centered at c=0) for the function f(x) = e^(4x), we have:

\(\large e^{4x} = \sum_{n=0}^{\infty} \frac{e^{4(0)}}{n!}(x-0)^n\)

\(\large e^{4x} = \sum_{n=0}^{\infty} \frac{4^n}{n!}x^n\)

Therefore, the Taylor series (centered at c=0) for the function f(x) = e^(4x) is given by:

\($$\large f(x) = \sum_{n=0}^{\infty} \frac{4^n}{n!}x^n$$\)

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The Taylor series for f(x) = e^(4x) centered at c = 0 is:

f(x) = 1 + 4x + 8x^2 + 32x^3/3 + ...

To find the Taylor series for the function f(x) = e^(4x) centered at c = 0, we can use the definition of the Taylor series. The general formula for the Taylor series expansion of a function f(x) centered at c is given by:

f(x) = f(c) + f'(c)(x - c) + f''(c)(x - c)^2/2! + f'''(c)(x - c)^3/3! + ...

First, let's find the derivatives of f(x) = e^(4x):

f'(x) = d/dx(e^(4x)) = 4e^(4x)

f''(x) = d^2/dx^2(e^(4x)) = 16e^(4x)

f'''(x) = d^3/dx^3(e^(4x)) = 64e^(4x)

Now, let's evaluate these derivatives at x = c = 0:

f(0) = e^(4*0) = e^0 = 1

f'(0) = 4e^(4*0) = 4e^0 = 4

f''(0) = 16e^(4*0) = 16e^0 = 16

f'''(0) = 64e^(4*0) = 64e^0 = 64

Now we can write the Taylor series expansion:

f(x) = f(0) + f'(0)(x - 0) + f''(0)(x - 0)^2/2! + f'''(0)(x - 0)^3/3! + ...

Substituting the values we found:

f(x) = 1 + 4x + 16x^2/2! + 64x^3/3! + ...

Simplifying the terms:

f(x) = 1 + 4x + 8x^2 + 32x^3/3 + ...

Therefore, the Taylor series for f(x) = e^(4x) centered at c = 0 is:

f(x) = 1 + 4x + 8x^2 + 32x^3/3 + ...

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Answer:

The value of x is 11.5

Step-by-step explanation:

Here, we want to find the value of x

Since Q bisects PR, it means it divides PR into ii equal angles

Thus PR = PQ

28 = 2x + 5

2x = 28-5

2x = 23

x = 23/2

x = 11.5

A polynomial can have as many real zeros as its degree, hence one with three degrees can have as many as three zeros.

The roots of an equation are the solution of that equation since an equation consists of hidden values of the variable to determine them by different processes and then the resultant is called roots.

A polynomial with n degrees can have as many variables as n in total.

For example, a quadratic equation ax² + bx + c = 0 is a two-degree equation so it has a maximum of two roots or zeros.

A polynomial with the given degree structure will have exactly 3 roots because it has 3 degrees.

Hence "The maximum number of real zeros in a polynomial will be same as its degree thus 3 degrees will have 3 zeros".

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The range would be the most appropriate measure of spread in this case because it takes into account the extreme values of $300 and $1,300 and provides a clear measure of the difference between them.

To measure the amount of money college students spend on rent per month, the most appropriate measure of spread would be the range. The range is the simplest measure of spread and is calculated by subtracting the lowest value from the highest value in a data set. In this case, the range would be $1,300 - $300 = $1,000.

The median would not be the best choice in this scenario because it only represents the middle value in a data set. It does not take into account extreme values like the $1,300 rent expense.

Standard deviation would not be the most appropriate measure of spread in this case because it calculates the average deviation of each data point from the mean. However, it may not accurately represent the spread when extreme values like the $1,300 rent expense are present.

The interquartile range (IQR) would not be the best choice either because it measures the spread of the middle 50% of the data set. It does not consider extreme values and would not accurately represent the range of rent expenses in this scenario.

In summary, the range would be the most appropriate measure of spread in this case because it takes into account the extreme values of $300 and $1,300 and provides a clear measure of the difference between them.

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Answer:

3 gallons a minute

Step-by-step explanation:

when you begin filling the tub it only needs 15 additional gallons until it's full

if it takes 5 minutes then the rate at which the tub if filling is 3 gallons per minute

The standard equation for the given situation of the bathtub is w = 5t + 12.

The standard equation to model this linear situation:

w = 5t + 12

where:

w is the number of gallons of water in the bathtub after t minutes

5 is the rate at which the bathtub is being filled (in gallons per minute)

12 is the initial number of gallons of water in the bathtub

To come up with this equation, we know that the bathtub holds 32 gallons of water and initially contains 12 gallons of water. We also know that after 5 minutes, the bathtub is full. This means that in 5 minutes, 32 - 12 = 20 gallons of water were added to the bathtub. Since the bathtub is being filled at a constant rate, we can assume that this rate of 20 gallons per 5 minutes is also the rate at which the bathtub is being filled at any other time.

We can now plug these values into the standard equation for linear relationships:

w = rt + b

where:

w is the dependent variable (the number of gallons of water in the bathtub)

r is the slope of the line (the rate at which the bathtub is being filled)

b is the y-intercept (the initial number of gallons of water in the bathtub)

In this case, we have:

w = 20t + 12

This equation models the linear relationship between the number of gallons of water in the bathtub and the number of minutes it has been filling.

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Correct Question:

A bathtub that holds 32 gallons of water contains 12 gallons of water. You begin filling it, and after 5 minutes the tub is filled. Write a standard equation.

Answer:

-8/9z - 3

Step-by-step explanation:

Answer:

(-8/9)z-3=(blank)

Step-by-step explanation:

((5/9)-(6/9)-(7/9))z+3-6= (-8/9)z-3

you get -8/9 by taking 5 and subtracting the 6 and 7 from it since they have the same denominators

Answer:

I don't see any answer choices or models, so I will tell you that 60% can also be written as 6/10 and 3/5. Whichever model or answer choice represents 3/5 is the correct answer.

Answer: that 60% can also be written as 6/10 and 3/5. Whichever model or answer choice represents 3/5 is the correct answer.

Step-by-step explanation:

hope you help

Answer:

Step-by-step explanation:

x-.20x

Lets say the hat cost $100

x=100

multiplying 100 by 20% which is .20 yields $20

S0 $20 is the discount which we subtract from the original price

100-20 and get the sale price of $80

They use a shortcut so you don't have to do the subtracting of the discount

They say if the price is being discounted subtract the discount from 1 and multiply that by the original amount

So in this case the discount percent was 20% = .20

Subtracted from 1

1-.20=.80

Since x is the original price we multiply x by the .80 to get  

.80x