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Exploring large amount of data in other to explore underlying trends which cannot be uncovered by visual inspection or simple algorithms are analysed using Data mining.

Data mining are often performed using a network of interconnected computed or networks with very high processing capability and can handling high computational complexity due to the very large amount of data involved when data is being mined.

Linear regression are used on small data sets which cannot be compared to the vast amount of data involved in data mining.

Hence, data mining helps to uncover trends when exploring very large datasets.

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A. The distribution of the average price of 41 textbooks is approximately normal with a mean of $155 and a standard deviation of ($25 / sqrt(41)).

B. To find the probability that the average price is between $161 and $164, first calculate the z-scores for $161 and $164 using the formula: z = (x - mean) / (standard deviation / sqrt(n)). Next, find the probability by using a z-table or calculator.

C. To find the 95th percentile for the average textbook price, use the formula: mean + (z-score * standard deviation / sqrt(n)). The z-score for the 95th percentile is approximately 1.645. Plug in the values and round to the nearest cent.

D. To find the 95th percentile for an individual textbook price, use the formula: mean + (z-score * standard deviation). Plug in the values and round to the nearest cent.

For part B, the assumption that the distribution is normal is necessary to accurately calculate the probability.

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Answer:

9.

Step-by-step explanation:

The square root of 10 is approximately 3.16 so it would be closer to 9.

Answer:

What is the question?

Step-by-step explanation:

Comment it

Answer:

same i feel you bru

Step-by-step explanation:

i'm actually, uh, procrastinating on brainly. can i vent? actually i will anyways so here: i have an science quiz on space and the moon phrases and i barely payed attention in class so i don't even know how to solve half of the problems. i normally always do ok on quizzes but i feel like this one is different and i'm going to fail. it's due by today at midnight and i'm procrastinating on brainly to take my mind away from reality. i know i'm being a total coward by trying to avoid what is my own consequences but... here i am haha ;-; it would be better if i at least started studying now even if it's short  to get my grade up just a little but i'm scared to even look at the quiz. i also have a lot of homework and an essay that's due tomorrow that i haven't started on yet... and yet i procrastinate. i don't understand myself and sometimes i want to cry because i don't know why i'm like this. i feel like the more homework i get, the more i procrastinate. i'm miserable really.

The table for the marginal product is as below

workers    output     marginal product

10                0                 -

20               80               8

30               140              6

40               180              4

The marginal product is computed by dividing the change in the output functions by the change in the input functions.

first

(80 - 0) / (20 - 10)

= 80 / 10

= 8

second

(140 - 80) / (30 - 20)

= 60 / 10

= 6

third

(180 - 140) / (40 - 30)

= 40 / 10

= 4

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Answer:

Step-by-step explanation:

7, 14, 21, 28, 35, 42, 49, 56, 63, 70, ... 8, 16, 24, 32, 40, 48, 56, 64, 72, 80, ... 9, 18, 27, 36, 45, 54, 63, 72, 81, 90, ... 10, 20, 30, 40, 50, 60, 70, 80, 90, 100, ...

Answer:

97.85

I hope this helps!

The unit tangent vector at the point (0,1,4) is T(0,1,4)=(0, -1, 0).

The unit tangent vector at the point (0,1,4) for the curve r(t)=2ln(t),e^(1-t), 4sqrt(t) is given by:

T(0,1,4)=∇r(t)/|∇r(t)|=(2/t, -e^(1-t), 8/2√t)/√(4/t^2 + e^2(1-t) + 64/4t)

Therefore, the unit tangent vector at the point (0,1,4) is:

T(0,1,4)=(2/0, -e^(1-0), 8/2√0)/√(4/0^2 + e^2(1-0) + 64/4*0)

=(0, -1, 0)/1

=(0, -1, 0)

To find the unit tangent vector, the first step is to find the gradient vector of r(t) at the point (0,1,4). The gradient vector is given by ∇r(t)=(2/t, -e^(1-t), 8/2√t).

Next, the unit tangent vector is calculated by dividing the gradient vector by its magnitude. The magnitude is given by the square root of the dot product of the gradient vector with itself, which is √(4/t^2 + e^2(1-t) + 64/4t). Finally, the unit tangent vector at the point (0,1,4) is T(0,1,4)=(0, -1, 0).


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-( ( 7 - u )( u - 2 ) ) is the factorized form of the polynomial -7u² + 12u + 4, using the AC method.

Given the polynomial in the question;

-7u² + 12u + 4

Factor out -1 out of the polynomial

-1( 7u² - 12u - 4 )

Compare to the form ax² + bx + c

To factor, compare to the form ax² + bx + c and rewrite the middle term as a sum of two terms whose product is;

a × c = 7 × -4 = -28

and whose sum is;

b = -12

Now, factor -12 out of -12x

-1( 7u² - 12(u) - 4 )

We know that -13 is the same as 2 plus -14

-1( 7u² - ( 2 - 14 )u - 4 )

Apply distributive property

-1( 7u² - 2u - 14u - 4 )

Group the terms

-1( u(7u - 2) - 2(7u - 2 ) )

-1( (7-u)(u-2) )

-( (7-u)(u-2) )

Therefore, the factorized form of the polynomial is -( ( 7 - u )( u - 2 ) ).

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-(7u+2)(u-2) is the factorized form of expression -7u²+12u+4.

An expression is combination of variables, numbers and operators.

The given expression is -7u²+12u+4.

We need to find the factors of this expression.

-7u²+12u+4.

This can be written as

-7u^2+14u-2u+4.

Take 7u from first two terms and 2 from last two terms in the expression.

-7u(u-2)-2(u-2)

(-7u-2)(u-2)

-(7u+2)(u-2)

Hence -(7u+2)(u-2) is the factorized form of -7u^2+12u+4.

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Answer:

28.26658805 (I included every digit in case your teacher needs you to round)

Step-by-step explanation:

In order to find x, we need to isolate x by subtracting 15^2 and taking the square root of both sides.

Thus, we have:

\(15^2+x^2=32^2\\x^2=32^2-15^2\\\sqrt{x^2} =\sqrt{(32^2-15^2)} \\\sqrt{x^2}=\sqrt{799} \\x=28.26658805\)

The sine and the cosine of the acute angle are the same for θ = π / 4. (Correct choice: 2)

Acute angles are angles whose measures are greater than 0° and less than 90°. According to the statement, we must find at least a value such that sin θ = cos θ:

sin θ = cos θ                     Given

sin θ / cos θ = 1                 Compatibility with multiplication / Existence of multiplicative inverse / Modulative property

tan θ = 1                            Definition of tangent

θ = π / 4                            Inverse trigonometric function / Result

In a nutshell, the sine and the cosine of the acute angle are the same for θ = π / 4. (Correct choice: 2)

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Answer:

37°

Step-by-step explanation:

angle B = angle D (alternate angle)

2X = 74°

X = 37°

Answer:

29

Step-by-step explanation:

right in acellus

Answer:

Step-by-step explanation:

If AD=DB  and  AE=EC,

then DE¯¯¯¯¯∥BC¯¯¯¯¯ and DE=12BC .

Answer:

Options A C and D

Step-by-step explanation:

Did the edge

Answer:

\(\mbox{\large $0.5 + 0.16 \bar {3}$ = \boxed{\dfrac{199}{300}}}\)

Step-by-step explanation:

\(0.16\bar{3} = 0.16333333333\\\)

the 3 repeats until infinity

Let's multiply this by 100 to move the non-repeating part to the left of the decimal point

0.1633333333...... x 100 = 16.333333333333333...

.333333 = 1/3

Therefore the recurring number multiplied by 100 is
\(16 + \dfrac{1}{3} = \dfrac{16 \times 3 + 1}{3}=\dfrac{49}{3}\)

Since this fraction was arrived at by multiplying by 100, divide this fraction by 100 to get back the fraction in its original decimal value of 0.163333

\(\dfrac{49}{3} \div 100\)

To divide by a number, multiply by the reciprocal of that number

Reciprocal of 100 is 1/100:

\(\dfrac{49}{3} \div 100 = \dfrac{49}{3} \times \dfrac{1}{100} = \dfrac{49}{300}\)

(You can verify this by dividing 49 by 300 in a calculator and seeing that the result is 0.163333333333333333333 i.e. 0.16333 recurring

We want to add 0.5 to this.

0.5 = \(\dfrac{1}{2}\)

so
0.5 + 0.16333333 = 0.6633333

\(= \dfrac{1}{2} + \dfrac{49}{300}\)

We can write \(\dfrac{1}{2}\) as \(\dfrac{150}{300}\)  by multiplying numerator and denominator by 150

So we get

\(0.5 + 0.1633333 = \dfrac{150}{300} + \dfrac{49}{300} = \dfrac{150+49}{300} = \dfrac{199}{300}\)

If you perform this division on a calculator you will get the answer as 0.663333 = \(0.66\bar{3}\) which is what you get when you add 0.5 and \(0.16\bar{3}\)

The mean and standard deviation of the data sets are;

a. 60.83, 15.11

b. 44, 4.03

c. 7.2, 3.7

d. 114.4, 10.74

The term "standard deviation" (or "") refers to a measurement of the data's dispersion from the mean. A low standard deviation implies that the data are grouped around the mean, whereas a large standard deviation shows that the data are more dispersed.

The mean of a data is the average of the data across the points.

a. data set; 35, 50, 60, 75, 65, 80

mean = 60.83

standard deviation = 15.11

b. data set; 51, 48, 47, 46, 45, 43, 41, 40, 40, 39

mean = 44

standard deviation = 4.03

c. data set; 11, 7, 14, 2, 8, 13, 3, 6, 10, 3, 8, 4, 8, 4, 7

mean = 7.2

standard deviation = 3.7

d. data set; 135, 115, 120, 110, 110, 100, 105, 110, 125

mean = 114.4

standard deviation = 10.74

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Answer:

Please finish question.

Step-by-step explanation:

Hello! I would be able to answer your question if you finish your question.

Answer:

MIXED NUMBER

Step-by-step explanation:

A fraction number is not changed when it is divided by _mixed_ numbers.

The probability that the experiment results in 6 or more successes is 0.7437.

To find the probability of 6 or more successes in a binomial experiment with probability of success = 0.64 and n=8 trials, we need to use the binomial probability formula:

P(X ≥ 6) = P(X=6) + P(X=7) + P(X=8)

where X is the number of successes in the 8 trials.

Using the binomial probability formula, we can calculate each of these probabilities:

P(X=6) = (8 choose 6) * 0.64^6 * 0.36^2 = 0.2546

P(X=7) = (8 choose 7) * 0.64^7 * 0.36^1 = 0.3213

P(X=8) = (8 choose 8) * 0.64^8 * 0.36^0 = 0.1678

Now, we can add these probabilities to get the probability of 6 or more successes:

P(X ≥ 6) = 0.2546 + 0.3213 + 0.1678 = 0.7437

Therefore, the probability that the experiment  in 6 or more successes is 0.7437.

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Answer:

y= -4

Step-by-step explanation:

Since x=1, then you would plug in 1 for x. 3 times 1 is 3, then you subtract 7 to get -4.

The derivative of arcsin(x/3) is\((3/sqrt(1-(x/3)^2))\). This can be derived by using the chain rule on arcsin(x/3) and simplifying.

The derivative of arcsin(x/3) can be derived by using the chain rule.

The chain rule states that the derivative of a function f composed with another function g is the derivative of f multiplied by the derivative of g.

Therefore, the derivative of arcsin(x/3) is

\(d/dx arcsin(x/3) = d/dx (x/3) * (1/cos(x/3))\)

Simplifying this expression, we get

\(d/dx arcsin(x/3) = (3/cos(x/3)) * (1/cos(x/3))\)

Which simplifies to

\(d/dx arcsin(x/3) = (3/cos^2(x/3))\)

Using the identity \(1/cos^2(x) = 1 + tan^2(x)\), we can rewrite this expression as

\(d/dx arcsin(x/3) = 3/sqrt(1-(x/3)^2)\)

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The intervals are nested, each subsequent interval is contained within the previous one. Mathematically, this means I₁ ⊇ I₂ ⊇ ... In ⊇ ... . Therefore, we have:

1. I₁ ⊇ I₂ implies [a₁; b₁] ⊇ [a₂; b₂], which means a₁ ≤ a₂ and b₁ ≥ b₂.
2. I₂ ⊇ I₃ implies [a₂; b₂] ⊇ [a₃; b₃], which means a₂ ≤ a₃ and b₂ ≥ b₃.

To show that a1 ≤ a2 ≤ ... ≤ an ≤ ..., we need to use the fact that the sequence of intervals is nested, meaning that each interval is contained within the next one.

First, we know that I1 contains I2, so every point in I2 is also in I1. That means that a1 ≤ a2 and b1 ≥ b2.

Now consider I2 and I3. Again, every point in I3 is also in I2, so a2 ≤ a3 and b2 ≥ b3.

We can continue this process for all the intervals in the sequence, until we reach In. So we have:

a1 ≤ a2 ≤ ... ≤ an-1 ≤ an

and

b1 ≥ b2 ≥ ... ≥ bn-1 ≥ bn

This shows that the endpoints of the intervals are ordered in the same way.

Given that I₁ ⊇ I₂ ⊇ ... In ⊇ ... is a nested sequence of intervals and In = [an; bn], we can show that a₁ ≤ a₂ ≤ ... ≤ an ≤ ... and b₁ ≥ b₂ ≥ ... ≥ bn ≥ ... as follows:

Since the intervals are nested, each subsequent interval is contained within the previous one. Mathematically, this means I₁ ⊇ I₂ ⊇ ... In ⊇ ... . Therefore, we have:

1. I₁ ⊇ I₂ implies [a₁; b₁] ⊇ [a₂; b₂], which means a₁ ≤ a₂ and b₁ ≥ b₂.
2. I₂ ⊇ I₃ implies [a₂; b₂] ⊇ [a₃; b₃], which means a₂ ≤ a₃ and b₂ ≥ b₃.

Continuing this pattern for all intervals in the sequence, we can conclude that a₁ ≤ a₂ ≤ ... ≤ an ≤ ... and b₁ ≥ b₂ ≥ ... ≥ bn ≥ ... .

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The maximum period of time they could reserve the meeting space is 9 hours.

Mathematical expressions with the symbols > and are known as inequality. Finding a range, or ranges within ranges, of values that an unknown x can have while still satisfying the inequality is referred to as "solving" an inequality. In this lesson, inequalities are resolved using graphs and algebra.

An algebraic inequality expression is a mathematical statement that uses the it as a sign to connect an expression to a value, a variable, or another expression. One type of variable inequalities can have solutions that can be graphed either in a coordinate plane or on a number line.

Inequality expression is 31 + 5.9*t < 84.10.

To understand it, collect all constant on the right side:

5.9*t < 84.10 - 31 = 53.10,

Hence, t < 53.10 % 5.9 = 9 hours.

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Correct Question:

To rent a certain meeting room, a college charges a reservation fee of $31 and an additional fee of $5.90 per hour. The chemistry club wants to spend less than $84.10 on renting the meeting room. What are the possible amounts of time for which they could rent the meeting room? Use t for the number of hours the meeting room is rented, and solve your inequality for t.

Answer:

5h+6

Step-by-step explanation:

I was litterly just doing this trust me im right lol

Answer:

D. 10h+12

Step-by-step explanation:

You have to multiply to find the area of each rectangle. There are 3 pairs of rectangles that are identical to one another.

2*h = 2h * 2 = 4h

3*h = 3h *2 = 6h

2*3 = 6 *2 = 12

10h+12