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1. A rocket has a mass of 0.8 kg and an engine that provides 100 N of force. A second rocket is being designed to use the same engine but accelerate at half the rate of the first rocket. What is the mass of the second rocket?

a. 0.4 kg
b. 1.6 kg
c. 2.4 kg
d. 0.8 kg


2. Which of the following would be a situation with unbalanced forces?

a. Two people pulling on the same side of a wheelbarrow
b. A team of players in tug of war pulling on the rope, each team with equal numbers of people pulling with equal strength
c. Two people of opposite sides of a big tire. One pushes the tire and one pulls it with equal force
d. Two people not touching a crate that is sitting stationary.


3. Why is it generally easier to push a heavy object that is already moving instead of the same heavy object that is stationary

a. The force of gravity on the object is different if it is stationary or not.
b. The force of friction on the object is different if it is stationary or not
c. The force of the push on the object is different if it is stationary or not
d. The normal force on the object is different if it is stationary or not.

Thanks In Advance!! (I will mark brainliest) :)

An astronaut measure the period of a mass spring system on Earth.

The period of a mass spring system on the moon would be longer than the period on Earth. This is because the period of a mass spring system is dependent on the square root of the ratio of the mass to the spring constant, and the acceleration due to gravity. Since the acceleration due to gravity on the moon is only 1/6th of that on Earth, the restoring force on the mass will be weaker, resulting in a longer period. Therefore, the astronaut would measure a longer period for the same mass spring system on the moon than on Earth.

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Answer:

The difference between the positions of the two events as measured in = 3.53 *10^8 m/s

Explanation:

As we know -

\(\Delta x = -\gamma \mu\Delta t\)

Here,

\(\Delta x\) is the difference between the positions of the two events as measured in S^

\(\gamma\) \(= \frac{1}{\sqrt{1-\frac{\mu^2}{c^2} } }\)

And

\(\mu\) = 0.547 c

Substituting the given values in above equation, we get -

\(\Delta x = (0.547 c)*\frac{1}{\sqrt{1-\frac{\mu^2}{c^2} } }*2.15\\\Delta x = (0.547 c)*\frac{1}{\sqrt{1-\frac{(0.547 c)^2}{c^2} } }*2.15\\\Delta x = (0.547 *3*10^8)*\frac{1}{\sqrt{(1-\(0.547 )^2 } }*2.15\\\Delta x = 3.53 *10^8\)meter per second

The magnitude of the resulting angular acceleration about the pivot point is approximately 0.0021 rad/s^2.

To solve this problem, we need to use the equation for the torque on a rigid body:

τ = Iα

where τ is the torque, I is the moment of inertia, and α is the angular acceleration. We can also use the fact that the torque is given by:

τ = r × F

where r is the vector from the pivot point to the point of application of the force, and F is the force. The vector cross product r × F gives the torque about the pivot point.

First, we need to find the vector r. Since the force is acting at an angle of 95° to the horizontal, the vertical component of the force is given by:

Fy = F sin(95°) = 1.5 sin(95°) ≈ 0.15 N

The horizontal component of the force is given by:

Fx = F cos(95°) = 1.5 cos(95°) ≈ 0.04 N

The vector r points vertically downward from the pivot point and has a magnitude equal to half the length of the rod:

|r| = 0.5(1.9 m) = 0.95 m

Therefore, the vector r is given by:

r = -0.95j

where j is the unit vector in the vertical direction.

The torque about the pivot point is given by:

τ = r × F = (-0.95j) × (0.04i + 0.15j) = -0.15k

where i is the unit vector in the horizontal direction and k is the unit vector in the direction perpendicular to the plane of the rod and pointing out of the page.

Substituting the moment of inertia and torque into the equation for angular acceleration, we have:

α = τ/I = (-0.15k)/(930.02/12) ≈ -0.0021 rad/s^2

Therefore, the magnitude of the resulting angular acceleration about the pivot point is approximately 0.0021 rad/s^2.

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Answer:

nothing moves if anything other doesn't move it.

natural position of things is the resting

Explanation:

yeah that's it

Answer:

The book does not move because all the forces acting on the book are in equilibrium, creating a net force of zero magnitude on the book. Since the net force on the book is zero, this means that the book will remain in its present state of motion (which is that the book is motionless).

Explanation:

Newton's first law states that all body will remain in  their present state of motion unless acted upon by an external force. In order word, a moving body should continue moving forever, and a body at rest should remain like that forever, unless they are acted upon by a force to either cause them to stop stop or to start moving respectively.

Let the circumference of the circle be 10L.

A moves at 10L/2 = 5L per hour

B moves at 10L/5 = 2L per hour

Therefore it takes 10L/(5L+2L) = 10/7 hours

ANSWER:

False​

STEP-BY-STEP EXPLANATION:

A body can have a constant velocity and continue to accelerate. Acceleration can be due to a change in speed or due to the direction of motion or both. For example, in uniform circular motion the body moves with a constant velocity but we still say that it is accelerating due to the change of direction (centripetal acceleration).

Therefore the statement is false

Answer:

A

Explanation:

The force on the test charge is 14 N.

When a test charge is placed in an electric field, it experiences a force. The strength of the electric field is measured in newtons per coulomb, and the magnitude of the force exerted on the test charge is proportional to the amount of charge on it. The formula to calculate the force is given by:

F = q*E

where F is the force, q is the amount of charge on the test charge, and E is the strength of the electric field. Given:

Test charge = 2 C CoulombsElectric field = 7 N/C

Using the formula above,

F = q*E = 2C * 7N/C = 14 N

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The linear velocity of the CD is 1.03 m/s.

We know that the angular velocity and the linear velocity are related by the use of the formula;

v = rω

v = velocity of the body (linear)

r = radius of the body

ω = angular velocity

Given that we have to convert from rpm to rad/s

1 RPM = 0.10472 rad/s

180 RPM =  180 RPM * 0.10472 rad/s/1 RPM

= 18.7 rad/s

We know that radius = diameter/2 = 110 millimeters/2 = 55 millimeters or 55 * 10^-3 m

Substituting values;

v = 55 * 10^-3 m *  18.7 rad/s

v = 1.03 m/s

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Answer:

v = (1500/10) = 150 [miles/h]

Explanation:

The velocity can be easily calculated using the following kinematics expression:

v = x/t

where:

v = velocity [miles/h]

t = time = 10 [hr]

x = distance = 1500 [miles]

v = (1500/10) = 150 [miles/h]

Answer:

Explanation:

3.  answer is d.

Displacement increases b/c slopes of both lines are positive. Spring 1 displaces more than Spring 2 per unit force applied.  Graphs are straight lines, so the increase is proportional.

4.  Fnet = 5 - 30 - 5 = -30 N       Positive direction is to the right, negative direction is to the left.

answer is d. 30 N to the LEFT

Answer:

when gravitational force suddenly disappears, then only centrifugal force will be acting and velocity is tangential to the orbit and hence, the satellite will fly off tangentially with same velocity v.

Answer: U(0) = 0 + C_{1},

V(b) = - 16t + v_{0}, displacement

S(t) = integrate vu * t ^ 2 dt = - 8t ^ 2 + v_{0}*t + c_{e} s(0) = 0 - Cx

How do you find the displacement between two points?

Δx = xf − xi = 3 − 0 = + 3 m, i.e. to the right. So, the ball has traveled 3 meters from A to B. Now the ball has moved −4 points or −4 m to point C. Therefore, the final position now becomes the initial position and the final position, xi = − 4 m.

What is displacement and How Is It measured?

Displacement measurement, simply speaking, is the change in length, usually by calculating the number of sides when the measured object (or reference surface) is moved.

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The displacement from the point where the driver sees a traffic light turn red is 3 m.

Δx = xf − xi = 3 − 0 = + 3 m, i.e. to the right. So, the ball has traveled 3 meters from A to B. Now the ball has moved −4 points or −4 m to point C. Therefore, the final position now becomes the initial position and the final position, xi = − 4 m.

Displacement measurement, simply speaking, is the change in length, usually by calculating the number of sides when the measured object (or reference surface) is moved.

U(0) = 0 + \(C_{1}\),

V(b) = - 16t + \(v_{0}\), displacement

S(t) = integrate vu * t²dt = - 8t² + \(v_{0}\) *t + \(c_{e}\) s(0)

= 0 - Cx

Δx = xf − xi

= 3 − 0

= +3 m

Thus, the displacement from the point where the driver sees a traffic light turn red is 3 m.

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Answer:

0

Explanation:

0 is the answer

Answer:

a) 0.47MW

b) 39.24%

Explanation:

In order to find the power needed for the elevator to operate at its maximum capacity, we can make use of the following formula:

P=Fv

where P is the power, F is the force and v is the velocity.

The force the elevator must carry can be calculated with the following formula:

F=mg

where m is the mass of the elevator and g is the acceleration of gravity, so:

\(F=(8000 kg)(9.81 m/s^{2})\)

F=78 480 N

so now we can make use of the power formula:

P=Fv

P=(78 480N)(6 m/s)

P=470 880W

P=0.47W

b)

In order to find the efficiency, we will suppose that the generator can generate a maximum of 0.47 W so we use the following formula:

\(efficiency = \frac{P_{in}}{P_{out}}*100\%\)

\(efficiency=\frac{0.470880}{1.2}*100\%\)

efficiency=39.24%

Answer:

See below

Explanation:

rho = R A/l     R = resistance   A = cross sectional area l = length

Answer:

the intellectual and practical activity encompassing the systematic study of the structure and behaviour of the physical and natural world through observation and experiment.

Explanation:

Mark's work decreases when he climbs the same flight of stairs again in the same amount of time without the cello.

The correct answer is option D.

The amount of work Mark does depends on the weight of the cello, as well as the distance he climbs and the time it takes. Work is calculated using the formula :

Work = Force × Distance.
In the given scenario, Mark is carrying a full-sized cello while climbing the stairs. The weight of the cello adds to the force he exerts. So, the total force Mark exerts is the weight of the cello plus his own weight (375 N).

When Mark climbs the stairs with the cello, he is doing work against the force of gravity.

The work done is equal to the force exerted multiplied by the distance climbed (375 N + weight of cello) × 4 m.

Now, if Mark were to climb the same flight of stairs again in the same amount of time (3 seconds), but this time without the cello, the amount of work he does would decrease. This is because without the cello, the force exerted would only be Mark's weight (375 N), which is less than the total force exerted with the cello.

Therefore, mark's work decreases.

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Answer:

E.

Explanation:

becasue E. is everything

Vehicles need to be serviced for several reasons such as preventing costly repairs and improving fuel economy.

First, regular maintenance can help to prevent costly repairs down the road. Second, maintenance can help to improve fuel economy and emissions. Third, maintenance can help to keep your vehicle safe and reliable.

The servicing requirements for petrol/diesel and electric vehicles differ in a number of ways. Petrol/diesel vehicles require oil changes more frequently than electric vehicles. This is because petrol/diesel engines use oil to lubricate the moving parts, while electric motors do not. Petrol/diesel vehicles also require tune-ups more frequently than electric vehicles.

This is because petrol/diesel engines have more moving parts that need to be synchronized, while electric motors have fewer moving parts.

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Answer: mass is neither created nor destroyed

Explanation: For example, the carbon atom in coal becomes carbon dioxide when it is burned. The carbon atom changes from a solid structure to a gas but its mass does not change.

Answer:

The ratio is  \(\frac{I_{min}}{I_{max}} = 0.029\)

Explanation:

Let assume that the intensity of the unpolarized  photon beam is  \(I_o\)

   The through the linear polarizer is mathematically represented as

       \(I_1 = I_ocos^2(\theta )\)

Here \(\theta = 0\) given that the polarizer is  linear

   So

        \(I_1 = I_o\)

The intensity of the \(I_o\)  emerging from the polarizer oriented 45° to the horizontal is  

         \(I_2 = I_o cos^2(45)\)

       \(I_2 = \frac{I_o}{2}\)

The maximum photon probability density is  mathematically represented as

          \(I_{max} = ( \sqrt{I_1} + \sqrt{I_2})^2\)

=>      \(I_{max} = ( \sqrt{I_o} + \sqrt{\frac{I_o}{2} })^2\)

The minimum photon probability density is  mathematically represented as

        \(I_{max} = ( \sqrt{I_1} - \sqrt{I_2})^2\)

        \(I_{max} = ( \sqrt{I_o} - \sqrt{\frac{I_o}{2} })^2\)

The ratio of minimum to maximum is mathematically represented as

          \(\frac{I_{min}}{I_{max}} = \frac{ I_o - \frac{I_o}{I_2} }{I_o + \frac{I_o}{I_2}}\)

         \(\frac{I_{min}}{I_{max}} = \frac{I_o (1 - \frac{1}{\sqrt{2} } ) }{I_o(1 + \frac{1}{\sqrt{2} })}\)

        \(\frac{I_{min}}{I_{max}} = \frac{(\sqrt{2} - 1 )^2}{(\sqrt{2} + 1 )^2}\)

       \(\frac{I_{min}}{I_{max}} = \frac{0.17157}{5.8284}\)

       \(\frac{I_{min}}{I_{max}} = 0.029\)

Answer: A flower pot falling

Explanation:

The car on the curve (its direction is changing) and the falling flower pot (its speed is changing) are both undergoing acceleration.

Each of the five friends needs to pay £12 to cover the cost of their own meals and contribute towards the birthday person's meal. Using mean allows us to distribute the cost equally among the friends, ensuring a fair division of expenses for the meal.

To determine how much each of the five friends needs to pay, we can use the concept of averages (mean) and divide the total cost by the number of people paying.

In this scenario, the total cost of the meal for 6 people is £12 per person. Since the other 5 friends have decided to pay for the birthday person's meal, they will collectively cover the cost of their own meals plus the birthday person's meal.

To calculate the total cost covered by the five friends, we can subtract the cost of one person's meal (since the birthday person's meal is being paid by the group) from the total cost. The cost of one person's meal is £12.

Total cost covered by the five friends = Total cost - Cost of one person's meal

= (£12 x 6) - £12

= £72 - £12

= £60

Now, to find out how much each of the five friends needs to pay, we divide the total cost covered by the five friends (£60) by the number of friends (5).

Amount each friend needs to pay = Total cost covered by the five friends / Number of friends

= £60 / 5

= £12

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Answer:

the tension in the string is 5.59 N

Explanation:

Here ,

m_1 = 0.385 Kg

m_2 = 0.710 Kg

Using second law of motion ,

a = F_net / effective mass

a = (0.710- 0.385)×9.8/(0.710 + 0.385 + 0.0125/0.15^2)

a = 1.93 m/s^2

Now , let tension be T ,

then,

mg-T=ma

0.710×g - T = 0.710×1.93

T = 5.59 N

the tension in the string is 5.59 N

Answer:

Explanation:

       Kirchhoff's Current Law, often shortened to KCL, states that “The algebraic sum of all currents entering and exiting a node must equal zero.

           #I AM ILLITERATE

Answer:

A = 21 î + 28 ĵ

B = 12 î + 5 ĵ

Explanation:

a.

To write A and B in terms of î and ĵ, we need to use the trigonometric ratios and the vector notation

According to the diagram, we have:

tan a = 4/3 tan ß = 5/12

Using the identity tan θ = opposite/adjacent, we can find the x and y components of A and B.

For A, we have:

x component = 35 cos a y component = 35 sin a

Using tan a = 4/3, we can find cos a and sin a by using Pythagoras’ theorem:

cos a = 3/5 sin a = 4/5

Therefore, the x and y components of A are:

x component = 35 cos a = 35 (3/5) = 21 y component = 35 sin a = 35 (4/5) = 28

Using the vector notation, we can write A as:

A = 21 î + 28 ĵ

Similarly, for B, we have:

x component = 13 cos ß y component = 13 sin ß

Using tan ß = 5/12, we can find cos ß and sin ß by using Pythagoras’ theorem:

cos ß = 12/13 sin ß = 5/13

Therefore, the x and y components of B are:

x component = 13 cos ß = 13 (12/13) = 12 y component = 13 sin ß = 13 (5/13) = 5

Using the vector notation, we can write B as:

B = 12 î + 5 ĵ

b.

To show that A + B makes an angle of 45° to the x-axis, we need to find the resultant vector R and its angle θ with the x-axis.

To find R, we can use the vector addition rule :

R = A + B R = (21 î + 28 ĵ) + (12 î + 5 ĵ) R = (21 + 12) î + (28 + 5) ĵ R = 33 î + 33 ĵ

To find θ, we can use the inverse tangent function :

tan θ = y component / x component tan θ = 33 / 33 tan θ = 1

θ = tan^-1(1) θ = 45°

Therefore, A + B makes an angle of 45° to the x-axis.

Answer:

Am doing well am fine thank you

The free body diagram of the given system will include a normal force of value 9 Newton perpendicular to the surface with friction force at 30° with 12 newton force and the weight of 15 Newton pointing downwards.

Free body diagram refers to the formation of a system showing all the possible forces that are being exerted on the body isolating it from the surrounding.

System refers to the object of inspection i.e. the thing that is being noted down a system can be anything from an object to multiple objects and even surrounding whereas surrounding is everything else that is not a part of the system.

We have been already given all the required inputs that will help us to create a free body diagram including:

Friction force on the body being = 12 Newton

Weight of the body = 15 Newton

Normal acting on the body = 9 Newton

To create the free body diagram we simply isolate or from the surrounding and consider it to be a system then help of the vectors we will create the system consisting of the body and all the possible forces that acting on it.

We now draw the vectors for friction force weight of the body and normal acting on the body to get our required free body diagram.

Therefore, the free body diagram of the given system will include a normal force of value 9 Newton perpendicular to the surface with friction force at 30° with 12 newton force and the weight of 15 Newton pointing downwards.

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