plz help this was due yesterday butttttt i didn’t want to do it...

Answer:

Hydrogen

Explanation:

It is pretty much present everywhere :)

Answer: 0.8 liters

Explanation:

Given chemical reaction is:

N₂ + 3H₂ → 2NH₃

From the stoichiometry of the reaction, it is clear that:

3 liters of H₂ = produce 2 liters of NH₃

1.2 liters of H₂ = produce 2/3 × 1.2 = 0.8 liters of NH₃

(If it says 0.80, that's the same as 0.8!)

Answer: 0.8 liters

Explanation: Given chemical reaction is:N₂ + 3H₂ → 2NH₃From the stoichiometry of the reaction, it is clear that:3 liters of H₂ = produce 2 liters of NH₃1.2 liters of H₂ = produce 2/3 × 1.2 = 0.8 liters of NH₃(If it says 0.80, that's the same as 0.8!)

Answer: l

2

+

2

K

B

r

→

2

K

C

l

+

B

r

2

Given:

300

g

of

C

l

2

300

g

of

K

B

r

(a) Mass of

C

l

2

= 300g

Molecular mass of

C

l

2

= 2(35.45) = 70.906 g

/

m

o

l

No.of moles of

C

l

2

=

m

a

s

s

/

m

o

l

a

r

m

a

s

s

=

300

/

70.906

=

4.23

moles

Mass of

K

B

r

=

300

g

Molar mass of

K

B

r

=

39

+

79.9

=

118.9

g

/

m

o

l

No.of moles of

K

B

r

=

300

/

118.9

=

2.52

moles

Now,

Consider the equation:

C

l

2

+

2

K

B

r

→

2

K

C

l

+

B

r

2

1

mole of

C

l

2

= 2 moles of

K

C

l

4.23

moles of

C

l

2

= 2x4.23=

8.46

moles

2

moles of

K

B

r

= 2 moles of

K

C

l

2.52

moles of

K

B

r

=

2.52

moles

Now convert moles to mass,

Mass of

K

C

l

produced by

C

l

2

=

8.46

×

70.906

=

599.8

g

Mass of

K

C

l

produced by potassium bromide =

2.52

×

74.5

=

187.74

g

As

K

B

r

is producing lesser moles of product so,

K

B

r

is limiting reactant and produced potassium chloride=

187

Explanation:

Taking into account the reaction stoichiometry, 1 mol of KCl is formed from 119 grams of KBr.

In first place, the balanced reaction is:

Cl₂ + 2 KBr → 2 KCI + Br₂

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

The molar mass of the compounds is:

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

The following rule of three can be applied: if by reaction stoichiometry 238 grams of KBr form 2 moles of KCl, 119 grams of KBr form how many moles of KCl?

\(moles of KCl=\frac{119 grams of KBrx2 moles of KCl}{238 grams of KBr}\)

moles of KCl= 1 mole

Then, 1 mol of KCl is formed from 119 grams of KBr.

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⟪ The microwave properties of dielectric materials are usually tuned by chemical methods like doping, slight nonstoichiometric, formation of solid solution or mixtures of dielectrics with opposite τf [1–7]. ⟫

What's the effect of surface area change

We know

Pressure is indirectly proportional to area

The given parameters of the problem are:

Calculate the number of moles in 75. 0 g of dinitrogen trioxide.

First, we need to find the molar mass of dinitrogen trioxide (N₂O₃) which is the sum of the atomic masses of each element in the compound.

Therefore, its molar mass is:

Molar mass of N₂O₃ = (2 × molar mass of N) + (3 × molar mass of O)

= (2 × 14.01 g/mol) + (3 × 16.00 g/mol)

= 28.02 g/mol + 48.00 g/mol

= 76.02 g/mol

Next, we will use the formula to calculate the number of moles:

moles = mass/molar mass

Given mass of dinitrogen trioxide = 75.0 g

Molar mass of dinitrogen trioxide = 76.02 g/mol

Now, we can calculate the number of moles of dinitrogen trioxide as follows:

moles = 75.0 g/76.02 g/mol

= 0.9878 mol

Therefore, the number of moles in 75.0 g of dinitrogen trioxide is 0.9878 mol.

Note: The answer should be rounded to four significant figures since the given quantity, 75.0 g, has four significant figures

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Dinitrogen trioxide is a molecule that contains two nitrogen atoms and three oxygen atoms. To calculate the number of moles of dinitrogen trioxide in 75.0 g, we need to use its molar mass. The molar mass of dinitrogen trioxide (N2O3) can be calculated as follows.

Molar mass of N2O3 = (2 x molar mass of N) + (3 x molar mass of O)The molar mass of nitrogen (N) is 14.01 g/mol, and the molar mass of oxygen (O) is 16.00 g/mol. Therefore: Molar mass of N2O3 = (2 x 14.01 g/mol) + (3 x 16.00 g/mol)= 28.02 g/mol + 48.00 g/mol= 76.02 g/mol.

Now, we can use the molar mass to calculate the number of moles in 75.0 g of dinitrogen trioxide:Number of moles = mass / molar mass= 75.0 g / 76.02 g/mol= 0.987 moles Therefore, there are 0.987 moles in 75.0 g of dinitrogen trioxide. This answer is more than 100 words.

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Answer:

Explanation:

Vale, y entonces que ahora???

Answer:

friction

Explanation:

conduction doesn't really need much to start it. it basically has that reaction from the start so it's not conduction. Since heat is produced by friction in this situation it causes static to happen. so i think its friction

Answer:

P4O10 + H2O → H3PO4

Explanation:

Answer: The nebular theory is an explanation for the formation of solar systems.

Explanation:

Answer:

Two similar atoms or different atoms

Explanation:

A molecule is made up of at least two similar atoms or different atoms.

A molecule is the smallest particle of a substance capable of independent existence.

Answer: Two similar atoms or different atoms.

Have a great day!

Answer

Volume of O2 = 1326 L

Explanation

Given:

2C8H18(I) + 25 O2 (g) = 16 CO2(g) + 18 H2O (g)

moles of gasoline = 4.00 mol

Pressure = 0.953 atm

Temperature = 35 C = 308 K

Required: volume of oxygen

Solution

Step 1: use stoichiometry to find the moles of oxygen

The molar ratio between gasoline and O2 is 2:25

Therefore the moles of o2 = 4.0 mol x (25/2) = 50.0 mol

Step 2: Calculate the volume using ideal gas law

PV = nRT

V = nRT/P

V = (50.0 x 0,08206 x 308)/0.953

V = 1326 L

Answer: there is no photo so we can’t answer it:)

Explanation:

Answer: organic

Explanation:

Answer:

ionic

Explanation:

The elements that would be the equivalent of the noble gases are the group 18 elements. This group is also known as the noble gases.

The elements in this group are helium (He), neon (Ne), argon (Ar), krypton (Kr), xenon (Xe), and radon (Rn). These elements are called noble gases because they are very stable and don't easily react with other elements. Their electron configurations make them particularly unreactive. They all have a full outer shell of electrons, which makes them stable. In addition, these elements have very low boiling points and are all gases at room temperature. Additionally, noble gases have low boiling points, existing as gases at room temperature. These unique properties make noble gases valuable in various applications, including lighting, cryogenics, and as non-reactive atmospheres in industrial processes.

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Molar expansion accounts for the changes in the number of moles of a component within a reactor and can have a significant impact on the volume of a plug flow reactor, particularly in cases where the reactor volume is not constant.

(iii) "ei" is commonly used to represent the molar expansion term in chemical reaction engineering equations. It refers to the change in molar flow rate of a particular component i per unit time, per unit volume. The molar expansion term accounts for the variation in the number of moles of a component within a reactor due to chemical reactions or phase changes.

In a plug flow reactor, molar expansion can have different impacts on the reactor volume depending on the specific case. In part (i), where there is a constant volume, the molar expansion does not affect the reactor volume. The molar flow rates of reactants and products may change due to reactions, but the overall volume remains constant.

In part (ii), where the reactor is a semi-batch reactor with a varying volume, the molar expansion can significantly influence the volume of the reactor. As the reaction proceeds, the molar flow rates of reactants and products change, which can lead to changes in the total number of moles and, consequently, impact the reactor volume. The volume may increase or decrease depending on the molar expansion and the specific reaction taking place.

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The percent yield of the iodination reaction is 96%.  To calculate the percent yield of the iodination reaction, we need to know the amount of iodine produced and the amount of iodine that was expected to be produced based on the amount of reactant used.

The amount of iodine produced can be calculated using the balanced chemical equation for the reaction:

2NaI + 3C₆H₅OH + O2 → 2NaIO₃ + 3CO₂ + 3H₂O

The stoichiometric coefficients for this reaction are:

2NaI (1 mol) + 3C₆H₅OH (1 mol) + O₂ (2 mol) → 2NaIO₃ (1 mol) + 3CO₂ (1 mol) + 3H₂O (1 mol)

The molarity of the sodium iodide solution is 0.3 M, and the volume of the solution is 9.2 mL. Therefore, the number of moles of sodium iodide in the solution is:

0.3 mol * 0.3 L / 1 L/mol = 0.096 mol

The volume of the sodium hypochlorite solution is 9.2 mL, and the number of moles of sodium hypochlorite in the solution is:

0.3 g / 149.89 g/mol = 0.020 mol

The volume of the sodium hypochlorite solution is 9.2 mL / 0.020 mol = 46.4 mL

The number of moles of iodine produced is:

2 * 0.096 mol = 1.92 mol

The expected yield of iodine is the number of moles of iodine produced based on the amount of reactant used. In this case, the expected yield is 2 moles, since there are 2 moles of sodium iodide in the reaction.

Therefore, the percent yield of the iodination reaction is:

(1.92 mol / 2 mol) * 100% = 96%

The percent yield of the iodination reaction is 96%.  

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Calcium element with symbol Ca has an atomic number of 20 has electron configuration  [Ar] 4s² .

Electrons start filling orbitals in increasing energy levels.

First energy shell contains the s orbital which can hold only 2 electrons.

Second energy shell contains a both p orbital and s orbital, p orbital can hold upto 6 electrons, so a total of 8 electrons in the 2nd shell.

Third energy shell contains s, p and d orbital. d orbital can hold upto 10 electrons, so the third shell can hold up to 18 electrons.

electronic configuration of Ca is 1s² 2s² 2p⁶ 3s²3p⁶ 4s²

we are asked to write in the condensed form, which means we have to write the noble gas with the nearest electronic configuration to Ga.

Noble gas with electronic configuration closest to Ca is neon with atomic number 18.

Ar  - 1s² 2s² 2p⁶ 3s²3p⁶

Ca in condensed form - [Ar] 4s²

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Answer:

See explanation

Explanation:

Given that the row number is the same as the period or energy level(shell) in which the electron is found.

If we designate this row number as "n", we know that the  highest principal energy level for the f orbitals is obtained as (n-2) f.

Thus, we obtain the highest principal energy levels for the "f block" elements by subtracting 2 from  the row number.

Answer:

si estoy de acuerdo cien por ciento

Answer:

C) DC power source

(2nd picture shows all the symbols so you can answer the other question)

Explanation:

Edmentum/Plato

Metal wires are generally used in electric circuits because metals are good conductors of electricity and allow current to pass through them. Here the component DC power source is represented. The correct option is C.

A DC power supply is defined as a type of power supply which gives the direct current (DC) voltage to power a device. Because DC power supply is commonly used on an engineer's or technician's bench for a ton of power tests, they are also often called a bench power supply.

In direct current circuits, the flow of electrical charge is unidirectional and unlike AC current, it does not periodically reverse its direction. This form of power is most commonly produced by sources such as solar cells, batteries, and thermocouples.

DC power is commonly used in low voltage applications such as charging batteries, automotive applications and air craft applications.

Thus the correct option is C.

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Answer:

Nitrogen gas is the limiting reactant

Hydrogen gas is the excess reactant

The theoretical yield is 425 g of ammonia

Explanation:

Equation of reaction: 3H2 + N2 ---> 2NH3

From the equation of reaction, 3 moles of hydrogen gas reacts with 1 mole of nitrogen to produce 2 moles of ammonia gas.

Molar mass of hydrogen gas = 2.0 g

Molar mass of nitrogen gas = 14.0 g

Molar mass of ammonia gas = 17.0 g

Number of moles of hydrogen gas in 250 g = 250/2 = 125 moles

Number of moles of nitrogen gas in 175 g = 175/14 = 12.5 moles

Mole ratio of Hydrogen to Oxygen = 125/12.5 = 10 : 1

Therefore, nitrogen gas is the limiting reactant.

Hydrogen gas is the excess reactant

14 g of nitrogen gas produces 17 × 2 g of ammonia = 34 g of ammonia

175 g will produce (34 × 175)/14 = 425 g of ammonia

Therefore the theoretical yield is 425 g of ammonia

Answer:

the water which are very healthy is known as hydrated water

Electron pair repulsion is the repulsion of electron pairs in a molecule which determines the molecular geometry. This repulsion is caused by negative charges, which causes electron pairs to move away from each other. As a result, the molecular shape that allows for the maximum separation between electron pairs is the most stable.

Electron pair repulsion theory (VSEPR) is a technique used to explain how molecules take on their shapes. This theory is based on the idea that electrons repel each other, and the way they are arranged around the central atom determines the molecular shape. This theory states that the arrangement of atoms, along with the lone pairs around a central atom, is mainly determined by the electrostatic repulsion between the electrons, especially in the valence shell.In brief, electron pair repulsion is the theory that explains how electrons behave when they are in close proximity to each other. The theory, in turn, helps to explain the molecular shape that is produced when certain atoms bond together to form molecules.There are various different geometries and shapes of molecules depending on how the electrons are arranged. The molecular geometry is dependent on the position of atoms surrounding the central atom. In summary, the electron pair repulsion theory is the backbone of the VSEPR model which is useful in predicting the shapes and arrangements of molecules.

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The molar concentration of acetic acid in the vinegar is 0.611M

Molar concentration is the most convenient method of expressing the concentration of a solute in the given solution. Molarity is the number of moles of the solute dissolved per liter of the solution.

Thus M = mol per L.

All mole calculations will determine the amount in moles of the solution, for which it is the molar concentration.

Given,

Concentration of NaOH = 0.1906M

Volume of NaOH = 32.1 ml

Volume of acetic acid = 10 ml

During neutralization, the number of moles of acid is the same as the number of moles of base.

concentration of NaOH × Volume = Concentration of acetic acid × volume

0.1906 × 32.1 = Concentration of acetic acid × 10

Concentration of acetic acid = 0.611 M

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Answer: This is the process of chemical change. Examples of chemical properties are flammability (a material's ability to burn in the presence of oxygen) and reactivity (how easily a material combines chemically with other materials).

Explanation: Chemical properties are properties that can be measured or observed only when matter undergoes a change to become an entirely different kind of matter. They include reactivity, flammability, and the ability to rust. ... Flammability is the ability of matter to burn. Burning of wood is a chemical change as new substances which cannot be changed back (e.g. carbon dioxide) are formed. For example, if wood is burned in a fireplace, there is not wood anymore but ash. ... Special details which do not change in a substance without new substances being formed are called physical properties.

Answer:

chemical property

Explanation:

first, we need the molar mass of HNO3(azotic acid) it's equal to 1AH+1AN+3AO(where A is the atomic mass of the element present within the molecule and, it's multiplied by how many times it's present)=1*1+1*14+3*16=15+54=69g/mole

now we multiply the molar mass with the number of moles 69*1.2=82.8 grames

Answer:

1s22s22p32d6

Explanation:

is a reasonable electron configuration