PLZZ HELPP ILL GIVE BRAINLIST

Which equation has a = 5 as the solution?

Answer:

outliers

explanation:

Answer:

the right answer is

no d (outliers)

Circumference of a circle is pi x diameter

Circumference = 3.14 x 8 = 25.12 feet.

Arc AB is 45 degrees.

Arc length = circumference x angle/360

Arc length = 25.12 x 45/360 = 3.14 feet

Answer: 3.14 feet

Answer:

im sorry i dont know but you can try

Step-by-step explanation:

Divide a row or column total by the grand total. The correct option is B.

In a two-way table, you must divide a row or column total by the total to find the marginal relative frequency. The sum of a row or column is divided by the overall sum.

The proportion or percentage of a certain category within a row or column in relation to the overall number of categories is represented by a marginal relative frequency.

You calculate it by dividing the overall count of a particular row or column by the sum of all the values in the table. This gives the proportion or relative frequency of that category in respect to the overall count.

To calculate the marginal relative frequency, the correct way is to divide a row or column total by the overall total.

Thus, the correct option is B.

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Answer:

75.39 in^2 (round to the nearest hundreds)

Step-by-step explanation:

I think that we have to find the lateral area

circumference = 2 x radius x pi = 2 x 4 x pi = 25,13 in^2 (round to the nearest hundreds)

lateral surface = (circumference x slant height)/2 = (25,13 x 6)/2 = 75,39 in^2 (round to the nearest hundreds)

The positions are 3, 7, or 13 from 407

To determine if 407 is an N position under the normal game rule, we need to consider all possible moves from this number. Since the set is {3, 7, 13}, we can subtract either 3, 7, or 13 from 407. Let's examine each option:

Subtracting 3 from 407:

This yields 404. Now, we need to consider the possible moves from 404. In this case, we can subtract either 3, 7, or 13. If we subtract 3, we get 401, and so on.

Subtracting 7 from 407:

This results in 400. Similar to before, we need to consider the possible moves from 400.

Subtracting 13 from 407:

This gives us 394. Again, we need to consider the possible moves from 394.

At each step, we continue exploring the possible moves until we reach a point where no valid move can be made. This process is known as game tree traversal.

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The polynomial that is written in standard form out of the given options is given by: Option 2: x^4 + 4x^3 + 10x

Suppose the considered polynomial is of only one variable.

Then, the standard form of that polynomial is the one in which the terms with higher exponents are written on left side to those which have lower exponents.

Terms are added or subtracted to make a polynomial. They're composed of variables and constants all in multiplication.

Example:

\(x^3 + 3x +5\)

is a polynomial consisting 3 terms as \(x^3, 3x \: \rm and \: 5\)

Cheking all the options for them being in standard form or not:

Second term has 4 as exponent, but on its left, the first term has 2 as exponent. So higher expoent holding term is not on left. Thus, this polynomial is not in standard form.

4 > 3 > 1 (comparing the exponents), and the terms holding them are also in this order (left to right).

Thus, this polynomial is in standard form.

Not in standard form because the last term has bigger power then the term on its left.

Not in standard form because the last term has bigger power then the term on its left.

Thus, the polynomial that is written in standard form out of the given options is given by: Option 2: x^4 + 4x^3 + 10x

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The properties of exponents

1. \((64)^{1/2}\) = √(64) = 8

2.  \(3m(mn)^(3/2)\) = \(3m(m^{3/2}n^{3/2})\)

3. 2a(5ab)² = \(2a(25a^2b^2) = 50a^3b^2\)

The properties of exponents can be used to simplify and rewrite expressions involving powers and roots. The most common properties are:

Product of powers: \(a^m\) * aⁿ = \(a^{m+n}\)

Quotient of powers: \(a^m\)/ aⁿ = \(a^{m-n}\)

Power of a power: \((a^m)^n\) = \(a^{mn}\)

Power of a product: \((ab)^m\) = \(a^m\) * \(b^m\)

Power of a quotient: \((a/b)^m\) = \(a^m\)/ \(b^m\)

Using these properties, we can rewrite the given equations as follows:

1. \((64)^{1/2}\) = √(64) = 8

The square root of 64 is 8. The power of 1/2 represents the square root.

2. \(3m(mn)^(3/2)\) = \(3m(m^{3/2}n^{3/2})\)

The power of 3/2 represents the square root of the square. We can use the product of powers property to combine the m and n terms under the same square root.

3. 2a(5ab)² = \(2a(25a^2b^2) = 50a^3b^2\)

We can use the power of a product property to square the 5ab term, and then simplify by combining the like terms.

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By taking the average of the two middle numbers, Diane ensures that the median represents the central tendency of the dataset when there are an even number of values.

When there are two middle numbers in a set of scores, Diane can determine the value of the median by taking the average of the two middle numbers.

To find the median, Diane should follow these steps:

1. Arrange the scores in ascending order.

2. Identify the two middle numbers. If there is an even number of scores, there will be two middle numbers.

3. Take the average of the two middle numbers to determine the median value.

For example, let's say Diane has the following set of scores: 82, 75, 90, 86, 79, 88. To find the median, she would follow these steps:

1. Arrange the scores in ascending order: 75, 79, 82, 86, 88, 90.

2. Identify the two middle numbers: 82 and 86.

3. Take the average of the two middle numbers: (82 + 86) / 2 = 84.

Therefore, in this case, the median of the set of scores is 84.

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There are no real values for X and Y that satisfy the given equations X + Y = 17 and XY = 164.

To find the values of X and Y in the given equations, we can use a system of equations approach.

Let's start by solving the first equation, X + Y = 17, for one variable in terms of the other. We can choose to solve for X:

X = 17 - Y

Now, substitute this expression for X in the second equation, XY = 164:

(17 - Y)Y = 164

Expanding the equation gives us:

17Y - Y^2 = 164

Rearranging the equation to a quadratic form, we have:

Y^2 - 17Y + 164 = 0

To solve this quadratic equation, we can use factoring, completing the square, or the quadratic formula. Let's use the quadratic formula:

Y = (-(-17) ± √((-17)^2 - 4(1)(164))) / (2(1))

Simplifying further:

Y = (17 ± √(289 - 656)) / 2

Y = (17 ± √(-367)) / 2

Since the expression under the square root is negative, there are no real solutions for Y. This means that there are no real values for X and Y that satisfy both equations simultaneously.

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The product of the terms   \((d - 9)\)  and  \((2d^{2} + 11d -4)\)  will be \((2d^{3} - 7d^{2} - 103d + 36)\).

We have to find the product of two terms.

First term = (d - 9)

Second term = \((2d^{2} + 11d -4)\)

To find the product of these two terms, we will be using the distributive property. According to the distributive property, when we multiply the sum of two or more addends by a number, it will give the same result as when we multiply each addend individually by the number and then add the products together.

We have to find :  \((d - 9) (2d^2 + 11d -4)\)

Using the distributive property,

\(d * 2d^{2} + d * 11 + d * (-4) - 9 * 2d^2 - 9 * 11d - 9 * (-4)\)

After further multiplication, we get

\(2d^{3} + 11d^2 - 4d - 18d^{2} - 99d + 36\)

Now, combine all the like terms.

\(2d^{3} + 11d^{2} - 18d^{2} - 4d - 99d + 36\)

\(2d^{3} - 7d^{2} - 103d + 36\)

Therefore, the product of d-9 and 2d^2 + 11d -4 is \(2d^{3} - 7d^{2} - 103d + 36\)

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Answer:

7.14

Step-by-step explanation:

Answer:

the answer is 10 5. you welcome

The solution to the inequality is y ≤ -8. This means that any value of y that is less than or equal to -8 will satisfy the original inequality.

To solve the inequality y + 7 ≤ -1, we need to isolate the variable y on one side of the inequality sign.

Starting with the given inequality:

y + 7 ≤ -1

We can begin by subtracting 7 from both sides of the inequality:

y + 7 - 7 ≤ -1 - 7

y ≤ -8

The solution to the inequality is y ≤ -8. This means that any value of y that is less than or equal to -8 will satisfy the original inequality.

In the context of a number line, all values to the left of -8, including -8 itself, will make the inequality true. For example, -10, -9, -8, -8.5, and any other value less than -8 will satisfy the inequality. However, any value greater than -8 will not satisfy the inequality.

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The following question may be like this:

What is a solution of the inequality shown below? y+7≤-1

Answer:

1.626 and then theres a lot more numbers

Step-by-step explanation:

Answer:

1.62614012e-7

Step-by-step explanation:

this is the answer to 7/9 to the 8th power

Step-by-step explanation:

ABD+DBC+ABC =180° ( TRIANGLE)

(2x-7)°+(8x+16)°+159=180°

2x+8x-7°+16°+156=180

10x+165=180

10x=180-165

10x=15

x=15/10

x=1.5

Hi! I believe your answer is C- 2.1 because the number 2 is in the whole number spot and the first number after the decimal is the tenth. So, it's 2 and one-tenth, because there's a one. I hope this helps you! Good luck and have a great day. ❤️

Answer:

Step-by-step explanation:

11 ÷ 4 = 2 + 2 = 4

1 + 4 + 4 = 9

19 ÷ 4 = 4

The mean-square end-to-end distance for the fractal line is ⟨R2⟩ = b².L^(1-D).

The mean-square end-to-end distance for the fractal line is as follows.⟨R2⟩ = ⟨(R(u)- R(v))^2⟩ for u = 0 and v = L where L is the length of the line.⟨R2⟩ = b²/L^2.D.L = b².L^(1-D).

Thus, the mean-square end-to-end distance for the fractal line is ⟨R2⟩ = b².L^(1-D).

The radius of gyration Rg is defined as follows.

Rg² = (1/N)∑_(i=1)^N▒〖(R(i)-R(mean))〗²where N is the number of monomers in the fractal line and R(i) is the position vector of the ith monomer.

R(mean) is the mean position vector of all monomers.

Since the fractal dimension is D, the number of monomers varies with the length of the line as follows.N ~ L^(D).

Therefore, the radius of gyration for the fractal line is Rg² = (1/L^D)∫_0^L▒〖(b/v^(1-D))^2 v dv〗 = b²/L^2.D(1-D). Thus, Rg² = b².L^(2-D).

The ratio R²/Rg² is given by R²/Rg² = L^(D-2).

When D = 1, R²/Rg² = 1/L. When D = 1.7, R²/Rg² = 1/L^0.7. When D = 2, R²/Rg² = 1/L.

This provides information on mean-square end-to-end distance and radius of gyration for fractal line with a given fractal dimension.

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Hi there!

~

⇒ \(- \frac{1}{2(x + 3)} + \frac{1}{2(x - 3)}\)

Step by Step :

∴ Factor \(x^2 - 9\) : \(( x+ 3 ) ( x - 3)\)

\(= \frac{3}{(x +3)(x - 3)}\)

∴ Create the partial fraction template using the denominator \(( x + ) ( x - 3)\)

\(\frac{3}{( x + 3) ( x -3)} = \frac{a^0}{x + 3} + \frac{a^1}{x - 3}\)

∴ Multiply the equation by the denominator.

\(\frac{3(x+3)(x-3)}{( x+3)(x-3)} = \frac{a^0(x +3)(x-3)}{x + 3} + \frac{a^1 (x+3)(x-3)}{x - 3}\)

∴ Simplify.

\(3 = a^0 ( x - 3) + a^1 ( x+3)\)

∴ Solve the unknown parameters by plugging the real roots of the denominator : - 3,3

⇅

∴ Solve the denominator root -3 : \(a^0 = -\frac{1}{2}\)

∴ For the denominator root 3 : \(a^1 = \frac{1}{2}\)

\(a^0 = -\frac{1}{2} , a^1 \frac{1}{2}\)

∴Plug the solutions to the partial fraction parameters to obtain the final result.

\(\frac{(-\frac{1}{2}) }{x + 3} + \frac{\frac{1}{2} }{ x- 3}\)

∴ Simplify

\(- \frac{1}{2(x + 3)} + \frac{1}{2(x - 3)}\)

Hope this helped you!

The given statement "The intercept gives the predicted attendance rate when one of the predictors, either cumulative GPA prior to the term or ACT score, equals 1" is FALSE.

Regression analysis is used to establish a relationship between the response variable (dependent variable) and one or more predictor variables (independent variable). A linear regression equation has a slope, intercept, and error term. The intercept is the value of Y when X is zero.The intercept in a linear regression is the mean value of Y when all the predictor variables are equal to zero.

he regression equation is as follows: y = a + bx Here, y is the dependent variable, a is the intercept, b is the slope, and x is the independent variable.In the context of this question, the intercept gives the predicted attendance rate when both cumulative GPA prior to the term and ACT score are zero. The intercept can't predict the attendance rate when one of the predictors equals one.

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In computer programming, variables are used to store and manipulate data. In this case, an int variable named strawsoncamel has been declared and assigned a value.

To increase the value of strawsoncamel by 1, you can use the increment operator (++). This operator adds 1 to the current value of the variable and assigns the result back to the variable.

For example, if strawsoncamel has a value of 5, the statement strawsoncamel++; would increase its value to 6. This can be useful in many scenarios, such as counting or iterating through a loop. It's important to note that the increment operator can also be used in other ways, such as ++strawsoncamel, which increments the value of the variable before it is used in an expression.

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To increase the value of the variable strawsoncamel by 1, you can use the increment operator "++". So the statement would be:
strawsoncamel++;

This will increment the value of strawsoncamel by 1. The increment operator is an example of an operator in programming, which performs a specific operation on a variable. In this case, it increases the value of the variable by 1, which is also known as an increment.
To increase the value of the integer variable `strawsoncamel` by 1 using the increment operator, follow this step:
Write the statement: `strawsoncamel++;`
This line of code will use the increment operator (`++`) to increase the value of the variable `strawsoncamel` by 1.

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The box measures 100.79 cm by 100.79 cm by 50.40 cm in size, which minimizes the quantity of material used.

Given,

Let the side of the square base be x

h be the height of the box

Volume V = x²h

512000 = x²h

h = 512000/x² ..... 1

Surface area =  x² + 2xh + 2xh

Surface area S =  x² + 4xh  ...... 2

Substitute 1 into 2;

From 2;

S =  x² + 4xh

S = x² + 4x(512000/x²)

S = x² + 2048000/x

To minimize the amount of material used;

dS/dx = 0

dS/dx = 2x - 2048000/x²

0 = 2x - 2048000/x²

0 = 2x³ - 2048000

2x³ = 2048000

x³ = 1024000

x = ∛1024000

x = 100.79 cm

Since Volume = x²h

512000 = 100.79²h

h = 512000/10158.62

h = 50.40 cm

Hence the dimensions of the box that minimize the amount of material used is 100.79 cm by 100.79 cm by 50.40 cm

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Answer:

2 degrees celsius

The final temperature in Ottawa is 2°C.

We have,

Given:

Initial temperature = -4°C

Temperature rise = 14°C

Temperature fall = -8°C

The formula to calculate the final temperature.

Final temperature = Initial temperature + Temperature rise + Temperature fall

Final temperature = -4°C + 14°C + (-8°C)

Simplify

Final temperature = -4°C + 14°C - 8°C

Final temperature = 2°C

Therefore,

The final temperature in Ottawa is 2°C.

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The true or false statements based on the graph on the lengths of ribbons are:

The graph shows that most common length that a ribbon has is 11²/₈ with 3 ribbons. At a simpler term, this becomes 11¹/₄.

The sum of the longest and shortest lengths is:

= 11¹/₄ + 9⁷/₈

= 21⁹/₈

The sum is therefore not 20¹/₈.

The difference between the longest and shortest lengths is:

= 11¹/₄ - 9⁷/₈

= 1³/₈

This is not 2 ¹/₈

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The inequality that represents how many DVDs Andy can rent in one month that satisfies this condition is 10 + .75n ≤ 25

The correct answer choice is option B

Cost of rental per month = $10

Additional cost = $0.75

Number of DVD's rented = n

Total amount Andy want to spend ≤ $25

The inequality:

10 + 0.75n ≤ 25

subtract 10 from both sides

0.75n ≤ 25 - 10

0.75n ≤ 15

divide both sides by 0.75

n ≤ 15 / 0.75

n ≤ 20

Ultimately, Andy can rent no more than 20 DVD's in a month.

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The solution to the initial value problem is y(t) = (-1/2)e⁻ˣ+ (1/2)e⁻²ˣ+ (1/2)δ(t) + (1/2)u10(t)

The given differential equation is:

y'' + 3y' + 2y = δ(t − 5) + u10(t)

where δ(t) is the Dirac delta function, and u10(t) is the unit step function. The initial conditions are:

y(0) = 0, y'(0) = 1/2

To solve this IVP, we need to find the general solution to the homogeneous equation:

y'' + 3y' + 2y = 0

The characteristic equation is:

r^2 + 3r + 2 = 0

Solving for r, we get:

r = -1, -2

Therefore, the general solution to the homogeneous equation is:

y_h(t) = c₁e⁻ˣ+ c₂e⁻²ˣ

where c₁ and c₂ are constants to be determined.

Next, we need to find the particular solution to the non-homogeneous equation. We have two non-homogeneous terms: δ(t − 5) and u10(t). We will solve for each separately.

For the Dirac delta function δ(t − 5), we know that its integral over any interval containing 5 is equal to 1. Therefore, we can write:

δ(t − 5) = (d/dt)u(t − 5)

where u(t) is the unit step function. Using this, we can write the non-homogeneous term as:

δ(t − 5) = (d/dt)u(t − 5) = (d/dt)(u(t) − u(t − 5)) = δ(t) − δ(t − 5)

Now, we can write the non-homogeneous equation as:

y'' + 3y' + 2y = δ(t) − δ(t − 5) + u10(t)

To find the particular solution to δ(t), we can use the method of undetermined coefficients. We assume a particular solution of the form:

y_p(t) = Aδ(t)

where A is a constant to be determined. Substituting this into the non-homogeneous equation, we get:

0 + 0 + 2Aδ(t) = δ(t)

Therefore, A = 1/2, and the particular solution to δ(t) is:

y_p1(t) = (1/2)δ(t)

Next, we need to find the particular solution to u10(t). We can again use the method of undetermined coefficients and assume a particular solution of the form:

y_p(t) = Bu10(t)

where B is a constant to be determined. Substituting this into the non-homogeneous equation, we get:

0 + 0 + 2Bu10(t) = u10(t)

Therefore, B = 1/2, and the particular solution to u10(t) is:

y_p2(t) = (1/2)u10(t)

Now, we can write the general solution to the non-homogeneous equation as:

y_p(t) = y_p1(t) + y_p2(t) = (1/2)δ(t) + (1/2)u10(t)

Therefore, the general solution to the initial value problem is:

y(t) = y_h(t) + y_p(t) = c₁e⁻ˣ+ c₂e⁻²ˣ+ (1/2)δ(t) + (1/2)u10(t)

To determine the values of c₁ and c₂, we use the initial conditions:

y(0) = 0, y'(0) = 1/2

Substituting these into the general solution and simplifying, we get:

c₁ + c₂ + (1/2) = 0

-c₁ - 2c₂ + (1/2) = 1/2

Solving for c₁ and c₂, we get:

c₁ = -1/2, c₂ = 1/2

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Answer:

Below in bold.

Step-by-step explanation:

As its direct variation the graph is a straight line and passes through the origin (0,0) and the slope (y/x) is a constant.

The  fraction (y/x) for any point will be a constant.

The fraction for (6, 4)  is 4/6 = 2/3.

So also on the line we have:

(-9, -6)  (because  -6/-9 = 2/3).

and (3, 2).

The zeros of the polynomial are: 0, 1, -2

The multiplicities of the polynomial are:

x = 0 has a multiplicity of 2

x = 1 has a multiplicity of 3

x = -2 has a multiplicity of 2

The zeros of a Polynomial are defined as the roots of the polynomial which means the values of x that makes the polynomial to be zero.

We are given the polynomial as:

z(x) = -4x²(x - 1)³(x + 2)²

Thus, the zeros here are:

-4x = 0

x = 0

x - 1 = 0

x = 1

x + 2 = 0

x = -2

The number of times a given factor appears in the factored form of the equation of a polynomial is called the multiplicity.

Thus,

x = 0 has a multiplicity of 2

x = 1 has a multiplicity of 3

x = -2 has a multiplicity of 2

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