PLZ HELP
keiko tosses one penny and ephraim tosses two pennies. what is the probability that ephriam gets the same numbers of heads as keiko

So the lens should be held 9.7 cm away from the eye.

A) When the lens forms a virtual image at negative infinity, it is being used as a simple magnifying glass. The angular magnification M of a simple magnifying glass is given by:

M = 1 + (s/f)

where s is the distance between the object and the lens, and f is the focal length of the lens. When the lens forms a virtual image at negative infinity, s is equal to f. Therefore, the angular magnification is:

M = 1 + (f/f) = 2

To hold the lens at the correct distance, we need to use the thin lens equation:

1/s + 1/f = 1/d

where d is the distance between the lens and the eye. In this case, we want the final image to be at the near point of the eye, which is 25 cm. Therefore, we can solve for d:

1/s + 1/f = 1/d

1/14 + 1/25 = 1/d

d = 9.7 cm

So the lens should be held 9.7 cm away from the eye.

So the lens should be held 31.4 cm away from the object.

B) When the lens forms a virtual image at the person's near point (assumed to be 25 cm), the distance between the object and the lens is:

s = 25 cm - f = 11 cm

Using the same formula as before, the angular magnification is:

M = 1 + (s/f) = 1 + (11 cm / 14 cm) = 1.79

To find the distance between the lens and the object, we can again use the thin lens equation:

1/s + 1/f = 1/d

where d is now the distance between the lens and the object. Solving for d, we get:

1/s + 1/f = 1/d

1/11 + 1/14 = 1/d

d = 31.4 cm

So the lens should be held 31.4 cm away from the object.

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Answer:

B

Step-by-step explanation:

f(x)=(x-3)(x²+2x+2)

when solve for x using quadratic formula fo x in (x²+2x+2):

x=(-b±√b²-4ac)/2a  a=1,b=2,c=2

x=-1±i

f(x)=(x-3)(x+1-i)(x+1+i)

The complete factored form of the polynomial is F(x) = (x - 3)(x + 1 + i)(x + 1 - i).

To find the complete factored form of the polynomial F(x) = x³ - x² - 4x - 6, we can factor it using various methods such as synthetic division or factoring by grouping.

Factoring the polynomial, we get:

F(x) = (x + 3)(x - 1)(x + 2)

Comparing the factored form with the options provided:

A. F(x) = (x + 3)(x + 1)(x - 1)

This option does not match the factored form of the polynomial.

B. F(x) = (x - 3)(x + 1 + i)(x + 1 - i)

f(x)=(x-3)(x²+2x+2)

When solve for x using quadratic formula fo x in (x²+2x+2):

x=(-b±√b²-4ac)/2a  

x=-1±i

f(x)=(x-3)(x+1-i)(x+1+i)

So, the is the required factored form.

C. F(x) = (x - 3)(x + 1 + i)(x - 1 - i)

This option does not match the factored form of the polynomial.

D. F(x) = (x + 3)(x + 1 + i)(x + 1 - i)

This option does not match the factored form of the polynomial.

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Answer:

hope this helps

.look it once

now

Solution is

225° is most suitable because it has accurate value -1/√2.

-π/4 is the principal value

Answer:

x1 = -4

x2 = 3

Step-by-step explanation:

\(x^{2} + x = 12\\x^{2} +x-12=0\\x^{2} +4x-3x-12=0\\x*(x+4)-3(x+4)=0\\(x+4)*(x-3)=0\\x+4= 0 \\x-3=0\\x=-4 \\x=3\\x1=-4 \\x2=3\)

Step-by-step explanation:

=> x² + x = 12

=> x² + x -12 = 0

=> x² + 4x - 3x -12 = 0

=> x ( x + 4)-3(x + 4) = 0

=> ( x + 4)(x-3)=0

=> x = 3 , -4

The answer is yes, (x + 6) is a possible length of a rectangle with area x² + x − 30.

To determine whether (x + 6) is a possible length of a rectangle with area x^² + x − 30, we can use an area model to visualize the situation.

First, we need to find the width of the rectangle.

The area of a rectangle is given by the formula A = lw,

where A is the area, l is the length, and w is the width.

We are given that the area is x² + x − 30, so we can set this equal to lw and solve for w:

x² + x − 30 = (x + 6)w

w = (x² + x − 30)/(x + 6)

The length of a rectangle must be greater than or equal to its width, so we need to check whether (x + 6) is greater than or equal to (x² + x − 30)/(x + 6). This simplifies to:

(x + 6) ≥ x² + x − 30

Expanding the left side and simplifying, we get:

x² + 12x + 36 ≥ x² + x − 30

11x ≥ -66

x ≥ -6

Since x must be a positive number (since we are dealing with lengths), we can conclude that (x + 6) is the possible length of the rectangle. Therefore, the answer is yes, (x + 6) is a possible length of a rectangle with an area x² + x − 30.

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Answer:

2. 42 hrs

Step-by-step explanation:

we know that there are 60 minutes in one hour.

60 mins = 1 hour

162 mins = 162/ 60

\( \frac{162}{60} = \frac{120 + 42}{60} \\ = \frac{120}{60} + \frac{42}{60} \\ = 2 hrs+ \frac{42}{60} hrs\)

42/ 60 hourse would mean 42 mins ( multiply the fractions with 60)

= 42 mins

therefore,

2hrs 42 mins

= 2. 42 hrs.

Answer:

Step-by-step explanation:

they are all made of numbers

Answer: x= 6

Step-by-step explanation:

Since the shape is a parallelogram, the angles will either be equal to each other or add up to 180.  

You can see they do not look the same so they add up to equal 180

12x + 3 +105 = 180

12x + 108 = 180

12x = 72

x = 6

Answer:

5 1/5 is rational, because it can be written as a fraction.

Step-by-step explanation:

All rational numbers are numbers that can be written as a fraction. We can make 5 1/5 into an improper fraction. 5 1/5 = 26/5.

The reasons that proves the congruency of the triangles are;

2.7 \( \Delta EDF \cong \Delta FGE\) by SSS congruency postulate

2.8 \( \Delta AOB \cong \Delta COB\), by SAS congruency rule

\( \Delta AOB \cong \Delta COB\), by ASA congruency rule or postulate

The rules that proves two triangles to be congruent is if they satisfy any of the 5 rules of congruency, which are; Side–side–side, or SSS, side–angle–side, or SAS, side–angle–angle, or SAA, angle–side–angle, or ASA, and right angle–hypotenuse–side, or RHS

2.7 The given parameters of the two triangles are;

DE = GF, and DF = GE

Required;

To prove that

\( \Delta EDF \cong \Delta FGE\)

Solution;

From the given diagram, we have;

\(EF \cong FE\)

Reflexive property

Therefore;

\( \Delta EDF \cong \Delta FGE\)

Side–Side–Side, SSS rule of congruency

The Side–Side–Side congruency postulate states that if the three sides of one triangle are congruent to three sides of another triangle, then both triangles are congruent.

2.8 The circle information are;

The midpoint (center) of the circle = Point O

Segment OB is perpendicular to segment AC, \( OB \perp AC \)

OB bisects AC

Required;

To prove that \( \Delta AOB \cong \Delta COB\)

Solution;

Segment OA and OC are the radius of circle O

Therefore;

\( OA \cong OC\) by the properties of the radius of a circle

The angle \( \angle OAB \cong \angle OCB \) ; Base angles of isosceles triangle ∆OAC

\( AB \cong BC\), Segments formed by the perpendicular bisector OB

Given that AB, \( \angle OAB \) and OA in \( \Delta AOB \) are congruent to BC, \( \angle OCB \) and OB in \( \Delta COB \), we have;

Second proof;

Given that OB is the perpendicular bisector of AC, we have;

\( \angle OBA \cong \angle OBC = 90^{\circ} \), definition of angles formed by perpendicular lines

\( AB \cong BC\)

Therefore;

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Answer:

Yes

Step-by-step explanation:

Answer:

Just push next... also the next question is -

Which of the following statements is true when comparing numbers using a number line?

The number closest to zero is always the least.

The number farthest from zero is always the greatest.

The number farthest right is always the least.

The number left is always the least.

YOUR ANSWER IS

D. The number left is always the least.

Your welcome peoples

All of the above options a) implement an expansion strategy b)attract capital c)reduce tax burdens d)easy entry into an industry e)take advantage of limited liability ,are correct.

A corporation is generally set up to take advantage of limited liability. This means that the owners of the corporation (the shareholders) are not personally responsible for the debts and obligations of the corporation. The other options you have listed are also potential reasons for setting up a corporation, but they are not the primary purpose of a corporation.

An expansion strategy refers to a company's plan for growth and expansion, and setting up a corporation can be one way to implement this strategy. Attracting capital refers to the process of raising funds for a business, and a corporation may be able to attract more capital because it is a separate legal entity that can issue stocks and bonds. Reducing tax burdens refers to the process of minimizing the amount of taxes a business has to pay, and a corporation may be able to do this because it is taxed as a separate entity. Finally, setting up a corporation can also make it easier for a business to enter an industry because it provides a legal framework for the business and can make it easier to raise capital.

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Answer:

h ≈ 6

Step-by-step explanation:

Using the formula:

\(V = \frac{1}{3} \pi r^{2} h\)     Or:   \(V = \pi r^{2} \frac{h}{3}\)

We can rearrange to make h the formula:

\(h = 3 \frac{V}{\pi r^{2} }\)

h= 3 (64/3.14×3.2²)

h = 3(64/3.14×10.24)

h=3(64/32.1536)

h=3(1.99044585987)

h= 5.97133757962

h ≈ 6

Answer: Gabriella's distance from the stadium is modeled by the function G(t) = 550 - 25t.

Ian's distance from the stadium is modeled by the function I(t) = 950 - 50t.

To find the number of hours after noon when Gabriella and Ian are the same distance from the stadium, we need to set the two equations equal to each other and solve for t:

G(t) = 550 - 25t = I(t) = 950 - 50t

Combining like terms we get:

25t = 400

t = 16

So, 16 hours after noon, Gabriella and Ian will be the same distance away from the stadium.

To graph the functions, we can substitute different values of t into the equations to find the corresponding values of G(t) and I(t). Then we can plot the points on a coordinate plane and connect them to form the graph of the two functions.

It is important to note that we are assuming that both Gabriella and Ian don't make any stops, so the speed is constant through the whole trip and no time is wasted.

Step-by-step explanation:

Answer:

\(volume \ of \ hemisphere = \frac{2}{3} \pi r^3 = \frac{2}{3}\pi \cdot (3)^3 = \frac{2}{3} \pi 27 = 2\pi \cdot9 = 18\pi cubicfeet\)

We are comparing the average gain in test scores for two different groups of girls - those assigned to coeducational chemistry classes and those assigned to single-sex chemistry classes. Since these gains are calculated from the data obtained from these specific groups of girls, they represent statistics rather than parameters.

In the given scenario:

The boldface number "12.2" represents a statistic.

The boldface number "15.1" represents a statistic.

A statistic is a numerical value that summarizes a sample of data, while a parameter is a numerical value that summarizes a population.

In this case, we are comparing the average gain in test scores for two different groups of girls - those assigned to coeducational chemistry classes and those assigned to single-sex chemistry classes. Since these gains are calculated from the data obtained from these specific groups of girls, they represent statistics rather than parameters.

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Answer: Sorry i can't see that brah

Step-by-step explanation: Thanks homie

Answer: Maybe both Domain and range are 0 to positive infinity in the graph shown here.

BUT

This graph seems incorrect because m squared would normally be a parabola, not a straight line.

Anyway. . .

Step-by-step explanation:

Range is normally the lowest y-value to the greatest y-value. You might remember that you go up and down over a mountain range.

In this graph, the solid dot on 0 means the lowest value is 0. The arrow goes to positive infinity.

Domain is the lowest x-value to the greatest x-value. Here, the domain is also 0 to positive infinity.

Answer:

Step-by-step explanation:

A. 9w33 - y12

B. 18p15-q21

C. 36a22-b16

D. 64c15 - d27

Answer:

Answer:

D. 64c15 - d27

Step-by-step explanation:

A. 9w33 - y12

No. 9 is not a perfect cube

B. 18p15-q21

No. 18 is not a perfect cube

C. 36a22-b16

No. 36 is not a perfect cube and 16 is not divisible by 3

D. 64c15 - d27

Yes. (4c^5)^3 - (d^9)^3

Step-by-step explanation:

Given that cos(A) = √5/6 with A in Quadrant 1, and tan(B) = 3/7 with B in Quadrant 1, the value of cos(A + B) is (3√31 + 7√5)/(6√58).

To find cos(A + B), we can use the cosine addition formula: cos(A + B) = cos(A)cos(B) - sin(A)sin(B).

Given that cos(A) = √5/6, we can find sin(A) using the Pythagorean identity:

sin(A) = √(1 - cos²(A))

= √(1 - (5/6)²)

= √(1 - 25/36)

= √(11/36)

= √11/6

Given that tan(B) = 3/7, we can determine cos(B) using the definition of tangent:

cos(B) = 1 / √(1 + tan²(B))

= 1 / √(1 + (3/7)²)

= 1 / √(1 + 9/49)

= 1 / √(58/49)

= 1 / (7/√58)

= √58/7

Now, we can calculate cos(A + B):

cos(A + B) = cos(A)cos(B) - sin(A)sin(B)

= (√5/6) * (√58/7) - (√11/6) * (3/7)

= (√5 * √58)/(6 * 7) - (3√11)/(6 * 7)

= (√290)/(42) - (3√11)/(42)

= (√290 - 3√11)/(42)

= (3√31 + 7√5)/(6√58)

Therefore, the value of cos(A + B) is (3√31 + 7√5)/(6√58).

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Factoring integers with sublinear resources on a superconducting quantum processor can be achieved using quantum approximate optimization algorithm" (QAOA) or quantum phase estimation algorithm (QPE) approach.

Factoring large integers is a problem of significant importance in the field of cryptography.

Classical computers have limited efficiency in solving this problem, and their performance is expected to decline further as the size of the integers to be factored increases.

In contrast, quantum computers are expected to have exponential speedup in factoring large integers, thanks to Shor's algorithm.

Recently, researchers have been exploring the possibility of using superconducting quantum processors to factor integers with sublinear resources.

One approach is to use a so-called "quantum approximate optimization algorithm" (QAOA), which maps the problem of factoring integers to a problem of finding the ground state of a certain Hamiltonian.

The QAOA can be implemented using a superconducting quantum processor, with the problem Hamiltonian implemented by a set of two-qubit gates.

Another approach is to use the quantum phase estimation algorithm (QPE) to estimate the eigenvalues of the problem Hamiltonian.

This can be used to factor integers by finding the period of a certain function using the quantum Fourier transform, as in Shor's algorithm. QPE can be implemented on a superconducting quantum processor using phase estimation circuits, which require only polynomial resources.

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Answer:

Cost of 1 pound if sliced ham = $4

Step-by-step explanation:

Mrs. Ruiz bought 4 1/4 pounds of sliced ham for $17. At that rate, what is the cost of 1 pound of sliced ham?

Total pounds of ham bought= 4 1/4 pounds

Total cost = $17

what is the cost of 1 pound of sliced ham

Cost of 1 pound if sliced ham = Total cost of 4 1/4 sliced ham / 4 1/4

= $17 ÷ 17/4

= 17 × 4/17

= 4

Note:4 1/4 = 17/4

Cost of 1 pound if sliced ham = $4

Check:

4 1/4 pounds × $4 per pound

= 17/4 × 4

= $17

Based on the given side lengths (a=16 mm, b=63 mm, c=65 mm), the triangle is a(n) right triangle. This is because it satisfies the Pythagorean theorem: a² + b² = c² (16² + 63² = 65²).

A right triangle is a triangle with two perpendicular sides and one angle that is a right angle (i.e., a 90-degree angle). The foundation of trigonometry is the relationship between the sides and various angles of the right triangle.

The hypotenuse, or side c in the illustration, is the side that is opposite the right angle. Legs are the sides that meet at the correct angle. Side a may be thought of as the side that is opposite angle A and next to angle B, whereas side b is the side that is next to angle A and next to angle B.

A right triangle is considered to be a Pythagorean triangle and its three sides are referred to as a Pythagorean triple if the lengths of all three of its sides are integers.

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To sketch the curve, we can analyze the equation y = 3x^2 - 25. This is a quadratic function with a coefficient of 3 for the x^2 term and a constant term of -25.

Determine the vertex: The vertex of the parabolic curve can be found using the formula x = -b / (2a). In this case, a = 3 and b = 0. Therefore, the x-coordinate of the vertex is 0.

Determine the y-intercept: Substitute x = 0 into the equation to find the y-intercept. y = 3(0)^2 - 25 = -25. Hence, the y-intercept is (0, -25).

Plot the vertex and y-intercept: Plot the point (0, -25) for the y-intercept and mark the vertex at (0, 0).

Find additional points: To draw the curve, choose a few more x-values and calculate the corresponding y-values. For example, you can choose x = -2, -1, 1, and 2. Substitute these values into the equation to find the corresponding y-values.

Plot the points and sketch the curve: Use the obtained points to plot them on the graph and connect them smoothly to sketch the curve. Since the coefficient of x^2 is positive, the curve opens upward.

By following these steps, you can sketch the curve represented by the equation y = 3x^2 - 25.

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Answer:

The answer to your problem is negative 9