Answer:
To estimate the enthalpy change for Equilibrium 1, we need to calculate the bond energies for the reactants and products of the reaction and use them to determine the change in enthalpy.
The bond energies for the reactants of Equilibrium 1 are:
C2H4(g): 412 kJ/mol
Cl2(g): 243 kJ/mol
The bond energies for the products of Equilibrium 1 are:
C2H4Cl2(g): 575 kJ/mol
We can use these bond energies to calculate the enthalpy change for Equilibrium 1 as follows:
ΔrH = [C2H4Cl2(g)] - ([C2H4(g)] + [Cl2(g)])
ΔrH = 575 kJ/mol - (412 kJ/mol + 243 kJ/mol)
ΔrH = 120 kJ/mol
Therefore, the enthalpy change for Equilibrium 1 is approximately 120 kJ/mol.
For Equilibrium 2, the bond energies for the reactants are:
C2H4Cl2(g): 575 kJ/mol
The bond energies for the products are:
C2H3Cl(g): 328 kJ/mol
HCl(g): 432 kJ/mol
We can use these bond energies to calculate the enthalpy change for Equilibrium 2 as follows:
ΔrH = ([C2H3Cl(g)] + [HCl(g)]) - [C2H4Cl2(g)]
ΔrH = (328 kJ/mol + 432 kJ/mol) - 575 kJ/mol
ΔrH = -215 kJ/mol
Therefore, the enthalpy change for Equilibrium 2 is approximately -215 kJ/mol.
Pure sodium metal explodes when it makes contact with water. In its natural state, chlorine is a deadly, poisonous gas. When these two chemicals combine, they form a harmless, white powder known as sodium chloride or table salt. Which of the following statements does this information support?
A.
Heat must be added in order to change the chemical properties of substances.
B.
When substances are chemically combined, the properties of the new substances that are formed are often different from the properties of the original substances.
C.
The properties of substances change during chemical reactions but then later go back to their original condition.
D.
When substances are chemically combined, the properties of the new substances that are formed are the same as the properties of the original substances.
Answer:
B) "When substances are chemically combined, the properties of the new substances that are formed are often different from the properties of the original substances."
Explanation:
From the information given, the question was juxtaposing how dangerous the reactants Sodium and Chlorine were at their elemental, natural states with how harmless the product is by combining both of them. There isn't any other statement beside B which is supported by this.
Usually however, most reactions that make NaCl are done through acid-base titrations because they form the salt and water when neutralized.
Answer:
B
Explanation:
All substances have their own unique chemical and physical properties. When substances are chemically combined (i.e., when substances undergo a chemical reaction), the properties of the new substances that are formed are often different from the properties of the original substances.
Consider the following chemical reaction:
C(s)+H2O(g)→CO(g)+H2(g)
How many liters of hydrogen gas are formed from the complete reaction of 1.07 mol of C? Assume that the hydrogen gas is collected at a pressure of 1.0 atm
and a temperature of 317 K.
Express your answer using two significant figures.
Answer: 27.85 L
Explanation:
Ideal gas law
V = nRT/P
V = 1.07 X 0.0821 X 317 / 1= 27.85 L
How many molecules of acetylene (C2H2) are in 1.79 moles of acetylene
The simplest alkyne chemical molecule, known as acetylene chemically, is C2H2. Ethyne, Narcy Len, and Vinylene are other names for acetylene.
C2H2 has how many moles?Two. C2H2 molecules contain 2 carbon atoms each. As a result, there are 2 moles of carbon atoms in every mole of C2H2. You may determine how many moles of an element there are in one mole of a compound by looking at the subscripts in any formula.
The C2H2 chemical formula
Acetylene has the extended chemical formula CHCH and the chemical formula C2H2. Acetylenes' molar mass can be expressed as 26.04 g/mol-1.
Grams Acetylene = 46.60673120000018
Mol = 1.79.
C2H2 molecule
Acetylene, C2H2 / Formula is below.
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Which is the best example for genetic diversity?
Answer:
Genetic Diversity Examples
Different breeds of dogs. ...Different varieties of rose flower, wheat, etc.There are more than 50,000 varieties of rice and more than a thousand varieties of mangoes found in India.Genetic diversity is the total number of genetic characteristics in the genetic makeup of a species, it ranges widely from the number of species to differences within species and can be attributed to the span of survival for a species.
Explanation:
i hope this helps u.
A 20.0L container holds 0.650 mol of He gas at 37.0C at a pressure of 628.3torr. The new pressure inside the container will be _______ torr if the volume is reduced to 12.0L, the temperature increased to 177C, and 1.25 mol of additional He gas was added.
Answer:
2918.4 torr
Explanation:
From;
PV=nRT
We have that the new conditions of the gas are;
V = 12.0 L
T1 = 177 + 273 = 450 K
n = 1.25 mol
R= 0.082 atm LK-1mol-1
P= ?
P = nRT/V
P = 1.25 * 0.082 * 450/12.0
P = 3.84 atm
Since
1 atm = 760 torr
3.84 atm = 3.84 * 760 = 2918.4 torr
I need help I don’t understand this is hitting
Reagents that are entirely consumed by a chemical reaction are known as limiting reagents.
Thus, They are additionally known as limiting reactants or limiting agents. A predetermined quantity of reactants are necessary for the reaction to be completed, according to the stoichiometry of chemical reactions.
In the aforementioned reaction, 2 moles of ammonia are created when 3 moles of hydrogen gas react with 1 mole of nitrogen gas.
In most cases, this reactant dictates when the reaction will end. The reaction stoichiometry can be used to determine the precise quantity of reactant that will be required to react with another element. The limiting agent is determined by the mole ratio rather than the mass of the reactants.
Thus, Reagents that are entirely consumed by a chemical reaction are known as limiting reagents.
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How many grams are in 87.37e26 atoms of (NH4)2SO4?
Answer
1917149.087 grams of (NH₄)₂SO₄ are in 87.37 x 10²⁶ atoms of (NH₄)₂SO₄.
Explanation
Given that:
The number of atoms of (NH₄)₂SO₄ = 87.37 x 10²⁶ atoms
What to find:
To find the grams of (NH₄)₂SO₄ in 87.37 x 10²⁶ atoms of (NH₄)₂SO₄.
Step-by-step solution:
Step 1: Convert 87.37 x 10²⁶ atoms of(NH₄)₂SO₄ to moles.
Conversion factor: One mole of a substance will contain 6.022 × 10²³ atoms of that substance
\(\begin{gathered} 1\text{ }mole\left(NH₄\right)₂SO₄=6.022×10²³\text{ }atoms \\ \\ x=87.37×10²⁶\text{ }atoms \\ \\ x=\frac{87.37×10²⁶\text{ }atoms}{6.022×10²³\text{ }atoms}\times1\text{ }mole\left(NH₄\right)₂SO₄ \\ \\ x=14508.46895\text{ }mol\left(NH₄\right)₂SO₄ \end{gathered}\)Step 2: Convert 14508.46895 moles of (NH₄)₂SO₄ to grams.
Using the molar mass of (NH₄)₂SO₄ = 132.14 g/mol and the mole formula below, the grams of (NH₄)₂SO₄ can be determined as follows:
\(\begin{gathered} Moles=\frac{Mass}{Molar\text{ }mass} \\ \\ Mass=Moles\times Molar\text{ }mass \\ \\ Mass\text{ }of\text{ }\left(NH₄\right)₂SO₄=14508.46895\text{ }mol\times132.14\text{ }g\text{/}mol \\ \\ Mass\text{ }of\text{ }\left(NH₄\right)₂SO₄=1917149.087\text{ }g \end{gathered}\)Therefore, 1917149.087 grams of (NH₄)₂SO₄ are in 87.37 x 10²⁶ atoms of (NH₄)₂SO₄.
Fossil fuels are clean-burning fuels. true or false
Answer:
Energy cannot be converted from one form to another.
Answer:
false
Explanation:
Fossils fuels are actually polluting the atmosphere therefore, it can not be a clean-burning fuel.
How many grams of Aluminum Sulfate do you have if you have 2.837x10^26 atoms of Sulfur?
Apparently, the right answer is 5.373x10^4, but I do not know how to get there, please help.
The mass of Aluminum Sulfate is 5.373 grams if you have \(2.837*10^{26\) atoms of Sulfur .
The molecular formula of Aluminum Sulfate is \(Al_2(SO_4)_3.\) In one molecule of aluminum sulfate, there are 3 sulfur atoms. To calculate the mass of aluminum sulfate, follow the steps below:
Step 1: Calculate the molar mass of aluminum sulfate using the periodic table.Al = 27.0 g/molS = 32.1 g/molO = 16.0 g/mol
(2 × Al) + (3 × S) + (12 × O) = molar mass of \(Al_2(SO_4)_3.\) = 342.2 g/mol
Step 2: Find the number of moles of sulfur in the given number of atoms of sulfur.2\(2.837*10^{26\) atoms of sulfur × 1 mol S/\(6.022 * 10^{23\)atoms S = 0.0470 mol S
Step 3: Use the molar ratio of sulfur to aluminum sulfate to calculate the number of moles of aluminum sulfate.1 mol \(Al_2(SO_4)_3.\) / 3 mol S = 0.333 mol\(Al_2(SO_4)_3.\) per mol S0.0470 mol S × 0.333 mol \(Al_2(SO_4)_3.\)/mol S = 0.0157 mol \(Al_2(SO_4)_3.\)
Step 4: Calculate the mass of aluminum sulfate.0.0157 mol \(Al_2(SO_4)_3.\) × 342.2 g/mol\(Al_2(SO_4)_3.\)= 5.373 g\(Al_2(SO_4)_3.\)
Therefore, the mass of Aluminum Sulfate is 5.373 grams if you have \(2.837*10^{26\) atoms of Sulfur.
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Determine the molar solubility of BaF2 in a solution containing 0.0550 M LIF. Ksp (BaF2) = 2.45 x 10^-5
Answer:
8.1*10^-3 or 0.00809917
Explanation:
Step 1: Identify the common ion
LiF and BaF2 both share the ion F^- therefore we can interchange the molarity of LiF for F.
Step 2: Set up a balanced equation
BaF2---Ba2+ + 2F
Step 3: Set up a solubility ice table
initial- Ba^2+: 0 2F: 0.0550
change- S 2F: S^2(exponent is result of coefficient)
Step 4: Set up Ksp equation
2.45*10^-5=[S][S]^2
Step 5: Plug in values
2.45*10^-5=[S][0.0550]^2
S=8.1*10^-3
an ion has 38 protons, 36 electrons, qnd 40 neutrons, what is its mass #?
Answer:
Strontium - 38 (atomic #)
Explanation:
An ion with 38 protons, 36 electrons, and 40 electrons is Strontium. Strontium's atomic number is 38.
WILL GIVE BRAINLIEST (also pls don't copy answers from other ppl :D) Question: Choose two spheres of Earth which interact when hot springs are formed. Use complete sentences to explain how they interact during this process.
Answer:
Geosphere and Hydrosphere.
Explanation:
Hot springs are heated by geothermal heat—heat from the Earth's interior. In volcanic areas, water may come into contact with very hot rock heated by magma. The geosphere and hydrosphere interact when hot springs form. The geosphere gets a little melted by the hot hydrosphere and then when the springs shoot up in the air they break some rocks.
Explain why Florida does not have long winters?
Which atom would be expected to have a half-filled 6s subshell
Answer: I think the answer is Cesium (Cs)
Explanation:
A half-filled 6s subshell would be 6s^1
About how many harvests of bamboo can be collected during the time it takes to fully grow one pine tree?
Answer:
bamboo can grow 910 mm (36 in) within a 24-hour period,at a rate of almost 40 mm (1 1⁄2 in) an hour (a growth around 1 mm every 90 seconds, or 1 inch {2.54 centimeters} every 40 minutes).
Explanation:
Given the following data. (i) Ca(s) + 2C(grafite) -> Cacis) X Ca(s) + ⅐0›(g) -> Cao(s) (iit) CaO(s) + H›O(I) -> Ca(OH)(ag) (iv) CHi(g) + 5/20,(8) -> 2C0,(g) + H,0(1) X* (v) C(grafite) + 02(g) -> CO›(g) [4 marks] AH = -62.8 kJ AH = -635.5 kJ AH = -653.1 kJ AH= -1300.0 kJ AH = -393.5 kJ / Calculate AH for the following reaction by using Hess's law and manipulating the given reactions: CaC(s) + H,O(I) - Ca(OH),(ag) + GHa(g) AH = ?
The enthalpy change (ΔH) for the reaction CaC(s) + H2O(I) → Ca(OH)(ag) + CH4(g) is -3617.6 kJ.
To calculate ΔH for the reaction CaC(s) + H2O(l) → Ca(OH)2(ag) + CH4(g), we can use Hess's law, which states that the enthalpy change of a reaction is independent of the pathway taken and depends only on the initial and final states.
We can manipulate the given reactions to obtain the desired reaction:
(i) Ca(s) + 2C(graphite) → CaC2(s) ΔH = X (unknown value)
(ii) Ca(s) + 1/2O2(g) → CaO(s) ΔH = -635.5 kJ
(iii) CaO(s) + H2O(l) → Ca(OH)2(ag) ΔH = -653.1 kJ
(iv) CH4(g) + 2O2(g) → CO2(g) + 2H2O(l) ΔH = -1300.0 kJ
(v) C(graphite) + 1/2O2(g) → CO(g) ΔH = -393.5 kJ
Now, let's manipulate these equations to cancel out the common reactants and products and obtain the desired reaction:
(i) Ca(s) + 2C(graphite) → CaC2(s) ΔH = X
(ii) Ca(s) + 1/2O2(g) → CaO(s) ΔH = -635.5 kJ
(iii) CaO(s) + H2O(l) → Ca(OH)2(ag) ΔH = -653.1 kJ
(iv) CH4(g) + 2O2(g) → CO2(g) + 2H2O(l) ΔH = -1300.0 kJ
(v) C(graphite) + 1/2O2(g) → CO(g) ΔH = -393.5 kJ
Now, let's sum up the equations to obtain the desired reaction:(i) Ca(s) + 2C(graphite) → CaC2(s) ΔH = X
(ii) 2Ca(s) + O2(g) → 2CaO(s) ΔH = -1271 kJ
(iii) CaO(s) + H2O(l) → Ca(OH)2(ag) ΔH = -653.1 kJ
(iv) CH4(g) + 2O2(g) → CO2(g) + 2H2O(l) ΔH = -1300.0 kJ
(v) C(graphite) + 1/2O2(g) → CO(g) ΔH = -393.5 kJ
By adding equations (ii), (iii), (iv), and (v), we can cancel out CaO(s), H2O(l), and O2(g):
2Ca(s) + 2C(graphite) + CH4(g) → 2Ca(OH)2(ag) + CO(g) ΔH = X -1271 -653.1 -1300.0 -393.5
2Ca(s) + 2C(graphite) + CH4(g) → 2Ca(OH)2(ag) + CO(g) ΔH = X -3617.6 kJ
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1. What organ system is responsible for controlling all of the body
functions?
Answer:
The human brain is the body's control center, receiving and sending signals to other organs through the nervous system and through secreted hormones. It is responsible for our thoughts, feelings, memory storage and general perception of the world. The human heart is a responsible for pumping blood throughout our body
Choose all the answers that apply. Which of the following energy forms are involved in a nuclear power plant?
1)heat
2)mechanical
3)electrical
4)nuclear
Answer:Three mutual conversions of energy forms occur at nuclear power plants: nuclear energy is converted into thermal energy, thermal energy is converted into mechanical energy, and mechanical energy is converted into electric energy.
Explanation:
What is the function of the chloroplast? A. Breaks down sugar to make energy B. To hold the cell together C. To make animals green D. Uses sunlight to create glucose (sugar)
Answer:
D. Uses sunlight to create glucose (sugar)
Explanation:
The function of the chloroplast is that it uses sunlight to create glucose.
The chloroplast allows for light to be trapped which is used for the synthesis of glucose from carbon dioxide and water.
The chloroplast is a rich in a pigment called the chlorophyll. This chlorophyll is a green pigment which allows for the trapping of solar energy
This solar energy is used to carryout the photosynthetic reaction.
if 3 moes of cl reacts with 3 moles oxygen, then which substance is the limitting reactant and excess reactant
If 3 moles of cl reacts with 3 moles oxygen, there is no limiting reactant or excess reactant because the reactants are in stoichiometric proportions.
To determine the limiting reactant and excess reactant, we need to compare the stoichiometry of the reaction to the given amounts of each reactant.
The balanced chemical equation for the reaction between chlorine (Cl2) and oxygen (O2) can be represented as follows:
2Cl2 + O2 → 2Cl2O
According to the balanced equation, it requires 2 moles of chlorine (Cl2) to react with 1 mole of oxygen (O2) to produce 2 moles of chlorine oxide (Cl2O).
Given that we have 3 moles of chlorine (Cl2) and 3 moles of oxygen (O2), we can determine the limiting reactant by comparing the ratio of moles between the two reactants.
The ratio of Cl2 to O2 required for complete reaction is 2:1. However, since we have equal amounts of Cl2 and O2 (both 3 moles), neither reactant is present in excess.
Therefore, in this scenario, there is no limiting reactant or excess reactant because the reactants are in stoichiometric proportions. All of the chlorine and oxygen will be consumed in the reaction, resulting in the complete conversion to chlorine oxide (Cl2O).
It's important to note that if the amounts of Cl2 and O2 were different, the reactant present in lesser quantity would be the limiting reactant, and the reactant in greater quantity would be the excess reactant.
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What is the volume (in liters) of 1.51 x10^24 molecules of Argon gas at STP?
Answer:
Explanation:
The molar volume of a gas at STP (Standard Temperature and Pressure), which is equal to 22.4 liters.
There are 6.02x10^23 molecules in 1 mole of Argon.
So for 1.51x10^24 molecules of Argon, the volume at STP should be
(1.51x10^24 / (6.02x10^23)) * 22.4
= 56.19 liters
Moles of Argon:-
No of molecules/Avagadro's constant1.51×10^24/6.022×10^23=2.5molNow
1mol of gas contains 22.4L2.5mol contains:-\(\\ \rm\Rrightarrow 2.5(22.4)=56L\)
A compound has a similar molecular mass of 180grams/mol. It contains 40.8% carbon,5.8% hydrogen and 53.4% oxygen. Calculate its empirical formula and molecular formula, and give its common name.
Answer:
To find the empirical formula of the compound, we need to determine the simplest whole-number ratio of atoms in the molecule.
First, we can assume that we have 100 grams of the compound, and calculate the number of moles of each element present in it:
Carbon: 40.8 g / 12.011 g/mol = 3.398 mol
Hydrogen: 5.8 g / 1.008 g/mol = 5.753 mol
Oxygen: 53.4 g / 15.999 g/mol = 3.337 mol
Next, we divide each of these values by the smallest one, which is 3.337, to get the mole ratio:
Carbon: 3.398 mol / 3.337 mol = 1.019
Hydrogen: 5.753 mol / 3.337 mol = 1.723
Oxygen: 3.337 mol / 3.337 mol = 1.000
Rounding these values to the nearest whole number, we get the empirical formula: C1.0H1.7O1.0, which can be simplified to CH1.7O.
To find the molecular formula, we need to know the actual molecular mass of the compound. We can estimate it by adding the atomic masses of the elements in the empirical formula:
Carbon: 1 x 12.011 = 12.011
Hydrogen: 1.7 x 1.008 = 1.714
Oxygen: 1 x 15.999 = 15.999
Total = 29.724 g/mol (approx.)
The molecular mass is close to 180 g/mol, which suggests that the actual molecular formula is a multiple of the empirical formula. Dividing 180 by 29.724, we get a value of about 6.05. Multiplying the subscripts in the empirical formula by this value, we get the molecular formula: C6H10.2O6, which can be further simplified to C3H5.1O3.
The compound with the empirical formula CH1.7O and the molecular formula C3H5.1O3 is commonly known as glyoxylic acid.
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100 NaNO3
90
Solute per 100 g of H₂O (g)
0,80
NH,CI
70 KNO3
60
50
40
30
20
10
0
0 10 20 30 40 50 60 70 80 90 100
Temperature (°C)
KCIO3
60 g KNO3 has
been added to
100 g H₂O at
30 °C. What
type of solution
is this?
A. unsaturated
B. saturated
C. supersaturated
If 60 grams of the substance are added to 100 g of water, the solution can be categorized as supersaturated.
How saturated is this solution?The graph shows the number of grams that can be dissolved in 100 grams of water at different temperatures. In general, solubility increases with temperature.
According to the graph, at a temperature of 30°C, it is possible to dissolve a total of 48 to 49 grams of \(KNO_{3}\). This information implies that if we add 60 grams at this temperature not all the substance would be dissolved, and therefore the solution would be supersaturated.
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A balloon containing 7.2 L of gas at 27℃ and 760 mmHg is launched into the atmosphere. The balloon travels upward before bursting where the temperature is -32℃ and the pressure is 9.76 mmHg. What is the volume of the balloon just before it bursts?
A. 660 L
B. 45.0 L
C. 560 L
D. 450 L
B. 45.0 L.The balloon has a 45.0 L volume shortly before it bursts.
When temperature is held constant, a gas's volume and pressure have an inverse relationship. This implies that the volume increases as the pressure falls.
Using the Ideal Gas Law, we can calculate the change in volume with the following equation:
\(\frac{V2}{T2} = \frac{V1}{T1}\)
where T1 denotes the starting temperature, T2 denotes the finished temperature, V1 denotes the starting volume, and V2 is the finished volume.
Given:
V1 = 7.2 L
T1 = 27℃ = 300 K
T2 = -32℃ = 241 K
We can solve for V2:
\(V2 = \frac{(V1 * T2) }{ T1} \\\)
\(V2 =\frac{ (7.2 L * 241 K) }{ 300 K }\\V2 = 45.0 L\)
Therefore, the volume of the balloon just before it bursts is 45.0 L.
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1. Which of the following statements about carbon oxides is FALSE?
Answer:
what are the following statements?
Explanation:
What is the molarity of a solution of NaOH that contains 0.350 moles of sodium hydroxide in
1.25 liters of solution?
Explanation:
from chemical basics is the law of solution concentration which is no. of moles÷ volume
see image attached please and thank you
hope it helps:)
\(a. \: Ca + Cl _{2} → CaCl _{2} \\
\\ b. \: Cl _{2}+H _{2} O+ NaOH → \\ NaCl+ H _{2}O \\ \\
c. \: \: \: H _{2} SO _{4} +CaCO _{3} → \\ CaSO _{4} +H _{2}O+CO _{2} \\ \\
d. \: \: Fe+Cu(NO _{3}) _{2} → \\ Fe(NO _{3} ) _{2}+Cu\)
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What are all the possible metabolites for the clofibrate structure through metabolism pathways like hydrolysis, alkylation, conjugation, oxidation etc. ?
Clofibrate is a lipid-lowering pharmaceutical that has been utilized to treat hyperlipidemia. Its metabolism system includes different pathways such as hydrolysis, oxidation, conjugation, and others.
What are a few potential metabolites of clofibrate?Metabolites are little molecules that are produced during the process of metabolism in living living beings.
Clofibrate hydrolysis metabolite:
2-(4-Chlorophenoxy)-2-methylpropanoic acid (phenoxyisobutyric acid)Clofibrate oxidation metabolites:
4-Chlorophenylacetic acid4-Chlorobenzaldehyde4-Chlorophenylacetyl-CoAClofibrate alkylation metabolites:
No specific alkylation metabolites have been widely reported for clofibrate.Clofibrate conjugation metabolites:
Glucuronide conjugatesSulfate conjugatesConclusively, the relative abundance and significance of each metabolite can vary among individuals.
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1. State how increasing the temperature of a gas changes its volume, assuming pressure is held
constant.
Explanation:
the volume and temperature of a gas have a ditect relationship,as the temperature increases the volume also increases when pressure is held constand, heating the gas increases the kinetic energy of the particles or atoms,causing the gas to expand until the pressure returns to its original value
which of the following shows correctly an ion pair and ionic compound the two ions from
Answer:
what are the choices?
Explanation: